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  • Match over multiple lines perl regular expression

    - by John
    Hi, I have a file like this: 01 00 01 14 c0 00 01 10 01 00 00 16 00 00 00 64 00 00 00 65 00 00 01 07 40 00 00 22 68 61 6c 2e 6f 70 65 6e 65 74 2e 63 6f 6d 3b 30 30 30 30 30 30 30 30 32 3b 30 00 00 00 00 01 08 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 28 40 00 00 21 72 65 61 6c 6d 31 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 00 01 25 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 1b 40 00 00 20 72 65 61 6c 6d 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 01 02 40 00 00 0c 01 00 00 16 00 00 01 a0 40 00 00 0c 00 00 00 01 00 00 01 9f 40 00 00 0c 00 00 00 00 00 00 01 16 40 00 00 0c 00 00 00 00 00 00 01 bb 40 00 00 28 00 00 01 c2 40 00 00 0c 00 00 00 00 00 00 01 bc 40 00 00 13 31 39 37 37 31 31 31 32 32 33 31 00 I am reading the file and then finding certain octets and replacing them with tags: while(<FH>){ $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; # } So for example, 00 00 00 64 would be replaced by the tag. This was working fine, but it doesn't seem to able to match over multiple lines any more. For example the pattern 31 31 32 32 33 31 runs over multiple lines, and the regular expression doesn't seem to catch it. I tried using /m /s pattern modifiers to ignore new lines but they didn't match it either. The only way around it I can come up with, is to read the whole file into a string using: undef $/; my $whole_file = <FH>; my $line = $whole_file; $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; This works, the tags get inserted correctly, but the structure of the file is radically altered. It is all dumped out on a single line. I would like to retain the structure of the file as it appears here. Any ideas as to how I might do this? /john

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  • Does ASP.NET need to be configured for Full Trust to implement 'PageHandlerFactory' ?

    - by Kev
    Our hosting platform (running IIS6/ASP.NET 2.0) is configured to run under partial trust. In the machine wide web.config file we set the ASP.NET trust level to Medium (and lock to prevent overrides) and use a modified policy file. When trying to add a custom HttpHandler to handle .aspx requests for a website running in this configuration I get the following security exception: Security Exception Description: The application attempted to perform an operation not allowed by the security policy. To grant this application the required permission please contact your system administrator or change the application's trust level in the configuration file. Exception Details: System.Security.SecurityException: Request failed. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [SecurityException: Request failed.] System.Reflection.Assembly._GetType(String name, Boolean throwOnError, Boolean ignoreCase) +0 System.Reflection.Assembly.GetType(String name, Boolean throwOnError, Boolean ignoreCase) +42 System.Web.Compilation.CompilationUtil.GetTypeFromAssemblies(AssemblyCollection assembliesCollection, String typeName, Boolean ignoreCase) +172 System.Web.Compilation.BuildManager.GetType(String typeName, Boolean throwOnError, Boolean ignoreCase) +291 System.Web.Configuration.ConfigUtil.GetType(String typeName, String propertyName, ConfigurationElement configElement, XmlNode node, Boolean checkAptcaBit, Boolean ignoreCase) +52 I'm using a class derived from PageHandlerFactory, for example: public class MyPageHandlerFactory : PageHandlerFactory { public override System.Web.IHttpHandler GetHandler(System.Web.HttpContext context, string requestType, string virtualPath, string path) { // CustomPageHandler derives from System.Web.UI.Page return new CustomPageHandler(); } } My web.config httpHandler configuration is as follow: <httpHandlers> <add verb="*" path="*.aspx" type="MyPageHandler.MyPageHandlerFactory" /> </httpHandlers> The documentation for PageHandlerFactory shows that PageHandlerFactory is decorated with the following attributes: [PermissionSetAttribute(SecurityAction.LinkDemand, Unrestricted = true)] [PermissionSetAttribute(SecurityAction.InheritanceDemand, Unrestricted = true)] public class PageHandlerFactory : IHttpHandlerFactory Does this mean that I need to set ASP.NET to run at Full Trust to be able to create my own PageHandlerFactory classes?

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  • View Body not showing in Spring 3.2

    - by Dennis Röttger
    I'm currently trying to get into Java Web Development in general in Spring more specifically. I've set up my project as follows - hello.jsp: <html> <head> <title>Spring 3.0 MVC Series: Hello World - ViralPatel.net</title> </head> <body> <p>ABC ${message}</p> </body> </html> HelloWorldController.java: package controllers; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; System.out.println(message); return new ModelAndView("hello", "message", message); } } web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> </web-app> spring-servlet.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <context:component-scan base-package="controllers" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> </beans> I can start up the Server just fine and navigate to hello.html, which is resolved by the servlet to give me hello.jsp, the title of the .jsp shows (Spring 3.0 MVC Series: etc. etc.), alas, the body does not. Not the JSTL-Variable and not the "ABC" either. I've implemented jstl-1.2 in my lib-folder.

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  • "You have already activated" message even when using bundle exec

    - by juanpastas
    I am installing gems in my Gemfile in shared path as Capistrano does by default, and when I run: bundle exec rake assets:precompile RAILS_ENV=production I get: You have already activated rake 0.9.2.2, but your Gemfile requires rake 10.0.4. Using bundle exec may solve this. See that: cat Gemfile.lock | grep rake returns: rake (>= 0.8.7) rake (10.0.4) This is my gem environment output: - RUBYGEMS VERSION: 1.8.24 - RUBY VERSION: 1.9.3 (2013-06-27 patchlevel 448) [x86_64-linux] - INSTALLATION DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - RUBY EXECUTABLE: /opt/bitnami/ruby/bin/ruby - EXECUTABLE DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/bin - RUBYGEMS PLATFORMS: - ruby - x86_64-linux - GEM PATHS: - /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - "gemhome" => "/home/bitnami/my_app/shared/bundle/ruby/1.9.1/" - "gempath" => ["/home/bitnami/my_app/shared/bundle/ruby/1.9.1/"] - REMOTE SOURCES: - http://rubygems.org/ Update which -a rake /opt/bitnami/rvm/bin/rake /opt/bitnami/ruby/bin/rake Update 2 I tried giving full path to rake, but same problem

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  • Help with Struts Action mapping

    - by nicotine
    I am having a problem with my struts application it is a class enrollment app and when the user clicks on a "show enrolled courses" button it is supposed to show the courses they are enrolled in but it shows nothing at the moment. Struts/Apache does not return any errors, it Just shows a blank page and I cannot figure out why. My action mapping in my struts-config: <action path="/showEnrolled" type="actions.ShowEnrolledAction" name="UserFormEnrolled" scope="request" validate="true" input="/students/StudentMenu.jsp"> <forward name="success" path="/students/enrolled.jsp"/> </action> My link to the jsp enrolled.jsp page: <li><html:form action="/showEnrolled"> <html:hidden property="id" value= "<%=request.getRemoteUser()%>"/> <html:submit value = "View Enrolled Classes"/> </html:form> </li> When I click the link I get nothing but my menu on the page. The text headings for the page are not even displayed.

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  • How to choose my own filename format for subscribed podcast files?

    - by meomaxy
    I subscribe to several podcasts where the filenames of the downloaded mp3 files have no particular pattern to them. When I copy the directory of accumulated mp3 files into my mp3 player, the files play in alphabetical order. What I really want is to play the files chronologically by release date. I currently use iTunes on Windows XP to download the files. What I do now is manually rename the files, adding the date in YYYYMMDD format to the start of each filename so that an alphabetical listing of files will correspond to their chronological order when I listen to them later in PocketTunes on my Palm Centro. Is there some way to get the release date into the filename automatically? If so, I could automate or possibly skip the file renaming step. I would switch from iTunes to something else if that would solve my problem. The file creation time on my local disk isn't a reliable indicator because sometimes I download a few days worth of content at one time, and the files don't necessarily get downloaded in chronological order.

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  • What do encrypted files' data look like?

    - by Frost Shadow
    I know there are a lot of encryption programs available, that I would guess use different methods for encryption, and thus have different types of output files (.fve .tc .cha .dmg (bitlocker, truecrypt, challenger, ect.)), but if someone didn't know what the file was and just looked at the data, what would it look like? Does it just look like random bits, or can you still pick out a pattern? If it does look random, how is it if I moved the encrypted file to another computer, the other computer can tell it's a file, and is able to decrypt it (how would it even know where to start or stop, if it all looked random)? Also, how is the structure affected by encrypting files twice, using the same method, or a different one? Thanks for any help, and if you know any books or site about encryption for complete idiots, I'd appreciate it!

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  • after .htaccess url rewrite, cannot perform logoff in some of the url rewrited page

    - by Patrick
    Recently, I was doing .htaccess url rewrite, make all my php url into html, in some page, the logout button wont work properly. for example, in page ‘quotedetails/Q9999.html’ (rewrited from ‘quotedetails.php?quoteID=Q9999'), when I click logout button in this page, it wont do the trick, but when i use the old php url of this page, it works again, other rewrited pages like index.html (index.php), search.html(search.php), all works perfectly. I use firebug to debug, after I click the logout button, it stays in the same page without redirect me to the index.html, but I saw the the ‘logoff’ params has been passed through, but just dont let me logout and redirect to index page. I’ve changed all the relavent file path to absolute path, still no luck…..help please. I’ve also noticed from firebug, that page cannot get the redirect ‘location’ as I tried in other pages, their response headers come with ‘location: index.html’, but in that no-workin-page, there is no such line called ‘location: index.html’ in its response headers. Here is my .htaccess file, no-workin-pages are related to the first four ReweiteRules Options +FollowSymlinks RewriteEngine on RewriteRule ^reps/all,all.html$ rep.php?repID=all&repName=all RewriteRule ^reps/([A-Z]+),([A-Za-z\sA-Za-z]+).html$ rep.php?repID=$1&repName=$2 RewriteRule ^reps/([A-Za-z]+),([A-Za-z\sA-Za-z]+),([0-9]+).html$ rep.php?repID=$1repName=$2&page=$3 RewriteRule ^quotedetails/(Q[0-9]+).html$ quotedetails.php?quoteID=$1 RewriteRule ^index.html$ index.php RewriteRule ^addquote.html$ addquote.php RewriteRule ^search.html$ search.php RewriteRule ^viewall.html$ viewall.php RewriteRule ^howto.html$ howto.php

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  • Generating two thumbnails from the same image in Django

    - by Titus
    Hello, this seems like quite an easy problem but I can't figure out what is going on here. Basically, what I'd like to do is create two different thumbnails from one image on a Django model. What ends up happening is that it seems to be looping and recreating the same image (while appending an underscore to it each time) until it throws up an error that the filename is to big. So, you end up something like: OSError: [Errno 36] File name too long: 'someimg________________etc.jpg' Here is the code: def save(self, *args, **kwargs): if self.image: iname = os.path.split(self.image.name)[-1] fname, ext = os.path.splitext(iname) tlname, tsname = fname + '_thumb_l' + ext, fname + '_thumb_s' + ext self.thumb_large.save(tlname, make_thumb(self.image, size=(250,250))) self.thumb_small.save(tsname, make_thumb(self.image, size=(100,100))) super(Artist, self).save(*args, **kwargs) def make_thumb(infile, size=(100,100)): infile.seek(0) image = Image.open(infile) if image.mode not in ('L', 'RGB'): image.convert('RGB') image.thumbnail(size, Image.ANTIALIAS) temp = StringIO() image.save(temp, 'png') return ContentFile(temp.getvalue()) I didn't show imports for the sake of brevity. Assume there are two ImageFields on the Artist model: thumb_large, and thumb_small. If this isn't the correct way to do it, I'd appreciate any feedback. Thanks!

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  • mailsend not sending to (or qmail not receiving from) the same machine

    - by roman
    A web applications sends two emails: to the user of the webapp to the administrator the administrators mailbox (qmail) is on the same machine as the web application (php, apache, /usr/sbin/sendmail). email 1 works, email 2 sometimes doesn't work. I don't see any pattern in the mails that don't work. Also because I don't exactly know WHICH emails failed (since the email itself would be the only notification). email 2 looks like this: from: <[email protected]> #changes for each user to: <[email protected]> What could be the problem? Are rejected emails stored somewhere? (if they are rejected.. how do I check this?)

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  • Android, how to use DexClassLoader to dynamically replace an Activity or Service

    - by RickNotFred
    I am trying to do something similar to this stackoverflow posting. What I want to do is to read the definition of an activity or service from the SD card. To avoid manifest permission issues, I create a shell version of this activity in the .apk, but try to replace it with an activity of the same name residing on the SD card at run time. Unfortunately, I am able to load the activity class definition from the SD card using DexClassLoader, but the original class definition is the one that is executed. Is there a way to specify that the new class definition replaces the old one, or any suggestions on avoiding the manifest permission issues without actually providing the needed activity in the package? The code sample: ClassLoader cl = new DexClassLoader("/sdcard/mypath/My.apk", getFilesDir().getAbsolutePath(), null, MainActivity.class.getClassLoader()); try { Class<?> c = cl.loadClass("com.android.my.path.to.a.loaded.activity"); Intent i = new Intent(getBaseContext(), c); startActivity(i); } catch (Exception e) { Intead of launching the com.android.my.path.to.a.loaded.activity specified in /sdcard/mypath/My.apk, it launches the activity statically loaded into the project.

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  • UNIX "find" command, match literal "dot"

    - by Robottinosino
    I need files ending with ".pdf" or ".png"; here's my attempt: find /Users/robottinosino/Desktop/_PublishMe_ -type f -regex '.*[pdf|png]' this incorrectly includes files ending with "Apdf", "Zpdf", etc. (missing literal dot before file extension) I tried adjusting the pattern to: find /Users/robottinosino/Desktop/_PublishMe_ -type f -regex '.*\.[pdf|png]' but then no results are returned. Escaping the . with a backslash does not work. Why? [0] $ uname -a Darwin Robottinosino.local 10.8.0 Darwin Kernel Version 10.8.0: Tue Jun 7 16:33:36 PDT 2011; root:xnu-1504.15.3~1/RELEASE_I386 i386 Thanks!

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  • Extracting a .app from a zip file in Python, using ZipFile

    - by Yakattak
    I'm trying to extract new revisions of Chromium.app from their snapshots, and I can download the file fine, but when it comes to extracting it, ZipFile either extracts the chrome-mac folder within as a file, says that directories don't exist, etc. I am very new to python, so these errors make little sense to me. Here is what I have so far. import urllib2 response = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/LATEST') latestRev = response.read() print latestRev # we have the revision, now we need to download the zip and extract it latestZip = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/%i/chrome-mac.zip' % (int(latestRev)), '~/Desktop/ChromiumUpdate/%i-update' % (int(latestRev))) #declare some vars that hold paths n shit workingDir = '/Users/slehan/Desktop/ChromiumUpdate/' chromiumZipPath = '%s%i-update.zip' % (workingDir, (int(latestRev))) chromiumAppPath = 'chrome-mac/' #the path of the chromium executable within the zip file chromiumAppExtracted = '%s/Chromium.app' % (workingDir) # path of the extracted executable output = open(chromiumZipPath, 'w') #delete any current file there output.write(latestZip.read()) output.close() # we have the .zip now we need to extract the Chromium.app file, it's in ziproot/chrome-mac/Chromium.app import zipfile, os zippedFile = open(chromiumZipPath) zippedChromium = zipfile.ZipFile(zippedFile, 'r') zippedChromium.extract(chromiumAppPath, workingDir) #print zippedChromium.namelist() zippedChromium.close() #zippedChromium.close() Any ideas?

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  • wsgi django not working

    - by MaKo
    im installing django, the test for wsgi is ok, but when i point my default file to the django test, it doesnt work, this is the test that works fine: default: /etc/apache2/sites-available/default <VirtualHost *:80> ServerName www.example.com ServerAlias example.com ServerAdmin [email protected] DocumentRoot /var/www <Directory /var/www/documents> Order allow,deny Allow from all </Directory> WSGIScriptAlias / /home/ubuntu/djangoProj/micopiloto/application.wsgi <Directory /home/ubuntu/djangoProj/mysitio/wsgi_handler.py> Order allow,deny Allow from all </Directory> </VirtualHost> application.wsgi:: ~/djangoProj/micopiloto import os import sys sys.path.append('/srv/www/cucus/application') os.environ['PYTHON_EGG_CACHE'] = '/srv/www/cucus/.python-egg' def application(environ, start_response): status = '200 OK' output = 'Hello World!MK SS9 tkt kkk' response_headers = [('Content-type', 'text/plain'), ('Content-Length', str(len(output)))] start_response(status, response_headers) return [output] but if I change the default to point to application_sa.wsgi the django test, it doesnt work :( application_sa.wsgi import os, sys sys.path.append('/home/ubuntu/djangoProj/micopiloto') os.environ['DJANGO_SETTINGS_MODULE'] = 'micopiloto.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I restart the apache server every time i change the wsgi to test, so what im i missing? thanks a lot!

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  • Tab Completion In Emacs shell-mode SSH Sessions

    - by Sean M
    My current use pattern of emacs results in my having several shell-mode buffers open, each running an ssh session. I am running into an issue with this, though - when I try to tab-complete file names and other things in my remote session, the shell attempts to use completions available on the local machine instead of on the remote machine. For example, if the file ~/foobar exists on the local machine and ~/frob exists on the remote machine, typing in ~/f and pressing tab results in ~/foobar instead of completing correctly. If I use ssh outside of emacs and try the same thing, I get the correct completion of ~/frob instead. How can I get tab-completion to complete the way it does in normal ssh sessions ?

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  • Using inheritance and polymorphism to solve a common game problem

    - by Barry Brown
    I have two classes; let's call them Ogre and Wizard. (All fields are public to make the example easier to type in.) public class Ogre { int weight; int height; int axeLength; } public class Wizard { int age; int IQ; int height; } In each class I can create a method called, say, battle() that will determine who will win if an Ogre meets and Ogre or a Wizard meets a Wizard. Here's an example. If an Ogre meets an Ogre, the heavier one wins. But if the weight is the same, the one with the longer axe wins. public Ogre battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else if (this.axeLength > o.axeLength) return this; else if (this.axeLength < o.axeLength) return o; else return this; // default case } We can make a similar method for Wizards. But what if a Wizard meets an Ogre? We could of course make a method for that, comparing, say, just the heights. public Wizard battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else return this; } And we'd make a similar one for Ogres that meet Wizard. But things get out of hand if we have to add more character types to the program. This is where I get stuck. One obvious solution is to create a Character class with the common traits. Ogre and Wizard inherit from the Character and extend it to include the other traits that define each one. public class Character { int height; public Character battle(Character c) { if (this.height > c.height) return this; else if (this.height < c.height) return c; else return this; } } Is there a better way to organize the classes? I've looked at the strategy pattern and the mediator pattern, but I'm not sure how either of them (if any) could help here. My goal is to reach some kind of common battle method, so that if an Ogre meets an Ogre it uses the Ogre-vs-Ogre battle, but if an Ogre meets a Wizard, it uses a more generic one. Further, what if the characters that meet share no common traits? How can we decide who wins a battle?

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  • Trouble with setting entry point for GWT service

    - by Xorty
    Hello. I've followed serveral tutorials and read official docs at code.google.com, but still didn't manage to resolve this thing. I am creating simple service that'll check if user can be logged. CLIENT SIDE: public interface LoginService extends RemoteService { /** * Checks, if user has valid login. * @param user User's login. * @return True if such a login is in the database. */ boolean isValidUser(User user); } And here is Async interface: public interface LoginServiceAsync { /** * Checks, if user has valid login. * @param user User's login. * @param callback the callback to return True if such a login is in the database. */ void isValidUser(User user, AsyncCallback<Boolean> callback); } SERVER SIDE: public class LoginServiceImpl extends RemoteServiceServlet implements LoginService { /** * serial version UID */ private static final long serialVersionUID = 1044980345057997696L; /**{@inheritDoc} */ @Override public boolean isValidUser(User user) { boolean success = true; //TODO change } } Now I have entry point class MailClient.java. I append here widget like: CustomWidgets.getLoginWidget(this); // access rootPanel and append widget Now I need to make actual call to my service, and here is problem: LoginServiceAsync loginService = (LoginServiceAsync) GWT.create(LoginService.class); User user = new User(boxName.getText(), boxPassword.getText()); AsyncCallback<Boolean> callback = new AsyncCallback<Boolean>() { @Override public void onFailure(Throwable caught) { Window.alert(caught.getMessage()); //TODO change } @Override public void onSuccess(Boolean result) { Window.alert("success"); //TODO change } }; ((ServiceDefTarget) loginService).setServiceEntryPoint(GWT.getModuleBaseURL()+"login"); // dunno what should be here So to recap, I don't know how to set service's entry point. Here's my MailClient.gwt.xml file: <module> <inherits name="com.google.gwt.user.User"/> <inherits name="com.google.gwt.user.theme.standard.Standard"/> <entry-point class="com.xorty.mailclient.client.MailClient"/> <servlet path="/login" class="com.xorty.mailclient.server.servlets.LoginServiceImpl" /> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> </module> My web.xml file: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <!-- Default page to serve --> <welcome-file-list> <welcome-file>MailClient.html</welcome-file> </welcome-file-list> <servlet> <servlet-name>LoginService</servlet-name> <servlet-class>com.xorty.mailclient.server.servlets.LoginServiceImpl</servlet-class> </servlet> <servlet-mapping> <servlet-name>LoginService</servlet-name> <url-pattern>/com.xorty.mailclient.MailClient/login</url-pattern> </servlet-mapping> </web-app> And here is screenshot of project structure:

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  • Spring MVC application - URL gives No file found (404)

    - by user1700184
    I created a Spring-MVC project. web.xml: <servlet> <servlet-name>mvc-dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>mvc-dispatcher</servlet-name> <url-pattern>/soundmails</url-pattern> </servlet-mapping> mvc-dispatcher-servlet.xml <?xml version="1.0"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <mvc:annotation-driven /> <context:component-scan base-package="somepkg.controllers" /> <bean id="multipartResolver" class="org.gmr.web.multipart.GMultipartResolver"> <property name="maxUploadSize" value="1048576" /> </bean> <bean id="placeholderConfig" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <!-- property name="location"> <value>/WEB-INF/social.properties</value> </property--> </bean> <bean id="jacksonMessageConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"></bean> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"> <property name="messageConverters"> <list> <ref bean="jacksonMessageConverter"/> </list> </property> </bean> </beans> The controller has this code: ProjectController.java @Controller @RequestMapping("/soundmails") public class FileUploadController { @RequestMapping(value="/test", method=RequestMethod.GET) public @ResponseBody String test() { System.out.println("Hai"); return "Hai"; } } I am using Google App Engine in my local machine to test this. I am getting these in my log: [INFO] Oct 24, 2013 1:54:18 AM com.google.appengine.tools.development.LocalResourceFileServlet doGet [INFO] WARNING: No file found for: /soundmails/test I tried /soundmails/soundmails/test as well. That is also giving the same error. I am using Spring 3.1.0.RELEASE Can someone help me figure out what I am missing - /soundmails/test is giving 404 error. Edit I am unable to enable DEBUG logs for this. For some reason, it is not taking log level configured in logging.properties But I observed something interesting: 1) If I map the request to empty string (value = "") @RequestMapping(value="", method=RequestMethod.GET) public @ResponseBody String test() { System.out.println("Hai"); return "Hai"; } Then, when I try to access 127.0.0.1/soundmails, it works fine (returns string "Hai"). 2) When I have value="/test" @RequestMapping(value="/test", method=RequestMethod.GET) public @ResponseBody String test() { System.out.println("Hai"); return "Hai"; } and I try to access 127.0.0.1/soundmails/test, it is giving HTTP 404. This is weird.

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  • Getting spurious undo (ctrl-z) sent randomly on a Dell Laptop

    - by squelart
    For the past couple of weeks, my laptop has had a strange problem where it looks like ctrl-z is pressed, so I usually lose bits of text I just typed. If I press ctrl-shit-z (redo), the text comes back, proving it's really as if ctrl-z was pressed. It's difficult to see a pattern, I can be undo-free for hours, then get a few within minutes, sometimes 2-3 undoes at a time. Very frustrating! Running WinXP+SP3 on Dell Latitude D820, Clamwin antivirus. I've tried another keyboard, no difference. Any clue on what this could be, or how I could trace this problem? 2009-09-25: Tried a few things that were listed or linked to on this page: http://www.selfishman.net/2008/06/24/problem-with-dell-inspiron-1501-keypress-every-second/ but nothing helped. Though it seems to point at a Dell laptop issue. I upgraded the BIOS and other drivers, but still got the problem.

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  • Ubuntu server hangs on reboot "could not stat resume device file"

    - by matnagel
    Instead of booting into the running system this machine stops and on the terminal I can see a message: could not stat resume device file /dev/sdb5 When I attach a keyboard and press enter the boot continues and the machine comes up like normal. But it's essential that this machine comes up under most circumstancs alone. There never was something like a "resume" on this machine. I tried several times to reboot, but this does not happen on all boots, I can not find a pattern here. There is a software raid running on the box. This is the syslog during boot: http://privatepaste.com/ff0fd0a51c/sdabfjahfgasjkgfu4gfsdzjcgfafasdjfhgasdcjfgauzfgafasgdufzg How can I get rid of this boot failure? We do not need resumes and best would be something that works here and now.

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  • Strange Behaviour in DataGrid SilverLight 3 Control

    - by Asim Sajjad
    Here is the my Xaml Code. Here I have changed the Foreground of the cell depending on the current age of the person. <data:DataGridTemplateColumn Header="First Name" Width="150" MinWidth="150" CanUserReorder="False" SortMemberPath="FirstName"> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate > <TextBlock Foreground ="{Binding Path=DateOfBirth,Mode=OneWay,Converter={StaticResource CellColor}}" Text="{Binding FirstName}" ToolTipService.ToolTip="{Binding FirstName}" FontFamily="Arial" FontSize="11" VerticalAlignment="Center" Margin="5,0,0,0" /> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> <data:DataGridTextColumn Foreground ="{Binding Path=DateOfBirth,Mode=OneWay,Converter={StaticResource CellColor}}" Header="Last Name" Width="150" MinWidth="150" Binding="{Binding LastName}" CanUserSort="True" IsReadOnly="True" CanUserReorder="False"/> When I run the above code it return following Exception AG_E_PARSER_BAD_PROPERTY_VALU My question is that when I remove the Foreground converter from the DataGridTextColumn Column it runs fine As the Foreground converter is applied in the DataGridTemplateColumn Column which will not through excepction. But when I used same Converter to the DataGridTextColumn it throw execption why, can anyone know why is th is behaviour thanks in advance.

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  • Why do some devices seemingly need the wifi router to reboot before they can connect?

    - by CreeDorofl
    I've noticed a pattern but I'm not sure if it's a crappy router, crappy wireless device, or maybe everything is working as intended. I can wirelessly connect my office PC to the router's settings page for a day, maybe two, then afterwards I can't anymore until it's reset. Unrelated, but similar, in various places that offer free wifi, my kindle will connect fine most days, but occasionally won't unless the router is reset. After the reset, I connect ok. What's happening behind the scenes that makes a router stop allowing you to connect? Is it something on my end that's changing, or on the router's end?

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  • WPF - List items not visible in Blend when 'DisplayMemberPath' is used

    - by Andy T
    Hi, We're currently working out how to implement MVVM and I've got to the point where I've got the MVVM Light Toolkit set up in blend and can specify dummy data to be supplied if running in Blend. All good. I've created a dummy list of data. The list contains 6 instances of a very simple class called DummyItem which has Age and Name properties. Here's the main code from my 'DummyList' class: public class DummyItem{ public string Name; public int Age; public DummyItem(string name, int age){ this.Name = name; this.Age = age; } } public class DummyList : ArrayList { public DummyList() { this.Add(new DummyItem("Dummy1", 00)); this.Add(new DummyItem("Dummy2", 01)); this.Add(new DummyItem("Dummy3", 02)); this.Add(new DummyItem("Dummy4", 03)); this.Add(new DummyItem("Dummy5", 04)); this.Add(new DummyItem("Dummy6", 05)); } } Here's the operative part of my XAML. The DataContext line does work and points to the correct ViewModel. <Grid x:Name="LayoutRoot"> <ListBox x:Name="ListViewBox" DataContext="{Binding Source={StaticResource Locator}, Path=ListViewModel}" ItemsSource="{Binding TheList}" DisplayMemberPath="Name"> </ListBox> </Grid> The problem is, when I add 'DisplayMemberPath', as I have above, then I can no longer see the list items in Blend. If I remove 'DisplayMemberPath', then I see a list of objects (DummyItem) with their full path. When the app is run, everything works perfectly. It's just that in Blend itself I cannot see the list items when I use 'DisplayMemberPath'. Anyone know why I can't see the items inside Blend itself when I use DisplayMemberPath? Thanks! AT

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  • ASP.NET MVC 2 - How do I use an Interface as the Type for a Strongly Typed View

    - by Rake36
    I'd like to keep my concrete classes separate from my views. Without using strongly typed views, I'm fine. I just use a big parameter list in the controller method signatures and then use my service layer factory methods to create my concrete objects. This is actually just fine with me, but it got me thinking and after a little playing, I realized it was literally impossible for a controller method to accept an interface as a method parameter - because it has no way of instantiating it. Can't create a strongly-typed view using an interface through the IDE either (which makes sense actually). So my question. Is there some way to tell the controller how to instantiate the interface parameter using my service layer factory methods? I'd like to convert from: [Authorize] [AcceptVerbs(HttpVerbs.Post)] [UrlRoute(Path = "Application/Edit/{id}")] public ActionResult Edit(String id, String TypeCode, String TimeCode, String[] SelectedSchoolSystems, String PositionChoice1, String PositionChoice2, String PositionChoice3, String Reason, String LocationPreference, String AvailableDate, String RecipientsNotSelected, String RecipientsSelected) { //New blank app IApplication _application = ApplicationService.GetById(id); to something like [Authorize] [AcceptVerbs(HttpVerbs.Post)] [UrlRoute(Path = "Application/Edit/{id}")] public ActionResult Edit(String id, IApplication app) { //Don't need to do this anymore //IApplication _application = ApplicationService.GetById(id);

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  • Why can't pass Marshaled interface as integer(or pointer)

    - by cemick
    I passed ref of interface from Visio Add-ins to MyCOMServer (http://stackoverflow.com/questions/2455183/interface-marshalling-in-delphi).I have to pass interface as pointer in internals method of MyCOMServer. I try to pass interface to internal method as pointer of interface, but after back cast when i try call method of interface I get exception. Simple example(Fisrt block execute without error, but At Second block I get Exception after addressed to property of IVApplication interface): procedure TMyCOMServer.test(const Interface_:IDispatch); stdcall; var IMy:_IMyInterface; V: Variant; Str: String; I: integer; Vis: IVApplication; begin ...... Self.QuaryInterface(_IMyInterface,IMy); str := IA.ApplicationName; V := Integer(IMy); i := V; Pointer(IMy) := Pointer(i); str := IMy.SomeProperty; // normal completion str := (Interface_ as IVApplication).Path; V := Interface_; I := V; Pointer(Vis) := Pointer(i); str := Vis.Path; // 'access violation at 0x76358e29: read of address 0xfeeefeee' end; Why I can't do like this?

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