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  • Using xml to feed a silverlight application

    - by Aidenn
    Hey! I am building a Silverlight application that should get it's elements from XML defined objects, but I am kinda stuck: how should I feed the Silverlight application with the data in the XML? What would be a good approach? Can this be done by transforming XML to XAML using XSLT? Any other suggestion?

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  • PHP - Parse XML subitems using foreach()

    - by Nate Shoffner
    I have an XML file that needs parsing in PHP. I am currenlty using simplexml_load_file to load the file like so: $xml = simplexml_load_file('Project.xml'); Inside that XML file lies a structure like this: <?xml version="1.0" encoding="ISO-8859-1"?> <project> <name>Project 1</name> <features> <feature>Feature 1</feature> <feature>Feature 2</feature> <feature>Feature 3</feature> <feature>Feature 4</feature> </features> </project> What I am trying to do is print the <name> contents along with EACH <feature> element within <features>. I'm not sure how to do this because there is more than 1 element called <feature>. Any help is greatly appreciated.

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  • Sql Server XML-type column duplicate entry detection

    - by aaaa bbbb
    In Sql Server I am using an XML type column to store a message. I do not want to store duplicate messages. I only will have a few messages per user. I am currently querying the table for these messages, converting the XML to string in my C# code. I then compare the strings with what I am about to insert. Unfortunately, Sql Server pretty-prints the data in the XML typed fields. What you store into the database is not necessarily exactly the same string as what you get back out later. It is functionally equivalent, but may have white space removed, etc. Is there an efficient way to compare an XML string that I am considering inserting with those that are already in the database? As an aside, if I detect a duplicate I need to delete the older message then insert the replacement.

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  • Simple Java to XML example

    - by Tom Brito
    I've read a time ago about generate xml from Java using annotations, but I'm not finding a simple example now. If I want to make a xml file like: <x:element uid="asdf">value</x:element> from my java class: public class Element { private String uid = "asdf"; } Which annotations I should use to perform that? (I have a xml-schema, if this helps the generation)

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  • Tilde not recognised in XML public identifier

    - by phantom-99w
    Hi everyone I found an interesting bug and wanted to know you think. Brief background: I've written a custom DTD and an example XML file (both UTF-8). I have now implemented a SAX parser in Java which I want to test. I got a SAXException complaining "An invalid XML character (Unicode: 0x7e) was found in the public identifier". Now, the URL of my DTD does contain a tilde character (unicode 0x7e). If I move the DTD file to another URL which does not contain a tilde, then my example XML file parses without causing a SAXException. So I have a work-around for this problem, but I am interested to know: why does this happen? Is this a bug? If so, is it with UTF-8, Java (1.6.0_18 x86), Windows (Server 2008 R2 x86_64) or what? Or is this one of those little obscure nuances of the XML 1.0 specification?

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  • Android XML file doesn't save

    - by Shane
    I'm writing a game with LibGDX, and I'm trying to save an XML file, but there's always an exception (java.io.FileNotFoundException: /data/Slugfest/teams/Team1.xml: open failed: ENOENT (No such file or directory)) when saving the file. This code saves the file. public void save() { try { TransformerFactory transformerFactory = TransformerFactory.newInstance(); Transformer transformer = transformerFactory.newTransformer(); DOMSource source = new DOMSource(doc); StreamResult result; if (Gdx.app.getType() == ApplicationType.Android) { result = new StreamResult(new File("/data/Slugfest/teams/" + name + ".xml")); } else { result = new StreamResult(new File(name + ".xml")); } transformer.transform(source, result); Gdx.app.log("Slugfest", "File saved."); } catch (TransformerException tfe) { Gdx.app.log("Slugfest", tfe.getLocalizedMessage()); } } My manifest file includes the WRITE/READ_EXTERNAL_STORAGE permissions, by the way.

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  • how to get xml html after transpose and databind()

    - by rlee923
    Hi. I have some code that uses xsl and xml. The Xml control is on the design page. The xml control id is xmlApplication The xmlstring is generated and xsl has the format with all the tables and cells etc. Here is a part of thecode of a page which generates the final product which shows the xml in a certain format. xmlApplication.Document = xmlDoc; xmlApplication.Transform = transApp; xmlApplication.DataBind(); I am guessing after xmlApplication.Databind(), xmlApplication will be converted into something that can be put inside . Is it possible to grab as a string? Please let me know if I have a wrong idea abut this. Thanks a lot.

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  • Programatically opening an xml file in MS Word

    - by Dan Revell
    I'm opening an xml file in Microsoft Word 2007 using C#. I'm using an xsl file to define the layout which worked up to the point that I needed to include an image. I used the typical src html tag and the image displays when the xml is viewed in ie but not when it's opened in Word. I get the image place holder so I can only assume Word simply can't find the image. It's sitting next to both the xml file and xsl file but that doesn't make any difference. To open the document I'm passing the filenames for both the xml and xsl. I would imagine that as the src is in the xsl it would just look relative to one of these files. Any suggestions would be much appreciated. [EDIT] Apologies I lost track of this one. I fixed it in the end. I'll check what my solution was tomorrow and update this.

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  • delete XML node, keep original

    - by marzsman
    I need to delete some nodes from an XML variable and I want to keep the original intact. So I pass the XML to a new variable and delete the nodes from that one but the original changes with it. Is there a way to protect the XML from the original variable?

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  • Write easily readable XML in Python

    - by dutch
    Is there any way other than creating a method myself to write XML using python which are easily readable? xMLFile.write(xmlDom.toxml()) does create proper xml but reading them is pretty difficult. I tried toprettyxml but doesn't seem like it does much. e.g. following is what I would consider a human readable xml:

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  • PHP Simple XML Parse Attributes

    - by jwzk
    I have an XML file with data stored like this: <myxml> <item name="column18">88744544</item> <item name="column11">47884994</item> <item name="column3">44788894</item> </myxml> I need to first check (and be sure that) column11 is defined (there is no particular order), and then get its value. Using simple XML is not seeming to work too well. I have the following, but the value is missing. <?php if (count($xml->myxml->item) > 0) { foreach ($xml->myxml->item as $item) { var_dump($item->attributes()); } } ?>

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  • Loading xml with encoding UTF 16 using XDocument

    - by Sangram
    Hi, I am trying to read the xml document using XDocument method . but i am getting an error when xml has <?xml version="1.0" encoding="utf-16"?> When i removed encoding manually.It works perfectly. I am getting error " There is no Unicode byte order mark. Cannot switch to Unicode. " i tried searching and i landed up here-- Why does C# XmlDocument.LoadXml(string) fail when an XML header is included? But could not solve my problem. My code : XDocument xdoc = XDocument.Load(path); Any suggestions ?? thank you.

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  • PHP File System or XML : Security Issue

    - by jasmine
    I want to make a news portal(php) site with minimum mysql force. :create a cron, fetch data from mysql and write to a php file . (I dont know is it right way) But Can I use xml instead of php file? Write mysql data to xml. Is this a secure way? What is the best way? XML or php file? Thanks in advance

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  • How to assign XML attribute values to drop down list using XSL

    - by Vijay
    Hi, I have a sample xml as; <?xml version="1.0" encoding="iso-8859-9"?> <DropDownControl id="dd1" name="ShowValues" choices="choice1,choice2,choice3,choice4"> </DropDownControl > I need to create a UI representation of this XML using XSL. I want to fill the drop down list with values specified in choices attribute. Does anyone have any idea about this ? Thanks in advance :)

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  • php loop xml data with xsd schema - how do get the data

    - by miholzi
    i try to geht the data from a xml file and i have troubles to get data, for example, how can i get the caaml:locRef value or the caaml:beginPosition value? here is the code so far: /* a big thank you to helderdarocha */ /* – he already helped me yesterday with a part of this code */ $doc = new DOMDocument(); $doc->load('xml/test.xml'); $xpath = new DOMXpath($doc); $xpath->registerNamespace("caaml", "http://caaml.org/Schemas/V5.0/Profiles/BulletinEAWS"); if ($doc->schemaValidate('http://caaml.org/Schemas/V5.0/Profiles/BulletinEAWS/CAAMLv5_BulletinEAWS.xsd')) { foreach ($xpath->query('//caaml:DangerRating') as $key) { echo $key->nodeValue; print_r($key); } } and here ist the print_r from $key DOMElement Object ( [tagName] => caaml:DangerRating [schemaTypeInfo] => [nodeName] => caaml:DangerRating [nodeValue] => 2014-03-03+01:00 2 [nodeType] => 1 [parentNode] => (object value omitted) [childNodes] => (object value omitted) [firstChild] => (object value omitted) [lastChild] => (object value omitted) [previousSibling] => (object value omitted) [nextSibling] => (object value omitted) [attributes] => (object value omitted) [ownerDocument] => (object value omitted) [namespaceURI] => http://caaml.org/Schemas/V5.0/Profiles/BulletinEAWS [prefix] => caaml [localName] => DangerRating [baseURI] => /Applications/MAMP/htdocs/lola/xml/test.xml [textContent] => 2014-03-03+01:00 2 ) 2014-03-04+01:00 2 and here a part of the xml <caaml:DangerRating> <caaml:locRef xlink:href="AT7R1"/> <caaml:validTime> <caaml:TimePeriod> <caaml:beginPosition>2014-03-06T00:00:00+01:00</caaml:beginPosition> <caaml:endPosition>2014-03-06T11:59:59+01:00</caaml:endPosition> </caaml:TimePeriod> </caaml:validTime> <caaml:validElevation> <caaml:ElevationRange uom="m"> <caaml:beginPosition>2200</caaml:beginPosition> </caaml:ElevationRange> </caaml:validElevation> <caaml:mainValue>2</caaml:mainValue> </caaml:DangerRating> <caaml:DangerRating> <caaml:locRef xlink:href="AT7R1"/> <caaml:validTime> <caaml:TimePeriod> thanks!

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  • Comparing XML in SSRS

    - by silves89
    I'm new to SSRS. We'll have two slightly different chunks of XML in a single row of an SQL Server database table. In an SSRS report we'll want to show only the differences between the XML chunks. I don't know how to do this, but I suspect the XML Type in SQLServer 2005 might be useful, or XSLT transformations in SSRS. Could anyone point me in the right direction?

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  • XML through web service

    - by Krt_Malta
    Hi, I have some data which I think would be best to be represented in XML. I want this data to be transmitted from a Java Web service to a web client so basically I want the XML data to be transmitted. What I'm thinking is reading from the XML file from the web service converting it to an object and sending it to the client and the client would convert it to xml again. But I'm not sure if this is the best way I could do it... Any opinions please? Thanks and regards, Krt_Malta

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  • [java] how to parse XML document?

    - by user32167
    I have xml document in variable (not in file). How can i get data storaged in that? I don't have any additional file with that, i have it 'inside' my sourcecode. When i use DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(XML); (XML is my xml variable), i get an error java.io.FileNotFoundException: C:\netbeans\app-s7013\<network ip_addr="10.0.0.0\8" save_ip="true"> File not found.

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  • libxml2 or NSXMLDocument for create a XML

    - by zp26
    Hi, I have a question for my iPhone app. I looking for a documentation for libxml2. I have find more example for reading by XML, but my program must create a XML and i don't find anything (example or tutorial) for this. I can create a XML with libxml2 or i must use NSXMLDocument? Can you take me a example? Thanks so much.

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  • Querying XML using node numbers

    - by CP
    Okay, so I'm writing a utility that compares 2 XML documents using Microsoft's XML diff patch tool. The result looks something like this: <?xml version="1.0" encoding="utf-16"?><xd:xmldiff version="1.0" srcDocHash="10728157883908851288" options="IgnoreChildOrder IgnoreComments IgnoreWhitespace " fragments="yes" xmlns:xd="http://schemas.microsoft.com/xmltools/2002/xmldiff"><xd:node match="1"><xd:node match="1"><xd:node match="1"><xd:node match="2"><xd:node match="1"><xd:node match="1"><xd:node match="2"><xd:change match="1">testi22n2123</xd:change></xd:node></xd:node><xd:add match="/1/1/1/2/1/8" opid="1" /><xd:node match="7"><xd:node match="1"><xd:change match="1">31</xd:change></xd:node><xd:node match="2"><xd:change match="1">test2ing</xd:change></xd:node></xd:node><xd:remove match="8" opid="1" /></xd:node></xd:node></xd:node></xd:node></xd:node><xd:descriptor opid="1" type="move" /></xd:xmldiff> What I'm trying to do is go back into the source document and get the source data that represents the difference. I initially tried creating an Xpath query, but as I understand it now this XmlDiff thing works off the DOM... which seems like the dinosaur of XML objects these days. What's the best way to get at the node in the source XML by using the numbers provided in the diff result?

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  • JAVA: XML parsers gives null element

    - by Johan
    When I try to parse a XML-file, it gives sometimes a null element by the title. I think it has to do with HTML-tags &#039; How can I solve this problem? I have the follow XML-file: <item> <title>&#039; Nieuwe DVD &#039;</title> <description>tekst, tekst tekst</description> <link>dvd.html</link> <category>nieuws</category> <pubDate>Sat, 1 Jan 2011 9:24:00 +0000</pubDate> </item> And the follow code to parse the xml-file: //DocumentBuilderFactory, DocumentBuilder are used for //xml parsing DocumentBuilderFactory dbf = DocumentBuilderFactory .newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); //using db (Document Builder) parse xml data and assign //it to Element Document document = db.parse(is); Element element = document.getDocumentElement(); //take rss nodes to NodeList element.normalize(); NodeList nodeList = element.getElementsByTagName("item"); if (nodeList.getLength() > 0) { for (int i = 0; i < nodeList.getLength(); i++) { //take each entry (corresponds to <item></item> tags in //xml data Element entry = (Element) nodeList.item(i); entry.normalize(); Element _titleE = (Element) entry.getElementsByTagName( "title").item(0); Element _categoryE = (Element) entry .getElementsByTagName("category").item(0); Element _pubDateE = (Element) entry .getElementsByTagName("pubDate").item(0); Element _linkE = (Element) entry.getElementsByTagName( "link").item(0); String _title = _titleE.getFirstChild().getNodeValue(); String _category = _categoryE.getFirstChild().getNodeValue(); Date _pubDate = new Date(_pubDateE.getFirstChild().getNodeValue()); String _link = _linkE.getFirstChild().getNodeValue(); //create RssItemObject and add it to the ArrayList RssItem rssItem = new RssItem(_title, _category, _pubDate, _link); rssItems.add(rssItem); conn.disconnect(); }

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  • Help me choose between XML or SQL Lite on android

    - by Ngetha
    I have an android app that periodically, say once a week downloads content from a server in XML. The content is used by the app, different Acitivities use different parts of the content. My question is a design one, should I save the data in SQlite or just keep it as an XML file, which one would be faster to read? The app can only use one content piece at a time, which means subsequent XML content downloads replace the old one.

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  • Serializing a class containing a custom class

    - by Netfangled
    I want to serialize an object as xml that contains other custom classes. From what I understand (I've been reading MSDN and SO mostly), the XmlSerializer doesn't take this into account. This is the line that's confusing me: XML serialization serializes only the public fields and property values of an object into an XML stream. XML serialization does not include type information. For example, if you have a Book object that exists in the Library namespace, there is no guarantee that it will be deserialized into an object of the same type. Taken from MSDN, here For example, I want to serialize an object of type Order, but it contains a list of Products, and each one contains an object of type Category: class Order { List<Product> products; } class Product { Category type; } class Category { string name; string description; } And I want my Order object to be serialized like so: <Order> <Product> <Category Name=""> <Description></Description> </Category> </Product> <Product> <Category Name=""> <Description></Description> </Category> </Product> <Order> Does the XmlSerializer already do this? If not, is there another class that does or do I have to define the serialization process myself?

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