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  • How to use Many to Many in Rails?

    - by Newbie
    Hello! In my project, I have users and quests. One User can join multiple quests and one quest can have multiple users. So I created a table called questing, containing the user_id and the quest_id. In my user.rb I did following: require 'digest/sha1' class User < ActiveRecord::Base has_many :questings has_many :quests ,:through =>:questings ... My Quest.rb: class Quest < ActiveRecord::Base has_many :questings has_many :users ,:through =>:questings ... My Questing.rb: class Questing < ActiveRecord::Base belongs_to :quest belongs_to :user end Now I want to create a link or button on my /quests/show.html.erb, calling an action in my controller, which will create the relationship between user and quest. So, in my quest_controller I did: def join_quest @quest = Quest.find(params[:id]) puts '************************' puts 'join quest:' + @quest.id puts '************************' respond_to do |format| format.html { redirect_to(@quest) } format.xml { head :ok } end end and in my show.html.erb I did: <%= link_to 'join this quest!!!', :action => :join_quest %> Now, clicking on this link will cause an error like: Couldn't find Quest with ID=join_quest and the url points to */quests/join_quest* instead of */quests/1/join_quest* Now my questions: Is my quests_controller the right place for my join_quest action, or should I move it to my users_controller? Why do I get this error? How to solve it? What do I have to write in my join_quest action for saving the relationship? On my /users/show.html.erb I want to output all quests the user joined. How to do this? I have to get all this quests from my relationship table, right? How? I hope you can help me! THX!

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  • Positioning objects in views during re-orientation in iPad

    - by Arni
    iPad Gurus: Apple wants us to support all orientations. I take that to mean that a particular layout should either rotate so that all objects are positioned relatively the same OR, if that doesn't look good, then they ought to be repositioned, OR two views ought to be designed and built. If I rely on the built-in rotation mechanism, the objects either get resized or they straddle the edge of the page in one orientation or the other, or they disappear from view altogether. I can't seem to find the right settings to get the objects to align clearly so they are seen in each orientation. Repositioning leads to a lot of if statements in the View Controller. So I don't think Apple had that in mind. I tried replacing views and even view controllers in "willRotateToInterfaceOrientation" method, but that either causes crashes or the portrait views end up in landscape unexpectedly and vv. Moreover, two view controllers means double the coding for the same view. There must be proper way to handle orientation changes, but I have searched the internet and documentation and sample code in vain for something that works. How is this done properly? Thanks!

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  • Passing user_id, site_id, and question_id to same table on create...

    - by bgadoci
    I can't seem to figure out how to do this. I am trying to pass four different variables to a single table. To be more specific I am trying to create a "like" in a likes table that also captures the site_id (like an answer), user_id, and the question_id. Here is the set up. class Like < ActiveRecord::Base belongs_to :site belongs_to :user belongs_to :question end I will spare you the reverse, has_many associations but they are there. Here is the likes controller where I think the problem is. class LikesController < ApplicationController def create @user = current_user @site = Site.find(params[:site_id]) @like = @site.likes.create!(params[:like]) @like.user = current_user @like.save respond_to do |format| format.html { redirect_to @site} format.js end end end This code successfully passes the like and site_id but after many different variations of trying I can't get it to pass the question id. Here is my form: /views/sites/_site.html.erb (though the partial is being displayed in the /views/questions/show.html.erb file). <% remote_form_for [site, Like.new] do |f| %> <%= f.hidden_field :site_name, :value => "#{site.name}" %> <%= f.hidden_field :ip_address, :value => "#{request.remote_ip}" %> <%= f.hidden_field :like, :value => "1" %> <%= submit_tag "^" , :class => 'voteup' %> <% end %>

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  • validation before ajax form submission

    - by ZX12R
    How do i introduce validation before remote_form_for submits? I have javascript function called validateForm(). I am able to call it before the AJAX request process. I tried to use return false and event.preventDefault. But there seems to be no effect. Here is what my code looks like <% remote_form_for :customer, :update =>"uxScreenLoaderDiv", :url => {:action => "login", :controller => "site"}, :html => {:id => "uxLoginForm"}, :onsubmit => "validateForm(event)" do |f| %> User name : <%= f.text_field "uxUserName", :class => "TextBox", :style => "width:100px;" %>&nbsp;* &nbsp;Password : <%= f.password_field "uxPassword", :class => "TextBox", :style => "width:100px;" %>&nbsp;* <%= f.submit "Go!", :class => "Button-Simple", :id => "uxSubmitButton" %> <% end %> the javascript function is simple as follows function validateForm(event){ return false; //event.preventDefault(); }

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  • Spring MessageSource not being used during validation

    - by Jeremy
    I can't get my messages in messages.properties to be used during Spring validation of my form backing objects. app-config.xml: <bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource"> <property name="basename" value="messages" /> </bean> WEB-INF/classes/messages.properties: NotEmpty=This field should not be empty. Form Backing Object: ... @NotEmpty @Size(min=6, max=25) private String password; ... When I loop through all errors in the BindingResult and output the ObjectError's toString I get this: Field error in object 'settingsForm' on field 'password': rejected value []; codes [NotEmpty.settingsForm.password,NotEmpty.password,NotEmpty.java.lang.String,NotEmpty]; arguments [org.springframework.context.support.DefaultMessageSourceResolvable: codes [settingsForm.password,password]; arguments []; default message [password]]; default message [may not be empty] As you can see the default message is "may not be empty" instead of my message "This field should not be empty". I do get my correct message if I inject the messageSource into a controller and output this: messageSource.getMessage("NotEmpty", new Object [] {"password"}, "default empty message", null); So why isn't the validation using my messages.properties? I'm running Spring 3.1.1. Thanks!

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  • better way of showing File Upload Errors?

    - by coure06
    Model: public class EmailAttachment { public string FileName { get; set; } public string FileType { get; set; } public int FileSize { get; set; } public Stream FileData { get; set; } } public class ContactEmail: IDataErrorInfo { public string Name { get; set; } public string Email { get; set; } public string Message { get; set; } public EmailAttachment Attachment { get; set; } public string Error { get { return null; } } public string this[string propName] { get { if (propName == "Name" && String.IsNullOrEmpty(Name)) return "Please Enter your Name"; if (propName == "Email"){ if(String.IsNullOrEmpty(Email)) return "Please Provide an Email Address"; else if(!Regex.IsMatch(Email, ".+\\@.+\\..+")) return "Please Enter a valid email Address"; } if (propName == "Message" && String.IsNullOrEmpty(Message)) return "Please Enter your Message"; return null; } }} And my controller file [AcceptVerbs(HttpVerbs.Post)] public ActionResult Con(ContactEmail ce, HttpPostedFileBase file) { return View(); } Now the Problem From the form i am getting Name,Email, Message and uploaded file. I can get validation errors automatically for Name,Email,Message using public string this[string propName]. How can i show validation errors if Attachment.FileSize 10000? If i write its code in public string this[string propName] i alwasy getting Attachment null. How can i fill Attachment Object of ContactEmail so that i can manage all errors on same place?

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  • ViewController doesn't get released

    - by ObjectiveFlash
    Every time I turn the page in my app, I am removing and releasing the previous viewController - but for some reason it is still in memory. I know this, because after using the app for a while, I get 47 memory warnings - one from each view controller - if I had opened 47 pages before the memory warning occurred. I get 60 memory warnings if I had opened 60 pages before the memory warning occurred. And so on... This is the code that runs from page to page: UIViewController *nextController; Class nextClass = [pageClasses objectAtIndex:(currentPageIndex - 1)]; nextController = [[nextClass alloc] initWithNibName:[pageNibs objectAtIndex:(currentPageIndex - 1)] bundle:nil]; [nextController performSelector:@selector(setDelegate:) withObject:self]; [currentPageController.view removeFromSuperview]; [self.view addSubview:nextController.view]; [currentPageController release]; currentPageController = nextController; [currentPageController retain]; [nextController release]; Can anybody point to any issues they see? Thanks so much!

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  • How can i get my delete messages function just appear for the user's own messages left on their friends page?

    - by Hannah_B
    I had been working on this trying the delete message button to work on my own profile page of my site. When I delete a message left by a friend it not only deletes it from the screen but deletes it from the database. The messages in the database have 4 fields: message_id, from, to and message. Here is my profile view that shows how Im deleting messages from my friends: if(!empty($messages)){ foreach($messages as $message): $delete = $message['message_id']; //var_dump($message); ?> <li><?=$message['from']?> says...: "<?=$message['message']?>"(<?=anchor("home/deleteMsg/$delete", 'delete')?>)</li> //this is where the delete button appears beside messages left <?php endforeach?> <?php }else{ ?> <?php echo 'No messages left yet !!!'; }?> Here is my controller showing the deleteMsg function called: function deleteMsg($messageid) { $this->messages->deleteMsg($messageid); redirect('home'); } Here is the messages model showing the deleteMsg model itself: function deleteMsg($message_id) { $this->db->where(array('message_id' => $message_id)); $this->db->delete('messages'); } Here is my friendprofile view where I want to implement the delete message command just so the button appears for messages Ive left and I can delete them. The delete button will not appear beside other friends comments on this page: <li><?=$message['from']?> says...: "<?=$message['message']?>"</li> Now I've tried creating a new delete Message function to no success so far, am I better off doing this than calling the same function? As this didnt work either.

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  • Does anybody have any tips for managing polymorphic nested resources in Rails 3?

    - by Ryan
    in config/routes.rb: resources posts do resources comments end resources pictures do resources comments end I would like to allow for more things to be commented on as well. I'm currently using mongoid (mongomapper isn't as compatible with rails3 yet as I would like), and comments are an embedded resource (mongoid can't yet handle polymorphic relational resources), which means that I do need the parent resource in order to find the comment. Are there any elegant ways to handle some of the following problems: in my controller, I need to find the parent before finding the comment. if params[:post_id] parent = Post.find(params[:post_id] else if params[:picture_id] parent = Picture.find(params[:picture_id] end which is going to get messy if I start adding more things to be commentable also url_for([comment.parent,comment]) doesn't work, so I'm going to have to define something in my Comment model, but I think I'm also going to need to define an index route in the Comment model as well as potentially an edit and new route definition. There might be more issues that I have to deal with as I get further. I can't imagine I'm the first person to try and solve this problem, are there any solutions out there to make this more manageable?

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  • Kohana 3, problem with m2m data adding

    - by Marek
    Hello I posted this on official forum but with no result. I am getting :Undefined index: enrollment error when trying to save data. My pivot model: class Model_Enrollment extends ORM { protected $_belongs_to = array('page' => array(), 'menugroup' => array()); } Model_Page protected $_has_many = array('templates' => array(), 'menugroups' => array('through' => 'enrollment')); Model_Menugroup protected $_has_many = array('menuitems' => array(), 'pages' => array('through' => 'enrollment')); //Overriden save() method in Model_Menugroup: public function save() { if (empty($this->created)) { $this->created = time(); } parent::save(); $this->reload(); if (! $this->is_global) { if (! empty($this->groupOwnerPagesId) { $page = ORM::factory('page'); foreach($this->groupOwnerPagesId as $id) { $this->add('enrollment', $page->find($id)); } } } } I did: I corrected table names in pivot model by changing them to singular I even now using the same name for pivot table / model = enrollment. The same as in tutorial. Just in case So the pivot table has name 'enrollment' and has 2 columns: page_id , menugroup_id I tried to add pk in pivot table, but it changed nothing I tried to add/remove db relation between pages/menugroups and pivot table (InnoDB) but with no luck I tried save all data in controller, but with the same bad result:( I am still getting the same error: Undefined index: enrollment in ORM line: $columns = array($this-_has_many[$alias]['foreign_key'], $this-_has_many[$alias]['far_key']); Could somebody tell me, what can be else wrong? I have no other ideas:( Kind regards

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  • Representing versions of objects with CakePHP

    - by user636901
    Hi people, Have just started to get into CakePHP since a couple of weeks back. I have some experience with MVC-frameworks, but this problem holds me back a bit. I am currently working on a model foo, containing a primary id and some attributes. Since a complete history of the changes of foo is necessary, the content of foo is saved in the table foo_content. The two tables are connected through foo_content.foo_id = foo.id, in Cake with a foo hasMany foo_content-relationship. To track the versions of foo, foo_content also contains the column version, and foo itself the field currentVersion. The version is an number incremented by one everytime the user updates foo. This is an older native PHP-app btw, to be rewritten on top of Cake. 9 times out of 10 in the app, the most recent version (foo.currentVersion) is the db-entry that need to be represented in the frontend. My question is simply: is there someway of representing this directly in the model? Or does this kind of logic simply need to be defined in the controller? Most grateful for your help!

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  • With ASP.NET MVC, what is the preferred way to Ajaxify a simple form?

    - by Swoop
    I am trying to add a simple comments/message box to a web page. When the user enters the comment and hits submit, I would like to save this message to the database and add the comment to the list displayed on the page, without refreshing the entire page. However, I am not sure of the best way to do that these days. I am using ASP.NET MVC 2. I have been trying to read up on using JQuery for this type of functionality, but I am having problems getting a full picture of the correct approach that isn't also out of date (i.e. it is using an preview version of MVC 1 or older version of JQuery). I can either find snippets of different pieces without the information of how they work together, or the information appears to be quite dated and no longer valid. Can someone point me in the right direction for something like this? Ideally, I am looking for a simple example of the JQuery code, a snippet of any key differences in an HTML form from a normal post method, and the basic method used in the MVC Controller. I need something to help the lightbulb of understanding to turn on. :) Any help would be greatly appreciated!!

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  • Sanitizing User Input with Ruby on Rails

    - by phreakre
    I'm writing a very simple CRUD app that takes user stories and stores them into a database so another fellow coder can organize them for a project we're both working on. However, I have come across a problem with sanitizing user input before it is saved into the database. I cannot call the sanitize() function from within the Story model to strip out all of the html/scripting. It requires me to do the following: def sanitize_inputs self.name = ActionController::Base.helpers.sanitize(self.name) unless self.name.nil? self.story = ActionController::Base.helpers.sanitize(self.story) unless self.story.nil? end I want to validate that the user input has been sanitized and I am unsure of two things: 1) When should the user input validation take place? Before the data is saved is pretty obvious, I think, however, should I be processing this stuff in the Controller, before validation, or some other non-obvious area before I validate that the user input has no scripting/html tags? 2) Writing a unit test for this model, how would I verify that the scripting/html is removed besides comparing "This is a malicious code example" to the sanitize(example) output? Thanks in advance.

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  • Custom bean instantiation logic in Spring MVC

    - by Michal Bachman
    I have a Spring MVC application trying to use a rich domain model, with the following mapping in the Controller class: @RequestMapping(value = "/entity", method = RequestMethod.POST) public String create(@Valid Entity entity, BindingResult result, ModelMap modelMap) { if (entity== null) throw new IllegalArgumentException("An entity is required"); if (result.hasErrors()) { modelMap.addAttribute("entity", entity); return "entity/create"; } entity.persist(); return "redirect:/entity/" + entity.getId(); } Before this method gets executed, Spring uses BeanUtils to instantiate a new Entity and populate its fields. It uses this: ... ReflectionUtils.makeAccessible(ctor); return ctor.newInstance(args); Here's the problem: My entities are Spring managed beans. The reason for this is to inject DAOs on them. Instead of calling new, I use EntityFactory.createEntity(). When they're retrieved from the database, I have an interceptor that overrides the public Object instantiate(String entityName, EntityMode entityMode, Serializable id) method and hooks the factories into that. So the last piece of the puzzle missing here is how to force Spring to use the factory rather than its own BeanUtils reflective approach? Any suggestions for a clean solution? Thanks very much in advance.

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  • Get Form Input via Ajax

    - by user3651491
    I have a jqgrid plugin which I call via Ajax. I have index.php and a getGridData.php. How will I pass form input in getGridData.php via ajax and use it in getGridData.php? I tried serialize but I can't pass or access it on getGridData.php. I need it as parameters for mysql. Here's my code. <script language="javascript" type="text/javascript"> function jgGrid() { $(document).ready(function () { $("#grid").jqGrid({ url: "inc/Controller/getGridData.php"+$("#thisForm").serialize(), data : formData, datatype: "json", mtype: "POST", colNames: ["SiteID", "TerminalID", "TransactionType", "Amount", "ServiceStatus"], colModel: [ { name: "SiteID"}, { name: "TerminalID"}, { name: "TransactionType"}, { name: "Amount"}, { name: "ServiceStatus"}, ], pager: "#pager", rowNum: 10, rowList: [10,20], sortname: "SiteID", sortorder: "asc", height: 'auto', viewrecords: true, gridview: true, caption: "" }); }); } </script> getGridData.php include('../Model/Queries.php'); $cardnumber = $_POST['cardnumber']; $transact_type = $_POST['transact_type']; $fromdate = $_POST['fromdate']; $todate = $_POST['todate']; $loyalty = new Queries(); $get_mid = $loyalty->loyaltyConn($cardnumber); $somedata = json_encode($loyalty->nposConn($get_mid, $transact_type, $fromdate, $todate)); echo $somedata;

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  • codeigniter cron job with http access

    - by user1313850
    Sorry if this is a duplicate question...I've searched around and found similar advice but nothing that helps my exact problem. And please excuse the noob questions, CRON is a new thing for me. I have a codeigniter script that scrapes the html DOM of another site and stores some of that in a database. I'd like to run this script at a regular interval. This has lead me to looking into cron jobs. The page I have is at myserver.com/index.php/update I realize I can run a cron job with curl and run this page. If I want to be a bit more secure I can put a string at the end like: myserver.com/index.php/update/asdfh2784fufds And check for that in my CI controller. This seems like it would be mostly secure, but doesn't seem like the "right" way to do things. I've looked into running CI from the command line, and can execute basic pages like: php index.php mycontroller But when I try to do: php index.php update It doesn't work. I suspect this is because it needs to use HTTP to scrape the DOM of the outside page. So, my question: How do I securely run a codeigniter script with a cron job that needs HTTP access?

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  • query not displaying proper result

    - by ravindra
    In my Rails 3 project I have the following code for My controller: class TasksController < ApplicationController def today @tasks = Task.today @task = Task.new respond_to do |format| format.html { render :text=> "Sorry , you don't have any task pending today." } format.html # new.html.erb format.xml { render :xml => @tasks } end end def this_week @tasks = Task.this_week @task = Task.new respond_to do |format| format.html { render :text => "Sorry , No content for selected period." } format.html # new.html.erb format.xml { render :xml => @tasks } end end end My model: class Task < ActiveRecord::Base def self.today Task.where(:due_date => "Date.today" , :task_status => "open").order("due_date ASC") end def self.this_week Task.where(:due_date =>"Time.now.this_week" , :task_status => "open" ).order("due_date ASC") end end Why it does not displaying anything in the relative view. Please help me. Thanks

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  • Stop lazy-loading images?

    - by Greg
    Here's the issue – I followed along with the Apple lazy-load image sample code to handle my graphical tables. It works great. However, my lazy-load image tables are being stacked within a navigation controller so that you can move in and out of menus. While all this works, I'm getting a persistent crash when I move into a table then move immediately back out of it using the "back" button. This appears to be a result of the network connections loading content not being closed properly, or calling back to their released delegates. Now, I've tried working through this and carefully setting all delegates to nil and calling close on all open network connections before releasing a menu. However, I'm still getting the error. Also – short posting my entire application code into this post, I can't really post a specific code snippet that illustrates this situation. I wonder if anyone has ideas for tasks that I may be missing? Do I need to do anything to close a network connection other than closing it and setting it to nil? Also, I'm new to debugging tools – can anyone suggest a good tool to use to watch network connections and see what's causing them to fail? Thanks!

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  • asp.net mvc getting id of button clicked

    - by mazhar kaunain baig
    <div id="4591" > <input type="text" id="Title1" name="Title1" value="a" /> <input type="submit" name="button" value="Save" /> </div> <div id="4592" > <input type="text" id="Title2" name="Title2" value="a" /> <input type="submit" name="button" value="Save" /> </div> <div id="4593" > <input type="text" id="Title3" name="Title3" value="a" /> <input type="submit" name="button" value="Save" /> </div> This is the copy paste version of the html source generated by the browser which is making it clear that i am generating the dynamic fields on the page. name in the textbox is the field in the database. After pressing the one of the save buttons how would i send the particular textbox name and value to the controller action to be updated.

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  • How to model and handle presentation DTO's to abstract from complicated domain model?

    - by arrages
    Hi I am developing an application that needs to work with a complex domain model using Hibernate. This application uses Spring MVC and using the domain objects in the presentation layer is very messy so I think I should use DTO's that go to and from my service layer so that these match what I need in my views. Now lets assume I have a CarLease entity whose properties are not simple java primitives but it's composed with other entities like Make, Model, etc public class CarLease { private Make make; Private Model model; . . . } most properties are in this fashion and they are selectable using drop down selects on the jsp view, each will post back an ID to the controller. Now considering some standard use cases: create, edit, display How would you go about modeling the presentation DTO's to be used as form backing objects and communication between presentation and service layers?? Would you create a different DTO for each case (create, edit, display), would you make DTO's for the complex attributes? if so where would you translate the ID to entity? how and where would you handle validation, DTO/Domain assembly, what would you return from service layer methods? (create, edit, get) As you can see, I now I will benefit by separating my view from the domain objects (very complex with lots of stuff I don't need.) but I am having a hard time finding any real world examples and best practices for this. I need some architecture guidance from top to bottom, please keep in mind I will use Spring MVC in case that may leverage on your anwser. thanks in advance.

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  • cakephp - form for belongsTo Model

    - by user1511579
    I createt the following model to link 2 relational tables: class Ficha extends AppModel { //public $useTable = 'ficha_seg'; var $primaryKey = 'id_ficha'; var $name = 'Ficha'; var $belongsTo = array( 'Perigo' => array( 'className' => 'Perigo', 'foreignKey' => false, 'conditions' => 'Perigo.id_fichas = Ficha.id_ficha' ) ); } Now, i have a form that requires data from the class Ficha, and then is redirected to another ctp page where i will input the data for the table "Perigos". However, since i'm still a newbie in cakephp i'm having difficult building that second form to insert the data on the table "Perigos". Here goes the code i built at the moment related to the second form: FichasController.php (the method where is it supposed to save the data on the table "Perigos": public function preencher_ficha(){ if ($this->request->is('ficha')) { $this->Ficha->create(); if ($this->Ficha->Perigo->save($this->request->data)) { $last_id=$this->Ficha->getLastInsertID(); $this->Session->setFlash('Your post has been updated '.$last_id.'.'); //$this->redirect(array('action' => 'preencher_ficha')); } else { $this->Session->setFlash('Unable to qualquer coisa your post.'); } } } The preencher_ficha.ctp file with the form: echo $this->Form->create('Ficha->Perigo', array('action' => 'index')); echo $this->Form->input('class_subst', array('label' => 'Classificação:')); echo $this->Form->input('simbolos_perigo', array('label' => 'Símbolos:')); echo $this->Form->input('frases_r', array('label' => 'Frases:')); echo $this->Form->end('Finalizar Ficha'); Here i guess the create part is wrong, but i think i have errors too in the controller part.

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  • CI + Joomla 1.5

    - by DMin
    Hi, This is something that I just cooked up with Joomla and CodeIgniter(CI). I Wrote my database intensive application in CodeIgniter and frontend is Joomla. I'm using Jumi(Joomla Extention) so I can include the CI files inside joomla to basically insert the content generated by CI into Joomla articles. Problem is, you can't include CI files directly using JUMI from joomla because CI tends to route the pages so instead of seeing your joomla page with the CI content, you be redirected to the CI page itself. I did a little work around for this : Made an additional page that just basically does cURL to the CI page - gets the data and echos it out. From jumi, I include this cURL page instead. Couple of questions: I've seen at least a few posts that CI + Joomla is difficult to do(link). 1) Do you see any glaring security issues or possible performance issues? 2) Do you know of a better way to implement this? 3) What do you think of this? Do you think this is a good way to do this? There is one component out there that plugs CI with Joomla but it requires you to have a fresh CI install. It allows only one controller & the download link is down as well.

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  • Error after redirection using CakePHP

    - by Praveen kalal
    I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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  • Adding UIView on top of all views dynamically during runtime?

    - by Easwaramoorthy Kanagaraj
    Team, I am trying to bring a menu in top of all visible views during runtime. This menu should be easily addable and removable dynamically in certain conditions. To do this, I have tried adding a button view to the UIWindow as a subview during runtime. UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [button addTarget:self action:nil forControlEvents:UIControlEventTouchDown]; [button setTitle:@"Show View" forState:UIControlStateNormal]; button.frame = CGRectMake(80.0, 210.0, 160.0, 40.0); [window addSubview:button]; [window makeKeyAndVisible]; [window bringSubviewToFront:button]; But it doesnt worked. Also I have tried to place this button in the root view controller, but no luck again. Edit - Note: This code is not from a UIViewController. I am trying to build a library this will be in that library code. Use case be like you could post NSNotification to enable and disable this menu dynamically during runtime. Please suggest. Thanks !

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  • Frame sizing of tableview within nested child controllers/subviews

    - by jwoww
    I'm a bit confused by the proper frame sizing of a table view to fit within my screen. Here's my setup of view controllers within view controllers: UITabBarController UINavigationController as one of the tab bar viewcontrollers; title bar hidden ViewController - a container view controller because I need the option to place some controls beneath the UITableView, sometimes (but not in the current scenario) UITableViewController Now, my question is what the proper frame dimensions of the UITableview should be. Here's what I've got in the ViewController viewDidLoad method. I used subtracted 49.0 (the size of the tab bar) from 480.0. However, this leaves a black bar at the bottom. 20.0 appears to do it (coincidentally?) the size of the status bar, but I don't understand why that would be. Wouldn't the true pixel dimensions of the tableview be 480-49? // MessageTableViewController is my subclass of UITableViewController MessagesTableViewController *vcMessagesTable = [[MessagesTableViewController alloc] init]; CGRect tableViewFrame = CGRectMake(0, 0, 320.0, 480.0 - 49.0); [[vcMessagesTable view] setFrame:tableViewFrame]; self.tableViewController = vcMessagesTable; [self addChildViewController:vcMessagesTable]; [[self view] addSubview:vcMessagesTable.view]; Here's how it looks:

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