Search Results

Search found 27663 results on 1107 pages for 'input mode'.

Page 336/1107 | < Previous Page | 332 333 334 335 336 337 338 339 340 341 342 343  | Next Page >

  • Cannot clear the form after Submit using the Validation plugin in jQuery

    - by novellino
    Hello, I an quite new to jQuery and I have a problem while trying to create a form. I am using the Validation plugin for validate the email (one the form's field). When I click the Submit button I want to call my own function because I want to save the data in an XML file. This is my button: (as I understood the plugin uses "submit" for understand the button) <input type="submit" name="submit" class="submit" id="submit_btn" value="Send"/> and here is the script for the validation: <script type="text/javascript"> $(document).ready(function() { //this is my form $("#contactForm").validate(); /*save the valid data in the xml*/ $(".submit").click(function() { var email = $("input#email").val(); var subject = $("input#subject").val(); var message = $("textarea#message").val(); if (email == "" || !$("#contactForm").valid()) { return false; } var dataString = 'email='+ email + '&subject=' + subject + '&message=' + message; //alert("DATA: " +dataString); $.ajax({ type: "POST", url: "SaveData.jsp", data: dataString, success: function(data){} }); return false; }); }); </script> In general it works ok but I have two basic problems. When I click the button in the beginning having all the form empty, I get no message for the field required. Also when the data are valid and I am doing the submit, the form does not become clear after the submit. If I deleted this script code, these actions are working properly but I can not save the data! Does anyone know what is wrong? Thanks a lot!

    Read the article

  • How do I determine if form field is empty with jQuery?

    - by user338413
    I've got a form with two fields, firstname and lastname. The user does not have to fill in the fields. When the user clicks the submit button, a jquery dialog displays with the data the user entered in the form. I only want to show the data for the fields that were entered. I'm trying to do an if statement and use the length() function but it isn't working. Help would be great! Here is my dialog jquery script: $(function(){ //Initialize the validation dialog $('#validation_dialog').dialog({ autoOpen: false, height: 600, width: 600, modal: true, resizable: false, buttons: { "Submit Form": function() { document.account.submit(); }, "Cancel": function() { $(this).dialog("close"); } } }); // Populate the dialog with form data $('form#account').submit(function(){ $("p#dialog-data").append('<span>First Name: </span>'); $("p#dialog-data").append('<span>'); $("p#dialog-data").append($("input#firstname").val()); $("p#dialog-data").append('</span><br/>'); if (("input#lastname").val().length) > 0) { $("p#dialog-data").append('<span>Last Name: </span>'); $("p#dialog-data").append('<span>'); $("p#dialog-data").append($("input#lastname").val()); $("p#dialog-data").append('</span><br/>'); }; $('#validation_dialog').dialog('open'); return false; }); });

    Read the article

  • Piping EOF problems with stdio and C++/Python

    - by yeus
    I got some problems with EOF and stdio. I have no idea what I am doing wrong. When I see an EOF in my program I clear the stdin and next round I try to read in a new line. The problem is: for some reason the getline function immediatly (from the second run always, the first works just as intended) returns an EOF instead of waiting for a new input from py python process... Any idea? alright Here is the code: #include <string> #include <iostream> #include <iomanip> #include <limits> using namespace std; int main(int argc, char **argv) { for (;;) { string buf; if (getline(cin,buf)) { if (buf=="q") break; /*****///do some stuff with input //my actual filter program cout<<buf; /*****/ } else { if ((cin.rdstate() & istream::eofbit)!=0)cout<<"eofbit"<<endl; if ((cin.rdstate() & istream::failbit)!=0)cout<<"failbit"<<endl; if ((cin.rdstate() & istream::badbit)!=0)cout<<"badbit"<<endl; if ((cin.rdstate() & istream::goodbit)!=0)cout<<"goodbit"<<endl; cin.clear(); cin.ignore(numeric_limits<streamsize>::max()); //break;//I am not using break, because I //want more input when the parent //process puts data into stdin; } } return 0; } and in python: from subprocess import Popen, PIPE import os from time import sleep proc=Popen(os.getcwd()+"/Pipingtest",stdout=PIPE,stdin=PIPE,stderr=PIPE); while(1): sleep(0.5) print proc.communicate("1 1 1") print "running"

    Read the article

  • CSS: Possible to define styles mid way through an html document?

    - by Dr. Zim
    In ASP.NET MVC, there are these snippets of html called view templates which appear when their matching data appears on the screen. For example, if you have a customer order and it has a vendor address, the vendor address view template shows up populated with data. Unfortunately, these don't have access to "MasterPages" nor are aware of their CSS surroundings. Instead of loading these up with style tags, is there any way to create partial CSS files that could work for that particular html snippet, a sort of in-line CSS style section? It would be really nice to plop this down just before we render the partial view: <style type="text/css"> input { margin: .2em .2em; overflow: hidden; width: 18.8em; height: 1.6em; border: 1px solid black;} </style> to have the 15 or so input fields in that particular Html snippet be formatted the same. These are swapped out, so the positions of the input fields change. This may also imply a CSS reset on each partial view.

    Read the article

  • Keeping iPhone application in sync with GWT application.

    - by Reflog
    Hi, I'm working on an iPhone application that should work in offline and online modes. In it's online mode it's supposed to feed all the information the user enters to a webservice backed by GWT/GAE. In it's offline mode it's supposed to store the information locally, and when connection is available sync it up to the web service. Currently my plan is as follows: Provide a connection between an app and a webservice using Protobuffers for efficient over-the-wire communication Work with local DB using Core Data Poll the network status, and when available sync the database and keep some sort of local-db-to-remote-db key synchronization. The question is - am I in the right direction? Are the standard patterns for implementing this? Maybe someone can point me to an open-source application that works in a similar fashion? I am really new to iPhone coding, and would be very glad to hear any suggestions. Thanks

    Read the article

  • Database design: Using hundred of fields for little values

    - by user964260
    I'm planning to develop a PHP Web App, it will mainly be used by registered users(sessions) While thinking about the DB design, I was contemplating that in order to give the best user experience possible there would be lots of options for the user to activate, deactivate, specify, etc. For example: - Options for each layout elements, dialog boxes, dashboard, grid, etc. - color, size, stay visible, invisible, don't ask again, show everytime, advanced mode, simple mode, etc. This would get like 100s of fields ranging from simple Yes/No or 1 to N values..., for each user. So, is it having a field for each of these options the way to go? or how do those CRMs or CMS or other Web Apps do it to store lots of 1-2 char long values? Do they group them on Text fields separated by a special char and then "explode" them as an array for runtime usage? thank you

    Read the article

  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

    Read the article

  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

    Read the article

  • Unable to send '+' through AJAX post?

    - by Harish Kurup
    I am using Ajax POST method to send data, but i am not able to send '+'(operator to the server i.e if i want to send 1+ or 20k+ it will only send 1 or 20k..just wipe out '+') HTML code goes here.. <form method='post' onsubmit='return false;' action='#'> <input type='input' name='salary' id='salary' /> <input type='submit' onclick='submitVal();' /> </form> and javascript code goes here, function submitVal() { var sal=document.getElementById("salary").value; alert(sal); var request=getHttpRequest(); request.open('post','updateSal.php',false); request.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); request.send("sal="+sal); if(request.readyState == 4) { alert("update"); } } function getHttpRequest() { var request=false; if(window.XMLHttpRequest) { request=new XMLHttpRequest(); } else if(window.ActiveXObject) { try { request=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try { request=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e) { request=false; } } } return request; } in the function submitVal() it first alert's the salary value as it is(if 1+ then alerts 1+), but when it is posted it just post's value without '+' operator which is needed... is it any problem with query string, as the PHP backend code is working fine...

    Read the article

  • I Clean Solution'd my Winform App and now it's broken...

    - by Refracted Paladin
    I have a Winform App that uses a 3rd Party Library of Controls, DevExpress. I also created a bunch of Controls myself, extending those controls. Everything has been working fine when all of a sudden I opened VS today and on the Design Page all my extended controls were missing. I then tried rebuilding to no avail. Then I tried Cleaning and Rebuilding and made it even worse. Now I have tons(520) of erros stating things like -- Error 179 The name 'datBirthDate' does not exist in the current context D:\Documents\Visual Studio 2008\Projects\MatrixReloaded\MatrixReloaded\Controls\Member\ucGeneral.cs 339 17 MatrixReloaded also if I try to open a form or user control in Design Mode I first get this -- could not find type, "MyType" please make sure that the assembly that contains this type is referenced and then, if I click Ignore and Continue I get this for all Forms and Contros when I try and look at them in Design Mode -- Exception of type System.OutOfMemoryException was thrown Help!?!? When I googled I came across mostly references to VS 2003...I am on 2008 sp1.

    Read the article

  • Multiple inputs on a single line with Twitter Bootstrap and Simple Form 2.0

    - by noel_g
    I am using simple_form 2.0 with twitter bootstrap. I am trying to determine what is the proper wrapper format in order to get something like [city] [State] [Zip] I believe my form needs to be <div class="control-group"> <%= f.input :city,:wrapper => :small, :placeholder => "City", :input_html => { :class=>"span2", :maxlength => 10},:label => false %> <%= f.input :region, :wrapper => :small , :placeholder => "Region", :input_html => { :class=>"span1", :maxlength => 5}, :label => false %> <%= f.input :postal_code, :wrapper => :small, :placeholder => "Postal Code",:input_html => { :class=>"span2", :maxlength => 10},:label => false %> </div> I tried this wrapper config.wrappers :small, :tag => 'div', :class => 'controls inline-inputs', :error_class => 'error' do |b| b.use :placeholder b.use :label_input end I believe I would need to define the CSS as well, but before I go down a rabbit hole I thought I would ask if this is built in somewhere.

    Read the article

  • Why are my ActiveRecord class instance variables disappearing after the first request in development

    - by Paul C
    I have a class instance variable on one of my AR classes. I set its value at boot with an initializer and, after that, never touch it again except to read from it. In development mode, this value disappears after the first request to the web server. However, when running tests, using the console or running the production server this does not happen. # The AR class class Group < ActiveRecord::Base class << self attr_accessor :path end end # The initializer Group.path = File.join(RAILS_ROOT, "public", "etc") # First request in a view %p= Group.path #=> "/home/rails/app/public/etc" # Second request in a view %p= Group.path #=> nil Is there something about development mode that nukes instance variables from classes with each request? If so, is there a way to disable this for specific variables or classes?

    Read the article

  • Merging a custom ContextMenuStrip with the system edit context menu in a DataGridView

    - by Tom
    I have a DataGridView in a VB.NET app that I have limited to cell selection only. The control has two columns, the first is not editable, the second is editable. I have a ContextMenuStrip that provides some additional functionality and I am able to make it appear when an editable cell receives a right click and is not in edit mode. Based on an example in a Microsoft forum, I am able to now show the context menu when an editable cell receives a right click while also in edit mode. That code is as follows: Private Sub DataGridView1_EditingControlShowing(ByVal sender As System.Object, ByVal e As System.Windows.Forms.DataGridViewEditingControlShowingEventArgs) Handles DataGridView1.EditingControlShowing If TypeOf e.Control Is TextBox Then With DirectCast(e.Control, TextBox) .ContextMenuStrip = ContextMenuStrip1 End With End If End Sub This, however, completely overwrites the system context menu of the editing control. How can I merge my Context Menu Strip (ContextMenuStrip1) with the system context menu? For further information, I am using VS2008, but targeting the .NET 2.0 platform.

    Read the article

  • Alternatives to connect to ORACLE database server without install the Oracle client.

    - by Salvador
    i am looking for an Delphi component to connect to an ORACLE database server in an direct way without install the oracle client. i knew the Oracle Data Access (ODAC) from DevArt. there are any other component with this capability? ODAC offers two connection modes to the Oracle server: connection through the Oracle Call Interface in Client mode and direct connection over TCP/IP in Direct mode. ODAC-based database applications are easy to deploy, do not require installation of other data provider layers. Thanks in advance.

    Read the article

  • OnSubmit does work right in the Validation plugin in jQuery

    - by novellino
    Hello, I an quite new to jQuery and I have a problem while trying to create a form. I am using the Validation plugin for validate the email (one the form's field). When I click the Submit button I want to call my own function because I want to save the data in an XML file. This is my button: (as I understood the plugin uses "submit" for understand the button) <input type="submit" name="submit" class="submit" id="submit_btn" value="Send"/> and here is the script for the validation: <script type="text/javascript"> $(document).ready(function() { //this is my form $("#contactForm").validate(); /*save the valid data in the xml*/ $(".submit").click(function() { var email = $("input#email").val(); var subject = $("input#subject").val(); var message = $("textarea#message").val(); if (email == "" || !$("#contactForm").valid()) { return false; } var dataString = 'email='+ email + '&subject=' + subject + '&message=' + message; //alert("DATA: " +dataString); $.ajax({ type: "POST", url: "SaveData.jsp", data: dataString, success: function(data){} }); return false; }); }); In general it works ok but I have two basic problems. When I click the button in the beginning having all the form empty, I get no message for the field required. Also when the data are valid and I am doing the submit, the form does not become clear after the submit. If I deleted this script code, these actions are working properly but I can not save the data! Does anyone know what is wrong? Thanks a lot!

    Read the article

  • jquery change event not working with IE6

    - by manivineet
    It is indeed quite unfortunate that my client still uses IE6. using jquery 1.4.2 The problem is that I open a window using a click event and do some edit operation in the new window. I have a 'change' event attached to the row of a table which has input fields. Now when the window loads for the first time and I make a change in the input for the FIRST time, the change event does not fire. however, on a second try it starts working. I have noticed that I e.g. I run a dummy page, i.e. create a new page(i work with visual studio) and run that page individually , the 'change' event works just fine. what it going on? and what can i do, besides going back to 1.3.2 (by the way that doesn't work either, but haven't fully tested it yet) <!--HTML--> <table id="tbReadData"> <tr class="nenDataRow" id="nenDr2"> <td> <input type="text" class="nenMeterRegister" value="1234" /> </td> <tr /> <table> <script type="text/javascript"> $(document).ready(function(){ $('#tbReadData').find('tr').change(function() { alert('this works'); } }); </script>

    Read the article

  • photo upload with codeigniter

    Hi friends, I know there are many tutorials online, but I could not make them work :( maybe something particularly wrong with my system :/ My Controller localpath is: /localhost/rl/applications/backend/controller/ Controller: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('add_image', $error); } else { $data = array('upload_data' => $this->upload->data()); $data['id'] = $this->input->post['id_work']; $this->load->view('add_image', $data); } } My View localpath is: /localhost/rl/applications/backend/view/ View: echo form_open_multipart('do_upload'); <ul class="frm"> <li><label>File: *</label><input type="file" name="userfile" class="frmlmnt" size="50" /></li> <li><label></label><input type="submit" class="btn" value="Upload" /></li> </ul> </form> Maybe I do something wrong with path

    Read the article

  • Google app engine error when I login.

    - by zjm1126
    i am using http://code.google.com/p/gaema/source/browse/#hg/demos/webapp, and this is my traceback: Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 510, in __call__ handler.get(*groups) File "D:\gaema\demos\webapp\main.py", line 31, in get google_auth.get_authenticated_user(self._on_auth) File "D:\gaema\demos\webapp\gaema\auth.py", line 641, in get_authenticated_user OpenIdMixin.get_authenticated_user(self, callback) File "D:\gaema\demos\webapp\gaema\auth.py", line 83, in get_authenticated_user url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) File "D:\Python25\lib\urllib.py", line 1250, in urlencode v = quote_plus(str(v)) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) how to do this thanks updated i change the code from args = dict((k, v[-1]) for k, v in self.request.arguments.iteritems()) args["openid.mode"] = u"check_authentication" url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) to args = dict((k, v[-1].encode('utf-8')) for k, v in self.request.arguments.iteritems()) args["openid.mode"] = u"check_authentication" url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) but also error.

    Read the article

  • Why Is my UISlider Thumb Image Being Shown Multiple Times and Not Disappearing As They Should?

    - by Gorgando
    This slider is possessed: When I move the slider thumb left or right, it leaves the original image there (creating an extra image). This doesn't happen every time and the only consistency i've noticed is that it's inconsistent. When the table is in "Editing mode" it is more likely to create a duplicate thumb image, but it also does so in regular mode. This is the code that I use to create the slider: CGRect frame = CGRectMake(20, 42.0, 280.0, 22); self.slider = [[UISlider alloc] initWithFrame:frame]; [self.slider addTarget:self action:@selector(sliderAction:) forControlEvents:UIControlEventValueChanged]; self.slider.continuous = YES; self.slider.minimumValue = 0.0; self.slider.maximumValue = 5.0; self.slider.value = 0.0; [sliderCell addSubview:self.slider]; Appreciate any thoughts you might have!

    Read the article

  • GridView take a Row

    - by GIbboK
    Hi I use asp.net 4 and c#. I have a GridView, I would like take a Row when in Edit Mode in my code and find a control. Here my code, but does not work, it takes only the first row for the GridView. Any ideas? protected void uxManageSlotsDisplayer_RowDataBound(object sender, GridViewRowEventArgs e) { switch (e.Row.RowType) { case DataControlRowType.DataRow: // Take Row in Edit Mode DOES NOT WORK PROEPRLY if (e.RowState == DataControlRowState.Edit) { Label myTest = (Label)e.Row.FindControl("uxTest"); } break; }

    Read the article

  • Styling individual radio buttons in drupal form

    - by Andrew
    I have this group of radio buttons in which each of individual button has of its own position set through style attribute. I would like to how can I archive the same by using drupal form api. I found how to style as whole but, not as individual control within group. Here's how my html code look like - <input type="radio" name="base_location" checked="checked" value="0" style="margin-left:70px;float:left;"/><span style="float:left;">District</span> <input type="radio" name="base_location" value="1" style="margin-left:50px;float:left;"/><span style="float:left;">MRT</span> <input type="radio" name="base_location" value="2" style="margin-left:60px;float:left;"/><span style="float:left;">Address</span> And this is the drupal code I'm stuck at - $form['base_location'] = array( '#type' => 'radios', '#title' => t('base location'), '#default_value' => variable_get('search_type', 0), '#options' => array( '0'=>t('District'), '1'=>t('MRT'), '2'=>t('Address')), '#description' => t('base location'), I'm aware of #type=radio existence. However, I do not know how to group all my radio buttons together in this regard. If I use same array key for all of them, they would collide each other. If I don't, they aren't seen as part of the same group. I thank you in advance.

    Read the article

  • why doesn't IE8 refresh textbox right away?(Jquery)

    - by AndrewSmith
    I have 3 radio buttons and one textbox in my page. These 3 radio controls represent corresponding choice and among them, the third one enables textbox that is disabled by default. If user clicks any one from the first twos after clicking the third, the textbox will be emptied(if user input any) and disabled again. The problem is, in IE, the textbox isn't emptied not until I click back once again on the said textbox. I've used jquery val methods as well as attr but nothing seems to work. You can see my code as follows. The very same code works just fine in Mozilla. I'm not sure why IE is having problem. m.bind_eventform = function(){ $('input[name=poster]').change(function(){ if($('input[name=poster]:checked').val()==2) $('#poster_other').removeAttr('disabled'); else if(!($('#poster_other').is(':disabled'))) { $('#poster_other').attr('disabled','disabled'); $('#poster_other').attr('value',''); //this one doesn't work $('#poster_other').val(''); //as well as this one } }); }; $(document).ready(m.bind_eventform);

    Read the article

  • Displaying data from a linked table and displaying it as a list with HTML/PHP/MySQL

    - by user1672694
    I have three tables. students studentID | FirstName | LastName | Email | Form course CCode | Title courseenrolement courseenrolementid | studentID | ccode | complete | scode With the website, I have a page where I can view all the current enrolements and I wish to be able to view the list displaying the first name, surname and course title. I know I could do it with the following SQL (for the names): SELECT FirstName, LastName FROM student, courseenrolement WHERE courseenrolement.studentID = student.studentID But I am unsure how to get this to work using HTML/PHP. At present I only know how to display the studentID and CCode from the courseenrolement table using the following code: <ul> <?php foreach ($courseenrolements as $ce): ?> <li> <form action="" method="post"> <div> <?php htmlout($ce['studentID']); ?> <?php htmlout($ce['CCode']); ?> <input type="hidden" name="courseenrolementid" value="<?php echo $ce['courseenrolementid']; ?>"> <input type="submit" name="action" value="Edit"> <input type="submit" name="action" value="Delete"> </div> </form> </li> <?php endforeach; ?> </ul> which displays this: But I would like the names and course title. I managed to get it to show the names etc in the dropdown on the 'Add new' form, so I would assume it will be similar, but just unsure on how exactly. Thanks in advance

    Read the article

  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

    Read the article

< Previous Page | 332 333 334 335 336 337 338 339 340 341 342 343  | Next Page >