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  • How can call a JQuery function when it in side the from view (asp.net control)?

    - by ricky roy
    Hi, All I have a Span in side the Form view. I wanted to Call a Jquery Fucntion when the from load how can i do this? Thanks Waiting for your reply here is my code <asp:FormView ID="FormView1" runat="server" OnItemCommand="FormView1_ItemCommand"> <ItemTemplate> <asp:HiddenField ID="hidProductID" Value='<%#Eval("ProductID") %>' runat="server" /> <asp:HiddenField ID="hidCustomerID" Value='<%#Eval("CustomerID") %>' runat="server" /> <a href='<%=WinToSave.SettingsConstants.SiteURL%>WintoSave/AuctionProduct.aspx?id=<%#Eval("ProductID") %>'> <%#Eval("ProductName")%> </a> <br /> <img src='<%#Eval("ImagePath")%>' alt="Image No available" /> <br /> <asp:Label ID="lblTime" runat="server" Text='<%#Convert.ToDateTime(Eval("ModifiedOn")).ToString("hh:mm:ss") %>'></asp:Label> <span id='Countdown_<%#Eval("ProductID") %>' onload="GetTimeOnLoad('<%#Eval("ModifiedOn")%>','Countdown_<%#Eval("ProductID") %>');"></span> <br /> <asp:Label ID="lblFinalPrice" runat="server" Text='<%#Convert.ToDouble(Eval("FinalPrice")).ToString("#.00")%>'></asp:Label> <br /> <asp:Label ID="lblFullName" runat="server" Text='<%#Eval("FullName") %>'></asp:Label> <br /> <asp:Button ID="btnAddbid" Text="Bid" CommandName="AddBid" CommandArgument='<%#Eval("ID")%>' runat="server" /> </ItemTemplate> </asp:FormView> and following is my jquery code function GetTimeOnLoad(shortly,DivID) { var dt = new Date(shortly); alert(dt); alert(shortly); alert(DivID); var ProductDivID = "#" +DivID; alert(ProductDivID); $(ProductDivID).countdown({ until: dt, onExpiry: liftOff, onTick: watchCountdown, format: 'HMS', layout: '{hnn}{sep}{mnn}{sep}{snn}' }); } function liftOff(){}; function watchCountdown(){}; In above code I Used ' onload="GetTimeOnLoad('<%#Eval("ModifiedOn")%','Countdown_<%#Eval("ProductID") %');" but is not working

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  • jQuery plugin: Validation can't be customized without setting all fields to 'required'?

    - by rasx
    I've spent the day looking at jQuery plugin: Validation by Jörn Zaefferer. I notice that it works fine as long as you call the validate() method without options. In my little squalid world, as soon as I add options, like errorPlacement, I notice that validation ignores form fields that are not marked required. I also notice that many, many demos mark all fields required---or do not pass options. Am I writing about anything familiar here? Or should I astral project to a parallel universe?

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  • How can you use jQuery to make sIFR-replaced elements fade in?

    - by Sam Goldman
    This is what I currently have: // #content is visibility=hidden sIFR.replace(mix_bold, { selector: '#content p', onReplacement: function(fi) { $('#content').fadeIn("slow"); } }); The fade in happens, but for a split second the replaced flash movie appears before being hidden. Has anyone gotten this to work? I am using jQuery 1.2.6 and sIFR 3 r436. Tested in Safari 4 and FF 3. Thanks!

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  • Jquery - Loading a page with .load and selector doesn't execute script?

    - by PirateKitten
    I'm trying to load one page into another using the .load() method. This loaded page contains a script that I want to execute when it has finished loading. I've put together a barebones example to demonstrate: Index.html: <html> <head> <title>Jquery Test</title> <script type="text/javascript" src="script/jquery-1.3.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $('#nav a').click(function() { $('#contentHolder').load('content.html #toLoad', '', function() {}); return false; }); }); </script> </head> <body> <div id="nav"> <a href="content.html">Click me!</a> </div> <hr /> <div id="contentHolder"> Content loaded will go here </div> </body> </html> Content.html: <div id="toLoad"> This content is from content.html <div id="contentDiv"> This should fade away. </div> <script type="text/javascript"> $('#contentDiv').fadeOut('slow', function() {} ); </script> </div> When the link is clicked, the content should load and the second paragraph should fade away. However it doesn't execute. If I stick a simple alert("") in the script of content.html it doesn't execute either. However, if I do away with the #toLoad selector in the .load() call, it works fine. I am not sure why this is, as the block is clearly in the scope of the #toLoad div. I don't want to avoid using the selector, as in reality the content.html will be a full HTML page, and I'll only want a select part out of it. Any ideas? If the script from content.html was in the .load() callback, it works fine, however I obviously don't want that logic contained within index.html. I could possibly have the callback use .getScript() to load "content.html.js" afterwards and have the logic in there, that seems to work? I'd prefer to keep the script in content.html, if possible, so that it executes fine when loaded normally too. In fact, I might do this anyway, but I would like to know why the above doesn't work.

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  • Live search results as you type... am I going about this the right way? jQuery + PHP

    - by dallen
    This is my first time building a tool like this, so please bare with me. I'm doing this to learn more about jQuery and AJAX. Basically, I have a search input and a hidden div. When you start typing in the search input, the hidden div becomes visible and results are brought in. In this case, I'm searching for client names. It all works fine, however I think my code could be better but I'm not sure exactly where to begin. Each keyup requests a PHP script which accesses a table in a database to find a like string. But in my PHP script, I'm echo'ing some JS/jQuery which I'm not sure is good practice. Below is my code. Am I going about this the right way or am I totally off base? Any suggestions for improvement? Javascript $("#search").keyup(function() { $("#search_results").show("fast"); $.ajax ({ type: "POST", url: "http://localhost:8888/index.php/welcome/search/" + $("#search").val(), success: function(html) { $("#search_results").html(html); } }); }); PHP function search($search_string = false) { if ($search_string) { $this->db->like('name', $search_string); $query = $this->db->get('clients'); if ($query->num_rows() == 0) { echo "No client exists."; } else { foreach ($query->result() as $row) { echo '<script>'; echo ' $("#client_results_'.$row->id.'").hide(); $("#'.$row->id.'").toggle(function() { $.ajax ({ type: "POST", url: "http://localhost:8888/index.php/welcome/search_client_ads/" + '.$row->id.', success: function(html) { $("#client_results_'.$row->id.'").html(html).show("fast"); } }); }, function() { $("#client_results_'.$row->id.'").hide("fast").html(""); });'; echo '</script>'; echo '<p><span id="'.$row->id.'">'.$row->name.'</span></p>'; echo '<div id="client_results_'.$row->id.'"></div>'; } } } else { echo ''; } } function search_client_ads($client_id) { $query = $this->db->get_where('online_ads', array('client' => $client_id)); if ($query->num_rows() == 0) { echo "No ads exist."; } else { foreach ($query->result() as $row) { echo $row->id; } } }

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  • Under what circumstances is jQuery's document.ready() not required?

    - by Phil.Wheeler
    While John Resig's recommendation is, quite rightly, to declare all events within a jquery.document.ready() function, I know that you don't actually have to put everything in there. In fact, there are cases where it may be more appropriate to deliberately put methods outside of the ready event. But what are those cases? Obviously best practice dictates that all events are declared within the ready event, so what would best practice be for declarations outside that event?

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  • How do I simulate a scrollbar click with jQuery?

    - by Ian Davis
    How do I simulate a scrollbar click with jQuery? So, if a user clicks on a div that says "scroll down," it'll be the exact same behavior as if he/she clicked on the down arrow of the browser's scrollbar. Using the current browser's behavior would be optimal, vs. doing something like $.browser.scrolldown(200,'fast'). Something like $.browser.triggerDownArrowOnScrollBar() would be sweet!

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  • How to get object values and properties in jquery ?

    - by Rachel
    I am using jQuery selector to get the values of all CMS components on the page using $('div.cmscomponent') but how can I test this to see if am actually getting the list of compoents on the page. I use: var temp = $('div.cmscomponent'); alert(temp); and result that I get is [object OBJECT] and so how can I test this ? and how can I get values of the object and its properties.

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  • How can I recreate the Evernote 5 iOS tabbed layout using CSS3 an jQuery?

    - by Ismailp
    Looking for a tutorial on how I could make a web interface similar to the Evernote 5 iOS tabbed layout, using CSS3 and jQuery?! Here is a link showing the tabs: http://www.google.se/search?q=evernote+5+tabbed&hl=en&tbo=d&source=lnms&tbm=isch&sa=X&ei=wxWoUKPxF-TO4QTQk4DwDQ&ved=0CAgQ_AUoAQ&biw=320&bih=416#i=8 Do you guys know any good tutorials/resources for this? All help appreciated! Thanks in advance

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  • Is it possible to return the "highlighted" (like Firebug) css selector or dom id with jquery?

    - by Jonathan
    Hi Folks, When you click the "Click an element on the page to inspect" arrow with FireBug, it puts a Blue Border around the target element, and also returns the DOM Id. I am building an application and that feature would be awesome to add. Be able to hover over elements and highlight the target, upon clicking return the DOM Id or CSS selector to the application. Is there a jquery plugin that does this magic? Some other smart way? Thanks!, Jonathan

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  • jQuery - Show field based on value of a type-hidden on refresh.

    - by Sebhael
    Hello, I'm trying to create something in jQuery and having a bit of problems with it. I'm not too adept on the framework, so I'm sure this is all wrong. Anyways, the ultimate goal is a full form that contains 3 radio buttons - depending on the value of the button, a LI is shown. I have all of that done, but my problem is coming with validation. If something fails then the page is reloaded and the div that was selected doesn't show without clicking another radio first, then back to the original. This process is basically the same as someone came up with here. Here's what I got so far. HTML <li> <label> License (radio) </label> <label for="commercial" class="checkBox"> Commercial </label> <input type="radio" name="license" value="commercial" id="commercial" class="checkBox" <?php echo set_radio('license', 'commercial'); ?> /> <label for="abandonware" class="checkBox"> Abandonware </label> <input type="radio" name="license" value="abandonware" id="abandonware" class="checkBox" <?php echo set_radio('license', 'abandonware'); ?> /> <label for="freeware" class="checkBox"> Freeware </label> <input type="radio" name="license" value="freeware" id="freeware" class="checkBox" <?php echo set_radio('license', 'freeware'); ?> /> </li> This is followed by three LI's that contain id="commercial, abandonware, and freeware" and class="licenseli" My jQuery is, as said, something from here. $('li.licenseli').hide(); $('input[name=license]:radio').change(function(){ var Type = $(this).val(); // Get value of radio $('li.licenseli').slideUp(); // Hide non-selected $('li#'+Type).slideDown(); // Show Selected }); So what I need help with is I have a hidden input that retrieves the value of the radio box from validation - I want to take this value (or the radio's if possible?) and have the original selected option's LI already visible.

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Sending string to wcf service using jquery ajax. why can i only send strings of numbers?

    - by Robodude
    Hi Guys, For some reason, I'm only able to pass strings containing numbers to my web service when using jquery ajax. This hasn't been an issue so far because I was always just passing IDs to my wcf service. But I'm trying to do something more complex now but I can't figure it out. In my interface: [OperationContract] [WebInvoke(ResponseFormat = WebMessageFormat.Json)] DataTableOutput GetDataTableOutput(string json); My webservice: public DataTableOutput GetDataTableOutput(string json) { DataTableOutput x = new DataTableOutput(); x.iTotalDisplayRecords = 9; x.iTotalRecords = 50; x.sColumns = "1"; x.sEcho = "1"; x.aaData = null; return x; } Javascript/Jquery: var x = "1"; $.ajax({ type: "POST", async: false, url: "Services/Service1.svc/GetDataTableOutput", contentType: "application/json; charset=utf-8", data: x, dataType: "json", success: function (msg) { }, error: function (XMLHttpRequest, textStatus, errorThrown) { //alert(XMLHttpRequest.status); //alert(XMLHttpRequest.responseText); } }); The above code WORKS perfectly. But when I change x to "t" or even to "{'test':'test'}" I get a Error 400 Bad Request error in Firebug. Thanks, John EDIT: Making some progress! data: JSON.stringify("{'test':'test'}"), Sends the string to my function! EDIT2: var jsonAOData = JSON.stringify(aoData); $.ajax({ type: "POST", async: false, url: sSource, contentType: "application/json; charset=utf-8", data: "{'Input':" + jsonAOData + "}", dataType: "json", success: function (msg) { }, error: function (XMLHttpRequest, textStatus, errorThrown) { //alert(XMLHttpRequest.status); //alert(XMLHttpRequest.responseText); } }); EDIT3: I modified the code block I put in EDIT2 up above. Swapping the " and ' did the trick! $.ajax({ type: "POST", async: false, url: sSource, contentType: "application/json; charset=utf-8", data: '{"Input":' + jsonAOData + '}', dataType: "json", success: function (msg) { }, error: function (XMLHttpRequest, textStatus, errorThrown) { //alert(XMLHttpRequest.status); //alert(XMLHttpRequest.responseText); } }); However, I have a new problem: public DataTableOutput GetDataTableOutput(DataTableInputOverview Input) { The input here is completely null. The values I passed from jsonAOData didn't get assigned to the DataTableInputOverview Input variable. :(

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