Search Results

Search found 34688 results on 1388 pages for 'java ee 6 apis'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 334/1388 | < Previous Page | 330 331 332 333 334 335 336 337 338 339 340 341  | Next Page >

  • toString() in Java

    - by Allain Lalonde
    A lead developer on my project has taken to referring to the project's toString() implementations as "pure cruft" and is looking to remove them from the code base. I've said that doing so would mean that any clients wishing to display the objects would have to write their own code to convert the object to string, but that was answered with "yes they would". Now specifically, the objects in this system are graphic elements like rectangles, circles, etc and the current representation is to display x, y, scale, bounds, etc... So, where does the crowd lie? When should you and when shouldn't you implement toString?

    Read the article

  • incompatible types in java

    - by user2975357
    Should I point out that I am a begginer at this? double averageMonthlyTemp() { double[] amt = new double[52]; int sum = 0; int index = 0; for (int i = 0; i < temp.length - 1; i = i + 7) { //where temp is an existiing //previously initialized array //of 365 elements, form 0 to 364 for (int j = 0; j < 7; j++) { sum = sum + temp[i + j]; if (j % 7 == 6) { double average = ((double) sum) / 7; amt[index] = average; index++; sum = (int) 0; } } } return amt; } When I try to compile, I get an "incompatible types" error, with the "amt" at return amt marked in red. Does somebody know why?

    Read the article

  • Why does (360 / 24) / 60 = 0 ... in Java

    - by Ankur
    I am trying to compute (360 / 24) / 60 I keep getting the answer 0.0 when I should get 0.25 In words: I want to divide 360 by 24 and then divide the result by 60 public class Divide { public static void main(String[] args){ float div = ((360 / 24) / 60); System.out.println(div); } } This prints out: 0.0 Why is that? Am I doing something really stupid, or is there a good reason for this

    Read the article

  • Insertion into BST without header Node JAVA

    - by Petiatil
    I am working on a recursive insertion method for a BST. This function is suppose to be a recursive helper method and is in a private class called Node. The Node class is in a class called BinarySearchTree which contains an instance variable for the root. When I am trying to insert an element, I get a NullPointerException at : this.left = insert(((Node)left).element); I am unsure about why this occurs. If I understand correctly, in a BST, I am suppose to insert the item at the last spot on the path transversed. Any help is appreciated! private class Node implements BinaryNode<E> { E item; BinaryNode<E> left, right; public BinaryNode<E> insert(E item) { int compare = item.compareTo(((Node)root).item); if(root == null) { root = new Node(); ((Node)root).item = item; } else if(compare < 0) { this.left = insert(((Node)left).item); } else if(compare > 0) { this.right = insert(((Node)right).item); } return root; } }

    Read the article

  • startsWith using error in java

    - by user1838839
    defined variable: LinkedList list1=new LinkedList(); Object get() in list1 obtains a node of list1 Object remove() in list1 deletes a node of list1 count() is length of list1 for(int i=1;i<list1.count();i++){ if(list1.get(i).startsWith('"',0)) //Error here list1.remove(i); } Error: cannot find symbol symbol: method charAt(int) location: class Object how to fix this problem? I would like to delete the node in list1 which starts with (").

    Read the article

  • Can i query a List? Java

    - by Nitesh Panchal
    Hello, Say i have List<SomeObject> objList = new ArrayList<SomeObject>(); If someObject contains a field named id. Can we find it through some query like objList.filter('id=2'); wihout looping through the list? If not, then why? This can be so useful method and used as an alternative to write tedious for loop? Just a question that came to my mind so i thought i must clear it here :) Thanks in advance :)

    Read the article

  • Confusing calling method in Java

    - by vBx
    class Parent { private void method1() { System.out.println("Parent's method1()"); } public void method2() { System.out.println("Parent's method2()"); method1(); } } class Child extends Parent { public void method1() { System.out.println("Child's method1()"); } } class test { public static void main(String args[]) { Parent p = new Child(); p.method2(); } } I'm confuse why does in Parent::method2() when invoking method1() it will cal Parents method1() and not Childs method1 ? I see that this happens only when method1() is private? Can someone explain me why ? Thanks you.

    Read the article

  • Java: howto write equals() shorter

    - by erikb
    I get headaches when I have to write nearly 10 lines of code to say 2 Objects are equal, when their type is equal and both's attribute is equal. You can easily see that in this way of writing the number of lines increase drastically with your number of attributes. public class Id implements Node { private String name; public Id(String name) { this.name = name; } public boolean equals(Object o) { if (o == null) return false; if (null == (Id) o) return false; Id i = (Id) o; if ((this.name != null && i.name == null) || (this.name == null && i.name != null)) return false; return (this.name == null && i.name == null) || this.name.equals(i.name); } }

    Read the article

  • Accessing variables in other classes (Java)

    - by George
    Why doesn't the following program return 0, since I am accessing p from a new A(), which has not had main called on it? public class A { public int p = 0; public static void main(String[] args) { p = Integer.parseInt(args[0]); new B().go(); } } class B { public void go() { System.out.println(new A().p); } }

    Read the article

  • List Question in Java

    - by TiNS
    Hello All, I have a following ArrayList, [Title,Data1,Data2,Data3] [A,2,3,4] [B,3,5,7] And I would like to convert this one like this, [Title,A,B] [Data1,2,3] [Data2,3,5] [Data3,4,7] I'm bit confused with the approach. Any hint would be much appreciated. Thanks.

    Read the article

  • Does Java not support multiple inheritance?

    - by user1720616
    Lets us take instances of two classes public abstract class Shapes { public abstract void draw(Graphics g); } public class Rectangle extends Shapes { public void draw(Graphics g) { //implementation of the method } } here the class Rectangle has extended class Shapes and implicitly it extends class Object.I know no other extension is possible but cant we call inheriting classes Shapes and Object multiple inheritance?(Since inheriting two classes is multiple inheritance from one perspective)

    Read the article

  • java source code doubt

    - by abson
    Why is it that class swi22 { public static void main(String[] args) { int a=98; switch(a) { default:{ System.out.println("default");continue;} case 'b':{ System.out.println(a); continue;} case 'a':{ System.out.println(a);} } System.out.println("Switch Completed"); } } gives error as: continue outside of loop

    Read the article

  • question about comlen function in java

    - by davit-datuashvili
    in c or c++ function comlen is defined such int comlen(char *p,char *q){ int i=0; while *p && (*p++==*q++) i++; return i; is this code equivalent of this function int comlen(String s,String m){ int i=0; while (i<s.length() && s.charAt(i)==m.charAt(i)){ i++; } return i; ? please help

    Read the article

  • Pagination in Java

    - by user569125
    I wrote paging logic: My requirement: total elements to display:100 per page,if i click next it should display next 100 records,if i click previous 100 records. Initial varaible values: showFrom:1, showTo:100 max elements:depends on size of data. pageSize:100. Code: if(p*emphasized text*aging.getAction().equalsIgnoreCase("Next")){ paging.setTotalRec(availableList.size()); showFrom = (showTo + 1); showTo = showFrom + 100- 1; if(showTo >= paging.getTotalRec()) showTo = paging.getTotalRec(); paging.setShowFrom(showFrom); paging.setShowTo(showTo); } else if(paging.getAction().equalsIgnoreCase("Previous")){ showTo = showFrom - 1; showFrom = (showFrom - 100); paging.setShowTo(showTo); paging.setShowFrom(showFrom); paging.setTotalRec(availableList.size()); } Here i can remove and add the elements to the existing data.above code works fine if i add and remove few elements.but if i remove or add 100 elements at a time counts are not displaying properly above code works fine if i add and remove few elements.

    Read the article

  • Subtyping and assignment in Java

    - by Danrex
    Arghh I just know people are going to hate me for asking this... I was just playing around with inheritance and I noticed you can instantiate a subclass object in one of two ways when you write code. So then I wondered if there is any functional difference between these two methods. So in the code below, does this produce the exact same result...a MountainBike object, or is there some difference I should know about? Bicycle is the superclass for this example. If I do Bicycle bike or MountainBike bike I am effectively making a MountainBike due to new MountainBike()? So basically the difference is just semantics at this point? Bicycle bike = new MountainBike(); MountainBike bike = new MountainBike();

    Read the article

  • Call subclass constructor from abstract class in Java

    - by Joel
    public abstract class Parent { private Parent peer; public Parent() { peer = new ??????("to call overloaded constructor"); } public Parent(String someString) { } } public class Child1 extends parent { } public class Child2 extends parent { } When I construct an instance of Child1, I want a "peer" to automatically be constructed which is also of type Child1, and be stored in the peer property. Likewise for Child2, with a peer of type Child2. The problem is, on the assignment of the peer property in the parent class. I can't construct a new Child class by calling new Child1() because then it wouldn't work for Child2. How can I do this? Is there a keyword that I can use that would refer to the child class? Something like new self()?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 330 331 332 333 334 335 336 337 338 339 340 341  | Next Page >