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  • iphone: Adding UIRequiredDeviceCapabilitie

    - by pion
    I am reading the "Device Support - Setting Required Hardware Capabilities" on http://developer.apple.com/iphone/library/documentation/iPhone/Conceptual/iPhoneOSProgrammingGuide/AdvancedFeatures/AdvancedFeatures.html I want to add still-camera capability by doing the following: Open my Info.plist Click + Add UIRequiredDeviceCapabilities on the Key column Add still-camera on the Value column Save the updated Info.plist Is this the correct way? Thanks in advance for your help.

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  • Cocoa App with Python extension which use Scipy -> ImportError: No module named scipy

    - by Snej
    Hi: I have installed Scipy (via macports) for Python on my Mac and it runs fine when running Python scripts. But now I'm using Scipy (via PyObjc) for calculations embedded in a Cocoa App frontend. The following error occurs: ImportError: No module named scipy I am using the "Python.framework" in XCode. Does anybody know why Scipy module is not found? I even added it manually to the module search path via sys.path.append("/opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/") EDIT: I found the problem myself. The path should be without "/scipy" at the end. But now I got an architecture problem: ImportError: dlopen(/opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/fftpack/_fftpack.so, 2): no suitable image found. Did find: /opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/fftpack/_fftpack.so: mach-o, but wrong architecture EDIT 2: I checked the architectures: Yes, sure it is an architecture problem. But when I run: file /opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/fftpack/_fftpack.so I get a result Mach-O 64-bit bundle x86_64. And the Mac OS 10.6 PYTHON is: Mach-O universal binary with 3 architectures /usr/bin/python (for architecture x86_64): Mach-O 64-bit executable x86_64 /usr/bin/python (for architecture i386): Mach-O executable i386 /usr/bin/python (for architecture ppc7400): Mach-O executable ppc I build the XCode project as x86_64.

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  • web development using google sites

    - by CHID
    Hi, I have hosted a website. But now my client asks to change it to http://sites.google.com. They hav registered their domain in google. I logged in the site and saw the procedures to create a website from scratch. But is there any way to directly replace the site into google sites. Like, in my site i hav included css files in a folder called stylesheets/css and access it through the link tag. And there are several folders lik that, viz images, scripts etc. 1.Now if i have to transfer it to google sites, where do i create the folders and stuff. I have the priviliges to login to the admin part of the site. 2.And also is there anyway to create database and access it in google sites? 3.Also i see that only html pages can be created. Is there a way to add php pages or other scripting languages? 4.Going forward will google sites be usefull for professional web designing. pls give ideas on whether or not google sites is a good idea to go with

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  • How do I recover from pushing a gitosis.conf file with parsing errors due to line breaks?

    - by Kasia
    I have successfully set up gitosis for an Android mirror (containing multiple git repositories). While adding a new .git path following writable= in gitosis.conf I managed to insert a few line breaks. Saved, committed and pushed to server when I received the following parsing error: Traceback (most recent call last): File "/usr/bin/gitosis-run-hook", line 8, in load_entry_point('gitosis==0.2', 'console_scripts', 'gitosis-run-hook')() File "/usr/lib/python2.5/site-packages/gitosis-0.2-py2.5.egg/gitosis/app.py", line 24, in run return app.main() File "/usr/lib/python2.5/site-packages/gitosis-0.2-py2.5.egg/gitosis/app.py", line 38, in main self.handle_args(parser, cfg, options, args) File "/usr/lib/python2.5/site-packages/gitosis-0.2-py2.5.egg/gitosis/run_hook.py", line 75, in handle_args post_update(cfg, git_dir) File "/usr/lib/python2.5/site-packages/gitosis-0.2-py2.5.egg/gitosis/run_hook.py", line 33, in post_update cfg.read(os.path.join(export, '..', 'gitosis.conf')) File "/usr/lib/python2.5/ConfigParser.py", line 267, in read self._read(fp, filename) File "/usr/lib/python2.5/ConfigParser.py", line 490, in _read raise e ConfigParser.ParsingError: File contains parsing errors: ./gitosis-export/../gitosis.conf (...) I have removed the line break and amendend the commit by git commit -m "fix linebreak" --amend However git push still yields the exact same error. It leads me to believe gitosis is preventing me from doing any further pushes. How do I recover from this?

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  • HTTPSConnection module missing in Python 2.6 on CentOS 5.2

    - by d2kagw
    Hi guys, I'm playing around with a Python application on CentOS 5.2. It uses the Boto module to communicate with Amazon Web Services, which requires communication through a HTTPS connection. When I try running my application I get an error regarding HTTPSConnection being missing: "AttributeError: 'module' object has no attribute 'HTTPSConnection'" Google doesn't really return anything relevant, I've tried most of the solutions but none of them solve the problem. Has anyone come across anything like it? Here's the traceback: Traceback (most recent call last): File "./chatter.py", line 114, in <module> sys.exit(main()) File "./chatter.py", line 92, in main chatter.status( ) File "/mnt/application/chatter/__init__.py", line 161, in status cQueue.connect() File "/mnt/application/chatter/tools.py", line 42, in connect self.connection = SQSConnection(cConfig.get("AWS", "KeyId"), cConfig.get("AWS", "AccessKey")); File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/sqs/connection.py", line 54, in __init__ self.region.endpoint, debug, https_connection_factory) File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/connection.py", line 418, in __init__ debug, https_connection_factory) File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/connection.py", line 189, in __init__ self.refresh_http_connection(self.server, self.is_secure) File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/connection.py", line 247, in refresh_http_connection connection = httplib.HTTPSConnection(host) AttributeError: 'module' object has no attribute 'HTTPSConnection'

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  • Query notation for the sitecore 'source' field in template builder

    - by M.R.
    I am trying to set the the source field of a template using the query notation (or xpath - whichever works), but none of them seems to be working. My content tree is a multisite content tree: France --Page 1 ----Page1A -------Page1AA --Page 2 --Page 3 --METADATA ----Regions US --Page 1 ----Page1A -------Page1AA --Page 2 --Page 3 --METADATA ----Regions Each site has its own METADATA folder, and I want it so that when adding a page inside each of the main country nodes, I want the values to reflect whatever is in the METADATA of that site. I have two different fields for now - a droplink and a treelistex field. So I thought I can just get the parent item that is a country site, and get the metadata folder for that. When I put the following query in both the fields, I get different results: query:./ancestor::*[@@templatename='CountryHome']/METADATA/Regions/* For the droplink field, I get only the first Region (one item) For the treelistex field, I get the entire content tree I then tried to modify the query a little bit and took the 'query' notation out ./ancestor::*[@@templatename='CountryHome']/METADATA/Regions/* If I go to the developer center/xpath builder, and set the context node to any item underneath the main country site, it returns me exactly what I need, but when I put this in the source, I get the entire content tree in both the cases. Help!

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  • Get textbox binding in wpf datagridtemplatecolumn

    - by klawusel
    Hi I have a wpf datagrid containing multiple datagridtemplatecolumns, which all are build up from a datatemplate which contains a textbox. Now I want to get the binding of the textbox (I have a reference to the template column which textbox's binding I woukld like to determine). Alternatively it would be nice to return the X:Name of the template column Any hints? Regards klaus

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  • RESTful design, how to name pages outside CRUD et al?

    - by sscirrus
    Hi all, I'm working on a site that has quite a few pages that fall outside my limited understanding of RESTful design, which is essentially: Create, Read, Update, Delete, Show, List Here's the question: what is a good system for labeling actions/routes when a page doesn't neatly fall into CRUD/show/list? Some of my pages have info about multiple tables at once. I am building a site that gives some customers a 'home base' after they log on. It does NOT give them any information about themselves so it shouldn't be, for example, /customers/show/1. It does have information about companies, but there are other pages on the site that do that differently. What do you do when you have these situations? This 'home-base' is shown to customers and it mainly has info about companies (but not uniquely so). Second case: I have a table called 'Matchings' in between customers and companies. These matchings are accessed in completely different ways on different parts of the site (different layouts, different CSS sheets, different types of users accessing them, etc. They can't ALL be matchings/show. What's the best way to label the others? Thanks very much. =)

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  • How to update multiple rows with different values in mysql?

    - by user210481
    I have a table with a column 'A'. Some rows have 14 digits for the column 'A' and some have only 12. I need to transform all the entries to 14 digits. The datatype is varchar I would like to update all the rows at once (one query), adding zeros before the first digit, so an entry like 012345678910 would become 00012345678910. Is it possible to do it in one single query? Thanks

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  • Microsoft SQL Count problem

    - by Matt
    Hey smarties. I'm having trouble with the following SQL statement. I know that I can't do a GROUP BY on the OnlineStatus column, and it makes sense because it's a function call, not an actual column in my table. How would I modify this so that I can get a count of how many users are online? SELECT CASE dbo.fnGetWebUserOnlineStatus(W.Id) WHEN 1 THEN 'Online' WHEN 2 THEN 'Ingame' ELSE 'Offline' END AS OnlineStatus FROM dbo.WebUsers W WHERE W.[Status]=1 GROUP BY OnlineStatus

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  • Zend_DB_Table Update problem

    - by davykiash
    Am trying to construct a simple update query in my model class Model_DbTable_Account extends Zend_Db_Table_Abstract { protected $_name = 'accounts'; public function activateaccount($activationcode) { $data = array( 'accounts_status' => 'active', ); $this->update($data, 'accounts_activationkey = ' . $activationcode); } However I get an SQLSTATE[42S22]: Column not found: 1054 Unknown column 'my activation code value' in 'where clause' error. What am I missing in Zend_Table update construct?

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  • Any way to speed up this hierarchical query?

    - by RenderIn
    I've got a serious performance problem with a hierarchical query that I can't seem to fix. I am modeling several organization charts in my database, each representing a virtual organization within our company. For example, we have several temporary committees that are created from time to time and there may be a Committee Organizer role at the top of this virtual hierarchy, with several people assigned to the Committee Member role beneath the organizer. Some of our virtual organizations have many levels and several branches at each level. I have a single table in which I represent all the role assignments. i.e. a ROLE_ID column and a PARENT_ROLE_ID column which is a foreign key to the ROLE_ID column. For each assignment we also store as a column the location in the company where this person has the assignment. For example, the Committee Organizer would have a company-level/ CEO assignment, while the committee members would have department-level assignments such as ACCOUNTING, MARKETING, etc. So to model the organizer/member relationship for two individuals we would have: ROLE_ID = 4 PARENT_ROLE_ID = NULL EMPLOYEE_NUMBER = 213423 COMPANY_LOCATION = CEO ROLE_ID = 5 PARENT_ROLE_ID = 4 EMPLOYEE_NUMBER = 838221 COMPANY_LOCATION = ACCOUNTING Here's where things get tricky. I have an application that every person in the organization can log in to. When they log in they should be able to view all the virtual organizations in our company. e.g. the committee members should be able to see the committee organizer and vice-versa. However, only the committee organizer should be able to edit the committee members. The difficulty is in determining whether an individual (who can have multiple role assignments) has edit access for each other assignment. While this seems simple in the example, consider a virtual organization in which we have President at the top, 5 departments directly beneath him, 2 subdepartments below each department. We only want people in the Accounting department to be able to edit individuals in the subdepartments belonging to the Accounting department. They should not have edit access to anybody in the Marketing department or its subdepartments. To determine edit access when a user views a virtual organization in our company I run a query that executes two inline views: A) Hierarchically query for all assignments in this virtual organization and using SYS_CONNECT_BY_PATH to store the entire path to each user/role/company_location and B) Hierarchically retrieve all the assignments the individual logged in has and using the SYS_CONNECT_BY_PATH to store the entire path to each of these assignments. The result of the query is all the records from A) plus a boolean determined by joining with B) which flags whether the logged in user has edit access for each record. Indexes don't seem to be helping... it simply appears that there is too much processing going on to separate all the records and then determine edit access. One issue is that I can't store the SYS_CONNECT_BY_PATH and index it... determining whether an individual record has edit access consists of comparing if: test_record_sys_path LIKE individual_record_sys_path || '%' Is a materialized view the answer?

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  • ClassCastExcpetion Linq to SQL

    - by BitFiddler
    I have a column definition in my generated Dbml file: <Column(Storage:="_Low", DbType:="Decimal(18,2)", UpdateCheck:=UpdateCheck.WhenChanged)> Public Property Low() As System.Nullable(Of Decimal) When I try to assign: With someObject .Low = 21.33D End With I get a ClassCastException when I call db_context.SubmitChanges(). Anyone have an idea why this is? Thanks

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  • Configuring Displays for Different Mobile Devices

    - by Mike
    Does anyone know a way to have specific CSS style sheets based on the type of Mobile Device? I have been researching it a few days now and haven't found anything except this snippet of code for iPhones. <link media="only screen and (max-device-width: 480px)" href="iPhone.css" type="text/css" rel="stylesheet" /> This works great for iPhones, but on all other mobile devices (android, blackberry, Nokia), it's still displaying the same as my site. I tried: <link media="handheld" href="iPhone.css" type="text/css" rel="stylesheet" /> but that didn't seem to have any effect on the other mobile devices. So I'm not sure how to reach the blackberry's/androids/nokia's without effect the code of my actual site. I'm building my site using the PHP framework CodeIgniter and I looked into this code which is suppose to be able to tell if it is being looked at through a mobile device or browser. if ($this->agent->is_browser()) { $agent = $this->agent->browser().' '.$this->agent->version(); } elseif ($this->agent->is_mobile()) { $agent = $this->agent->mobile(); } else { $agent = 'Unidentified User Agent'; } The only problem is that the newer phones we are building on render the site as a browser and not as a mobile (I think, I've only tested the iphone because it's all I have at the moment). So does anyone have any work arounds for the other phone platforms?

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  • Help with error creating SharePoint list (probably due to privilege issues)

    - by Swami
    I'm getting an error when trying to activate a webpart. It activates fine in one setup , but fails in a different one. Administrator in both. Seems like it fails because it's not able to create the list. The error is: Message: Value cannot be null. Stack Trace: at Microsoft.Sharepoint.SPRoleAssignment..ctor at ClientRequestHandler.CreateList(... private static void CreateLists() { try { SPSecurity.RunWithElevatedPrivileges(delegate() { using (SPSite site = SPContext.Current.Site) { using (SPWeb web = site.RootWeb) { string listName = LIST_NAME; bool listExist = ContainList(web, listName); if (!listExist) { AddFieldDelegate _delegate = new AddFieldDelegate(AddAttachmentFields); SPList list = CreateList(web, listName, _delegate); RegisterList(web, list, KEY); } } } }); } catch (Exception ex) { throw new Exception(String.Format("Message: {0} Stack Trace: {1}", ex.Message, ex.StackTrace.ToString())); } } private static SPList CreateList(SPWeb web, string listName, AddFieldDelegate _delegate) { web.AllowUnsafeUpdates = true; SPListTemplateType genericList = new SPListTemplateType(); genericList = SPListTemplateType.GenericList; Guid listGuid = web.Lists.Add(listName, "List", genericList); SPList list = web.Lists[listGuid]; list.Hidden = true; SPView view = _delegate(list); view.Update(); //Remove permissions from the list list.BreakRoleInheritance(false); //Make site owners the list administrators SPPrincipal principal = web.AssociatedOwnerGroup as SPPrincipal; SPRoleAssignment assignment = new SPRoleAssignment(principal); assignment.RoleDefinitionBindings.Add(web.RoleDefinitions.GetByType(SPRoleType.Administrator)); list.RoleAssignments.Add(assignment); //update list changes list.Update(); return list; }

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  • HTML table with fixed headers?

    - by Cheekysoft
    Does anyone know a cross-browser CSS/Javascript technique to display a long html table such that the column headers stay fixed on-screen and do not scroll with the table body. Think of the "freeze panes" effect in excel. I want to be able to scroll through the contents of the table, but to always be able to see the column headers at the top.

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  • how to use conditional select query ? in sqlserver

    - by Arunachalam
    how to use conditional select query ? in sqlserver i have a column in which i store date type variable .now i should retrieve one value from that column and find the difference with the curent_timestamp and if the difference is less than 10 mins i should a return 1 and if more than 10 mins i should return 0.is it possible ? 05-12-2010 13.58.30 - 05-12-2010 13.56.30 here the difference is 2 so it should return 1 .

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  • How do i replace a key up keyCode with another in jQuery?

    - by Brian Scott
    I currently have a table which only has a single editable column. I have a jQCuery change() event associated with the column's input controls to prevent any non numeric keys being pressed, other than tab / delete / backspace. I would like to replace the Enter key with a Tab press. Can someone please show me the relevant statement to replace the keyCode based on the Enter character being intercepted?

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  • WPF tooltip in MS datagrid

    - by klawusel
    Hi I show my business objects in a MS datagrid, containing "country", "city", "street", for example. I can set a tooltip for each column showing its content using a style, so I get the "country" as tooltip when hooverinmg over the "country" column and so on. But I did not succeed 1) to show the content of "country" when hoovering over "city" 2) to show the content of some other property (not even displayed in the datagrid) when hoovering the datagrid Any clues? Regards

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  • Specifying Cell Format in CSV File

    - by Someone
    I am generating a csv file from a PHP array. It opens just fine in Excel and OpenOffice Calc, however the data in one of the column are zip codes. Excel makes the cell formats of the column number general by default. This results in the leading 0 getting dropped in zip codes. Is there any way I can specify the cell formats within the CSV file?

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  • Execute SQL SP in Excel VBA

    - by TheOCD
    HI I am having problem with getting all the columns back when i execute following code in excel vba. I only get 6 out of 23 columns back. Connection, command etc works fine (i can see exec command in the SQL Profiler), data headers are created for all 23 columns but i only get data for 6 column. Side Note: it's not prod level code, have missed out error handling on purpose, sp works fine in SQL management studio, ASP.Net, C# win form app, it is for Excel 2003 connecting to SQL 2008. Can someone help me troubleshoot it? Dim connection As ADODB.connection Dim recordset As ADODB.recordset Dim command As ADODB.command Dim strProcName As String 'Stored Procedure name Dim strConn As String ' connection string. Dim selectedVal As String 'Set ADODB requirements Set connection = New ADODB.connection Set recordset = New ADODB.recordset Set command = New ADODB.command If Workbooks("Book2.xls").MultiUserEditing = True Then MsgBox "You do not have Exclusive access to the workbook at this time." & _ vbNewLine & "Please have all other users close the workbook and then try again.", vbOKOnly + vbExclamation Exit Sub Else On Error Resume Next ActiveWorkbook.ExclusiveAccess 'On Error GoTo No_Bugs End If 'set the active sheet Set oSht = Workbooks("Book2.xls").Sheets(1) 'get the connection string, if empty just exit strConn = ConnectionString() If strConn = "" Then Exit Sub End If ' selected value, if <NOTHING> just exit selectedVal = selectedValue() If selectedVal = "<NOTHING>" Then Exit Sub End If If Not oSht Is Nothing Then 'Open database connection connection.ConnectionString = strConn connection.Open ' set command stuff. command.ActiveConnection = connection command.CommandText = "GetAlbumByName" command.CommandType = adCmdStoredProc command.Parameters.Refresh command.Parameters(1).Value = selectedVal 'Execute stored procedure and return to a recordset Set recordset = command.Execute() If recordset.BOF = False And recordset.EOF = False Then Sheets("Sheet2").[A1].CopyFromRecordset recordset ' Create headers and copy data With Sheets("Sheet2") For Column = 0 To recordset.Fields.Count - 1 .Cells(1, Column + 1).Value = recordset.Fields(Column).Name Next .Range(.Cells(1, 1), .Cells(1, recordset.Fields.Count)).Font.Bold = True .Cells(2, 1).CopyFromRecordset recordset End With Else MsgBox "b4 BOF or after EOF.", vbOKOnly + vbExclamation End If 'Close database connection and clean up If CBool(recordset.State And adStateOpen) = True Then recordset.Close Set recordset = Nothing If CBool(connection.State And adStateOpen) = True Then connection.Close Set connection = Nothing Else MsgBox "oSheet2 is Nothing.", vbOKOnly + vbExclamation End If

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  • What is the mysql 5.5 equivalent for the sys.dm_fts_index_keywords_by_document in sql 2008

    - by djsurge
    I'm making a web application that uses the data in the sys.dm_fts_index_keywords_by_document. I'm interested how many times a given term occurs in each string that is indexed. For example, I have a table with a column called comments, the table has various strings in the comments field. When I make that column full text searchable, the dm_fts_index_keywords_by_document is created and I can see the word per document data. Can i do the same thing in mySQL?

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  • List MySQL enum in Java

    - by Pieter
    Is there a way to get all possible values from a MySQL enum column? The MySQL documentation says the MySQL enum type is returned as a Java String, so I basically would like a way to get all possible strings I can pass when querying a table with such an enum. I couldn't immediately find anything when I was looking through the metadata returned for such a column, but since enum isn't standard SQL, I'm not sure it's even possible... any suggestions?

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  • How to use jquery grid formatter for links with grails ?

    - by Neoryder
    I have this column in a html table in my gsp. <td><g:remoteLink action="show" id="${a.id}" update="form">${a.name}</g:remoteLink></td> I'd like to use jquery grid http://www.trirand.com/blog/?page_id=6 with my grails application. I'd like to format the above link for use in a jquery grid column. Does anybody know how to do this?

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  • Why is it that, table is not printing in the xsl-fo here? please help me guys.

    - by atrueguy
    This is my xml file <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="currency.xsl"?> <currencylist> <title>Currencies By Country</title> <countries> <country>Australia</country> <currency>Australian Dollar</currency> </countries> <countries> <country>Austria</country> <currency>Schilling</currency> </countries> <countries> <country>Belgium</country> <currency>Belgium Franc</currency> </countries> <countries> <country>Canada</country> <currency>Canadian Dollar</currency> </countries> <countries> <country>England</country> <currency>Pound</currency> </countries> <countries> <country>Fiji</country> <currency>Fijian Dollar</currency> </countries> <countries> <country>France</country> <currency>Franc</currency> </countries> <countries> <country>Germany</country> <currency>DMark</currency> </countries> <countries> <country>Hong Kong</country> <currency>Hong Kong Dollar</currency> </countries> <countries> <country>Italy</country> <currency>Lira</currency> </countries> <countries> <country>Japan</country> <currency>Yen</currency> </countries> <countries> <country>Netherlands</country> <currency>Guilder</currency> </countries> <countries> <country>Switzerland</country> <currency>SFranc</currency> </countries> <countries> <country>USA</country> <currency>Dollar</currency> </countries> </currencylist> This is my xsl-fo file: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format"> <fo:layout-master-set> <fo:simple-page-master master-name="Letter" page-height="11in" page-width="8.5in"> <fo:region-body region-name="only_region" margin="0.7in" margin-top="1.2in" margin-left="1.1in"/> <fo:region-before region-name="xsl-region-before" extent="1.5in" /> <fo:region-after region-name="xsl-region-after" extent="1.5in" /> <fo:region-start region-name="xsl-region-after" extent="1.5in" /> </fo:simple-page-master> </fo:layout-master-set> <fo:page-sequence master-reference="Letter"> <fo:flow flow-name="only_region"> <fo:block text-align="left"><xsl:call-template name="show_title"/></fo:block> <fo:table-and-caption> <fo:table> <fo:table-column column-width="25mm"/> <fo:table-column column-width="25mm"/> <fo:table-column column-width="25mm"/> <fo:table-header> <fo:table-row> <fo:table-cell> <fo:block font-weight="bold">SI No</fo:block> </fo:table-cell> <fo:table-cell> <fo:block font-weight="bold">Country</fo:block> </fo:table-cell> <fo:table-cell> <fo:block font-weight="bold">Currency</fo:block> </fo:table-cell> </fo:table-row> </fo:table-header> <fo:table-body> <xsl:for-each select="currencylist/countries"> <fo:table-row> <fo:table-cell> <fo:block> <xsl:value-of select="position()"/> </fo:block> </fo:table-cell> <fo:table-cell> <fo:block> <xsl:value-of select="country"/> </fo:block> </fo:table-cell> <fo:table-cell> <fo:block> <xsl:value-of select="currency"/> </fo:block> </fo:table-cell> </fo:table-row> </xsl:for-each> </fo:table-body> </fo:table> </fo:table-and-caption> </fo:flow> </fo:page-sequence> </fo:root> </xsl:template> <xsl:template name="show_title" match="currencylist"> <xsl:value-of select="currencylist/title"/> </xsl:template> </xsl:stylesheet> Table structure is not printing, but the values are printing, please help guys.

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