Search Results

Search found 17036 results on 682 pages for 'mysql administrator'.

Page 361/682 | < Previous Page | 357 358 359 360 361 362 363 364 365 366 367 368  | Next Page >

  • PHP - How to get, and display the biggest values from a database?

    - by Dodi300
    Hello. Can anyone tell me how to get and display the biggest values from a database? I have multiple values in my database with the heading "gmd", but how would I get only the first 3 biggest ones to be displayed? How would I do it in this example: $query = "SELECT gmd FROM account"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { } Thanks.

    Read the article

  • SQL Injection When Using MySQLi Prepared Statements

    - by Sev
    If all that is used to do any and all database queries is MySQLi prepared statements with bound parameters in a web-app, is sql injection still possible? Notes I know that there are other forms of attack other than sql-injection, but my question is specific to sql-injection attacks on that particular web application only.

    Read the article

  • SQL Query Math Gymnastics

    - by keruilin
    I have two tables of concern here: users and race_weeks. User has many race_weeks, and race_week belongs to User. Therefore, user_id is a fk in the race_weeks table. I need to perform some challenging math on fields in the race_weeks table in order to return users with the most all-time points. Here are the fields that we need to manipulate in the race_weeks table. races_won (int) races_lost (int) races_tied (int) points_won (int, pos or neg) recordable_type(varchar, Robots can race, but we're only concerned about type 'User') Just so that you fully understand the business logic at work here, over the course of a week a user can participate in many races. The race_week record represents the summary results of the user's races for that week. A user is considered active for the week if races_won, races_lost, or races_tied is greater than 0. Otherwise the user is inactive. So here's what we need to do in our query in order to return users with the most points won (actually net_points_won): Calculate each user's net_points_won (not a field in the DB). To calculate net_points, you take (1000 * count_of_active_weeks) - sum(points__won). (Why 1000? Just imagine that every week the user is spotted a 1000 points to compete and enter races. We want to factor-out what we spot the user because the user could enter only one race for the week for 100 points, and be sitting on 900, which we would skew who actually EARNED the most points.) This one is a little convoluted, so let me know if I can clarify further.

    Read the article

  • Why is the ( ) mandatory in the SQL statement select * from gifts INNER JOIN sentgifts using (giftID

    - by Jian Lin
    Why is the ( ) mandatory in the SQL statement select * from gifts INNER JOIN sentgifts using (giftID); ? The ( ) usually is for specifying grouping of something. But in this case, are we supposed to be able to use 2 or more field names... in the example above, it can be all clear that it is 1 field, is it just that the parser is not made to bypass the ( ) when it is all clear? (such as in the language Ruby).

    Read the article

  • Matching process , issue with query

    - by Blerta Blerta
    i have this code which helps me match two different tables.. now, each of this tables, has a epos_id and a rbpos_id ! I have another table which has pairs of rbpos_id and epos_id, something like: id | epos_id | rbpos_id 1 a3566 465jd 2 hkiyb rbposi When i join this other table, i need to check this condition, i mean, the matching should be done, only and if, the epos_id and rbpos_id of the join i'm doing, have the same id,i mean, belong to the same row.. Here is my current query... Thanks! SELECT retailer.date, retailer.time, retailer.location, retailer.user_id,imovo.mobile_number ". "FROM retailer LEFT JOIN imovo ". " ON addtime(retailer.time, '0:0:50')>imovo.time AND retailer.time <imovo.time AND retailer.date=imovo.date

    Read the article

  • Getting dynamic childs for a parent in SQL

    - by Islam
    I have a table called Categories which contains category_Id and parent_category_Id, so each category can has a child and the child can has a child and so on (it is dynamic). So if i have category A and category A has child B and child B has child C and child C has child D. I want to get all the child tree of A using SQL so when I give this query the id of A its result will be the ids of A's child which is B,C & D.....any ideas. Thanks in regards,

    Read the article

  • In MATLAB can I convert a java boolean to a MATLAB logical?

    - by Adrian
    In MATLAB I'm using a couple of java routines I've written to interface with a MyQSL database. One routine returns a boolean value result <1x1 java.lang.Boolean> >> result result = true When I then use it in a conditional statement I get an error message. >> if result, disp('result is true') end ??? Conversion to logical from java.lang.Boolean is not possible. Is there a way to use the java boolean class as a MATLAB logical type? Or do I have to resort to returning integer values from my java routines?

    Read the article

  • Rails advanced queries with join and sum calculation

    - by Dustin Brewer
    I have two models: companies and expenses. Companies have many expenses and expenses belong to companies. My expense model has an 'amount' column. I was wondering if there is a way to perform a find based on a date range and the amount column of the expenses. Something like top 3 companies by total expense amounts over a 7 day period. I've tried for the better part of the day to get this to work, I've attempted joins, chaining named scopes, raw sql, etc. and I'm not having any luck. Thanks for the help.

    Read the article

  • In SQL, can we always write an inner join statement as a main query and subquery if we only want to

    - by Jian Lin
    In SQL, can we always write an inner join statement as a main query and subquery or vice versa if we only want to find the intersection? For example, select * from gifts g where g.giftID in (select giftID from sentGifts); can do a join and show the gifts sent in the sentGifts table, but it won't be able to show the sentTime because that is inside the subquery. But if all we care is to find the intersection, without caring what is being displayed, then we can always convert one to the other?

    Read the article

  • SQL: How can i update a value on a column only if that value is null?

    - by user321185
    Hey, I have an SQL question which may be basic to some but is confusing me. Here is an example of column names for a table 'Person': PersonalID, FirstName, LastName, Car, HairColour, FavDrink, FavFood Let's say that I input the row: 121312, Rayna, Pieterson, BMW123d, Brown, NULL, NULL Now I want to update the values for this person, but only if the new value is not null, Update: 121312, Rayna, Pieterson, NULL, Blonde, Fanta, NULL The new row needs to be: 121312, Rayna, Pieterson, BMW123d, Blonde, Fanta, NULL So I was thinking something along the lines of: Update Person(PersonalID, FirstName, LastName, Car, HairColour, FavDrink, FavFood) set Car = @Car (where @Car is not null), HairColour = @HairColour (where @HairColour...)... etc. My only concern is that I can't group all the conditions at the end of the query because it will require all the values to have the same condition. Can't i do something like Update HairColour if @HairColour is not Null

    Read the article

  • Javascript Confirm Delete in One PHP File (on href)

    - by gamerzfuse
    <p><span class="linky"><a href="deletephone.php?id=' . $row['id'] . '">Delete Phone</a></span></p><br /> I have the above code that I am using to link to a delete script. I want to somehow incorporate Javascript with a simple onclick confirmation. This way if they choose OK, I can run the code to delete the item from the database, but if they choose Cancel then I can cancel the operation and do nothing. I have tried a whole variety of functions with changing the window.location to the delete file, and trying to cancel the href= if they choose Cancel, but it always goes to the link regardless of what the user clicks. I would like to be able to keep the delete functions inside the same PHP file if possible, but this is not necessary at all. Thanks in advance! ASIDE: If there is a simple PHP way to check IF the alert was confirmed or denied, that could work also. Any way to check what the user chooses and then run my simple delete PHP command.

    Read the article

  • Remove redundant SQL code

    - by Dave Jarvis
    Code The following code calculates the slope and intercept for a linear regression against a slathering of data. It then applies the equation y = mx + b against the same result set to calculate the value of the regression line for each row. Can the two separate sub-selects be joined so that the data and its slope/intercept are calculated without executing the data gathering part of the query twice? SELECT AVG(D.AMOUNT) as AMOUNT, Y.YEAR * ymxb.SLOPE + ymxb.INTERCEPT as REGRESSION_LINE, Y.YEAR as YEAR, MAKEDATE(Y.YEAR,1) as AMOUNT_DATE FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D, (SELECT ((avg(t.AMOUNT * t.YEAR)) - avg(t.AMOUNT) * avg(t.YEAR)) / (stddev( t.AMOUNT ) * stddev( t.YEAR )) as CORRELATION, ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT FROM ( SELECT AVG(D.AMOUNT) as AMOUNT, Y.YEAR as YEAR, MAKEDATE(Y.YEAR,1) as AMOUNT_DATE FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE $X{ IN, C.ID, CityCode } AND SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < $P{Radius} AND S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND Y.YEAR BETWEEN 1900 AND 2009 AND M.YEAR_REF_ID = Y.ID AND M.CATEGORY_ID = $P{CategoryCode} AND M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ) t ) ymxb WHERE $X{ IN, C.ID, CityCode } AND SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < $P{Radius} AND S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND Y.YEAR BETWEEN 1900 AND 2009 AND M.YEAR_REF_ID = Y.ID AND M.CATEGORY_ID = $P{CategoryCode} AND M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR Question How do I execute the duplicate bits only once per query, instead of twice? The duplicate bit is the WHERE clause: $X{ IN, C.ID, CityCode } AND SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < $P{Radius} AND S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND Y.YEAR BETWEEN 1900 AND 2009 AND M.YEAR_REF_ID = Y.ID AND M.CATEGORY_ID = $P{CategoryCode} AND M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' Related http://stackoverflow.com/questions/1595659/how-to-eliminate-duplicate-calculation-in-sql Thank you!

    Read the article

  • SQL hidden techniques?

    - by AlexRednic
    What are those pro/subtle techniques that SQL provides and not many know about which also cut code and improve performance? eg: I have just learned how to use CASE statements inside aggregate functions and it totally changed my approach on things. Are there others?

    Read the article

  • how to combine these queries

    - by mmcgrail
    and get meaningful results. Currently I am running these three queries: SELECT t.type,t.id,s.title FROM db1.tags t INNER JOIN db1.st s ON s.id=t.id WHERE id LIKE '%%' AND t.tag='foo' AND t.type='s' ORDER BY tag desc LIMIT 0, 19 SELECT t.type,t.id,v.title FROM db1.tags t INNER JOIN db1.vi v ON v.id=t.id WHERE id LIKE '%%' AND t.tag='foo' AND t.type='v' ORDER BY tag desc LIMIT 0, 19 SELECT t.type,t.id,i.ca AS title FROM db1.tags t INNER JOIN db2.tablename i ON i.id=t.id WHERE id LIKE '%%' AND t.tag='foo' AND t.type='i' ORDER BY tag desc LIMIT 0, 19 then trying to combine the data results but what I would really prefer is if I could combine them into a single query. Any thoughts?

    Read the article

  • How to get the answers version and use it in IF loop

    - by sai
    delimiter // DROP PROCEDURE `getData`// CREATE DEFINER=`root`@`localhost` PROCEDURE `getData`(IN templateName VARCHAR(45),IN templateVersion VARCHAR(45),IN userId VARCHAR(45)) BEGIN set @version = CONCAT("SELECT `saveOEMsData_answersVersion` FROM `saveOEMsData` WHERE `saveOEMsData_templateName` = '",templateName,"' AND `saveOEMsData_templateVersion` = ",templateVersion," AND `saveOEMsData_userId`= ",userId); PREPARE s1 from @version; EXECUTE S1; END // delimiter ; I am retreiving saveOEMsData_answersVersion, but I have to use it in an IF loop, as in if the version == 1, then I would use a query, else I would use something else. But I am not able to use the version. Could someone help with this?? I am only able to print but not able to use the version.

    Read the article

  • function and class to show image not working in php

    - by Gully
    i am trying to get get the following working nothing is happen when i use the function i am trying to get it to display images class ItemRes { //items DB var $img=""; } function ShowItemImage($index,$res_a){ if(sizeof($res_a) > $index){ if($res_a[$index] != NULL) { $cimg = $res_a[$index]->img; return "<img src='$cimg' width='70' height='70' style='cursor:pointer'></img>"; } }else{ return "<center class='whitetxt'><strong>Empty</strong></center>"; } } $res_array = array(); $idx=0; $result21 = mysql_query("SELECT * FROM photos WHERE eid='$eid' ORDER BY id DESC") or die (mysql_error()); while ($row21 = mysql_fetch_array($result21)) { $img_path = $row21['path']; $obj = new ItemRes(); $obj->img = $img_path; $res_array[$idx] = $obj; $idx++; } ShowItemImage(0,$res_array) ShowItemImage(1,$res_array)

    Read the article

  • pagination and url encoding help

    - by Sufyan
    <?php $name=$_POST['name']; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="text" name="name"> <input type="submit" value="GO" name="submit"> </form> <?php include ('db.php'); if(isset($_POST['submit'])) { mysql_query ("INSERT INTO example (name) VALUES('$name')") or die(mysql_error()); } if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) { $startrow = 0; } else { $startrow = (int)$_GET['startrow']; } $query = "SELECT * FROM example ORDER BY id DESC LIMIT $startrow, 20"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "<li>"; echo $row['name'] ." "." <a href= 'like.php?quote=" . urlencode( $row['name'] ) . "'>Click Here</a>"; echo "</li>"; } echo '<a href="'.$_SERVER['PHP_SELF'].'?startrow='.($startrow+10).'">Next</a>'; ?> I want to make my page links hidden , how can i make then hidden so that a user cant edit it. 2nd question, currently i am showing total 10 records on each page and then a next page button , but the next button is keep showing even when there is no more records...! how to remove a next page button when records ended. ?? line number 28 is the link to pages which can be easyily editable by any user, i wnat to make them secure (using ID) and line 35 is n'next' page link , this link should not be appear when number of records ended

    Read the article

  • Dummies guide to locking in innodb

    - by ming yeow
    The typical documentation on locking in innodb is way too confusing. I think it will be of great value to have a "dummies guide to innodb locking" I will start, and I will gather all responses as a wiki: The column needs to be indexed before row level locking applies. EXAMPLE: delete row where column1=10; will lock up the table unless column1 is indexed

    Read the article

  • how to send value to the from action page from database

    - by Mayank swami
    I am creating a faq panel for there can be multiple answers for question and i want to take the answer id .because i am storing comment by answer id the problem is that how to sent the $answer_id to the comment_submit_process.php and how to recognize the answer ? $selected_ques= mysql_prep($_GET['ques']); $query = "SELECT * FROM formanswer where question_id = {$selected_ques}"; $ans= mysql_query($query); if($ans){ while($answer = mysql_fetch_array($ans)) //here is the form <form id="add-comment" action="comment_submit_process.php" > <textarea class="comment-submit-textarea" cols="78" name="comment" style="height: 64px;"></textarea> <input type="submit" name="submitbutton" value="Add Comment" class="comment-submit-button" > <br> <?php $ans_id= $answer['id']; echo $ans_id; ?> <input type="hidden" name="ques" value="<?php echo $_GET['$ans_id'] ?>" /> <span class="counter ">enter at least 15 characters</span> <span class="form-error"></span> </form> <?php }} ?>

    Read the article

  • Fast, easy, and secure method to perform DB actions with GET

    - by rob - not a robber
    Hey All, Sort of a methods/best practices question here that I am sure has been addressed, yet I can't find a solution based on the vague search terms I enter. I know starting off the question with "Fast and easy" will probably draw out a few sighs, so my apologies. Here is the deal. I have a logged in area where an ADMIN can do a whole host of POST operations to input data relating to their profile. The way I have data structured is pretty distinct and well segmented in most tables as it relates to the ID of the admin. Now, I have a table where I dump one type of data into and differentiate this data by assigning the ADMIN's unique ID to each record. In other words, all ADMINs have this one type of data writing to this table. I just differentiate by the ADMIN ID with each record. I was planning on letting the ADMIN remove these records by clicking on a link with a query string - obviously using GET. Obviously, the query structure is in the link so any logged in admin could then exploit the URL and delete a competitor's records. Is the only way to safely do this through POST or should I pass through the session info that includes password and validate it against the ADMIN ID that is requesting the delete? This is obviously much more work for me. As they said in the auto repair biz I used to work in... there are 3 ways to do a job: Fast, Good, and Cheap. You can only have two at a time. Fast and cheap will not be good. Good and cheap will not have fast turnaround. Fast and good will NOT be cheap. haha I guess that applies here... can never have Fast, Easy and Secure all at once ;) Thanks in advance...

    Read the article

< Previous Page | 357 358 359 360 361 362 363 364 365 366 367 368  | Next Page >