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  • Django: Serving Media Behind Custom URL

    - by TheLizardKing
    So I of course know that serving static files through Django will send you straight to hell but I am confused on how to use a custom url to mask the true location of the file using Django. http://stackoverflow.com/questions/2681338/django-serving-a-download-in-a-generic-view but the answer I accepted seems to be the "wrong" way of doing things. urls.py: url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), views.py: def song_download(request, song_id): song = Song.objects.get(id=song_id) fsock = open(os.path.join(song.path, song.filename)) response = HttpResponse(fsock, mimetype='audio/mpeg') response['Content-Disposition'] = "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response This solution works perfectly but not perfectly enough it turns out. How can I avoid having a direct link to the mp3 while still serving through nginx/apache? EDIT 1 - ADDITIONAL INFO Currently I can get my files by using an address such as: http://www.example.com/music/song/1692/download/ But the above mentioned method is the devil's work. How can I accomplished what I get above while still making nginx/apache serve the media? Is this something that should be done at the webserver level? Some crazy mod_rewrite? http://static.example.com/music/Aphex%20Twin%20-%20Richard%20D.%20James%20(V0)/10%20Logon-Rock%20Witch.mp3

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  • JSON serialization of Google App Engine models

    - by user111677
    I've been search for quite a while with no success. My project isn't using Django, is there a simple way to serialize App Engine models (google.appengine.ext.db.Model) into JSON or do I need to write my own serializer? My model class is fairly simple. For instance: class Photo(db.Model): filename = db.StringProperty() title = db.StringProperty() description = db.StringProperty(multiline=True) date_taken = db.DateTimeProperty() date_uploaded = db.DateTimeProperty(auto_now_add=True) album = db.ReferenceProperty(Album, collection_name='photo') Thanks in advance.

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  • cannot output a json encoded dict containing accents (noob inside)

    - by user296546
    Hi all, here is a fairly simple example wich is driving me nuts since a couple of days. Considering the following script: # -*- coding: utf-8 -* from json import dumps as json_dumps machaine = u"une personne émérite" print(machaine) output = {} output[1] = machaine jsonoutput = json_dumps(output) print(jsonoutput) The result of this from cli: une personne émérite {"1": "une personne \u00e9m\u00e9rite"} I don't understand why their such a difference between the two strings. i have been trying all sorts of encode, decode etc but i can't seem to be able to find the right way to do it. Does anybody has an idea ? Thanks in advance. Matthieu

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  • Rewriting Live TCP Streams

    - by user213060
    I want to rewrite TCP/IP streams. Ettercap's etterfilter command lets you perform simple live replacements of TCP/IP data based on fixed strings or regexes. Example: http://ettercap.sourceforge.net/forum/viewtopic.php?t=2833 I would like to rewrite streams based on my own filter program instead of just simple string replacements. Anyone have an idea of how to do this? Is there anything other than Ettercap that can do live replacement like this, maybe as a plugin to a VPN software or something? Thanks!

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  • How to call Twiter's Streaming/Filter Feed with urllib2/httplib?

    - by Simon
    Update: I switched this back from answered as I tried the solution posed in cogent Nick's answer and switched to Google's urlfetch: logging.debug("starting urlfetch for http://%s%s" % (self.host, self.url)) result = urlfetch.fetch("http://%s%s" % (self.host, self.url), payload=self.body, method="POST", headers=self.headers, allow_truncated=True, deadline=5) logging.debug("finished urlfetch") but unfortunately finished urlfetch is never printed - I see the timeout happen in the logs (it returns 200 after 5 seconds), but execution doesn't seem tor return. Hi All- I'm attempting to play around with Twitter's Streaming (aka firehose) API with Google App Engine (I'm aware this probably isn't a great long term play as you can't keep the connection perpetually open with GAE), but so far I haven't had any luck getting my program to actually parse the results returned by Twitter. Some code: logging.debug("firing up urllib2") req = urllib2.Request(url="http://%s%s" % (self.host, self.url), data=self.body, headers=self.headers) logging.debug("called urlopen for %s %s, about to call urlopen" % (self.host, self.url)) fobj = urllib2.urlopen(req) logging.debug("called urlopen") When this executes, unfortunately, my debug output never shows the called urlopen line printed. I suspect what's happening is that Twitter keeps the connection open and urllib2 doesn't return because the server doesn't terminate the connection. Wireshark shows the request being sent properly and a response returned with results. I tried adding Connection: close to my request header, but that didn't yield a successful result. Any ideas on how to get this to work? thanks -Simon

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  • How to limit choice field options based on another choice field in django admin

    - by umnik700
    I have the following models: class Category(models.Model): name = models.CharField(max_length=40) class Item(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) class Demo(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) item = models.ForeignKey(Item) In the admin interface when creating a new Demo, after user picks category from the dropdown, I would like to limit the number of choices in the "items" drop-down. If user selects another category then the item choices should update accordingly. I would like to limit item choices right on the client, before it even hits the form validation on the server. This is for usability, because the list of items could be 1000+ being able to narrow it down by category would help to make it more manageable. Is there a "django-way" of doing it or is custom JavaScript the only option here?

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  • socket.shutdown vs socket.close

    - by Jason Baker
    I recently saw a bit of code that looked like this (with sock being a socket object of course): sock.shutdown(socket.SHUT_RDWR) sock.close() What exactly is the purpose of calling shutdown on the socket and then closing it? If it makes a difference, this socket is being used for non-blocking IO.

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  • Inside a decorator-class, access instance of the class which contains the decorated method

    - by ifischer
    I have the following decorator, which saves a configuration file after a method decorated with @saveconfig is called: class saveconfig(object): def __init__(self, f): self.f = f def __call__(self, *args): self.f(object, *args) # Here i want to access "cfg" defined in pbtools print "Saving configuration" I'm using this decorator inside the following class. After the method createkvm is called, the configuration object self.cfg should be saved inside the decorator: class pbtools() def __init__(self): self.configfile = open("pbt.properties", 'r+') # This variable should be available inside my decorator self.cfg = ConfigObj(infile = self.configfile) @saveconfig def createkvm(self): print "creating kvm" My problem is that i need to access the object variable self.cfg inside the decorator saveconfig. A first naive approach was to add a parameter to the decorator which holds the object, like @saveconfig(self), but this doesn't work. How can I access object variables of the method host inside the decorator? Do i have to define the decorator inside the same class to get access?

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  • Reliable and fast way to convert a zillion ODT files in PDF?

    - by Marco Mariani
    I need to pre-produce a million or two PDF files from a simple template (a few pages and tables) with embedded fonts. Usually, I would stay low level in a case like this, and compose everything with a library like ReportLab, but I joined late in the project. Currently, I have a template.odt and use markers in the content.xml files to fill with data from a DB. I can smoothly create the ODT files, they always look rigth. For the ODT to PDF conversion, I'm using openoffice in server mode (and PyODConverter w/ named pipe), but it's not very reliable: in a batch of documents, there is eventually a point after which all the processed files are converted into garbage (wrong fonts and letters sprawled all over the page). Problem is not predictably reproducible (does not depend on the data), happens in OOo 2.3 and 3.2, in Ubuntu, XP, Server 2003 and Windows 7. My Heisenbug detector is ticking. I tried to reduce the size of batches and restarting OOo after each one; still, a small percentage of the documents are messed up. Of course I'll write about this on the Ooo mailing lists, but in the meanwhile, I have a delivery and lost too much time already. Where do I go? Completely avoid the ODT format and go for another template system. Suggestions? Anything that takes a few seconds to run is way too slow. OOo takes around a second and it sums to 15 days of processing time. I had to write a program for clustering the jobs over several clients. Keep the format but go for another tool/program for the conversion. Which one? There are many apps in the shareware or commercial repositories for windows, but trying each one is a daunting task. Some are too slow, some cannot be run in batch without buying it first, some cannot work from command line, etc. Open source tools tend not to reinvent the wheel and often depend on openoffice. Converting to an intermediate .DOC format could help to avoid the OOo bug, but it would double the processing time and complicate a task that is already too hairy. Try to produce the PDFs twice and compare them, discarding the whole batch if there's something wrong. Although the documents look equal, I know of no way to compare the binary content. Restart OOo after processing each document. it would take a lot more time to produce them it would lower the percentage of the wrong files, and make it very hard to identify them. Go for ReportLab and recreate the pages programmatically. This is the approach I'm going to try in a few minutes. Learn to properly format bulleted lists Thanks a lot.

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  • wx Menu disappears from frame when shown as a popup

    - by Adam Fraser
    I'm trying to create a wx.Menu that will be shared between a popup (called on right-click), and a sub menu accessible from the frame menubar. The following code demonstrates the problem. If you open the "MENUsubmenu" from the menubar the item "asdf" is visible. If you right click on the frame content area, "asdf" will be visible from there as well... however, returning to the menubar, you will find that "MENUsubmenu" is vacant. Why is this happening and how can I fix it? import wx app = wx.PySimpleApp() m = wx.Menu() m.Append(-1, 'asdf') def show_popup(evt): ''' R-click callback ''' f.PopupMenu(m, (evt.X, evt.Y)) f = wx.Frame(None) f.SetMenuBar(wx.MenuBar()) frame_menu = wx.Menu() f.MenuBar.Append(frame_menu, 'MENU') frame_menu.AppendMenu(-1,'submenu', m) f.Show() f.Bind(wx.EVT_RIGHT_DOWN, show_popup) app.MainLoop() Interestingly, appending the menu to MenuBar works, but is not the behavior I want: import wx app = wx.PySimpleApp() m = wx.Menu() m.Append(-1, 'asdf') def show_popup(evt): f.PopupMenu(m, (evt.X, evt.Y)) f = wx.Frame(None) f.SetMenuBar(wx.MenuBar()) f.MenuBar.Append(m, 'MENU') f.Show() f.Bind(wx.EVT_RIGHT_DOWN, show_popup) app.MainLoop()

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  • Graphing a line and scatter points using Matplotlib?

    - by Patrick O'Doherty
    Hi guys I'm using matplotlib at the moment to try and visualise some data I am working on. I'm trying to plot around 6500 points and the line y = x on the same graph but am having some trouble in doing so. I can only seem to get the points to render and not the line itself. I know matplotlib doesn't plot equations as such rather just a set of points so I'm trying to use and identical set of points for x and y co-ordinates to produce the line. The following is my code from matplotlib import pyplot import numpy from pymongo import * class Store(object): """docstring for Store""" def __init__(self): super(Store, self).__init__() c = Connection() ucd = c.ucd self.tweets = ucd.tweets def fetch(self): x = [] y = [] for t in self.tweets.find(): x.append(t['positive']) y.append(t['negative']) return [x,y] if __name__ == '__main__': c = Store() array = c.fetch() t = numpy.arange(0., 0.03, 1) pyplot.plot(array[0], array[1], 'ro', t, t, 'b--') pyplot.show() Any suggestions would be appreciated, Patrick

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  • Favorite Django Tips & Features?

    - by Haes
    Inspired by the question series 'Hidden features of ...', I am curious to hear about your favorite Django tips or lesser known but useful features you know of. Please, include only one tip per answer. Add Django version requirements if there are any.

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  • Django templates check condition

    - by Hulk
    If there are are no values in the table how can should the code be to indicate no name found else show the drop down box in the below code {% for name in dict.names %} <option value="{{name.id}}" {% for selected_id in selected_name %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.firstname}}</option>{% endfor %} </select> Thanks..

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  • Writing a blocking wrapper around twisted's IRC client

    - by Andrey Fedorov
    I'm trying to write a dead-simple interface for an IRC library, like so: import simpleirc connection = simpleirc.Connect('irc.freenode.net', 6667) channel = connection.join('foo') find_command = re.compile(r'google ([a-z]+)').findall for msg in channel: for t in find_command(msg): channel.say("http://google.com/search?q=%s" % t) Working from their example, I'm running into trouble (code is a bit lengthy, so I pasted it here). Since the call to channel.__next__ needs to be returned when the callback <IRCClient instance>.privmsg is called, there doesn't seem to be a clean option. Using exceptions or threads seems like the wrong thing here, is there a simpler (blocking?) way of using twisted that would make this possible?

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  • Sort and limit queryset by comment count and date using queryset.extra() (django)

    - by thornomad
    I am trying to sort/narrow a queryset of objects based on the number of comments each object has as well as by the timeframe during which the comments were posted. Am using a queryset.extra() method (using django_comments which utilizes generic foreign keys). I got the idea for using queryset.extra() (and the code) from here. This is a follow-up question to my initial question yesterday (which shows I am making some progress). Current Code: What I have so far works in that it will sort by the number of comments; however, I want to extend the functionality and also be able to pass a time frame argument (eg, 7 days) and return an ordered list of the most commented posts in that time frame. Here is what my view looks like with the basic functionality in tact: import datetime from django.contrib.comments.models import Comment from django.contrib.contenttypes.models import ContentType from django.db.models import Count, Sum from django.views.generic.list_detail import object_list def custom_object_list(request, queryset, *args, **kwargs): '''Extending the list_detail.object_list to allow some sorting. Example: http://example.com/video?sort_by=comments&days=7 Would get a list of the videos sorted by most comments in the last seven days. ''' try: # this is where I started working on the date business ... days = int(request.GET.get('days', None)) period = datetime.datetime.utcnow() - datetime.timedelta(days=int(days)) except (ValueError, TypeError): days = None period = None sort_by = request.GET.get('sort_by', None) ctype = ContentType.objects.get_for_model(queryset.model) if sort_by == 'comments': queryset = queryset.extra(select={ 'count' : """ SELECT COUNT(*) AS comment_count FROM django_comments WHERE content_type_id=%s AND object_pk=%s.%s """ % ( ctype.pk, queryset.model._meta.db_table, queryset.model._meta.pk.name ), }, order_by=['-count']).order_by('-count', '-created') return object_list(request, queryset, *args, **kwargs) What I've Tried: I am not well versed in SQL but I did try just to add another WHERE criteria by hand to see if I could make some progress: SELECT COUNT(*) AS comment_count FROM django_comments WHERE content_type_id=%s AND object_pk=%s.%s AND submit_date='2010-05-01 12:00:00' But that didn't do anything except mess around with my sort order. Any ideas on how I can add this extra layer of functionality? Thanks for any help or insight.

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  • Fastest way to generate delimited string from 1d numpy array

    - by Abiel
    I have a program which needs to turn many large one-dimensional numpy arrays of floats into delimited strings. I am finding this operation quite slow relative to the mathematical operations in my program and am wondering if there is a way to speed it up. For example, consider the following loop, which takes 100,000 random numbers in a numpy array and joins each array into a comma-delimited string. import numpy as np x = np.random.randn(100000) for i in range(100): ",".join(map(str, x)) This loop takes about 20 seconds to complete (total, not each cycle). In contrast, consider that 100 cycles of something like elementwise multiplication (x*x) would take than one 1/10 of a second to complete. Clearly the string join operation creates a large performance bottleneck; in my actual application it will dominate total runtime. This makes me wonder, is there a faster way than ",".join(map(str, x))? Since map() is where almost all the processing time occurs, this comes down to the question of whether there a faster to way convert a very large number of numbers to strings.

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  • How to get "paster request" to use config host value instead of localhost?

    - by mmartinez
    I'm trying to access my pylons application via cron job to send notifications to my users. The way I'm doing this is by running the application using something like: paster request myconfig.ini /maintenance/do In the actual controller I check for the "paste.command_request" to block public access. Everything works but the only problem is that within the notifications that I send to my users there is a link to their profile and the host is "localhost" which should instead be the domain name of the application. When the notifications are sent from within the served application (say, a user modifies their settings on the site) the notifications have the correct url. I am using mako to render my email tamplates and within the template I am using the "pylons.url" method with "qualified" set to "True". Am I missing something here? Thanks in advance.

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  • stdout and stderr anomalies

    - by momo
    from the interactive prompt: >>> import sys >>> sys.stdout.write('is the') is the6 what is '6' doing there? another example: >>> for i in range(3): ... sys.stderr.write('new black') ... 9 9 9 new blacknew blacknew black where are the numbers coming from?

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  • Preserve time stamp when shrinking an image

    - by Ckhrysze
    My digital camera takes pictures with a very high resolution, and I have a PIL script to shrink them to 800x600 (or 600x800). However, it would be nice for the resultant file to retain the original timestamp. I noticed in the docs that I can use a File object instead of a name in PIL's image save method, but I don't know if that will help or not. My code is basically name, ext = os.path.splitext(filename) # open an image file (.bmp,.jpg,.png,.gif) you have in the working folder image = Image.open(filename) width = 800 height = 600 w, h = image.size if h > w: width = 600 height = 800 name = name + ".jpg" shunken = image.resize((width, height), Image.ANTIALIAS) shunken.save(name) Thank you for any help you can give!

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  • django admin site make CharField a PasswordInput

    - by Paul
    I have a Django site in which the site admin inputs their Twitter Username/Password in order to use the Twitter API. The Model is set up like this: class TwitterUser(models.Model): screen_name = models.CharField(max_length=100) password = models.CharField(max_length=255) def __unicode__(self): return self.screen_name I need the Admin site to display the password field as a password input, but can't seem to figure out how to do it. I have tried using a ModelAdmin class, a ModelAdmin with a ModelForm, but can't seem to figure out how to make django display that form as a password input...

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