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  • Timer Service in ejb 3.1 - schedule calling timeout problem

    - by Greg
    Hi Guys, I have created simple example with @Singleton, @Schedule and @Timeout annotations to try if they would solve my problem. The scenario is this: EJB calls 'check' function every 5 secconds, and if certain conditions are met it will create single action timer that would invoke some long running process in asynchronous fashion. (it's sort of queue implementation type of thing). It then continues to check, but as long as long running process is there it won't start another one. Below is the code I came up with, but this solution does not work, because it looks like asynchronous call I'm making is in fact blocking my @Schedule method. @Singleton @Startup public class GenerationQueue { private Logger logger = Logger.getLogger(GenerationQueue.class.getName()); private List<String> queue = new ArrayList<String>(); private boolean available = true; @Resource TimerService timerService; @Schedule(persistent=true, minute="*", second="*/5", hour="*") public void checkQueueState() { logger.log(Level.INFO,"Queue state check: "+available+" size: "+queue.size()+", "+new Date()); if (available) { timerService.createSingleActionTimer(new Date(), new TimerConfig(null, false)); } } @Timeout private void generateReport(Timer timer) { logger.info("!!--timeout invoked here "+new Date()); available = false; try { Thread.sleep(1000*60*2); // something that lasts for a bit } catch (Exception e) {} available = true; logger.info("New report generation complete"); } What am I missing here or should I try different aproach? Any ideas most welcome :) Testing with Glassfish 3.0.1 latest build - forgot to mention

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  • How do I fork correctly in a perl module for znc?

    - by rarbox
    I'm currently writing an IRC bot. The scripts are loaded as perl modules in ZNC but the bot gets disconnected with an Input/Output error if I create a forked process. This is a working example script without fork, but this causes the bot to freeze until the script finishes doing its task. package imdb; use warnings; use strict; sub new { my ($class) = @_; my $self = {}; bless( $self, $class ); return( $self ); } sub OnChanMsg { my ($self, $nick, $channel,$text) = @_; #unless (my $pid = fork()) { my $result = a_slow_process($text); ZNC::PutIRC( "PRIVMSG $channel :$result" ); # exit; #} return( ZNC::CONTINUE ); } sub OnShutdown { my ( $me ) = @_; } sub a_slow_process { my $input = shift; sleep 10; return "You said $input."; } 1; The fork code that is causing the error is commented out. How do I fix this? Edited to add: I was told that ZNC::PutIRC should not be put in the child process.

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  • Set HttpContext.Current.User from Thread.CurrentPrincipal

    - by Argons
    I have a security manager in my application that works for both windows and web, the process is simple, just takes the user and pwd and authenticates them against a database then sets the Thread.CurrentPrincipal with a custom principal. For windows applications this works fine, but I have problems with web applications. After the process of authentication, when I'm trying to set the Current.User to the custom principal from Thread.CurrentPrincipal this last one contains a GenericPrincipal. Am I doing something wrong? This is my code: Login.aspx protected void btnAuthenticate_Click(object sender, EventArgs e) { Authenticate("user","pwd"); FormsAuthenticationTicket authenticationTicket = new FormsAuthenticationTicket(1, "user", DateTime.Now, DateTime.Now.AddMinutes(30), false, ""); string ticket = FormsAuthentication.Encrypt(authenticationTicket); HttpCookie authenticationCookie = new HttpCookie(FormsAuthentication.FormsCookieName, ticket); Response.Cookies.Add(authenticationCookie); Response.Redirect(FormsAuthentication.GetRedirectUrl("user", false)); } Global.asax (This is where the problem appears) protected void Application_AuthenticateRequest(object sender, EventArgs e) { HttpCookie authCookie = Context.Request.Cookies[FormsAuthentication.FormsCookieName]; if (authCookie == null) return; if (HttpContext.Current.User != null && HttpContext.Current.User.Identity.IsAuthenticated && HttpContext.Current.User.Identity is FormsIdentity) { HttpContext.Current.User = System.Threading.Thread.CurrentPrincipal; //Here the value is GenericPrincipal } Thanks in advance for any help. }

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  • How do I maximize a window in one monitor and do other things on the other monitor

    - by RoboShop
    Hi, I have windows 7 installed on my laptop which is a Dell studio XPS 16. I recently set up a second monitor for it. I've noticed that when I load up "full maximisation" applications (I don't know the term) like a game or media center on one monitor, I can't seem to do anything with the other monitor. With the game, I can see the other monitor, I can play a movie on it even, but if I click the mouse button on it, it'll stop the game and alt-tab away. In Media Center, I can't even cross my mouse over the other monitor. So my question is, in Windows 7, is it possible to run programs like this that are designed to be run in one maximised window and still be able to do things on the other window?

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  • Blackberry app stuck trying to access a server.

    - by Tejaswi Yerukalapudi
    Hi, I've built a ASP.NET webservice and I'm trying to access it from a Blackberry. I've been testing it out with multiple devices and the simulator and it works fine, but there's just the one Blackberry 9000 (It's not the model, I've tried it out with another Blackberry 9000), and it's stuck waiting for a response from the server. Relevant section of the code that accesses this - System.out.println("IN ntwk access thread, start point"); HttpConnection connection = (HttpConnection)Connector.open(serviceURL + WSNAME); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); connection.setRequestProperty("Content-length", Integer.toString(postData1.length)); OutputStream requestOutput = connection.openOutputStream(); requestOutput.write(postData1); requestOutput.close(); final int responseCode = connection.getResponseCode(); if(responseCode!= HttpConnection.HTTP_OK) { //Process the error condition } // Request succeeded process the data. It seems to be getting stuck after connection.getResponseCode(). Is there some way I can verify what's going wrong with this particular device? Thanks, Teja

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  • Is there software that lets me drag windows between two PCs? (there is!)

    - by Jonathan
    I'm looking for a preferably free program that is similar to MaxiVista, which lets you extend you desktop to another desktops screen on the same network. But with MaxiVista you have to extend the entire screen. I'd like to just drag one window onto the other computers screen without extending the desktop. So on top of the other computer's windows. Kind of like a cross between MaxiVista and Windows 7' XP mode where you can run XP programs on the windows 7 desktop. EDIT: I am pleased to announce this is possible, though the windows is poor quality (8-bit color) but I believe thats just because MetaVNC isn't very up to date.

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  • Byte-Pairing for data compression

    - by user1669533
    Question about Byte-Pairing for data compression. If byte pairing converts two byte values to a single byte value, splitting the file in half, then taking a gig file and recusing it 16 times shrinks it to 62,500,000. My question is, is byte-pairing really efficient? Is the creation of a 5,000,000 iteration loop, to be conservative, efficient? I would like some feed back on and some incisive opinions please. Dave, what I read was: "The US patent office no longer grants patents on perpetual motion machines, but has recently granted at least two patents on a mathematically impossible process: compression of truly random data." I was not inferring the Patent Office was actually considering what I am inquiring about. I was merely commenting on the notion of a "mathematically impossible process." If someone has, in some way created a method of having a "single" data byte as a placeholder of 8 individual bytes of data, that would be a consideration for a patent. Now, about the mathematically impossibility of an 8 to 1 compression method, it is not so much a mathematically impossibility, but a series of rules and conditions that can be created. As long as there is the rule of 8 or 16 bit representation of storing data on a medium, there are ways to manipulate data that mirrors current methods, or creation by a new way of thinking.

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  • Find computer names on a private network (with nmap?)

    - by paracaudex
    On a LAN, I want to find out the names of all the connected computers using a cross-platform program, preferably nmap. I know I can do nmap -sn xxx.xxx.xxx.xxx/24 (where xxx.xxx.xxx.xxx is a local IP address) to find hosts which are up, but how do I find the computers' hostnames? Do they broadcast this in a way that I can find using nmap? UPDATE: It looks like Angry IP Scanner can do this. How does it do this? Can I replicate it with nmap?

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  • Should java try blocks be scoped as tightly as possible?

    - by isme
    I've been told that there is some overhead in using the Java try-catch mechanism. So, while it is necessary to put methods that throw checked exception within a try block to handle the possible exception, it is good practice performance-wise to limit the size of the try block to contain only those operations that could throw exceptions. I'm not so sure that this is a sensible conclusion. Consider the two implementations below of a function that processes a specified text file. Even if it is true that the first one incurs some unnecessary overhead, I find it much easier to follow. It is less clear where exactly the exceptions come from just from looking at statements, but the comments clearly show which statements are responsible. The second one is much longer and complicated than the first. In particular, the nice line-reading idiom of the first has to be mangled to fit the readLine call into a try block. What is the best practice for handling exceptions in a funcion where multiple exceptions could be thrown in its definition? This one contains all the processing code within the try block: void processFile(File f) { try { // construction of FileReader can throw FileNotFoundException BufferedReader in = new BufferedReader(new FileReader(f)); // call of readLine can throw IOException String line; while ((line = in.readLine()) != null) { process(line); } } catch (FileNotFoundException ex) { handle(ex); } catch (IOException ex) { handle(ex); } } This one contains only the methods that throw exceptions within try blocks: void processFile(File f) { FileReader reader; try { reader = new FileReader(f); } catch (FileNotFoundException ex) { handle(ex); return; } BufferedReader in = new BufferedReader(reader); String line; while (true) { try { line = in.readLine(); } catch (IOException ex) { handle(ex); break; } if (line == null) { break; } process(line); } }

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  • Should I return an NSMutableString in a method that returns NSString

    - by Casey Marshall
    Ok, so I have a method that takes an NSString as input, does an operation on the contents of this string, and returns the processed string. So the declaration is: - (NSString *) processString: (NSString *) str; The question: should I just return the NSMutableString instance that I used as my "work" buffer, or should I create a new NSString around the mutable one, and return that? So should I do this: - (NSString *) processString: (NSString *) str { NSMutableString *work = [NSMutableString stringWithString: str]; // process 'work' return work; } Or this: - (NSString *) processString: (NSString *) str { NSMutableString *work = [NSMutableString stringWithString: str]; // process 'work' return [NSString stringWithString: work]; // or [work stringValue]? } The second one makes another copy of the string I'm returning, unless NSString does smart things like copy-on-modify. But the first one is returning something the caller could, in theory, go and modify later. I don't care if they do that, since the string is theirs. But are there valid reasons for preferring the latter form over the former? And, is either stringWithString or stringValue preferred over the other?

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  • Visual Studio .NET 2003 on Windows 7 hangs on search

    - by Nikhil
    So I have Visual Studio 2003 running on Windows 7 - yeah I am aware it isn't officially supported - and no, unfortunately I can't change that situation :-( For the most part it works OK but I have a specific problem, that I can't figure out. The application hangs if you do a project wide search (Ctrl - Shift - F) for a string. I have a reasonably powerful machine and all the other heavy tasks like compiling and debugging all work fine. It also works if I restrict the search to the current document (Ctrl - F). I am running it as administrator and VS.NET 2003 SP1 has been applied. The size of the project does not seem to be a problem since a colleague is also experiencing this issue for a single project solution containing 5 pages. I am currently using Windows Search as a work-around and I was wondering if there is something I missed that I should try. PS: I have asked this question on stack overflow as well - but I suspect this might be problem with Windows 7 OS - so I thought I'd cross post it here as well.

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  • Help with accessing a pre-existing window AFTER opener is refreshed!

    - by Wilhelm Murdoch
    Alright, I'm at my wit's end on this issue. First, backstory. I'm working on a video management system where we're allowing users, when adding new content, to upload and, optionally, transcode a media file. We're using Java applet for the browser-based FTP client. What I want to do is allow a user to initiate an upload and then send the FTP connection instance to a popup window. This window will act as a job queue for the FTP transfer process. This will allow users to move about the main interface without having to stay on the original page until an individual file transfer is complete. For the most part I have all of this working, but here's a problem. If the window is closed, all connections are dropped and the upload process for all queued files will be canceled. So, if Window One opens the Popup Window, adds stuff to the queue, refreshes the screen or moves to a different page, how will I access the Popup Window? The popup window and its contents must remain persistent while the user navigates through the original window. The original window must be able to access the popup to add a new job to the queue. The popup window itself is independent of the opening window, so communication only happens in one direction: Parent - Popup Not Parent <- Popup Window.open(null, 'WINDOW_NAME'); will not work in this case. I need to check if a window exists BEFORE using window.open. Help!?!?

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  • Connecting switch to switch to router

    - by elated
    Hello, Not sure if this is the right place to ask this question. But I have a router which connects to the internet. Now I have a switch connected to this router. I added a lot more computers so I added another switch and connected it to the first switch using a cross-over cable. As soon as I connect it to the first switch, my lights in first switch start blinking like crazy and my entire network simply stops working. The minute I remove the second switch's wire, its all fine again. What could be the problem?

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  • problem with fork()

    - by john
    I'm writing a shell which forks, with the parent reading the input and the child process parsing and executing it with execvp. pseudocode of main method: do{ pid = fork(); print pid; if (p<0) { error; exit; } if (p>0) { wait for child to finish; read input; } else { call function to parse input; exit; } }while condition return; what happens is that i never seem to enter the child process (pid printed is always positive, i never enter the else). however, if i don't call the parse function and just have else exit, i do correctly enter parent and child alternatingly. full code: int main(int argc, char *argv[]){ char input[500]; pid_t p; int firstrun = 1; do{ p = fork(); printf("PID: %d", p); if (p < 0) {printf("Error forking"); exit(-1);} if (p > 0){ wait(NULL); firstrun = 0; printf("\n> "); bzero(input, 500); fflush(stdout); read(0, input, 499); input[strlen(input)-1] = '\0'; } else exit(0); else { if (parse(input) != 0 && firstrun != 1) { printf("Error parsing"); exit(-1); } exit(0); } }while(strcmp(input, "exit") != 0); return 0; }

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  • Typical Hadoop setup for remote job submission

    - by Artii
    So I am still a bit new to hadoop and am currently in the process of setting up a small test cluster on Amazonaws. So my question relates to some tips on the structuring of the cluster so it is possible to work submit jobs from remote machines. Currently I have 5 machines. 4 are basically the Hadoop cluster with the NameNodes, Yarn etc. One machine is used as a manager machine( Cloudera Manager). I am gonna describe my thinking process on the setup and if anyone can chime in the points I am not clear with, that would be great. I was thinking what was the best setup for a small cluster. So I decided to expose only one manager machine and probably use that to submit all the jobs through it. The other machines will see each other etc, but not be accessible from the outside world. I am have conceptual idea on how to do this,but I am not sure how to properly go about doing this though, if anyone could point me in the right direction that would great. Also another big point is, I want to be able to submit jobs to the cluster through exposed machine from a client machine (might be Windows). I am not so clear on this setup as well. Do I need to have Hadoop installed on the machine in order to use the normal hadoop commands, and to write/submit jobs say from Eclipse or something similar. So to sum it up my questions are, Is this an ok setup for a small test cluster How can I go about using one exposed machine to submit/route jobs to the cluster, without having any of the Hadoop nodes on it. How do I setup a client machine to submit jobs to a remote cluster, and an example on how to do it on Windows. Also if there are any reason not to use Windows as a client machine in this setup. Thanks I would greatly appreciate any advice or help on this.

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  • How to upload files to server using JSP/Servlet?

    - by Thang Pham
    How can I upload files to server using JSP/Servlet? I tried this: <form action="upload" method="post"> <input type="text" name="description" /> <input type="file" name="file" /> <input type="submit" /> </form> However, I only get the file name, not the file content. When I add enctype="multipart/form-data" to the <form>, then request.getParameter() returns null. During research I stumbled upon Apache Common FileUpload. I tried this: FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List items = upload.parseRequest(request); // This line is where it died. Unfortunately, the servlet threw an exception without a clear message and cause. Here is the stacktrace: SEVERE: Servlet.service() for servlet UploadServlet threw exception javax.servlet.ServletException: Servlet execution threw an exception at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:637)

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  • Bootstrap - Typehead on multiple inputs

    - by Clem
    I have two text intputs, both have to run an autocompletion. The site is using Bootstrap, and the « typeahead » component. I have this HTML : <input type="text" class="js_typeahead" data-role="artist" /> <input type="text" class="js_typeahead" data-role="location" /> I'm using the « data-role » attribute (that is sent to the Ajax controller as a $_POST index), in order to determine what kind of data has to be retrieved from the database. The Javascript goes this way : var myTypeahead = $('input.js_typeahead').typeahead({ source: function(query, process){ var data_role; data_role = myTypeahead.attr('data-role'); return $.post('/ajax/typeahead', { query:query,data_role:data_role },function(data){ return process(data.options); }); } }); With PHP, I check what $_POST['data-role'] contains, an run the MySQL query (in this case, a query either on a list of Artists, or a list of Locations). But the problem is the second "typeahead" returns the same values than the first one (list of Artists). I assume it's because the listener is attached to the object « myTypeahead », and this way the "data-role" attribute which is used, will always be the same. I think I could fix it by using something like : data_role = $(this).attr('data-role'); But of course this doesn't work, as it's a different scope. Maybe I'm doing it all wrong, but at least maybe you people could give me a hint. Sorry if this has already been discussed, I actually searched but without success. Thanks in advance, Clem (from France, sorry for my english)

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  • IE 8 issue where window.close() is not occuring after winword.exe is fired to print a document

    - by Dave
    In my web application, a popup page is called using window.open javascript. There is a Print button on the page that has an onclick event that calls a printchecks() function. The code in the printchecks() function is function printchecks(){ window.print(); window.close(); } Issue is that the window.print brings up the printer dialog fine and then you select a printer. The page is actually then printed and is a reference to an rtf document that opens in winword.exe behind the scenes. For some reason in IE 8, the window.close() does not occur. This worked in IE 7. In both cases, WINWORD.EXE process appears to run in the background after the page is printed but in the case of IE 8, control is not give back to that popup page until the WINWORD.EXE process dies which takes a minute or so. I am thinking that becasue control is not being sent back to the page in IE 8, the page is not closed automatically. You can close the page after control is given back after the minute or so. This does happen in IE on both Windows XP and Windows 7. Any ideas if there is a setting in IE 8 or some other reason this may be occuring?

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  • How to fore Word to recompute image numbers?

    - by Vojtech Ruzicka
    I have a word document containing images and tables. These have captions which are numbered, like "Image 1-Example of something". Later on I decided to rearrange some of chapters of my document. However numbering of objects remained the same, so the first image is image 8, the second is image 3, etc. I want to force Word to recompute image numbering so first image in document would be image 1, the second - image 2, etc. Is that possible? Will references (added through cross reference feature) to those objects be updated?

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  • Are all SFP+ tranceivers usable for FEX between Nexus 5000 and Nexus 2000?

    - by Alain O'Dea
    I am looking at building a network with Nexus 5000 parent switches and Nexus 2000 fabric extenders. The mystery at the moment is what kind of SFP+ tranceivers are required for cross-connecting racks. Right now I am considering FET-10G, but I am not sure that 100m is long enough given the separation between racks is potentially very large since it is a rented rack environment. Are all SFP+ tranceivers usable for FEX between Nexus 5000 and Nexus 2000? Specifically, can SFP-10G-SR transceivers be used for longer distance FEX?

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  • What limits scaling in this simple OpenMP program?

    - by Douglas B. Staple
    I'm trying to understand limits to parallelization on a 48-core system (4xAMD Opteron 6348, 2.8 Ghz, 12 cores per CPU). I wrote this tiny OpenMP code to test the speedup in what I thought would be the best possible situation (the task is embarrassingly parallel): // Compile with: gcc scaling.c -std=c99 -fopenmp -O3 #include <stdio.h> #include <stdint.h> int main(){ const uint64_t umin=1; const uint64_t umax=10000000000LL; double sum=0.; #pragma omp parallel for reduction(+:sum) for(uint64_t u=umin; u<umax; u++) sum+=1./u/u; printf("%e\n", sum); } I was surprised to find that the scaling is highly nonlinear. It takes about 2.9s for the code to run with 48 threads, 3.1s with 36 threads, 3.7s with 24 threads, 4.9s with 12 threads, and 57s for the code to run with 1 thread. Unfortunately I have to say that there is one process running on the computer using 100% of one core, so that might be affecting it. It's not my process, so I can't end it to test the difference, but somehow I doubt that's making the difference between a 19~20x speedup and the ideal 48x speedup. To make sure it wasn't an OpenMP issue, I ran two copies of the program at the same time with 24 threads each (one with umin=1, umax=5000000000, and the other with umin=5000000000, umax=10000000000). In that case both copies of the program finish after 2.9s, so it's exactly the same as running 48 threads with a single instance of the program. What's preventing linear scaling with this simple program?

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  • Is there a way to control how pytest-xdist runs tests in parallel?

    - by superselector
    I have the following directory layout: runner.py lib/ tests/ testsuite1/ testsuite1.py testsuite2/ testsuite2.py testsuite3/ testsuite3.py testsuite4/ testsuite4.py The format of testsuite*.py modules is as follows: import pytest class testsomething: def setup_class(self): ''' do some setup ''' # Do some setup stuff here def teardown_class(self): '''' do some teardown''' # Do some teardown stuff here def test1(self): # Do some test1 related stuff def test2(self): # Do some test2 related stuff .... .... .... def test40(self): # Do some test40 related stuff if __name__=='__main()__' pytest.main(args=[os.path.abspath(__file__)]) The problem I have is that I would like to execute the 'testsuites' in parallel i.e. I want testsuite1, testsuite2, testsuite3 and testsuite4 to start execution in parallel but individual tests within the testsuites need to be executed serially. When I use the 'xdist' plugin from py.test and kick off the tests using 'py.test -n 4', py.test is gathering all the tests and randomly load balancing the tests among 4 workers. This leads to the 'setup_class' method to be executed every time of each test within a 'testsuitex.py' module (which defeats my purpose. I want setup_class to be executed only once per class and tests executed serially there after). Essentially what I want the execution to look like is: worker1: executes all tests in testsuite1.py serially worker2: executes all tests in testsuite2.py serially worker3: executes all tests in testsuite3.py serially worker4: executes all tests in testsuite4.py serially while worker1, worker2, worker3 and worker4 are all executed in parallel. Is there a way to achieve this in 'pytest-xidst' framework? The only option that I can think of is to kick off different processes to execute each test suite individually within runner.py: def test_execute_func(testsuite_path): subprocess.process('py.test %s' % testsuite_path) if __name__=='__main__': #Gather all the testsuite names for each testsuite: multiprocessing.Process(test_execute_func,(testsuite_path,))

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  • How to specify a different ip address in virtual box guest os

    - by Nrew
    I am using Windows 7 as the host. And xp as guest. I've already check out this site: http://forums.virtualbox.org/viewtopic.php?f=3&t=17232 But the info is not complete. What do I need to set here, so that the guest would have another IP Address but can still connect to the internet. Because what I'm trying to accomplish here is to be able to try Team Viewer or Cross loop. With the host os and guest os. Because I only have one computer.

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  • Obsessive behaviors in sysadmins

    - by squillman
    I have been told by colleagues (mainly non-technical) that some of my admin behaviors border on / cross the line between normal and obsessive, which sometimes leads me to wonder how screwed up I really am (read "how screwed up everyone else really is"). What are your obsessive behaviors when it comes to your sysadmin tasks and job functions? What do you do religiously that would make you twitch if you didn't do it or that others just roll their eyes at? I have reasons for my actions. I want to prove to my coworkers that I'm not alone.

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  • Piping EOF problems with stdio and C++/Python

    - by yeus
    I got some problems with EOF and stdio. I have no idea what I am doing wrong. When I see an EOF in my program I clear the stdin and next round I try to read in a new line. The problem is: for some reason the getline function immediatly (from the second run always, the first works just as intended) returns an EOF instead of waiting for a new input from py python process... Any idea? alright Here is the code: #include <string> #include <iostream> #include <iomanip> #include <limits> using namespace std; int main(int argc, char **argv) { for (;;) { string buf; if (getline(cin,buf)) { if (buf=="q") break; /*****///do some stuff with input //my actual filter program cout<<buf; /*****/ } else { if ((cin.rdstate() & istream::eofbit)!=0)cout<<"eofbit"<<endl; if ((cin.rdstate() & istream::failbit)!=0)cout<<"failbit"<<endl; if ((cin.rdstate() & istream::badbit)!=0)cout<<"badbit"<<endl; if ((cin.rdstate() & istream::goodbit)!=0)cout<<"goodbit"<<endl; cin.clear(); cin.ignore(numeric_limits<streamsize>::max()); //break;//I am not using break, because I //want more input when the parent //process puts data into stdin; } } return 0; } and in python: from subprocess import Popen, PIPE import os from time import sleep proc=Popen(os.getcwd()+"/Pipingtest",stdout=PIPE,stdin=PIPE,stderr=PIPE); while(1): sleep(0.5) print proc.communicate("1 1 1") print "running"

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