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  • PHP pass variable after form is submitted

    - by user342391
    I have a form that posts to process.php. Process.php send all the data to mysql then returns back to the page using: <?php header("Location: /campaigns"); ?> On the page it returns to I want to display a message saying form submitted. Can I post a variable to the Location: /campaigns. And use the variable to display the message (or modal box)? and if so what would be the best way to do it?

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  • Defining action on window load

    - by zac
    I am trying to get a page to display specific properties depending on whether or not a specific cookie is set... I am trying this var x = readCookie('age'); window.onload=function(){ if (x='null') { document.getElementById('wtf').innerHTML = ""; }; if (x='over13') { document.getElementById('wtf').innerHTML = ""; }; if (x='not13') { document.getElementById('emailBox').innerHTML = "<style type=\"text/css\">.formError {display:none}</style><p>Good Bye</p><p>You must be 13 years of age to sign up.</p>"; }; } It always just defaults to whatever is in the first if statement... I am still learning my javaScript so I am sure this is sloppy.. can someone please help me get this working?

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  • AdMob won't load programmatically

    - by scottbot95
    I'm need to include ads into my app and I have a settings option to disable ads. so I need to load the ad in code. I copied the code from google to handle that and when I set ads:loadAdOnCreate to true, it works just fine. But if I set it to false and add the two lines AdView adView = (AdView)this.findViewById(R.id.ad); adView.loadAd(new AdRequest()); The ads stop displaying. If I look at log cat, it shows that it is receiving an ad and trying to display it. However it won't actually display on screen. Help?

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • PHP Array Not Working in Function

    - by lemonpole
    Hello all. I'm currently experimenting with arrays in PHP, and I created a fake environment where a team's information will be displayed. $t1 = array ( "basicInfo" => array ( "The Sineps", "December 25, 2010", "lemonpole" ), "overallRecord" => array (0, 0, 0, 0), "overallSeasons" => array ( 1 => array (14, 0, 0), 2 => array (9, 5, 2), 3 => array (12, 4, 0), 4 => array (3, 11, 2) ), "games" => array ( "<img src=\"images/cs.gif\" alt=\"Counter-Strike\" />", "<img src=\"images/cs.gif\" alt=\"Counter-Strike\" />", "<img src=\"images/cs.gif\" alt=\"Counter-Strike\" />", "<img src=\"images/cs.gif\" alt=\"Counter-Strike\" />" ), "seasonHistory" => array ( "Season I", "Season II", "Season III", "Season IV" ), "divisions" => array ( "Open", "Main", "Main", "Invite" ) ); // Displays the seasons the team has been in along // with the record of each season. function seasonHistory() { // Make array variable local-scope. global $t1; // Count the number of seasons. $numrows = count($t1["seasonHistory"]); // Loop through all the variables until // it reaches the last entry made and display // each item seperately. for($v = 0; $v <= $numrows; $v++) { // Echo each season. echo "<tr><td>{$t1["games"][$v]}</td>"; echo "<td>{$t1["seasonHistory"][$v]}</td>"; echo "<td>{$t1["divisions"][$v]}</td></tr>"; } } I have tested several possible problems out and after narrowing them down I have come down to one conclusion and that is my function is not connecting to the array for some reason. I don't know what else to do because I thought making the array global would fix that problem. What works: I can echo $t1["games"][0] on the page I need it to display and it gives me the content. I tried echo $t1["games"][0] INSIDE the function and then calling the function and it doesn't display anything.

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  • How to use php variables (arrays) in mysql select statements?

    - by davidconn
    Hi everybody, How do you use a php variable (array) inside a mysql select statement? I am designing an auction site and currently working on a page that lets people view a list of all the current bids for an item. I want to display 3 columns: amountbid - the amount each bidder has bid for the item (held in tblbid) bidderid - the id of each bidder who has bid (found in tbluser) total_positivity_feedback - how many users have left positive feedback for the bidder (calculated from tblfeedback) To find the 'amount' and the 'bidderid' columns i pass the essayid URL parameter from the previous page. This works fine. Despite this, i can't display the total_positivity_feedback column for the various users who have made each bid. My mysql query looks like this: select tblbid.bidderid, tblbid.amount, (select count(tblfeedback.feedbackid) from tblfeedback WHERE tblfeedback.writerid = "ARRAY VARIABLE GOES HERE") AS total_positivity_feedback FROM tblbid WHERE tblbid.essayid = $essayid_bids I assume that the only way to accomplish this is to make the variable contain the bidderid's of those people who bid for that particular essay? I can't seem to work out how to do this tho?!? Many thanks for your help

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  • jquery/ajax load new content when available

    - by Tim
    I know this is quite a vague question -- sorry about that. If I have a forum, shoutbox or something similar where users enter and submit data, running on PHP and MySQL, what is the best way to have the newly submitted content automatically display on the page for all users when it is submitted? Much like a live newsfeed, if you like... The effect sort-of works here at stackoverflow, when you are answering a question you are told when new answer is submitted. I want to test for newly submitted content and then display it automatically. Any suggestions? Many thanks :)

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • Add two webview in framelayout

    - by user1478916
    I want to add two webview in a layout..I use frameLayout <?xml version="1.0" encoding="utf-8"?> <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" > <WebView android:id="@+id/webview1" android:layout_width="350dip" android:layout_height="350dip" /> <WebView android:layout_height="250dip" android:layout_width="250dip" android:id="@+id/webview2" /> </FrameLayout> And in Main Activity : web1=(WebView)findViewById(R.id.webview1); web2=(WebView)findViewById(R.id.webview2); web1.loadUrl("http://www.google.com"); web2.loadUrl("http://www.youtube.com"); web2.setOnClickListener(new OnClickListener() { public void onClick(View v) { // TODO Auto-generated method stub Animation anim=AnimationUtils.loadAnimation(FrameWebViewActivity.this, android.R.anim.slide_in_left); web2.setAnimation(anim); } }); But when run project,it only display webview youtube full screen ..I want to display both two webview..What i must do??

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  • Struts2 scriptlet

    - by Bret
    Using struts2 with jsp with standard struts tag libraries. I'm trying to dynamically hide a DIV on page load, but still send it to the browser. This is so I can show it later via javascript. The request objects one and two are not easily referenced via a jsp:usebean tag. (They are enums and cannot be instantiated) I tried using a combination of s:if tags or c:if tags and it just looks ugly. <% String displayStr = "display: none;"; if(request.getAttribute("one") != null || request.getAttribute("two") != null ) { displayStr = "display: block;"; } %> <div id="next" style="<%=displayStr %>"> Any suggestions for a better way to do this?

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  • waht is the differnce between these two types using jquery

    - by kumar
    hi, $('tr td:first-child').click(function() { var foobar = $(this).text(); $("#showgrid").load('/Product/List/Item?id=' + foobar); }); when I am seding foobar value like this in the Actionresult method I am getting string id value perfectly but I am not able to display the grid? but intresting thing is when I am seding like this $("#showgrid").load('/Product/List/Item?id=' + "12345"); then I am able to display the grid.. foobar result is same 12345.. what is the differnt between these two types? can any body help me out.. thanks

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  • Problems with capturing an event in child object in Actionscript

    - by Raigomaru
    I have two classes. The first one (the starting class): package { import flash.display.Sprite; import flash.events.KeyboardEvent; import tetris.*; public class TetrisGame extends Sprite { private var _gameWell:Well; public function TetrisGame() { _gameWell = new Well(); addChild(_gameWell); } } } The second: package tetris { import flash.display.Sprite; import flash.events.KeyboardEvent; public class Well extends Sprite { public function Well() { super(); addEventListener(KeyboardEvent.KEY_DOWN, onKeyboard); } private function onKeyboard():void { //some code is here } } } But when I press any buttons on my keyboard, the child class Well doesn't have any reaction. What's the problem?

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  • An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING cla

    - by brz dot net
    I have to find the indentid from the status table based on below two conditions: 1. If there are more than one record having same indentid in status table and the same indentID has count1 in feasibilitystatus table then I don't want to display the record. 2. If there is only one record of indentid in status table and the same indentID has count0 in feasibilitystatus table then I don't want to display the record. Query: select distinct s.indentid from status s where s.status='true' and s.indentid not in(select case when count(s.indentid)>1 then (select indentid from feasibilitystatus group by indentid having count(indentid)>1) else (select indentid from feasibilitystatus group by indentid having count(indentid)>0) end as indentid from status) Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

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  • Spring / Hibernate project with Tomcat and JQuery.

    - by Tiago
    Hi, I have a Dynamic Web Project that implements Spring and Hibernate using a Tomcat Server (v6). I'm lauching Tomcat with my Eclipse Galileo and I'm not getting any errors in the console but Tomcat is rendering my webpages randomly. The page just keep loading but without displaying anything, there's nothing on the console either. When I go in debug mode, it goes throught the right steps, everything seems alright. When I display the source code on the web browser (Firefox latest build) it shows me the right code that is needed to display the page I called. What am I not getting here? Plus when I stop Tomcat, it renders a part of the page. I'm wondering if JQuery could be the problem? The thing is that it's a collaborative project and that the others managed to run the web application in the most alright way. Please, share your experience with me.

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  • Manipulating values from database table with php

    - by charliecodex23
    I currently have 5 tables in MySQL database. Some of them share foreign keys and are interdependent of each other. I am displaying classes accordingly to their majors. Each class is taught during the fall, spring or all_year. In my database I have a table named semester which has an id, year, and semester fields. The semester field in particular is a tinyint that has three values 0, 1, 2. This signifies the fall, spring or all_year. When I display the query instead of having it show 0 or 1 or 2 can I have it show fall, spring etc? Extra: How can I add space to the end of each loop so the data doesn't look clustered? Key 0 Fall 1 Spring 2 All-year PHP <? try { $pdo = new PDO ("mysql:host=$hostname;dbname=$dbname","$username","$pw"); } catch (PDOException $e) { echo "Failed to get DB handle: " . $e->getMessage() . "\n"; exit; } $query = $pdo->prepare("SELECT course.name, course.code, course.description, course.hours, semester.semester, semester.year FROM course LEFT JOIN major_course_xref ON course.id = major_course_xref.course_id LEFT JOIN major ON major.id = major_course_xref.major_id LEFT JOIN course_semester_xref ON course.id = course_semester_xref.course_id LEFT JOIN semester ON course_semester_xref.semester_id = semester.id"); $query->execute(); if ($query->execute()){ while ($row = $query->fetch(PDO::FETCH_ASSOC)){ print $row['name'] . "<br>"; print $row['code'] . "<br>"; print $row['description'] . "<br>"; print $row['hours'] . " hrs.<br>"; print $row['semester'] . "<br>"; print $row['year'] . "<br>"; } } else echo 'Could not fetch results.'; unset($pdo); unset($query); ?> Current Display Computer Programming I CPSC1400 Introduction to disciplined, object-oriented program development. 4 hrs. 0 2013 Desire Display Computer Programming I CPSC1400 Introduction to disciplined, object-oriented program development. 4 hrs. Fall 2013

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  • Changing the way widgets are rendered/displayed in a form on the template

    - by user334017
    I have a form with a few other embedded forms and some various widgets. The widgets are all saved in an array $form['elements'] and for some of them, I want to display labels and things, but for others I only want to display the basic rendering. foreach($form['elements'] as $elem) echo $elem->render(); this displays everything about the widget. The way it is right now, I couldn't for example call $elem['..'] because the different subforms appear in a random order and have different variable names. I assume I could still put some checks in the template, but it seems easier to fix this in the widget class, like override one of the render functions or something. How would I go about doing this or do you have any links that could help me understand how do do this? on a side note, one of my widgets is the sfWidgetFormChoice and I have no clue where it actually renders or how renderer_classes work

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  • Fancy box with one image only

    - by Mohamed Samy
    I using fancy box with my photo gallery, the problem is found it upload 2 images. one for the Thumbnail and one for fancy box <a style="display: block;" class="fancybox imgContainer" href="images/lorenteJerome_barcelona.jpg" data-fancybox-group="gallery" data-filter="arch"><img src="images/lorenteJerome_barcelona.jpg" alt=""></a> any way , I can upload 1 pic but I need to re-size the Thumbnail image with css or jquery. any one can help . CSS of the Thumbnail : .imgContainer { width: 100px; height: 100px; overflow: hidden; text-align: center; margin: 10px 20px 10px 0; float: left; border: solid 1px #999; display: block; }

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • Jquery UI modal (popup box) control size and hide by default

    - by user782104
    jsfddle page I am currently using bootstrap modal , which is a jquery plugin to create a popup box, here is its documentation, only few lines, so it takes a minute to read only I encountered problem in 3 aspect : How can i define the size of the modal(pop up box)? I tried: <div class="modal" id="myModal" style="width:800px;height:900px;"> but it does not display correctly. And how can i hide the modal by default, it currently display when i enter the page I tried the method in doucment $(document).ready(function() { $('#myModal').modal("hide"); } ); but not working as well. Thank you

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  • Possibly simple PHP/MYSQL issue with retrieving and showing data

    - by envoys
    I have been racking my brains over this for a while now. Here is the data i have in the sql data base as an example: ID | TYPE | DATA 1 | TXT | TEST 2 | PHP | php 3 | JS | JAVASCRIPT That is just an example, there are multiple listing for TXT, PHP and JS throughout the table. What I want to do is retrive all the data and display it all into separate drop down/select boxes. Meaning, select box one would list all data with type TXT, select box two would list all data with type PHP and select box 3 would list all data with type JS. The only way I have came about doing this is doing individual sql queries for each different type. I know there is a way to do it all in 1 query and then display it the way I want to but I just can't seem to figure out how and I know its going to drive me nuts when someone helps and I see just how they did it. Thanks for the input.

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  • jquery toggle did not work properly...

    - by pradeep
    function advanced_search() { $("#advanced_link").toggle( function(){ $('#advanced_link').text('Hide - Advanced Search'); $('.advanced_search').show(); }, function(){ $('#advanced_link').text('Show - Advanced Search'); $('.advanced_search').hide(); }); } this code worked for me..but when i tried to use the css property like function advanced_search() { $("#advanced_link").toggle( function(){ $('#advanced_link').text('Hide - Advanced Search'); $('.advanced_search').css('display','inline'); }, function(){ $('#advanced_link').text('Show - Advanced Search'); $('.advanced_search').css('display','none'); }); } it did not work...is there any thing wrong in second code...??

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  • my DetailViewController has text field. It appears empty at my first tap after that ...

    - by ahmet732
    I have a table view which has full of items getting from my database. I open my app. I tap one of my items in table view, then DetailViewController that has only text field does not display anything it is empty. But when I go back to table view then tap any other item again , at this time it displays value what I wanted to display.. It does it for my only first tap.. I have no errors and warnings.. What am i missing?

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