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  • How to use Facebook graph API to retrieve fan photos uploaded to wall of fan page?

    - by Joe
    I am creating an external photo gallery using PHP and the Facebook graph API. It pulls thumbnails as well as the large image from albums on our Facebook Fan Page. Everything works perfect, except I'm only able to retrieve photos that an ADMIN posts to our page. (graph.facebook.com/myalbumid/photos) Is there a way to use graph api to load publicy uploaded photos from fans? I want to retrieve the pictures from the "Photos from" album, but trying to get the ID for the graph query is not like other albums... it looks like this: http://www.facebook.com/media/set/?set=o.116860675007039 Another note: The only way i've come close to retreiving this data is by using the "feed" option.. ie: graph.facebook.com/pageid/feed EDIT: This is about as far as I could get- it works, but has certain issues stated below. Maybe someone could expand on this, or provide a better solution. (Using FB PHP SDK) <?php require_once ('config.php'); // get all photos for album $photos = $facebook->api("/YourID/tagged"); $maxitem =10; $count = 0; foreach($photos['data'] as $photo) { if ($photo['type'] == "photo"): echo "<img src='{$photo['picture']}' />", "<br />"; endif; $count+= 1; if ($count >= "$maxitem") break; } ?> Issues with this: 1) The fact that I don't know a method for graph querying specific "types" of Tags, I had to run a conditional statement to display photos. 2) You cannot effectively use the "?limit=#" with this, because as I said the "tagged" query contains all types (photo, video, and status). So if you are going for a photo gallery and wish to avoid running an entire query by using ?limit, you will lose images. 3) The only content that shows up in the "tagged" query is from people that are not Admins of the page. This isn't the end of the world, but I don't understand why Facebook wouldn't allow yourself to be shown in this data as long as you posted it "as yourself" and not as the page.

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  • Data mining google's web search results?

    - by cheesebunz
    Currently, i have a google web search. If a user searches starbucks, I would only want to retrieve the company or product information, not some other weird links like blog pages, using javascript, is it possible to do so? if yes, how am i able to do it? Kind of a newbie in the data mining part..thanks! Added my coding for download for clearer understanding : http://www.mediafire.com/?mzgo233kngm

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  • how to set default focus?

    - by Elaine
    Now one Submit button is the default focused control. but I need to set the default focus to another imagebutton. Can only use $(document).ready(function(){ctrl.focus();} ? or has another property to fulfill it?

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  • Why IE6 is messing the menu?

    - by Nitz
    Hey Guys, I had made website. This is Link for that. There is one menu in this site which works well in Firefox , Chrome, Opera. But it is messed in the IE 6. I want to know why is not showing correctly?

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  • ABSMIDDLE works differently on firefox and chrome?

    - by Axel
    Hi, i have an icon image and text like the following, the code source of everything is : <img src="...." align="absmiddle" /> My Title Here The problem is that the icon is not aligned vertically with the title in chrome better than firefox. I think the absmiddle doesn't work at all ! is there any solution, i don't want to use a table with 2 columns to fix this issue. Thanks

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  • Variable not implementing correctly from if statement

    - by swiftsly
    I have an if statement that is supposed to set the variable $pc162v to a link specified in the MySQL table if content exists in the $vid column of the row. The problem is, the PHP is detecting that there's a link in the MySQL, but isn't setting the $pc162v variable correctly. Here's the variable declarations: $pc162v = ""; $vid162 = '<embed width="420" height="236" src="'.$pc162v.'" type="application/x-shockwave-flash"></embed>'; Here's the section of the if statement: if (empty($row[7])) { $vid162 = ''; } else { $pc162v = $row[7]; } In my web browsers, the part of the code where the variable $vid162 is used, shows up as the following: <embed width="420" height="236" src="" type="application/x-shockwave-flash"> I have also tried setting $vid162 to: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"></embed> and that just makes the code in my web browser: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"> Hope someone has a solution! Thanks in advance.

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  • Accepting Payment with local debit cards from foreign countries

    - by megatr0n
    Hi all. I have an ecommerce website and I am currently accepting payments from visa, master card and all the other major cards. However, one issue I am having is accepting payment from customers using local debit cards. Say someone from China doesn't have a major credit and he wants to use his local debit card, I want be able to accept payment from him as long as its legal. How do I go about this? Thanks.

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  • Creating dynamic text for a literal control

    - by strakastroukas
    On the ListView1_ItemDataBound of a list view event, i create the literal.text like so... <span style="position:relative"> <span id="term1" class="popup">This is the answer!</span> <a href="javascript:void(0);"onMouseover="ShowPop('term1')" onMouseout="HidePop('term1')">Show me the answer</a></span> The problem is that the text is not rendered as it should. On mousing over the literal control the url is http://localhost:1391/"javascript:void(0);"onMouseover="ShowPop('term1');" So what is going on here? What am i missing?

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  • IE6 background appears-disappears on scrolling

    - by itarato
    Hi, Given IE6, an UL-LI list and a background image for the UL container. <style> ul {background-image: url(images/bgr.png);} </style> ... <ul> <li>...</li> ... </ul> When I load the page, the background is randomly loaded, some parts are visible, some are not. Moreover, it changes on runtime when I'm scrolling on the page. When I scroll out the UL list and scroll back, different parts of the background will be visible, depends on the speed of scrolling. Do you have any idea? Thanks in advance.

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  • How to force a line break in a loooooong word in a DIV?

    - by George Edison
    Okay, this is really confusing me. I have some content inside of a div like so: <div style="background-color: green; width: 200px; height: 300px;"> Thisisatest.Thisisatest.Thisisatest.Thisisatest.Thisisatest.Thisisatest. </div> However, the content overflows the DIV (as expected) because the 'word' is too long. How can I force the browser to 'break' the word where necessary to fit all of the content inside?

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  • Semantically correct XHTML markup

    - by Dori
    Hello all. Just trying to get the hang of using the semantically correct XHTML markup. Just writing the code for a small navigation item. Where each button has effectivly a title and a descrption. I thought a definition list would therefore be great so i wrote the following <dl> <dt>Import images</dt> <dd>Read in new image names to database</dd> <dt>Exhibition Management</dt> <dd>Create / Delete an exhibition </dd> <dt>Image Management</dt> <dd>Edit name, medium and exhibition data </dd> </dl> But...I want the above to be 3 buttons, each button containing the dt and dd text. How can i do this with the correct code? Normally i would make each button a div and use that for the visual button behaviour (onHover and current page selection stuff). Any advice please Thanks

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  • blank space on google home page

    - by topgun_ivard
    2 questions, i was doing nothing productive, and tried selecting the google home page (a left click drag and select whole page) on google.com i see that beside the search box, on the left side, there is an empty space &nbsp; i looked up the source code and there indeed was a <td width=25%>&nbsp;</td> stupid as it may sound, but i was still curious to know why the blank space is out there..or is it just a simple typo?? :) also, any idea what window.lol&&lol() does? curious yet again, google search didnt get me any result and i thought i would turn to stackoverflow to enlighten me... thanks, ivar

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  • export a JOGL applet and embedd into a html page

    - by nkint
    hi guys it is some time that i'm testing opengl with java and JOGL. now i have good result and i wanto to pubblish it on web. but i have some problem. i'm in eclipse, and i'm testing an Applet with JOGL. first of all i have this run time error (but the program works correctly): java.lang.IllegalArgumentException: adding a window to a container at java.awt.Container.checkNotAWindow(Container.java:431) at java.awt.Container.addImpl(Container.java:1039) at java.awt.Container.add(Container.java:365) at AppletHelloWorld.init(AppletHelloWorld.java:30) at sun.applet.AppletPanel.run(AppletPanel.java:424) at java.lang.Thread.run(Thread.java:619) then i found this incredibly clear page and i do what is said, i open html with the browser, the libs are downloaded but it stops at "Starting applet AppletHelloWorld" that is the name i gave to my applet. mayebe i miss something like main function or exporting well the jar? this is my main code: public class AppletHelloWorld extends Applet { public static void main(String[] args) { JFrame fr=new JFrame(); fr.setBounds(0,0,1015,600); fr.add(new AppletHelloWorld()); fr.setVisible(true); } public void init() { setLayout(null); MyJOGLProject canvas = new MyJOGLProject(); //MyJOGLProject extends JFrame canvas.run(); Container c = new Container(); c.add(canvas); add(c); } //....

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  • Can't get values from Sqlite DB using query

    - by Sana Joseph
    I used sqlite to populate a DB with some Tables in it. I made a function at another javascript page that executes the database & selects some values from the table. Javascript: function GetSubjectsFromDB() { tx.executeSql('SELECT * FROM Subjects', [], queryNSuccess, errorCB); } function queryNSuccess(tx, results) { alert("Query Success"); console.log("Returned rows = " + results.rows.length); if (!results.rowsAffected) { console.log('No rows affected!'); return false; } console.log("Last inserted row ID = " + results.insertId); } function errorCB(err) { alert("Error processing SQL: "+err.code); } Is there some problem with this line ? tx.executeSql('SELECT * FROM Subjects', [], queryNSuccess, errorCB); The queryNSuccess isn't called, neither is the errorCB so I don't know what's wrong.

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  • Lining up Divs, while using JQuery

    - by user630581
    I am trying to create a flash header like element in JQuery, that has three images that fade to other images. I have each group of images in a div, but the divs line up vertically down the page, I want them to line up horizontally in a row. Currently my css code is: div#demos{ width:940px; border:0; } .s1{ float:left; display:inline; background-color:#000000; width:225px; margin:0; } .s2{ float:right; display:inline; background-color:#000000; width:225px; margin:0; } .s3{ float:left; display:inline; background-color:#000000; width:225px; margin:0; } and my markup is: <div id="demos"> <div id="s1" class="pics"> <img src="Image1.jpeg" width="200" height="200" /> <img src="Image2.jpeg" width="200" height="200" /> <img src="Image3.jpeg" width="200" height="200" /> </div> <div id="s2" class="pics"> <img src="Image4.jpeg" width="200" height="200" /> <img src="Image5.jpeg" width="200" height="200" /> <img src="Image6.jpeg" width="200" height="200" /> </div> <div id="s3" class="pics"> <img src="Image7.jpeg" width="200" height="200" /> <img src="Image8.jpeg" width="200" height="200" /> <img src="Image9.jpeg" width="200" height="200" /> </div> <div style="clear:both"></div> </div>

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  • Merging code with dependencies? - Javascript

    - by RadiantHex
    Hi folks, this might be quite simple, but I must say I'm a bit confused on this topic. I'm writing code based on two popular libraries: jQuery underscore.js I am just wondering what would be the best way to isolate the code and prevent conflicts and how to merge it with its dependencies. By merging I mean putting them within the same file. :) I hope I'm not asking something which is too basic. ...and a last thing MERRY CHRISTMAS EVERYONE! =D

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  • How to launch a browser in view source mode?

    - by JorgeLarre
    I want to open a file in a web browser (anyone will do) and I want to see it in the view source mode instead of in the standard browser window. This can be done in two steps, by opening the file and then go to the view source window (different shortcuts in each browser), but I want to directly go to the view source window. I have not found any such command line argument for Firefox nor Chrome. Is this possible just with the base browser functionality?

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  • Is it possible to use an input within a <label> field?

    - by javanix
    I have a bunch of optional "write-in" values for a survey I'm working on. These are basically a radio button with a textbox within the answer field - the idea being that you would toggle the button and write something into the box. What I'd like to do is have the radio button toggled whenever a user clicks in the text field - this seems like a use-case that makes a lot of sense. Doing this: <input type="radio" id="radiobutton"><label for="radiobutton">Other: <input type="text" id="radiobutton_other"></label> works fine in Chrome (and I am guessing, other WebKit browsers as well), but there are weird selection issues in Firefox, so I'm assuming its a non-standard practice that I should stay away from. Is there a way to replicate this functionality without using JavaScript? I have an onclick function that will work, but we're trying to make our site usable for people who might have NoScript-type stuff running.

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  • opening and viewing a file in php

    - by Christian Burgos
    how do i open/view for editing an uploaded file in php? i have tried this but it doesn't open the file. $my_file = 'file.txt'; $handle = fopen($my_file, 'r'); $data = fread($handle,filesize($my_file)); i've also tried this but it wont work. $my_file = 'file.txt'; $handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); $data = 'This is the data'; fwrite($handle, $data); what i have in mind is like when you want to view an uploaded resume,documents or any other ms office files like .docx,.xls,.pptx and be able to edit them, save and close the said file. edit: latest tried code... <?php // Connects to your Database include "configdb.php"; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM employees") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data //Echo "<img src=localhost/uploadfile/images".$info['photo'] ."> <br>"; Echo "<b>Name:</b> ".$info['name'] . "<br> "; Echo "<b>Email:</b> ".$info['email'] . " <br>"; Echo "<b>Phone:</b> ".$info['phone'] . " <hr>"; //$file=fopen("uploadfile/images/".$info['photo'],"r+"); $file=fopen("Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt","r") or exit("unable to open file");; } ?> i am getting the error: Warning: fopen(Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt): failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/uploadfile/view.php on line 17 unable to open file the file is in that folder, i don't know it wont find it.

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  • How to find what ActiveX control is referred on a web page?

    - by Sly
    I have developed a web application (ASP.NET Web Forms). One of my customer has very restrictive policies. When he accesses the web page, IE shows this message: Your security settings do not allow Web sites to use ActiveX controls installed on your computer. This page may not display correctly. As far as I know, we don't use ActiveX controls on our page. I did a "View Souce" and did not find anything suspect. How can I find what part of my page refers to an ActiveX. The application uses jQuery and a few jQuery plug-ins. Is there a tool/add-in like "Fire Bug" that I can use to list the ActiveX controls referred on a page?

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