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  • PHP readdir(): 3 is not a valid Directory resource

    - by Jordan
    <?php function convert(){ //enable error reporting for debugging error_reporting(E_ALL | E_STRICT); //convert pdf's to html using payroll.sh script and //pdftohtml command line tool $program = "payroll.sh"; $toexec="sh /var/www/html/tmp/" . $program . " 2>&1"; $exec=shell_exec($toexec); //display message from payroll.sh //echo $exec; //echo ('<br/>'); } function process(){ $dir = '/var/www/html/tmp/converted'; //echo ('one'); if (is_dir($dir)) { //echo ('two'); if ($dh = opendir($dir)) { //echo ('three'); while (($file = readdir($dh)) !== false) { //echo ('four'); if ($file != "." && $file != ".."){ echo 'opening file: '; echo $file; echo ("<br/>"); $fp = fopen('/var/www/html/tmp/converted/' . $file, 'r+'); $count = 0; //while file is not at the EOF marker while (!feof($fp)) { $line = fgets($fp); if($count==21) { $employeeID = substr($line,71,4); echo 'employee ID: '; echo $employeeID; echo ('<br/>'); //echo ('six'); $count++; } else if($count==30) { $employeeDate = substr($line,71,10); echo 'employee Date: '; echo $employeeDate; echo ('<br/>'); //echo ('seven'); $count++; } else { //echo ('eight'); //echo ('<br/>'); $count++; } } fclose($fp); closedir($dh); } } } } } convert(); process(); ?> I am setting up a php script that will take a paystub in pdf format, convert it to html, then import it into Drupal after getting the date and employee ID. The code only seems to process the first file in the directory then it gives me this: opening file: dd00000112_28_2010142011-1.html employee ID: 9871 employee Date: 12/31/2010 Warning: readdir(): 3 is not a valid Directory resource in /var/www/html/pay.mistequaygroup.com/payroll.php on line 29 The '3' in the error really confuses me, and google is not helping much. Could it be the 3rd iteration of the loop? The only files in the directory reddir() is scanning are the .html files waiting to be processed. Any ideas? Also, how does my code look? I'm fairly new to doing any real programming and I don't get too much input around work.

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  • Switching to FormViewMode.Edit is very slow

    - by Tim
    When i switch an ASP.Net Formview from readonly mode to edit mode it takes more than 6 seconds(from edit to readonly takes a split second). I have no idea whats the reason for it. The EditItemTemplate contains a lot of controls(table,textboxes,dropdownlists) but in fact not more than the ItemTemplate has. Yet i have even commented out the complete FormView.DataBound where the controls are data bounded but without significant change. My ASP.Net Web Apllication is using Ajax and the Formview is completely nested in an UpdatePanel. Any suggestions or assumptions for this behaviour?

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  • PHP and Javascript: Getting file contents with Javascript variable

    - by celliott1997
    Could someone help me to understand why this isn't working? var uname = "<?php echo strtolower($_GET['un']) ?>"; var source = "<?php echo file_get_contents('accounts/"+uname+"') ?>"; console.log(source); I've been trying for a while to get this working and it just doesn't seem to. Before I added in the source variable, it was working fine and displayed the un variable on the page. Thanks.

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  • viewing data using php and mysql

    - by circle
    hello, i'm circle.very new in php and mysql.i need to develop a website include with database.but i have a problem with this. i'm using php and sql to develop it.my task is: i have two table, investor and commission. investor have three level which is coordinator, consultant and participant.what should i do is, only coordinator can add consultant and participant in their profile.and only coordinator can add participant in their profile. so here, when investor was login, and they go to view commission, they only can see their owned coordinator and participant. but i'm stuck when they want to view the commission.maybe it only a simple thing, but i cannot solved it. help me..:(

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  • PHP troubleshooting unexpected T_PUBLIC error

    - by jasondavis
    PHP is driving me insane right now, please help me, I must be missing something. In this VERY BASIC example below I get this error... Parse error:syntax error, unexpected T_PUBLIC in C:\filename here on line 12 On this line.... public static function getInstance(){ The code... <?PHP class Session{ private static $instance; function __construct() { { session_start(); echo 'Session object created<BR><BR>'; } public static function getInstance(){ if (!self::$instance) { self::$instance = new Session(); } return self::$instance; } }

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  • Not Inserted into database in PHP script

    - by Aruna
    Hi, i am having an form for uploading an excel file like <form enctype="multipart/form-data" action="http://localhost/joomla/Joomla_1.5.7/index.php?option=com_jumi&fileid=7" method="POST"> Please choose a file: <input name="file" type="file" id="file" /><br /> <input type="submit" value="Upload" /> </form> And in the FIle http://localhost/joomla/Joomla_1.5.7/index.php?option=com_jumi&fileid=7 i have retrived the uploaded file contents by <?php echo "Name". $_FILES['file']['name'] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Stored in: " . $_FILES["file"]["tmp_name"] . "<br />"; $string = file_get_contents( $_FILES["file"]["tmp_name"] ); foreach ( explode( "\n", $string ) as $userString ) { $userString = trim( $userString ); echo $userString; $array = explode( ';', $userString ); $userdata = array ( 'cf_id'=>trim( $array[0] ), 'text_0'=>trim( $array[1] ), 'text_1'=>trim( $array[2] ), 'text_2'=>trim( $array[3] ), 'text_3'=>trim($array[4]), 'text_6'=>trim($array[5]), 'text_7'=>trim($array[6]), 'text_9'=>trim($array[7]), 'text_12'=>trim($array[8])); global $db; $db =& JFactory::getDBO(); $query = 'INSERT INTO #__chronoforms_UploadAuthor VALUES ("'.$userdata['cf_id'].'","'.$userdata['text_0'].'","'.$userdata['text_1'].'","'.$userdata['text_2'].'","'.$userdata['text_3'].'","'.$userdata['text_6'].'","'.$userdata['text_7'].'","'.$userdata['text_9'].'")'; $db->Execute($query); echo "<br>"; } i am trying to insert the contents into the table #__chronoforms_UploadAuthor in Joomla database . it doent shows any error but it is not inserted into the database.. Please help me.. Y the contents are not inserted into the database...And how to make it inserted into the database..

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Help with PHP and associative arrays

    - by errata
    Hello. I have to do a simple calculator in php based on user's input and choice from select field, something like this: <?php $a = $_GET['a']; $b = $_GET['b']; $array = array( "option1" => 0.1, "option2" => 0.15, "option3" => 0.3, "option4" => 3, "option5" => 3, "option6" => 16, "option7" => 16, "option8" => 16 ); echo "<form action='calc.php' method='get'>"; echo "<input type='text' name='a' value='".$a."'> of "; echo "<select name='b'>"; foreach ($array as $k => $v) { echo "<option value='".$v."'>".$k."</option>"; } echo "</select> "; echo "<input type='submit' value='='> "; $total_volume = $a * $b; echo $total_volume; echo "</form>"; ?> Well, for now everything works fine, but the idea is that after user submits form, the page reloads with sent amount in input field and selected option which user actually selected... First thing is easy: I just put value="a" in my input field, but I'm not sure how to make a selected option in <select> field??? I started with this: foreach ($array as $k => $v) { echo "<option value='".$v."'"; if ($b == $v) { echo " selected "; } echo ">".$k."</option>"; } ...but this is obviously not working as expected... Please help me with this easy one :) Thanks!

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  • Adding links to this PHP statement

    - by poindexter
    Here is a PHP statement that basically sets off a javascript image slider. Only problem is I can't figure out how to get each individual image to a link to a different page. Any tips or suggestions? I appreciate it! <?php jsbrotate('height=316&width=924&imgdisp=4&imgfade=2&images=/wp-content/uploads/image_1_linked.png|/wp-content/uploads/image_2.png|/wp-content/uploads/image_3.png|/wp-content/uploads/image_4.png|/wp-content/uploads/image_5.png'); ?>

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  • Populate javascript array with PHP array of Variables

    - by user1704514
    The following code is used to populate a pie chart in javascript: <script type="text/javascript"> var agg = { label: 'Aggressive', pct: [60, 10, 6, 30, 14, 10] }, bal = { label: 'Balanced', pct: [24, 7, 2, 18, 13, 36] }, mod = { label: 'Moderate', pct: [12, 4, 2, 10, 11, 61] }, inc = { label: 'Income', pct: [ 0, 0, 0, 0, 0,100] }, </script> Instead of tm: [40, 60, 67, 30, 74, 50] as seen above, I would like to make each of 6 values a php variable. Like: tm: [$r1, $r2, $r3, $r4, $r5, $r6] . How do I do this? How do I do this with? A php array or json encode?

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  • Any valid use of goto in PHP?

    - by nikic
    I know, there are other questions about the goto statement introduced in PHP 5.3. But I couldn't find any decent answer in there, all were of the type "last resort", "xkcd", "evil", "bad", "EVIL!!!". But no valid example. Only statements that there aren't any uses. Or statements that there are some rare use cases (again, without examples). So, the question is: "Which are the valid uses of goto in PHP". Answers for "Is goto evil" are not welcome and will get downvoted. Thanks :) Or does somebody have a link to an RFC where the decision is explained - I couldn't find one.

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  • retrieved upload images in php

    - by hunter
    i want to retrieve image from client (ipod) programmed in objective c i use the following code $TARGET_PATH = "pics/"; $image = $_FILES['photo']; $TARGET_PATH =$TARGET_PATH . basename( $_FILES['photo']['name']); $TARGET_PATH =$TARGET_PATH.".jpg"; if(file_exists($TARGET_PATH)) { $TARGET_PATH =$TARGET_PATH .uniqid() . ".jpg"; } if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { $TARGET_PATH="http://www.".$_SERVER["SERVER_NAME"]."/abc/".$TARGET_PATH; echo $TARGET_PATH; echo "image upload successfully";} else{ echo "could not upload image"; } this code upload five to six images successfully and after that it gives me error i.e Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 42 Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 53 could not upload image

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  • php's strip_tags() won't work

    - by Maxime ARNSTAMM
    Hello everyone I'm trying to tweak a tiny bit a wordpress, but i am level 0 in php, so i kinda suck :/ I want to add a custom 'tweet this' button (i know there already is a gazillion of them, i just wanted to do it on my own, for fun) So, i'm trying this : <a href="http://twitter.com/home?status=<?php strip_tags(the_excerpt()) ?>" >tweet this</a> the_excerpt() returns "<p> ... excerpt ... </p>" and the strip_tags function does not strip those <p> tags ! What do i do wrong ? Thanks, and sorry if it is obvious.

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  • Is a server side script necessary to process a form?

    - by jitendra
    Is a server side script necessary to send a form to email? For example, suppose I want to submit this form. Is it only possible with php asp.net etc. or it can be done with javascript only? <HTML> <HEAD> <TITLE>HTML form tutorial example</TITLE> </HEAD> <BODY> <H1>HTML form tutorial example</H1> <FORM> Name: <INPUT TYPE="TEXT" NAME="Name" VALUE="" SIZE="25" MAXLENGTH="50"> <BR> Email: <INPUT TYPE="TEXT" NAME="Email" VALUE="" SIZE="25" MAXLENGTH="50"><BR> <INPUT TYPE="SUBMIT" NAME="submit" VALUE="Sign Me Up!"> </FORM> </BODY> </HTML>

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  • Please help me understand this PHP script.Noob here

    - by NissGTR
    I'm learning PHP,MySQL and came across this function today function get_director($director_id) { global $db; $query = 'SELECT people_fullname FROM people WHERE people_id = ' . $director_id; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); extract($row); return $people_fullname; } I understand what functions are and I've created a few while learning PHP.But this one is a bit more complicated.I can't understand the WHERE people_id = ' . $director_id I'm new to MySQL.I guess the single quote ends the MySQL statement?And then it is concatenated with the argument? Please help me out.

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  • Passing a String from PHP to a JavaScript function

    - by user635614
    Hello. am trying to write a code to pass a php string when clicked on the table : <?php . . . echo("<td onclick = 'print_("$file[$i]->Name");' >". $files[$i]->Name."</td>"); ... ?> where files[] is an array, and each element is a class with Name as a String, and it is put in a ''for'' loop, Am trying to pass it to a JavaScript function where i need the name there,and it's not working,i tried passing the i variable and it was passed correctly so i thought there should be a special syntax for dealing with strings... function print_(var x) { alert(x);}

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  • Using PHP interfaces in Codeigniter

    - by John Stewart
    I am trying to find out how can I used PHP interfaces in my MVC design. I want to make sure that the design enforces an interface so that any new module would follow that. For example: <?php interface BaseAPI { public function postMessage($msg); } class ServiceAPI implements BaseAPI { public function postMessage($msg) { return $msg; } } class Service_Two_API implements BaseAPI { public function postMessage($msg) { return "can't do this: ".$msg; } } ?> I want to do this in CI. Is it possible? how should I design it?

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