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  • php - disconnecting and connecting to multiple databases

    - by Phil Jackson
    Hi, I want to be able to switch from the current db to multiple dbs though a loop: $query = mysql_query("SELECT * FROM `linkedin` ORDER BY id", $CON ) or die( mysql_error() ); if( mysql_num_rows( $query ) != 0 ) { $last_update = time() / 60; while( $rows = mysql_fetch_array( $query ) ) { $contacts_db = "NNJN_" . $rows['email']; // switch to the contacts db mysql_select_db( $contacts_db, $CON ); $query = mysql_query("SELECT * FROM `linkedin` WHERE token = '" . TOKEN . "'", $CON ) or die( mysql_error() ); if( mysql_num_rows( $query ) != 0 ) { mysql_query("UPDATE `linkedin` SET last_update = '{$last_update}' WHERE token = '" . TOKEN . "'", $CON ) or die( mysql_error() ); }else{ mysql_query("INSERT INTO `linkedin` (email, token, username, online, away, last_update) VALUES ('" . EMAIL . "', '" . TOKEN . "', '" . USERNAME . "', 'true', 'false', '$last_update')", $CON ) or die( mysql_error() ); } } mysql_free_result( $query ); } // switch back to your own mysql_select_db( USER_DB, $CON ); It does insert and update details from the other databases but it also inserts and edits data from the current users database which I dont want. Any ideas?

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  • Looking for a good database structure to achieve Facebook/SO like notifications

    - by user156814
    I want to be able to have notifications on my site, similar to the way SO does it. I have looked for a good table structure to do this, but I cant seem to figure it out. I was thinking something like this. Notifications id, notification_type_id, user_id, type_id Notification Types id, notification_text Where the notification type would relate to either a new post, a new comment, or whatever features I add later down the line... User Id would relate to whoever the notification is for. Type_id and notification type would go hand in hand, so if the notification_type was a new comment, the type_id would be the comment_id to go to. This seems good to me, but i want to be able to notify ALL users when something changes.. like on facebook when you comment on something, you get a notification that someone else has also commented on the same thing after you. I cant seem to figure this out... Help wanted Thanks

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  • SQLSTATE[HY093]: Invalid parameter number: mixed named and positional parameters

    - by Gremo
    Weird error and this is driving me crazy all the day. To me it seems a bug because there are no positional parameters in my query. Here is the method: public function getAll(User $user, DateTime $start = null, DateTime $end = null) { $params = array('user_id' => $user->getId()); $rsm = new \Doctrine\ORM\Query\ResultSetMapping(); // Result set mapping $rsm->addScalarResult('subtype', 'subtype'); $rsm->addScalarResult('count', 'count'); $sms_sql = "SELECT CONCAT('sms_', IF(is_auto = 0, 'user' , 'auto')) AS subtype, " . "SUM(messages_count * (customers_count + recipients_count)) AS count " . "FROM outgoing_message AS m INNER JOIN small_text_message AS s ON " . "m.id = s.id WHERE status <> 'pending' AND user_id = :user_id"; $news_sql = "SELECT CONCAT('news_', IF(is_auto = 0, 'user' , 'auto')) AS subtype, " . "SUM(customers_count + recipients_count) AS count " . "FROM outgoing_message AS m JOIN newsletter AS n ON m.id = n.id " . "WHERE status <> 'pending' AND user_id = :user_id"; if($start) : $sms_sql .= " AND sent_at >= :start"; $news_sql .= " AND sent_at >= :start"; $params['start'] = $start->format('Y-m-d'); endif; $sms_sql .= ' GROUP BY type, is_auto'; $news_sql .= ' GROUP BY type, is_auto'; return $this->_em->createNativeQuery("$sms_sql UNION ALL $news_sql", $rsm) >setParameters($params)->getResult(); } And this throws the exception: SQLSTATE[HY093]: Invalid parameter number: mixed named and positional parameters Array $arams is OK and so generated SQL: var_dump($params); array (size=2) 'user_id' => int 1 'start' => string '2012-01-01' (length=10) Strangest thing is that it works with "$sms_sql" only! Any help would make my day, thanks. Update Found another strange thing. If i change only the name (to start_date instead of start): if($start) : $sms_sql .= " AND sent_at >= :start_date"; $news_sql .= " AND sent_at >= :start_date"; $params['start_date'] = $start->format('Y-m-d'); endif; What happens is that Doctrine/PDO says: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'sent1rt_date' in 'where clause' ... as string 1rt was added in the middle of the column name! Crazy...

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  • Case insensitive duplicates SQL

    - by hdx
    So I have a users table where the user.username has many duplicates like: username and Username and useRnAme john and John and jOhn That was a bug and these three records should have been only one. I'm trying to come up with a SQL query that lists all of these cases ordered by their creation date, so ideally the result should be something like this: username jan01 useRnAme jan02 Username jan03 john feb01 John feb02 jOhn feb03 Any suggestions will be much appreciated

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  • Problem with SQL, ResultSet in java

    - by aphex
    How can I iterate ResultSet ? I've tried with the following code, but i get the error java.sql.SQLException: Illegal operation on empty result set. while ( !rs.isLast()) { rs.next(); int id = rs.getInt("person_id"); SQL.getInstance().getSt().execute("INSERT ref_person_pub(person_id) VALUES(" + id + ")"); }

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  • Non Working Relationship

    - by Dominik K.
    Hello everyone, I got a problem with cake's model architecture. I got a Users-Model and a Metas-Model. Here are the model codes: Users: <?php class User extends AppModel { var $name = 'User'; var $validate = array( 'username' => array('notempty'), 'email' => array('email'), 'password' => array('notempty') ); var $displayField = 'username'; var $hasMany = array( 'Meta' => array( 'className' => 'Meta', 'foreignKey' => 'user_id' ) ); } ?> and the Metas Model: <?php class Meta extends AppModel { var $name = 'Meta'; //The Associations below have been created with all possible keys, those that are not needed can be removed var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id', 'required' => true ) ); } ?> So now the question is why do I not get the Meta data into the User array? Should I get it in the Auth object? Or where can I work with the meta data? hope you can help me! Have a nice Day! Dom

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  • In SQL, if we rename INNER JOIN as INTERSECT JOIN, LEFT OUTER JOIN as LEFT UNION JOIN, and FULL OUTE

    - by Jian Lin
    In SQL, the name Join gives an idea of "merging" or a sense of "union", making something bigger. But in fact, as in the other post http://stackoverflow.com/questions/2706051/in-sql-a-join-is-actually-an-intersection-and-it-is-also-a-linkage-or-a-sidew it turns out that a Join (Inner Join) is actually an Intersection. So if we think of Join = Inner Join = Intersect Join Left Outer Join = Left Union Join Full Outer Join = Full Union Join = Union Join then we always get a feel of what's happening, and maybe never forget what they are easily. In a way, we can think of Intersect as "making it less", therefore it is excluding something. That's why the name "Join" won't go with the idea of "Intersect". But in fact, both Intersect and Union can be thought of as: Union: bringing something together and merge them unconditionally. Intersect: bringing something together and merge them based on some condition. so the "bringing something together" is probably what "Join" is all about. It is like, Intersection is a "half glass of water" -- we can thinking of it as "excluding something" or as "bringing something together and accepting the common ones". So if the word "Intersect Join" is used, maybe a clear picture is there, and "Union Join" can be a clear picture too. Maybe the word "Inner Join" and "Outer Join" is very clear when we use SQL a lot. Somehow, the word "Outer" tends to give a feeling that it is "outside" and excluding something rather than a "Union".

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  • Is it dangerous to keep an admin page to administer your database?

    - by Scarface
    Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

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  • Comparing two date ranges within the same table

    - by Danny Herran
    I have a table with sales per store as follows: SQL> select * from sales; ID ID_STORE DATE TOTAL ---------- -------- ---------- -------------------------------------------------- 1 1 2010-01-01 500.00 2 1 2010-01-02 185.00 3 1 2010-01-03 135.00 4 1 2009-01-01 165.00 5 1 2009-01-02 175.00 6 5 2010-01-01 130.00 7 5 2010-01-02 135.00 8 5 2010-01-03 130.00 9 6 2010-01-01 100.00 10 6 2010-01-02 12.00 11 6 2010-01-03 85.00 12 6 2009-01-01 135.00 13 6 2009-01-02 400.00 14 6 2009-01-07 21.00 15 6 2009-01-08 45.00 16 8 2009-01-09 123.00 17 8 2009-01-10 581.00 17 rows selected. What I need to do is to compare two date ranges within that table. Lets say I need to know the differences in sales between 01 Jan 2009 to 10 Jan 2009 AGAINST 01 Jan 2010 to 10 Jan 2010. I'd like to build a query that returns something like this: ID_STORE_A DATE_A TOTAL_A ID_STORE_B DATE_B TOTAL_B ---------- ---------- --------- ---------- ---------- ------------------- 1 2010-01-01 500.00 1 2009-01-01 165.00 1 2010-01-02 185.00 1 2009-01-02 175.00 1 2010-01-03 135.00 1 NULL NULL 5 2010-01-01 130.00 5 NULL NULL 5 2010-01-02 135.00 5 NULL NULL 5 2010-01-03 130.00 5 NULL NULL 6 2010-01-01 100.00 6 2009-01-01 135.00 6 2010-01-02 12.00 6 2009-01-02 400.00 6 2010-01-03 85.00 6 NULL NULL 6 NULL NULL 6 2009-01-07 21.00 6 NULL NULL 6 2009-01-08 45.00 6 NULL NULL 8 2009-01-09 123.00 6 NULL NULL 8 2009-01-10 581.00 So, even if there are no sales in one range or another, it should just fill the empty space with NULL. So far, I've come up with this quick query, but I the "dates" from sales to sales2 sometimes are different in each row: SELECT sales.*, sales2.* FROM sales LEFT JOIN sales AS sales2 ON (sales.id_store=sales2.id_store) WHERE sales.date >= '2010-01-01' AND sales.date <= '2010-01-10' AND sales2.date >= '2009-01-01' AND sales2.date <= '2009-01-10' ORDER BY sales.id_store ASC, sales.date ASC, sales2.date ASC What am I missing?

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  • Python and MySQLdb

    - by rohanbk
    I have the following query that I'm executing using a Python script (by using the MySQLdb module). conn=MySQLdb.connect (host = "localhost", user = "root",passwd = "<password>",db = "test") cursor = conn.cursor () preamble='set @radius=%s; set @o_lat=%s; set @o_lon=%s; '%(radius,latitude,longitude) query='SELECT *, 6371*1000 * acos(cos(radians(@o_lat)) * cos(radians(lat)) * cos(radians(lon) - radians(@o_lon)) + sin(radians(@o_lat)) * sin(radians(lat))) as distance FROM poi_table HAVING distance < @radius ORDER BY distance ASC LIMIT 0, 50' complete_query=preamble+query results=cursor.execute (complete_query) print results The values of radius, latitude, and longitude are not important, but they are being defined when the script executes. What bothers me is that the snippet of code above returns no results; essentially meaning that the way that the query is being executed is wonky. I executed the SQL query (including the set variables with actual values, and it returned the correct number of results). If I modify the query to just be a simple SELECT FROM query (SELECT * FROM poi_table) it returns results. What is going on here?

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  • ON DELETE RESTRICT Causing Error 150

    - by Levi Hackwith
    CREATE TABLE project ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), INDEX(name, created_at) ) ENGINE = INNODB; CREATE TABLE role ( id INTEGER NOT NULL, name VARCHAR(50) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE organization ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(100) NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE user ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, role_id INTEGER NOT NULL, organization_id INTEGER NOT NULL, last_login_at DATETIME NOT NULL, last_ip_address VARCHAR(25) NOT NULL, username VARCHAR(45) NOT NULL, password CHAR(32) NOT NULL, email_address VARCHAR(255) NOT NULL, first_name VARCHAR(45) NOT NULL, last_name VARCHAR(45) NOT NULL, address_1 VARCHAR(100) NOT NULL, address_2 VARCHAR(25) NULL, city VARCHAR(25) NOT NULL, state CHAR(2) NOT NULL, zip_code VARCHAR(10) NOT NULL, primary_phone_number VARCHAR(10) NOT NULL, secondary_phone_number VARCHAR(10) NOT NULL, is_primary_organization_contact TINYINT NOT NULL DEFAULT '0', is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), CONSTRAINT fk_user_role_id FOREIGN KEY (role_id) REFERENCES role (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_user_organization_id FOREIGN KEY (organization_id) REFERENCES organization (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE project_user ( user_id INTEGER NOT NULL, project_id INTEGER NOT NULL, PRIMARY KEY (user_id, project_id), CONSTRAINT fk_project_user_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE CASCADE, CONSTRAINT fk_project_user_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_category ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_type ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_status ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, project_id INTEGER NOT NULL, created_by INTEGER NOT NULL, submitted_by INTEGER NOT NULL, assigned_to INTEGER NULL, category_id INTEGER NOT NULL, type_id INTEGER NOT NULL, title VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, contact_type_id TINYINT NOT NULL, affects_all_clients TINYINT NOT NULL DEFAULT '0', is_billable TINYINT NOT NULL DEFAULT '1', esimated_hours DECIMAL(4, 1) NOT NULL DEFAULT '0', hours_worked DECIMAL (4, 1) NOT NULL DEFAULT '0', status_id TINYINT NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_created_by FOREIGN KEY (created_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_submitted_by FOREIGN KEY (submitted_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_assigned_to FOREIGN KEY (assigned_to) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_category_id FOREIGN KEY (category_id) REFERENCES ticket_category (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_type_id FOREIGN KEY (type_id) REFERENCES ticket_type (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_status_id FOREIGN KEY (status_id) REFERENCES ticket_status (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_time_entry ( id INTEGER NOT NULL AUTO_INCREMENT, user_id INTEGER NOT NULL, ticket_id INTEGER NOT NULL, started_at DATETIME NOT NULL, ended_at DATETIME NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_time_entry_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_time_entry_ticket_id FOREIGN KEY (ticket_id) REFERENCES ticket (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; The ticket table's create statement causes an error 150. I have no clue why. When I remove the ON DELETE RESTRICT statements from the table declaration, it works. Why is that?

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  • How do I call up values in PHP for user input in forms (radio buttons and selects)

    - by Derek
    Ok so my admin sets to edit a book which was created. I know how to bring in the values that were initially entered via a simple text field like 'bookname'. On the edit book page the book name field stores the currently assigned 'bookname' in the field (which is what I want! :) ) However I have other field types like selects and radio button entries...I'm having trouble calling in the already set value when the book was created. For example, there is a 'booklevel' field, which I have set as radio button entries as; Hard, Normal, and Easy. When the user goes to edit the book, I'm not too sure on how to have the current value drawn up (its stored as text) and the radio button being checked. I.e. 'Normal' is checked if this is what was set when the book was created. So far I have this as the code for the adding book level: <label>Book Level:</label> <label for="booklevel1" class="radio">Hard <input type="radio" name="booklevel" id="booklevel1" value="<?php echo 'Hard'; if (isset($_POST['booklevel'])); ?>"></label> <label for="booklevel2" class="radio">Medium<input type="radio" name="booklevel" id="booklevel2" value="<?php echo 'Normal'; if (isset($_POST['booklevel'])); ?>"></label> <label for="booklevel" class="radio">Low<input type="radio" name="booklevel" id="booklevel3" value="<?php echo 'Easy'; if (isset($_POST['booklevel'])); ?>"></label> This all works fine by the way when the user adds the book... But does anyone know how in my update book form, I can draw the value of what level has been set, and have the box checked?? To draw up the values in the text fields, I'm simply using: <?php echo $row['bookname']?> I also noticed a small issue when I call up the values for my Select options. I have the drop down select field display the currently set user (to read the book!), however, the drop down menu again displays the user in the list available options to select - basically meaning 2 of the same names appear in the list! Is there a way to eliminate the value of the SELECTED option? So far my setup for this is like: <select name="user_id" id="user_id"> <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['fullname']?></option> <?php while($row = mysql_fetch_array($result)) { ?> <option value="<?php echo $row['user_id']?>"><?php echo $row['name']?></option> <?php } ?> </select> If anyone can help me I'll be very greatful. Sorry for the incredibly long question!! :)

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  • Linq for java

    - by Milhous
    Would a LINQ for java be a useful tool? I have been working on a tool that will allow a java object to map to a row in a database. Would this be useful for java programmers? What features would be useful?

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  • Why can't I get a TRUE return in this prepared statement?

    - by Cortopasta
    I can't seem to get this to do anything but return false. My best guess is that the prepared statement isn't executing, but I have no idea why. private function check_credentials($plain_username, $md5_password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); $id = $userid->fetch(); Return $id; } *EDIT:*I've even tried hard coding the username and password into the function itself to try and isolate the problem like this: private function check_credentials($plain_username, $md5_password) { global $dbcon; $plain_username = "jim"; $md5_username = "waffles"; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); print_r($dbcon->errorInfo()); $id = $userid->fetch(); Return $id; } Still nothing :-/

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  • does php mysql_fetch_array works with html input box?

    - by dexter
    this is my entire PHP code: <?php if(empty($_POST['selid'])) {echo "no value selected"; } else { $con = mysql_connect("localhost","root",""); if(mysql_select_db("cdcol", $con)) { $sql= "SELECT * FROM products where Id = '$_POST[selid]'"; if($result=mysql_query($sql)) { echo "<form name=\"updaterow\" method=\"post\" action=\"dbtest.php\">"; while($row = mysql_fetch_array($result)) { echo "Id :<input type=\"text\" name=\"ppId\" value=".$row['Id']." READONLY></input></br>"; echo "Name :<input type=\"text\" name=\"pName\" value=".$row['Name']."></input></br>"; echo "Description :<input type=\"text\" name=\"pDesc\" value=".$row['Description']."></input></br>"; echo "Unit Price :<input type=\"text\" name=\"pUP\" value=".$row['UnitPrice']."></input></br>"; echo "<input type=\"hidden\" name=\"mode\" value=\"Update\"/>"; } echo "<input type=\"submit\" value=\"Update\">"; echo "</form>"; } else {echo "Query ERROR";} } } ?> PROBLEM here is, ....if the value i am getting from database using mysql_fetch_array($result) is like:(say Description is:) "my product" then; in input box it shows only "my" the word(or digit) after "SPACE"(ie blank space) doesn't get displayed? can input box like above can display the data with two or more words(separated by blank spaces)?

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  • Join Query returns empty result, unexpected result

    - by Abs
    Hello all, Can anyone explain why this query returns an empty result. SELECT * FROM (`bookmarks`) JOIN `tags` ON `tags`.`bookmark_id` = `bookmarks`.`id` WHERE `tag` = 'clean' AND `tag` = 'simple' In my bookmarks table, I have a bookmark with an id of 70 and in my tags table i have two tags 'clean' and 'simple' both that have the column bookmark_id as 70. I would of thought a result would have been returned? How can I remedy this so that I have the bookmark returned when it has a tag of 'clean' and 'simple'? Thanks all for any explanation and solution to this.

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  • Mysqli query only works on localhost, not webserver

    - by whamo
    Hello. I have changed some of my old queries to the Mysqli framework to improve performance. Everything works fine on localhost but when i upload it to the webserver it outputs nothing. After connecting I check for errors and there are none. I also checked the php modules installed and mysqli is enabled. I am certain that it creates a connection to the database as no errors are displayed. (when i changed the database name string it gave the error) There is no output from the query on the webserver, which looks like this: $mysqli = new mysqli("server", "user", "password"); if (mysqli_connect_errno()) { printf("Can't connect Errorcode: %s\n", mysqli_connect_error()); exit; } // Query used $query = "SELECT name FROM users WHERE id = ?"; if ($stmt = $mysqli->prepare("$query")) { // Specify parameters to replace '?' $stmt->bind_param("d", $id); $stmt->execute(); // bind variables to prepared statement $stmt->bind_result($_userName); while ($stmt->fetch()) { echo $_userName; } $stmt-close(); } } //close connection $mysqli-close(); As I said this code works perfectly on my localserver just not online. Checked the error logs and there is nothing so everything points to a good connection. All the tables exists as well etc. Anyone any ideas because this one has me stuck! Also, if i get this working, will all my other queries still work? Or will i need to make them use the mysqli framework as well? Thanks in advance.

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  • PHP Variable with Array

    - by Crays
    Hi guys, i'm trying to make a "update user's power" page. It is something similar to those you can find in say, invisionfree forums. I need it to generate a list of members with checkbox [done] Add an option for it [done] What i don't know how to do is to update, to say, give all the selected users the selected power. Then i went searching for something and found most of them uses array to do this, but i never found one that actually explains how it works. The example i took (with my own modification) was this: while($row = mysql_fetch_array($result)) { echo '<tr>'.$id[]=$rows['id'].''; echo '<td width="50px" align="center" class="TableFormCell"><input type="checkbox" name="option[]" /></td>'; echo '<td width="170px" align="center" class="TableFormCell">'.$row['uname'].'</td>'; echo '</tr>'; } I'm not sure what exactly $id[]=$rows['id'] does I know after the row, my option[] would become an array of option[1], option[2], option[3] for what power should be given, i've got no problem with that but on how to update the database i'm got no clue... for($i=0;$i<$count;$i++){ $sql1="UPDATE ninos SET power='$power' WHERE id='$option[$i]'"; $result1=mysql_query($sql1); } So Say i have 5 users, Aye, Bee, Cee, Dee, Eee with IDs of 1,2,3,4,5 how can i make it so that my script would run like $sql1="UPDATE ninos SET power = '$power' Where id='1','2','3','4','5'"; Please help, thanks.

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  • SubSonic: MySqlDataReader closes connection.

    - by SchlaWiener
    I am using SubSonic 2.1 and entcountered a problem while executing a Transaction with SharedDbConnectionScope and TransactionScope. The problem is that in the obj.Save() method I get an "The connection must be valid and open" exception I tracked down the problem to this line: // Loads a SubSonic ActiveRecord object User user = new User(User.Columns.Username, "John Doe"); in this Constructor of the User class a method "LoadParam" is called which eventually does if (rdr != null) rdr.Close(); It looks like the rdr.Close() implicitly closes my connection which is fine when using the AutomaticConnection. But during a transaction it is usally not a good idea to close the connection :-) My Question is if this is by design or if it's an error in the MySqlDataReader.

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  • Add information through a stored procedure and PHP?

    - by theband
    I have a form which contains a lot of elements, my DB guy has generated an SP and now i need to call that stored procedure. My form has twenty elements, when i click on submit the data must be saved in database. I know how to do this on insert query, but how to call an SP and perform this operation.

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  • How do I delete a foreign key in SQLAlchemy?

    - by Travis
    I'm using SQLAlchemy Migrate to keep track of database changes and I'm running into an issue with removing a foreign key. I have two tables, t_new is a new table, and t_exists is an existing table. I need to add t_new, then add a foreign key to t_exists. Then I need to be able to reverse the operation (which is where I'm having trouble). t_new = sa.Table("new", meta.metadata, sa.Column("new_id", sa.types.Integer, primary_key=True) ) t_exists = sa.Table("exists", meta.metadata, sa.Column("exists_id", sa.types.Integer, primary_key=True), sa.Column( "new_id", sa.types.Integer, sa.ForeignKey("new.new_id", onupdate="CASCADE", ondelete="CASCADE"), nullable=False ) ) This works fine: t_new.create() t_exists.c.new_id.create() But this does not: t_exists.c.new_id.drop() t_new.drop() Trying to drop the foreign key column gives an error: 1025, "Error on rename of '.\my_db_name\#sql-1b0_2e6' to '.\my_db_name\exists' (errno: 150)" If I do this with raw SQL, i can remove the foreign key manually then remove the column, but I haven't been able to figure out how to remove the foreign key with SQLAlchemy? How can I remove the foreign key, and then the column?

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  • How to design tag database structure?

    - by liuxingruo
    I have a subjects database, and I want to create a new tag database to tag the subjects, but I have no idea how to design the new tag database structure. I'm assuming the new database looks like this: tag_id tag_name tagged_subject_ids 1 tag1 1, 2, 3, 5, 10 2 tag2 2, 4, 5, 6, 10, 12 so, if I want to select the tags belong to subject 1: SELECT tag_name FROM tag_database WHERE tagged_subject_ids LIKE '1'; I think the way that I select tag may be very slow, so please help me. Thanks!

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  • HTML anchor too pull all Sticky Posts ?

    - by Gnee
    Is there a way to format an tag to send a query, pull all Sticky Posts, and loop through them? Since 'sticky' is not a category, I cant format the link in the normal : http://mysite.com/category/cars I'm thinking is probably going to have to be some kind of url query string sent in as GET.

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