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  • Creating DB views in Ruby on Rails

    - by Zigu
    Hey guys, I'm building a "reports" functionality to a project. 3 roles here: 1) Volunteers (they report what hours they volunteered) 2) Supervisors (they look at the reported stuff, note: one supervisor can view all projects) 3) Projects (Represents a work project that some collection of volunteers work on) To explain what it does: A report will be specified by the supervisor to generate based on a query of what he needs. These could be plausible reports: 1) The total number of volunteers, and the total amount of volunteer hours on this project 2) All the volunteer's names and emails associated with a project 3) The number of active projects vs. the total number of projects I was thinking maybe that creating a view in rails and storing the name of that view so Rails will just check the view whenever a supervisor wants to pull up the "report". Is a view really the answer or is it better to just save a query? Can Rails do this or is there an even better or more simple way of achieving this functionality? Cheers, -Jeremiah Tantongco

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  • remote_form_for in index.html.erb file not working w/ AJAX...Ruby on Rails...

    - by bgadoci
    Just curious if I am overlooking something simple here. I have deployed the remote_form_for in the show.html.erb code before to render comments on a post (project in this case) without a problem. I have moved this code to the index view and seems to degrade to the normal form_for action (page refresh). I am not getting any javascript errors so not sure what is wrong here. Here is my code: index.html.erb <% remote_form_for [project, Comment.new] do |f| %> <p> <%= f.label :body, "New Comment" %><br/> <%= f.text_area (:body, :class => "textarea") %> </p> <p> <%= f.label :name, "Name" %> (Required)<br/> <%= f.text_field (:name, :class => "textfield") %> </p> <p> <%= f.label :email, "Email" %> (Required but will not be displayed)<br/> <%= f.text_field (:email, :class => "textfield") %> </p> <p><%= f.submit "Add Comment" %></p> <% end %> CommentsController#create def create @project = Project.find(params[:project_id]) @comment = @project.comments.create!(params[:comment]) respond_to do |format| format.html { redirect_to projects_path } format.js end end /views/comments/create.js.rjs page.insert_html :bottom, :commentwrapper, :partial => @comment page[@comment].visual_effect :highlight page[:new_comment].reset page.replace_html :notice, flash[:notice] flash.discard /views/comments/_comment.html.erb <% div_for comment do %> <div id="commentwrapper"> <% if admin? %> <%=link_to_remote "X", :url => [@project, comment], :method => :delete %> <% end %> <%= h(comment.body) %><br/><br/> Posted <%= time_ago_in_words(comment.created_at) %> ago by <%= h(comment.name) %> <% if admin? %> | <%= h(comment.email) %> <% end %></div> <% end %>

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  • Django ModelForm Imagefield Upload

    - by Wei Xu
    I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

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  • How to get the Actual Link file location in VSS?

    - by Regi
    I use VSS and currently I am adding a link file using following code: int ShareFlags = (int)VSSFlags.VSSFLAG_RECURSNO; //Link in sourcesafe IVSSDatabase ssdb = GetVssDatabase(); Shared.Enums.SqlObjectSubType _sqlSubType = new Shared.Enums.SqlObjectSubType(); VSSItem SourceItem = ssdb.get_VSSItem(pSourceItemPath, false); //if source is a proj, recursively share the whole thing if (SourceItem.Type == (int)VSSItemType.VSSITEM_PROJECT) ShareFlags = (int)VSSFlags.VSSFLAG_RECURSYES; VSSItem DestItem = ssdb..get_VSSItem(pDestItemPath, false); //share the item DestItem.Share(SourceItem, pComment, ShareFlags); if (SourceItem.Type == (int)VSSItemType.VSSITEM_FILE) { bResult = true; } return bResult; This will works fine. My issue is that I need to find the actual link location. For example I have a Project named as Link and it contains 2 files say file1 and file2. I added a Link to my Working project (say CurrentProject). This current project have 2 files say f1 and f2. After sharing the Link project then we get the item in Current project as: $/CurrentProject/File1 $/CurrentProject/File2 $/CurrentProject/F1 $/CurrentProject/F2 Here File1 and File2 are link files. I need to get its parent (Actual) location i.e. $/Link/file1 and $/Link/File2 Is there any way to find Link files location using SourceSafeTypeLib?

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