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  • VBA How to find last insert id?

    - by Muiter
    I have this code: With shtControleblad Dim strsql_basis As String strsql_basis = "INSERT INTO is_calculatie (offerte_id) VALUES ('" & Sheets("controleblad").Range("D1").Value & "')" rs.Open strsql_basis, oConn, adOpenDynamic, adLockOptimistic Dim last_id As String last_id = "select last_insert_id()" End With The string last_id is not filled. What is wrong? I need to find te last_insert_id so I can use it in an other query.

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  • ob_start() is partially capturing data

    - by AAA
    I am using the following code: PHP: // Generate Guid function NewGuid() { $s = strtoupper(uniqid(rand(),true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); $alphabet = '123456789abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ'; function base_encode($num, $alphabet) { $base_count = strlen($alphabet); $encoded = ''; while ($num >= $base_count) { $div = $num/$base_count; $mod = ($num-($base_count*intval($div))); $encoded = $alphabet[$mod] . $encoded; $num = intval($div); } if ($num) $encoded = $alphabet[$num] . $encoded; return $encoded; } function base_decode($num, $alphabet) { $decoded = 0; $multi = 1; while (strlen($num) > 0) { $digit = $num[strlen($num)-1]; $decoded += $multi * strpos($alphabet, $digit); $multi = $multi * strlen($alphabet); $num = substr($num, 0, -1); } return $decoded; } ob_start(); echo base_encode($Guid, $alphabet); //should output: bUKpk $theid = ob_get_contents(); ob_get_clean(); The problem: When i echo $theid, it shows the complete entry, but as it is being inserted into the database, only the first entry in the sequence gets inserted, for example for the entry buKPK, only 'b' is being inserted not the rest.

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  • PHP error problem.

    - by TaG
    I get the following error on line 8: Undefined index: real_name which is $privacy_policy = mysqli_real_escape_string($mysqli, $_POST['privacy_policy']); I was wondering how can I fix this problem? Here is the PHP. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $privacy_policy = mysqli_real_escape_string($mysqli, $_POST['privacy_policy']); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, privacy_policy) VALUES ('$user_id', '$privacy_policy')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET privacy_policy = '$privacy_policy' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the HTML. <form method="post" action="index.php"> <fieldset> <ul> <li><input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" <?php if (isset($_POST['privacy_policy'])) { echo 'checked="checked"'; } else if($privacy_policy == "yes") { echo 'checked="checked"'; } ?> /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • How to select DISTINCT rows without having the ORDER BY field selected

    - by JannieT
    So I have two tables students (PK sID) and mentors (PK pID). This query SELECT s.pID FROM students s JOIN mentors m ON s.pID = m.pID WHERE m.tags LIKE '%a%' ORDER BY s.sID DESC; delivers this result pID ------------- 9 9 3 9 3 9 9 9 10 9 3 10 etc... I am trying to get a list of distinct mentor ID's with this ordering so I am looking for the SQL to produce pID ------------- 9 3 10 If I simply insert a DISTINCT in the SELECT clause I get an unexpected result of 10, 9, 3 (wrong order). Any help much appreciated.

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  • How to add space between the images being fetched using database through php

    - by ParveenArora
    I am using following code to fetch images using database with php. while($row = mysql_fetch_array($result)) //To excute result query { echo "<a href='http://".$row['website']."' target='_blank'><img src=\"" . $PathImage . $row['logo'] . "\" height = $FooterWidth /></a>XX; } Here I am using $row[logo] is fetching the path of images stored on the server and XX to put the spaced between the images having the same color of text XX as background, and but I want to use the proper method I know this can be done using table but I want to do it without using table. Any Suggestions?

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  • How do I use Django to insert a Geometry Field into the database?

    - by alex
    class LocationLog(models.Model): user = models.ForeignKey(User) utm = models.GeometryField(spatial_index=True) This is my database model. I would like to insert a row. I want to insert a circle at point -55, 333. With a radius of 10. How can I put this circle into the geometry field? Of course, then I would want to check which circles overlap a given circle. (my select statement)

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  • Need help in Select query..

    - by Parth
    If I have four rows for a field with different values with other fields similar and then other four rows with same condition, as given below here u can see there different rows for insert with only difference in the "newvalue" and "field" excluding "id" for the table_name=jos_menu, operation=INSERT and live=0 now here what select query should be used to get only single row from the table on every change of table_name...??

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  • Preg_match differences?

    - by sky
    Hi, i want to ask, what is the meaning or difference between these two line? if( preg_match_all('/\#([?-?À-ÿ?-??-?a-z0-9\-_]{1,50})/iu', $message, $matches, PREG_PATTERN_ORDER) ) { if( preg_match_all('/\#([?-?a-z0-9\-_\x{4e00}-\x{9fa5}]{1,50})/iu', $message, $matches, PREG_PATTERN_ORDER) ) { and what does the number 3 mean in this line? (Arrow pointing) if( preg_match_all('/\@([a-zA-Z0-9\-_\x{4e00}-\x{9fa5}]{->3,30})/u', $message, $matches, PREG_PATTERN_ORDER) ) { Thanks!

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  • Php mysqli and stored-procedure

    - by Mneva skoko
    I have a stored procedure: Create procedure news(in dt datetime,in title varchar(10),in desc varchar(200)) Begin Insert into news values (dt,title,desc); End Now my php: $db = new mysqli("","","",""); $dt = $_POST['date']; $ttl = $_POST['title']; $desc = $_POST['descrip']; $sql = $db-query("CALL news('$dt','$ttl','$desc')"); if($sql) { echo "data sent"; }else{ echo "data not sent"; } I'm new with php please help thank you

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  • Need help with SQL Query

    - by StackOverflowNewbie
    Say I have 2 tables: Person - Id - Name PersonAttribute - Id - PersonId - Name - Value Further, let's say that each person had 2 attributes (say, gender and age). A sample record would be like this: Person->Id = 1 Person->Name = 'John Doe' PersonAttribute->Id = 1 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Gender' PersonAttribute->Value = 'Male' PersonAttribute->Id = 2 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Age' PersonAttribute->Value = '30' Question: how do I query this such that I get a result like this: 'John Doe', 'Male', '30'

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  • Display a ranking grid for game : optimization of left outer join and find a player

    - by Jerome C.
    Hello, I want to do a ranking grid. I have a table with different values indexed by a key: Table SimpleValue : key varchar, value int, playerId int I have a player which have several SimpleValue. Table Player: id int, nickname varchar Now imagine these records: SimpleValue: Key value playerId for 1 1 int 2 1 agi 2 1 lvl 5 1 for 6 2 int 3 2 agi 1 2 lvl 4 2 Player: id nickname 1 Bob 2 John I want to display a rank of these players on various SimpleValue. Something like: nickname for lvl Bob 1 5 John 6 4 For the moment I generate an sql query based on which SimpleValue key you want to display and on which SimpleValue key you want to order players. eg: I want to display 'lvl' and 'for' of each player and order them on the 'lvl' The generated query is: SELECT p.nickname as nickname, v1.value as lvl, v2.value as for FROM Player p LEFT OUTER JOIN SimpleValue v1 ON p.id=v1.playerId and v1.key = 'lvl' LEFT OUTER JOIN SimpleValue v2 ON p.id=v2.playerId and v2.key = 'for' ORDER BY v1.value This query runs perfectly. BUT if I want to display 10 different values, it generates 10 'left outer join'. Is there a way to simplify this query ? I've got a second question: Is there a way to display a portion of this ranking. Imagine I've 1000 players and I want to display TOP 10, I use the LIMIT keyword. Now I want to display the rank of the player Bob which is 326/1000 and I want to display 5 rank player above and below (so from 321 to 331 position). How can I achieve it ? thanks.

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  • Wordpress - Total User Count who only have posts

    - by knightrider
    I want to display total number of user who only have posts at Wordpress. I can get all users by this query <?php $user_count = $wpdb->get_var("SELECT COUNT(*) FROM $wpdb->users;"); echo $user_count ?> But for the user count only with posts, i think i might need to join another table, does anyone have snippets ? Thanks.

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  • Create Downloadable CSV File from PHP Script

    - by Aphex22
    How would I create a formatted version of the following PHP script as a downloadable CSV file from the code below (1.0) At the moment the fputcsv function is currently dumping the unparsed PHP/HTML code into a CSV file. This is incorrect. The downloaded CSV file should contain the columns and rows generated from the code at (1.0) as shown in the image link below. I've tried using the following code at the top of the PHP file: // output headers so that the file is downloaded rather than displayed header('Content-Type: text/csv; charset=utf-8'); header('Content-Disposition: attachment; filename=amazon.csv'); // create a file pointer connected to the output stream $output = fopen('php://output', 'w'); $mysql_hostname = ""; $mysql_user = ""; $mysql_password = ""; $mysql_database = ""; $bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Could not connect database"); mysql_select_db($mysql_database, $bd) or die("Could not select database"); $sql = "select * from product WHERE on_amazon = 'on' AND active = 'on'"; $result = mysql_query($sql) or die ( mysql_error() ); // loop over the rows, outputting them while ($sql_result = mysql_fetch_assoc($sql)) fputcsv($output, $sql_result); 1.0 The start of the code outputs the column headings for the CSV file: // set headers echo " item_sku, external_product_id, external_product_id_type, item_name, brand_name, manufacturer, product_description, feed_product_type, update_delete, part_number, model, standard_price, list_price, currency, quantity, product_tax_code, product_site_launch_date, merchant_release_date, restock_date ... <br>"; And then follows PHP script for the column values // load all stock while ($line = mysql_fetch_assoc($result) ) { ?> <?php $size_suffix = array ("",'_chain','_con_b','_con_c'); $arrayLength = count ($size_suffix); for($y=0;$y<$arrayLength;$y++) { //Possible size array to loop through when checking quantity $con_size = array (36,365,37,375,38,385,39,395,40,405,41,415,42,425,43,435,44,445,45,455,46,465,47,475,48,485); $arrlength=count($con_size); for($x=0;$x<$arrlength;$x++) { // check if size is available if($line['quantity_c_size_'.$con_size[$x].$size_suffix[$y]] > 0 ) { ?> <!-- item sku --> <?=$line['product_id']?>, <!-- external product id --> <?=$line['code_size_'.$con_size[$x].'']?>, <? // external product id type $barcode = $line['code_size_'.$con_size[$x]]; $trim_barcode = trim($barcode); $count = strlen($trim_barcode); if ($count == 12) { echo "UPC"; } if ($count == 13) { echo "EAN"; } elseif ($count < 12) { echo " "; } ?>, <!-- item name --> <?=$line['title']?>, <? // brand_name $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <? // manufacturer $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <!-- product description --> <?=preg_replace('/[^\da-z]/i', ' ', $line['amazon_desc']) ?>, <!-- feed product type --> Shoes, , , , <!-- standard price --> <?=$line['price']?>, , <!-- currency --> GBP, <!-- quantity --> <?=$line['quantity_size_'.$con_size[$x].$size_suffix[$y]]?>, , <!-- product site launch date --> <?=$line['added_y']?>-<?=$line['added_m']?>-<?=$line['added_d']?>, <!-- merchat release date --> <?=$line['added_y']?>-<?=$line['added_m']?>-<?=$line['added_d']?>, , , , , <!-- item package quantity --> 1, , , , , <!-- fulfillment latency --> 2, <!-- max aggregate ship quantity --> 1, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , <!-- main image url, url1, url2, url3 --> http://www.getashoe.co.uk/full/<?=$line['product_id']?>_1.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_2.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_3.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_4.jpg, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , <!-- heel height --> <?=$line['heel']?>, , , , , , , , , , , <!-- colour name --> <?=$line['colour']?>, <!-- colour map --> <? $colour = preg_replace('/[()]/i', ' ', $line['colour']); if (preg_match( '/[\/].*/i', $colour)) { echo 'Multicolour'; } if (preg_match( '/off.*/i', $colour)) { echo 'Off-White'; } elseif( preg_match( '/white.*/i', $colour)) { echo 'White'; } elseif( preg_match( '/moro.*/i', $colour)) { echo 'Brown'; } elseif( preg_match( '/morado.*/i', $colour)) { echo 'Purple'; } elseif( preg_match( '/cream.*/i', $colour)) { echo 'Off-White'; } elseif( preg_match( '/pewter.*/i', $colour)) { echo 'Silver'; } elseif( preg_match( '/yellow.*/i', $colour)) { echo 'Yellow'; } elseif( preg_match( '/camel.*/i', $colour)) { echo 'Beige'; } elseif( preg_match( '/navy.*/i', $colour)) { echo 'Blue'; } elseif( preg_match( '/tan.*/i', $colour)) { echo 'Brown'; } elseif( preg_match( '/rainbow.*/i', $colour)) { echo 'Multicolour'; } elseif( preg_match( '/orange.*/i', $colour)) { echo 'Orange'; } elseif( preg_match( '/leopard.*/i', $colour)) { echo 'Multicolour'; } elseif( preg_match( '/red.*/i', $colour)) { echo 'Red'; } elseif( preg_match( '/pink.*/i', $colour)) { echo 'Pink'; } elseif( preg_match( '/purple.*/i', $colour)) { echo 'Purple'; } elseif( preg_match( '/blue.*/i', $colour)) { echo 'Blue'; } elseif( preg_match( '/green.*/i', $colour)) { echo 'Green'; } elseif( preg_match( '/brown.*/i', $colour)) { echo 'Brown'; } elseif( preg_match( '/grey.*/i', $colour)) { echo 'Grey'; } elseif( preg_match( '/black.*/i', $colour)) { echo 'Black'; } elseif( preg_match( '/gold.*/i', $colour)) { echo 'Gold'; } elseif( preg_match( '/silver.*/i', $colour)) { echo 'Silver'; } elseif( preg_match( '/multi.*/i', $colour)) { echo 'Multicolour'; } elseif( preg_match( '/beige.*/i', $colour)) { echo 'Beige'; } elseif( preg_match( '/nude.*/i', $colour)) { echo 'Beige'; } ?>, <!-- size name --> <? echo $con_size[$x];?>, <!-- size map --> <? if ($con_size[$x] == 36) { echo "3 UK"; } elseif ($con_size[$x] == 37 ) { echo "4 UK"; } elseif ($con_size[$x] == 38) { echo "5 UK"; } elseif ($con_size[$x] == 39 ) { echo "6 UK"; } elseif ($con_size[$x] == 40 ) { echo "7 UK"; } elseif ($con_size[$x] == 41) { echo "8 UK"; } elseif ($con_size[$x] == 42) { echo "9 UK"; } elseif ($con_size[$x] == 43) { echo "10 UK"; } elseif ($con_size[$x] == 44 ) { echo "11 UK"; } elseif ($con_size[$x] == 45 ) { echo "12 UK"; } elseif ($con_size[$x] == 46 ) { echo "13 UK"; } elseif ($con_size[$x] == 47 ) { echo "14 UK"; } elseif ($con_size[$x] == 48 ) { echo "15 UK"; } elseif ($con_size[$x] == 365) { echo "3.5 UK"; } elseif ($con_size[$x] == 375 ) { echo "4.5 UK"; } elseif ($con_size[$x] == 385) { echo "5.5 UK"; } elseif ($con_size[$x] == 395 ) { echo "6.5 UK"; } elseif ($con_size[$x] == 405 ) { echo "7.5 UK"; } elseif ($con_size[$x] == 415) { echo "8.5 UK"; } elseif ($con_size[$x] == 425) { echo "9.5 UK"; } elseif ($con_size[$x] == 435) { echo "10.5 UK"; } elseif ($con_size[$x] == 445 ) { echo "11.5 UK"; } elseif ($con_size[$x] == 455 ) { echo "12.5 UK"; } elseif ($con_size[$x] == 465 ) { echo "13.5 UK"; } elseif ($con_size[$x] == 475 ) { echo "14.5 UK"; } elseif ($con_size[$x] == 485 ) { echo "15.5 UK"; } ?>, <br> <? // finish checking if size is available } } } ?> I've included an image of how the CSV file should appear. https://i.imgur.com/ZU3IFer.png Any help would be great.

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  • Get number of posts in a topic PHP

    - by Wayne
    How do I get to display the number of posts on a topic like a forum. I used this... (how very noobish): function numberofposts($n) { $sql = "SELECT * FROM posts WHERE topic_id = '" . $n . "'"; $result = mysql_query($sql) or die(mysql_error()); $count = mysql_num_rows($result); echo number_format($count); } The while loop of listing topics: <div class="topics"> <div class="topic-name"> <p><?php echo $row['topic_title']; ?></p> </div> <div class="topic-posts"> <p><?php echo numberofposts($row['topic_id']); ?></p> </div> </div> Although it is a bad method of doing this... All I need is to know what would be the best method, don't just point me out to a website, do it here, because I'm trying to learn much. Okay? :D Thanks.

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  • Recursive Function To Create Array

    - by mTuran
    Hi, i use kohana framework and i am trying to code recursive function to create category tree. My Categories Table id int(11) NO PRI NULL auto_increment name varchar(50) NO NULL parent_id int(11) NO NULL projects_count int(11) NO NULL My Example Which Is Not Work public static function category_list($parent_id = 0) { $result = Database::instance()->query(' SELECT name, projects_count FROM project_categories WHERE parent_id = ?', array($parent_id) ); $project_categories = array(); foreach($result as $row) { $project_categories[] = $row; Project_Categories_Model::factory()->category_list($parent_id + 1); } return $project_categories; }

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  • URL Rewrite query database?

    - by Liam
    Im trying to understand how URL rewriting works. I have the following link... mysite.com/profile.php?id=23 I want to rewrite the above url with the Users first and last name... mysite.com/directory/liam-gallagher From what Ive read however you specify the rule for what the url should be output as, But how do i query my table to get each users name? Sorry if this is hard to understand, ive confused myself!

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  • How can I prevent a double submit with jQuery or Javascript?

    - by kielie
    Hi guys, I keep getting duplicate entries in my database because of impatient users clicking the submit button multiple times. I googled and googled and found a few scripts, but none of them seem to be sufficient. How can I prevent these duplicate entries from occurring using javascript or preferably jQuery? Thanx in advance!

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  • AIR: sync gui with data-base?

    - by John Isaacks
    I am going to be building an AIR application that shows a list (about 1-25 rows of data) from a data-base. The data-base is on the web. I want the list to be as accurate as possible, meaning as soon as the data-base data changes, the list displayed in the app should update asap. I do not know of anyway that the air application could be notified when there is a change, I am thinking I am going to have to poll the data-base at certain intervals to keep an up to date list. So my question is, first is there any way to NOT have to keep checking the data-base? or if I do keep have to keep checking the data-base what is a reasonable interval to do that at? Thanks.

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  • PHP auto refresh page without losing user input

    - by Tony
    I'm working on a PHP collaboration software project. I have a page that shows the latest updates from other users who are adding content to the database, but also has a form input to allow the user to enter text. I am currently using this code to refresh the page automatically every 30 seconds: header('Refresh: 30'); The problem is that the header code refreshes the entire page, and not just what is pulled from the database. Is there any PHP code that will just pull any new data from the database without refreshing the entire page? If someone could point me in the right direction I'd appreciate it.

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  • Analyzing Web Application Speed

    - by Amy
    I'm a bit confused because the logical/programmer brain in me says that if all things are constant, the speed of a function must be constant. I am working on a PHP web application with jqGrid as a front end for showing the data. I am testing on my personal computer, so network traffic does not apply. I make an HTTP request to a PHP function, it returns the data, and then jqGrid renders it. What has me befuddled is that sometimes, Firebug reports that this is taking 300-600 milliseconds sometimes, and sometimes, it's taking 3.68 seconds. I can run the request over and over again, with very radically different response times. The query is the same. The number of users on the system is the same. No network latency. Same code. I'm not running other applications on the computer while testing. I could understand query caching improving performance on subsequent requests, but the speed is just fluctuating wildly with no rhyme or reason. So, my question is, what else can cause such variability in the response time? How can I determine what's doing it? More importantly, is there any way to get things more consistent?

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  • PHP in Wordpress Posts - Is this okay?

    - by Thomas
    I've been working with some long lists of information and I've come up with a good way to post it in various formats on my wordpress blog posts. I installed the exec-PHP plugin, which allows you to run php in posts. I then created a new table (NEWTABLE) in my wordpress database and filled that table with names, scores, and other stuff. I was then able to use some pretty simple code to display the information in a wordpress post. Below is an example, but you could really do whatever you wanted. My question is - is there a problem with doing this? with security? or memory? I could just type out all the information in each post, but this is really much nicer. Any thoughts are appreciated. <?php $theResult = mysql_query("SELECT * FROM NEWTABLE WHERE Score < 100 ORDER BY LastName"); while($row = mysql_fetch_array($theResult)) { echo $row['FirstName']; echo " " . $row['LastName']; echo " " . $row['Score']; echo "<br />"; } ?>

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  • SQL: GROUP BY after JOIN without overriding rows?

    - by krismeld
    I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

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  • Prevent two users from editing the same data

    - by Industrial
    Hi everyone, I have seen a feature in different web applications including Wordpress (not sure?) that warns a user if he/she opens an article/post/page/whatever from the database, while someone else is editing the same data simultaneously. I would like to implement the same feature in my own application and I have given this a bit of thought. Is the following example a good practice on how to do this? It goes a little something like this: 1) User A enters a the editing page for the mysterious article X. The database tableEvents is queried to make sure that no one else is editing the same page for the moment, which no one is by then. A token is then randomly being generated and is inserted into a database table called Events. 1) User B also want's to make updates to the article X. Now since our User A already is editing the article, the Events table is queried and looks like this: | timestamp | owner | Origin | token | ------------------------------------------------------------ | 1273226321 | User A | article-x | uniqueid## | 2) The timestamp is being checked. If it's valid and less than say 100 seconds old, a message appears and the user cannot make any changes to the requested article X: Warning: User A is currently working with this article. In the meantime, editing cannot be done. Please do something else with your life. 3) If User A decides to go on and save his changes, the token is posted along with all other data to update the database, and toggles a query to delete the row with token uniqueid##. If he decides to do something else instead of committing his changes, the article X will still be available for editing in 100 seconds for User B Let me know what you think about this approach! Wish everyone a great weekend!

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  • Correlate GROUP BY and LEFT JOIN on multiple criteria to show latest record?

    - by Sunbird
    In a simple stock management database, quantity of new stock is added and shipped until quantity reaches zero. Each stock movement is assigned a reference, only the latest reference is used. In the example provided, the latest references are never shown, the stock ID's 1,4 should have references charlie, foxtrot respectively, but instead show alpha, delta. How can a GROUP BY and LEFT JOIN on multiple criteria be correlated to show the latest record? http://sqlfiddle.com/#!2/6bf37/107 CREATE TABLE stock ( id tinyint PRIMARY KEY, quantity int, parent_id tinyint ); CREATE TABLE stock_reference ( id tinyint PRIMARY KEY, stock_id tinyint, stock_reference_type_id tinyint, reference varchar(50) ); CREATE TABLE stock_reference_type ( id tinyint PRIMARY KEY, name varchar(50) ); INSERT INTO stock VALUES (1, 10, 1), (2, -5, 1), (3, -5, 1), (4, 20, 4), (5, -10, 4), (6, -5, 4); INSERT INTO stock_reference VALUES (1, 1, 1, 'Alpha'), (2, 2, 1, 'Beta'), (3, 3, 1, 'Charlie'), (4, 4, 1, 'Delta'), (5, 5, 1, 'Echo'), (6, 6, 1, 'Foxtrot'); INSERT INTO stock_reference_type VALUES (1, 'Customer Reference'); SELECT stock.id, SUM(stock.quantity) as quantity, customer.reference FROM stock LEFT JOIN stock_reference AS customer ON stock.id = customer.stock_id AND stock_reference_type_id = 1 GROUP BY stock.parent_id

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