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  • Shopping Cart Database Structure

    - by Paul Atkins
    Hi, I have been studying the database structure for shopping carts and notice that when storing order details the product information is repeated and stored again in the table. I was wondering what the reasoning behind this would be? Here is a small example of what i mean: Product Table product_id name desc price 1 product 1 This is product 1 27.00 Order Table order_id customer id order_total 1 3 34.99 Order Details Table order_details_id product_id product name price qty 1 1 product 1 27.00 1 So as you can see the product name and price are stored again in the order details table. Why is this? The only reason i can think of is because the product details may change after the order has been placed which may cause confusion. Is this correct? Thanks Paul

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  • Altering constraint delete action

    - by Hobhouse
    I did this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`); I should have done this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`) ON DELETE SET NULL; Is it possible to ALTER this, or do I have to drop the constraint and add again?

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  • Sql query - selecting top 5 rows and further selecting rows only if User is present

    - by Gublooo
    Hello, I kind of stuck on how to implement this query - this is pretty similar to the query I posted earlier but I'm not able to crack it. I have a shopping table where everytime a user buys anything, a record is inserted. Some of the fields are * shopping_id (primary key) * store_id * user_id Now what I need is to pull only the list of those stores where he's among the top 5 visitors: When I break it down - this is what I want to accomplish: * Find all stores where this UserA has visited * For each of these stores - see who the top 5 visitors are. * Select the store only if UserA is among the top 5 visitors. The corresponding queries would be: select store_id from shopping where user_id = xxx select user_id,count(*) as 'visits' from shopping where store_id in (select store_id from shopping where user_id = xxx) group by user_id order by visits desc limit 5 Now I need to check in this resultset if UserA is present and select that store only if he's present. For example if he has visited a store 5 times - but if there are 5 or more people who have visited that store more than 5 times - then that store should not be selected. So I'm kind of lost here. Thanks for your help

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  • can i use MAX function for each tuple in the retrieved data set

    - by kshama
    Hi, My table result contains fields: id count ____________ 1 3 2 2 3 2 From this table i have to form another table **score** which should look as follows id my_score ___________ 1 1.0000 2 0.6667 3 0.6667 That is my_score=count/MAX(count) but if i give the query as create TEMPORARY TABLE(select id,(count/MAX(count)) AS my_score from result); only 1 st row is retrieved.Can any one suggest the query so that my_score is calculated for all tuples. Thanks in advance.

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  • Echo autoincrement id doubt

    - by Marcelo
    Hi, can I print the id, even if it's autoincrement ? Because the way I'm doing I'm using an empty variable for id. $id= ""; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die ("Não conectou com a base $database"); mysql_query("INSERT INTO table1(id,...) VALUES ('".$id."',....)") or die(mysql_error()); mysql_close(); echo "Your id is :"; echo "".$id; I'm trying to print the id, but it's coming blank. I checked the table and there's an id number there. How can I print it then at? Thanks for the attention

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  • SQL select statement

    - by kwokwai
    Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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  • how do I insert an hidden token in my form to prevent double posts? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit.

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  • PHP replace string help...

    - by MILESMIBALERR
    i am designing a site with a comment system and i would like a twitter like reply system. The if the user puts @a_registered_username i would like it to become a link to the user's profile. i think preg_replace is the function needed for this. $ALL_USERS_ROW *['USERNAME'] is the database query array for all the users and ['USERNAME'] is the username row. $content is the comment containing the @username i think this should not be very hard to solve for someone who is good at php. Does anybody have any idea how to do it?

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  • Is using Natural Join or Implicit column names not a good practice when writing SQL in a programming

    - by Jian Lin
    When we use Natural Join, we are joining the tables when both table have the same column names. But what if we write it in PHP and then the DBA add some more fields to both tables, then the Natural Join can break? The same goes for Insert, if we do a insert into gifts values (NULL, "chocolate", "choco.jpg", now()); then it will break the code as well as contaminating the table when the DBA adds some fields to the table (example as column 2 or 3). So it is always best to spell out the column names when the SQL statements are written inside a programming language and stored in a file in a big project.

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • Using a table-alias in Kohana queries?

    - by Aristotle
    I'm trying to run a simple query with $this->db in Kohana, but am running into some syntax issues when I try to use an alias for a table within my query: $result = $this->db ->select("ci.chapter_id, ci.book_id, ci.chapter_heading, ci.chapter_number") ->from("chapter_info ci") ->where(array("ci.chapter_number" => $chapter, "ci.book_id" => $book)) ->get(); It seems to me that this should work just fine. I'm stating that "chapter_info" ought to be known as "ci," yet this isn't taking for some reason. The error is pretty straight-forward: There was an SQL error: Table 'gb_data.chapter_info ci' doesn't exist - SELECT `ci`.`chapter_id`, `ci`.`book_id`, `ci`.`chapter_heading`, `ci`.`chapter_number` FROM (`chapter_info ci`) WHERE `ci`.`chapter_number` = 1 AND `ci`.`book_id` = 1 If I use the full table name, rather than an alias, I get the expected results without error. This requires me to write much more verbose queries, which isn't ideal. Is there some way to use shorter names for tables within Kohana's query-builder?

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  • Hibernate constraint ConstraintViolationException. Is there an easy way to ignore duplicate entries?

    - by vincent
    Basically I've got the below schema and I'm inserting records if they don't exists. However when it comes to inserting a duplicate it throws and error as I would expect. My question is whether there is an easy way to make Hibernate to just ignore inserts which would in effect insert duplicates? CREATE TABLE IF NOT EXISTS `method` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(10) DEFAULT NULL, PRIMARY KEY (`id`), UNIQUE KEY `name` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; SEVERE: Duplicate entry 'GET' for key 'name' Exception in thread "pool-11-thread-4" org.hibernate.exception.ConstraintViolationException: could not insert:

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  • In Django, how to create tables from an SQL file when syncdb is run

    - by Sidney
    Hi, How do I make syncdb execute SQL queries (for table creation) defined by me, rather then generating tables automatically. I'm looking for this solution as some particular models in my app represent SQL-table-views for a legacy-database table. So, I've created their SQL-views in my django-DB like this: CREATE VIEW legacy_series AS SELECT * FROM legacy.series; I have a reverse engineered model that represents the above view/legacytable. But whenever I run syncdb, I have to create all the views first by running sql scripts, otherwise syncdb simply creates tables for them (if a view is not found). How do I make syncdb run the above mentioned SQL?

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  • SQL join produces one result only

    - by Rami
    Can anyone please tell me why this result is generation only one results? taking in mind that everything is set right and the three tables are populated correctly, i took out the group_concat and it worked but of course with a php undefined index error! SELECT `songs`.`song_name`, `songs`.`add_date`, `songs`.`song_id`, `songs`.`song_picture`, group_concat(DISTINCT artists.artist_name) as artist_name FROM (`songs`) JOIN `mtm_songs_artists` ON `songs`.`song_id` = `mtm_songs_artists`.`song_id` JOIN `artists` ON `artists`.`artist_id` = `mtm_songs_artists`.`artist_id` ORDER BY `songs`.`song_id` DESC LIMIT 10 so i'm guessing it's something related to group_concat. best regards, Rami

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  • is it possible to write a method which creates a method?

    - by Alan Bennett
    hey guys, this might seem like a no brainer but hopefully after i explain my problem you might understand why i am asking this. is it possible to have a method which creates a method and its arguements? the problem: in my current project i have to many times call different sql statements which arent all that different. for example i have one where i inserts some new rows but only has 2 columns and another which also inserts new rows but has 12 columns. i have created a class called utils.cs and in there i have sorted many "handy" methods, such as validation methods which check for numeric input to text boxes etc. so i thought well instead of having sql writing methods everywhere ill make one in there and call it when i need to so i have but it currently looks like this: public static string getInsertSQL(string tablename, string colOne, string colTwo, string colThree, string colFour, string colFive, string colSix, string colSeven, string colEight, string colNine, string colTen, string colEleven, string colTwelve,bool active, string valueOne, string valueTwo, string valueThree, string valueFour, string valueFive, string valueSix, string valueSeven, string valueEight, string valueNine, string valueTen, string valueEleven) { string strSQL = ""; strSQL += "INSERT INTO " + tablename; strSQL += "(" + colOne + " " + colTwo + " " + colThree + " " + colFour + " " + colFive + " " + colSix + " " + colSeven + " " + colEight + " " + colNine + " " + colTen + " " + colEleven + " " + colTwelve + " )"; strSQL += " values ("+active+", " + valueOne + " " + valueTwo + " " + valueThree + " " + valueFour + " " + valueFive + " " + valueSix + " " + valueSeven + " " + valueEight + " " + valueNine + " " + valueTen + " " + valueEleven + " )"; return strSQL; } as you can see thats quite a mess so i wondered if it was at all possible to write a method which would take an arguement of how many colums needed to be inserted and then could create a method with that many arguements. i hope you can see what i am getting at and dont just sound like a plep! thanks in advance

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  • Take Current Snapshot of DB and send it to FTP in same PHP Scripts: Advice Needed

    - by Rachel
    Not sure if I can do it this way. I want to get current snapshot of the database and send it via FTP Server, both of this functionality should be implemented in PHP scripts. Here are the steps I am thinking on right now. In my php scripts(basically am extending an PDO into my Dao class and then preparing the query), $qry = SELECT * FROM MyTablename; $stmt = $this->prepare($qry); $stmt = $this->execute(); Now I will store $stmt in csv file using fputcsv or I will execute the sql command from the script itself and than try to store the result in the $file(csv file) note here that I do not have any csv file with me at this point to basically I will have to create one and let's say its $file, so then $file = fputcsv($stmt); or $file = exec("Select * from MyTablename"); Will this put all records in the file ? If yes, then I will use FTP Functionality to transfer file to the FTP Folder. I am not sure if this approach would work and also have concerns regarding the need of preparing the $qry Any suggestions or different approach advised would be highly appreciated. Thanks !!!

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  • problem parsing JSON Strings

    - by blacktooth
    var records = JSON.parse(JsonString); for(var x=0;x<records.result.length;x++) { var record = records.result[x]; ht_text+="<b><p>"+(x+1)+" " +record.EMPID+" " +record.LOCNAME+" " +record.DEPTNAME+" " +record.CUSTNAME +"<br/><br/><div class='slide'>" +record.REPORT +"</div></p></b><br/>"; } The above code works fine when the JsonString contains an array of entities but fails for single entity. result is not identified as an array! Whats wrong with it? http://pastebin.com/hgyWw5hd

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  • How to setup testing LAMP environment to work with outsourcing companies?

    - by Kelvin
    Hello Guys, I need to setup testing LAMP environment in my office to work with outsourcing companies. This is what I think should be done on my side: Setup testing web server with the same configuration as on production Setup testing SQL server with "fake data"? Outsourcers should have access only to some part of original code Outsourcers should use CVS to update their code Once testing is finished someone releases the update ............ How would you separate original code and database from testing environment, but keep it as close as possible to production? What is the general practice for setting up testing environment and how other companies deal with outsourcers? I will appreciate for any of your thoughts and ideas from your personal experience. Maybe someone can suggest some article on this topic. Thank you a lot!

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  • Form is trying to save the login value of the submit button to my DB.

    - by Sergio Tapia
    Here's my Zend code: <?php require_once ('Zend\Form.php'); class Sergio_Form_registrationform extends Zend_Form { public function init(){ /*********************USERNAME**********************/ $username = new Zend_Form_Element_Text('username'); $alnumValidator = new Zend_Validate_Alnum(); $username ->setRequired(true) ->setLabel('Username:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($username); /*********************EMAIL**********************/ $email = new Zend_Form_Element_Text('email'); $alnumValidator = new Zend_Validate_Alnum(); $email ->setRequired(true) ->setLabel('EMail:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($email); /*********************PASSWORD**********************/ $password = new Zend_Form_Element_Password('password'); $alnumValidator = new Zend_Validate_Alnum(); $password ->setRequired(true) ->setLabel('Password:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($password); /*********************NAME**********************/ $name = new Zend_Form_Element_Text('name'); $alnumValidator = new Zend_Validate_Alnum(); $name ->setRequired(true) ->setLabel('Name:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($name); /*********************LASTNAME**********************/ $lastname = new Zend_Form_Element_Text('lastname'); $alnumValidator = new Zend_Validate_Alnum(); $lastname ->setRequired(true) ->setLabel('Last Name:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($lastname); /*********************DATEOFBIRTH**********************/ $dateofbirth = new Zend_Form_Element_Text('dateofbirth'); $alnumValidator = new Zend_Validate_Alnum(); $dateofbirth->setRequired(true) ->setLabel('Date of Birth:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($dateofbirth); /*********************AVATAR**********************/ $avatar = new Zend_Form_Element_File('avatar'); $alnumValidator = new Zend_Validate_Alnum(); $avatar ->setRequired(true) ->setLabel('Please select a display picture:'); $this->addElement($avatar); /*********************SUBMIT**********************/ $this->addElement('submit', 'login', array('label' => 'Login')); } } ?> Here's the code I use to save the values: public function saveforminformationAction(){ $form = new Sergio_Form_registrationform(); $request = $this->getRequest(); //if($request->isPost() && $form->isValid($_POST)){ $data = $form->getValues(); $db = $this->_getParam('db'); $db->insert('user',$data); //} } When trying to save the values, I recieve a ghastly error: Column 'login' not found.

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  • SQL Query Returning Duplicate Results

    - by Jesse Bunch
    Hi, I've been working out this query now for a while and I thought I had it where I wanted it, but apparently not. There are two records in the database (orders). The query should return two different rows, but instead returns two rows that have exactly the same values. I think it may be something to do with the GROUP BY or derived tables I'm using but my eyes are tired and not seeing the problem. Can any of you help? Thanks in advance. SELECT orders.billerID, orders.invoiceDate, orders.txnID, orders.bName, orders.bStreet1, orders.bStreet2, orders.bCity, orders.bState, orders.bZip, orders.bCountry, orders.sName, orders.sStreet1, orders.sStreet2, orders.sCity, orders.sState, orders.sZip, orders.sCountry, orders.paymentType, orders.invoiceNotes, orders.pFee, orders.shipping, orders.tax, orders.reasonCode, orders.txnType, orders.customerID, customers.firstName AS firstName, customers.lastName AS lastName, customers.businessName AS businessName, orderStatus.statusName AS orderStatus, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax AS orderTotal, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax - IFNULL(payments.totalPayments, 0.00) AS orderBalance FROM orders LEFT JOIN customers ON orders.customerID = customers.id LEFT JOIN orderStatus ON orders.orderStatus = orderStatus.id LEFT JOIN ( SELECT orderItems.orderID, SUM(orderItems.itemPrice * orderItems.itemQuantity) as itemTotal FROM orderItems GROUP BY orderItems.orderID ) orderItems ON orderItems.orderID = orders.id LEFT JOIN ( SELECT payments.orderID, SUM(payments.amount) as totalPayments FROM payments GROUP BY payments.orderID ) payments ON payments.orderID = orders.id

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  • Editing/Updating one of the results in a search query.

    - by eggman20
    Hi guys. I'm creating a page that searches for an item and then be able to edit/update it. I was able to do it when it returns just one result but when it gives me multiple results I could only edit the very last item. Below is my code: ....... $dj =$_POST[djnum]; $sql= "SELECT * From dj WHERE datajack LIKE '$dj%'"; $result = mysql_query($sql); //more code in here// while ($info =mysql_fetch_array($result)) { // display the result echo "<form action=\"dj_update.php\" method=\"POST\"><input type=\"hidden\" name=\"djnumber\" value=\"".$info['datajack']."\">"; echo "<tr><td>DJ ".$info['datajack']."</td>"; echo "<td>".$info['building']."&nbsp;</td>"; echo "<td>Rm ".$info['room']."&nbsp;</td>"; echo "<td>".$info['switch']."&nbsp;</td>"; echo "<td>".$info['port']."&nbsp;</td>"; echo "<td>".$info['notes']."&nbsp;</td>"; echo "<td style=\"text-align:center;\"><input type=\"Submit\" value=\"Edit\" ></td></tr>"; } // more code here // Then this is the screen shot of the result: The idea is the user should be able to click on "Edit" and be able to edit/update that particular item. But when I click any of the Edit button I could only edit the last item. What am I missing here? Is there an easier way to do this? Thanks guys and Happy new year!

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  • Query Only Specified Number Of Items From Parent/Child Categories

    - by RogeR
    I'm having trouble figureing out how to query every item in a certain category and only list the newest 10 items by date. Here is my table layout: download_categories category_id (int) primary key title (var_char) parent_id (int) downloads id (int) primary key title (var_char) category_id (int) date (date) I need to query every file in a main category that lets say has 100 items and 5 child categories and only spit out the last 10 added. I have functions right now that just add up all the files so I can get a count by category, but I can't seem to modify the code to only display a certain amount of items based on the date.

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