Variable not implementing correctly from if statement
- by swiftsly
I have an if statement that is supposed to set the variable $pc162v to a link specified in the MySQL table if content exists in the $vid column of the row. The problem is, the PHP is detecting that there's a link in the MySQL, but isn't setting the $pc162v variable correctly.
Here's the variable declarations:
$pc162v = "";
$vid162 = '<embed width="420" height="236" src="'.$pc162v.'" type="application/x-shockwave-flash"></embed>';
Here's the section of the if statement:
if (empty($row[7])) {
$vid162 = '';
}
else {
$pc162v = $row[7];
}
In my web browsers, the part of the code where the variable $vid162 is used, shows up as the following:
<embed width="420" height="236" src="" type="application/x-shockwave-flash">
I have also tried setting $vid162 to:
<embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"></embed>
and that just makes the code in my web browser:
<embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash">
Hope someone has a solution! Thanks in advance.
