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  • How to maintain precision using DateTime.Now.Ticks in C#

    - by nmr
    I know that when I use DateTime.Now.Ticks in C# it returns a long value but I need to store it in an int variable and I am confused as to whether or not I can maintain that precision. As of right now I just have a cast int timeStampValue = (int)DateTime.Now.Ticks; Any suggestions or advice on how to maintain the precision, if possible, would be much appreciated.

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  • Shell loops using non-integers?

    - by mary
    I wrote a .sh file to compile and run a few programs for a homework assignment. I have a "for" loop in the script, but it won't work unless I use only integers: #!/bin/bash for (( i=10; i<=100000; i+=100)) do ./hw3_2_2 $i done The variable $i is an input for the program hw3_2_2, and I have non-integer values I'd like to use. How could I loop through running the code with a list of decimal numbers?

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  • jquerry in rails

    - by Matthias Günther
    I'm iteration over records and want to create the toggle-options for records but I can't replace the div-id with the records: <% for bill in @bills % <% tmp = "test"% <%= link_to '&raquo now','#', :onclick = '$("#{tmp}").toggle();' % Instead of getting: &raquo now I'm getting: &raquo now So he isn't evaluation the ruby variable in the string. How can I do this? Thanks for your help and I'm new in jquerry.

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  • PHP PDO - Num Rows

    - by Ian
    PDO apparently has no means to count the number of rows returned from a select query (mysqli has the num_rows variable). Is there a way to do this, short of using count($results->fetchAll()) ?

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  • Block copy PDF document

    - by Wiliam Witter
    hello Gentlemen, I would like block copy (ctrl+c ctrl+v) PDF document using java. I have a code that build a PDF document with JasperReport... //seta o caminho dos arquivos jasper String pathLote = ScopeSupport.getServletContext().getRealPath("priv/sgc/relatorios/AtaPregaoLotePageReport.jasper"); String pathCabecalho = ScopeSupport.getServletContext().getRealPath("priv/sgc/relatorios/CabecalhoPageReport.jasper"); String pathRodape = ScopeSupport.getServletContext().getRealPath("priv/sgc/relatorios/rodapePageReport.jasper"); String imagemDir = ScopeSupport.getServletContext().getRealPath("/priv/comum/img"); //HashMap parametros passa o parametro usado na query e o caminho da imagem HashMap<String,Object> parametros = new HashMap<String,Object>(); parametros.put("idPregao", idPregao); parametros.put("idLote", idLote); parametros.put("IMAGEM_DIR", imagemDir + "/"); parametros.put("USUARIO", "NomeUsuario" ); parametros.put("texto", texto); parametros.put("numeroAta", numAta); if(numAta != null && numAta > 0) parametros.put("relatorio", "Ata "+numAta); HashMap<String,Object> parametrosSub = new HashMap<String,Object>(); parametrosSub.put("CabecalhoPageReport", pathCabecalho); parametrosSub.put("rodapePageReport", pathRodape); parametrosSub.put("AtaPregaoPorLotePageReport", pathLote); for(String element : parametrosSub.keySet()){ parametros.put(element, (JasperReport) JRLoader.loadObject((String) (parametrosSub.get(element)))); } JasperReport report = (JasperReport) JRLoader.loadObject( pathLote ); JasperPrint printRel = JasperFillManager.fillReport( report, parametros, getJDBCConnection() ); byte[] bytes = JasperExportManager.exportReportToPdf(printRel); httpResponse.setHeader("Content-Disposition","attachment; filename=\""+ report.getName() + ".pdf" +"\";"); httpResponse.setContentLength(bytes.length); httpResponse.setContentType("application/pdf"); ServletOutputStream ouputStream = httpResponse.getOutputStream(); ouputStream.write(bytes, 0, bytes.length); ouputStream.flush(); ouputStream.close(); Who can help me with this?

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  • Adding a link to image breaks jquery slider, help please!

    - by lewisqic
    Hi All, I am working on a site for a friend and trying to add a link to each image in a slide show. The slide show uses jquery and a script called easySlider1.7.js. Everything works just fine if the images are left alone, but when I try and wrap the images with a link, the slides no longer progress as they should. Here is the live website that is displaying the problem... http://www.splits59.com/ Here is the html code for each of the slide images... <div class="covercontent2box"> <div class="covercontent2"> <div id="slideshow"> <a href="/ashton-jacket-p-107.html"><img src="img/homepagesummer2010_2.2-cut.jpg" class="active" /></a> <a href="/carly-coverup-p-106.html"><img src="img/homepagesummer2010_3.2-cut.jpg" /></a> <a href="/shop-online-bottoms-c-15_14.html"><img src="img/homepagesummer2010_1.2-cut.jpg" /></a> </div> </div> </div> And here is the jquery code on the page that controls the slider... <script type="text/javascript"> function slideSwitch() { var $active = $('#slideshow IMG.active'); if ( $active.length == 0 ) $active = $('#slideshow IMG:last'); // use this to pull the images in the order they appear in the markup var $next = $active.next().length ? $active.next() : $('#slideshow IMG:first'); $active.addClass('last-active'); $next.css({opacity: 0.0}) .addClass('active') .animate({opacity: 1.0}, 1000, function() { $active.removeClass('active last-active'); }); } $(function() { setInterval( "slideSwitch()", 4500 ); }); </script> Does anyone have any idea why adding a link tag to the images breaks the slider? Any help or direction provided would be appreciated. Thanks, Devin

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  • Microsoft Word Document Controls not accepting carriage returns

    - by Scott
    So, I have a Microsoft Word 2007 Document with several Plain Text Format (I have tried Rich Text Format as well) controls which accept input via XML. For carriage returns, I had the string being passed through XML containing "\r\n" when I wanted a carriage return, but the word document ignored that and just kept wrapping things on the same line. I also tried replacing the \r\n with System.Environment.NewLine in my C# mapper, but that just put in \r\n anyway, which still didn't work. Note also that on the control itself I have set it to "Allow Carriage Returns (Multiple Paragrpahs)" in the control properties. This is the XML for the listMapper <Field id="32" name="32" fieldType="SimpleText"> <DataSelector path="/Data/DB/DebtProduct"> <InputField fieldType="" path="/Data/DB/Client/strClientFirm" link="" type=""/> <InputField fieldType="" path="strClientRefDebt" link="" type=""/> </DataSelector> <DataMapper formatString="{0} Account Number: {1}" name="SimpleListMapper" type=""> <MapperData> </MapperData> </DataMapper> </Field> Note that this is the listMapper C# where I actually map the list (notice where I try and append the system.environment.newline) namespace DocEngine.Core.DataMappers { public class CSimpleListMapper:CBaseDataMapper { public override void Fill(DocEngine.Core.Interfaces.Document.IControl control, CDataSelector dataSelector) { if (control != null && dataSelector != null) { ISimpleTextControl textControl = (ISimpleTextControl)control; IContent content = textControl.CreateContent(); CInputFieldCollection fileds = dataSelector.Read(Context); StringBuilder builder = new StringBuilder(); if (fileds != null) { foreach (List<string> lst in fileds) { if (CanMap(lst) == false) continue; if (builder.Length > 0 && lst[0].Length > 0) builder.Append(Environment.NewLine); if (string.IsNullOrEmpty(FormatString)) builder.Append(lst[0]); else builder.Append(string.Format(FormatString, lst.ToArray())); } content.Value = builder.ToString(); textControl.Content = content; applyRules(control, null); } } } } } Does anybody have any clue at all how I can get MS Word 2007 (docx) to quit ignoring my newline characters??

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  • How to add string to jQuery selector?

    - by Deshiknaves
    I'm trying to select an id that changes on different posts of same page. So the they have been given an id="show_posts_{PostID}" - on the final output the {PostID} is replaced with a number. In the function I need to call $('show_posts_XXXXXX') - XXXXXX being the generated ID. I have stored this ID in a variable called postId. But I can't seem to do this $("'" + "show_posts_" + postId + "'") Can anyone tell me how I can add a string to the end of a selector?

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  • what's the DRY version of the following Makefile targets?

    - by carneades
    I don't know how to execute a command stored as a variable or how to use ifeq inside of a target, so I have a very redundant Makefile at the moment! Ideally I'd like to have just one target (all) which would run the stored command on Mac and run it twice on Linux, once with -m32 and once with -m64. all: echo PLEASE SELECT OS, e.g. make linux exit 1 mac: gcc $(SHARED_OPT) $(GENERAL_CFLAGS) $(PLATFORM_CFLAGS) -o $(BUILD_DIR)$(BUILD_NAME) $(SOURCE) $(LIBRARIES) linux: gcc $(SHARED_OPT) $(GENERAL_CFLAGS) $(PLATFORM_CFLAGS) -o $(BUILD_DIR)$(BUILD_NAME64) $(SOURCE) $(LIBRARIES64) -m64 gcc $(SHARED_OPT) $(GENERAL_CFLAGS) $(PLATFORM_CFLAGS) -o $(BUILD_DIR)$(BUILD_NAME) $(SOURCE) $(LIBRARIES) -m32

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  • How do I get rid of LD_LIBRARY_PATH at run-time?

    - by Kjir
    I am building a C++ application that uses Intel's IPP library. This library is installed by default in /opt and requires you to set LD_LIBRARY_PATH both for compiling and for running your software (if you choose the shared library linking, which I did). I already modified my configure.ac/Makefile.am so that I do not need to set that variable when compiling, but I still can't find the shared library at run-time; how do I do that? I'm compiling with the -Wl, -R/path/to/lib flag using g++

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  • cx_Oracle and output variables

    - by Tim
    I'm trying to do this again an Oracle 10 database: cursor = connection.cursor() lOutput = cursor.var(cx_Oracle.STRING) cursor.execute(""" BEGIN %(out)s := 'N'; END;""", {'out' : lOutput}) print lOutput.value but I'm getting DatabaseError: ORA-01036: illegal variable name/number Is it possible to define PL/SQL blocks in cx_Oracle this way?

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  • php/ldap - bind fails but errorno doesn't execute

    - by user240907
    I am trying to connect to ldap with a php web application. If the username/password is correct everything works fine however if the username/password is incorrect I get the following error: PHP Warning: ldap_bind() [function.ldap-bind]: Unable to bind to server: Invalid credentials for some reason I am not able to look at the errorno or the state of the bind variable afterwards to print the appopriate user friendly error message. any ideas?

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  • use pin.title in other class

    - by Marco
    Hello i have implemented the following code: - (void) mapView:(MKMapView *)mapView annotationView:(MKAnnotationView *)annView calloutAccessoryControlTapped:(UIControl *)control { name = annView.annotation.title; NSLog(name, [annView description]); } and how can I use the variable name in another class? can you please help me, i am new in iphone developing!

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  • What is the meaning of method class in the class definition in Ruby?

    - by Steven Xu
    I'm familiar with function definitions and variable declarations being in class definitions: public class MyClass { public int myvar; public void doSomething() { } } But what does it "mean" in Ruby when a method is actually called in the class definition? This happens amply in Rails, for instance: class User < ActiveRecord::Base has_many :posts end What exactly does this do (at a lower level than "it adds some methods to the class")? How would I implement such a function (e.g., one that mixes in some additional methods)?

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  • infix operation to postfix using stacks

    - by Chris De La O
    We are writing a program that needs to convert an infix operation (4 5/3) to postfix (4 5 3 / ) using stacks. however my convert to postfix does not work as it doesnt not output the postFix array that is supposed to store the conversion from infix notation to postfix notation. here is the code for the convertToPostix fuction. //converts infix expression to postfix expression void ArithmeticExpression::convertToPostfix(char *const inFix, char *const postFix) { //create a stack2 object named cow Stack2<char> cow; cout<<postFix; char thing = '('; //push a left parenthesis onto the stack cow.push(thing); //append a right parenthesis to the end of inFix array strcat(inFix, ")"); int i = 0;//declare an int that will control posFix position //if the stack is not empty if (!cow.isEmpty()) { //loop to run until the last character in inFix array for (int x = 0; inFix[x]!= '\0'; x++ ) { //if the inFix element is a digit if (isdigit(inFix[x])) { postFix[i]=inFix[x];//it is assigned to the next element in postFix array i++;//move on to next element in postFix } //if the inFix element is a left parenthesis else if (inFix[x]=='(') { cow.push(inFix[x]);//push it unto the stack } //if the inFix element is an operator else if (isOperator(inFix[x])) { char oper2 = inFix[x];//char variable holds inFix operator if (isOperator(cow.stackTop()))//if the top node in the stack is an operator { while (isOperator(cow.stackTop()))//and while the top node in the stack is an operator { char oper1 = cow.stackTop();//char variable holds node operator if(precedence( oper1, oper2))//if the node operator has higher presedence than node operator { postFix[i] = cow.pop();//we pop such operator and insert it in postFix array's next element cow.push(inFix[x]);//and push inFix operator unto the stack i++;//move to the next element in posFix } } } //if the top node is not an operator //we push the current inFix operator unto the top of the stack else cow.push(inFix[x]); } //if the inFix element is a right parenthesis else if (inFix[x]==')') { //we pop everything in the stack and insert it in postFix //until we arrive at a left paranthesis while (cow.stackTop()!='(') { postFix[i] = cow.pop(); i++; } //we then pop and discard left parenthesis cow.pop(); } } postFix[i]='\0'; //print !!postFix array!! (not stack) print();//code for this is just cout<<postFix; }

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  • SSIS - 'Execute SQL' Task and Record Sets

    - by Mick Walker
    Hi, How can I access a 'RecordSet' within a 'Execute SQL' task when using SSIS? I have looked at the parameter mapping options within the Execute SQL Task Editor and cannot find a type of object to allow me to pass the variable holding my record set to the task.

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