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  • handle an arrray posted with $.ajax (jquery) to a webservice

    - by burktelefon
    I'm trying to post data to a webservice (asp.net 3.5), like below (two variants, one commented): var array = [3, 2, 5, 1, 7]; var jsonString = JSON.stringify(array); //var jsonString = '{ "firstName": "John", "lastName": "Smith", "age": 25, "address": { "streetAddress": "21 2nd Street", "city": "New York", "state": "NY", "postalCode": "10021" }, "phoneNumber": [ { "type": "home", "number": "212 555-1234" }, { "type": "fax", "number": "646 555-4567" } ] }' $.ajax({ type: "POST", url: "WebService2.asmx/AddRoute", data: jsonString, contentType: "application/json; charset=utf-8", dataType: "json", processData: "false", error: function(msg) { alert('error' + msg.toString); } }); So I need a matching webmethod to recieve it. Something like this: [WebMethod] public string AddRoute(/* xxx */) { //handle data } Could someone please elaborate on how I can fetch the data, where I've typed "xxx"? I would have thought "int[] array" would do the trick, but it's not working. Any help would be greatly appreciated :)

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  • Need help... how to add md5 to password field in php?

    - by jones
    Hi mates, i looking some help and nice attention here.. i bought some php script many years ago and now no suport anymore... i just want to add md5 to password field.. here my form: <?php $SQL = "SELECT * from USERS WHERE USERNAME = '$_SESSION[username]'"; $result = @mysql_query( $SQL ); $row = @mysql_fetch_array( $result ); include 'menu.php'; ?> <FORM METHOD="post" ACTION="?page=query_client"> <INPUT TYPE="hidden" NAME="controller" VALUE="USERS~update~account_details&up=1~<?php echo $row[ID]; ?>"> <TABLE CLASS="basictable"> <TR> <TD CLASS="tdmenu" WIDTH="40%">Username</TD> <TD CLASS="tdmenu" WIDTH="60%"> <b><?php echo $row[USERNAME]; ?></b> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Password *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="PASSWORD" NAME="PASSWORD" SIZE="40" VALUE="<?php echo $row[PASSWORD]; ?>"> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Email Address *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="EMAIL" SIZE="40" VALUE="<?php echo $row[EMAIL]; ?>"> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Full Name *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="FULLNAME" SIZE="40" VALUE="<?php echo $row[FULLNAME]; ?>"> </TD> <TR> <TD CLASS="tdmenu" WIDTH="40%">Address *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="ADDRESS1" SIZE="40" VALUE="<?php echo $row[ADDRESS1]; ?>"> </TD> </TR> <BR> <TABLE CLASS="basictable"> <TR> <TD CLASS="tdhead2" > <DIV ALIGN="CENTER"><B> <INPUT TYPE="submit" NAME="Submit" VALUE="Submit"> </B></DIV> </TD> </TR> </TABLE> </FORM> and the it self as query_client.php inside look like: <?PHP @session_start(); $controller = $_POST['controller']; $pieces = explode("~", $controller); $table = $pieces[0]; $qt = $pieces[1]; $return = $pieces[2]; $id = $pieces[3]; $hack = $pieces[4]; if ($qt == insert) $qt = 'INSERT INTO'; if ($qt == update) { $qt = 'UPDATE'; $end = "WHERE ID = '$id'"; } $pre = array_keys( $_POST ); mysql_query ("CREATE TABLE IF NOT EXISTS `$table` (`ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY ( `id` ) )"); $count = count($pre); $count = $count - 2; $sql = "$qt $table SET"; for ($i=0; $i < $count; $i++) { $x=$i+1; $y = $_POST[$pre[$x]]; $d = $y; mysql_query ("ALTER TABLE `$table` ADD `$pre[$x]` TEXT NOT NULL"); $sql .= " `$pre[$x]` = '$d',"; } $sql .= " ID = '$id' $end"; $query = mysql_query($sql) or die("$sql_error" . mysql_error()); if (empty($hack)) { } else { $pieces = explode("/", $hack); $h0 = $pieces[0]; $h1 = $pieces[1]; $h2 = $pieces[2]; $h3 = $pieces[3]; $h4 = $pieces[4]; $h5 = $pieces[5]; mysql_query ("ALTER TABLE `$table` $h0 $h1 $h2 $h3 $h4 $h5"); $query = mysql_query($sql) or die("$sql_error" . mysql_error()); } if (isset($_GET[inc])) include "$_GET[inc].php"; ?> so please help me how to add md5 in PASSWORD field? thanks in advance..

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  • In Spring MVC, is it possible to have different return types in one request handler method?

    - by Bobo
    For example, if a request succeeds, I will return a View ,if not, return a String indicating error message and set the content-type to either xml or json. Based on what I read, seems like I should use "void" as the return type for handler methods. Check this out: "void if the method handles the response itself (by writing the response content directly, declaring an argument of type ServletResponse / HttpServletResponse for that purpose) or if the view name is supposed to be implicitly determined through a RequestToViewNameTranslator (not declaring a response argument in the handler method signature)."(Spring Framework reference). What I dont understand is what " the view name is supposed to be implicitly determined through a RequestToViewNameTranslator (not declaring a response argument in the handler method signature)" means? Any anyone give me an example?

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  • PHP-OOP extending two classes?

    - by user1292810
    I am very beginner to OOP and now I am trying to write some PHP class to connect with FTP server. class ftpConnect { private $server; private $user; private $password; private $connection_id; private $connection_correct = false; public function __construct($server, $user = "anonymous", $password = "[email protected]") { $this->server = $server; $this->user = $user; $this->password = $password; $this->connection_id = ftp_connect($this->server); $this->connection_correct = ftp_login($this->connection_id, $this->user, $this->password); if ( (!$this->connection_id) || (!$this->connection_correct) ){ echo "Error! Couldn't connect to $this->server"; var_dump($this->connection_id); var_dump($this->connection_correct); return false; } else { echo "Successfully connected to $this->server, user: $this->user"; $this->connection_correct = true; return true; } } } I reckon that body of the class is insignificant at the moment. Main issue is that I have some problems with understanding OOP idea. I wanted to add sending emails every time, when the code is run. I have downloaded PHPMailer Class and extended my class with it: class ftpConnect extends PHPMailer {...} I have added some variables and methods and everything works as expected to that point. I thought: why not to add storing everything in database. Everytime user runs above code, proper information should be stored in database. I could edit my ftpConnect class and add database connecting to the constructor, and some other methods to updating tables. But database connecting and all that stuff could be used by other classes in the future, so it definitely should be implemented in seperate class. But my "main" ftpConnect class already extends one class and could not extend not a single one more. I have no idea how can I resolve this problem. Maybe my ftpConnect class is to complex and I should somehow divide it into couple smaller classes? Any help is much appreciated.

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  • alternative to lag SQL command

    - by mahen
    I have a table which has a table like this. Month-----Book_Type-----sold_in_Dollars Jan----------A------------ 100 Jan----------B------------ 120 Feb----------A------------ 50 Mar----------A------------ 60 Mar----------B------------ 30 and so on I have to calculate the expected sales for each month and book type based on the last 2 months sales. So for March and type A it would be (100+50)/2 = 75 For March and type B it is 120/1 since no data for Feb is there. I was trying to use the lag function but it wouldn't work since there is data missing in a few rows. Any ideas on this?

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  • What is wrong with selecting with my drop down element.

    - by Babiker
    <html> <head> <script type='text/javascript' language='javascript' src="http://localhost/javascript/jquery-1.4.2.js"> </script> <script type='text/javascript' language='javascript'> $(document).ready(function(){ $("#button").mousedown(function(){ dropDownMenu = $("#dropDownMenu"); alert(dropDownMenu.options[0].text); }); }); </script> </head> <body> <select id="dropDownMenu"><option>Test</option></select><br> <input id="button" type="button"> </body> </html>

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  • Rails - inheritance hierarchy of classes where a subtype can play two roles

    - by Miquel
    I need to model Owners and Rentees in an application, so you have stuff that is always owned by someone and can be rented for someone else. I first approached this problem with Single Table Inheritance because both types of person will share all attributes, so you would have a model called Person associated to a table people with Owner and Rentee inheriting from Person. The problem is that Single type inheritance discerns subtypes using a field type and therefore a record in the table can represent either an Owner or a Rentee but not both at the same time, while in the real context you can have an Owner which is renting something from another Owner and therefore that person is at the same time an Owner and a Rentee. How would you approach this problem? Would you use separated tables for owners and rentees? Is there any other type of table inheritance in Rails?

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  • Histrogram matching - image processing - c/c++

    - by Raj
    Hello I have two histograms. int Hist1[10] = {1,4,3,5,2,5,4,6,3,2}; int Hist1[10] = {1,4,3,15,12,15,4,6,3,2}; Hist1's distribution is of type multi-modal; Hist2's distribution is of type uni-modal with single prominent peak. My questions are Is there any way that i could determine the type of distribution programmatically? How to quantify whether these two histograms are similar/dissimilar? Thanks

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  • how can i send jquery ajax http request with php

    - by testkhan
    i have following form... <form action="http://mydomain.com/get.php" method="post"> <input type="hidden" value="thisisvalue" name="hdnvalue"> <input type="text" name="cost" id="cost"><br><br> <textarea id="msg" name="message"></textarea><br><br> <input type="submit" value="Send" id="send"> </form> the get.php file will response in 1 or 0 i.e 1 means recieved and 0 means not recieved now i want to send it to http://mydomain.com/get.php via http request with jquery ajax how can i do that get the returned value..

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  • Jquery - how i can get the video src value?

    - by 3gwebtrain
    i need to get the value of a video and need to change in to new value... for that i used this function: var video = $('#task2ResultVideo').get(0); console.log($(video).attr('poster')); // i am getting this $(video).attr('src',function(num,val){ console.log(num,val) // i am not getting this.. }) ? HTML: <video id="task2ResultVideo" autobuffer poster="img/task2-results-host-poster.jpg"> <source src="Video/webm/Task_2.4a_Host_treated.webm" type="video/webm" /> <source src="Video/ogv/Task_2.4a_Host_treated.theora.ogv" type="video/ogg" /> <source src="Video/MP4/Task_2.4a_Host_treated.mp4" type="video/mp4" /> </video>? But i am not able to get the values. what is wrong with my code? in case if i get the value how can i change the src? any suggestion please?

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  • Which code snipplets in PHP can create a input form, which creates a new set of data in my mysql dat

    - by smiyazaki
    I am using the Google Maps API with parts in javascript and others in PHP. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> Google Maps AJAX + mySQL/PHP Example // var iconBlue = new GIcon(); iconBlue.image = 'icon.png'; iconBlue.shadow = ''; iconBlue.iconSize = new GSize(19, 19); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'icon.png'; iconRed.shadow = ''; iconRed.iconSize = new GSize(19, 19); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.setMapType(G_SATELLITE_MAP); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); // Change this depending on the name of your PHP file GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> (I suppose the php will be called by "GDownloadUrl("phpsqlajax_genxml.php", function(data) { ..." in the javascript part of the sourcecode of phpsqlajax_map.htm) Now I need another php file and the code snipplets for it, which creates an input form where I can add some new locations to the google map. Following code is used to create the xml file here: http://detektors.de/maptest/phpsqlajax_genxml.php The next step would be, trying to make an plugin for wordpress that I could easily post a blog entry with a new location on the same map, which displays already some other locations stored in the mysql database. thanks! <?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers WHERE 1"; $result = mysql_query($query); if (!$result) { die('Invalid query: ' . mysql_error()); } header("Content-type: text/xml"); // Start XML file, echo parent node echo ''; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo ''; } // End XML file echo ''; ?

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  • How to find the submit button in a specific form in jQuery

    - by leifg
    I try to get jQuery object of a submit button in a specific form (there are several forms on the same page). I managed to get the form element itself. It looks something like this: var curForm = curElement.parents("form"); The current Element has the context HTMLInputElement. The several techniques I tried to get the according submit element of the form: var curSubmit = curForm.find("input[type='submit']"); var curSubmit = $(curForm).find("input[type='submit']"); var curSubmit = curForm.find(":submit"); var curSubmit = $(curForm).find(":submit"); var curSubmit = $(curSubmit, "input[type='submit']"); the result is always the same (and very strange). The result that I get is the same element as "curElement". So how can I get the right submit button?

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  • spring-security and jsf

    - by Mike
    Hi! i am developing in JSF a Spring Security application. the login form is fine. however, when i try to retrieve the authentication object, in future code, i always get the authentication pricipal as anonymous. i try to fetch is like this: Authentication auth = SecurityContextHolder.getContext().getAuthentication();

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  • Unable to open my project in C# .Net

    - by user210332
    Hello sir/madam, I'm unable to open my project in visual studio2008. It was developed in C# .net by my friend. When i try to open any open it is showing the error as: "Could not find type 'LibrarySystem.ctrlSeparator'. Please make sure that the assembly that contains this type is referenced. If this type is a part of your development project, make sure that the project has been successfully built. " Also "The variable 'ctrlSeparator1' is either undeclared or was never assigned. " Please anyone help me about how to rectify this problem. With regards and waiting for your answer

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  • How to make an private property?

    - by mystify
    I tried to make a private property in my *.m file: @interface MyClass (Private) @property (nonatomic, retain) NSMutableArray *stuff; @end @implementation MyClass @synthesize stuff; // not ok Compiler claims that there's no stuff property declared. But there's a stuff. Just in an anonymous category. Let me guess: Impossible. Other solutions?

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  • Determine if FieldInfo is compiler generated backingfield

    - by Steffen
    The title pretty much says it all, how do I know if I'm getting a compiler generated backingfield for a {get; set;} property ? I'm running this code to get my FieldInfos: Class MyType { private int foo; public int bar {get; private set; } } Type type = TypeOf(MyType); foreach (FieldInfo fi in type.GetFields(BindingFlags.Instance | BindingFlags.Public | BindingFlags.DeclaredOnly | BindingFlags.NonPublic)) { // Gets both foo and bar, however bar is called <bar>k__backingfield. } so the question is, can I somehow detect that the FieldInfo is a backingfield, without relying on checking its name ? (Which is pretty undocumented, and could be broken in next version of the framework)

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  • What's wrong with my If-statement to check uploaded file? (PHP)

    - by ggfan
    I am trying to test if the uploaded file is the image type I want. If it isn't a gif,jpeg, png, it should echo "Problem". But when I execute this code, it always says there's a problem. What's wrong with my if statement? $uploadfile_type=$_FILES['userfile']['type']; if ( ($uploadfile_type !='image/gif') || ($uploadfile_type !='image/jpeg') || ($uploadfile_type !='image/png')) { echo 'Problem: file is not a gif or jpeg or png!'; exit; } This code works when I am only checking one type of image. Ex: if($uploadfile_type !='image/gif') -- this statement would work but when I add a OR it doesn't.

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  • crash happens when NSMutableArray is returned?

    - by senthilmuthu
    Hi, I have coded like that(that function will be called again and again), but the returned object gives "BAD ACCESS", the NSLog prints correct string, but toReturn sometimes(i called again and again) gives crashes..any help to alter this code - (NSMutableArray *)getAll:(NSString *)type { NSLog(@"Type: %@", type); NSMutableArray *toReturn = [[NSMutableArray alloc] initWithCapacity:0] ; rs = [db executeQuery:Query1]; while ([rs next]) { [toReturn addObject:[rs stringForColumn:@"Name"]]; NSLog(@"name: %@", [rs stringForColumn:@"Name"]); } [rs close]; return toReturn; }

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  • How can I figure out where all these extra sqlite3 selects are being generated in my rails app?

    - by radixhound
    I'm trying to figure out where a whole pile of extra queries are being generated by my rails app. I need some ideas on how to tackle it. Or, if someone can give me some hints, I'd be grateful. I get these: SQL (1.0ms) SELECT name FROM sqlite_master WHERE type = 'table' AND NOT name = 'sqlite_sequence' SQL (0.8ms) SELECT name FROM sqlite_master WHERE type = 'table' AND NOT name = 'sqlite_sequence' SQL (0.8ms) SELECT name FROM sqlite_master WHERE type = 'table' AND NOT name = 'sqlite_sequence' repeated over and over on every request to the DB (as much as 70 times for a single request) I tried installing a plugin that traced the source of the queries, but it really didn't help at all. I'm using the hobofields gem, dunno if that is what's doing it but I'm somewhat wedded to it at the moment Any tips on hunting down the source of these extra queries?

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  • How to convet DataTable to List on runtype with out existin class property [closed]

    - by shamim
    Work on VS2010 C#,Have one DataTable ,want to convert this DataTable to List Suppose: Table dt; On run time want to create similar field from a datatable and fill fields in List.There is no existing class for list properties. ListName=TableName List property name=Table column name List Property type=Table column type List items=Table rows Note: Recently work on EF.To fullfill my project requirement, need to give flexibility to use to input and execute ESQL at runtime .I don’t want to put this execute result on datatable or List ,want to put this result on list. List has no existing class and property,don’t want to convert DataTable on list Type:DataRow If have any query please ask,Thanks in advanced.

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  • JavaScript to enable "submit" button (doesn't work)

    - by Halst
    I need the button "submit" to be disabled unless JavaScript is on. I tried: 1. <input onLoad="this.disabled=false" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 2. <input onLoad="this.removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 3. <input onLoad="document.getElementById("post-comment").removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> Doesn't work. I'm new to JavaScript, but can't find answer on the net.

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  • GIT not functionnal on Mac OS X Lion?

    - by user1187727
    I am trying to use GIT to manage my computing projects. But all commands using GIT do not respond on my terminal. For example if I try git --version followed by entry keyboard typing, a blank line appear and wait until ever. If I type again the entry key on my keyboard the command line is again available but nothing appear. It's the same for all git function that I type. Do you have any solution or explanation for this ?

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  • Why do you sometimes need to write <typename T> instead of just <T> ?

    - by StackedCrooked
    I was reading the Wikipedia article on SFINAE and encountered following code sample: struct Test { typedef int Type; }; template < typename T > void f( typename T::Type ) {} // definition #1 template < typename T > void f( T ) {} // definition #2 void foo() { f< Test > ( 10 ); //call #1 f< int > ( 10 ); //call #2 without error thanks to SFINAE } Now I've actually written code like this before, and somehow intuitively I knew that I needed to type "typename T" instead of just "T". However, it would be nice to know the actual logic behind it. Anyone care to explain?

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