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  • XML url link in Flash

    - by Vickyboy
    Hi, I am new to XML and am having a small problem in Flash. I have a number of buttons. Each of these buttons need to open up a different URL which is in a xml file (I have added only one button for now (banstead), as I wasn´t sure how to add more). My XML: <?xml version="1.0" encoding="utf-8"?> <banstead targ="_self" href="http://www.marca.com"> </banstead> My AS: weblinkXML = new XML(); weblinkXML.ignoreWhite = true; weblinkXML.load("xml/counties.xml"); weblinkXML.onLoad = function (success) { var url = weblinkXML.firstChild.attributes.href; banstead.onRelease = function () { getURL(weblinkXML.url); } } For some reason when I test the movie and click on the button it doesn´t open the URL I requested. Appreciate any help

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  • Emacs: annoying Flymake dialog box.

    - by baol
    Hello I have the following lines in my ~/.emacs.d/init.el (custom-set-variables '(flymake-allowed-file-name-masks (quote ( ("\\.cc\\'" flymake-simple-make-init) ("\\.cpp\\'" flymake-simple-make-init))))) (add-hook 'find-file-hook 'flymake-find-file-hook) When I open a cc/cpp file that has a Makefile with the following content in the same folder I get proper on-the-fly compilation and error reporting (Flymake will check the syntax and report errors and warnings during code editing) .PHONY: check-syntax check-syntax: $(CXX) -Wall -Wextra -pedantic -fsyntax-only $(CHK_SOURCES) The problem is that when I open a .cc file that has no corresponding Makefile i get an annoying dialog box that warns me about flymake being disabled for every file opened. Is there some hook I can use to disable that warning? Can you provide sample elisp code and explanation on how you found the proper hook?

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  • Inline & not-inline

    - by anon
    Suppose I have: struct Vec3 { double x; double y; double z; } ; inline double dot(const Vec3& lhs, const Vec3& rhs) { return lhs.x * rhs.x + lhs.y * rhs.y + lhs.z * rhs.z ; } Is it possible to have "dot" also exist in a non-inlined version, so that it can be in the *.so , so that when I dl open it I can call it? I.e. I want files that include the above header to use the inlined version, but I also want the function to exist in a *.so, so I can dl open it and call it dynamically.

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  • Spry Collapsible Panel within Collapsible Panel, inconsistent errors.

    - by Robin I Knight
    Hello everyone it is me again with another question. The booking system located here http://www.divethegap.com/scuba-diving-programmes-dive-the-gap/divemaster-training.php?cat=16 There are 3 main collapsible panels controlled by the spry framework. There are then over a dozen more inside the first collapsible panel as you can see on that page. When you open one of those by pressing one of the 'learn more' buttons you will see that the main collapsible panel that it is in also expands to fit that content and the contracts if you close the smaller panel again. However as soon as you go to the next main collapsible panel 'summery and quote' and then go back to the first main panel by pressing the button that says 'back' there are problems. Now if you open up one of the smaller panels inside the first main panel you will see that the main panel does not expand to fit the contents and in fact the content of the smaller panels spreads over the other content, floating above it. Does anybody know how to fix this? Many Thanks,

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  • How to fix weird scrolling/alignment behavior when using keyboard in MenuStrip?

    - by bentsai
    I started noticing strange behavior when navigating the main toolbar of my Winforms application, and I don't know how to fix it. When I initially open the dropdown of the File menu, it looks like this: I begin to scroll down each item with the arrow keys, and everything is fine until I reach "Exit". As soon as I hit the down arrow key from "Log Off", or if I hit the up arrow key from "Open", the menu rearranges itself to look like this: I'm puzzled by this behavior. The menu still works, and from this point, if I start scrolling up, I can get the arrangement back to normal: A few observations: The menu still works. This doesn't happen when using the mouse. I have some code that toggles the Visible property of some of the menu items. I was able to modify what the arrangement was by playing around with this, but it was still messed up. Can anyone help me understand what is going on, and how to fix it?

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  • Resetting or refreshing a database connection

    - by cdonner
    This Android application on Google uses the following method to refresh the database after replacing the database file with a backup: public void resetDbConnection() { this.cleanup(); this.db = SQLiteDatabase.openDatabase( "/data/data/com.totsp.bookworm/databases/bookworm.db", null, SQLiteDatabase.OPEN_READWRITE); } I did not build this app, and I am not sure what happens. I am trying to make this idea work in my own application, but the data appears to be cached by the views, and the app continues to show data from the database that was replaced, even after I call cleanup() and reopen the database. I have to terminate and restart the activity in order to see the new data. I tried to call invalidate on my TabHost view, which pretty much contains everything. I thought that the views would redraw and refresh their underlying data, but this did also not have the expected result. I ended up restarting the activity programmatically, which works, but this seems to be a drastic measure. Is there a better way?

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  • Errno socket error in python

    - by Emma
    i wrote this code : import random import sys import urllib openfile = open(sys.argv[1]).readlines() c = random.choice(openfile) i = 0 while i < 5: i=i+1 c = random.choice(openfile) proxies = {'http': c} opener = urllib.FancyURLopener(proxies).open("http://whatismyip.com.au/").read() ::: I put 3 proxy in a txt file . : http://211.161.159.74:8080 http://119.70.40.101:8080 http://124.42.10.119:8080 but when execute it i get this error : IOError: [Errno socket error] (10054, 'Connection reset by peer') what am i going to do ? please help me .

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  • How to get full control of umask/PAM/permissions?

    - by plua
    OUR SITUATION Several people from our company log in to a server and upload files. They all need to be able to upload and overwrite the same files. They have different usernames, but are all part of the same group. However, this is an internet server, so the "other" users should have (in general) just read-only access. So what I want to have is these standard permissions: files: 664 directories: 771 My goal is that all users do not need to worry about permissions. The server should be configured in such a way that these permissions apply to all files and directories, newly created, copied, or over-written. Only when we need some special permissions we'd manually change this. We upload files to the server by SFTP-ing in Nautilus, by mounting the server using sshfs and accessing it in Nautilus as if it were a local folder, and by SCP-ing in the command line. That basically covers our situation and what we aim to do. Now, I have read many things about the beautiful umask functionality. From what I understand umask (together with PAM) should allow me to do exactly what I want: set standard permissions for new files and directories. However, after many many hours of reading and trial-and-error, I still do not get this to work. I get many unexpected results. I really like to get a solid grasp of umask and have many question unanswered. I will post these questions below, together with my findings and an explanation of my trials that led to these questions. Given that many things appear to go wrong, I think that I am doing several things wrong. So therefore, there are many questions. NOTE: I am using Ubuntu 9.10 and therefore can not change the sshd_config to set the umask for the SFTP server. Installed SSH OpenSSH_5.1p1 Debian-6ubuntu2 < required OpenSSH 5.4p1. So here go the questions. 1. DO I NEED TO RESTART FOR PAM CHANGS TO TAKE EFFECT? Let's start with this. There were so many files involved and I was unable to figure out what does and what does not affect things, also because I did not know whether or not I have to restart the whole system for PAM changes to take effect. I did do so after not seeing the expected results, but is this really necessary? Or can I just log out from the server and log back in, and should new PAM policies be effective? Or is there some 'PAM' program to reload? 2. IS THERE ONE SINGLE FILE TO CHANGE THAT AFFECTS ALL USERS FOR ALL SESSIONS? So I ended up changing MANY files, as I read MANY different things. I ended up setting the umask in the following files: ~/.profile -> umask=0002 ~/.bashrc -> umask=0002 /etc/profile -> umask=0002 /etc/pam.d/common-session -> umask=0002 /etc/pam.d/sshd -> umask=0002 /etc/pam.d/login -> umask=0002 I want this change to apply to all users, so some sort of system-wide change would be best. Can it be achieved? 3. AFTER ALL, THIS UMASK THING, DOES IT WORK? So after changing umask to 0002 at every possible place, I run tests. ------------SCP----------- TEST 1: scp testfile (which has 777 permissions for testing purposes) server:/home/ testfile 100% 4 0.0KB/s 00:00 Let's check permissions: user@server:/home$ ls -l total 4 -rwx--x--x 1 user uploaders 4 2011-02-05 17:59 testfile (711) ---------SSH------------ TEST 2: ssh server user@server:/home$ touch anotherfile user@server:/home$ ls -l total 4 -rw-rw-r-- 1 user uploaders 0 2011-02-05 18:03 anotherfile (664) --------SFTP----------- Nautilus: sftp://server/home/ Copy and paste newfile from client to server (777 on client) TEST 3: user@server:/home$ ls -l total 4 -rwxrwxrwx 1 user uploaders 3 2011-02-05 18:05 newfile (777) Create a new file through Nautilus. Check file permissions in terminal: TEST 4: user@server:/home$ ls -l total 4 -rw------- 1 user uploaders 0 2011-02-05 18:06 newfile (600) I mean... WHAT just happened here?! We should get 644 every single time. Instead I get 711, 777, 600, and then once 644. And the 644 is only achieved when creating a new, blank file through SSH, which is the least probable scenario. So I am asking, does umask/pam work after all? 4. SO WHAT DOES IT MEAN TO UMASK SSHFS? Sometimes we mount a server locally, using sshfs. Very useful. But again, we have permissions issues. Here is how we mount: sshfs -o idmap=user -o umask=0113 user@server:/home/ /mnt NOTE: we use umask = 113 because apparently, sshfs starts from 777 instead of 666, so with 113 we get 664 which is the desired file permission. But what now happens is that we see all files and directories as if they are 664. We browse in Nautilus to /mnt and: Right click - New File (newfile) --- TEST 5 Right click - New Folder (newfolder) --- TEST 6 Copy and paste a 777 file from our local client --- TEST 7 So let's check on the command line: user@client:/mnt$ ls -l total 8 -rw-rw-r-- 1 user 1007 3 Feb 5 18:05 copyfile (664) -rw-rw-r-- 1 user 1007 0 Feb 5 18:15 newfile (664) drw-rw-r-- 1 user 1007 4096 Feb 5 18:15 newfolder (664) But hey, let's check this same folder on the server-side: user@server:/home$ ls -l total 8 -rwxrwxrwx 1 user uploaders 3 2011-02-05 18:05 copyfile (777) -rw------- 1 user uploaders 0 2011-02-05 18:15 newfile (600) drwx--x--x 2 user uploaders 4096 2011-02-05 18:15 newfolder (711) What?! The REAL file permissions are very different from what we see in Nautilus. So does this umask on sshfs just create a 'filter' that shows unreal file permissions? And I tried to open a file from another user but the same group that had real 600 permissions but 644 'fake' permissions, and I could still not read this, so what good is this filter?? 5. UMASK IS ALL ABOUT FILES. BUT WHAT ABOUT DIRECTORIES? From my tests I can see that the umask that is being applied also somehow influences the directory permissions. However, I want my files to be 664 (002) and my directories to be 771 (006). So is it possible to have a different umask for directories? 6. PERHAPS UMASK/PAM IS REALLY COOL, BUT UBUNTU IS JUST BUGGY? On the one hand, I have read topics of people that have had success with PAM/UMASK and Ubuntu. On the other hand, I have found many older and newer bugs regarding umask/PAM/fuse on Ubuntu: https://bugs.launchpad.net/ubuntu/+source/gdm/+bug/241198 https://bugs.launchpad.net/ubuntu/+source/fuse/+bug/239792 https://bugs.launchpad.net/ubuntu/+source/pam/+bug/253096 https://bugs.launchpad.net/ubuntu/+source/sudo/+bug/549172 http://bugs.debian.org/cgi-bin/bugreport.cgi?bug=314796 So I do not know what to believe anymore. Should I just give up? Would ACL solve all my problems? Or do I have again problems using Ubuntu? One word of caution with backups using tar. Red Hat /Centos distributions support acls in the tar program but Ubuntu does not support acls when backing up. This means that all acls will be lost when you create a backup. I am very willing to upgrade to Ubuntu 10.04 if that would solve my problems too, but first I want to understand what is happening.

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  • How can I find which process has opened a specific file?

    - by Hosam Aly
    How can I find which processes have a specific file opened, and their open, access and share modes? Additionally, is it possible to change these values for a process? Or is it even possible to open a file for reading if it is already opened for exclusive access by another process? Please note that I don't want to invalidate the handle of the process having the file opened. I just want to be able to access the file (if possible). (I'm mainly asking about Windows, but solutions for other platforms are welcome, since they contribute to the community's knowledge.) Edit: I found some answers for my first question here and there. Edit 2: Thanks everybody for the tools you mentioned, but I am mainly looking for programmatical techniques (e.g. using Win32 APIs).

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  • Ensure a new session every time the user connects to a Servlet

    - by Daziplqa
    Hi, I've a JSP/Servlet Web App that consist of more than one servlet (and some JSPs) I need to create an new HttpSession whenever the users access servlet A, knowing that, servlet A is the home page (i.e. he access it as the first servlet/page in the application) so far so good, I can write the following code at the start of the servlet A: HttpSession session = request.getSession(false); if (session == null) { logger.debug("starting new session..."); session = request.getSession(); // other staff here } But the problem is, if the user didn't close his browser (even if he closes the tab - in firefox for instance - the session will still be open), so when he try to open my site again, the last session will be re-used (in the rage of session timeout ofcourse), and this I don't need. I need whenever he access Servlet A, he got created a brand new HttpSession. but unfortunately, he may access this servlet twice per session based on some scenario!! Please help.

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  • Writing JSON with XSLT

    - by JP
    Hi, I'm trying to write XSLT to transform a specific web page to JSON. The following code demonstrates how Ruby would do this conversion, but the XSLT doesn't generate valid JSON (there's one too many commas inside the array) - anyone know how to write XSLT to generate valid JSON? require 'rubygems' require 'nokogiri' require 'open-uri' doc = Nokogiri::HTML(open('http://bbc.co.uk/radio1/playlist')) xslt = Nokogiri::XSLT(DATA.read) puts out = xslt.transform(doc) # Now follows the XSLT __END__ <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml"> <xsl:output method="text" encoding="UTF-8" media-type="text/plain"/> <xsl:template match="/"> [ <xsl:for-each select="//*[@id='playlist_a']//div[@class='artists_and_songs']//ul[@class='clearme']"> {'artist':'<xsl:value-of select="li[@class='artist']" />','track':'<xsl:value-of select="li[@class='song']" />'}, </xsl:for-each> ] </xsl:template> </xsl:stylesheet>

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  • RuntimeException: Could not start Selenium session: Internal Server Error

    - by user79685
    I am trying to detect a midair collision problem (simultaneous editin) using selenium. So I start a selenium session A with following (Super Class) selenium = new MASSelenium(serverHost, serverPort, *iexplore, browserURL); selenium.start(); selenium.open("index.cgi"); then I try starting a different selenium session B pointing to a different browser from the superclass (Sub Class): selenium2 = new MASSelenium(getServerHost(), getServerPort(), *firefox, getBrowserURL()); selenium2.start(); selenium2.open("index.cgi"); It works fine on my local machine (behaves as expected) but then when i run this same test on a remote machine (using bamboo build tool), i get this exception: java.lang.RuntimeException: Could not start Selenium session: Internal Server Error at com.thoughtworks.selenium.DefaultSelenium.start(DefaultSelenium.java:89) at gov.baba.arc.mas.selenium.tests.SimultaneousEditingConflictDetected.setUp(SimultaneousEditingConflictDetected.java:78) Caused by: com.thoughtworks.selenium.SeleniumException: Internal Server Error at com.thoughtworks.selenium.HttpCommandProcessor.throwAssertionFailureExceptionOrError(HttpCommandProcessor.java:97) at com.thoughtworks.selenium.HttpCommandProcessor.getCommandResponseAsString(HttpCommandProcessor.java:168) at com.thoughtworks.selenium.HttpCommandProcessor.executeCommandOnServlet(HttpCommandProcessor.java:104) at com.thoughtworks.selenium.HttpCommandProcessor.doCommand(HttpCommandProcessor.java:86) Any idea why this is happening?

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  • SSIS For Each File Loop and File System Task to copy Files

    - by Marlon
    I'm using a files system task inside a for each loop container, just as described here: link text However, when I execute the package I get this error: [File System Task] Error: An error occurred with the following error message: "The process cannot access the file 'C:\Book1.xlsx' because it is being used by another process.". I do not have the file open, and I assume no one else does, as I am able to copy, and open, and overwrite the file. Any suggestions would be appreciated. If you want an example package plz let me know.

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  • Release another user's lock obtained with sp_getapplock on SQL Server

    - by joshperry
    We have a system that uses sp_getapplock to create an exclusive mutex any time someone opens an order in the GUI. This is used to prevent multiple people from making changes to an order simultaneously. Sometimes people will open an order and go home, leaving it open. This effectively blocks anyone from being able to make changes to the order. I then get emails, calls and end up doing a kill <spid> in enterprise manager. Obviously I've gotten sick of this and want to make a quick self-service webform. The main problem I've run into is that kill requires sysadmin privileges, which I do not want to give to the user that the our website runs as. I have tried sp_releaseapplock but this doesn't let you release another user's lock (even when calling it as a sysadmin). So, finally my question; does anyone know of an alternative method to release a lock that was obtained by another user using sp_getapplock?

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  • Need PHP script to decompress and loop through zipped file.

    - by Jim H.
    I am using a fairly straight-forward script to open and parse several xml files that are gzipped. I also need to do the same basic operation with a ZIP file. It seems like it should be simple, but I haven't been able to find what looked like equivalent code anywhere. Here is the simple version of what I am already doing: $import_file = "source.gz"; $sfp = gzopen($import_file, "rb"); ///// OPEN GZIPPED data while ($string = gzread($sfp, 4096)) { //Loop through the data /// Parse Output And Do Stuff with $string } gzclose($sfp); What would do the same thing for a zipped file?

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  • kill -9 + disable messages (standart output) from kill command

    - by yael
    hi all I write the following script this script enable timeout of 20 second if grep not find the relevant string in the file the script working well but the output from the script is like that: ./test: line 11: 30039: Killed how to disable this message from the kill command? how to tell kill command to ignore if process not exist? THX Yael !/bin/ksh ( sleep 20 ; [[ ! -z ps -ef | grep "qsRw -m1" | awk '{print $2}' ]] && kill -9 2/dev/null ps -ef | grep "qsRw -m1" | awk '{print $2}' ; sleep 1 ) & RESULT=$! print "the proccess:"$RESULT grep -qsRw -m1 "monitohhhhhhhr" /var if [[ $? -ne 0 ]] then print "kill "$RESULT kill -9 $RESULT fi print "ENDED" ./test the proccess:30038 ./test: line 11: 30039: Killed kill 3003

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  • ASP.NET Windows Authentication

    - by Jason M
    Hi All I have an ASP.NET website set up using Windows authentication. Each time I open IE and try to access the webpage I get a windows authentication screen. Once I have logged in I can see the website fine. My problem is that every time I open a new IE browser I have to re-enter my username and password. I have heard about thew double hop issue, is this what it could be. If so how many ip fix this. Any ideas how i can stop this box showing up each time? I have ticked the "remember my username/password" tick box but still no joy. I am using Windows Server 2003, IIS 6.0 and .NET 4.0. Thanks JM

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  • python coockie,request another page

    - by polovinamozga
    #!/usr/bin/python # -*- coding: utf-8 -*- import urllib2 import urllib import httplib import Cookie import cookielib Login = 'user' Password = 'password' Domain = 'inbox.ru' Auth = 'https://auth.mail.ru/cgi-bin/auth' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'Login' : Login, 'Domain' :Domain, 'Password' : Password }) opener.open('https://auth.mail.ru/cgi-bin/auth', login_data) resp = opener.open('https://auth.mail.ru/cgi-bin/auth').read() print resp.decode('cp1251') #output page in cp1251 When script sucessfully executed i see in print resp.decode('cp1251') my page with auth. But when a try to request another page for example http://my.mail.ru i see autorization request. How i can use cookie with another page?

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  • sharpziplib + Whenever i try to add a file to existing archive, it overwrites previous contents

    - by schmoopy
    I am trying to add files to an existing zip file. Whenever i do, the new one contains the new list of files im passing in, but all of the previous ones are wiped out. I have also tried the code here: http://stackoverflow.com/questions/1356003/c-sharpziplib-adding-file-to-existing-archive -- same results Any idea why i cannot add files to an existing zip while maintaining the previous files? Here is the code: public static void AddFileToZip(string currentZipPath, List<string> files, bool includeFullPathInEntry, int compressionLevel) { ZipOutputStream zipStrm = new ZipOutputStream(File.Open(currentZipPath, FileMode.Open, FileAccess.ReadWrite)); zipStrm.SetLevel(compressionLevel); foreach (string str in files) { string entryName = str; if (!includeFullPathInEntry) entryName = new FileInfo(str).Name; ZipEntry entry = new ZipEntry(entryName); zipStrm.PutNextEntry(entry); Byte[] b = File.ReadAllBytes(str); zipStrm.Write(b, 0, b.Length); } zipStrm.Finish(); zipStrm.Close(); }

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  • fstream - correct error checking after output

    - by Truncheon
    What's the correct way to check for a general error when sending data to an fstream? I have the following code, which seems a bit overkill. int Saver::output() { save_file_handle.open(file_name.c_str()); if (save_file_handle.is_open()) { save_file_handle << save_str.c_str(); if (save_file_handle.bad()) { x_message("Error - failed to save file"); return 0; } save_file_handle.close(); if (save_file_handle.bad()) { x_message("Error - failed to save file"); return 0; } return 1; } else { x_message("Error - couldn't open save file"); return 0; } }

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  • ^M characters when using Tramp (on Windows) to connect to Ubuntu Server

    - by jamting
    I've set up Tramp on Emacs on my Windows 7 box (64 bit). For this test, this is the only thing in my emacs-config: (setq tramp-default-method "plink") Then I connect to my Ubuntu Server 9.10 running in a VM on my local network. Connection goes fine, i can use dired to browse folders and open files. Yay! However, git status shows up as: Git:master^M An when i open speedbar all folders and files ends with ^M, ie: <+ conf/^M Does anyone know how to prevent this line-ending collision from occurring?

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  • Good implementations of reinforced learning?

    - by Paperino
    For an ai-class project I need to implement a reinforcement learning algorithm which beats a simple game of tetris. The game is written in Java and we have the source code. I know the basics of reinforcement learning theory but was wondering if anyone in the SO community had hands on experience with this type of thing. What would your recommended readings be for an implementation of reinforced learning in a tetris game? Are there any good open source projects that accomplish similar things that would be worth checking out? Thanks in advanced Edit: The more specific the better, but general resources about the subject are welcomed. Follow up: Thought it would be nice if I posted a followup. Here's the solution (code and writeup) I ended up with for any future students :). Paper / Code

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  • Django : presenting a form very different from the model and with multiple field values in a Django-

    - by sebpiq
    Hi ! I'm currently doing a firewall management application for Django, here's the (simplified) model : class Port(models.Model): number = models.PositiveIntegerField(primary_key=True) application = models.CharField(max_length=16, blank=True) class Rule(models.Model): port = models.ForeignKey(Port) ip_source = models.IPAddressField() ip_mask = models.IntegerField(validators=[MaxValueValidator(32)]) machine = models.ForeignKey("vmm.machine") What I would like to do, however, is to display to the user a form for entering rules, but with a very different organization than the model : Port 80 O Not open O Everywhere O Specific addresses : --------- delete field --------- delete field + add address field Port 443 ... etc Where Not open means that there is no rule for the given port, Everywhere means that there is only ONE rule (0.0.0.0/0) for the given port, and with specific addresses, you can add as many addresses as you want (I did this with JQuery), which will make as many rules. Now I did a version completely "handmade", meaning that I create the forms entirely in my templates, set input names with a prefix, and parse all the POSTed stuff in my view (which is quite painful, and means that there's no point in using a web framework). I also have a class which aggregates the rules together to easily pre-fill the forms with the informations "not open, everywhere, ...". I'm passing a list of those to the template, therefore it acts as an interface between my model and my "handmade" form : class MachinePort(object): def __init__(self, machine, port): self.machine = machine self.port = port @property def fully_open(self): for rule in self.port.rule_set.filter(machine=self.machine): if ipaddr.IPv4Network("%s/%s" % (rule.ip_source, rule.ip_mask)) == ipaddr.IPv4Network("0.0.0.0/0"): return True else : return False @property def partly_open(self): return bool(self.port.rule_set.filter(machine=self.machine)) and not self.fully_open @property def not_open(self): return not self.partly_open and not self.fully_open But all this is rather ugly ! Do anyone of you know if there is a classy way to do this ? In particular with the form... I don't know how to have a form that can have an undefined number of fields, neither how to transform these fields into Rule objects (because all the rule fields would have to be gathered from the form), neither how to save multiple objects... Well I could try to hack into the Form class, but seems like too much work for such a special case. Is there any nice feature I'm missing ?

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  • Creating excel template 2003 in C# on a machine with both 2003 and 2007 installed.

    - by Ragha J
    I have both 2003 and 2007 Excel versions installed on my machine. The current source code uses Office11 (2003) interop assembly Microsoft.Office.Interop.Excel.dll to create the Excel template. When I create the template and open in Excel 2007, it opens perfectly. The same template when I open in 2003 I get the message "File format is not valid". _excel = new Excel.Application(); _workbooks = _excel.Workbooks; _excel.Visible = false; _excel.DisplayAlerts = false; // create and add a workbook with 1 worksheet named "Sheet1" _workbook = _workbooks.Add(Excel.XlWBATemplate.xlWBATWorksheet); _sheet = (Excel.Worksheet)_workbook.ActiveSheet;

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