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  • Lining up Divs, while using JQuery

    - by user630581
    I am trying to create a flash header like element in JQuery, that has three images that fade to other images. I have each group of images in a div, but the divs line up vertically down the page, I want them to line up horizontally in a row. Currently my css code is: div#demos{ width:940px; border:0; } .s1{ float:left; display:inline; background-color:#000000; width:225px; margin:0; } .s2{ float:right; display:inline; background-color:#000000; width:225px; margin:0; } .s3{ float:left; display:inline; background-color:#000000; width:225px; margin:0; } and my markup is: <div id="demos"> <div id="s1" class="pics"> <img src="Image1.jpeg" width="200" height="200" /> <img src="Image2.jpeg" width="200" height="200" /> <img src="Image3.jpeg" width="200" height="200" /> </div> <div id="s2" class="pics"> <img src="Image4.jpeg" width="200" height="200" /> <img src="Image5.jpeg" width="200" height="200" /> <img src="Image6.jpeg" width="200" height="200" /> </div> <div id="s3" class="pics"> <img src="Image7.jpeg" width="200" height="200" /> <img src="Image8.jpeg" width="200" height="200" /> <img src="Image9.jpeg" width="200" height="200" /> </div> <div style="clear:both"></div> </div>

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  • Can't get values from Sqlite DB using query

    - by Sana Joseph
    I used sqlite to populate a DB with some Tables in it. I made a function at another javascript page that executes the database & selects some values from the table. Javascript: function GetSubjectsFromDB() { tx.executeSql('SELECT * FROM Subjects', [], queryNSuccess, errorCB); } function queryNSuccess(tx, results) { alert("Query Success"); console.log("Returned rows = " + results.rows.length); if (!results.rowsAffected) { console.log('No rows affected!'); return false; } console.log("Last inserted row ID = " + results.insertId); } function errorCB(err) { alert("Error processing SQL: "+err.code); } Is there some problem with this line ? tx.executeSql('SELECT * FROM Subjects', [], queryNSuccess, errorCB); The queryNSuccess isn't called, neither is the errorCB so I don't know what's wrong.

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  • How to design websites for all display sizes

    - by katie bekell
    I like to use a lot of unique graphics on my pages, which often results in making different page sizes depending on available screen width/height. Here are two examples: http://www.uvm.edu/~areid/homesite/ - the image floats at the bottom of my screen but on a larger browser, the image floats near the middle making it look off. It looks best when the bottom of the window aligns with the bottom of the image www.stevenlebel.com - it loads two different pages depending on what monitor size is detected. This seems like a lot of redundant coding. My question is, how can I make sliced/Photoshop images transition well to different screen sizes. Does Photoshop allow you to make DIVS instead of tables? Can i make each of the slices created by Photoshop grow/shrink when the browser window size changes? If anyone has any input on creating websites like this I would be very interested to hear what they have to say. Thanks Katie

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  • opening and viewing a file in php

    - by Christian Burgos
    how do i open/view for editing an uploaded file in php? i have tried this but it doesn't open the file. $my_file = 'file.txt'; $handle = fopen($my_file, 'r'); $data = fread($handle,filesize($my_file)); i've also tried this but it wont work. $my_file = 'file.txt'; $handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); $data = 'This is the data'; fwrite($handle, $data); what i have in mind is like when you want to view an uploaded resume,documents or any other ms office files like .docx,.xls,.pptx and be able to edit them, save and close the said file. edit: latest tried code... <?php // Connects to your Database include "configdb.php"; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM employees") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data //Echo "<img src=localhost/uploadfile/images".$info['photo'] ."> <br>"; Echo "<b>Name:</b> ".$info['name'] . "<br> "; Echo "<b>Email:</b> ".$info['email'] . " <br>"; Echo "<b>Phone:</b> ".$info['phone'] . " <hr>"; //$file=fopen("uploadfile/images/".$info['photo'],"r+"); $file=fopen("Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt","r") or exit("unable to open file");; } ?> i am getting the error: Warning: fopen(Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt): failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/uploadfile/view.php on line 17 unable to open file the file is in that folder, i don't know it wont find it.

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  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

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  • Drag and drop an image from desktop to a web text editor (implementation in javascript)

    - by fatmatto
    I tried to write reasonably short title but i failed i guess.. Hi everybody here's what i'm trying to do: I want to implement a web text editor able to recognize when the user drag a image file over it's editing surface and it automa(gically) starts the upload and insert the image near the cursor position. In other words i don't want the user to do the usual "insert-image-browse-ok". Atm i am not very good at javascript ... i know JQuery but i have not a clear idea about how to implement this... i don't know if there's an event handler able to help me in this situation... if not then there should be i think or web apps would miss some kind of interactivity. I've heard miracles about HTML5 could it help me? I've seen such things in Google Wave but that surface doesn't seem to be a form field... google lab's black magic i guess.... Thank you in advance.

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  • What does this code means? Odd & Even

    - by Rodolfo Contreras
    <?php $Odd = "even"; $query = $MySQLi->query("SELECT id, look, username, motto FROM users WHERE rank = '7'"); if($query->num_rows > 0): while($UserRow = $query->fetch_assoc()) { $Odd = ($Odd == "even") ? "odd" : "even"; ?> I'm using a CMS for some web. But i can't stand this code exactly. Well i do know what does it do. But im not sure how to work with it. Mostly this line: $Odd = ($Odd == "even") ? "odd" : "even"; Can you guys help me?

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  • CSS Forms/Input Maniuplation

    - by user983969
    input:required{ background-color:#f00; } input:required label{ color: #FF3434; } I have the above CSS code currently for my form, I want to be able to make the label red when the field is required. My input field is: <label for="frmComTelephone">Telephone</label> <input type="number" name="Telephone" id="frmComTelephone"/> But that CSS isn't working how do I solve this? 2ND problem is I have the following CSS: input:focus { background-color:yellow; } input[type="text"], input[type="date"],input[type="time"],input[type="number"],textarea,select { border-radius:5px; border-width: 1px; border-style: solid; border-color: #C6C6C6; height:41px; background-color: #FF3434; width: 100%; } But when the item is focused it doesn't change to yellow, if i remove "background-color: #FF3434;" it turns yellow on focus? Is what I am doing not able to be done? Or am I going about this wrong? Thanks

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  • WordPress + Facebook comments addition (php knowledge needed)

    - by user1356223
    I succeded to fetch Facebok comments number via this function: <?php function fb_comment_count() { global $post; $url = get_permalink($post->ID); $filecontent = file_get_contents('https://graph.facebook.com/?ids=' . $url); $json = json_decode($filecontent); $count = $json->$url->comments; if ($count == 0 || !isset($count)) { $count = 0; } echo $count; } ;?> And I call it with: <?php fb_comment_count();?> Now how do I add it to this code: <?php comments_number(__('No Comments'), __('1 Comment'), __('% Comments'), '', __('Comments Closed') ); ?> so that WordPress shows number of WP and FB comments together in one number. Thank you very much to everyone!

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  • document.getElementByID - checking whether an element has been found or not

    - by be here now
    Hi, guys. Here's a sample code, that opens an internet explorer window, navigates to google, and gets some element on the page by its unique id: set ie = CreateObject("InternetExplorer.Application") ie.navigate("www.google.com") ie.visible = true while ie.readystate <> 4 wscript.sleep 100 WEnd set some_object = ie.document.getelementbyid("xjsc") MsgBox some_object.tagname, 0 This sample brings me a DIV popup, which satisfies me completely. But at the next step I'd like to check whether some id exists in the page, or not. Unfortunately, I can't just be, like, set some_object = ie.document.getelementbyid("some_non_existant_id") if some_object.tagname = "" then ... because it gives me the following error: ie.vbs(12, 1) Microsoft VBScript runtime error: Object required: 'some_object' So, what's the best practice to check whether an element has been found or not?

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  • How to make an object go to a higher layer

    - by MrEnder
    I want this to be on top... how can I do this and not have it go underneath... http://opentech.durhamcollege.ca/~intn2201/brittains/chatter/signup_step2.php I think there is a way in CSS to make stuff go on higher layers I think I read something about it a few years ago but I forget what its called.

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  • Get the position of a div/span tag

    - by schmoopy
    Can someone show me how to get the .top & .left position of a div or span tag when one is not specified? ie: <span id='11a' style='top:55px;' onmouseover="GetPos(this);">stuff</span> <span id='12a' onmouseover="GetPos(this);">stuff</span> In the above, if i do: document.getElementById('11a').style.top The the value of 55px is returned. However if i try that for span '12a', then nothing gets returned. I have a bunch of div/spans on a page that i cannot specify the top/left properties for, but i need to display a div directly under that element. Thanks for lookin :-)

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  • How to launch a browser in view source mode?

    - by JorgeLarre
    I want to open a file in a web browser (anyone will do) and I want to see it in the view source mode instead of in the standard browser window. This can be done in two steps, by opening the file and then go to the view source window (different shortcuts in each browser), but I want to directly go to the view source window. I have not found any such command line argument for Firefox nor Chrome. Is this possible just with the base browser functionality?

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  • Slow form submission.

    - by Tony
    When I submit a form, I can see my browser's progress bar slowly increased, it takes 4-6s to submit a form. It was a generic form like : <form id="someid" name="someName" action="someAction.do"> ... </form> I test it in IE8 and Firefox 3,both are very slow. My network condition is fine, my server works great. What could be the problem?

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  • how to set default focus?

    - by Elaine
    Now one Submit button is the default focused control. but I need to set the default focus to another imagebutton. Can only use $(document).ready(function(){ctrl.focus();} ? or has another property to fulfill it?

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  • File paths with XSLT includes

    - by Andrew Parisi
    Hi again everyone. I'm working on a website with a large number of pages, and each one has this in it: <xsl:include href="team-menu.xsl" /> This xsl file is stored in the root directory. Essentially including my "team menu" on each page. My problem is when I include this on nested pages, e.g. "/teammembers/smith.xsl", the links in the menu are broken because they refer to pages that aren't in the same directory as the page i'm viewing. This is probably really easy, but I just don't know how to fix it. Is there a way to tell the XSL the root directory and/or set some sort of global directory? Thanks for your help!

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  • Variable disappears when I log in

    - by John
    Hello, I have profile page where the profile is retrieved via GET. The index file has this: $profile = $_GET['profile']; When I log in on the profile page, the $profile variable disappears. Here is the form action on the login function: <form name="login-form" id="login-form" method="post" action="./index.php"> (The $profile variable is separate of the login username.) How could I make the page retain the $profile variable? Thanks in advance, John

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  • Using textbox text in javascript

    - by Jambo
    I am working with Twitter widgets with the following script- <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> <input type="button" value="Run Function" onclick="test();" /> <script> function test() { new TWTR.Widget({ version: 3, type: 'profile', rpp: 8, interval: 30000, width: 315, height: 340, theme: { shell: { background: '#333333', color: '#ffffff' }, tweets: { background: '#000000', color: '#ffffff', links: '#4aed05' } }, features: { scrollbar: false, loop: false, live: false, behavior: 'all' } }).render().setUser(document.getElementById('TextBox1').value).start(); } When using the function test(); in the button click it is ocming up with the error - Error: Unable to get value of the property 'value': object is null or undefined So it seems like it is not getting to the value at - (document.getElementById('TextBox1').value) I am not sure why it is null if the text box has a value and then the script is run on the button click?

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  • Keep div:hover open when changing nested select box

    - by JMC Creative
    This is an IE-only problem. .toolTip becomes visible when it's parent element is :hovered over. Inside of .toolTip is a select box. When the user opens the select box to make a selection, the parent element is being "un-hovered", if you will. To put it another way, when I try to select something from the dropdown, the whole thing hides itself again. I'm sure it has something to do with the way IE interprets the stylesheet, but I don't know what or where. Here is some relevant code (edited for clarity): #toolBar .toolTip { position: absolute; display:none; background: #fff; line-height: 1em; font-size: .8em; min-width: 300px; bottom: 47px; left: -5px; padding: 0 ; } #toolBar div:hover .toolTip { display:block; } and <div id="toolBar"> <div class="socialIcon"> <a href=""><img src="/im/social/nytimes.png" alt="NY Times Bestsellers" /></a> <span class="toolTip"> <h1>NY Times Bestsellers Lists</h1> <div id="nyTimesBestsellers"> <?php include('/ny-times-bestseller-feed.php') ?> </div> <p><img src="/im/social/nytimes.png" alt="NY Times Bestseller Lists" /> Change List <select id="nyTimesChangeCurrentList" name="nyTimesChangeCurrentList"> <option value="hardcover-fiction">Hardcover Fiction</option> <option value="hardcover-nonfiction">Hardcover Nonfiction</option> <option value="hardcover-advice">Hardcover Advice</option> </select> </p> </span> </div> </div>

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  • Having issues with div layouts

    - by Chowderhound
    new here and I'm crossing fingers for help. I'm working on http://www.catgriz.com On the frontpage I have a slideshow that stacks all of the information on top of itself when you initially visit the page. But after a simple browser refresh, it displays correctly. I was hoping someone could look at it and point me in the right direction of what I've done wrong. I'm using Joomla with a Yootheme. Thank you so much in advance!

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