Search Results

Search found 44327 results on 1774 pages for 'python image library'.

Page 324/1774 | < Previous Page | 320 321 322 323 324 325 326 327 328 329 330 331  | Next Page >

• It's possible make an OCR in Python to check words...

  - by Shady

  in opened applications? I want to automate firefox in some web page and I don't have a way to "know" if the page already load completely or if it still loading... I was thinking about making an OCR to check the status bar... it's difficult ? For example, when the word DONE appears at the status bar, the program continues to the next command...

  Read the article

• PIP: how do I install a python package into a different directory?

  - by Monika Sulik

  I know the obvious answer is to use virtualenv and virtualenvwrapper, but for various reasons I can't/don't want to do that. So how do I modify this command: pip install package_name to make pip install the package somewhere other than the default site-packages?

  Read the article

• How to delete avery reference of an object in Python?

  - by Juanjo Conti

  Supose you have something like: x = "something" b = x l = [b] How can you delete the object only having one reference, say a? del a won't do the tric; the object is still reachable from b, for example.

  Read the article

• Creating a list in Python with multiple copies of a given object in a single line.

  - by Deniz

  Suppose I have a given Object (a string "a", a number - let's say 0, or a list ['x','y'] ) I'd like to create list containing many copies of this object, but without using a for loop: L = ["a", "a", ... , "a", "a"] or L = [0, 0, ... , 0, 0] or L = [['x','y'],['x','y'], ... ,['x','y'],['x','y']] I'm especially interested in the third case. Thanks!

  Read the article

• Anyone use Pyjamas (pyjs) python to javascript compiler (like GWT..)

  - by mike

  Has any one used this? I don't have a large background in Javascript and this lib looks like it may speed things along. www.pyjs.org

  Read the article

• How to access a superclass's class attributes in Python?

  - by Brecht Machiels

  Have a look at the following code: class A(object): defaults = {'a': 1} def __getattr__(self, name): print('A.__getattr__') return self.get_default(name) @classmethod def get_default(cls, name): # some debug output print('A.get_default({}) - {}'.format(name, cls)) try: print(super(cls, cls).defaults) # as expected except AttributeError: #except for the base object class, of course pass # the actual function body try: return cls.defaults[name] except KeyError: return super(cls, cls).get_default(name) # infinite recursion #return cls.__mro__[1].get_default(name) # this works, though class B(A): defaults = {'b': 2} class C(B): defaults = {'c': 3} c = C() print('c.a =', c.a) I have a hierarchy of classes each with its own dictionary containing some default values. If an instance of a class doesn't have a particular attribute, a default value for it should be returned instead. If no default value for the attribute is contained in the current class's defaults dictionary, the superclass's defaults dictionary should be searched. I'm trying to implement this using the recursive class method get_default. The program gets stuck in an infinite recursion, unfortunately. My understanding of super() is obviously lacking. By accessing __mro__, I can get it to work properly though, but I'm not sure this is a proper solution. I have the feeling the answer is somewhere in this article, but I haven't been able to find it yet. Perhaps I need to resort to using a metaclass?

  Read the article

• Trouble with this Python newbie exercise. Using Lists and finding if two adjacent elements are the s

  - by Sergio Tapia

  Here's what I got: # D. Given a list of numbers, return a list where # all adjacent == elements have been reduced to a single element, # so [1, 2, 2, 3] returns [1, 2, 3]. You may create a new list or # modify the passed in list. def remove_adjacent(nums): for number in nums: numberHolder = number # +++your code here+++ return I'm kind of stuck here. What can I do?

  Read the article

• How do I list all classes of a given type in a python file?

  - by Hobhouse

  I use django, and have a lengthy models.py file. class Foo(models.Model): name = models.CharField() class Bar(models.Model): name = models.CharField() class Fab(models.Model): name = models.CharField() Is there a way to make a list of all the classes in the file which are an instance of (models.Model)?

  Read the article

• Python: Recursively access dict via attributes as well as index access?

  - by Luke Stanley

  I'd like to be able to do something like this: from dotDict import dotdictify life = {'bigBang': {'stars': {'planets': [] } } } dotdictify(life) #this would be the regular way: life['bigBang']['stars']['planets'] = {'earth': {'singleCellLife': {} }} #But how can we make this work? life.bigBang.stars.planets.earth = {'singleCellLife': {} } #Also creating new child objects if none exist, using the following syntax life.bigBang.stars.planets.earth.multiCellLife = {'reptiles':{},'mammals':{}} My motivations are to improve the succinctness of the code, and if possible use similar syntax to Javascript for accessing JSON objects for efficient cross platform development.(I also use Py2JS and similar.)

  Read the article

• Python: Number of rows affected by cursor.execute("SELECT ...)

  - by Tie-fighter

  How can I access the number of rows affected by: cursor.execute("SELECT COUNT(*) from result where server_state='2' AND name LIKE '"+digest+"_"+charset+"_%'")

  Read the article

• How can I convert data encoded in WE8MSWIN1252 to utf8 for use in Python scripts?

  - by James Dean

  This data comes from an Oracle database and is extracted to flatfiles in encoding 'WE8MSWIN1252'. I want to parse the data and do some analysis. I want to see the text fields but do not need to publish the results to any other system so if some characters do not get converted perfectly I do not have a problem with that. I just do not want my parsing to fail with a decode error which is what I get if I use: inputFile = codecs.open( dataFileName, "r", "utf-8'")

  Read the article

• How to make Python check if ftp directory exists?

  - by Phil

  I'm using this script to connect to sample ftp server and list available directories: from ftplib import FTP ftp = FTP('ftp.cwi.nl') # connect to host, default port (some example server, i'll use other one) ftp.login() # user anonymous, passwd anonymous@ ftp.retrlines('LIST') # list directory contents ftp.quit() How do I use ftp.retrlines('LIST') output to check if directory (for example public_html) exists, if it exists cd to it and then execute some other code and exit; if not execute code right away and exit?

  Read the article

• 'int' object is not callable when the object is a list? Python

  - by controlfreak123

  coinCount = [2 for i in range(4)] total = sum(coinCount) This gives me TypeError: 'int' object is not callable I don't understand why because print type(coinCount) Gives me type <'list'>

  Read the article

• Python: Why "is" keyword act different behavior when there is dot in the string?

  - by S.Mark

  >>> x = "test" >>> x is "test" True >>> x = "test.test" >>> x is "test.test" False Can someone give me some hints why its like that?

  Read the article

• python and paramiko: how to check if end of ssh tunnel is still alive and reestablish if not?

  - by Christian

  Hello all, I'm trying to achieve the following: I have two hosts A and B. A establishes a remote port forwarding tunnel on B, i.e. B is the one a port is forwarded on to some where else and A is the one that sets up the tunnel. I tried the script rforward.py that ships with paramiko and it works very well so far. (I'm running rforward.py on A, which connects to B and forwards a port of B to somewhere else) However, when B is shutting down, A doesn't seem to recognize it. I'd rather like A to recognize that B is down and to try to reestablish the connection periodically in case B comes up again. Is there a way to do this? Thanks.

  Read the article

• How do I do an "OR" for my python regex?

  - by alex

  re.compile("abc") I would like to do "abc" OR "xyz".

  Read the article

• How do I get a decimal value when using the division operator in Python?

  - by Ray Vega

  For example, the standard division symbol '/' rounds to zero: >>> 4 / 100 0 However, I want it to return 0.04. What do I use?

  Read the article

• What's the standard config file name and extension in Python?

  - by froadie

  I'm creating a config file to hold configuration/properties settings for my project that frequently change, such as file paths. What's the standard name/extension for such a file? (e.g. in Java I've used config.xml, in VB.NET I've used App.config...)

  Read the article

• How to read a file byte by byte in Python and how to print a bytelist as a binary?

  - by zaplec

  Hi, I'm trying to read a file byte by byte, but I'm not sure how to do that. I'm trying to do it like that: file = open(filename, 'rb') while 1: byte = file.read(8) # Do something... So does that make the variable byte to contain 8 next bits at the beginning of every loop? It doesn't matter what those bytes really are. The only thing that matters is that I need to read a file in 8-bit stacks. EDIT: Also I collect those bytes in a list and I would like to print them so that they don't print out as ASCII characters, but as raw bytes i.e. when I print that bytelist it gives the result as ['10010101', '00011100', .... ]

  Read the article

• Python Introspection: How to get varnames of class methods?

  - by daccle

  I want to get the names of the keyword arguments of the methods of a class. I think I understood how to get the names of the methods and how to get the variable names of a specific method, but I don't get how to combine these: class A(object): def A1(self, test1=None): self.test1 = test1 def A2(self, test2=None): self.test2 = test2 def A3(self): pass def A4(self, test4=None, test5=None): self.test4 = test4 self.test5 = test5 a = A() # to get the names of the methods: for methodname in a.__class__.__dict__.keys(): print methodname # to get the variable names of a specific method: for varname in a.A1.__func__.__code__.co_varnames: print varname # I want to have something like this: for function in class: print function.name for varname in function: print varname # desired output: A1 self test1 A2 self test2 A3 self A4 self test4 test5

  Read the article

• Save memory in Python. How to iterate over the lines and save them efficiently with a 2million line

  - by skyl

  I have a tab-separated data file with a little over 2 million lines and 19 columns. You can find it, in US.zip: http://download.geonames.org/export/dump/. I started to run the following but with for l in f.readlines(). I understand that just iterating over the file is supposed to be more efficient so I'm posting that below. Still, with this small optimization, I'm using 10% of my memory on the process and have only done about 3% of the records. It looks like, at this pace, it will run out of memory like it did before. Also, the function I have is very slow. Is there anything obvious I can do to speed it up? Would it help to del the objects with each pass of the for loop? def run(): from geonames.models import POI f = file('data/US.txt') for l in f: li = l.split('\t') try: p = POI() p.geonameid = li[0] p.name = li[1] p.asciiname = li[2] p.alternatenames = li[3] p.point = "POINT(%s %s)" % (li[5], li[4]) p.feature_class = li[6] p.feature_code = li[7] p.country_code = li[8] p.ccs2 = li[9] p.admin1_code = li[10] p.admin2_code = li[11] p.admin3_code = li[12] p.admin4_code = li[13] p.population = li[14] p.elevation = li[15] p.gtopo30 = li[16] p.timezone = li[17] p.modification_date = li[18] p.save() except IndexError: pass if __name__ == "__main__": run()

  Read the article

• How do I split filenames from paths using python?

  - by Rasputin Jones

  I have a list of files that look like this: Input /foo/bar/baz/d4dc7c496100e8ce0166e84699b4e267fe652faeb070db18c76669d1c6f69f92.mp4 /foo/baz/bar/60d24a24f19a6b6c1c4734e0f288720c9ce429bc41c2620d32e01e934bfcd344.mp4 /bar/baz/foo/cd53fe086717a9f6fecb1d0567f6d76e93c48d7790c55e83e83dd1c43251e40e.mp4 And I would like to split out the filenames from the path while retaining both. Output ['/foo/bar/baz/', 'd4dc7c496100e8ce0166e84699b4e267fe652faeb070db18c76669d1c6f69f92.mp4'] ['/foo/baz/bar/', '60d24a24f19a6b6c1c4734e0f288720c9ce429bc41c2620d32e01e934bfcd344.mp4'] ['/bar/baz/foo', 'd53fe086717a9f6fecb1d0567f6d76e93c48d7790c55e83e83dd1c43251e40e.mp4'] How would one go about this? Thanks!

  Read the article

• How I can get rid of None values in dictionary? Python

  - by Vojtech R.

  Something like: for (a,b) in kwargs.iteritems(): if not b : del kwargs[a] This code raise exception because changing of dictionary when itering... I discover only non pretty solution with another dictionary: res ={} res.update((a,b) for a,b in kwargs.iteritems() if b is not None) Thanks

  Read the article

• Python: re-initialize a function's default value for subsequent calls to the function.

  - by Peter Stewart

  I have a function that calls itself to increment and decrement a stack. I need to call it a number of times, and I'd like it to work the same way in subsequent calls but, as expected, it doesn't re-use the default value. I've read that this is a newbie trap and I've seen suggested solutions, but I haven't been able to make any solution work. It would be nice to be able to "fun.reset" def a(x, stack = [None]): print x,' ', stack if x > 5: temp = stack.pop() if x <=5: stack.append(1) if stack == []: return a(x + 1) print a(0) print a(2) #second call print a(3) #third call I expected this to work, but it doesn't. print a(0, [None]) print a(2, [None]) #second call print a(3, [None]) #third call Can I reset the function to it's initial state? Any help would be appreciated.

  Read the article

• Python. How to iterate through a list of lists looking for a partial match

  - by Becca Millard

  I'm completely stuck on this, without even an idea about how to wrap my head around the logic of this. In the first half of the code, I have successfully generation a list of (thousands of) lists of players names and efficiency scores: eg name_order_list = [["Bob", "Farley", 12.345], ["Jack", "Donalds", 14.567], ["Jack", "Donalds", 13.421], ["Jack", "Donalds", 15.232],["Mike", "Patricks", 10.543]] What I'm trying to do, is come up with a way to make a list of lists of the average efficiency of each player. So in that example, Jack Donalds appears multiple times, so I'd want to recognize his name somehow and average out the efficiency scores. Then sort that new list by efficiency, rather than name. So then the outcome would be like: average_eff_list = [[12.345, "Bob", "Farley"], [14.407, "Jack", "Donalds"], [10.543, "Mike", "Patricks"]] Here's what I tried (it's kind of a mess, but should be readable): total_list = [] odd_lines = [name_order_list[i] for i in range(len(name_order_list)) if i % 2 == 0] even_lines = [name_order_list[i] for i in range(len(name_order_list)) if i % 2 == 1] i = 0 j = i-1 while i <= 10650: iteration = 2 total_eff = 0 while odd_lines[i][0:2] == even_lines[i][0:2]: if odd_lines[i][0:2] == even_lines[j][0:2]: if odd_lines[j][0:2] != even_lines[j][0:2]: total_eff = even_lines[j][2]/(iteration-1) iteration -= 1 #account fr the single (rather than dual) additional entry else: total_eff = total_eff if iteration == 2: total_eff = (odd_lines[i][2] + even_lines[i][2]) / iteration else: total_eff = ((total_eff * (iteration - 2)) + (odd_lines[i][2] + even_lines[i][2])) / iteration iteration += 2 i += 1 j += 1 if i > 10650: break else: if odd_lines[i][0:2] == even_lines[j][0:2]: if odd_lines[j][0:2] != even_lines[j][0:2]: total_eff = (odd_lines[i][2] + even_lines[j][2]) / iteration else: total_eff = ((total_eff * (iteration -2)) + odd_lines[i][2]) / (iteration - 1) if total_eff == 0: #there's no match at all total_odd = [odd_lines[i][2], odd_lines[i][0], odd_lines[i][1]] total_list.append(total_odd) if even_lines[i][0:2] != odd_lines[i+1][0:2]: total_even = [even_lines[i][2], even_lines[i][0], even_lines[i][1]] else: total = [total_eff, odd_lines[i][0], odd_lines[i][1]] total_list.append(total) i += 1 if i > 10650: break else: print(total_list) Now, this runs well enough (doesn't get stuck or print someone's name multiple times) but the efficiency values are off by a large amount, so I know that scores are getting missed somewhere. This is a problem with my logic, I think, so any help would be greatly appreciated. As would any advice about how to loop through that massive list in a smarter way, since I'm sure there is one... EIDT: for this exercise, I need to keep it all in a list format. I can make new lists, but no using dictionaries, classes, etc.

  Read the article

< Previous Page | 320 321 322 323 324 325 326 327 328 329 330 331  | Next Page >