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  • Connection Pool Strategy: Good, Bad or Ugly?

    - by Drew
    I'm in charge of developing and maintaining a group of Web Applications that are centered around similar data. The architecture I decided on at the time was that each application would have their own database and web-root application. Each application maintains a connection pool to its own database and a central database for shared data (logins, etc.) A co-worker has been positing that this strategy will not scale because having so many different connection pools will not be scalable and that we should refactor the database so that all of the different applications use a single central database and that any modifications that may be unique to a system will need to be reflected from that one database and then use a single pool powered by Tomcat. He has posited that there is a lot of "meta data" that goes back and forth across the network to maintain a connection pool. My understanding is that with proper tuning to use only as many connections as necessary across the different pools (low volume apps getting less connections, high volume apps getting more, etc.) that the number of pools doesn't matter compared to the number of connections or more formally that the difference in overhead required to maintain 3 pools of 10 connections is negligible compared to 1 pool of 30 connections. The reasoning behind initially breaking the systems into a one-app-one-database design was that there are likely going to be differences between the apps and that each system could make modifications on the schema as needed. Similarly, it eliminated the possibility of system data bleeding through to other apps. Unfortunately there is not strong leadership in the company to make a hard decision. Although my co-worker is backing up his worries only with vagueness, I want to make sure I understand the ramifications of multiple small databases/connections versus one large database/connection pool.

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  • how to escape a string before insert or update in Ruby

    - by ywenbo
    Hi guy, In ruby ActiveRecord doesn't provide dynamic binding for update and insert sqls, of course i can use raw sql, but that need maintain connection, so i want to know if there is simpler way to escape update or insert sql before executing like code below: ActiveRecord::Base.connection.insert(sql) i think i can write code by gsub, but i know if there has been a ready method to do it. thank you very much, and Merry Christmas for you all.

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  • Get the count of A -> B and B->A without duplicates

    - by TomGasson
    I have a table like so: index|from | to ------------------ 1 | ABC | DEF 2 | ABC | GHI 3 | ABC | GHI 4 | ABC | JKL 5 | ABC | JKL 6 | ABC | JKL 7 | DEF | ABC 8 | DEF | GHI 9 | DEF | JKL 10 | GHI | ABC 11 | GHI | ABC 12 | GHI | ABC 13 | JKL | DEF And I need to count how the total times between the points (regardless of direction) to get the result: A | B | count ----------------- ABC | DEF | 2 ABC | GHI | 5 ABC | JKL | 3 DEF | GHI | 1 DEF | JKL | 2 So far I can get: SELECT `a`.`from` as `A`, `a`.`to` as `B`, (`a`.`count` + `b`.`count`) as `count` FROM (SELECT `from`, `to`, count(*) as `count` FROM `table` GROUP BY 1,2) `a` LEFT OUTER JOIN (SELECT `from`,`to`, count(*) as `count` FROM `table` GROUP BY 1,2) `b` ON `a`.`from` = `b`.`to` AND `a`.`to` = `b`.`from` But I'm unsure how to remove the A/B swapped duplicates.

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  • getting sql records

    - by droidus
    when i run this code, it returns the topic fine... $query = mysql_query("SELECT topic FROM question WHERE id = '$id'"); if(mysql_num_rows($query) > 0) { $row = mysql_fetch_array($query) or die(mysql_error()); $topic = $row['topic']; } but when I change it to this, it doesn't run at all. why is this happening? $query = mysql_query("SELECT topic, lock FROM question WHERE id = '$id'"); if(mysql_num_rows($query) > 0) { $row = mysql_fetch_array($query) or die(mysql_error()); $topic = $row['topic']; $lockedThread = $row['lock']; echo "here: " . $lockedThread; }

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  • Mysqli prepared insert statements always returning false

    - by user1754679
    I'm writing prepared statements that are supposed to insert data into a table, on a database that's been pre-selected in the variable $GLOBALS['mysqli']. The connection has been tested, and that's not the problem I'm having. I'm only running into trouble whenever my prepared statement involves INSERT INTO. I know the tablename, and field names are correct, but $stmt is ALWAYS false. What gives? $stmt = $GLOBALS['mysqli']->prepare("INSERT INTO audit_RefreshCount (user, count, lastrefresh) values (?,?,?)"); if ($stmt == TRUE) { $stmt->bindParam('ssi', $_SESSION['username'], '0', time()); //$stmt->bind_Param('ssi', $_SESSION['username'], '0', time()); // Also doesn't work. $stmt->execute(); }

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  • Want to calculate the sum of the count rendered by group by option..

    - by Vijay
    i have a table with the columns such id, tid, companyid, ttype etc.. the id may be same for many companyid but unique within the companyid and tid is always unique and i want to calculate the total no of transactions entered in the table, a single transaction may be inserted in more than one row, for example, id tid companyid ttype 1 1 1 xxx 1 2 1 may be null 2 3 1 yyy 2 4 1 may be null 2 5 1 may be null the above entries should be counted as only 2 transactions .. it may be repeated for many companyids.. so how do i calculate the total no of transactions entered in the table i tried select sum(count(*)) from transaction group by id,companyId; but doesn't work select count(*) from transaction group by id; wont work because the id may be repeated for different companyids.

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  • Database design: objects with different attributes

    - by Álvaro G. Vicario
    I'm designing a product database where products can have very different attributes depending on their type, but attributes are fixed for each type and types are not manageable at all. E.g.: magazine: title, issue_number, pages, copies, close_date, release_date web_site: name, bandwidth, hits, date_from, date_to I want to use InnoDB and enforce database integrity as much as the engine allows. What's the recommended way to handle this? I hate those designs where tables have 100 columns and most of the values are NULL so I thought about something like this: product_type ============ product_type_id INT product_type_name VARCHAR product ======= product_id INT product_name VARCHAR product_type_id INT -> Foreign key to product_type.product_type_id valid_since DATETIME valid_to DATETIME magazine ======== magazine_id INT title VARCHAR product_id INT -> Foreign key to product.product_id issue_number INT pages INT copies INT close_date DATETIME release_date DATETIME web_site ======== web_site_id INT name VARCHAR product_id INT -> Foreign key to product.product_id bandwidth INT hits INT date_from DATETIME date_to DATETIME This can handle cascaded product deletion but... Well, I'm not fully convinced...

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  • How to do left joins with least-n-per-group query?

    - by Nate
    I'm trying to get a somewhat complicated query working and am not having any luck whatsoever. Suppose I have the following tables: cart_items: +--------------------------------------------+ | item_id | cart_id | movie_name | quantity | +--------------------------------------------+ | 0 | 0 | braveheart | 4 | | 1 | 0 | braveheart | 9 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +--------------------------------------------+ movies: +------------------------------+ | movie_id | movie_name | ... | +------------------------------+ | 0 | braveheart | . | | . | . | . | | . | . | . | | . | . | . | | . | . | . | +------------------------------+ pricing: +-----------------------------------------+ | id | movie_name | quantity | price_per | +-----------------------------------------+ | 0 | braveheart | 1 | 1.99 | | 1 | braveheart | 2 | 1.50 | | 2 | braveheart | 4 | 1.25 | | 3 | braveheart | 8 | 1.00 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +-----------------------------------------+ I need to join the data from the tables, but with the added complexity that I need to get appropriate price_per from the pricing table. Only one price should be returned for each cart_item, and that should be the lowest price from the pricing table where the quantity for the cart item is at least the quantity in the pricing table. So, the query should return for each item in cart_items the following: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ Example 1: Variable passed to the query: cart_id = 0. Return: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ | 0 | braveheart | 4 | 1.25 | | 1 | braveheart | 9 | 1.00 | +---------------------------------------------+ Note that this is a minimalist example and that additional data will be pulled from the tables mentioned (particularly the movies table). How could this query be composed? I have tried using left joins and subqueries, but the difficult part is getting the price and nothing I have tried has worked. Thanks for your help. EDIT: I think this is similar to what I have working with my "real" tables: SELECT t1.item_id, t2.movie_name, t1.quantity FROM cart_items t1 LEFT JOIN movies t2 ON t2.movie_name = t1.movie_name WHERE t1.cart_id = 0 Assuming I wrote that correctly (I quickly tried to "port over" my real query), then the output would currently be: +---------------------------------+ | item_id | movie_name | quantity | +---------------------------------+ | 0 | braveheart | 4 | | 1 | braveheart | 9 | +---------------------------------+ The trouble I'm having is joining the price at a certain quantity for a movie. I simply cannot figure out how to do it.

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  • PHP:Wrong Login info does not redirect to the specific page

    - by sdr
    <?php include 'lib/db_conn.php'; $uid=$_REQUEST['uid']; $pass=$_REQUEST['pass']; if(($uid==NULL && $pass==NULL) ||($uid==NULL) ||($pass==NULL)) { header("location:index.php?msg=Fields can't be left blank.."); } $pass=md5($pass); $sql1="SELECT * FROM `tb_user` WHERE `email`='$uid' AND `pass`='$pass'"; $rs1=mysql_query($sql1) or die (mysql_error()); $row1=mysql_fetch_array($rs1) or die (mysql_error()); $email=$row1['email']; if($uid==$email) { session_start(); $_SESSION['id']=$row1['id']; header("location:home.php"); } else { header("location:index.php?msg=Wrong Credentials.."); } ?>

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  • Trying to grab several random videos from database, but it just shows the same one all the time.

    - by Birk
    Hi guys, I'm trying to grab several random videos from my database, and have them show on a page. However, it just keeps on grabbing the same video rather than several different ones. So I end up with 5 of the same video rather than 5 different ones. Here's the grab random PHP code file... and after it is the template output file. //===================================================== // Random | Previous | Next //===================================================== $show['random'] = $db->quick_fetch( "SELECT file_id, title, title_seo, category_id, thumb FROM files WHERE files.category_id = '".$show['main']['category_id']."' AND files.verified=1 ORDER BY RAND() LIMIT 0,1; "); Here's the template CSS html thingy code I have this pasted 5 times to show 5 random videos <td valign="top" width="53%"><? $sql="select * from files ORDER BY rand() limit 0,5"; $res=@mysql_query($sql); $data=@mysql_result($res,0,'filename'); $id=@mysql_result($res,0,'file_id'); $title=@mysql_result($res,0,'title'); $title2=str_replace(" ", "-",$title); $path="{$siteurl}/media/{$file.random.file_id}/{$file.random.title_seo}/"; $img="{$siteurl}/thumbs/{$file.random.thumb}"; echo " {$file.random.title}"

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  • Is it possible for a Grails Domain to have no 'id'?

    - by firnnauriel
    Is it possible to create a table that has no 'id'? For example, this is my domain: class SnbrActVector { int nid String term double weight static mapping = { version false id generator: 'identity' } static constraints = { } } When I run this SQL statement, it fails: insert into snbr_act_vector values (5, 'term', 0.5) I checked the table and 'id' is already set to autoincrement. I'm thinking that another option is to remove the 'id' itself. Or is there another workaround for this? Please assume that it is not an option to change the givent SQL statement.

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  • sql query need a help.

    - by benjamin button
    If i have a table with two fields.customer id and order. let's say i have in total order ID 1,2,3,4 all the customer can have all the four orders.like below 1234 1 1234 2 1234 3 1234 4 3245 3 3245 4 5436 2 5436 4 you can see above that 3245 customer doesnt have order id 1 and 2. how could i print in the query output like 3245 1 3245 2 5436 1 5436 3 EDIT: i dont order table but i have list of order's like we can hard code it in the query(1,2,3,4) i dont have an orders table.

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  • Dreamweaver recordset filter - Display all records as default

    - by Drew
    I am trying to create a simple search form to filter the results in the dynamic table. The search form is on the same pages as the results and posts to itself. I get the search string from the post variable. It is working, but I can't figure out how to set the default value to display all results. Dreamweaver automatically sets the default value to -1, and therefore no results are displayed on the initial load. How do I change this to display ALL records as default and the filter only if there is search string defined.

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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  • How Can I Join Two DB Tables and Return Lowest Price From Joined Table

    - by Jason
    I have two tables, the first table has the product and the second table the prices. The price table could have more than one price per product but I only want to display the lowest. But I keep getting all the prices returned and I'm having trouble figuring out how to do it. this is what I get returned in my query: SELECT * FROM products AS pr JOIN prices AS p ON pr.id = p.product_id WHERE pr.live = 1 AND p.live = 1 id product1 name description £100 id product1 name description £300 id product1 name description £200 id product2 name description £50 id product2 name description £80 id product2 name description £60 id product3 name description £222 id product3 name description £234 id product3 name description £235 but I'm after: id product1 name description £100 id product2 name description £50 id product3 name description £222 Any help would be appreciated

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  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

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  • Activetopics - Get max 5 topics per category

    - by Arjen
    Hey, I want to get the 5 latest active topics within several category's. Each topic has a subcatid and this subcatid relates to a catid. What I want is to get the 5 active topics within each catid. I'm trying to use the query below, but this isn't working at all: set @num := 0, @catid := 0; SELECT forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten, MAX(forum_cats.id) AS catid, MAX(forum_cats.titel) AS cattitel, MAX(forum_subcats.id) AS subcatid, MAX(forum_posts.id) AS maxid, DATE_FORMAT(MAX(forum_posts.datum), '%d-%m-%Y om %H:%i uur') AS datum, UNIX_TIMESTAMP(MAX(forum_posts.datum)) AS laatstereactieunix, (COUNT(forum_posts.id) - 1) AS reactieaantal, @num := IF(@catid = MAX(forum_cats.id), @num + 1, 1) AS row_number, @catid := MAX(forum_cats.id) AS dummy FROM forum_posts INNER JOIN forum_topics ON forum_topics.id = forum_posts.topicid INNER JOIN forum_subcats ON forum_subcats.id = forum_topics.subcat INNER JOIN forum_cats ON forum_cats.id = forum_subcats.cat WHERE forum_cats.id IN (1) AND forum_topics.gesloten != '1' GROUP BY forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten HAVING row_number <= 5 ORDER BY forum_cats.id ASC, MAX(forum_posts.datum) DESC When executing this code I get always the same number (1) for row_number, so this is not the result I want. Does anyone know how I can get this work? Thanks!

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  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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