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  • How can I use MVC ideas without using classes?

    - by jpjp
    As of right now, I am still shaky on classes, so I don't want to use any classes for my site. I'm still practicing with classes. But how can I implement the MVC idea without classes? Would this work for a MVC? index.php (the view) index_controller.php index_model.php Is this right for what a MVC should be? View: show html, css, forms Controller: get $_POST from forms and any data from the user, get info from db Model: do all the functions, insert/delete in db, etc Basically separate the HTML/css for the view, all the data collecting for the controller, and the logic for the model. And just connect them all using require_once.

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  • Actionscript package naming and directory structure

    - by danwoods
    Hello all, I've got some actionscript which begins with: package obfus_plugin{ import org.flowplayer.model.Plugin; import org.flowplayer.util.Arrange; import org.flowplayer.model.PluginModel; import org.flowplayer.view.Flowplayer; and when I try to publish, I get the error: 5001: The name of package 'obfus_plugin' does not reflect the location of this file. Please change the package definition's name inside this file, or move the file. C:\Documents and Settings\***\My Documents\My Dropbox\Public\obfus_plugin\obfus_plugin.as In my classpaths I have: C:\Documents and Settings\***\My Documents\My Dropbox\Public What am I doing wrong?

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  • Silverlight dataGrid binding with ria Service doesn' work

    - by Abdulrhman
    hi every one i'm new to Silverlight and it's totally driving me crazy !! i'm using SL4 and trying to bind datagrid with a Domain Service Query: what i did exactly is i generate an ado.net entity model from my database, then create a domain Service class from this model. then in my page i put Datagrid & button. in the click event for this button i write this code: RRDomainContext rr = new RRDomainContext(); this.dataGrid1.ItemsSource = rr.Rooms; this.rr.Load(this.rr.GetRoomsQuery()); when this method executed the nothing changed at the datagrid. can anyone help me with this ?

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  • can QuickGraph support these requirements? (includes database persistence support)

    - by Greg
    Hi, Would QuickGraph be able to help me out with my requirements below? (a) want to model a graph of nodes and directional relationships between nodes - for example to model web pages/files linked under a URL, or modeling IT infrastructure and dependencies between hardware/software. The library would include methods such as * Node.GetDirectParents() //i.e. there could be more than one direct parent for a node * Node.GetRootParents() //i.e. traverse the tree to the top root parent(s) for the given node * Node.GetDirectChildren() * Node.GetAllChildren() (b) have to persist the data to a database - so it should support SQL Server and ideally SQLite as well. If it does support these requirement then I'd love to hear: any pointers to any parts of QuickGraph to dig into? what is the best concept re it's usage in terms of how to use database persistence - is it a simpler design to assume every search/method works directly on the database, or does QuickGraph support smarts to be able to work in memory and the "save" to database all changes at an appropriate point in time (e.g. like ADO.net does with DataTable etc) Thanks in advance

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  • JSF data transfer between UI and business layer

    - by Ram
    Hi, We are using JSF in UI, Spring in business layer, Hibernate in persistence layer. Now my question is how to pass data from the JSF UI to spring business layer. Can I directly use my business object in my backing bean or should I transfer data between the layer through DTO? Can one explain me with clear explanation if possible with piece of code and that related websites?

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  • ASP.net MVC Using view models in different views

    - by Azhar Rana
    i have 2 customer views one for create and one for edit. i am using the same Customer view model for both. i want to make the 'customer no field' required on the add but not the edit. if i put the requiredfield attribute on the view model property then both views flag 'Customer No' as required (as you would expect). Is there a built in solution to get around this problem or am i going to have to create 2 seperate view models, one with the attribute and one without. Thanks

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  • Create / build / generate a web form that can be on my server and has modern looks and could be impl

    - by Luay
    I have a small web site and would like to add a 'contact us' form and a 'feedback' form. i would like the forms to satisfy the following: 1- be modern looking (with beautiful css effects) 2- the form fields are validated properly and 'inline'. What I mean is once a user skips a required field or enters an email address incorrectly some kind of tooltip or icon is displayed to ask him to cerrect the error (as opposed to a message box that appears after the user clicks 'submit') 3- once the submit button is clicked the form contents are emailed to me. 4- the whole thing can be setup by a noob like myself. 5- no ads on the form I have been searching for at least 5 days for a solution but I can't seem to find anything the would satisfy the above 5 conditions. I don't mind paying for a solution as long as it is hosted on my site and it is a one off payment and not a monthly payment. So far my search has lead me to the following: 1 wufoo. The good: the generated forms seem to look okay but not the best there is. The bad: the free service is limited to 100 submissions. ads on the form. it is not hosted on my server. Paid service requires monthly payments 2- emailmeform: almost same as above except the generated form looks old. They do have an offer where you pay only $4 to get the form and set it up on your own site but that doesn't solve the fact that the forms look old. 3- formAssembly: same as above with minor variations (the generated form looks better) 4- formchamp, formthis, kontaktr,... And other similar online services: the same problem. either the form generated looks outdated or require monthly payments or they put ads...they don't satisfy my conditions. 5- coffeecup form builder. a desktop software. The problem is the generated forms look too old and use flash. 6- simfatic. Another software. Much better than coffeecup. almost satisfies my conditions but the forms not as good as I like. 7- many, many php scripts or html templates that look so outdated or fail when tested (probably because they are too old). Seriously guys, how hard is this. At least 90%+ of website contain at least a 'contact us' form. Why aren't there better solutions? if there is I can't seem to find them. In terms of looks I want something similar to this: http://web-kreation.com/articles/lightform-free-ajaxphp-contact-form/ It is called lightform. And this is a perfect example of what I mean by 'inline' validation. the only problem: there is no script to handle sending the mail. Even if I find one, I don't know how to modify it for my needs. So could you please help me out. I really can't search anymore. I reached rock bottom with this issue. I need a complete solution. If nothing exists then at least a: 1- form template (html) that looks nice and can easily be modified 2- a validation script that does 'inline' validation like the example above (or similar to it) and can be easily implemented by a noob like me to work with the html form. 3- a php script that will handle sending the email and can be easily implemented (all three working in harmony). I hope there is a complete solution but am I asking for too much? Pretty please...help...

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  • How do you store sets in Cassandra?

    - by Ben W
    I'd like to convert this JSON to a data model in Cassandra, where each of the arrays is a set with no duplicates: var data = { "data1": { "100": [1, 2, 3], "200": [3, 4] }, "data2": { "k1", [1], "k2", [4, 5] } } I'd like to query like this: data["data1"]["100"] to retrieve the sets. Anyone know how you might model this in Cassandra? (The only thing I came up with was columns whose name was a set value and the value of the column was an empty string, but that felt wrong.) It's not OK to serialize the sets as JSON or some other string, which would make this much easier. Also, I should note that it's OK to split data1 and data2 into separate ColumnFamilies, it's not necessary that they're keys in the same one.

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  • Custom keys for Google App Engine models (Python)

    - by Cameron
    First off, I'm relatively new to Google App Engine, so I'm probably doing something silly. Say I've got a model Foo: class Foo(db.Model): name = db.StringProperty() I want to use name as a unique key for every Foo object. How is this done? When I want to get a specific Foo object, I currently query the datastore for all Foo objects with the target unique name, but queries are slow (plus it's a pain to ensure that name is unique when each new Foo is created). There's got to be a better way to do this! Thanks.

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  • How can I make properties in properties files mandatory in Spring?

    - by Paulo Guedes
    I have an ApplicationContext.xml file with the following node: <context:property-placeholder location="classpath:hibernate.properties, classpath:pathConfiguration.properties" /> It specifies that both properties files will be used by my application. Inside pathConfiguration.properties, some paths are defined, such as: PATH_ERROR=/xxx/yyy/error PATH_SUCCESS=/xxx/yyy/success A PathConfiguration bean has setters for each path. The problem is: when some of those mandatory paths are not defined, no error is thrown. How and where should I handle this problem?

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  • ACL implementation

    - by Kirzilla
    First question Please, could you explain me how simpliest ACL could be implemented in MVC. Here is the first approach of using Acl in Controller... <?php class MyController extends Controller { public function myMethod() { //It is just abstract code $acl = new Acl(); $acl->setController('MyController'); $acl->setMethod('myMethod'); $acl->getRole(); if (!$acl->allowed()) die("You're not allowed to do it!"); ... } } ?> It is very bad approach, and it's minus is that we have to add Acl piece of code into each controller's method, but we don't need any additional dependencies! Next approach is to make all controller's methods private and add ACL code into controller's __call method. <?php class MyController extends Controller { private function myMethod() { ... } public function __call($name, $params) { //It is just abstract code $acl = new Acl(); $acl->setController(__CLASS__); $acl->setMethod($name); $acl->getRole(); if (!$acl->allowed()) die("You're not allowed to do it!"); ... } } ?> It is better than previous code, but main minuses are... All controller's methods should be private We have to add ACL code into each controller's __call method. The next approach is to put Acl code into parent Controller, but we still need to keep all child controller's methods private. What is the solution? And what is the best practice? Where should I call Acl functions to decide allow or disallow method to be executed. Second question Second question is about getting role using Acl. Let's imagine that we have guests, users and user's friends. User have restricted access to viewing his profile that only friends can view it. All guests can't view this user's profile. So, here is the logic.. we have to ensure that method being called is profile we have to detect owner of this profile we have to detect is viewer is owner of this profile or no we have to read restriction rules about this profile we have to decide execute or not execute profile method The main question is about detecting owner of profile. We can detect who is owner of profile only executing model's method $model-getOwner(), but Acl do not have access to model. How can we implement this? I hope that my thoughts are clear. Sorry for my English. Thank you.

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  • Why do people still use C these days? [closed]

    - by Joshua
    C++ is clearly a far superior language than C, since it has many features that C lacks (although, C++'s object model isn't as ideal as say C#'s). With the coming off the new C++0x standard, why hasn't C been phased out to obscurity? C++ has been around for so long, since the '80s. The Linux kernel has already been ported to C++ with negligible performance differences. I believe, with no evidence, that larger program structures benefit in performance if written in C++ than in C, if only because of object interaction. Don't get me started on "objects-in-C!" libraries, which are all a terrible hack. (Not that C++'s object model is the most ideal, but it is almost up to snuff with C# using common ad-hoc techniques.)

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  • Why is Scaffolding Not Working in Ruby on Rails?

    - by Timmy
    I created a controller and a model. The controller is called "Admin" and the model is called "Album". I edited database.yml with proper info and did the rake db:migrate command which didn't return any errors and did migrate the db inside schema.rb. Inside the controller I wrote: class AdminController < ApplicationController scaffold :album end Next I started my server and went to http://localhost:3000/admin but instead of seeing the typical CRUD page I get the following error: app/controllers/admin_controller.rb:3 Request Parameters: None Show session dump --- flash: !map:ActionController::Flash::FlashHash {} Response Headers: {"cookie"=>[], "Cache-Control"=>"no-cache"} Any idea why?

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  • how do i load an image from a DB inside a jsf using managed beans?

    - by RhigoHR
    Hi.. i have a database with some images...could anyone tell me or explain me how could i can load an image in a jsf? I alredy have a managed bean that converts an Image object into a streamcontent...and this streamcontent is called from the page in a tag , but when a i check the source code of the page, there's no src where the image could be loaded. Hope an answer, thx

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  • C# Design a class with interface?

    - by Haroon
    I am having a bit of trouble understanding how I will design a class. My class will have 3 methods ICollection<Field> GetFields(); //perform validation internally - return back the object T UpdateFields(ICollection<Field> fields); //pass in model object with values on it, set up fields, then pass back all fields ICollection<Field> GetFieldsWithValues(T object); What is the best way to construct/design such a class keeping in mind: 1. The model object I pass in will be one of 3 or 4 tables, however when I call GetFIelds - internally for each object I know what fields will be there i.e. list.add(new Field{name = "id", value = "5"}); list.add(new Field{name = "nameofcompany", value = "super guys"});

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  • Managing Large Database Entity Models

    - by ChiliYago
    I would like hear how other's are effectively (or not) working with the Visual Studio Entity Designer when many database tables exists. It seems to me that navigating the Designer is tough enough to find what you are looking for with just a few tables but how about a database with say 100 to 200 tables? When a table change is made at the database level how is the model updated? Does it overwrite any manual changes you have made to the model? How would you quickly find an entity in the designer to make a change or inspect a change? Seems unrealistic to be scrolling around looking for specific entity. Thanks for your feedback!

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  • How to create a new line in the table cell

    - by Justin
    I am new to latex, and I am trying to create a table, but the content in the table cell is quite long, so I decided to create a new line for the cells. But I am not sure how to do that, could someone help me on that? Here is my code: \begin{table}[h!] \caption{Multirow table} \begin{center} \begin{tabular}{ |c|c|c| } \hline Observation(Species name) & Likelihood (Limnodynastes peronii Distribution Model) &Likelihood (Rhinella marina Distribution Model)\\ \hline Observation 1 (Limnodynastes peronii) &0.0712 &0.2699\\ \hline Observation 2 (Rhinella marina) &0.30 &0.013 \\ \hline \end{tabular} \end{center} \end{table}

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  • How to Import data from Excel 2010 to SQL table

    - by user2950101
    I am using this , Insert into smst(id,mobile,day,month,year,time,model,imie1,imie2,FullMessage)select * FROM OPENROWSET('Microsoft.Ace.OLEDB.14.0','Excel 14.0;Database=L:\SMS.xlsx;HDR=YES', 'SELECT id,mobile,day,month,year,time,model,imie1,imie2,FullMessage FROM [Sheet2]') Could you please help and find the error? sql error : 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '('Microsoft.Ace.OLEDB.14.0','Excel 14.0;Database=L:\SMS.xlsx;HDR=YES', 'SELECT i' at line 1 i am using excel 2010.

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  • JSON datetime to SQL Server database via WCF

    - by moikey
    I have noticed a problem over the past couple of days where my dates submitted to an sql server database are wrong. I have a webpage, where users can book facilities. This webpage takes a name, a date, a start time and an end time(BookingID is required for transactions but generated by database), which I format as a JSON string as follows: {"BookingEnd":"\/Date(2012-26-03 09:00:00.000)\/","BookingID":1,"BookingName":"client test 1","BookingStart":"\/Date(2012-26-03 10:00:00.000)\/","RoomID":4} This is then passed to a WCF service, which handles the database insert as follows: [WebInvoke(Method = "POST", RequestFormat = WebMessageFormat.Json, UriTemplate = "createbooking")] void CreateBooking(Booking booking); [DataContract] public class Booking { [DataMember] public int BookingID { get; set; } [DataMember] public string BookingName { get; set; } [DataMember] public DateTime BookingStart { get; set; } [DataMember] public DateTime BookingEnd { get; set; } [DataMember] public int RoomID { get; set; } } Booking.svc public void CreateBooking(Booking booking) { BookingEntity bookingEntity = new BookingEntity() { BookingName = booking.BookingName, BookingStart = booking.BookingStart, BookingEnd = booking.BookingEnd, RoomID = booking.RoomID }; BookingsModel model = new BookingsModel(); model.CreateBooking(bookingEntity); } Booking Model: public void CreateBooking(BookingEntity booking) { using (var conn = new SqlConnection("Data Source=cpm;Initial Catalog=BookingDB;Integrated Security=True")) using (var cmd = conn.CreateCommand()) { conn.Open(); cmd.CommandText = @"IF NOT EXISTS ( SELECT * FROM Bookings WHERE BookingStart = @BookingStart AND BookingEnd = @BookingEnd AND RoomID= @RoomID ) INSERT INTO Bookings ( BookingName, BookingStart, BookingEnd, RoomID ) VALUES ( @BookingName, @BookingStart, @BookingEnd, @RoomID )"; cmd.Parameters.AddWithValue("@BookingName", booking.BookingName); cmd.Parameters.AddWithValue("@BookingStart", booking.BookingStart); cmd.Parameters.AddWithValue("@BookingEnd", booking.BookingEnd); cmd.Parameters.AddWithValue("@RoomID", booking.RoomID); cmd.ExecuteNonQuery(); conn.Close(); } } This updates the database but the time ends up "1970-01-01 00:00:02.013" each time I submit the date in the above json format. However, when I do a query in SQL server management studio with the above date format ("YYYY-MM-DD HH:MM:SS.mmm"), it inserts the correct values. Also, if I submit a millisecond datetime to the wcf, the correct date is being inserted. The problem seems to be with the format I am submitting. I am a little lost with this problem. I don't really see why it is doing this. Any help would be greatly appreciated. Thanks.

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  • NameError when using act_as_ferret

    - by manish nautiyal
    Hi all I am getting this error when I am using acts_as_ferret :fields =[:competitor], :remote = true NameError in PartController#index uninitialized constant PartController::Competitor My Model class Competitor < ActiveRecord::Base validates_presence_of :fee_earner_id, :notes belongs_to :fee_earner belongs_to :country belongs_to :state belongs_to :user acts_as_ferret :fields =[:competitor], :remote = true end My controller class PartController < ApplicationController def index @proscribeds = Competitor.paginate(:all, :order = sort , :page = params[:page], :per_page = 70 ) end end Its working fine in localhost but when I deploy it in the server than I get this error. act_as_ferret is working good with other models. I don't know why this is not working with only Competitor model.

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  • devise register confirmation

    - by mattherick
    hello! i have a user and an admin role in my project. i created my authentification with devise, really nice and goot tool for handling the authentification. in my admin role i don´t have any confirmation or something like that. it is really simple and doesn´t make problems. but in my user model i have following things: model: devise :database_authenticatable, :confirmable, :recoverable, :rememberable, :trackable, :validatable, :timeoutable, :registerable # Setup accessible (or protected) attributes for your model attr_accessible :email, :username, :prename, :surname, :phone, :street, :number, :location, :password, :password_confirmation and few validations, but they aren´t relevant this time. my migration looks like following one: class DeviseCreateUsers < ActiveRecord::Migration def self.up create_table(:users) do |t| t.database_authenticatable :null = false t.confirmable t.recoverable t.rememberable t.trackable t.timeoutable t.validateable t.string :username t.string :prename t.string :surname t.string :phone t.string :street t.integer :number t.string :location t.timestamps end add_index :users, :email, :unique => true add_index :users, :confirmation_token, :unique => true add_index :users, :reset_password_token, :unique => true add_index :users, :username, :unique => true add_index :users, :prename, :unique => false add_index :users, :surname, :unique => false add_index :users, :phone, :unique => false add_index :users, :street, :unique => false add_index :users, :number, :unique => false add_index :users, :location, :unique => false end def self.down drop_table :users end end into my route.rb I added following statements: map.devise_for :admins map.devise_for :users, :path_names = { :sign_up = "register", :sign_in = "login" } map.root :controller = "main" and now my problem.. if I register a new user, I fill in all my data in the register form and submit it. After that I get redirected to the controller main with the flash-notice "You have signed up successfully." And I am logged in. But I don´t want to be logged in, because I don´t have confirmed my new user account yet. If I open the console I see the last things in the logs and there I see the confirmation-mail and the text and all stuff, but I am already logged in... I can´t explain why, ... does somebody of you have an idea? If I copy out the confirmation-token from the logs and confirm my account, I can log in, but if I don´t confirm, I also can log in..

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  • Does CakePHP treat all INT fields as ID's for join tables?

    - by Jonnie
    I am trying to save a User, their Profile, and some tags and my join table that links the profile and the tags keeps getting messed up. The profile model is called Instructor, the tag model is called Subject. The Instructor has a phone number and a zip code and for some reason CakePHP thinks these are the fields it should use when creating entries in my join table. My Join table always comes out as: id | instructor_id | subject_id | 1 | 90210 | 1 | // thinks that the zip code is an instructor_id 2 | 1112223333 | 1 | // thinks that the phone number is an instructor_id 3 | 1 | 1 | // thinks that user_id is an instructor_id 4 | 1 | 1 | // the actual instructor_id, this one's correct 5 | 90210 | 2 | 6 | 1112223333 | 2 | 3 | 1 | 2 | 4 | 1 | 2 | My Models: class Instructor extends AppModel { var $name = 'Instructor'; var $belongsTo = array('User', 'State'); var $hasAndBelongsToMany = array( 'Subject' = array( 'className' = 'Subject', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'instructor_id', 'associationForeignKey' = 'subject_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } class Subject extends AppModel { var $name = 'Subject'; var $hasAndBelongsToMany = array( 'Instructor' = array( 'className' = 'Instructor', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'subject_id', 'associationForeignKey' = 'instructor_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } My Model Associations: User hasOne Instructor Instructor belongsTo User Instructor hasAndBelongsToMany Subject Subject hasAndBelongsToMany Instructor My form data looks like: Array ( [User] = Array ( [username] = MrInstructor [password] = cddb06c93c72f34eb9408610529a34645c29c55d [group_id] = 2 ) [Instructor] = Array ( [name] = Jimmy Bob [email] = [email protected] [phone] = 1112223333 [city] = Beverly Hills [zip_code] = 90210 [states] = 5 [website] = www.jimmybobbaseballschool.com [description] = Jimmy Bob is an instructor. [user_id] = 1 [id] = 1 ) [Subject] = Array ( [name] = hitting, pitching ) ) My function for processing the form looks like: function instructor_register() { $this-set('groups', $this-User-Group-find('list')); $this-set('states', $this-User-Instructor-State-find('list')); if (!empty($this-data)) { // Set the group to Instructor $this-data['User']['group_id'] = 2; // Save the user data $user = $this-User-save($this-data, true, array( 'username', 'password', 'group_id' )); // If the user was saved, save the instructor's info if (!empty($user)) { $this-data['Instructor']['user_id'] = $this-User-id; $instructor = $this-User-Instructor-save($this-data, true, array( 'user_id', 'name', 'email', 'phone', 'city', 'zip_code', 'state_id', 'website', 'description' )); // If the instructor was saved, save the rest if(!empty($instructor)) { $instructorId = $this-User-Instructor-id; $this-data['Instructor']['id'] = $instructorId; // Save each subject seperately $subjects = explode(",", $this-data['Subject']['name']); foreach ($subjects as $_subject) { // Get the correct subject format $_subject = strtolower(trim($_subject)); $this-User-Instructor-Subject-create($this-data); $this-User-Instructor-Subject-set(array( 'name' = $_subject )); $this-User-Instructor-Subject-save(); echo ''; print_r($this-data); echo ''; } } } } }

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  • Can I not submit a form to a servlet from JSF?

    - by simpatico
    * Unable to find matching navigation case with from-view-id '/home.xhtml' for action 'MemoServlet' with outcome 'MemoServlet' I try to accomplish it through: <h:commandButton type="submit" value="add" action="MemoServlet"/> but all the tutorials in the world only do it with a bean, which i don't want. I've come across any navigation rule that accomplishes my request.

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  • Django admin page dropdowns

    - by zen
    I am building a high school team application using Django. Here is my working models file: class Directory(models.Model): school = models.CharField(max_length=60) website = models.URLField() district = models.SmallIntegerField() conference = models.ForeignKey(Conference) class Conference(models.Model): conference_name = models.CharField(max_length=50) url = models.URLField() class Meta: ordering = ['conference_name'] When I open my admin pages and go to edit a school's conference the drop down looks like this: <select> <option value="1">Conference Object</option> <option value="2">Conference Object</option> <select> How do I replace "Conference Object" with the conference_name?

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