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  • Capture global touch events (Symbian)

    - by Leonth
    Basically I wanted what the pys60 module keycapture does (global capture of keystrokes) but I wanted to do this with the touchscreen. So if the program is running, all touch events can be intercepted and logged by the program. How is this possible?

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  • List of Django model instance foreign keys losing consistency during state changes.

    - by Joshua
    I have model, Match, with two foreign keys: class Match(model.Model): winner = models.ForeignKey(Player) loser = models.ForeignKey(Player) When I loop over Match I find that each model instance uses a unique object for the foreign key. This ends up biting me because it introduces inconsistency, here is an example: >>> def print_elo(match_list): ... for match in match_list: ... print match.winner.id, match.winner.elo ... print match.loser.id, match.loser.elo ... >>> print_elo(teacher_match_list) 4 1192.0000000000 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 >>> teacher_match_list[0].winner.elo = 3000 >>> print_elo(teacher_match_list) 4 3000 # Object 4 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 # Object 4 >>> I solved this problem like so: def unify_refrences(match_list): """Makes each unique refrence to a model instance non-unique. In cases where multiple model instances are being used django creates a new object for each model instance, even if it that means creating the same instance twice. If one of these objects has its state changed any other object refrencing the same model instance will not be updated. This method ensure that state changes are seen. It makes sure that variables which hold objects pointing to the same model all hold the same object. Visually this means that a list of [var1, var2] whose internals look like so: var1 --> object1 --> model1 var2 --> object2 --> model1 Will result in the internals being changed so that: var1 --> object1 --> model1 var2 ------^ """ match_dict = {} for match in match_list: try: match.winner = match_dict[match.winner.id] except KeyError: match_dict[match.winner.id] = match.winner try: match.loser = match_dict[match.loser.id] except KeyError: match_dict[match.loser.id] = match.loser My question: Is there a way to solve the problem more elegantly through the use of QuerySets without needing to call save at any point? If not, I'd like to make the solution more generic: how can you get a list of the foreign keys on a model instance or do you have a better generic solution to my problem? Please correct me if you think I don't understand why this is happening.

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  • Real-time data on webpage with jQuery

    - by Steven Hepting
    I would like a webpage that constantly updates a graph with new data as it arrives. Regularly, all the data you have is passed to the page at the beginning of the request. However, I need the page to be able to update itself with fresh information every few seconds to redraw the graph. Background The webpage will be similar to this http://www.panic.com/blog/2010/03/the-panic-status-board/. The data coming in will temperature values to be graphed measured by an Arduino and saved to the Django database (this part is already complete). Update It sounds as though the solution is to use the jQuery.ajax() function ( http://api.jquery.com/jQuery.ajax/) with a function as the .complete callback that will schedule another request several seconds later to a URL that will return the data in JSON format. How can that method be scheduled? With the .delay() function?

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  • Splitting only long words in string

    - by owca
    I have some random string, let's say : s = "This string has some verylongwordsneededtosplit" I'm trying to write a function trunc_string(string, len) that takes string as argument to operate on and 'len' as the number of chars after long words will be splitted. The result should be something like that str = trunc_string(s, 10) str = "This string has some verylongwo rdsneededt osplit" For now I have something like this : def truncate_long_words(s, num): """Splits long words in string""" words = s.split() for word in words: if len(word) > num: split_words = list(words) After this part I have this long word as a list of chars. Now I need to : join 'num' chars together in some word_part temporary list join all word_parts into one word join this word with the rest of words, that weren't long enough to be splitted. Should I make it in somehow similar way ? : counter = 0 for char in split_words: word_part.append(char) counter = counter+1 if counter == num And here I should somehow join all the word_part together creating word and further on

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  • SQLAlchemy custom query column

    - by thrillerator
    I have a declarative table defined like this: class Transaction(Base): __tablename__ = "transactions" id = Column(Integer, primary_key=True) account_id = Column(Integer) transfer_account_id = Column(Integer) amount = Column(Numeric(12, 2)) ... The query should be: SELECT id, (CASE WHEN transfer_account_id=1 THEN -amount ELSE amount) AS amount FROM transactions WHERE account_id = 1 OR transfer_account_id = 1 My code is: query = Transaction.query.filter_by(account_id=1, transfer_account_id=1) query = query.add_column(func.case(...).label("amount") But it doesn't replace the amount column. Been trying to do this with for hours and I don't want to use raw SQL.

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  • Can a CLSID be different for the same program installed on two different machines?

    - by uberjumper
    I am using comtypes to generate wrappers for a certain com library. I am having certain issues with a few things, that are not being generated properly. I can get around this by doing the missing work, manually. However can i depend on the fact that CLSID's will not change? Lets say: I install a program with the com library Foo 1.0, now i install the exact same version of that program on another PC, will the CLSID's of the interfaces change? This might be a terribly dumb question.

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  • How should I rewrite my code to make it amenable to unittesting?

    - by justin
    I've been trying to get started with unit-testing while working on a little cli program. My program basically parses the command line arguments and options, and decides which function to call. Each of the functions performs some operation on a database. So, for instance, I might have a create function: def create(self, opts, args): #I've left out the error handling. strtime = datetime.datetime.now().strftime("%D %H:%M") vals = (strtime, opts.message, opts.keywords, False) self.execute("insert into mytable values (?, ?, ?, ?)", vals) self.commit() Should my test case call this function, then execute the select sql to check that the row was entered? That sounds reasonable, but also makes the tests more difficult to maintain. Would you rewrite the function to return something and check for the return value? Thanks

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  • Parse http GET and POST parameters from BaseHTTPHandler?

    - by ataylor
    BaseHTTPHandler from the BaseHTTPServer module doesn't seem to provide any convenient way to access http request parameters. What is the best way to parse the GET parameters from the path, and the POST parameters from the request body? Right now, I'm using this for GET: def do_GET(self): parsed_path = urlparse.urlparse(self.path) try: params = dict([p.split('=') for p in parsed_path[4].split('&')]) except: params = {} This works for most cases, but I'd like something more robust that handles encodings and cases like empty parameters properly. Ideally, I'd like something small and standalone, rather than a full web framework.

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  • Hyphenate a random string to an exact format

    - by chrissygormley
    Hello, I am creating a random ID using the below code: from random import * import string # The characters to make up the random password chars = string.ascii_letters + string.digits def random_password(): return "".join(choice(chars) for x in range(32)) This will output something like: 60ff612332b741508bc4432e34ec1d3e I would like the format to be in this format: 60ff6123-32b7-4150-8bc4-432e34ec1d3e I was looking at the .split() method but can't see how to do this with a random id, also the hyphen's must be at these places so splitting them by a certain amount of digits is out. I'm asking is there a way to split these random id's by 8 number's then 4 etc. Thanks

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  • Issue using GAE appcfg.py

    - by JustSmith
    I get nothing out of appcfg.py besides the default output. I'm trying to upload some data to my development project with no luck at at all. From the instructions on the Google App Engine page the steps are as follows: Edit app.yaml update with appcfg.py make upload script upload with appcfg.py After step one I try to run the update and it never shows any success. The following commands product the same output: appcfg.py appcfg.py update appDir appcfg.py update appDir/ appcfg.py update /appDir If i try to follow the instructions from the appcfg.py output and type help upload and get: "help <action>" I get a response from the system, This command is not supported by the help utility. Try "update /?". cause I'm calling the system help command. If I use the command appcfg.py help upload I get the same result as just typing appcfg.py Can someone show me examples of the syntax to update the dev site, upload data to it and get appcfg.py to actually give help on its commands? Also I'm just assuming that the upload script and the .csv file that are being uploaded are in they myApp directory. Appreciate any help,

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  • Compound dictionary keys

    - by John Keyes
    I have a particular case where using compound dictionary keys would make a task easier. I have a working solution, but feel it is inelegant. How would you do it? context = { 'database': { 'port': 9990, 'users': ['number2', 'dr_evil'] }, 'admins': ['[email protected]', '[email protected]'], 'domain.name': 'virtucon.com' } def getitem(key, context): if hasattr(key, 'upper') and key in context: return context[key] keys = key if hasattr(key, 'pop') else key.split('.') k = keys.pop(0) if keys: try: return getitem(keys, context[k]) except KeyError, e: raise KeyError(key) if hasattr(context, 'count'): k = int(k) return context[k] if __name__ == "__main__": print getitem('database', context) print getitem('database.port', context) print getitem('database.users.0', context) print getitem('admins', context) print getitem('domain.name', context) try: getitem('database.nosuchkey', context) except KeyError, e: print "Error:", e Thanks.

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  • Adding a generic image field onto a ModelForm in django

    - by Prairiedogg
    I have two models, Room and Image. Image is a generic model that can tack onto any other model. I want to give users a form to upload an image when they post information about a room. I've written code that works, but I'm afraid I've done it the hard way, and specifically in a way that violates DRY. Was hoping someone who's a little more familiar with django forms could point out where I've gone wrong. Update: I've tried to clarify why I chose this design in comments to the current answers. To summarize: I didn't simply put an ImageField on the Room model because I wanted more than one image associated with the Room model. I chose a generic Image model because I wanted to add images to several different models. The alternatives I considered were were multiple foreign keys on a single Image class, which seemed messy, or multiple Image classes, which I thought would clutter my schema. I didn't make this clear in my first post, so sorry about that. Seeing as none of the answers so far has addressed how to make this a little more DRY I did come up with my own solution which was to add the upload path as a class attribute on the image model and reference that every time it's needed. # Models class Image(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') image = models.ImageField(_('Image'), height_field='', width_field='', upload_to='uploads/images', max_length=200) class Room(models.Model): name = models.CharField(max_length=50) image_set = generic.GenericRelation('Image') # The form class AddRoomForm(forms.ModelForm): image_1 = forms.ImageField() class Meta: model = Room # The view def handle_uploaded_file(f): # DRY violation, I've already specified the upload path in the image model upload_suffix = join('uploads/images', f.name) upload_path = join(settings.MEDIA_ROOT, upload_suffix) destination = open(upload_path, 'wb+') for chunk in f.chunks(): destination.write(chunk) destination.close() return upload_suffix def add_room(request, apartment_id, form_class=AddRoomForm, template='apartments/add_room.html'): apartment = Apartment.objects.get(id=apartment_id) if request.method == 'POST': form = form_class(request.POST, request.FILES) if form.is_valid(): room = form.save() image_1 = form.cleaned_data['image_1'] # Instead of writing a special function to handle the image, # shouldn't I just be able to pass it straight into Image.objects.create # ...but it doesn't seem to work for some reason, wrong syntax perhaps? upload_path = handle_uploaded_file(image_1) image = Image.objects.create(content_object=room, image=upload_path) return HttpResponseRedirect(room.get_absolute_url()) else: form = form_class() context = {'form': form, } return direct_to_template(request, template, extra_context=context)

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  • Requires a valid Date or x-amz-date header?

    - by Jordan Messina
    I'm getting the following error when attempting to upload a file to S3: S3StorageError: <?xml version="1.0" encoding="UTF-8"?> <Error><Code>AccessDenied</Code><Message>AWS authentication requires a valid Date or x-amz-date header</Message><RequestId>7910FF83F3FE17E2</RequestId><HostId>EjycXTgSwUkx19YNkpAoY2UDDur/0d5SMvGJUicpN6qCZFa2OuqcpibIR3NJ2WKB</HostId></Error> I'm using Django with Django-Storages and Imagekit My S3 settings in my settings.py looks as follows: locale.setlocale(locale.LC_TIME, 'en_US') DEFAULT_FILE_STORAGE = 'backends.s3.S3Storage' AWS_ACCESS_KEY_ID = '************************' AWS_SECRET_ACCESS_KEY = '*****************************' AWS_STORAGE_BUCKET_NAME = 'static.blabla.com' AWS_HEADERS = { 'x-amz-date': datetime.datetime.utcnow().strftime('%a, %d %b %Y %H:%M:%S GMT'), 'Expires': 'Thu, 15 Apr 2200 20:00:00 GMT', } from S3 import CallingFormat AWS_CALLING_FORMAT = CallingFormat.SUBDOMAIN Thanks for any help you can give!

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  • Renaming TurboGears 2's Repoze Fields with TGAdmin

    - by William Chambers
    I've been working on renaming TurboGears 2's Repoze 'groups' field to 'roles' to free the namespace and db tables for other purposes. Also roles makes much more sense to me then groups because I have a strong Drupal background. Now I have found some of the docs to do this such as these: http://www.turbogears.org/2.1/docs/main/Auth/Customization.html#customizing-the-model-structure-assumed-by-the-quickstart http://code.gustavonarea.net/repoze.what-quickstart/#customizing-the-model-definition However these only go part of the way. I have made (I'm pretty sure at least, I've double checked a few times.) all the changes required as you can see in this diff. This seems to work fine however I've ran into a rather major issue with the TurboGears Admin system. I've tried http://turbogears.org/2.0/docs/main/Extensions/Admin/index.html and it didn't seem to make any difference, however I'm not 100% sure I did it correctly. The problem occurs when I attempt to go to localhost/admin/permissions/. It causes a Internal Server Error and outputs the following error. http://pastebin.com/YWMH3SiU This error does not happen on the Roles/Users pages and the permissions /edit/1 also works. I'm running kubuntu 10.04 with TG 2.1b2. (I'm running the beta mostly for easier mako support which is really important.) Any help would be very appreciated.

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  • Django stupid mark_safe?

    - by Mark
    I wrote this little function for writing out HTML tags: def html_tag(tag, content=None, close=True, attrs={}): lst = ['<',tag] for key, val in attrs.iteritems(): lst.append(' %s="%s"' % (key, escape_html(val))) if close: if content is None: lst.append(' />') else: lst.extend(['>', content, '</', tag, '>']) else: lst.append('>') return mark_safe(''.join(lst)) Which worked great, but then I read this article on efficient string concatenation (I know it doesn't really matter for this, but I wanted consistency) and decided to update my script: def html_tag(tag, body=None, close=True, attrs={}): s = StringIO() s.write('<%s'%tag) for key, val in attrs.iteritems(): s.write(' %s="%s"' % (key, escape_html(val))) if close: if body is None: s.write(' />') else: s.write('>%s</%s>' % (body, tag)) else: s.write('>') return mark_safe(s.getvalue()) But now my HTML get escaped when I try to render it from my template. Everything else is exactly the same. It works properly if I replace the last line with return mark_safe(unicode(s.getvalue())). I checked the return type of s.getvalue(). It should be a str, just like the first function, so why is this failing?? Also fails with SafeString(s.getvalue()) but succeeds with SafeUnicode(s.getvalue()). I'd also like to point out that I used return mark_safe(s.getvalue()) in a different function with no odd behavior.

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  • One Line 'If' or 'For'...

    - by aTory
    Every so often on here I see someone's code and what looks to be a 'one-liner', that being a one line statement that performs in the standard way a traditional 'if' statement or 'for' loop works. I've googled around and can't really find what kind of ones you can perform? Can anyone advise and preferably give some examples? For example, could I do this in one line: example = "example" if "exam" in example: print "yes!" Or: for a in someList: list.append(splitColon.split(a))

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  • I need to know what link is clicked, how do i get these variables with cherrypy?

    - by user291071
    Lets say I display 3 links, I want to accomplish 2 things, know which link is clicked, and record this choice in a list/pickle or txt file but also capture this variable in cherrypy so I can perform another action. How do I do this? Its been suggested that I use a query string which makes sense but I can't get the querystring variable to cherrypy to use for further actions. So would anyone have a simple code of cherrypy with lets say 2 pages and have one page display 2 links with a querystring in each and the second page able to get that value?

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  • Perceptron Classification and Model Training

    - by jake pinedo
    I'm having an issue with understanding how the Perceptron algorithm works and implementing it. cLabel = 0 #class label: corresponds directly with featureVectors and tweets for m in range(miters): for point in featureVectors: margin = answers[cLabel] * self.dot_product(point, w) if margin <= 0: modifier = float(lrate) * float(answers[cLabel]) modifiedPoint = point for x in modifiedPoint: if x != 0: x *= modifier newWeight = [modifiedPoint[i] + w[i] for i in range(len(w))] w = newWeight self._learnedWeight = w This is what I've implemented so far, where I have a list of class labels in answers and a learning rate (lrate) and a list of feature vectors. I run it for the numbers of iterations in miter and then get the final weight at the end. However, I'm not sure what to do with this weight. I've trained the perceptron and now I have to classify a set of tweets, but I don't know how to do that. EDIT: Specifically, what I do in my classify method is I go through and create a feature vector for the data I'm given, which isn't a problem at all, and then I take the self._learnedWeight that I get from the earlier training code and compute the dot-product of the vector and the weight. My weight and feature vectors include a bias in the 0th term of the list so I'm including that. I then check to see if the dotproduct is less than or equal to 0: if so, then I classify it as -1. Otherwise, it's 1. However, this doesn't seem to be working correctly.

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  • Graphing a line and scatter points using Matplotlib?

    - by Patrick O'Doherty
    Hi guys I'm using matplotlib at the moment to try and visualise some data I am working on. I'm trying to plot around 6500 points and the line y = x on the same graph but am having some trouble in doing so. I can only seem to get the points to render and not the line itself. I know matplotlib doesn't plot equations as such rather just a set of points so I'm trying to use and identical set of points for x and y co-ordinates to produce the line. The following is my code from matplotlib import pyplot import numpy from pymongo import * class Store(object): """docstring for Store""" def __init__(self): super(Store, self).__init__() c = Connection() ucd = c.ucd self.tweets = ucd.tweets def fetch(self): x = [] y = [] for t in self.tweets.find(): x.append(t['positive']) y.append(t['negative']) return [x,y] if __name__ == '__main__': c = Store() array = c.fetch() t = numpy.arange(0., 0.03, 1) pyplot.plot(array[0], array[1], 'ro', t, t, 'b--') pyplot.show() Any suggestions would be appreciated, Patrick

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  • getting keyboard events with pyqt

    - by Moayyad Yaghi
    hello i converted recently from wxpython to pyqt and im still facing alot of problems since im still noob in pyqt so is it possible to detected if user pressed (CTRL+key ) in pyqt ? and how ? i've been trying to find an answer for this for 3 days . if you know website or a good place to learn pyqt, it will be highly appreciated thanx in advance

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  • Javascript with Django?

    - by Rosarch
    I know this has been asked before, but I'm having a hard time setting up JS on my Django web app, even though I'm reading the documentation. I'm running the Django dev server. My file structure looks like this: mysite/ __init__.py MySiteDB manage.py settings.py urls.py myapp/ __init__.py admin.py models.py test.py views.py templates/ index.html Where do I want to put the Javascript and CSS? I've tried it in a bunch of places, including myapp/, templates/ and mysite/, but none seem to work. From index.html: <head> <title>Degree Planner</title> <script type="text/javascript" src="/scripts/JQuery.js"></script> <script type="text/javascript" src="/media/scripts/sprintf.js"></script> <script type="text/javascript" src="/media/scripts/clientside.js"></script> </head> From urls.py: (r'^admin/', include(admin.site.urls)), (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'media'}) (r'^.*', 'mysite.myapp.views.index'), I suspect that the serve() line is the cause of errors like: TypeError at /admin/auth/ 'tuple' object is not callable Just to round off the rampant flailing, I changed these settings in settings.py: MEDIA_ROOT = '/media/' MEDIA_URL = 'http://127.0.0.1:8000/media'

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  • Parsing names with pyparsing

    - by johnthexiii
    I have a file of names and ages, john 25 bob 30 john bob 35 Here is what I have so far from pyparsing import * data = ''' john 25 bob 30 john bob 35 ''' name = Word(alphas + Optional(' ') + alphas) rowData = Group(name + Suppress(White(" ")) + Word(nums)) table = ZeroOrMore(rowData) print table.parseString(data) the output I am expecting is [['john', 25], ['bob', 30], ['john bob', 35]] Here is the stacktrace Traceback (most recent call last): File "C:\Users\mccauley\Desktop\client.py", line 11, in <module> eventType = Word(alphas + Optional(' ') + alphas) File "C:\Python27\lib\site-packages\pyparsing.py", line 1657, in __init__ self.name = _ustr(self) File "C:\Python27\lib\site-packages\pyparsing.py", line 122, in _ustr return str(obj) File "C:\Python27\lib\site-packages\pyparsing.py", line 1743, in __str__ self.strRepr = "W:(%s)" % charsAsStr(self.initCharsOrig) File "C:\Python27\lib\site-packages\pyparsing.py", line 1735, in charsAsStr if len(s)>4: TypeError: object of type 'And' has no len()

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