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  • How to create a HTML world map with GeoDjango ?

    - by pierre-guillaume-degans
    The GeoDjango tutorial explains how to insert world borders into a spatial database. I would like to create a world Map in HTML with these data, with both map and area tags. Something like that. I just don't know how to retrieve the coordinates for each country (required for the area's coords attribute). from world.models import WorldBorders for country in WorldBorders.objects.all(): print u'<area shape="poly" title="%s" alt="%s" coords="%s" />' % (v.name, v.name, "???") Thanks !

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  • remove border of a gtk.button

    - by spanctus
    Hi, I want to remove the border of the gtk.button, but i Don't know how to do it. I tried with : button = gtk.Button() button.set_style("inner-border",0) but i have an error : the property doesn't exist. I tried too to create a new gtk.Style and use it for the button, but same error. Anyone has an idea ? Thanks

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  • Django save method

    - by Marijus
    So I have a model with a FileField for excel spreadsheet. What I need to do this add another column in this spreadsheet, in each row let user pick from a drop-down list then save it and display it in html. All the picking and uploading will happen through the admin interface. So I have figured out way how to display a spreadsheet in html, however I have no idea how to write this save method. I could really use some hints and tips..

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  • How can you dispatch on request method in Django URLpatterns?

    - by rcampbell
    It's clear how to create a URLPattern which dispatches from a URL regex: (r'^books/$', books), where books can further dispatch on request method: def books(request): if request.method == 'POST': ... else ... I'd like to know if there is an idiomatic way to include the request method inside the URLPattern, keeping all dispatch/route information in a single location, such as: (r'^books/$', GET, retrieve-book), (r'^books/$', POST, update-books), (r'^books/$', PUT, create-books),

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  • ahow can I resolve Django Error: str' object has no attribute 'autoescape'?

    - by Angelbit
    Hi have tried to create a inclusion tag on Django but don't work and return str' object has no attribute 'autoescape' this is the code of custom tag: from django import template from quotes.models import Quotes register = template.Library() def show_quote(): quote = Quotes.objects.values('quote', 'author').get(id=0) return {'quote': quote['quote']} register.inclusion_tag('quotes.html')(show_quote) EDIT: Quote class from django.db import models class Quotes(models.Model): quote = models.CharField(max_length=255) author = models.CharField(max_length=100) class Meta: db_table = 'quotes' quotes.html <blockquote id="quotes">{{ quote }}</blockquote>

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  • pyInotify performance

    - by tranimatronic
    I have a very large directory tree I am wanting pyInotify to watch. Is it better to have pyInotify watch the entire tree or is it better to have a number of watches reporting changes to specific files ? Thanks

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  • Url open encoding

    - by badc0re
    I have the following code for urllib and BeautifulSoup: getSite = urllib.urlopen(pageName) # open current site getSitesoup = BeautifulSoup(getSite.read()) # reading the site content print getSitesoup.originalEncoding for value in getSitesoup.find_all('link'): # extract all <a> tags defLinks.append(value.get('href')) The result of it: /usr/lib/python2.6/site-packages/bs4/dammit.py:231: UnicodeWarning: Some characters could not be decoded, and were replaced with REPLACEMENT CHARACTER. "Some characters could not be decoded, and were " And when i try to read the site i get: ?7?e????0*"I??G?H????F??????9-??????;??E?YÞBs????????????4i???)?????^W?????`w?Ke??%??*9?.'OQB???V??@?????]???(P??^??q?$?S5???tT*?Z

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  • how to model a follower stream in appengine?

    - by molicule
    I am trying to design tables to buildout a follower relationship. Say I have a stream of 140char records that have user, hashtag and other text. Users follow other users, and can also follow hashtags. I am outlining the way I've designed this below, but there are two limitaions in my design. I was wondering if others had smarter ways to accomplish the same goal. The issues with this are The list of followers is copied in for each record If a new follower is added or one removed, 'all' the records have to be updated. The code class HashtagFollowers(db.Model): """ This table contains the followers for each hashtag """ hashtag = db.StringProperty() followers = db.StringListProperty() class UserFollowers(db.Model): """ This table contains the followers for each user """ username = db.StringProperty() followers = db.StringListProperty() class stream(db.Model): """ This table contains the data stream """ username = db.StringProperty() hashtag = db.StringProperty() text = db.TextProperty() def save(self): """ On each save all the followers for each hashtag and user are added into a another table with this record as the parent """ super(stream, self).save() hfs = HashtagFollowers.all().filter("hashtag =", self.hashtag).fetch(10) for hf in hfs: sh = streamHashtags(parent=self, followers=hf.followers) sh.save() ufs = UserFollowers.all().filter("username =", self.username).fetch(10) for uf in ufs: uh = streamUsers(parent=self, followers=uf.followers) uh.save() class streamHashtags(db.Model): """ The stream record is the parent of this record """ followers = db.StringListProperty() class streamUsers(db.Model): """ The stream record is the parent of this record """ followers = db.StringListProperty() Now, to get the stream of followed hastags indexes = db.GqlQuery("""SELECT __key__ from streamHashtags where followers = 'myusername'""") keys = [k,parent() for k in indexes[offset:numresults]] return db.get(keys) Is there a smarter way to do this?

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  • Does urllib2.urlopen() actually fetch the page?

    - by beagleguy
    hi all, I was condering when I use urllib2.urlopen() does it just to header reads or does it actually bring back the entire webpage? IE does the HTML page actually get fetch on the urlopen call or the read() call? handle = urllib2.urlopen(url) html = handle.read() The reason I ask is for this workflow... I have a list of urls (some of them with short url services) I only want to read the webpage if I haven't seen that url before I need to call urlopen() and use geturl() to get the final page that link goes to (after the 302 redirects) so I know if I've crawled it yet or not. I don't want to incur the overhead of having to grab the html if I've already parsed that page. thanks!

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  • Removing a node from a linked list

    - by lost_with_coding
    I would like to create a delete_node function that deletes the node at the location in the list as a count from the first node. So far this is the code I have: class node: def __init__(self): self.data = None # contains the data self.next = None # contains the reference to the next node class linked_list: def __init__(self): self.cur_node = None def add_node(self, data): new_node = node() # create a new node new_node.data = data new_node.next = self.cur_node # link the new node to the 'previous' node. self.cur_node = new_node # set the current node to the new one. def list_print(self): node = ll.cur_node while node: print node.data node = node.next def delete_node(self,location): node = ll.cur_node count = 0 while count != location: node = node.next count+=1 delete node ll = linked_list() ll.add_node(1) ll.add_node(2) ll.add_node(3) ll.list_print()

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  • Get particular row as series from pandas dataframe

    - by Pratyush
    How do we get a particular filtered row as series? Example dataframe: >>> df = pd.DataFrame({'date': [20130101, 20130101, 20130102], 'location': ['a', 'a', 'c']}) >>> df date location 0 20130101 a 1 20130101 a 2 20130102 c I need to select the row where location is c as a series. I tried: row = df[df["location"] == "c"].head(1) # gives a dataframe row = df.ix[df["location"] == "c"] # also gives a dataframe with single row In either cases I can't the row as series.

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  • django link format words joined with hypens

    - by soField
    href="http://www.torontolife.com/daily/daily-dish/restauranto/2010/03/10/best-new-restaurants-2010-james-chatto-names-five-honourable-mentions/"Best new restaurants 2010: honourable mentions is django has built in mechanism to format links above i mean words joined with hypens how can achieve this ?

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  • Writing a post search algorithm.

    - by MdaG
    I'm trying to write a free text search algorithm for finding specific posts on a wall (similar kind of wall as Facebook uses). A user is suppose to be able to write some words in a search field and get hits on posts that contain the words; with the best match on top and then other posts in decreasing order according to match score. I'm using the edit distance (Levenshtein) "e(x, y) = e" to calculate the score for each post when compared to the query word "x" and post word "y" according to: score(x, y) = 2^(2 - e)(1 - min(e, |x|) / |x|) Each word in a post contributes to the total score for that specific post. This approach seems to work well when the posts are of roughly the same size, but sometime certain large posts manages to rack up score solely on having a lot of words in them while in practice not being relevant to the query. Am I approaching this problem in the wrong way or is there some way to normalize the score that I haven't thought of?

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  • Simple numpy question

    - by dassouki
    I can't get this snippet to work: #base code A = array([ [ 1, 2, 10 ], [ 1, 3, 20 ], [ 1, 4, 30 ], [ 2, 1, 15 ], [ 2, 3, 25 ], [ 2, 4, 35 ], [ 3, 1, 17 ], [ 3, 2, 27 ], [ 3, 4, 37 ], [ 4, 1, 13 ], [ 4, 2, 23 ], [ 4, 3, 33 ] ]) # Number of zones zones = unique1d(A[:,0]) for origin in zones: for destination in zones: if origin != destination: A_ik = A[(A[:,0] == origin & A[:,1] == destination), 2]

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  • Images to video - converting to IplImage makes video blue

    - by user891908
    I want to create a video from images using opencv. The strange problem is that if i will write image (bmp) to disk and then load (cv.LoadImage) it it renders fine, but when i try to load image from StringIO and convert it to IplImage, it turns video to blue. Heres the code: import StringIO output = StringIO.StringIO() FOREGROUND = (0, 0, 0) TEXT = 'MY TEXT' font_path = 'arial.ttf' font = ImageFont.truetype(font_path, 18, encoding='unic') text = TEXT.decode('utf-8') (width, height) = font.getsize(text) # Create with background with place for text w,h=(600,600) contentimage=Image.open('0.jpg') background=Image.open('background.bmp') x, y = contentimage.size # put content onto background background.paste(contentimage,(((w-x)/2),0)) draw = ImageDraw.Draw(background) draw.text((0,0), text, font=font, fill=FOREGROUND) pi = background pi.save(output, "bmp") #pi.show() #shows image in full color output.seek(0) pi= Image.open(output) print pi, pi.format, "%dx%d" % pi.size, pi.mode cv_im = cv.CreateImageHeader(pi.size, cv.IPL_DEPTH_8U, 3) cv.SetData(cv_im, pi.tostring()) print pi.size, cv.GetSize(cv_im) w = cv.CreateVideoWriter("2.avi", cv.CV_FOURCC('M','J','P','G'), 1,(cv.GetSize(cv_im)[0],cv.GetSize(cv_im)[1]), is_color=1) for i in range(1,5): cv.WriteFrame(w, cv_im) del w

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  • How to reset Scrapy parameters? (always running under same parameters)

    - by Jean Ventura
    I've been running my Scrapy project with a couple of accounts (the project scrapes a especific site that requieres login credentials), but no matter the parameters I set, it always runs with the same ones (same credentials). I'm running under virtualenv. Is there a variable or setting I'm missing? Edit: It seems that this problem is Twisted related. Even when I run: scrapy crawl -a user='user' -a password='pass' -o items.json -t json SpiderName I still get an error saying: ERROR: twisted.internet.error.ReactorNotRestartable And all the information I get, is the last 'succesful' run of the spider.

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  • Convert object to DateRange

    - by user655832
    I'm querying an underlying PostgreSQL database using Pandas 0.8. Pandas is returning the DataFrame properly but the underlying timestamp column in my database is being returned as a generic "object" type in Pandas. As I would eventually like to seasonal normalization of my data I am curious as to how to convert this generic "object" column to something that is appropriate for analysis. Here is my current code to retrieve the data: # get records from db example import pandas.io.sql as psql import psycopg2 # define query to get all subs created this year QRY = """ select i i, i * random() f, case when random() > 0.5 then true else false end t, (current_date - (i*random())::int)::timestamp with time zone tsz from generate_series(1,1000) as s(i) order by 4 ; """ CONN_STRING = "host='localhost' port=5432 dbname='postgres' user='postgres'" # connect to db conn = psycopg2.connect(CONN_STRING) # get some data set index on relid column df = psql.frame_query(QRY, con=conn) print "Row count retrieved: %i" % (len(df),) Thanks for any help you can render. M

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  • SQLAlchemy: a better way for update with declarative?

    - by hadrien
    I am a SQLAlchemy noob. Let's say I have an user table in declarative mode: class User(Base): __tablename__ = 'user' id = Column(u'id', Integer(), primary_key=True) name = Column(u'name', String(50)) When I know user's id without object loaded into session, I update such user like this: ex = update(User.__table__).where(User.id==123).values(name=u"Bob Marley") Session.execute(ex) I dislike using User.__table__, should I stop worrying with that? Is there a better way to do this? Thanx!

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  • split twice in the same expression?

    - by UcanDoIt
    Imagine I have the following: inFile = "/adda/adas/sdas/hello.txt" # that instruction give me hello.txt Name = inFile.name.split("/") [-1] # that one give me the name I want - just hello Name1 = Name.split(".") [0] Is there any chance to simplify that doing the same job in just one expression?

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  • Why doesn't this list comprehension do what I expect it to do?

    - by Az
    The original list project_keys = sorted(projects.keys()) is [101, 102, 103, 104, 105, 106, 107, 108, 109, 110] where the following projects were deemed invalid this year: 108, 109, 110. Thus: for project in projects.itervalues(): # The projects dictionary is mapped to the Project class if project.invalid: # Where invalid is a Bool parameter in the Project class project_keys.remove(project.proj_id) print project_keys This will return a list of integers (which are project id's) as such: [101, 102, 103, 104, 105, 106, 107] Sweet. Now, I wanted it try the same thing using a list comprehension. project_keys = [project_keys.remove(project.proj_id) for project in projects.itervalues() if project.invalid print project_keys This returns: [None, None, None] So I'm populating a list with the same number as the removed elements but they're Nones? Can someone point out what I'm doing wrong? Additionally, why would I use a list comprehension over the for-if block at the top? Conciseness? Looks nicer?

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