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• On android how would I go about creating a prompt for an app that requires a user to enter a username before fully launching the app?

  - by racl101

  I'll preface this with I'm really new to working on Android. So I have to work on an existing app and create a screen that prompts the user for a username if one isn't entered then it won't launch the currently existing main activity (i.e. it won't fully launch the app. Instead it will just sit on that screen until a username is entered.) I suppose that it's tantamount to a web app login page in that it will not let a user past that page if the user is not authenticated and authorized. However, there's no authentication nor authorization in this app. Instead, on first run a user must simply register with a username and that username gets saved to the database and for any subsequent runs the app's main activity will just start because a user has registered to that phone. In fact, the app will not prompt the user for their name again unless the app gets deleted with all its data and reinstalled again. This implicitly means that I have to save the user's name in the database or some other kind of storage. So I was wondering what would be the best way of doing this in an app with an existing main activity? Should I try to accomplish this on that existing main activity or create a new activity to display this prompt screen and, in effect, block the main activity from running until the user enters their name? Any tutorials or links would be helpful and thank you in advance for any help.

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• Replacing backslashes in Python strings

  - by user323659

  I have some code to encrypt some strings in Python. Encrypted text is used as a parameter in some urls, but after encrypting, there comes backslashes in string and I cannot use single backslash in urllib2.urlopen. I cannot replace single backslash with double. For example: print cipherText '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' print cipherText.replace('\\','\\\\') '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' Also putting r in front of \ in replace statement did not worked. All I want to do is calling that kind of url: http://awebsite.me/main?param="\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb" And also this url can be successfully called: http://awebsite.me/main?param="\\t3-@\\xab7+\\xc7\\x93H\\xdc\\xd1\\x13G\\xe1\\xfb" Any idea will be appreciated.

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• How can I mix command line arguments and filenames for <> in Perl?

  - by Jimmeh

  Consider the following silly Perl program: $firstarg = $ARGV[0]; print $firstarg; $input = <>; print $input; I run it from a terminal like: perl myprog.pl sample_argument And get this error: Can't open sample_argument: No such file or directory at myprog.pl line 5. Any ideas why this is? When it gets to the < is it trying to read from the (non-existent) file, "sample_argument" or something? And why?

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• How to calculate median of a Map<Int,Int>?

  - by Chris

  For a map where the key represents a number of a sequence and the value the count how often this number appeared in the squence, how would an implementation of an algorithm in java look like to calculate the median? For example: 1,1,2,2,2,2,3,3,3,4,5,6,6,6,7,7 in a map: Map<Int,Int> map = ... map.put(1,2) map.put(2,4) map.put(3,3) map.put(4,1) map.put(5,1) map.put(6,3) map.put(7,2) double median = calculateMedian(map); print(median); would result in: > print(median); 3 > So what i am looking for is a java implementation of calculateMedian.

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• Using methods on 2 input files - 2nd is printing multiple times - Java

  - by Aaa

  I have the following code to read in text, store in a hashmap as bigrams (with other methods to sort them by frequency and do v. v. basic additive smoothing. I had it working great for one language input file (english) and then I want to expand it for the second language input file (japanese - doens;t matter what it is I suppose) using the same methods but the Japanese bigram hashmap is printing out 3 times in a row with diff. values. I've tried using diff text in the input file, making sure there are no gaps in text etc. I've also put print statements at certain places in the Japanese part of the code to see if I can get any clues but all the print statements are printing each time so I can't work out if it is looping at a certain place. I have gone through it with a fine toothcomb but am obviously missing something and slowly going crazy here - any help would be appreciated. thanks in advance... package languagerecognition2; import java.lang.String; import java.io.InputStreamReader; import java.util.*; import java.util.Iterator; import java.util.List.*; import java.util.ArrayList; import java.util.AbstractMap.*; import java.lang.Object; import java.io.*; import java.util.Enumeration; import java.util.Arrays; import java.lang.Math; public class Main { /** public static void main(String[] args) { //training English ----------------------------------------------------------------- File file = new File("english1.txt"); StringBuffer contents = new StringBuffer(); BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(file)); String test = null; //test = reader.readLine(); // repeat until all lines are read while ((test = reader.readLine()) != null) { test = test.toLowerCase(); char[] charArrayEng = test.toCharArray(); HashMap<String, Integer> hashMapEng = new HashMap<String, Integer>(bigrams(charArrayEng)); LinkedHashMap<String, Integer> sortedListEng = new LinkedHashMap<String, Integer>(sort(hashMapEng)); int sizeEng=sortedListEng.size(); System.out.println("Total count of English bigrams is " + sizeEng); LinkedHashMap<String, Integer> smoothedListEng = new LinkedHashMap<String, Integer>(smooth(sortedListEng, sizeEng)); //print linkedHashMap to check values Set set= smoothedListEng.entrySet(); Iterator iter = set.iterator ( ) ; System.out.println("Beginning English"); while ( iter.hasNext()) { Map.Entry entry = ( Map.Entry ) iter.next ( ) ; Object key = entry.getKey ( ) ; Object value = entry.getValue ( ) ; System.out.println( key+" : " + value); } System.out.println("End English"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader != null) { reader.close(); } } catch (IOException e) { e.printStackTrace(); } } //End training English----------------------------------------------------------- //Training japanese-------------------------------------------------------------- File file2 = new File("japanese1.txt"); StringBuffer contents2 = new StringBuffer(); BufferedReader reader2 = null; try { reader2 = new BufferedReader(new FileReader(file2)); String test2 = null; //repeat until all lines are read while ((test2 = reader2.readLine()) != null) { test2 = test2.toLowerCase(); char[] charArrayJap = test2.toCharArray(); HashMap<String, Integer> hashMapJap = new HashMap<String, Integer>(bigrams(charArrayJap)); //System.out.println( "bigrams stage"); LinkedHashMap<String, Integer> sortedListJap = new LinkedHashMap<String, Integer>(sort(hashMapJap)); //System.out.println( "sort stage"); int sizeJap=sortedListJap.size(); //System.out.println("Total count of Japanese bigrams is " + sizeJap); LinkedHashMap<String, Integer> smoothedListJap = new LinkedHashMap<String, Integer>(smooth(sortedListJap, sizeJap)); System.out.println( "smooth stage"); //print linkedHashMap to check values Set set2= smoothedListJap.entrySet(); Iterator iter2 = set2.iterator(); System.out.println("Beginning Japanese"); while ( iter2.hasNext()) { Map.Entry entry2 = ( Map.Entry ) iter2.next ( ) ; Object key = entry2.getKey ( ) ; Object value = entry2.getValue ( ) ; System.out.println( key+" : " + value); }//end while System.out.println("End Japanese"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader2 != null) { reader2.close(); } } catch (IOException e) { e.printStackTrace(); } } //end training Japanese--------------------------------------------------------- } //end main (inner)

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• linux cpu usage

  - by davidbobo

  I am working on unix. I want to knwo the current cpu usage of a process. I understood that ps give the average of cpu used till the process is up - it is not the current usage. Is there a way to print only the cpu from the top command without 10 more parameters and headers? I know how to do it with awk - this is not the way i want to do it. top -p 20705 -bc -n 1 | tail -n 2 | awk '{ print $9}' | head -n 1 If there is another simple way to do it, not reading /proc/stat... If there is a simple way doing it from c++, it is also ok.

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• How to call a Zend lucene search function?

  - by stef

  I inherited a Zend project devoid of comments and I didn't get to talk to the previous developer. Since I have no Zend experience I'm having some issues :) I'd like to print out some variables inside an function that indexes items from the site using Zend_Search_Lucene because I think something is going wrong here. From what I've read, ::create creates a new index and ::open updates it. So it's in this ::open function I'd like to print out some variables. The name and params of the function are below. Does anyone have any idea how this function can be called so I can run some tests? private function search($category,$string,$page = 1,$itemsByPage = 5) EDIT: OR, is there a way I can nuke the existing index and force it to be rebuilt completely, for example by deleting the index files on the FS and then performing some searches?

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• Does template class/function specialization improves compilation/linker speed?

  - by Stormenet

  Suppose the following template class is heavily used in a project with mostly int as typename and linker speed is noticeably slower since the introduction of this class. template <typename T> class MyClass { void Print() { std::cout << m_tValue << std::endl;; } T m_tValue; } Will defining a class specialization benefit compilation speed? eg. void MyClass<int>::Print() { std::cout << m_tValue << std::endl; }

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• python win32api registery key change

  - by user340495

  Hi, I am trying to trigger an event every time a registry value is being modified. import win32api import win32event import win32con import _winreg key = _winreg.OpenKey(_winreg.HKEY_CURRENT_USER,'Control Panel\Desktop',0,_winreg.KEY_READ) sub_key = _winreg.CreateKey(key,'Wallpaper') evt = win32event.CreateEvent(None,0,0,None) win32api.RegNotifyChangeKeyValue(sub_key,1,win32api.REG_NOTIFY_CHANGE_ATTRIBUTES,evt,True) ret_code=win32event.WaitForSingleObject(evt,3000) if ret_code == win32con.WAIT_OBJECT_0: print "CHANGED" if ret_code == win32con.WAIT_TIMEOUT: print "TIMED" my problem is that this is never triggered , the event always time-out. (the reg key I am trying to follow is the wallpaper) [ please note I trigger the event by 1) manually changing the registry value in regedit 2) an automated script which run this : from ctypes import windll from win32con import * windll.user32.SystemParametersInfoA(SPI_SETDESKWALLPAPER, 0,"C:\wall.jpg",SPIF_UPDATEINIFILE | SPIF_SENDWININICHANGE) ] Thanks for any help in advance :) EDIT:: sorry about formatting

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• Windows Service Printing Behaviour

  - by Andre

  Alright, I was tasked to develop a Windows Service that listens to a directory for files that are dropped in it, read them, delete them and print out a report. I installed the service on my work laptop (Win 7 x86) and a test machine (XP x86) under a User account at first. It would do everything as it should except the print the report. No errors, nothing. Then I made it run under Local System and it produced a "No printers found" exception. Converting the app to a Console Application and running on these machines gave the desired result. OK, so now I was assuming that there are security "stuff" involved. Then I installed the service on a Server 2008 x64 machine (under Local System) and it just worked. Can anybody explain to me why this is happening? Why does the service allow printing from Server OS but not from a Desktop OS or am I missing something very obvious?

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• Searching for duplicate records within a text file where the duplicate is determined by only two fie

  - by plg

  First, Python Newbie; be patient/kind. Next, once a month I receive a large text file (think 7 Million records) to test for duplicate values. This is catalog information. I get 7 fields, but the two I'm interested in are a supplier code and a full orderable part number. To determine if the record is dupliacted, I compress all special characters from the part number (except . and #) and create a compressed part number. The test for duplicates becomes the supplier code and compressed part number combination. This part is fairly straight forward. Currently, I am just copying the original file with 2 new columns (compressed part and duplicate indicator). If the part is a duplicate, I put a "YES" in the last field. Now that this is done, I want to be able to go back (or better yet, at the same time) to get the previous record where there was a supplier code/compressed part number match. So far, my code looks like this: Compress Full Part to a Compressed Part and Check for Duplicates on Supplier Code and Compressed Part combination import sys import re import time ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ start=time.time() try: file1 = open("C:\Accounting\May Accounting\May.txt", "r") except IOError: print sys.stderr, "Cannot Open Read File" sys.exit(1) try: file2 = open(file1.name[0:len(file1.name)-4] + "_" + "COMPRESSPN.txt", "a") except IOError: print sys.stderr, "Cannot Open Write File" sys.exit(1) hdrList="CIGSUPPLIER|FULL_PART|PART_STATUS|ALIAS_FLAG|ACQUISITION_FLAG|COMPRESSED_PART|DUPLICATE_INDICATOR" file2.write(hdrList+chr(10)) lines_seen=set() affirm="YES" records = file1.readlines() for record in records: fields = record.split(chr(124)) if fields[0]=="CIGSupplier": continue #If incoming file has a header line, skip it file2.write(fields[0]+"|"), #Supplier Code file2.write(fields[1]+"|"), #Full_Part file2.write(fields[2]+"|"), #Part Status file2.write(fields[3]+"|"), #Alias Flag file2.write(re.sub("[$\r\n]", "", fields[4])+"|"), #Acquisition Flag file2.write(re.sub("[^0-9a-zA-Z.#]", "", fields[1])+"|"), #Compressed_Part dupechk=fields[0]+"|"+re.sub("[^0-9a-zA-Z.#]", "", fields[1]) if dupechk not in lines_seen: file2.write(chr(10)) lines_seen.add(dupechk) else: file2.write(affirm+chr(10)) print "it took", time.time() - start, "seconds." ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ file2.close() file1.close() It runs in less than 6 minutes, so I am happy with this part, even if it is not elegant. Right now, when I get my results, I import the results into Access and do a self join to locate the duplicates. Loading/querying/exporting results in Access a file this size takes around an hour, so I would like to be able to export the matched duplicates to another text file or an Excel file. Confusing enough? Thanks.

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• Wait until a webpage finished loading to load the next one in a list

  - by envy

  Hi! I'm using PyQT webView to visit some webpages I have stored on a dictionary the code is something like this: def loadLink(self, url): manager = QNetworkAccessManager() request = QNetworkRequest(QUrl(url)) self.ui.webView.load(QUrl(visitar)) def readUnreadLinks(self): print "Links to read: " + str(len(self.unreadLinks)) for link in self.unreadLinks: print "link-> " + str(link) self.loadLink(link) the problem is it doesn't wait until finished loading the web page and starts loading the next one. I want to load a webpage, wait until it finished loading and then load the next one. Thanks, this is driving me crazy :)

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• How to re-enable the idle timer in ios once it has been disabled (to allow the display to sleep again)?

  - by lindon fox

  I have figured out how to stop an iOS device from going to sleep (see below), but I am having troubles undoing that setting. According to the Apple Documentation, it should just be changing the value of the idleTimerDisabled property. But when I test this, it does not work. This is how I am initially stopping the device from going to sleep: //need to switch off and on for it to work initially [UIApplication sharedApplication].idleTimerDisabled = NO; [UIApplication sharedApplication].idleTimerDisabled = YES; I would have thought that the following would do the trick: [UIApplication sharedApplication].idleTimerDisabled = NO; From the Apple Documentation: The default value of this property is NO. When most applications have no touches as user input for a short period, the system puts the device into a "sleep” state where the screen dims. This is done for the purposes of conserving power. However, applications that don't have user input except for the accelerometer—games, for instance—can, by setting this property to YES, disable the “idle timer” to avert system sleep. Important: You should set this property only if necessary and should be sure to reset it to NO when the need no longer exists. Most applications should let the system turn off the screen when the idle timer elapses. This includes audio applications. With appropriate use of Audio Session Services, playback and recording proceed uninterrupted when the screen turns off. The only applications that should disable the idle timer are mapping applications, games, or similar programs with sporadic user interaction. Has anyone come across this problem? I am testing on iOS6 and iOS5. Thanks in advance.

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• how could it works if function is called before it is defined in python?

  - by user2131316

  I was wondering what does if __name__ == "__main__": really do in python, I have the following code in python3: def main(): test(); def test(): print("hello world " + __name__); if __name__ == "__main__": main(); we know that we have to declare a function before we use it, so function call inside of if part works fine, the main() is defined before it is called inside of if statement, but what about the test() function, it is defined after it is called and there is no errors: def main(): test(); def test(): print("hello world " + __name__); so how could it works if the test() function is defined after it is called?

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• jQueryUI dialog width

  - by user35295

  Fiddle Full Screen Example I use jQuery dialog to open tables. Some of them have a large amount of text and they tend to be too long and go way off the screen. How can I make the dialog wider if the table is too long like the first one in the fiddle? I've tried width:'auto' but it seems to just occupy the entire screen. HTML: <button class='label'>Click</button><div class='dialog'><p><table>.....</table></div> <button class='label'>Click</button><div class='dialog'><p><table>.....</table></div> Javascript: $(document).ready(function(){ $('.label').each(function() { var dialogopen = $(this).next(".dialog"); dialogopen.dialog({width:'auto',autoOpen: false,modal: true, open: function(){ jQuery('.ui-widget-overlay').bind('click',function(){ dialogopen.dialog('close'); }) } }); $(this).click(function(){ dialogopen.dialog('open'); return false; } ); }); });

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• How to test a regex password in Python?

  - by jCuga

  Using a regex in Python, how can I verify that a user's password is: At least 8 characters Must be restricted to, though does not specifically require any of: uppercase letters: A-Z lowercase letters: a-z numbers: 0-9 any of the special characters: @#$%^&+= Note, all the letter/number/special chars are optional. I only want to verify that the password is at least 8 chars in length and is restricted to a letter/number/special char. It's up to the user to pick a stronger / weaker password if they so choose. So far what I have is: import re pattern = "^.*(?=.{8,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=]).*$" password = raw_input("Enter string to test: ") result = re.findall(pattern, password) if (result): print "Valid password" else: print "Password not valid"

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• Django model class and custom property

  - by dArignac

  Howdy - today a weird problem occured to me: I have a modle class in Django and added a custom property to it that shall not be saved into the database and therefore is not represent in the models structure: class Category(models.Model): groups = models.ManyToManyField(Group) title = defaultdict() Now, when I'm within the shell or writing a test and I do the following: c1 = Category.objects.create() c1.title['de'] = 'german title' print c1.title['de'] # prints "german title" c2 = Category.objects.create() print c2.title['de'] # prints "german title" <-- WTF? It seems that 'title' is kind of global. If I change title to a simple string it works as expected, so it has to do something with the dict? I also tried setting title as a property: title = property(_title) But that did not work, too. So, how can I solve this? Thank you in advance! enter code here

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• Comparing Each Character in Java String

  - by user2760357

  I am a beginner at java, and I am trying to create two strings and compare each character. If there is a matching character or characters, the code has to print out the length of each string, without the matching characters. For example, if one string is "super," and the other is "perfect," the program should interpret the strings as superfect, and print out 9 However, if there is no matching part, like pencil and eraser, the code should printout 12, which is the length of two strings combined. Right now, I am having a problem with comparing each character, since I tried to use if(input_word.compareToIgnoreCase(input_word2) != 0) but it only compared the string as a whole.. any suggestion? Thank you for your efforts

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• How to find the width of the div or check wheather horizontal scroll apeear or not?

  - by Salil

  I want to print the page (div) if there is no horizontal scroll appear for that div. I have a div (1000px) with dynamic data which having property overflow:auto;. So, i want to print the div only if div's width is not getting crossed. to achieve this i used following method of a javascript var curr_width = parseInt(mydiv.style.width); But it gives 1000px; only althogh i can see horizontal scrollbar for the div. What should i do to achive this. Can i check wheather horizontal scrollbar is appear for the div or not. Any help is appreciated. NOTE:- i don't want to use any javascript library.

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• File::Find and $_ in nested subroutines.

  - by zedoo

  When running the following code, the filenames of all files below C:\Test are printed. Why doesn't it print just Hello (n times, depending on how many files are processed)? Does this imply that I cannot rely on shift to reliably assign to $_? Imagine a coworker implements the wtf function and doesn't know that it's called from a File::Find wanted sub. I run this code with Strawberry Perl 5.12 use strict; use warnings; use File::Find; find(\&wanted, "C:\\test"); sub wanted{ wtf("Hello"); } sub wtf { shift; print; #expecting Hello }

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• How can I interpolate the result of a function in a Perl here doc?

  - by Zerobu

  I was wondering if it was possible to call a function inside a perl here doc sub Function { } print<<HERE; Function() HERE

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• different behavior when using re.finditer and re.match.

  - by Shahzad

  Hi, I'm working on a regex to to collect some values from a page through some script. I'm using re.match in condition but it returns false but if i use finditer it returns true and body of condition is executed. i tested that regex in my own built tester and it's working there but not in script. here is sample script. result = [] RE_Add0 = re.compile("\d{5}(?:(?:-| |)\d{4})?", re.IGNORECASE) each = ''Expiration Date:\n05/31/1996\nBusiness Address: 23901 CALABASAS ROAD #2000 CALABASAS, CA 91302\n' if RE_Add0.match(each): result0 = RE_Add0.match(each).group(0) print result0 if len(result0) < 100: result.append(result0) else: print 'Address ignore' else: None

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• How to Replace only Part of the Variable using #define

  - by mahesh

  #define C_TX_ TX_ #define C_RX_ RX_ enum Test { C_TX_MAC 0x0100, // Pre-Processor should replace C_TX_ to TX_ C_RX_MAC 0x0101 // But Not Working. }; int main(int argc, char *argv[]) { cout << TX_MAC; // HOW TO PRINT ? cout << RX_MAC; // HOW TO PRINT ? return true; } Please Help. Thanks in Advance

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• String loops in Python

  - by Steve Hunter

  I have two pools of strings and I would like to do a loop over both. For example, if I want to put two labeled apples in one plate I'll write: basket1 = ['apple#1', 'apple#2', 'apple#3', 'apple#4'] for fruit1 in basket1: basket2 = ['apple#1', 'apple#2', 'apple#3', 'apple#4'] for fruit2 in basket2: if fruit1 == fruit2: print 'Oops!' else: print "New Plate = %s and %s" % (fruit1, fruit2) However, I don't want order to matter -- for example I am considering apple#1-apple#2 equivalent to apple#2-apple#1. What's the easiest way to code this? I'm thinking about making a counter in the second loop to track the second basket and not starting from the point-zero in the second loop every time.

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• im writing this code so the user would enter his/her name and followed by his/her marks to get the a

  - by WM

  What if the user wanted to enter his/her grades in the following way: Will 23, 34, 45, 45 how would i get rid of the commas public class StudentAverage { public static void main(String[] args) { int markSum = 0; double average = 0; Scanner input1 = new Scanner(System.in); System.out.print("Enter student record : "); String name = input1.next(); Scanner input2 = new Scanner(input1.nextLine()); int countTotal = 0; while (input2.hasNextInt()) { countTotal++; markSum += input2.nextInt(); } average = markSum / countTotal; // to calculate the total average System.out.print( name + " " + average ); } }

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