micro controller - Page 372

In RoR, is there an easy way to prevent the view from outputting <p> tags?

- by dt

I'm new to Ruby and Rails and I have a simple controller that shows an item from the database in a default view. When it is displaying in HTML it is outputting <p> tags along with the text content. Is there a way to prevent this from happening? I suppose if there isn't, is there at least a way to set the default css class for the same output in a statement such as this: <% @Items.each do |i| %> <%= i.itemname %> <div class="menu_body"> <a href="#">Link-1</a> </div> <% end %> So the problem is with the <%= i.itemname %> part. Is there a way to stop it from wrapping it in its own <p> tags? Or set the css class for the output? Thanks!

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Magento - save quote_address on cart addAction using observer

- by Byron

I am writing a custom Magento module that gives rate quotes (based on an external API) on the product page. After I get the response on the product page, it adds some of the info from the response into the product view's form. The goal is to save the address (as well as some other things, but those can be in the session for now). The address needs to be saved to the quote, so that the checkout (onestepcheckout, free version) will automatically fill those values in (city, state, zip, country, shipping method [of which there are 3]) and load the rate quote via ajax (which it's already doing). I have gone about this by using an Observer, and watching for the cart events. I fill in the address and save it. When I end up on the cart page or checkout page ~4/5 times the data is lost, and the sql table shows that the quote_address is getting save with no address info, even though there is an explicit save. The observer method's I've used are: checkout_cart_update_item_complete checkout_cart_product_add_after The code saving is: (I've tried this with the address, quote and cart all not calling save() with the same results, as well as not calling setQuote() $quote->getShippingAddress() ->setCountryId($params['estimate_to_country']) ->setCity($params['estimate_to_city']) ->setPostcode($params['estimate_to_zip_code']) ->setRegionId($params['estimate_to_state_code']) ->setRegion($params['estimate_to_state']) ->setCollectShippingRates(true) ->setShippingMethod($params['carrier_method']) ->setQuote($quote) ->save(); $quote->getBillingAddress() ->setCountryId($params['estimate_to_country']) ->setCity($params['estimate_to_city']) ->setPostcode($params['estimate_to_zip_code']) ->setRegionId($params['estimate_to_state_code']) ->setRegion($params['estimate_to_state']) ->setCollectShippingRates(true) ->setShippingMethod($params['carrier_method']) ->setQuote($quote) ->save(); $quote->save(); $cart->save(); I imagine there's a good chance this is not the best place to save this info, but I am not quite sure. I was wondering if there is a good place to do this without overriding a whole controller to save the address on the add to cart action. Thanks so much, let me know if I need to clarify

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where to store temporary data in MVC 2.0 project

- by StuffHappens

Hello! I'm starting to learn MVC 2.0 and I'm trying to create a site with a quiz: user is asked a question and given several options of answer. If he chooses the right answer he gets some points, if he doesn't, he looses them. I tried to do this the following way public class HomeController : Controller { private ITaskGenerator taskGenerator = new TaskGenerator(); private string correctAnswer; public ActionResult Index() { var task = taskGenerator .GenerateTask(); ViewData["Task"] = task.Task; ViewData["Options"] = task.Options; correctAnswer= task.CorrectAnswer; return View(); } public ActionResult Answer(string id) { if (id == correctAnswer) return View("Correct") return View("Incorrect"); } } But I have a problem: when user answers the cotroller class is recreated and I loose correct answer. So what is the best place to store correct answer? Should I create a static class for this purpose? Thanks for your help!

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Cakephp 1.3, Weird behavior on firefox when using $this->Html->link ...

- by ion

Greetings, I am getting a very weird and unpredictable result in firefox when using the following syntax: $this->Html->link($this->Html->div('p-cpt',$project['Project']['name']) . $this->Html->div('p-img',$this->Html->image('/img/projects/'.$project['Project']['slug'].'/project.thumb.jpg', array('alt'=>$project['Project']['name'],'width'=>100,'height'=>380))),array('controller' => 'projects', 'action' => 'view', $project['Project']['slug']),array('title' => $project['Project']['name'], 'escape' => false),false); OK I know it is big but bear with me. The point is to get the following output: <a href="x" title="x"> <div class="p-ctp">Name</div> <div class="p-img"><img src="z width="y" height="a" alt="d" /></div> </a> I'm not sure if this validates correctly both on cakephp and html but it works everywhere else apart from firefox. You can actually see the result here: http://www.gnomonconstructions.com/projects/browser To reproduce the result use the form with different categories and press search. At some point it will happen!! Although most of the time it renders the way it should, sometimes it produces an invalid output like that: <a href="x" title="x"></a> <div class="p-cpt"> <a href="x" title="x">name</a> </div> <div class="p-img"> <a href="x" title="x"><img src="x" width="x" height="x" alt="x" /></a> </div> Looks like it repeats the link inside each element. To be honest the only reason I used this syntax was because cakephp encourages it. Any help will be much appreciated :)

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understanding the ORM models in MVC

- by fayer

i cant fully understand the ORM models in MVC. so i am using symfony with doctrine. the doctrine models are created. does this mean that i don't have to create any models? are the doctrine models the only models i need? where should i put the code that uses the doctrine models: eg. $phoneIds = array(); $phone1 = new Phonenumber(); $phone1['phonenumber'] = '555 202 7890'; $phone1->save(); $phoneIds[] = $phone1['id']; $phone2 = new Phonenumber(); $phone2['phonenumber'] = '555 100 7890'; $phone2->save(); $phoneIds[] = $phone2['id']; $user = new User(); $user['username'] = 'jwage'; $user['password'] = 'changeme'; $user->save(); $user->link('Phonenumbers', $phoneIds); should this code be in the controller or in another model? and where should i validate these fields (check if it exists in database, that email is email etc)? could someone please shed a light on this. thanks.

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C#: Determine Type for (De-)Serialization

- by dbemerlin

Hi, i have a little problem implementing some serialization/deserialization logic. I have several classes that each take a different type of Request object, all implementing a common interface and inheriting from a default implementation: This is how i think it should be: Requests interface IRequest { public String Action {get;set;} } class DefaultRequest : IRequest { public String Action {get;set;} } class LoginRequest : DefaultRequest { public String User {get;set;} public String Pass {get;set;} } Handlers interface IHandler<T> { public Type GetRequestType(); public IResponse HandleRequest(IModel model, T request); } class DefaultHandler<T> : IHandler<T> // Used as fallback if the handler cannot be determined { public Type GetRequestType() { return /* ....... how to get the Type of T? ((new T()).GetType()) ? .......... */ } public IResponse HandleRequest(IModel model, T request) { /* ... */ } } class LoginHandler : DefaultHandler<LoginRequest> { public IResponse HandleRequest(IModel mode, LoginRequest request) { } } Calling class Controller { public ProcessRequest(String action, String serializedRequest) { IHandler handler = GetHandlerForAction(action); IRequest request = serializer.Deserialize<handler.GetRequestType()>(serializedRequest); handler(this.Model, request); } } Is what i think of even possible? My current Solution is that each handler gets the serialized String and is itself responsible for deserialization. This is not a good solution as it contains duplicate code, the beginning of each HandleRequest method looks the same (FooRequest request = Deserialize(serializedRequest); + try/catch and other Error Handling on failed deserialization). Embedding type information into the serialized Data is not possible and not intended. Thanks for any Hints.

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STI and accepts_nested_attributes_for in rails

- by ryanshackintosh

I have models as follows: class Entity < ActiveRecord::Base has_many :addresses accepts_nested_attributes_for :addresses, :reject_if => lambda { |a| a[:label].blank?} , :allow_destroy => true end class Client < Entity before_save :set_type private def set_type self.type = "Client" end end class Address < ActiveRecord::Base belongs_to :entity end I have recently implemented accepts_nested_attributes_for on the /clients/new form, as follows: <% form_for(@client, :html => {:class => 'form'}) do |f| -%> <%= f.label :name %> <%= f.text_field :name -%> <%= f.label :phone %> <%= f.text_field :phone %> <% f.fields_for :addresses do |a| %> <%= a.label :street %> <%= a.text_field :street%> <%= a.label :city %> <%= a.text_field :city %> <% end %> <% end %> And my controller as follows: class ClientsController < ApplicationController before_filter :load_client , :except => [:index, :new, :create, :render_clients] def new @client = Client.new @client.addresses.build end def create @client = Client.new(params[:client]) if @client.save flash[:notice] = 'Client has been successfully added' redirect_to @client else render :action => 'new' end end The issue is that when the record is saved it gives an error stating: "Entity can't be blank" I assume it is something to do with the fact that a 'Client' and not an 'Entity' is being added. Can anyone point me in the right direction?

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Still some questions about USB

- by b-gen-jack-o-neill

Hi, few days ago I asked here about implementing USB. Now, If I may, would like to ask few more questions, about thing I dind´t quite understood. So, first, If I am right, Windows has device driver for USB interface, for the physical device that sends and receives communication. But what this driver offers to system (user)? I mean, USB protocol is made so its devices are adressed. So you first adress device than send message to it. But how sophisticted is the device controller (HW) and its driver? Is it so sophisticated that it is a chip you just send device adress and data, and it writes the outcomming data out and incomming data to some internal register to be read, or thru DMA directly to memory? Or, how its drivers (SW) really work? Does its driver has some advanced functions like send _data to _device? Becouse I somewhat internally hope there is a way to directly send some data thru USB, maybe by calling USB drivers itself? Is there any good article, tutorial you know about to really explain how all this logic works? Thanks.

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paginate the class

- by small

please help me with pagination of this method my method is this one controller # def show @topic = Topic.find(params[:id]) @posts = @topic.posts.find(:all ,:order=> 'id') end views # %div{:style=>"margin: 0 auto;"} %table.sortable.style2{:cellpadding=>5} %thead %tr %td{:width => "25%",:align => "center",:style => "font-weight: bold;"}Posted By %td{:width => "75%",:style => "font-weight: bold;"}Comments %tbody - for post in @posts %tr %td{:align => "center"} &nbsp %div{:width=>"5px" , :style=>"border: 1px solid rgb(232, 232, 232);background-color: rgb(248, 248, 248);width: 60px; height:60px;" } - if post.posted_by.image = image_tag(post.posted_by.image.public_filename(),:width => "60px", :height => "60px",:align=>"center") %div{:style => "font-weight: bold; font-style: italic;"} = post.posted_by ? post.posted_by.firstname : "<em>Unknown User</em>" %br %div{:style => "font-style: italic;"} Posted on = post.created_at.strftime('%d of %B %Y ') = post.created_at.strftime('at %H:%M') %td{:valign => "top"} =post.body

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Extended Zend_Db_Table_Row_Abstract does not return values

- by WesleyE

Hi, I'm quite new to Zend and the database classes from it. I'm having problems mapping a Zend_Db_Table_Row_Abstract to my rows. The problem is that whenever I try to map it to a class (Job) that extends the Zend_Db_Table_Row_Abstract class, the database data is not receivable anymore. I'm not getting any errors, trying to get data simply returns null. Here is my code so far: Jobs: class Jobs extends Zend_Db_Table_Abstract { protected $_name = 'jobs'; protected $_rowsetClass = "Job"; public function getActiveJobs() { $select = $this->select()->where('jobs.jobDateOpen < UNIX_TIMESTAMP()')->limit(15,0); $rows = $this->fetchAll($select); return $rows; } } Job: class Job extends Zend_Db_Table_Row_Abstract { public function getCompanyName() { //Gets the companyName for this row (Is on another table), just for example } } Controller: $oJobs = new Jobs(); $aActiveJobs = $oJobs->getActiveJobs(); foreach ($aActiveJobs as $value) { var_dump($value->jobTitle); } When I remove the "protected $_rowsetClass = "Job";" line, so that the table row is not mapped to my own class, I get all the jobTitles perfectly. What am I doing wrong here? Thanks in advance, Wesley

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Using an objects date (without time) for a table header instead of an objects date and time (iphone)

- by billywilliamton

I've been working on an iphone project and have run into an issue. Currently In the table view where it displays all the objects, I use headers based on the objects datePerformed field. The only problem is that my code apparently creates a header that contains both the date and time resulting in objects not being grouped solely by their date as I intended, but rather based on their date and time. I'm not sure if it matters, but when an object is created I use a date picker to pick the date, but not the time. I was wondering if anyone could give me any suggestions or advice. Here is the code where i set up the fetchedResultsController - (NSFetchedResultsController *)fetchedResultsController { if (fetchedResultsController != nil) { return fetchedResultsController; } // Create and configure a fetch request with the Exercise entity. NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Exercise" inManagedObjectContext:managedObjectContext]; [fetchRequest setEntity:entity]; // Create the sort descriptors array using date and name NSSortDescriptor *dateDescriptor = [[NSSortDescriptor alloc] initWithKey:@"datePerformed" ascending:NO]; NSSortDescriptor *nameDescriptor = [[NSSortDescriptor alloc] initWithKey:@"name" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:dateDescriptor, nameDescriptor, nil]; [fetchRequest setSortDescriptors:sortDescriptors]; // Create and initialize the fetch results controller NSFetchedResultsController *aFetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:managedObjectContext sectionNameKeyPath:@"datePerformed" cacheName:@"Root"]; self.fetchedResultsController = aFetchedResultsController; fetchedResultsController.delegate = self; // Memory management calls [aFetchedResultsController release]; [fetchRequest release]; [dateDescriptor release]; [nameDescriptor release]; [sortDescriptors release]; return fetchedResultsController; } Here's where I set up the table header properties - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { // Display the exercise' date as section headings. return [[[fetchedResultsController sections] objectAtIndex:section] name]; } Any suggestions welcome. Thanks for your time. -Billy Williamton

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Codeigniter: validation problem

- by krike

For some reason a user can login with any password, first I thought I forgot to check for the password but I didn't... and I just cant find the problem here is the model: /*#######################################################*/ function validate() /*#######################################################*/ { $this->db->where('username', $this->input->post('username')); $this->db->where('password', md5($this->input->post('password'))); $q = $this->db->get('user_extra'); if($q->num_rows() == 1): return true; else: return false; endif; }//end of function validate() The controller /*#######################################################*/ function validate_credentials() /*#######################################################*/ { $this->load->model('membership_model'); $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Name', 'trim|required'); $this->form_validation->set_rules('password', 'password', 'trim|required'); if(!$this->membership_model->validate()): $this->form_validation->set_message('check_login', 'Login not correct, please try again.'); endif; if($this->form_validation->run() == FALSE): $this->index(); else: $this->membership_model->userinfo($this->input->post('username')); //should redirect to last view redirect($this->session->flashdata('redirect_url')); endif; }// end of validate_credentials()

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Easier way to populate form data and validation data in Code Igniter?

- by John

I'm new to code igniter. I'm following the form validation tutorial found at: http://www.codeignitor.com/user_guide/libraries/validation.html I find I am typing too much in the view to get the form to re-populate. For example, here's what one of my INPUT fields look like: <input type="text" name="email" value="<?=$this->validation->email ? $this->validation->email : $array_db_values['email'] ?>" /> Basically, when the form first loads, it should show a value from the database. If the user alters the value and it fails validation, then the form should post the erroneously submitted value. Does code igniter have a "cleaner" way of rendering this kind of output? Otherwise, I'm going to do something like this in my controller: $array_db_values = getdbresults(); if($_POST['submit']) foreach($_POST as $key=>$val) $array_db_values[$key] = $val; That way, if postback data exists, it will always override database values. Then input fields in my view can simply be: <input type="text" name="email" value="<?=$array_db_values['email'] ?>" /> Is there a better/native CI way to handle this scenario?

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BlackBerry 5.0 causing full menu to show on navigationClick

- by jwadsack

I have a BlackBerry app that is built for 4.5.x SDK. The first page of the app shows a list of fields and each field can be highlighted and clicked. The click action shows a new view with additional information about the field. This all works fine in 4.5, 4.6 and 4.7 and on the sim with 5.0. On a real 9000 running 5.0, when clicking the trackball on an item in the list, the full menu is showing rather than the click event getting consumed (or even fired) for the field. The view is derived from MainScreen and looks something like this: public class ListView extends MainScreen { public ItemCollection list = new ItemCollection; protected void sublayout( int maxWidth, int maxHeight ) { int i = 1; while(( item == (Item)list.nextElement()) != null) { ItemField field = new ItemField(item, i++); add(field); } } } This class does not consume navigationClick, but shouldn't need to, right? The field class does consume navigationClick event: public class ItemField extends Field { protected boolean navigationClick(int status, int time) { controller.showDeal(item.id, Session.current); return true; } } Is there something that changed in 5.0 that I need to add to have this app work the same for all platforms?

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"render as JSON" is display JSON as text instead of returning it to AJAX call as expected

- by typoknig

I'm navigating to the index action of MyController. Some of the on the index page I'm making an AJAX call back to myAction in MyController. I expect myAction action to return some data as JSON to my AJAX call so I can do something with the data client side, but instead of returning the data as JSON like I want, the data is being displayed as text. Example of my Grails controller: class MyController { def index() { render( view: "myView" ) } def myAction { def mapOfStuff = [ "foo": "foo", "bar":] render mapOfStuff as JSON } } Example of my JavaScript: $( function() { function callMyAction() { $.ajax({ dataType: 'json', url: base_url + '/myController/myAction', success: function( data ) { $(function() { if( data.foo ) { alert( data.foo ); } if( data.bar ) { alert( data.bar ); } }); } }); } }); What I expect is that my page will render, then my JavaScript will be called, then two alerts will display. Instead the JSON array is displayed as text in my browser window: {"foo":"foo","bar":"bar"} At this point the last segment of the URL in my address bar is myAction and not index. Now if I manually enter the URL of the index page and press refresh, all works as expected. I have half a dozen AJAX calls I do the exact same way and none of them are having problems. What is the deal here? UPDATE: I have noticed something. When I set a break point in the index action of MyController and another one in the myAction action, the break point in myAction gets hit BEFORE the break point in index, even though I am navigating to the index. This is obviously closer to the root cause of my problem, but why is it happening?

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Make a router like zend

- by Vahan

I have a url http://*.com/branch/module/view/id/1/cat/2/etc/3. It becomes. array ( 'module'=>'branch', 'controller'=>'module', 'action'=>'view' ); next I need to get the params. Ihave this array. /*function getNextSegments($n,$segments) { return array_slice ( $q = $this->segments, $n + 1 ); } $params = getNextSegments(3); */ array ( 0 => 'id', 1 => '1', 2 => 'cat', 3 => '2', 4 => 'etc', 5 => '3' );//params And i wanna convert it to this one: array ( 'id'=1, 'cat'=2, 'etc'=3, ); How i can do this using php function. I know I can do using for or foreach, but I think php has such function , but i cant find it :(. Thank you. class A { protected function combine($params) { $count = count ( $params ); $returnArray = array (); for($i = 0; $i < $count; $i += 2) { $g = $i % 2; if ($g == 0 or $g > 0) { if (isset ( $params [$i] ) and isset ( $params [$i + 1] )) $returnArray [$params [$i]] = $params [$i + 1]; } } return $returnArray; } } This works normaly. If anybody has better login for this please help. Thank you again.

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using action helpers in Zend Framework 1.8

- by Nasser

Hi am starting off with Zend Framework and have a question about action helpers. My first application is a simple authentication system (following a tutorial from a book). The registration and authentication seems to work fine but the redirect doesn't. I have a customer controller that has this among others: class CustomerController extends Zend_Controller_Action { // some code here...... public function authenticateAction() { $request = $this->getRequest(); if (!$request->isPost()) { return $this->_helper->redirector('login'); } // Validate $form = $this->_forms['login']; if (!$form->isValid($request->getPost())) { return $this->render('login'); } if (false === $this->_authService->authenticate($form->getValues())) { $form->setDescription('Login failed, please try again.'); return $this->render('login'); } return $this->_helper->redirector('index'); } the authenticate url is http://localhost/customer/authenticate and this seems to work fine but it does not redirect. After authentication I get a blank page which looks like its taking me to the index and just sits there. I tried using '/index' instead but that did not help either. Do I need to do anything special to make the redirector helper work? I have a logout action which behaves the same.

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Render different view depending on the type of the data

- by Miau

Hi there So lets suppose we have an action in a controller that looks a bit like this: public ViewResult SomeAction(int id) { var data = _someService.GetData(id); ... //create new view model based on the data here return View(viewModel); } What I m trying to figure out is the best way to render a diferent view based on the type fo the data. the "_someService.GetData method returns an data that knows its out type (ie not only you can do typeof(data) but also you can do data.DataType and you ll get an enum value so I could achieve what I m trying to do doing something kinda like this public ViewResult SomeAction(int id) { var data = _someService.GetData(id); //I m mapping fields to the viewModel here var viewModel = GetViewModel(data); swtich(data.DataType) case DataType.TypeOne: return View("TypeOne", viewModel); break; ... } But this does not seem to be the nicest way, (I dont event know if it would work) Is this the way to go? Should I use some sort of RenderPartial Aproach? after all , waht will change in the view is mostly the order of the data (ie the rest of the view would be quite similar) Cheers

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How to set background color of tableView

- by Praveen

Hi Folks, I have tried all the way but could not succeed to set backgroundColor of TableView. setting tableView.backgroundColor and/or cell.backgroundColor to clearColor didn't work when the parent view controller was UIViewContoller. My nib file structure is FileOwner View UITableView (Note: i set the TableView to groupedTable section) First attempt, I created the UIView in the code viewDidLoad UIView *view = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 160, 300)] autorelease; [view setBackgroundColor:UIColor blueColor]; // color it just to see if it is created at the right place [self.tableView sendSubViewToBack:view]; It works but it hides the content of cell. I am able to see the content of header but not cell content. (But when i change the co-ordinate of view(0,150,160,300) then i am able to see the cell's content but then it loose the backgroundColor of tableview. Second attempt, I created the imageView View ImageView UITableView and set the self.tableView.backgroundColor = [UIColor clearColor]; but did not work. I googled but did not the peaceful answer.

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C# - Is it possible to start my project with a class instead of a form?

- by Irro

I want my project to be started through an class instead of a form, is there any way to do this? Or to be more precise is there any good way to make sure that the first class, except Program, that is started isn't a form-class. I tried to change to my class in Program.main() but it looks like Application.run() needs a ApplicationContext. I guess that I could change the Program-class to start another class and let that class start the form with Application.run() but I think that it will cause a lot of problem since I don't want the same form to be started first each time and Application.run() have to be used at least once and at most once. So I think it will be hard to keep track of if Application.run() has been used or not. Another question that might be even more important; Is this a good way to do things in .net? The reason I want to do so is because I want to create some sort of MVC project where the class I want to start with is the controller and all forms I'll use will be views.

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Replacing one image with another image through ajax makes it dissappear for a split second

- by ooo

I have the following code (asp.net-mvc, jquery) (i have simplified the example to show the issue) where i want to click on an image and have it replaced with another image. This works fine but the first time i click it, the original image disappears (for a split second) before the other image shows up. After that it works seamlessly. Is there any way to eliminate this quirk so there is not split second where no image is shown? Here is my controller code: public ActionResult UpdateFavoriteExercise(int id, string toggle) { if (toggle == "off") { return Content("<img toggle='off' src='/images/vote-favorite-off1.png' border=0'>"); } return Content("<img toggle='on' src='/images/vote-favorite-on1.png' border=0'>"); } Here is my jquery code: $('div.favoriteExercise').live('click', function() { var id = $(this).attr("id"); var toggle = $(this).attr("toggle"); if (toggle == 'off') { onOff = 'on'; } else { onOff = 'off'; } var url = '/Tracker/UpdateFavoriteExercise/' + id + '?toggle=' + onOff; $(this).load(url); $(this).attr("toggle", onOff); });

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Mechanize form submit not going to the correct response page, no errors as to why. Something I'm doing?

- by Zack Shapiro

I threw this all in one controller for testing purposes. My code fills out the form correctly for adding a new address to your Amazon account. There are two buttons that submit this form, one takes you to add a new address which is what I don't want, and the other is just a Save & Continue input/image. When I submit the form via that button, as I do below, the form is still on the page, filled out as I have with my code. Inspecting the page titles, they're the same. There are no discernible errors that Mechanize or Amazon spit back. Any ideas? class AmazonCrawler def initialize @agent = Mechanize.new do |agent| agent.user_agent_alias = 'Mac Safari' agent.follow_meta_refresh = true agent.redirect_ok = true end end def login # login_url = "https://www.amazon.com/ap/signin?_encoding=UTF8&openid.assoc_handle=usflex&openid.claimed_id=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.identity=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.mode=checkid_setup&openid.ns=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0&openid.ns.pape=http%3A%2F%2Fspecs.openid.net%2Fextensions%2Fpape%2F1.0&openid.pape.max_auth_age=0&openid.return_to=https%3A%2F%2Fwww.amazon.com%2Fgp%2Fcss%2Fhomepage.html%3Fie%3DUTF8%26ref_%3Dgno_yam_ya" login_url = "https://www.amazon.com/gp/css/account/address/view.html?ie=UTF8&ref_=ya_add_address&viewID=newAddress" @agent.get(login_url) form = @agent.page.forms.first form.email = "[email protected]" form.radiobuttons.first.value = "0" form.radiobuttons.last.check form.password = "my_password" dashboard = @agent.submit(form) end end class UsersController < ApplicationController def index response = AmazonCrawler.new.login form = response.forms[1] # fill out form form.enterAddressFullName == "Your Name" form.enterAddressAddressLine1 = "123 Main Street" form.enterAddressAddressLine2 = "Apartment 34" form.enterAddressCity = "San Francisco" form.enterAddressStateOrRegion = "CA" form.enterAddressPostalCode = "94101" form.enterAddressPhoneNumber = "415-555-1212" form.AddressType = "RES" new_response = form.submit( form.button_with(value: /Save.*Continue/) ) end end

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Best way and problems when using ajax tabs with an MVC PHP project

- by Jonathan

Hi, I'm building an IMDB.com like website using PHP/jQuery and a MVC approach (no OOP). I have an index.php base controller to 'rule them all' :), a controllers folder with all the controllers, a models folder and a view folder. In some pages of the website I have tabbed navigation, when the visitor clicks on one of those tabs to get more information, jQuery gets that data using the $.post or $.get method and shows it on the tab container, obviously without refreshing the page. The problem is that those pages loaded by ajax are also generated using controllers, models, and views, and the things are getting a bit complicated for someone like me ( = 'no experience'). To dynamically get the data I some times need to include a model twice, include an include in an include in an include, send information multiple times, connect with the database again, and all sort of things like that and I'm sure there is a better and prettier way to do this. I'm searching for the best approach and common methods for this. I have no experience working with a big project like this. This is a personal project so I have full control and every answer is welcome. Thanks!!!

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Java scripts conflict on my home page

- by naveen

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Zend_Controller_Router_Route_Chain more routes - more problems

- by epmspec

When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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