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• How to reduce latency of data sent through a REST api

  - by Sid

  I have an application which obtains data in JSON format from one of our other servers. The problem I am facing is, there is is significant delay when when requesting for this information. Since a lot of data is passed (approx 1000 records per request where each record is pretty huge) is there a way that compression would help reducing the speed. If so which compression scheme would you recommend. I read on another thread that they pattern of data also matters a lot on they type of compression that needs to be used. The pattern of data is consistent and resembles the following :desc=>some_description :url=>some_url :content=>some_content :score=>some_score :more_attributes=>more_data Can someone recommend a solution to how I could reduce this delay. They delay is approx 6-8 seconds. I'm using Ruby on Rails to develop this application and the server providing the data uses Python for the most part.

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• What host do I have to bind a listening socket to?

  - by herrturtur

  I used python's socket module and tried to open a listening socket using import socket import sys def getServerSocket(host, port): for r in socket.getaddrinfo(host, port, socket.AF_UNSPEC, socket.SOCK_STREAM, 0, socket.AI_PASSIVE): af, socktype, proto, canonname, sa = r try: s = socket.socket(af, socktype, proto) except socket.error, msg: s = None continue try: s.bind(sa) s.listen(1) except socket.error, msg: s.close() s = None continue break if s is None: print 'could not open socket' sys.exit(1) return s Where host was None and port was 15000. The program would then accept connections, but only from connections on the same machine. What do I have to do to accept connections from the internet?

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• Counter variable for class

  - by George

  I am having problem getting this piece of code to run. The class is Student which has a IdCounter, and it is where the problem seems to be. (at line 8) class Student: def __init__(self): # Each student get their own student ID idCounter = 0 self.gpa = 0 self.record = {} # Each time I create a new student, the idCounter increment idCounter += 1 self.name = 'Student {0}'.format(Student.idCounter) classRoster = [] # List of students for number in range(25): newStudent = Student() classRoster.append(newStudent) print(newStudent.name) I am trying to have this idCounter inside my Student class, so I can have it as part of the student's name (which is really an ID#, for example Student 12345. But I have been getting error. Traceback (most recent call last): File "/Users/yanwchan/Documents/test.py", line 13, in <module> newStudent = Student() File "/Users/yanwchan/Documents/test.py", line 8, in __init__ idCounter += 1 UnboundLocalError: local variable 'idCounter' referenced before assignment I tried to put the idCounter += 1 in before, after, all combination, but I am still getting the referenced before assignment error, can you explain to me what I am doing wrong? Thank you Edit: Provided the full code I have

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• Some confusion with a class variable, but with a twist...

  - by Omega

  I have a class called MyPackage.WebServer and it has a property called DBEngine. I am also dynamically loading a module and class using load_module. Inside this class, it attempts to reference MyPackage.WebServer. When it does though, DBEngine is not set to the value given when WebServer is instantiated. It's the default (None). Would the fact that I'm using load_module cause a different object graph to be created and thus isolate my dynamically loaded class from the rest of my python app?

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• Magento - Code Question

  - by user349550

  I will have publications (news papers), under these publications there will be editions [location and language] and under these there will be offers and offers will have products. currently i have created all as modules i.e. publication to add / edit /delete publication, edition to add / edit/ update editions and so on. the problem is how can i get list of all publication when I am creating a edition and same way how can i get list of edition and publication when i am creating a offer. please help/ regards, saurabh

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• remove the spaces...

  - by tekknolagi

  !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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• Error reading file with accented vowels

  - by Daniel Dcs

  The following statement to fill a list from a file : action = [] with open (os.getcwd() + "/files/" + "actions.txt") as temp:          action = list (temp) gives me the following error: (result, consumed) = self._buffer_decode (data, self.errors, end) UnicodeDecodeError: 'utf-8' codec can not decode byte 0xf1 in position 67: invalid continuation byte if I add errors = 'ignore': action = [] with open (os.getcwd () + "/ files /" + "actions.txt", errors = 'ignore') as temp:          action = list (temp) Is read the file but not the ñ and vowels accented á-é-í-ó-ú being that python 3 works, as I have understood, default to 'utf-8' I'm looking for a solution for two or more days, and I'm getting more confused. In advance thank you very much for any suggestions.

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• Protocols/Interfaces in Ruby

  - by fifigyuri

  While coding in Ruby I did not really miss the type-orientedness of Java or C++ so far, but for some cases I think it is useful to have them. For Python there was a project PyProtocols which defined interfaces and protocols for objects. Does a similar initiative also exist for Ruby? I would like to be able to declare the expected parameters for some methods for some objects (for the entire code I find such think useless). It the method during the execution receives an unexpected input, it tries to adapt it or if it cannot, it throws an exception. Does something similar exist for Ruby? Introducing types for a type-less language like Ruby might sound freak, but I think types are sometimes useful. Thanks for help.

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• Iterate over the lines of a string

  - by Space_C0wb0y

  I have a multi-line string defined like this: foo = """ this is a multi-line string. """ I need an iterator that iterates over the individual lines of that string. I could of course do it like this: lineiterator = iter(foo.splitlines()) Is there a more direct way of doing this? In this scenario the string has to traversed once for the splitting, and then again by the parser. It doesn't matter in my test-case, since the string is very short there, I am just asking out of curiosity. Python has so many useful and efficient built-ins for such stuff, but I could find nothing that suits this need.

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• Building a financial app with Django

  - by mfalcon

  Hi guys, I'm building an app for a small business so I've to work with currencies, decimal numbers, etc... My goal is to create something like pulseapp.com. I've searched for opensource projects to look and the only thing I had found was django-cashflow. This app uses python-money. I've read some of the code and the ways it's coded seems a bit weird to me and it's not fully complete. Is the app worth to take a deep look? Does anyone know about another similar app? Is the task difficult or a begginer like me could find a way to code it himself?

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• Django development server serving css but not js

  - by Wisco crew

  I am developing a django (1.4) app on my local machine. I am running the built-in development server with python manage.py runserver. In base.html I have: <link href="{{ STATIC_URL }}bootstrap.css" rel="stylesheet" type="text/css" /> <script src="{{ STATIC_URL }}boostrap-dropdown.js" type="text/javascript"></script> boostrap.css loads just fine when I load a page, but bootstrap-dropdown.js is 404'd. They are sitting right next to each other in my static directory. Relevant parts of settings.py: STATIC_URL = '/static/' STATICFILES_DIRS = ( '/home/username/projects/projectname/static',) Debug is set to True. I have tried it both with and without the staticfiles_urlpatterns trick. Django can find one file in the directory but not the other? I think I'm going crazy.

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• Parse text of element with empty element inside

  - by Mando

  I'm trying to convert an XHTML document that uses lots of tables into a semantic XML document in Python using xml.etree. However, I'm having some trouble converting this XHTML <TD> Textline1<BR/> Textline2<BR/> Textline3 </TD> into something like this <lines> <line>Textline1</line> <line>Textline2</line> <line>Textline3</line> </lines> The problem is that I don't know how to get the text after the BR elements.

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• Why is my socket closing?

  - by Tommy3244

  Ok, so I am making a multiplayer game. I am working out the kinks in the server/client connectivity system. I can't seam to work out this error. Mainly, my server code does the following: Accepts Client Using SocketServer Module CLIENT -- SERVER sends Login byte (1 byte) + login username and password (200 bytes) SERVER request for 1 byte by struct.calcsize('b') CLIENT has exception on read SERVER recieves byte from CLIENT and sends CLIENT a struct packed byte with the value of 4 SERVER has exception on send So, it is the client excepting. The client exception is: socket.error: (10054, 'Connection reset by peer') And the server error is this: error: (9, 'Bad file descriptor')

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• If I start learning C on Ubuntu will it give me an edge when I start learning Objective-C later this

  - by Anonymous

  I know Ruby right now, however I want to learn a new language. I am running Ubuntu 10.04 right now but I am going to get a Mac later this summer. Anyways I want something more for GUI development. I was wondering if I should learn C on Ubuntu right now, and then learn Objective-C when I get an iMac? Will learning C give me an edge? Or should I just learn Python on Ubuntu and then learn Objective-C when I get a new computer? Please give me your opinions! Thanks!

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• xml parsing takes extra spaces.

  - by SDK

  I have been trying to write/parse xml file in python. The tags are very simple <main> <data> abcdef </data> </main> I have written this xml using xml document writer from xml.dom.minidom. How-ever when i try to parse this and try to fetch data-text value, i get 'abcdef' with spaces/carriage return/newline characters in beg and end. Does parsing does not take of indenting spaces? Following is the parsing snippet (ref from net) dom = parseString(data) clipTag = dom.getElementsByTagName('clipdata')[0].toxml() clipData=clipTag.replace('<clipdata>','').replace('</clipdata>','') Kindly suggest.

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• problem in extracting the data from text file

  - by parijat24

  hello , i am new to python , and I want to extract the data from this format FBpp0143497 5 151 5 157 PF00339.22 Arrestin_N Domain 1 135 149 83.4 1.1e-23 1 CL0135 FBpp0143497 183 323 183 324 PF02752.15 Arrestin_C Domain 1 137 138 58.5 6e-16 1 CL0135 FBpp0131987 60 280 51 280 PF00089.19 Trypsin Domain 14 219 219 127.7 3.7e-37 1 CL0124 to this format FBpp0143497 5 151 Arrestin_N 1.1e-23 FBpp0143497 183 323 Arrestin_C 6e-16 I have written code in hope that it works but it does not work , please help! file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') rec = file.read() for line in rec : field = line.split("\t") print field print field[:] print '>',field[0] print field[1], field[2], field[6], field[12] the hmmtext file is FBpp0143497 5 151 5 157 PF00339.22 Arrestin_N Domain 1 135 149 83.4 1.1e-23 1 CL0135 FBpp0143497 183 323 183 324 PF02752.15 Arrestin_C Domain 1 137 138 58.5 6e-16 1 CL0135 FBpp0131987 60 280 51 280 PF00089.19 Trypsin Domain 14 219 219 127.7 3.7e-37 1 CL0124

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• How to schedule hundreds of thousands of tasks?

  - by wehriam

  We have hundreds of thousands of tasks that need to be run at a variety of arbitrary intervals, some every hour, some every day, and so on. The tasks are resource intensive and need to be distributed across many machines. Right now tasks are stored in a database with an "execute at this time" timestamp. To find tasks that need to be executed, we query the database for jobs that are due to be executed, then update the timestamps when the task is complete. Naturally this leads to a substantial write load on the database. As far as I can tell, we are looking for something to release tasks into a queue at a set interval. (Workers could then request tasks from that queue.) What is the best way to schedule recurring tasks at scale? For what it's worth we're largely using Python, although we have no problems using components (RabbitMQ?) written in other languages.

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• Prevent RegEx Hang on Large Matches...

  - by developerjay

  This is a great regular expression for dates... However it hangs indefinitely on this one page I tried... I wanted to try this page ( http://pleac.sourceforge.net/pleac%5Fpython/datesandtimes.html ) for the fact that it does have lots of dates on it and I want to grab all of them. I don't understand why it is hanging when it doesn't on other pages... Why is my regexp hanging and/or how could I clean it up to make it better/efficient ? Python Code: monthnames = "(?:Jan\w*|Feb\w*|Mar\w*|Apr\w*|May|Jun\w?|Jul\w?|Aug\w*|Sep\w*|Oct\w*|Nov(?:ember)?|Dec\w*)" pattern1 = re.compile(r"(\d{1,4}[\/\\\-]+\d{1,2}[\/\\\-]+\d{2,4})") pattern4 = re.compile(r"(?:[\d]*[\,\.\ \-]+)*%s(?:[\,\.\ \-]+[\d]+[stndrh]*)+[:\d]*[\ ]?(PM)?(AM)?([\ \-\+\d]{4,7}|[UTCESTGMT\ ]{2,4})*"%monthnames, re.I) patterns = [pattern4, pattern1] for pattern in patterns: print re.findall(pattern, s) btw... when i say im trying it against this site.. I'm trying it against the webpage source.

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• Where should I declare a list of 5,000+ words?

  - by user647362

  I am writing a game in python in which I must periodically pull a random word from a list of words. When I prototyped my game I declared a word_list = ['cat','dog','rat','house'] of ten words at the top of one of my modules. I then use choice(word_list) to get a random word. However, I must must change this temporary hack into something more elegant because I need to increase the size of the word list to 5,000+ words. If I do this in my current module it will look ridiculous. Should I put all of these words in a flat txt file, and then read from that file as I need words? If so, how would I best do that? Put each word an a separate line and then read one random line? I'm not sure what the most efficient way is.

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• Upon USB insert, record unique identifer sting, format drive to FAT32 and copy a file. Bash or Pytho

  - by samsixty

  Hello, This is what I want to do, insert USB flash drive. mount it. record uniquie identifer string to a file. format the drive to FAT32. copy a text file to the drive. unmount it. remove the drive. 30 times The situation is this, I have bought 30 usb drives. I need to format each one to ensure they are clean, I need the unique string from each device. I need to put the same txt file on each one. I am not great at writing scripts but can read and follow bash and python. Any pointers would be appreciated.

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• How to add visible menu item from php code (drupal)

  - by uta

  I have a content type with important "created" date field. And I have a menu link (in primary links) which is link to page that shows list of all nodes of my content type. (http://example.com/mycontenttype) I want to have menu links (visible in primary links) to each year when nodes of my content type are displayed (http://example.com/mycontenttype/2010). And I want to add these menu links from mymodule_nodeapi function, when the node is creating and only if it has a "created" date of new year. I know that I can create a pathes in mymodule_menu function, but it doesn't create a visible menu item. (Maybe I can somehow set parent_link_id or something else to do it?)

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• One input file to multiple output files

  - by user1265669

  I found some helpful stuff on this site but my input file is different from the examples already posted and I cannot make the leap in an efficient manner. My input file looks like this: sample_dude data1 data2 data3 data4 sample_lady data5 data6 data7 data8 sample_dude data9 data10 data11 data12 sample_child data13 data14 data15 data16 I want to create a separate file for each sample with all the data columns. For example, one file would be called sample_dude.txt and look like this: data1 data2 data3 data4 data9 data10 data11 data12 There is an unknown number of samples but always just four data columns. Any help greatly appreciated. Thank you. PS: I'm trying to do this in python.

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• can list be converted into string

  - by PARIJAT

  Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

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• A 3-D grid of regularly spaced points

  - by Jack

  I want to create a list containing the 3-D coords of a grid of regularly spaced points, each as a 3-element tuple. I'm looking for advice on the most efficient way to do this. In C++ for instance, I simply loop over three nested loops, one for each coordinate. In Matlab, I would probably use the meshgrid function (which would do it in one command). I've read about meshgrid and mgrid in Python, and I've also read that using numpy's broadcasting rules is more efficient. It seems to me that using the zip function in combination with the numpy broadcast rules might be the most efficient way, but zip doesn't seem to be overloaded in numpy.

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• can this code be shortened or improved?

  - by user2816683

  Can this be shortened/improved? I'm trying to make a password checker in python. Could the if's be put into a for loop? And if so, how? pw = input("Enter password to test: ") caps = sum(1 for c in pw if c.isupper()) lower = sum(1 for c in pw if c.islower()) nums = sum(1 for c in pw if c.isnumeric()) scr = ['weak', 'medium', 'strong'] r = [caps, lower, nums] if len(pw) < 6: print("too short") elif len(pw) > 12: print("too long") if caps >= 1: if lower >= 1: if nums >= 1: print(scr[2]) elif nums < 1: print("your password is " + scr[1]) elif lower < 1: print("your password strength is " + scr[0]) elif caps < 1: print("your password strength is " + scr[1]) Thanks for any suggestions :D

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