Search Results

Search found 21548 results on 862 pages for 'url mapping'.

Page 367/862 | < Previous Page | 363 364 365 366 367 368 369 370 371 372 373 374  | Next Page >

• Rails: link_to with block and GET params?

  - by bobthabuilda

  How can I achieve query string and URL parameters in a link_to block declaration? Right now, I have this, which works: <%= link_to 'Edit', :edit, :type => 'book', :id => book %> The above works, and outputs: http://localhost:3000/books/edit/1?type=book What I want to do is something like this: <% link_to :edit, :type => 'book', :id => book do %> ... <% end %> But the above format outputs: http://localhost:3000/books/edit/ Which isn't what I'm looking for... I want it to output a URL like the previous example. How can I achieve this?

  Read the article

• Get unicode character with curl in PHP

  - by saturngod

  I tried to get URL with curl. Return value contain unicode character. curl convert to \u for unicode character. How to get unicode character with curl ? This is my code <?php $ch = curl_init(); // set URL and other appropriate options curl_setopt($ch, CURLOPT_URL, "http://www.ornagai.com/index.php/api/word/q/test/format/json"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $return=curl_exec($ch); echo $return; ?>

  Read the article

• Inspect in memory hsqldb while debugging

  - by Albert

  We're using hdsqldb in memory to run junit tests which operate against a database. The db is setup before running each test via a spring configuration. All works fine. Now when a tests fails it can be convinient to be able to inspect the values in the in memory database. Is this possible? If so how? Our url is: jdbc.url=jdbc:hsqldb:mem:testdb;sql.enforce_strict_size=true The database is destroyed after each tests. But when the debugger is running the database should also still be alive. I've tried connecting with the sqldb databaseManager. That works, but I don't see any tables or data. Any help is highly appreciated!

  Read the article

• How can I make these images download on a seperate thread?

  - by Andy Barlow

  Hello!! I have the following code running on my Android device. It works great and displays my list items wonderfully. It's also clever in the fact it only downloads the data when it's needed by the ArrayAdapter. However, whilst the download of the thumbnail is occurring, the entire list stalls and you cannot scroll until it's finished downloading. Is there any way of threading this so it'll still scroll happily, maybe show a place holder for the downloading image, finish the download, and then show? Any help with this would be really apreciated. Thank-you kindly. Andy Barlow private class CatalogAdapter extends ArrayAdapter { private ArrayList<SingleQueueResult> items; //Must research what this actually does! public CatalogAdapter(Context context, int textViewResourceId, ArrayList<SingleQueueResult> items) { super(context, textViewResourceId, items); this.items = items; } /** This overrides the getview of the ArrayAdapter. It should send back our new custom rows for the list */ @Override public View getView(int position, View convertView, ViewGroup parent) { View v = convertView; if (v == null) { LayoutInflater vi = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE); v = vi.inflate(R.layout.mylists_rows, null); } final SingleQueueResult result = items.get(position); // Sets the text inside the rows as they are scrolled by! if (result != null) { TextView title = (TextView)v.findViewById(R.id.mylist_title); TextView format = (TextView)v.findViewById(R.id.mylist_format); title.setText(result.getTitle()); format.setText(result.getThumbnail()); // Download Images ImageView myImageView = (ImageView)v.findViewById(R.id.mylist_thumbnail); downloadImage(result.getThumbnail(), myImageView); } return v; } } // This should run in a seperate thread public void downloadImage(String imageUrl, ImageView myImageView) { try { url = new URL(imageUrl); URLConnection conn = url.openConnection(); conn.connect(); InputStream is = conn.getInputStream(); BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm = BitmapFactory.decodeStream(bis); bis.close(); is.close(); myImageView.setImageBitmap(bm); } catch (IOException e) { /* Reset to Default image on any error. */ //this.myImageView.setImageDrawable(getResources().getDrawable(R.drawable.default)); } }

  Read the article

• Asynchronous Silverlight 4 call to the World of Warcraft armoury streaming XML in C#

  - by user348446

  Hello - I have been stuck on this all weekend and failed miserably! Please help me to claw back my sanity!! Your challenge For my first Silverlight application I thought it would be fun to use the World of Warcraft armoury to list the characters in my guild. This involves making an asyncronous from Silverlight (duh!) to the WoW armoury which is XML based. SIMPLE EH? Take a look at this link and open the source. You'll see what I mean: http://eu.wowarmory.com/guild-info.xml?r=Eonar&n=Gifted and Talented Below is code for getting the XML (the call to ShowGuildies will cope with the returned XML - I have tested this locally and I know it works). I have not managed to get the expected returned XML at all. Notes: If the browser is capable of transforming the XML it will do so, otherwise HTML will be provided. I think it examines the UserAgent I am a seasoned asp.net web developer C# so go easy if you start talking about native to Windows Forms / WPF I can't seem to set the UserAgent setting in .net 4.0 - doesn't seem to be a property off the HttpWebRequest object for some reason - i think it used to be available. Silverlight 4.0 (created as 3.0 originally before I updated my installation of Silverlight to 4.0) Created using C# 4.0 Please explain as if you talking to a web developer and not a proper programming lol! Below is the code - it should return the XML from the wow armoury. private void button7_Click(object sender, RoutedEventArgs e) { // URL for armoury lookup string url = @"http://eu.wowarmory.com/guild-info.xml?r=Eonar&n=Gifted and Talented"; // Create the web request HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create(url); // Set the user agent so we are returned XML and not HTML //httpWebRequest.Headers["User-Agent"] = "Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.0)"; // Not sure about this dispatcher thing - it's late so i have started to guess. Dispatcher.BeginInvoke(delegate() { // Call asyncronously IAsyncResult asyncResult = httpWebRequest.BeginGetResponse(ReqCallback, httpWebRequest); // End the response and use the result using (HttpWebResponse httpWebResponse = (HttpWebResponse)httpWebRequest.EndGetResponse(asyncResult)) { // Load an XML document from a stream XDocument x = XDocument.Load(httpWebResponse.GetResponseStream()); // Basic function that will use LINQ to XML to get the list of characters. ShowGuildies(x); } }); } private void ReqCallback(IAsyncResult asynchronousResult) { // Not sure what to do here - maybe update the interface? } Really hope someone out there can help me! Thanks mucho! Dan. PS Yes, I have noticed the irony in the name of the guild :)

  Read the article

• Why can't I get Python's urlopen() method to work?

  - by froadie

  Why isn't this simple Python code working? import urllib file = urllib.urlopen('http://www.google.com') print file.read() This is the error that I get: Traceback (most recent call last): File "C:\workspace\GarchUpdate\src\Practice.py", line 26, in <module> file = urllib.urlopen('http://www.google.com') File "C:\Python26\lib\urllib.py", line 87, in urlopen return opener.open(url) File "C:\Python26\lib\urllib.py", line 206, in open return getattr(self, name)(url) File "C:\Python26\lib\urllib.py", line 345, in open_http h.endheaders() File "C:\Python26\lib\httplib.py", line 892, in endheaders self._send_output() File "C:\Python26\lib\httplib.py", line 764, in _send_output self.send(msg) File "C:\Python26\lib\httplib.py", line 723, in send self.connect() File "C:\Python26\lib\httplib.py", line 704, in connect self.timeout) File "C:\Python26\lib\socket.py", line 514, in create_connection raise error, msg IOError: [Errno socket error] [Errno 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond I've tried it with several different pages but I can never get the urlopen method to execute correctly.

  Read the article

• Regexp to extract sources from different video embeds

  - by Ben

  My SMF forum contains posts with video and I want to extract them to show on the Wordpress main page. My current regexp (thanks to SO!) extracts the url of the videos, which I embed using AutoEmbed. Everything works up until a post looks like this: <embed height="600" width="600" allowscriptaccess="never" quality="high" loop="true" play="true" src="http://mmavlog.net/embed/player.swf?file=http://video.ufc.tv/CSG/UFC113/20100507_ufc113_weigh_in_400k.flv" type="application/x-shockwave-flash"> Here is my current regexp: $regexp = "/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i"; Since the posts can contain <embed> or <object> I realize that looking for the url by the "http" might be inaccurate. How can I use the regexp to look for "src=" for <embed> and "data=" for <object>?

  Read the article

• Dynamically add new HTML elements on page load after getting JSON data from Web API

  - by Luis D Urraca

  I'm building an hybrid Android App using Phonegap/Apache Cordova. My app should get data from my web api. I'm using JSON to serve the data to the APP. So i got a the following code: function init() { document.addEventListener('deviceready', onDeviceReady, false); var url = "http://23.21.128.153:3000/regions.json";var jsonresults; $.getJSON(url,function(data){ jsonresults = data; $.each(jsonresults, function(i,v){ $('#main-content').append('<li>'+jsonresults[i].name+'</li>'); }); }); } and also on the body of the html i have a div called main-content. Everythings works fine in the Eclipse browser, but on the Android Emulator is not working. Not sure if there's another way to pull data from Web API using JSON and dinamically create HMTL elements after getting the data. https://gist.github.com/2956660

  Read the article

• Handling Character Encoding in URI on Tomcat

  - by ZZ Coder

  On the web site I am trying to help with, user can type in an URL in the browser, like following Chinese characters, http://localhost:8080?a=?? On server, we get GET /a=%E6%B5%8B%E8%AF%95 HTTP/1.1 As you can see, it's UTF-8 encoded, then URL encoded. We can handle this correctly by setting encoding to UTF-8 in Tomcat. However, sometimes we get Latin1 encoding on certain browsers, http://localhost:8080?a=ß turns into GET /a=%DF HTTP/1.1 Is there anyway to handle this correctly in Tomcat? Looks like the server has to do some intelligent guessing. We don't expect to handle the Latin1 correctly 100% but anything is better than what we are doing now by assuming everything is UTF-8. The server is Tomcat 5.5. The supported browsers are IE 6+, Firefox 2+ and Safari on iPhone.

  Read the article

• Ajax And REST: Can I send an ajax request to a REST service and recieve response?

  - by Morteza M.

  Hi everybody here, I want to use mootools and SqueezBox class to handle a request to a RESTful service. I don't want to use any server-side script. I am using AJAX. I send a request to the following url using GET method. http://www.idevcenter.com/api/v1/links/links-upcoming.json but I receive a 404 error. Is it because cross-site scripting? here is my code: SqueezeBox.initialize({handler:'url',ajaxOptions:{method:'GET'}}); $('a.modal').addEvent('click',function(e){ new Event(e).stop(); SqueezeBox.fromElement($('a.modal')); }); In Firebug console, sometimes 'aborted' is shown and sometimes '404'.what is wrong with that?

  Read the article

• Needs some help with an apache mod-rewrite issue

  - by mike

  I've modified my .htaccess file to have the following statement RewriteCond $1 !^index.php$ RewriteRule ^/?([^/]+)$ index.php?c=home&m=details&seo=$1 [L,NS] This allows me to use product URL's like this: http://domain.com/product_name However, when trying to access a file at the same level as index.php, it always calls the RewriteRule above and errors out. I need to be able to access files like below, but each URL currently attempts to load index.php. http://domain.com/about.htm http://domain.com/terms.htm http://domain.com/robots.txt etc Any suggestions on how I can modify my htaccess file to get this to work correctly?

  Read the article

• Tomcat blankpage for default error page

  - by praspa

  First off, I'm using Tomcat 5.5 and my .jsp's live in /webapps/foo/bar/*.jsp. I followed the directions here to set up a default 404 error page. In my TOMCAT_HOME/conf/web.xml I entered: <error-page> <error-code>404</error-code> <location>/error.html</location> </error-page> I dropped copies of a test error.html file into each of the dirs (I wasn't sure where /error.html was referring to): /webapps/ /webapps/foo/ /webapps/foo/bar/ Whenever I attempt to access a non-existent page in a browser at url's /foo/missingpage.html or /foo/bar/missingpage.html I'm redirected to my error page that exists in /foo/error.html. However, attempting to access a non-existent page in a browser at url /missingpage.html yields a blankpage. Or any permutation of /missingDir/missingfile.html will also yield a blank page. Any suggestions? Am I missing some extra configuration? Thanks PR

  Read the article

• asp.net mvc json open dialog box problem

  - by mazhar kaunain baig

  function postForm() { $.ajax({ type: "POST", data: $("#myForm").serialize(), dataType: "json", url: '<%= Url.Action("JSONRequest","Home") %>', success: function(result) { window.alert(result.name); }, error : function() { window.alert('error'); } }); } Html.BeginForm("JSONRequest", "Home", FormMethod.Post, new { id = "myForm" }); Html.TextBox("mazhar") <input type="submit" onclick="postForm" /> Html.EndForm(); public ActionResult JSONRequest(FormCollection form) { string a = form["mazhar"]; var data = new { name = "aaaa", Success = "Record is Succesfully Saved", ErrorMessages = "abc" }; return Json(data); } Ok the problem is that the dialog box is opening after running this code which is asking to save file. Can someone tell me how to resolve this issue?

  Read the article

• Java - getClassLoader().getResource() driving me bonkers

  - by Click Upvote

  I have this test app: import java.applet.*; import java.awt.*; import java.net.URL; public class Test extends Applet { public void init() { URL some=Test.class.getClass().getClassLoader().getResource("/assets/pacman.png"); System.out.println(some.toString()); System.out.println(some.getFile()); System.out.println(some.getPath()); } } When I run it from Eclipse, I get the error: java.lang.NullPointerException at Test.init(Test.java:9) at sun.applet.AppletPanel.run(Unknown Source) at java.lang.Thread.run(Unknown Source) Classpath (from .CLASSPATH file) <classpathentry kind="src" path="src"/> In my c:\project\src folder, I have only the Test.java file and the 'assets' directory which contains pacman.png. What am I doing wrong and how to resolve it?

  Read the article

• ReturnUrl = Default.aspx for MVC?

  - by Cynthia

  I'm trying to secure my entire MVC site, so before the Home controller, I added an [Authorize] attribute. Now if you run it from Visual Studio or navigate using the root URL (e.g. http://localhost:2897) it does redirect to the login page, as expected. However the URL in the address bar after redirection looks like this: http://localhost:2897/Account/LogOn?ReturnUrl=%2fdefault.aspx%3f I haven't tested this out, seeing as I have not implemented my authentication code. However, this looks like a big problem to me, since I do not have a default.aspx in my project! My authentication tag in the web.config looks like this: <authentication mode="Forms"> <forms loginUrl="~/Account/LogOn" defaultUrl="~/Home/Index" timeout="2880"/> </authentication> Why doesn't it pick up this route as the default ReturnUrl instead of default.aspx?

  Read the article

• safely encode and pass a string from a html link to PHP program

  - by bert

  What series of steps would be reqired to safely encode and pass a string from a html href using javascript to construct the link to a php program. in javascript set up URL // encodes a URI component. path = "mypgm.php?from=" + encodeURIComponent(myvar) ; in php: // get passed variables $myvar = isset($_GET['myvar']) ? ($_GET['myvar']) : ''; // decode - (make the string readable) $myvar = (rawurldecode($myvar)); // converts characters to HTML entities (reduce risk of attack) $myvar = htmlentities($myvar); // maybe custom sanitize program as well? // see [http://stackoverflow.com/questions/2668854/php-sanitizing-strings-to-make-them-url-and-filename-safe][1] $myvar = sanitize($myvar);

  Read the article

• Javascript cross-domain web request fails with Status=0?

  - by Tav

  Yes, I know the following code does not work in IE. I know IE expects me to use XDomainRequest() instead. I don't care about that. This is firefox only. I'm trying to do a cross-domain web request in firefox javascript. I keep getting a status of 0. Does anyone know why? var url = "http://newyork.craigslist.org"; var xdr = new XMLHttpRequest(); //Yes, I know IE expects XDomainRequest. Don't care xdr.onreadystatechange = function() { if (xdr.readyState == 4) { alert(xdr.status); //Always returns 0! And xdr.responseText is blank too } } xdr.open("get", url, true); xdr.send(null); Shouldn't that work?

  Read the article

• Embedding a querystring parameter in a hidden input with JSP results ing 500 error.

  - by dacracot

  I need a hidden input to contain the value passed by the querystring via a JSP's URL. The URL looks like... http://nowhere.com/myapp/blah.jsp?key=12345 The JSP looks like... <html> <body> <input id="key" type="hidden" value="<%=request.getParameter('key')%>" /> </body> </html> This causes a 500 error... SEVERE: Servlet.service() for servlet jsp threw exception org.apache.jasper.JasperException: Unable to compile class for JSP: An error occurred at line: 3 in the jsp file: /myapp/blah.jsp Invalid character constant 1: <html> 2: <body> 3: <input id="key" type="hidden" value="<%=request.getParameter('key')%>" /> 4: </body> 5: </html>

  Read the article

• Git push origin master

  - by user306472

  I posted this question early yesterday, but the thread seems to have died out. For reference, see http://stackoverflow.com/questions/2619117/git-push-origin-master . Here's the low-down: I'm new to git. I just set up an account with github and I followed all their instructions flawlessly until I got to the last command of git push origin master Upon entering this command, I get the error message "fatal: No path specified. See 'man git-pull' for valid url syntax." If I type in git origin show the output I see is origin. If I type in git remote -n show the output is * remote origin URL: [email protected]: HEAD branch: (not queried) Local ref configured for 'git push' (status not queried): (matching) pushes to (matching) Please help me get to the bottom of this.

  Read the article

• serving files using django - is this a security vulnerability

  - by Tom Tom

  I'm using the following code to serve uploaded files from a login secured view in a django app. Do you think that there is a security vulnerability in this code? I'm a bit concerned about that the user could place arbitrary strings in the url after the upload/ and this is directly mapped to the local filesystem. Actually I don't think that it is a vulnerability issue, since the access to the filesystem is restricted to the files in the folder defined with the UPLOAD_LOCATION setting. UPLOAD_LOCATION = is set to a not publicly available folder on the webserver url(r'^upload/(?P<file_url>[/,.,\s,_,\-,\w]+)', 'aeon_infrastructure.views.serve_upload_files', name='project_detail'), @login_required def serve_upload_files(request, file_url): import os.path import mimetypes mimetypes.init() try: file_path = settings.UPLOAD_LOCATION + '/' + file_url fsock = open(file_path,"r") file_name = os.path.basename(file_path) file_size = os.path.getsize(file_path) print "file size is: " + str(file_size) mime_type_guess = mimetypes.guess_type(file_name) if mime_type_guess is not None: response = HttpResponse(fsock, mimetype=mime_type_guess[0]) response['Content-Disposition'] = 'attachment; filename=' + file_name #response.write(file) except IOError: response = HttpResponseNotFound() return response

  Read the article

• Django: tinyMCE and cross site javascript

  - by pistacchio

  Hi, follow this question, I was able to set some textareas in my admin page as richtext inputs. The most voted answer suggests to follow an example and is what i did. Also, it talks about a problem concerning "blank pages". I'm having the same problem and I'm not able to solve it. I have my media files served by a different server, so MEDIA_URL points to a different host with a different port. To simulate this in my dev environment, I also serve media files from a different port. Debugging the failing javascript, Chrome yelds: Unsafe JavaScript attempt to access frame with URL http://localhost:8000/admin/blog/post/add/ from frame with URL http://localhost:88/s3mangerie/js/tiny_mce/themes/advanced/image.htm. Domains, protocols and ports must match. How to solve this problem? Thanks

  Read the article

• http_post_data basic authentication?

  - by kristian nissen

  I have a remote service that I need to access, according to the documentation it's restricted using basic authentication and all requests have to be posted (HTTP POST). The documentation contains this code example - VB script: Private Function SendRequest(ByVal Url, ByVal Username, ByVal Password, ByVal Request) Dim XmlHttp Set XmlHttp = CreateObject("MSXML2.XmlHttp") XmlHttp.Open "POST", Url, False, Username, Password XmlHttp.SetRequestHeader "Content-Type", "text/xml" XmlHttp.Send Request Set SendRequest = XmlHttp End Function how can I accomplish this in PHP? When I post data to the remote server it replies: 401 Unauthorized Access which is fine because I'm not posting my user/pass just the data. Bu when I add my user/pass as it's describe here: http://dk.php.net/manual/en/http.request.options.php like this: $res = http_post_data('https://example.com', $data, array( 'Content-Type: "text/xml"', 'httpauth' => base64_encode('user:pass'), 'httpauthtype' => HTTP_AUTH_BASIC ) ); the protocol is https - I get a runtime error in return (it's a .Net service). I have tried it without the base64_encode but with the same result.

  Read the article

• Google Vizualization with CSV data

  - by Shlomo Shmai

  Hi, I have a URL that returns data in CSV format. I would like to use Google Vizualization to create an interactive chart of the data. I've looked at several examples on Google Chart and Vizualization web page but I'm a bit confused as I'm not familiar with JavaScript or web programming in general. Question: Do I have to use JavaScript to parse the CSV string myself and manually construct the DataTable with addColumn() and addRows()? Or, is there a way to simply pass the CSV url to the charting function? I'm hoping to do something like this: var csv_data = get_data_from_url('http://...') var data = new google.visualization.DataTable(csv_data); var chart = new google.visualization.PieChart(document.getElementById('chart_div')); chart.draw(data, ...); Can someone please help me out? Thanks.

  Read the article

• I can't change HTTP request header Content-Type value using jQuery

  - by Matt

  Hi I tried to override HTTP request header content by using jQuery's AJAX function. It looks like this $.ajax({ type : "POST", url : url, data : data, contentType: "application/x-www-form-urlencoded;charset=big5", beforeSend: function(xhr) { xhr.setRequestHeader("Accept-Charset","big5"); xhr.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=big5"); }, success: function(rs) { target.html(rs); } }); Content-Type header is default to "application/x-www-form-urlencoded; charset=UTF-8", but it obviously I can't override its value no matter I use 'contentType' or 'beforeSend' approaches. Could anyone adivse me a hint that how do I or can I change the HTTP request's content-type value? thanks a lot. btw, is there any good documentation that I can study JavaScript's XMLHttpRequest's encoding handling?

  Read the article

• json encodes aray

  - by Stan Forrest

  Okay I have been struggling with this for hours. What I am doing is creating array of what I call objects that can be moved around on a calendar. Below is my code $year = date('Y'); $month = date('m'); echo json_encode(array( array( 'id' => 111, 'title' => "Event3", 'start' => "$year-$month-10", 'url' => "http://domain.com/" ), array( 'id' => 222, 'title' => "Event2", 'start' => "$year-$month-20", 'end' => "$year-$month-22", 'url' => "http://domain.com/" ) )); Now here is my problem. I need to loop through a mysql database to retrieve the information for each object. For some reason I can't get this to work. Please help Thanks Stan

  Read the article

< Previous Page | 363 364 365 366 367 368 369 370 371 372 373 374  | Next Page >