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  • why doesn't IE8 refresh textbox right away?(Jquery)

    - by AndrewSmith
    I have 3 radio buttons and one textbox in my page. These 3 radio controls represent corresponding choice and among them, the third one enables textbox that is disabled by default. If user clicks any one from the first twos after clicking the third, the textbox will be emptied(if user input any) and disabled again. The problem is, in IE, the textbox isn't emptied not until I click back once again on the said textbox. I've used jquery val methods as well as attr but nothing seems to work. You can see my code as follows. The very same code works just fine in Mozilla. I'm not sure why IE is having problem. m.bind_eventform = function(){ $('input[name=poster]').change(function(){ if($('input[name=poster]:checked').val()==2) $('#poster_other').removeAttr('disabled'); else if(!($('#poster_other').is(':disabled'))) { $('#poster_other').attr('disabled','disabled'); $('#poster_other').attr('value',''); //this one doesn't work $('#poster_other').val(''); //as well as this one } }); }; $(document).ready(m.bind_eventform);

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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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  • Displaying data from a linked table and displaying it as a list with HTML/PHP/MySQL

    - by user1672694
    I have three tables. students studentID | FirstName | LastName | Email | Form course CCode | Title courseenrolement courseenrolementid | studentID | ccode | complete | scode With the website, I have a page where I can view all the current enrolements and I wish to be able to view the list displaying the first name, surname and course title. I know I could do it with the following SQL (for the names): SELECT FirstName, LastName FROM student, courseenrolement WHERE courseenrolement.studentID = student.studentID But I am unsure how to get this to work using HTML/PHP. At present I only know how to display the studentID and CCode from the courseenrolement table using the following code: <ul> <?php foreach ($courseenrolements as $ce): ?> <li> <form action="" method="post"> <div> <?php htmlout($ce['studentID']); ?> <?php htmlout($ce['CCode']); ?> <input type="hidden" name="courseenrolementid" value="<?php echo $ce['courseenrolementid']; ?>"> <input type="submit" name="action" value="Edit"> <input type="submit" name="action" value="Delete"> </div> </form> </li> <?php endforeach; ?> </ul> which displays this: But I would like the names and course title. I managed to get it to show the names etc in the dropdown on the 'Add new' form, so I would assume it will be similar, but just unsure on how exactly. Thanks in advance

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  • Keeping the application state - deploy/install apk

    - by Buffalo
    I'm trying to have my application minimized when paused and then when it's resumed, it should be restored to its previous state, not recreated. This works perfectly when deploying the application on a device/emulator from Eclipse. The problem occurs when I get the apk (either from bin\ or from Project - Android tools - Export signed application package) and install it on a device with a file browser (Astro): the application is destroyed when paused and then recreated. I can call moveTaskToBack(true); in my activity, yet it will still be recreated when launching it. All the discussions around this are based on achieving the opposite: closing the application when minimizing it. Is there any way of achieving what I want?

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  • Syntactical analysis with Flex/Bison part 2

    - by Imran
    Hallo, I need help in Lex/Yacc Programming. I wrote a compiler for a syntactical analysis for inputs of many statements. Now i have a special problem. In case of an Input the compiler gives the right output, which statement is uses, constant operator or a jmp instructor to which label, now i have to write so, if now a if statement comes, first the first command (before the else) must be give out when the assignment of the if is yes then it must jump to the end because the command after the else isnt needed, so after this jmp then the second command must be give out. I show it in an example maybe you understand what i mean. Input adr. Output if(x==0) 10 if(x==0) Wait 5 20 WAIT 5 else 30 JMP 50 Wait 1 40 WAIT 1 end 50 END like so. I have an idea, maybe i can do it whith a special if statement like IF exp jmp_stmt_end stmt_seq END when the if statement is given in the input the compiler has to recognize the end ofthe statement and like my jmp_stmt in my compiler ( you have to download the files from http://bitbucket.org/matrix/changed-tiny) only to jump to the end. I hope you understand my problem.thanks.

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  • .change(function) can control two command

    - by klox
    dear all..i've a textfield, it using barcode scanner for input data..after scan it shows KD-R411ED 105X0001... I'm successful separate them into two text field use ".change(function)" $("#tags1").change(function() { var barcode; barCode=$("#tags1").val(); var data=barCode.split(" "); $("#tags1").val(data[0]); $("#tags2").val(data[1]); }); what i want is beside make them separate after ".change(function)" another script can read two character behind "KD-R411ED"..that is "ED"..this character can make a radiobutton which id="check1" are checked.. what's code which can combine with code above? this my complete code.. $("#tags1").change(function() { var barcode; barCode=$("#tags1").val(); var data=barCode.split(" "); $("#tags1").val(data[0]); $("#tags2").val(data[1]); var code = data[0].substr(data[0].length - 2); // suggested by Jan Willem B if (code =='UD') $('#check1').attr('checked','checked'); } else { if (code == 'ED') { $('#check2').attr('checked','checked'); } } and this the form <input id="check1" type="radio" class="check" name="check" onclick="addtext()" value="U" />U <input id="check2" type="radio" class="check" name="check" onclick="addtext_1()" value="E" />E the radiobutton still not response

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  • jQuery Form Validation being bypassed

    - by user1953681
    Can someone tell me what is wrong with my jQuery validation? It is not validating my form, rather, just ignoring the code resulting in no check of the inputs. Form: <form class="form" accept-charset="UTF-8" action="URL-to-complete-form" method="POST" onsubmit="return validateForm();"> <input class="form-name" type="text" placeholder="Name"></div> <input class="form-email" type="text"placeholder="Email"></div> <input style="background-color: #fc8f12;" type="submit" value="Subscribe"> </div> </form> Javascript: function validateForm() { // Validate Name var title = $(".form-name").val(); if (title=="" ||title=="Name" || title==null) { } else { alert("Please enter a name!"); } // Validate Email var email = $(".form-email").val(); if ((/(.+)@(.+){2,}\.(.+){2,}/.test(email)) || email=="" || email=="Email" || email==null) { } else { alert("Please enter a valid email"); } return false; } Thank you all for your time and help.

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  • Codeigniter: Simple ajax submit not working

    - by Kevin Brown
    jQuery: $('#welcome-message').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit({}); $(this).fadeTo(400, 0, function () { // Links with the class "close" will close parent $(this).slideUp(400); }); return false; }); Controller: function welcome_message() { if(isset($_POST['welcome_message'])) { $this-_my_private_function(); } } private function _my_private_function() { $id = $this->session->userdata('id'); $profile['welcome_message'] = '0'; $this->db->update('be_user_profiles',$profile, array('user_id' => $id)); redirect('home', 'location'); } html: <?php print form_open('home/welcome_message',array('class'=>'horizontal','id'=>'welcome-message'))?> <p> Before you can complete the assessment, you need to complete your profile. Once that's done you'll be ready! After you have completed the assessment, you will be able to view the results from your profile. </p> <input type="checkbox" value="0" name="welcome_message" checked="false"> Don't show me this again </input> <p> <input class="button submit" type="submit" class="close-box" value="Close" /> </p> <?php print form_close()?> This should be working. My hypothesis is that the data isn't being passed to the function...but I really have no idea! It works when I visit the function in the url.

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  • select failing with C program but not shell

    - by Gary
    So I have a parent and child process, and the parent can read output from the child and send to the input of the child. So far, everything has been working fine with shell scripts, testing commands which input and output data. I just tested with a simple C program and couldn't get it to work. Here's the C program: #include <stdio.h> int main( void ) { char stuff[80]; printf("Enter some stuff:\n"); scanf("%s", stuff); return 0; } The problem with with the C program is that my select fails to read from the child fd and hence the program cannot finish. Here's the bit that does the select.. //wait till child is ready fd_set set; struct timeval timeout; FD_ZERO( &set ); // initialize fd set FD_SET( PARENT_READ, &set ); // add child in to set timeout.tv_sec = 3; timeout.tv_usec = 0; int r = select(FD_SETSIZE, &set, NULL, NULL, &timeout); if( r < 1 ) { // we didn't get any input exit(1); } Does anyone have any idea why this would happen with the C program and not a shell one? Thanks!

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  • ArrayList<Int> Collections.Sort and LineNumberReader Help How to

    - by user1819551
    I have a issue i can't get it to work now let going to the point a explain in the code thanks. This is my class: what I want to do is insert the Integers sort the list and buffer writer in a column with out coma. Now I getting this: [1110018, 1110032, 1110056, 1110059, 1110063, 1110085, 1110096, 1110123, 1110125, 1110185, 1110456, 1110459] I want like this: 111xxxxx 111xxxx xxxx....... I can't do it in single array, have to be in ArrayList. This is my collecting: list.addNumbers(numbers); list.display(); This is my writer: Is buffered coma.write("\n"+list.display()); coma.flush();<br/> Here is my class: public class IdCount {<br/> private ArrayList<Integer> properNumber = new ArrayList<>(); public void addNumbers(Integer numbers) { properNumber.add(numbers); Collections.sort(properNumber); } public String display() { //(I try .toString() Not work) return properNumber.toString(); } My second issue is LineNumberReader: This is my collecting and my writing: try { Reader input = new BufferedReader( new FileReader(inputFile)); try (Scanner in = new Scanner(input)) { while (in.hasNext()) { //(More Code) asp = new LineNumberReader(input); int rom = 0; while (asp.readLine()!=null){ rom++; } System.out.println(rom); coma.write(rom); This one will not write anything an my System Print give me only 12 0 in column.

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  • How do I post a .wav file from CS5 Flash, AS3 to a Java servlet?

    - by Muostar
    Hi, I am trying to send a byteArray from my .fla to my running tomcat server integrated in Eclipse. From flash I am using the following code: var loader:URLLoader = new URLLoader(); var header:URLRequestHeader = new URLRequestHeader("audio/wav", "application/octet-stream"); var request:URLRequest = new URLRequest("http://localhost:8080/pdp/Server?wav=" + tableID); request.requestHeaders.push(header); request.method = URLRequestMethod.POST; request.data = file;//wav; loader.load(request); And my java servlet looks as follows: try{ int readBytes = -1; int lengthOfBuffer = request.getContentLength(); InputStream input = request.getInputStream(); byte[] buffer = new byte[lengthOfBuffer]; ByteArrayOutputStream output = new ByteArrayOutputStream(lengthOfBuffer); while((readBytes = input.read(buffer, 0, lengthOfBuffer)) != -1) { output.write(buffer, 0, readBytes); } byte[] finalOutput = output.toByteArray(); input.close(); FileOutputStream fos = new FileOutputStream(getServletContext().getRealPath(""+"/temp/"+wav+".wav")); fos.write(finalOutput); fos.close(); When i run the flash .swf file and send the bytearray to the server, I receive following in the server's console window:: (loads of loads of Chinese symbols) May 20, 2010 7:04:57 PM org.apache.tomcat.util.http.Parameters processParameters WARNING: Parameters: Character decoding failed. Parameter '? (loads of loads of Chinese symbols) and then looping this for a long time. It is like I recieve the bytes but not encoding/decoding them correctly. What can I do?

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  • how to determine xpaths for ajax element.

    - by Anjali
    I need to detemine xpath for element 'mainForm:queryConfigure:fetchReport'. <span id="mainForm:queryConfigure:j_id18"> <table id="mainForm:queryConfigure:j_id19" class="showReportTable" align="center"> <tbody> <tr> <td> <input id="mainForm:queryConfigure:fetchReport" type="image" src="images/show_report.gif" name="mainForm:queryConfigure:fetchReport"/> </td> </tr> </tbody> </table> </span> i tried selenium.click("//input[@id='mainForm:queryConfigure:fetchReport'][@type='image'][@src='images/show_report.gif']"); AND selenium.click("//input[@id='mainForm:queryConfigure:fetchReport']"); One more case: <div class="tabUnselectedText" align="center"> <a href="javascript:renderPage('mainForm:consoleBeanId.1','Notifications' , 'notifications.faces');">Notifications</a> </div>

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  • jquery pass value class

    - by mckenzie
    $(".hidee2").click(function() { var type = $(".st").val(); } <form action="" method="POST"><input type="hidden" class="st" value="st"><div class="button">Room Status : Accepting Reservation <br /><span><span><a class="hidee2">Book Now!</a></span></span></div></form> <form action="" method="POST"><input type="hidden" class="st" value="st2"><div class="button">Room Status : Accepting Reservation <br /><span><span><a class="hidee2">Book Now!</a></span></span></div></form> <form action="" method="POST"><input type="hidden" class="st" value="st3"><div class="button">Room Status : Accepting Reservation <br /><span><span><a class="hidee2">Book Now!</a></span></span></div></form> How do i get which book now! link user click? because i need to pass over the st value? is there any way to achieve this using jquery? currently, only st value is passed over

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  • Why do the outputs differ when I run this code using Netbeans 6.8 and Eclipse?

    - by Vimal Basdeo
    When I am running the following codes using Eclipse and Netbeans 6.8. I want to see the available COM ports on my computer. When running in Eclipse it is returning me all available COm ports but when running t in Netbeans, it does not seem to find any ports .. public static void test(){ Enumeration lists=CommPortIdentifier.getPortIdentifiers(); System.out.println(lists.hasMoreElements()); while (lists.hasMoreElements()){ CommPortIdentifier cn=(CommPortIdentifier)lists.nextElement(); if ((CommPortIdentifier.PORT_SERIAL==cn.getPortType())){ System.out.println("Name is serail portzzzz "+cn.getName()+" Owned status "+cn.isCurrentlyOwned()); try{ SerialPort port1=(SerialPort)cn.open("ComControl",800000); port1.setSerialPortParams(9600, SerialPort.DATABITS_8, SerialPort.STOPBITS_1, SerialPort.PARITY_NONE); System.out.println("Before get stream"); OutputStream out=port1.getOutputStream(); InputStream input=port1.getInputStream(); System.out.println("Before write"); out.write("AT".getBytes()); System.out.println("After write"); int sample=0; //while((( sample=input.read())!=-1)){ System.out.println("Before read"); //System.out.println(input.read() + "TEsting "); //} System.out.println("After read"); System.out.println("Receive timeout is "+port1.getReceiveTimeout()); }catch(Exception e){ System.err.println(e.getMessage()); } } else{ System.out.println("Name is parallel portzzzz "+cn.getName()+" Owned status "+cn.isCurrentlyOwned()+cn.getPortType()+" "); } } } Output with Netbeans false Output using Eclipse true Name is serail portzzzz COM1 Owned status false Before get stream Before write After write Before read After read Receive timeout is -1 Name is serail portzzzz COM2 Owned status false Before get stream Before write After write Before read After read Receive timeout is -1 Name is parallel portzzzz LPT1 Owned status false2 Name is parallel portzzzz LPT2 Owned status false2

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  • sigleton EXC_BAD_ACCESS

    - by lclaud
    Hi, so I have a class that I decleare as a singleton and in that class I have a NSMutableArray that contains some NSDictionaries with some key/value pairs in them. The trouble is it doesn't work and I dont't know why... I mean it crashes with EXC_BAD_ACCESS but i don't know where. I followed the code and it did create a new array on first add, made it to the end of the funtion ..and crashed ... @interface dataBase : NSObject { NSMutableArray *inregistrari; } @property (nonatomic,retain) NSMutableArray *inregistrari; -(void)adaugaInregistrareCuData:(NSDate *)data siValoare:(NSNumber *)suma caVenit:(BOOL)venit cuDetaliu:(NSString *)detaliu; -(NSDictionary *)raportIntreData:(NSDate *)dataInitiala siData:(NSDate *)dataFinala; -(NSArray *)luniDisponibileIntreData:(NSDate *)dataInitiala siData:(NSDate *)dataFinala; -(NSArray *)aniDisponibiliIntreData:(NSDate *)dataInitiala siData:(NSDate *)dataFinala; -(NSArray *)vectorDateIntreData:(NSDate *)dataI siData:(NSDate *)dataF; -(void)salveazaInFisier; -(void)incarcaDinFisier; + (dataBase *)shareddataBase; @end And here is the .m file #import "dataBase.h" #import "SynthesizeSingleton.h" @implementation dataBase @synthesize inregistrari; SYNTHESIZE_SINGLETON_FOR_CLASS(dataBase); -(void)adaugaInregistrareCuData:(NSDate *)data siValoare:(NSNumber *)suma caVenit:(BOOL)venit cuDetaliu:(NSString *)detaliu{ NSNumber *v=[NSNumber numberWithBool:venit]; NSArray *input=[NSArray arrayWithObjects:data,suma,v,detaliu,nil]; NSArray *keys=[NSArray arrayWithObjects:@"data",@"suma",@"venit",@"detaliu",nil]; NSDictionary *inreg=[NSDictionary dictionaryWithObjects:input forKeys:keys]; if(inregistrari == nil) { inregistrari=[[NSMutableArray alloc ] initWithObjects:inreg,nil]; }else { [inregistrari addObject:inreg]; } [inreg release]; [input release]; [keys release]; } It made it to the end of that adaugaInregistrareCuData ... ok . said the array had one object ... and then crashed

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  • How to upload files to server using JSP/Servlet?

    - by Thang Pham
    How can I upload files to server using JSP/Servlet? I tried this: <form action="upload" method="post"> <input type="text" name="description" /> <input type="file" name="file" /> <input type="submit" /> </form> However, I only get the file name, not the file content. When I add enctype="multipart/form-data" to the <form>, then request.getParameter() returns null. During research I stumbled upon Apache Common FileUpload. I tried this: FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List items = upload.parseRequest(request); // This line is where it died. Unfortunately, the servlet threw an exception without a clear message and cause. Here is the stacktrace: SEVERE: Servlet.service() for servlet UploadServlet threw exception javax.servlet.ServletException: Servlet execution threw an exception at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:637)

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  • Problem with OnSubmit in Validation plugin in jQuery

    - by novellino
    Hello, I an quite new to jQuery and I have a problem while trying to create a form. I am using the Validation plugin for validate the email (one the form's field). When I click the Submit button I want to call my own function because I want to save the data in an XML file. This is my button: (as I understood the plugin uses "submit" for understand the button) <input type="submit" name="submit" class="submit" id="submit_btn" value="Send"/> and here is the script for the validation: <script type="text/javascript"> $(document).ready(function() { //this is my form $("#contactForm").validate(); /*save the valid data in the xml*/ $(".submit").click(function() { var email = $("input#email").val(); var subject = $("input#subject").val(); var message = $("textarea#message").val(); if (email == "" || !$("#contactForm").valid()) { return false; } var dataString = 'email='+ email + '&subject=' + subject + '&message=' + message; //alert("DATA: " +dataString); $.ajax({ type: "POST", url: "SaveData.jsp", data: dataString, success: function(data){} }); return false; }); }); </script> In general it works ok but I have two basic problems. When I click the button in the beginning having all the form empty, I get no message for the field required. Also when the data are valid and I am doing the submit, the form does not become clear after the submit. If I deleted this script code, these actions are working properly but I can not save the data! Does anyone know what is wrong? Thanks a lot!

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  • iPhone 4.0 Screen Resolution and writing robust code...

    - by Magic Bullet Dave
    Does anyone know what will happen with existing apps when they run on the iPhone 4.0 in terms of the new screen resolution? I am assuming, just like developing for the iPad that there should be no hard coded screen resolutions in your code. I'd also like advice on the best way of writing robust code to work well on any device. For instance, detecting the screen resolution is not enough - on the iPad the screen is physically bigger so you can display more items on it. On the new iPhone the screen is the same physical size but higher resolution, so the likely thing is that you wont want to display more items, just higher resolution versions of them. Any help would be useful, Regards Dave EDIT: I have read the other similar posts, I guess what I really would like to know is what is the recommended way to write code for all App Store devices in a robust way so they a) all work b) make best use of the device.

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  • Switch between speakerphone and headset on Android

    - by user210504
    Hi! I wish to know if there is a way, using which we can switch between the speaker and headset dynamically in an android application. I am using this sample code, I found online for my experiments final float frequency = 440; float increment = (float)(2*Math.PI) * frequency / 44100; // angular increment for each sample float angle = 0; AndroidAudioDevice device = new AndroidAudioDevice( ); AudioManager am = (AudioManager)getSystemService(AUDIO_SERVICE); am.setMode(AudioManager.MODE_IN_CALL); float samples[] = new float[1024]; int count = 0; while( count < 10 ) { count++; for( int i = 0; i < samples.length; i++ ) { samples[i] = (float)Math.sin( angle ) ; angle += increment; } device.writeSamples( samples ); } device.stop(); am.setMode(AudioManager.MODE_NORMAL); ---- next class public class AndroidAudioDevice { AudioTrack track; short[] buffer = new short[1024]; public AndroidAudioDevice( ) { int minSize =AudioTrack.getMinBufferSize( 44100, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_16BIT ); track = new AudioTrack( AudioManager.STREAM_VOICE_CALL, 44100, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_16BIT, minSize, AudioTrack.MODE_STREAM); track.play(); } public void writeSamples(float[] samples) { fillBuffer( samples ); track.write( buffer, 0, samples.length ); } private void fillBuffer( float[] samples ) { if( buffer.length < samples.length ) buffer = new short[samples.length]; for( int i = 0; i < samples.length; i++ ) buffer[i] = (short)(samples[i] * Short.MAX_VALUE);; } public void stop() { track.stop(); } } As per my understanding this should play audio on headset, because we have not enabled the speaker phone. However, the audio is playing on the speaker phone. 1 Am I doing something wrong here? 2 What would be a way to switch between internal speaker and speaker phone dynamically for same code peice Any help will be appreciated.

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  • How to insert an element between the two elements dynamically?

    - by Harish
    I am using a table, in which there are buttons, on button click i want the new TR element to be inserted between the two TR or at the end of the TR... my code goes here <table> <tbody> <tr> <td> <input type="submit" value="Add" onclick="addFunction()" /> </td> </tr> <tr> <td> <input type="submit" value="Add" onclick="addFunction()" /> </td> </tr> <tr> <td> <input type="submit" value="Add" onclick="addFunction()" /> </td> </tr> </tbody> </table> i want to insert new TR element next to the element which has triggered the event... NOTE: i am not using any javascript library, just plain javascript

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  • jquery how to make insertBefore work only once, on first click?

    - by user313271
    jquery $(function(){ $('#4').click(function() { $('<input name="if4" type="text" value="other price>"').insertBefore('form textarea'); }); }); html <form> < input name="name" type="text" value="Enter your name" /><br /> < input name="contacts" type="text" value="Contact info" /><br /> < select name="services"> < option value="1">1</option> < option value="2">2</option> < option value="3">3</option> < option id="4" value="Other">4</option> < /select><br /> < textarea name="description">Description</textarea><br /> < /form> And one more question about it, when i press on option number 4 two time,there appears 2 new fields, is there any way how to fix it, that new field appear only 1 time, after first click ?

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  • iPhone OS: Rotate just the button images, not the views

    - by Jongsma
    Hi, I am developing an iPad application which is basically a big drawing canvas with a couple of button at the side. (Doesn't sound very original, does it? :P) No matter how the user holds the device, the canvas should remain in place and should not be rotated. The simplest way to achieve this would be to support just one orientation. However, I would like the images on the buttons to rotate (like in the iPhone camera app) when the device is rotated. UIPopoverControllers should also use the users current orientation (and not appear sideways). What is the best way to achieve this? (I figured I could rotate the canvas back into place with an affineTransform, but I don't think it is ideal.) Thanks in advance!

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  • ImageAdapter and ListView (java.lang.OutOfMemoryError: bitmap size exceeds VM budget)

    - by theDude
    Hi, I'm using ListView to display images which I provide through an ImageAdapter class. it works great on my device (and on many other devices which I tested it on), but somehow when I'm using the emulator and I'm long-pressing the up/down button - I'm getting an outOfMemory error after 10-15 seconds. I tried clearing cache, canceling cache, etc. - nothing helped. I know this crash is pretty rare (i couldn't reproduced it on any "real" device), but I can see on DDMS that "GC freed" are getting bigger during that long press and I can't find a way to clear them. Any help will be appreciated, Tnx.

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  • Reading only one row from table in model binder

    - by user281180
    I am filling a table dynamically. I can see the table filled with 3 rows, but in my model binder I can read only one value. How can I solve this problem? My code is as follows: function AddTableRow(jQtable, value, text){ var count = 0; jQtable.each(function() { var $table = $(this); var tds = '<tr>'; tds += '<td>' + '<input type="text" value = ' + text + ' disabled ="disabled" style="width:auto"/>' + '<input type="hidden" name="projectList[' + count + '].ID" value = ' + value + ' /></td>' + '<td><input type="button" value="Remove"/></td>'; tds += '</tr>'; if ($('tbody', this).length > 0) { $('tbody', this).append(tds); } else { $(this).append(tds); } count++;}); } function ReadSelectedProject() { $("#Selected option").each(function() { AddTableRow($('#projectTable'), $(this).val(), $(this).text()); }); }

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