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  • How to echo an array in PHP?

    - by Kaoukkos
    The following code $results = $facebook->api('/fql', array('q'=>'SELECT page_id, type FROM page_admin WHERE uid = me()')); print_r($results); returned me this array Array ( [data] => Array ( [0] => Array ( [page_id] => 204725966262837 [type] => WEBSITE ) [1] => Array ( [page_id] => 163703342377960 [type] => COMMUNITY ) ) ) My question is how can I just echo the content without this structure? I tried foreach ($results as $result) { echo $result->type; echo "<br>"; }

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  • Need Help in PHP Regex

    - by amateurs
    I am studying about regex, i figured out some about matching one or more character, but i have a case, but don't know how to solve this.. For example i have: $data = "bla bla -start- blu blu blu -end- bla bla"; $pattern = "/\-start\-[\w]\-end\- /"; preg_match($pattern, $data, $matches); print_r($matches); i intend to take anything between '-start-' and '-end-', so i expect to get ' blu blu blu '. any suggestion ?

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  • php multidimensional array if loop

    - by user1091558
    I have a multidimensional array like this array[value][1][1] Now i would like to implement if loop like this if ($value = array[value][1][1]) { echo "It works"; } Now it works if i assign the values like [1][1],[2][1]. Is it possible to compare the whole array. I mean if the array looks like array[value][1][1],array[value][2][1],..........,array[value][n][1] It works should be echoed. I tried like this. if ($value = array[value][][]) { echo "It works"; } But its not working. Can anyone give me the correct syntax?

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  • PHP : If...Else...Query

    - by Rachel
    I am executing this statement under while (($data=fgetcsv($this->fin,5000,";"))!==FALSE) Now what I want in else loop is to throw exception only for data value which did not satisfy the if condition. Right now am displaying the complete row as I am not sure how to throw exception only for data which does not satisfy the value. Code if ((strtotime($data[11]) &&strtotime($data[12])&&strtotime($data[16]))!==FALSE && ctype_digit($data[0]) && ctype_alnum($data[1]) && ctype_digit($data[2]) && ctype_alnum($data[3]) && ctype_alnum($data[4]) && ctype_alnum($data[5]) && ctype_alnum($data[6]) && ctype_alnum($data[7]) && ctype_alnum($data[8]) && $this->_is_valid($data[9]) && ctype_digit($data[10]) && ctype_digit($data[13]) && $this->_is_valid($data[14])) { //Some Logic } else { throw new Exception ("Data {$data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $data[8], $data[9], $data[10], $data[11], $data[12], $data[13], $data[14], $data[16]} is not in valid format"); } Guidance would be highly appreciated as to how can I throw exception only for data which did not satisfy the if value.

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  • PHP - Search array in array

    - by Anonymous2011
    I have tried googling for the past one hour straight now and tried many ways to search for an array, in an array. My objective is, to find a keyword in the URL, and the keywords are in a txt file. This is what i have so far - but doesn't work. $file = "keywords.txt"; $open = fopen($file,'r'); $data = fread($open,filesize($file)); $data = explode(" ",$data); $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = parse_url($url); //parse the URL into an array foreach($data as $d) { if(strstr($d,$url)) { echo "yes"; } } This works WITHOUT the text file, or array - but that's not what i want. I'd appreciate it if anyone can assist me.

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • PHP Array to CSV

    - by JohnnyFaldo
    I'm trying to convert an array of products into a CSV file, but it doesn't seem to be going to plan. The CSV file is one long line, here is my code: for($i=0;$i<count($prods);$i++) { $sql = "SELECT * FROM products WHERE id = '".$prods[$i]."'"; $result = $mysqli->query($sql); $info = $result->fetch_array(); } $header = ''; for($i=0;$i<count($info);$i++) { $row = $info[$i]; $line = ''; for($b=0;$b<count($row);$b++) { $value = $row[$b]; if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$data"; Also, the header doesn't force a download. I've been copy and pasting the output and saving as .csv

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  • php: parsing and converting array structure

    - by mwb
    I need to convert one array structure into another array structure. I hope someone will find it worthy their time to show how this could be done in a simple manner. It's a little above my array manipulation skills. The structure we start out with looks like this: $cssoptions = array( array( 'group' => 'Measurements' , 'selector' => '#content' , 'rule' => 'width' , 'value' => '200px' ) // end data set , array( 'group' => 'Measurements' , 'selector' => '#content' , 'rule' => 'margin-right' , 'value' => '20px' ) // end data set , array( 'group' => 'Colors' , 'selector' => '#content' , 'rule' => 'color' , 'value' => '#444' ) // end data set , array( 'group' => 'Measurements' , 'selector' => '.sidebar' , 'rule' => 'margin-top' , 'value' => '10px' ) // end data set ); // END $cssoptions It's a collection of discreet datasets, each consisting of an array that holds two key = value pairs describing a 'css-rule' and a 'css-rule-value'. Further, each dataset holds a key = value pair describing the 'css-selector-group' that the 'css-rule' should blong to, and a key = value pair describing a 'rule-group' that should be used for structuring the rendering of the final css into a neat css code block arranged by the kind of properties they describe (colors, measurement, typography etc..) Now, I need to parse that, and turn it into a new structure, where the: 'rule' => 'rule-name' , 'value' => 'value-string' for each dataset is converted into: 'rule-name' => 'value-string' ..and then placed into a new array structure where all 'rule-name' = 'value-string' pairs should be aggregated under the respective 'selector-values' Like this: '#content' => array( 'width' => '200px' , 'margin-right' => '20px' ) // end selecor block ..and finally all those blocks should be grouped under their respective 'style-groups', creating a final resulting array structure like this: $css => array( 'Measurements' => array( '#content' => array( 'width' => '200px' , 'margin-right' => '20px' ) // end selecor block , '.sidebar' => array( 'margin-top' => '10px' ) // end selector block ) // end rule group , 'Colors' => array( '#content' => array( 'color' => '#444' ) // end selector block ) // end rule group ); // end css

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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  • generating images by user id php + mysql

    - by jay
    function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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  • clear php empty array

    - by redcoder
    i have the following array and want to get rid/remove the empty array and rearrange it in an order.can anyone help me please. Array ( [ufile] => Array ( [name] => Array ( [0] => chicken soup.jpg [1] => [2] => hot n sour sup.jpg [3] => [4] => [5] => [6] => [7] => [8] => ) [type] => Array ( [0] => [1] => [2] => [3] => [4] => [5] => [6] => [7] => [8] => ) [tmp_name] => Array ( [0] => [1] => [2] => [3] => [4] => [5] => [6] => [7] => [8] => ) [error] => Array ( [0] => 1 [1] => 4 [2] => 1 [3] => 4 [4] => 4 [5] => 4 [6] => 4 [7] => 4 [8] => 4 ) [size] => Array ( [0] => 0 [1] => 0 [2] => 0 [3] => 0 [4] => 0 [5] => 0 [6] => 0 [7] => 0 [8] => 0 ) ) )

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  • [PHP] converting mysql data into array?

    - by Mahmoud
    i have an ajax script that check if the user name is available or not, but it keeps taking the newest user name and the rest are out $result = mysql_query("Select username from customer"); while ($row = mysql_fetch_array($result)){ $existing_users=array(''.$row['username'].','); } i know i am doing something worng

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  • PHP - Patterns within Arrays

    - by Toby
    I am trying to create a function which maps a recurring pattern of integers using an array. As an example if I have a starting array of (0,1,3) and I know that I want to stop the pattern when I hit 15. The pattern gets incremented by a fixed integer each time (lets say 4) so my final pattern should be.. 0 1 3 4 (0 + 4) 5 (1 + 4) 7 (2 + 4) 8 (4 + 4) 9 (5 + 4) 11(7 + 4) 12(8 + 4) 13(9 + 4) 15(11+ 4) Does anyone have any pointers on how this can be achieved? My current implementation works but is stupidly inefficient which something like this... $array = array(0,1,3); $inc = 4; $end = end($array); $final = 15; while($end < $final) { $tmp = array(); foreach($array AS $row) { $tmp = $row + $inc; } $array = merge($tmp, $array); $end = end($array); }

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  • php web based portal authentication through IP.

    - by user434885
    i have a web portal running which involves basic data entry. The issue being that this is highly sensitive data. And the credibility of the data entry personel is very low. Therefore i have implemented recording of IP when an entry is made. The Problem i am facing is if this if this person starts forwarding his IP from a proxy server then i am unable to track authenticity of the data. How do i detect if the IP forwarding is happening/ get the real ip address of the person.

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  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

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  • PHP/MySQL - an array filter for bots

    - by Mike
    Hello, I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results. Here is what I have now: while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) { <-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -- } Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

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  • Login system and sessions (php)

    - by Jonathan
    I've created a login page and registration page and now I want to use that to password protect pages and have pages which show information specific to that user. Would storing the user ID of the user logged in in a Session variable be a safe and correct way of doing this? How easy would it be for a user to change the session variable to a different ID and access another user's information, and not having to type the users login details in?

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  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

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  • Php dynamic class construction

    - by pistacchio
    Hi to all, I'm trying to avoid the use of eval. I can dynamically instantiate a class like this: class myclass {} $my_class_name = 'myclass'; $obj = new $myclass(); If the constructor is like follows: class myclass { public function __construct( $argument1, $argument2 ) {} } and i have the values of the arguments in an array, how can i dynamically instantiate the class and pass it dynamic arguments? Mind that I have no way to modify the class, so I have to work on the way of using it. Thanks

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