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  • NameError in CompetitorsController#index

    - by manish nautiyal
    Hi all I am getting this problem when I run this code in server. In my localhost everything is running fine. But when I deploy my code in the server it shows me the error. I am using FERRET SERARCH IN MODEL. NameError in CompetitorsController#index uninitialized constant CompetitorsController::Competitor /opt/ruby_enterprise/lib/ruby/gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:102:in `const_missing' /home/troche/mrecip_tool/releases/20091219131859/app/controllerscompetitors_controller .rb :19:in `index' My controller is class CompetitorsController < ApplicationController include AuthenticatedSystem layout 'application' auto_complete_for :proscribed, :competitor auto_complete_for :fee_earner, :fee_earner protect_from_forgery :only = [:tag] before_filter :login_required, :only = [:index, :show, :new, :edit] @@total_company = 70 def index @compet = Competitor.find(:all) ### GETTING ERROR IN THIS LINE respond_to do |format| format.html # index.html.erb format.xml { render :xml => @compet } end end def show @competitor = Competitor.find(params[:id]) respond_to do |format| format.html # show.html.erb format.xml { render :xml => @competitor } end end end My Model is class Competitor < ActiveRecord::Base validates_presence_of :fee_earner_id, :notes belongs_to :fee_earner belongs_to :country belongs_to :state belongs_to :user acts_as_ferret :fields =[:competitor, :client, :subject_matter],:remote = true end

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  • How can I check if an order with a given increment id already exists in magento?

    - by Thomas Vander Stichele
    I am new to Magento. What's the proper way to check if an order with a given increment id already exists ? The obvious way: $order = Mage::getModel('sales/order')->loadByIncrementId($reservedOrderId); if ($order) { Mage::log('already have order with id ' . $reservedOrderId); return $order; } does not work, because I get a new and empty model instance back. What's the correct way in magento to see if I have no such model for that id ?

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  • why drawRect method is not being called?

    - by user338322
    #import <UIKit/UIKit.h> @interface quartzViewController : UIViewController { IBOutlet UIView *myView; } @end #import "quartzViewController.h" @implementation quartzViewController -(void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSelectFont(context, "Arial", 24, kCGEncodingFontSpecific); CGContextSetTextPosition(context,80,80); CGContextShowText(context, "hello", 6); //not even this works CGContextShowTextAtPoint(context, 1,1, "hello", 6); } - (void)viewDidLoad { [myView setNeedsDisplay]; [super viewDidLoad]; } Will I have to make any changed in the nib? Thanks

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  • can QuickGraph support these requirements? (includes database persistence support)

    - by Greg
    Hi, Would QuickGraph be able to help me out with my requirements below? (a) want to model a graph of nodes and directional relationships between nodes - for example to model web pages/files linked under a URL, or modeling IT infrastructure and dependencies between hardware/software. The library would include methods such as * Node.GetDirectParents() //i.e. there could be more than one direct parent for a node * Node.GetRootParents() //i.e. traverse the tree to the top root parent(s) for the given node * Node.GetDirectChildren() * Node.GetAllChildren() (b) have to persist the data to a database - so it should support SQL Server and ideally SQLite as well. If it does support these requirement then I'd love to hear: any pointers to any parts of QuickGraph to dig into? what is the best concept re it's usage in terms of how to use database persistence - is it a simpler design to assume every search/method works directly on the database, or does QuickGraph support smarts to be able to work in memory and the "save" to database all changes at an appropriate point in time (e.g. like ADO.net does with DataTable etc) Thanks in advance

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  • Where should I store user config data? Specificaly the path to the data file?

    - by jamone
    I have an app using a SQLite db, and I need the ability for the user to move the data file and point the app to where it moved to. I used the Entity Framework to create the model, and by default it puts the connection string in the App.Config file. From what I've read if I make changes to the connection string there then they won't take effect until the app is restarted. That seems a bit clunky for my use. I see how I can init my model and pass in a custom string but I'm unsure what the best practice is in where to store basic user prefrences such as this? Ini, Registry, somewhere else? I don't want the user to have to "Open" the file each time, just when it relocates and then the app will try to auto open from then on.

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  • Silverlight dataGrid binding with ria Service doesn' work

    - by Abdulrhman
    hi every one i'm new to Silverlight and it's totally driving me crazy !! i'm using SL4 and trying to bind datagrid with a Domain Service Query: what i did exactly is i generate an ado.net entity model from my database, then create a domain Service class from this model. then in my page i put Datagrid & button. in the click event for this button i write this code: RRDomainContext rr = new RRDomainContext(); this.dataGrid1.ItemsSource = rr.Rooms; this.rr.Load(this.rr.GetRoomsQuery()); when this method executed the nothing changed at the datagrid. can anyone help me with this ?

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  • Where to put to_xls and from_xls in a rails app

    - by Joe Arasin
    So I have a model that I need to be able to serialize to/read from an Excel(XLS) document. I am a bit of a loss as to where this code actually belongs. My initial thought is that the to_xls is a view, but after poking around and seeing things like (to|from)_xml and (to|from)_json in ActiveRecord, I was wondering if maybe this stuff belonged in the model. Alternatively, does it belong in just a whole separate container somewhere? For what it's worth, users will be downloading models from the site, modifying them in excel, then posting them.

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  • How can I use MVC ideas without using classes?

    - by jpjp
    As of right now, I am still shaky on classes, so I don't want to use any classes for my site. I'm still practicing with classes. But how can I implement the MVC idea without classes? Would this work for a MVC? index.php (the view) index_controller.php index_model.php Is this right for what a MVC should be? View: show html, css, forms Controller: get $_POST from forms and any data from the user, get info from db Model: do all the functions, insert/delete in db, etc Basically separate the HTML/css for the view, all the data collecting for the controller, and the logic for the model. And just connect them all using require_once.

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  • How do I get the Jetty 6 FileServerXml example to work?

    - by Norm
    I have followed along with the Tutorial and the examples. Yet I always get this error when I copy and paste the code: Exception in thread "main" java.lang.NullPointerException at net.test.FileServerXml.main(FileServerXml.java:13) In Eclipse I have the directory structured as such: package net.test -FileServerXml.java -fileserver.xml -index.html FileServerXml.java package net.test; import org.mortbay.jetty.Server; import org.mortbay.resource.Resource; import org.mortbay.xml.XmlConfiguration; public class FileServerXml { public static void main(String[] args) throws Exception { Resource fileserver_xml = Resource.newSystemResource("fileserver.xml"); XmlConfiguration configuration = new XmlConfiguration(fileserver_xml.getInputStream()); Server server = (Server)configuration.configure(); server.start(); server.join(); } } ` fileserver.xml `<?xml version="1.0"?> <Call name="addConnector"> <Arg> <New class="org.eclipse.jetty.server.nio.SelectChannelConnector"> <Set name="port">8080</Set> </New> </Arg> </Call> <Set name="handler"> <New class="org.eclipse.jetty.server.handler.HandlerList"> <Set name="handlers"> <Array type="org.eclipse.jetty.server.Handler"> <Item> <New class="org.eclipse.jetty.server.handler.ResourceHandler"> <Set name="directoriesListed">true</Set> <Set name="welcomeFiles"> <Array type="String"><Item>index.html</Item></Array> </Set> <Set name="resourceBase">.</Set> </New> </Item> <Item> <New class="org.eclipse.jetty.server.handler.DefaultHandler"> </New> </Item> </Array> </Set> </New> </Set> ` Thanks for your input. Norm

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  • view state in ASP.NET MVC Application

    - by Shetty
    Hi, I have read that viewstate is not there in asp.net MVC application. I am doing model validation. Now if i have two text boxes on my page,and i am doing required filed validation for both of them in model. This validation is done on server side on click of a button. I will fill one text box and click on submit button. It does the validation and returns the result saying second field is required. At this time value of the first text box is retained. So can you tell me how this text box is retaining the value even after postback?

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  • Custom keys for Google App Engine models (Python)

    - by Cameron
    First off, I'm relatively new to Google App Engine, so I'm probably doing something silly. Say I've got a model Foo: class Foo(db.Model): name = db.StringProperty() I want to use name as a unique key for every Foo object. How is this done? When I want to get a specific Foo object, I currently query the datastore for all Foo objects with the target unique name, but queries are slow (plus it's a pain to ensure that name is unique when each new Foo is created). There's got to be a better way to do this! Thanks.

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  • APP CAN'T LAUNCH IN XCODE

    - by user2977180
    I'm beginning to code in xCode 5 and I'm doing a really simple app. I just began and, when I try to test my game with iOS Simulator, the main page opens, but when I click on the button to launch the game, I'm redirected to xCode and this appears: #import "AppDelegate.h" #import "AppDelegate.h" int main(int argc, char * argv[]) { @autoreleasepool { return UIApplicationMain(argc, argv, nil, NSStringFromClass([AppDelegate class])); } } and just next to it, this is written: Thread 1 : Signal SIGABRT I searched on internet and I just can't seem to find an answer. Could someone help me please???

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  • WxPython multiple grid instances

    - by randomPythonHacker
    Does anybody know how I can get multiple instances of the same grid to display on one frame? Whenever I create more than 1 instance of the same object, the display of the original grid widget completely collapses and I'm left unable to do anything with it. For reference, here's the code: import wx import wx.grid as gridlib class levelGrid(gridlib.Grid): def __init__(self, parent, rows, columns): gridlib.Grid.__init__(self, parent, -1) self.moveTo = None self.CreateGrid(rows, columns) self.SetDefaultColSize(32) self.SetDefaultRowSize(32) self.SetColLabelSize(0) self.SetRowLabelSize(0) self.SetDefaultCellBackgroundColour(wx.BLACK) self.EnableDragGridSize(False) class mainFrame(wx.Frame): def __init__(self, parent, id, title): wx.Frame.__init__(self, parent, id, title, size=(768, 576)) editor = levelGrid(self, 25, 25) panel1 = wx.Panel(editor, -1) #vbox = wx.BoxSizer(wx.VERTICAL) #vbox.Add(editor, 1, wx.EXPAND | wx.ALL, 5) #selector = levelGrid(self, 1, 25) #vbox.Add(selector, 1, wx.EXPAND |wx.BOTTOM, 5) self.Centre() self.Show(True) app = wx.App() mainFrame(None, -1, "SLAE") app.MainLoop()

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  • Importing Classes Within a Module

    - by CodeJoust
    Currently, I have a parser with multiple classes that work together. For Instance: TreeParser creates multiple Product and Reactant modules which in turn create multiple Element classes. The TreeParser is called by a render method within the same module, which is called from the importer. Currently, using the class name in the imported module file works only if the file calling the module contains from module_name import *, so the classes are imported into the main namespace. Finally, if the package has dependencies (such as re and another another module within the same folder), where is the best place to require those modules? Within the __init__.py file or within the module itself? I don't really want to add the module name in front of every call to the class, in case I do call import *, however, is it possible to use a variable name of the current module to call the class, or use a workaround in the __init__.py file? I'm probably used to the ruby require '' method instead of python's module system.

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  • ASP.net MVC Using view models in different views

    - by Azhar Rana
    i have 2 customer views one for create and one for edit. i am using the same Customer view model for both. i want to make the 'customer no field' required on the add but not the edit. if i put the requiredfield attribute on the view model property then both views flag 'Customer No' as required (as you would expect). Is there a built in solution to get around this problem or am i going to have to create 2 seperate view models, one with the attribute and one without. Thanks

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  • Random generates same number in java

    - by user1613360
    This is my java code. import java.io.*; import java.util.*; import java.util.concurrent.TimeUnit; class search { private int numelem; private int[] input=new int[100]; public void setNumofelem() { System.out.println("Enter the total numebr of elements"); Scanner yz=new Scanner(System.in); numelem=yz.nextInt(); } public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { input[j]=rand.nextInt(max)+1; } } public void printinput() { int b=numelem,t=0; while(true) if(b!=0) { System.out.print(" "+input[t]); b--; t++; } else break; } } public class mycode { public static void main(String args[]) throws Exception { search a=new search(); a.setNumofelem(); a.randomnumber(); a.printinput(); } } Now the function randomnumber() just returns the same number.The function executes perfectly if I execute it as a separate java program but fails miserably if I call it using an object.I have also tried the following variations but nothing works everything return the same number. Variation 1: public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { TimeUnit.SECONDS.sleep(1); input[j]=rand.nextInt(max)+1; } } Variation 2: public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { rand.setSeed(System.nanoTime()); input[j]=rand.nextInt(max)+1; } } Variation 3: public void randomnumber() throws Exception { int max=500,min=1,n=numelem; Random rand = new Random(); for (int j=0;j < n;j++) { TimeUnit.SECONDS.sleep(1); rand.setSeed(System.nanoTime()); input[j]=rand.nextInt(max)+1; } } Sample input/Output: Enter the number of elements: 5 23 23 23 23 23 23

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  • Why do people still use C these days? [closed]

    - by Joshua
    C++ is clearly a far superior language than C, since it has many features that C lacks (although, C++'s object model isn't as ideal as say C#'s). With the coming off the new C++0x standard, why hasn't C been phased out to obscurity? C++ has been around for so long, since the '80s. The Linux kernel has already been ported to C++ with negligible performance differences. I believe, with no evidence, that larger program structures benefit in performance if written in C++ than in C, if only because of object interaction. Don't get me started on "objects-in-C!" libraries, which are all a terrible hack. (Not that C++'s object model is the most ideal, but it is almost up to snuff with C# using common ad-hoc techniques.)

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  • Problem with Eclipse and a Maven multi-module project

    - by earth
    I have created a Maven project with the following structure: + root-project pom.xml (pom) + sub-projectA (jar) + sub-projectB (jar) I have done the following steps: mvn archetype:create –DgroupId=my.group.id –DartifactId=root-project mvn archetype:create –DgroupId=my.group.id –DartifactId=sub-projectA mvn archetype:create –DgroupId=my.group.id –DartifactId=sub-projectB So I have, obviously, in the top-level pom.xml the following elements: <modules> <module>sub-projectA</module> <module>sub-projectB</module> </modules> The last step was: mvn eclipse:clean eclipse:eclipse Now if I import the root-project in Eclipse, it seems to look at my projects as resources and not like java projects. However if I import each of child projects sub-projectA and sub-projectB, it looks them like java projects. This is a big problem for me because I have a deeper hierarchy. Any help would be appreciated!

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  • How do you store sets in Cassandra?

    - by Ben W
    I'd like to convert this JSON to a data model in Cassandra, where each of the arrays is a set with no duplicates: var data = { "data1": { "100": [1, 2, 3], "200": [3, 4] }, "data2": { "k1", [1], "k2", [4, 5] } } I'd like to query like this: data["data1"]["100"] to retrieve the sets. Anyone know how you might model this in Cassandra? (The only thing I came up with was columns whose name was a set value and the value of the column was an empty string, but that felt wrong.) It's not OK to serialize the sets as JSON or some other string, which would make this much easier. Also, I should note that it's OK to split data1 and data2 into separate ColumnFamilies, it's not necessary that they're keys in the same one.

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  • Sympy python circumference

    - by Mattia Villani
    I need to display a circumference. In order to do that I thought I could calculata for a lot of x the two values of y, so I did: import sympy as sy from sympy.abc import x,y f = x**2 + y**2 - 1 a = x - 0.5 sy.solve([f,a],[x,y]) and this is what I get: Traceback (most recent call last): File "<input>", line 1, in <module> File "/usr/lib/python2.7/dist-packages/sympy/solvers/solvers.py", line 484, in solve solution = _solve(f, *symbols, **flags) File "/usr/lib/python2.7/dist-packages/sympy/solvers/solvers.py", line 749, in _solve result = solve_poly_system(polys) File "/usr/lib/python2.7/dist-packages/sympy/solvers/polysys.py", line 40, in solve_poly_system return solve_biquadratic(f, g, opt) File "/usr/lib/python2.7/dist-packages/sympy/solvers/polysys.py", line 48, in solve_biquadratic G = groebner([f, g]) File "/usr/lib/python2.7/dist-packages/sympy/polys/polytools.py", line 5308, i n groebner raise DomainError("can't compute a Groebner basis over %s" % domain) DomainError: can't compute a Groebner basis over RR How can I calculate the y's values ?

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  • why is this dictionary line number count not working?

    - by jad
    i have this piece of code the last bit of the code starting from d = {} im trying to print the words with its line number located in the text but it is not working its only printing the words anyone know why ??? need help ASAP import sys import string text = [] infile = open(sys.argv[1], 'r').read() for punct in string.punctuation: infile = infile.replace(punct, "") text = infile.split() dict = open(sys.argv[2], 'r').read() dictset = [] dictset = dict.split() words = [] words = list(set(text) - set(dictset)) words = [text.lower() for text in words] words.sort() d = {} counter = 0 for lines in text: counter += 1 if word not in d: d[words] = [counter] else: d[words.append[counter] print(word, d)

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  • Managing Large Database Entity Models

    - by ChiliYago
    I would like hear how other's are effectively (or not) working with the Visual Studio Entity Designer when many database tables exists. It seems to me that navigating the Designer is tough enough to find what you are looking for with just a few tables but how about a database with say 100 to 200 tables? When a table change is made at the database level how is the model updated? Does it overwrite any manual changes you have made to the model? How would you quickly find an entity in the designer to make a change or inspect a change? Seems unrealistic to be scrolling around looking for specific entity. Thanks for your feedback!

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  • NameError when using act_as_ferret

    - by manish nautiyal
    Hi all I am getting this error when I am using acts_as_ferret :fields =[:competitor], :remote = true NameError in PartController#index uninitialized constant PartController::Competitor My Model class Competitor < ActiveRecord::Base validates_presence_of :fee_earner_id, :notes belongs_to :fee_earner belongs_to :country belongs_to :state belongs_to :user acts_as_ferret :fields =[:competitor], :remote = true end My controller class PartController < ApplicationController def index @proscribeds = Competitor.paginate(:all, :order = sort , :page = params[:page], :per_page = 70 ) end end Its working fine in localhost but when I deploy it in the server than I get this error. act_as_ferret is working good with other models. I don't know why this is not working with only Competitor model.

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  • Why is Scaffolding Not Working in Ruby on Rails?

    - by Timmy
    I created a controller and a model. The controller is called "Admin" and the model is called "Album". I edited database.yml with proper info and did the rake db:migrate command which didn't return any errors and did migrate the db inside schema.rb. Inside the controller I wrote: class AdminController < ApplicationController scaffold :album end Next I started my server and went to http://localhost:3000/admin but instead of seeing the typical CRUD page I get the following error: app/controllers/admin_controller.rb:3 Request Parameters: None Show session dump --- flash: !map:ActionController::Flash::FlashHash {} Response Headers: {"cookie"=>[], "Cache-Control"=>"no-cache"} Any idea why?

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