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  • Condition checking vs. Exception handling

    - by Aidas Bendoraitis
    When is exception handling more preferable than condition checking? There are many situations where I can choose using one or the other. For example, this is a summing function which uses a custom exception: # module mylibrary class WrongSummand(Exception): pass def sum_(a, b): """ returns the sum of two summands of the same type """ if type(a) != type(b): raise WrongSummand("given arguments are not of the same type") return a + b # module application using mylibrary from mylibrary import sum_, WrongSummand try: print sum_("A", 5) except WrongSummand: print "wrong arguments" And this is the same function, which avoids using exceptions # module mylibrary def sum_(a, b): """ returns the sum of two summands if they are both of the same type """ if type(a) == type(b): return a + b # module application using mylibrary from mylibrary import sum_ c = sum_("A", 5) if c is not None: print c else: print "wrong arguments" I think that using conditions is always more readable and manageable. Or am I wrong? What are the proper cases for defining APIs which raise exceptions and why?

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  • PAM authentication problem

    - by mdipierro
    I am using this module to authenticate using pam: http://code.google.com/p/web2py/source/browse/gluon/contrib/pam.py I can call authenticate('username','password') and it returns True/ False. It works for any 'username' but 'root'. My guess is that there is a security restriction in PAM that does not allow to check for the root password. I need to be able to check the root password. Is there anything I can change in the pam.conf or somewhere else to remove this restriction?

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  • Dajano admin site foreign key fields

    - by user292652
    hi i have the following models setup class Player(models.Model): #slug = models.slugField(max_length=200) Player_Name = models.CharField(max_length=100) Nick = models.CharField(max_length=100, blank=True) Jersy_Number = models.IntegerField() Team_id = models.ForeignKey('Team') Postion_Choices = ( ('M', 'Manager'), ('P', 'Player'), ) Poistion = models.CharField(max_length=1, blank=True, choices =Postion_Choices) Red_card = models.IntegerField( blank=True, null=True) Yellow_card = models.IntegerField(blank=True, null=True) Points = models.IntegerField(blank=True, null=True) #Pic = models.ImageField(upload_to=path/for/upload, height_field=height, width_field=width, max_length=100) class PlayerAdmin(admin.ModelAdmin): list_display = ('Player_Name',) search_fields = ['Player_Name',] admin.site.register(Player, PlayerAdmin) class Team(models.Model): """Model docstring""" #slug = models.slugField(max_length=200) Team_Name = models.CharField(max_length=100,) College = models.CharField(max_length=100,) Win = models.IntegerField(blank=True, null=True) Loss = models.IntegerField(blank=True, null=True) Draw = models.IntegerField(blank=True, null=True) #logo = models.ImageField(upload_to=path/for/upload, height_field=height, width_field=width, max_length=100) class Meta: pass #def __unicode__(self): # return Team_Name #def save(self, force_insert=False, force_update=False): # pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class TeamAdmin(admin.ModelAdmin): list_display = ('Team_Name',) search_fields = ['Team_Name',] admin.site.register(Team, TeamAdmin) my question is how do i get to the admin site to show Team_name in the add player form Team_ID field currently it is only showing up as Team object in the combo box

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  • Process Name with inotify tool

    - by Priyanka
    Hi ALl Is there a way to find out which process is causing a particular event to occur? In the inotify-tool version 3.13, in struct_kernel , pid,uid and gid are used but it is not handled in the source code. Is there any latest patch available for the same. Please let me know.

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • Unable to control requests for static files on Google App Engine

    - by dan
    My simple GAE app is not redirecting to the /static directory for requests when url is multiple levels. Dir structure: /app/static/css/main.css App: I have two handlers one for /app and one for /app/new app.yaml: handlers: - url: /static static_dir: static - url: /app/static/(.*) static_dir: static\1 - url: /app/.* script: app.py login: required HTML: Description: When page is loaded from /app HTTP request for main.css is successful GET /static/css/main.css But when page is loaded from /app/new I see the following request: GET /app/static/css/main.cs That's when I tried adding the /app/static/(.*) in the app.yaml but it is not having any effect.

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  • Which software for intranet CMS - Django or Joomla?

    - by zalun
    In my company we are thinking of moving from wiki style intranet to a more bespoke CMS solution. Natural choice would be Joomla, but we have a specific architecture. There is a few hundred people who will use the system. System should be self explainable (easier than wiki). We use a lot of tools web, applications and integrated within 3rd party software. The superior element which is a glue for all of them is API. In example for the intranet tools we do use Django, but it's used without ORM, kind of limited to templates and url - every application has an adequate methods within our API. We do not use the Django admin interface, because it is hardly dependent on ORM. Because of that Joomla may be hard to integrate. Every employee should be able to edit most of the pages, authentication and privileges have to be managed by our API. How hard is it to plug Joomla to use a different authentication process? (extension only - no hacks) If one knows Django better than Joomla, should Django be used?

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  • Removing a node from a linked list

    - by lost_with_coding
    I would like to create a delete_node function that deletes the node at the location in the list as a count from the first node. So far this is the code I have: class node: def __init__(self): self.data = None # contains the data self.next = None # contains the reference to the next node class linked_list: def __init__(self): self.cur_node = None def add_node(self, data): new_node = node() # create a new node new_node.data = data new_node.next = self.cur_node # link the new node to the 'previous' node. self.cur_node = new_node # set the current node to the new one. def list_print(self): node = ll.cur_node while node: print node.data node = node.next def delete_node(self,location): node = ll.cur_node count = 0 while count != location: node = node.next count+=1 delete node ll = linked_list() ll.add_node(1) ll.add_node(2) ll.add_node(3) ll.list_print()

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  • Problem bounding name to a class in Django

    - by martinthenext
    Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

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  • foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = 15, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT c.*, ci.* FROM category c JOIN category_info ci ON (c.node_id = ci.node_id) WHERE c.type_id = 15 AND c.parent_id = 50 AND ci.type_id = 1 Any help is GREATLY appreciated. Regards

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  • Euclidian Distances between points

    - by R S
    I have an array of points in numpy: points = rand(dim, n_points) And I want to: Calculate all the l2 norm (euclidian distance) between a certain point and all other points Calculate all pairwise distances. and preferably all numpy and no for's.

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  • How to add a context processor from a Django app

    - by Edan Maor
    Say I'm writing a Django app, and all the templates in the app require a certain variable. The "classic" way to deal with this, afaik, is to write a context processor and add it to TEMPLATE_CONTEXT_PROCESSORS in the settings.py. My question is, is this the right way to do it, considering that apps are supposed to be "independent" from the actual project using them? In other words, when deploying that app to a new project, is there any way to avoid the project having to explicitly mess around with its settings?

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  • Duplicate django query set?

    - by Piotr Czapla
    I have a simple django's query set like: qs = AModel.objects.exclude(state="F").order_by("order") I'd like to use it as follows: qs[0:3].update(state='F') expected = qs[3] # throws error here But last statement throws: "Cannot update a query once a slice has been taken." How can I duplicate the query set?

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  • how to pass in dynamic data to decorators

    - by steve
    Hi, I am trying to write a base crud controller class that does the following: class BaseCrudController: model = "" field_validation = {} template_dir = "" @expose(self.template_dir) def new(self, *args, **kwargs) .... @validate(self.field_validation, error_handler=new) @expose() def post(self, *args, **kwargs): ... My intent is to have my controllers extend this base class, set the model, field_validation, and template locations, and am ready to go. Unfortunately, decorators (to my understanding), are interpreted when the function is defined. Hence it won't have access to instance's value. Is there a way to pass in dynamic data or values from the sub class? If not, I guess I could use override_template as a workaround to expose and set the template within the controller action. How would I go about validating the form within the controller action? Thanks, Steve

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  • Project design / FS layout for large django projects

    - by rcreswick
    What is the best way to layout a large django project? The tutuorials provide simple instructions for setting up apps, models, and views, but there is less information about how apps and projects should be broken down, how much sharing is allowable/necessary between apps in a typical project (obviously that is largely dependent on the project) and how/where general templates should be kept. Does anyone have examples, suggestions, and explanations as to why a certain project layout is better than another? I am particularly interested in the incorporation of large numbers of unit tests (2-5x the size of the actual code base) and string externalization / templates.

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  • Getting a specific bit value in a byte string

    - by ignoramus
    There is a byte at a specific index in a byte string which represents eight flags; one flag per bit in the byte. If a flag is set, its corresponding bit is 1, otherwise its 0. For example, if I've got b'\x21' the flags would be 0001 0101 # Three flags are set at indexes 3, 5 and 7 # and the others are not set What would be the best way to get each bit value in that byte, so I know whether a particular flag is set or not? (Preferably using bitwise operations)

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  • SQLAlchemy unsupported type error - and table design issues?

    - by Az
    Hi there, back again with some more SQLAlchemy shenanigans. Let me step through this. My table is now set up as so: engine = create_engine('sqlite:///:memory:', echo=False) metadata = MetaData() students_table = Table('studs', metadata, Column('sid', Integer, primary_key=True), Column('name', String), Column('preferences', Integer), Column('allocated_rank', Integer), Column('allocated_project', Integer) ) metadata.create_all(engine) mapper(Student, students_table) Fairly simple, and for the most part I've been enjoying the ability to query almost any bit of information I want provided I avoid the error cases below. The class it is mapped from is: class Student(object): def __init__(self, sid, name): self.sid = sid self.name = name self.preferences = collections.defaultdict(set) self.allocated_project = None self.allocated_rank = 0 def __repr__(self): return str(self) def __str__(self): return "%s %s" %(self.sid, self.name) Explanation: preferences is basically a set of all the projects the student would prefer to be assigned. When the allocation algorithm kicks in, a student's allocated_project emerges from this preference set. Now if I try to do this: for student in students.itervalues(): session.add(student) session.commit() It throws two errors, one for the allocated_project column (seen below) and a similar error for the preferences column: sqlalchemy.exc.InterfaceError: (InterfaceError) Error binding parameter 4 - probably unsupported type. u'INSERT INTO studs (sid, name, allocated_rank, allocated_project) VALUES (?, ?, ?, ?, ?, ?, ?)' [1101, 'Muffett,M.', 1, 888 Human-spider relationships (Supervisor id: 123)] If I go back into my code I find that, when I'm copying the preferences from the given text files, it actually refers to the Project class which is mapped to a dictionary, using the unique project id's (pid) as keys. Thus, as I iterate through each student via their rank and to the preferences set, it adds not a project id, but the reference to the project id from the projects dictionary. students[sid].preferences[int(rank)].add(projects[int(pid)]) Now this is very useful to me since I can find out all I want to about a student's preferred projects without having to run another check to pull up information about the project id. The form you see in the error has the object print information passed as: return "%s %s (Supervisor id: %s)" %(self.proj_id, self.proj_name, self.proj_sup) My questions are: I'm trying to store an object in a database field aren't I? Would the correct way then, be copying the project information (project id, name, etc) into its own table, referenced by the unique project id? That way I can just have the project id field for one of the student tables just be an integer id and when I need more information, just join the tables? So and so forth for other tables? If the above makes sense, then how does one maintain the relationship with a column of information in one table which is a key index on another table? Does this boil down into a database design problem? Are there any other elegant ways of accomplishing this? Apologies if this is a very long-winded question. It's rather crucial for me to solve this, so I've tried to explain as much as I can, whilst attempting to show that I'm trying (key word here sadly) to understand what could be going wrong.

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  • Dropdown sorting in django-admin

    - by Andrey
    I'd like to know how can I sort values in the Django admin dropdowns. For example, I have a model called Article with a foreign key pointing to the Users model, smth like: class Article(models.Model): title = models.CharField(_('Title'), max_length=200) slug = models.SlugField(_('Slug'), unique_for_date='publish') author = models.ForeignKey(User) body = models.TextField(_('Body')) status = models.IntegerField(_('Status')) categories = models.ManyToManyField(Category, blank=True) publish = models.DateTimeField(_('Publish date')) I edit this model in django admin: class ArticleAdmin(admin.ModelAdmin): list_display = ('title', 'publish', 'status') list_filter = ('publish', 'categories', 'status') search_fields = ('title', 'body') prepopulated_fields = {'slug': ('title',)} admin.site.register(Article, ArticleAdmin) and of course it makes the nice user select dropdown for me, but it's not sorted and it takes a lot of time to find a user by username.

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  • Dynamically setting the queryset of a ModelMultipleChoiceField to a custom recordset

    - by Daniel Quinn
    I've seen all the howtos about how you can set a ModelMultipleChoiceField to use a custom queryset and I've tried them and they work. However, they all use the same paradigm: the queryset is just a filtered list of the same objects. In my case, I'm trying to get the admin to draw a multiselect form that instead of using usernames as the text portion of the , I'd like to use the name field from my account class. Here's a breakdown of what I've got: # models.py class Account(models.Model): name = models.CharField(max_length=128,help_text="A display name that people understand") user = models.ForeignKey(User, unique=True) # Tied to the User class in settings.py class Organisation(models.Model): administrators = models.ManyToManyField(User) # admin.py from django.forms import ModelMultipleChoiceField from django.contrib.auth.models import User class OrganisationAdminForm(forms.ModelForm): def __init__(self, *args, **kwargs): from ethico.accounts.models import Account self.base_fields["administrators"] = ModelMultipleChoiceField( queryset=User.objects.all(), required=False ) super(OrganisationAdminForm, self).__init__(*args, **kwargs) class Meta: model = Organisation This works, however, I want queryset above to draw a selectbox with the Account.name property and the User.id property. This didn't work: queryset=Account.objects.all().order_by("name").values_list("user","name") It failed with this error: 'tuple' object has no attribute 'pk' I figured that this would be easy, but it's turned into hours of dead-ends. Anyone care to shed some light?

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  • pysvn client.log() returning empty dictionary

    - by nashr rafeeg
    i have the following script that i am using to get the log messages from svn import pysvn class svncheck(): def __init__(self, svn_root="http://10.11.25.3/svn/Moodle/modules", svn_user=None, svn_password=None): self.user = svn_user self.password = svn_password self.root = svn_root def diffrence(self): client = pysvn.Client() client.commit_info_style = 1 client.callback_notify = self.notify client.callback_get_login = self.credentials log = client.log( self.root, revision_start=pysvn.Revision( pysvn.opt_revision_kind.number, 0), revision_end=pysvn.Revision( pysvn.opt_revision_kind.number, 5829), discover_changed_paths=True, strict_node_history=True, limit=0, include_merged_revisions=False, ) print log def notify( event_dict ): print event_dict return def credentials(realm, username, may_save): return True, self.user, self.password, True s = svncheck() s.diffrence() when i run this script its returning a empty dictionary object [<PysvnLog ''>, <PysvnLog ''>, <PysvnLog ''>,.. any idea what i am doing wrong here ? i am using pysvn version 1.7.2 built again svn version 1.6.5 cheers Nash

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created')

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  • initialize a numpy array

    - by Curious2learn
    Is there way to initialize a numpy array of a shape and add to it? I will explain what I need with a list example. If I want to create a list of objects generated in a loop, I can do: a = [] for i in range(5): a.append(i) I want to do something similar with a numpy array. I know about vstack, concatenate etc. However, it seems these require two numpy arrays as inputs. What I need is: big_array # Initially empty. This is where I don't know what to specify for i in range(5): array i of shape = (2,4) created. add to big_array The big_array should have a shape (10,4). How to do this? Thanks for your help.

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  • Inexpensive ways to add seek to a filetype object

    - by becomingGuru
    PdfFileReader reads the content from a pdf file to create an object. I am querying the pdf from a cdn via urllib.urlopen(), this provides me a file like object, which has no seek. PdfFileReader, however uses seek. What is the simple way to create a PdfFileReader object from a pdf downloaded via url. Now, what can I do to avoid writing to disk and reading it again via file(). Thanks in advance.

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