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• Please help me understand this PHP script.Noob here

  - by NissGTR

  I'm learning PHP,MySQL and came across this function today function get_director($director_id) { global $db; $query = 'SELECT people_fullname FROM people WHERE people_id = ' . $director_id; $result = mysql_query($query, $db) or die(mysql_error($db)); $row = mysql_fetch_assoc($result); extract($row); return $people_fullname; } I understand what functions are and I've created a few while learning PHP.But this one is a bit more complicated.I can't understand the WHERE people_id = ' . $director_id I'm new to MySQL.I guess the single quote ends the MySQL statement?And then it is concatenated with the argument? Please help me out.

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• Simulating python's With statement in java

  - by drozzy

  Is there something like Python with context manager in Java? For example say I want to do something like the following: getItem(itemID){ Connection c = C.getConnection(); c.open(); try{ Item i = c.query(itemID); }catch(ALLBunchOfErrors){ c.close(); } c.close(); return c; } where in python I just have: with( C.getConnection().open() as c): Item i = c.query(itemID); return i;

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• jquery ajax form function(data)

  - by RussP

  Can some one please tell me where I have gone wrong. What ever I do I get the answer "no" JQuery to send data to php query $j.post("logincheck.php",{ username:$j('#username').attr('value'), password:$j('#password').attr('value'), rand:Math.random() } , function(data) { if(data=='yes') {alert('yes');} else {alert('no');} } ); Here is the php query if(isset($_POST['username'])): $username = $_POST['username']; $password = $_POST['password']; $posts = mysql_query("SELECT * FROM users WHERE username='$username'"); $no_rows = mysql_num_rows($posts ); while($row = mysql_fetch_array($posts)): print 'yes'; endwhile; else: print 'no'; //header('location: index.php'); endif; endif; Thank in adance

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• Getting Popular Topics on a Custom Made Forum

  - by Navarr

  For this website we're working on, we're trying to get the most popular topics (based on how many posts have been made in them within the last 24 hours). We have a medium to large based forum, and the current MySQL query looks like this: SELECT `forums_topics`.*, ( SELECT COUNT(`id`) FROM `forums_posts` WHERE `postdate` > (UNIX_TIMESTAMP()-60*60*24) AND `topicid`=`forums_topics`.`id` ) AS `trendy_threads` FROM `forums_topics` WHERE `deleted`=0 ORDER BY `trendy_threads` DESC,`postdate` DESC LIMIT 3 This unfortunately causes an SQL timeout with just one query and Error 500's. How can we get this information as quickly and as efficiently as possible?

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• mySQL Get First And Last Date Of Next Month

  - by Lennie De Villiers

  Hi, How can I get this in my mySQL query in the where clause?

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• Optimizing PHP code (trying to determine min/max/between case)

  - by Swizzh

  I know this code-bit does not conform very much to best coding practices, and was looking to improve it, any ideas? if ($query['date_min'] != _get_date_today()) $mode_min = true; if ($query['date_max'] != _get_date_today()) $mode_max = true; if ($mode_max && $mode_min) $mode = "between"; elseif ($mode_max && !$mode_min) $mode = "max"; elseif (!$mode_max && $mode_min) $mode = "min"; else return; if ($mode == "min" || $mode == "between") { $command_min = "A"; } if ($mode == "max" || $mode == "between") { $command_max = "B"; } if ($mode == "between") { $command = $command_min . " AND " . $command_max; } else { if ($mode == "min") $command = $command_min; if ($mode == "max") $command = $command_max; } echo $command;

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• Select where a value present

  - by Roy

  First a database example: id, product_id, cat, name, value -------------------------------- 1,1,Algemeen,Processor,2 Ghz 2,1,Algemeen,Geheugen,4 GB 3,2,Algemeen,Processor,3 Ghz 4,2,Algemeen,Geheugen,4 GB 5,3,Beeldscherm,Inch,22" 6,3,Beeldscherm,Kleur,Zwart 7,3,Algemeen,Geheugen,3 GB 8,3,Algemeen,Processor,3 Ghz I want with one query to select the follow id's: 1,2,3,4,7,8 Because the cat = algemeen and the name = processor by these products. ID 5,6 are only present by product 3. So, the entry's (cat and name) which are present by all products (product_id) have to be selected. The database contains 80.000 entry's with a lot of diffrent cat's, name's and value's. Is this possible with one query or is some php necessary? How do I do this? My apologies for the bad English.

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• How do check if PDO object is connected properly inside a different class?

  - by tgun926

  I want to fetch some information from my mysql database in a class, so I'm passing in the PDO object into a __construct function, and working from there. However, what's an elegant way of checking to see if the PDO object was correctly created, and that the connection is open when the Table class is instantiated? class Table{ public function __construct(PDO $db, $week){ try{ $query = $db -> query ("SELECT * FROM `table1` where `day` = 'monday'"); } catch(PDOExeption $e){ echo 'error: '. $e->getMessage(); //die(); } } } I don't think this code does what I want.

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• Help with MySQL and CASE WHEN with a range of values

  - by kickdaddy

  I have an accounts table and a records table where accounts have multiple records. I would like to break down the account totals by "count of records" range. i.e. show the breakdown of Count of Records | Count 0-25 | 100 25 - 50 | 122 50 - 100 | 300 etc. I am using the following query, but I can't get it to group by "grp" which is what I want, any help on the best way to modify query? Thanks! SELECT count(*) as ct, CASE WHEN COUNT(*) < 25 THEN '1-25' WHEN COUNT(*) >= 25 < 50 THEN '25-50' WHEN COUNT(*) >= 50 < 100 THEN '50-100' WHEN COUNT(*) >= 100 < 250 THEN '100-250' WHEN COUNT(*) >= 250 < 500 THEN '250-500' WHEN COUNT(*) >= 500 < 1000 THEN '500-1000' ELSE '1000+' END AS grp FROM records r,accounts a WHERE r.account_id=a.id ORDER BY ct

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• Count number of messages per user

  - by Pr0no

  Consider the following tables: users messages ----------------- ----------------------- user_id messages msg_id user_id content ----------------- ----------------------- 1 0 1 1 foo 2 0 2 1 bar 3 0 3 1 foobar 4 3 baz 5 3 bar I want to count the number of messages per user and insert the outcome into users.messages, like this: users ----------------- user_id messages ----------------- 1 3 2 0 3 2 I could use PHP to perform this operation, pseudo: foreach ($user_id in users) { $count = select count(msg_id) from messages where user_id = $user_id update users set messages = $count } But this is probably very inefficient as compared to one query executed in MySQL directly: UPDATE users SET messages = ( SELECT COUNT(msg_id) FROM messages ) But I'm sure this is not a proper query. Therefore, any help would be appreciated :-)

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• Broken count(*) after adding LEFT JOIN

  - by Iain Urquhart

  Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

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• Querying Active Directory using VBScript

  - by user84850

  I want to query Active Directory using VBScript (classic ASP). How can I accomplish that?

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• how to store session data in couchapp

  - by haki

  to query parameters for eventlies and show-functions? to store global language options for example?

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• Checking sqlite datetime NULL with RoR

  - by Paul N

  RoR/SQL newbie here. My datetime column 'deleted_at' are all uninitialized. Running this query returns an error: SELECT * FROM variants v ON v.id = ovv0.variant_id INNER JOIN option_values_variants ovv1 ON v.id = ovv1.variant_id INNER JOIN option_values_variants ovv2 ON v.id = ovv2.variant_id INNER JOIN option_values_variants ovv3 ON v.id = ovv3.variant_id INNER JOIN option_values_variants ovv4 ON v.id = ovv4.variant_id WHERE v.deleted_at = NULL AND v.product_id = 1060500595 However, if I set my datetime values to 0, and set my query to v.deleted_at = 0, the correct variant is returned to me. How do I check for uninitialized/NULL datetimes?

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• Why is my left join not returning nulls?

  - by Griz

  In sql server 2008, I have the following query: select c.title as categorytitle, s.title as subcategorytitle, i.title as itemtitle from categories c join subcategories s on c.categoryid = s.categoryid left join itemcategories ic on s.subcategoryid = ic.subcategoryid left join items i on ic.itemid = i.itemid where (ic.isactive = 1 or ic.isactive is null) and i.siteid = 132 order by c.title, s.title I am trying to get items in their subcategories, but I still want to return a record if there are no items in the category or subcategory. Subcategories that have no items are never returned. What am I doing wrong? Thank you EDIT Modified query with a second left join and where clause, but it's still not returning nulls. :/

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• What will happen if I change the type of a column from int to year?

  - by MachinationX

  I have a table in MySQL 4.0 which currently has a year field as a smallint(6) type. What will happen if I convert it directly to a Year type with a query like the following: ALTER TABLE t MODIFY y YEAR(4) NOT NULL DEFAULT CURRENT_TIMESTAMP; When the current members of column y have values like 2010? I assume that because the year type is technically values from 1-255, values above that will be truncated or broken. So if MySQL isn't smart enough to realize that 2010(int) = 110(year), what would be the simplest query or queries to convert the values? Thanks for your help!

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• MySQL count/sum fields

  - by Conor H

  Hi There, What I am trying to achieve is a report on daily financial transactions. With my SQL query I would like to count the total number of cash transactions, the total cash value and the same for checks. I only want to do this for a specified date. Here is a snippet of the query that I am having trouble with. These sum and count commands are processing all the data in the table and not for the selected date. (SELECT SUM(amount) FROM TRANSACTION WHERE payment_type.name = 'cash') AS total_cash, (SELECT COUNT(*) FROM TRANSACTION WHERE payment_type.name = 'cash') AS total_cash_transactions Sorry if I havent posted enough detail as I haven't time. If you need more info just ask.. Cheers.

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• Calling Google's Custom Search API via Python

  - by user353829

  I am writing in Python a module that will query Google's Custom Search API and return all listings of domain 'example.com' I Have been reading instructions at https://code.google.com/apis/customsearch/v1/getting_started.html and am a little stumped at the moment. Are my assumptions listed below correct? For example, to search for results that has 'example.com' in the URL, the query is: *'https://www.googleapis.com/customsearch/v1?key=my_key&cx=017576662512468239146:omuauf_lfve&q=site:example.com*' *key=my_key*: value of key given by google cx=017576662512468239146: name of the search engine (google)? *omuauf_lfve*: I have no idea what this is q=site:example.com: This should return all results with 'example.com'; e.g. www.a.example.com, b.example.com, example .com

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• Help with PHPExcel Library and mySQL data from a table

  - by user547363

  Hello! Everyone.. I have this script $query = "SELECT id,last_name,first_name FROM users WHERE tmima_id='6'"; $result = @mysql_query($query); while($row = mysql_fetch_array($result)) { $i = 3; $emp_id = $row['id']; $cell = 'A'.$i; $objPHPExcel->setActiveSheetIndex(0) ->setCellValue($cell, $row['last_name']. $row['first_name']); $i++; } But in the .xls file it prints only one user. Why id doesnt print all of the users ? W Thanks in advance.

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• Separate Datasource for Gridview Footer

  - by Mike Keller

  I need to able to display the results from a seperate query in the footer of a gridview. What is the best way to go about this? I did some google searches and what I found pretty much revolves using the original datasource and doing something like addition to display the information in the footer. However I really need to be able to display this single line of information from a seperate query. Any direction given would be appreciated. Links, tips, tricks, etc. Thanks.

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• problem in using while loop in php&mysql

  - by Mac Taylor

  hey guys im using a while loop to show my latest forum topics now i need to count some fields either I'm trying to do it in one query and here is my code : $result = $db->sql_query("SELECT t.*,p.*, SUM(t.topic_approved='1') AS Amount_Of_Topics, SUM(t.topic_views) AS Amount_Of_Topic_Views, SUM(t.topic_replies) AS Amount_Of_Topic_Replies, SUM(p.post_approved ='1') AS Amount_Of_Posts FROM bb3topics t left join bb3posts p ON t.topic_id=p.topic_id ORDER BY t.topic_last_post_id DESC LIMIT 10 " ); while( $row = $db->sql_fetchrow($result) ) { problem : this code shows only one forum topic and not the rest , but if i remove sum() part from it , then it shows the rest is there anything wrong with my query code ?!

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• How to delete a post in Nhibernate?

  - by marko

  I try to delete a post in NHibernate but nothing happens. Updating, selecting and inserting new items works fine but when I try to delete nothing happens. IQuery query = session.CreateQuery("from Color where name like '%" + TextBox2.Text.Trim() + "%'"); Color color = query.List<Color>()[0]; session.Delete(color); Edit: I forgot to call the flush method. Now works fine. Like this: session.Flush();

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• PHP PDO - bindValue PARAM_BOOL as string

  - by PHP_guy

  I'm freaking out here and can't figure out what's wrong. I'm pretty new to PDO, but everything works in my code except for booleans which are sent as strings. My code (simplified): $sql = 'SELECT * FROM pages WHERE clean_url_slo = :clean_url_slo AND published = :published LIMIT 1'; $clean_url_slo = 'home'; $published = true; Then I prepare stuff and execute it like this (simplified): $stmt = $db->prepare($sql); $stmt->bindValue(':clean_url_slo',$clean_url_slo,PDO::PARAM_STR); $stmt->bindValue(':published',$published,PDO::PARAM_BOOL); $stmt->execute(); And then here is what comes to mysql (from the mysql log - the query mysql received): 91 Query SELECT * FROM pages WHERE 1=1 AND clean_url_slo='domov' AND published='1' ORDER BY id desc LIMIT 1 As you can see, published is an integer - so always true, which is not OK. Why is that if I'm declaring it as a boolean? using: WAMP SERVER PHP version: 5.3.9 Mysql: 5.5.20 Many thanks for your help..

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• Mysql select most frequent and sort alphabetically

  - by user2605793

  I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

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• GROUP BY on multiple columns

  - by Tams

  I have a table that looks like the following - Id Reference DateAttribute1 DateAttribute2 1 MMM005 2011-09-11 2012-09-10 2 MMM005 2012-06-13 2012-09-10 3 MMM006 2012-08-22 2012-09-10 4 MMM006 2012-08-22 2012-09-11 I have handle to the id values. I would like to query such that I get the following result Id Reference DateAttribute1 DateAttribute2 2 MMM005 2012-06-13 2012-09-10 4 MMM006 2012-08-22 2012-09-11 I would like my result to be grouped by reference and then 'DateAttribute1' and then 'DateAttribute2' as such - DateAttribute1 has a priority over DateAttribute2 as you can see above in the result. How should I write my query to fetch the results in the above manner? Any solution?

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