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  • &nbsp; displays a tiny line.

    - by Kyle Sevenoaks
    Hi, when I make &nbsp; in my site, it displays a tiny line, which can be hidden on some elements because I'm usually using them on CSS buttons, but I have an if statement that says if this show the result if not show a non breaking space. How do you reset the &nbsp; to display nothing? Thanks.

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  • Chrome is creating duplicate sessions with the same id

    - by dlwiest
    I encountered an issue while I was revising my session library today, and this might be the first time I've ever seen a browser-specific problem on a back end script. I hope somebody can shed some light. Basically how the session library works is: when instantiated, it checks for a cookie called 'id' (in the form of a uniqid result) on the client machine. If a cookie is found, the script checks that and a hashed copy of the user agent string against entries in a session table. If a matching entry is found, the script resumes the session. If no cookie named 'id' is found, or if no matching entry exists in the sessions table, the script creates both. Fairly standard, I think. Now here's the weird part: in Firefox, everything works as predicted. The user gets one session, which he'll always resume upon connection, as long as 24 hours of inactivity has not elapsed. But when I visit the page in Chrome, even though it looks the same and appears to be executing queries in the same order, I see two entries in the session table. The sessions share an agent string, but the ids are different, and timestamp logs indicate that the ghost session is being created shortly (within a second) after the one created for the user. For debugging purposes, I've been printing queries to the screen as they're executed, and this is an example of what I'm seeing when Chrome should be opening one session and is somehow opening two instead: // Attempting to resume a session SELECT id FROM sessions WHERE id = '4fd24a5cd8df12.62439982' AND agent = '9bcd5c6aac911f8bcd938a9563bc4eca' // No result, so it creates a new one INSERT INTO sessions (id, agent, start, last) VALUES ('4fd24ef0347f26.72354606', '9bcd5c6aac911f8bcd938a9563bc4eca', '1339182832', '1339182832') // Clear old sessions DELETE FROM sessions WHERE last < 1339096432 And here's what I'm seeing in the database afterward: id, agent, start, last 4fd24ef0347f26.72354606, 9bcd5c6aac911f8bcd938a9563bc4eca, 1339182832, 1339182832 4fd24ef0857f94.72251285, 9bcd5c6aac911f8bcd938a9563bc4eca, 1339182833, 1339182833 Am I missing something obvious? The only thing I can think of is that Chrome might be creating a hidden session in the background, possibly to crawl the page. If that's the case though, it could become a problem later, when I begin associating active sessions with entries in the users table. I've been looking for possible bugs in my script, but I haven't found anything so far, and everything works as expected in Firefox.

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  • Using jQuery, how do you mimic the form serialization for a select with multiple options selected in

    - by CarolinaJay65
    Below is my $.ajax call, how do I put a selects (multiple) selected values in the data section? $.ajax({ type: "post", url: "http://myServer" , dataType: "text", data: { 'service' : 'myService', 'program' : 'myProgram', 'start' : start, 'end' : end , }, success: function(request) { result.innerHTML = request ; } // End success }); // End ajax method EDIT I should have included that I understand how to loop through the selects selected options with this code: $('#userid option').each(function(i) { if (this.selected == true) { but how do I fit that into my data: section?

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  • How to Count tickets as DateWise

    - by user560716
    I have a query regarding my report, the report format is as under **Date** **Received** **Closed** **Pending** 12/01/10 1000 900 100 12/02/10 2000 1000 1000 12/03/10 1500 1300 200 The above report shows the Help Desk tickets Received, Closed, Pending Count as date wise. How can I create a dynamic SQL query to show above result? Received Tickets is calculated on SubmitedDate Closed Tickets is calculated on ClosedDate with status "Closed" same for Pending Tickets whose status is "Pending". Please provide me the idea or some sample SQL queries.

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  • mysql search using for loop from php.

    - by deb
    hi, i am a beginner. but I'm practicing a lot for few days with php mysql, and I am trying to use for loop to search an exploded string, one by one from mysql server. Till now I have no results. I'm giving my codes, <?php // Example 1 $var = @$_GET['s'] ; $limit=500; echo " "; echo "$var"; echo " "; $trimmed_array = explode(" ", $var); echo "$trimmed_array[0]"; // piece1 echo " "; $count= count($trimmed_array); echo $count; for($j=0;$j<$count;$j++) { e cho "$trimmed_array[$j]";; echo " "; } echo " "; for($i=0; $i<$count ; $i++){ $query = "select * from book where name like \"%$trimmed_array[$i]%\" order by name"; $numresults=mysql_query($query); $numrows =mysql_num_rows($numresults); if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: &quot;" . $trimmed_array[i] . "&quot; returned zero results</p>"; } if (empty($s)) { $s=0; } $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); echo "<p>You searched for: &quot;" . $var . "&quot;</p>"; echo "Results<br /><br />"; $count=1; while ($row= mysql_fetch_array($result)) { $name = $row["name"]; $publisher=$row["publisher"]; $total=$row["total"]; $issued=$row["issued"]; $available=$row["available"]; $category=$row["category"]; echo "<table border='1'><tr><td>$count)</td><td>$name&nbsp;</td><td>$publisher&nbsp;</td><td>$total&nbsp;</td><td>$issued&nbsp;</td><td>$available&nbsp;</td><td>$category&nbsp;</td></tr></table>" ; $count++ ; } } ?>

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  • Counting the instances of customers

    - by Mikae Combarado
    Say that I have a table with one column named CustomerId. The example of the instance of this table is : CustomerId 14 12 11 204 14 204 I want to write a query that counts the number of occurences of customer IDs. At the end, I would like to have a result like this : CustomerId NumberOfOccurences 14 2 12 1 11 1 204 2 14 1 I cannot think of a way to do this.

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  • oracle query returns 4 duplicates of each row

    - by ajoe
    hello, I am Running a oracle query, it seems to work except that it returns 4 dupes of each result. here is the code: Select * from (Select a.*, rownum rnum From (SELECT NEW_USER.*, NEW_EHS_QUIZ_COMPLETE.datetime FROM NEW_USER, NEW_EHS_QUIZ_COMPLETE WHERE EXISTS(select * from NEW_EHS_QUIZ_COMPLETE where NEW_USER.id=NEW_EHS_QUIZ_COMPLETE.USER_ID) ORDER by last_name ASC ) a where rownum <= #pgtop# ) where rnum >= #pgbot# does anyone know why this isnt working properly? thanks in advance.

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  • What should be DefaultLocation property of VS2010 setup to install application in C:\Users\[username

    - by Michael
    I have to install windows service using Visual Studio. Target location for the install is handled by “DefaultLocation” property in Visual Studio setup project. I had used [AppDataFolder] tag to install the application. As the result, it has been installed in “C:\Users[username]\AppData*Roaming*” folder. I can not figure out how to modify “DefaultLocation” property in such a way that application will be installed in C:\Users[username]\AppData*Local* folder. Any idea how to accomplish that?

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  • boolean VB expression returning false for integer 1

    - by Bill
    This is probably a really basic (no pun intended) question, but I can't seem to find an answer anywhere. Why does the result of func1 return False and func2 returns True? On every other test I have done, integer 1 is converted to boolean true and 0 to false. Works ok if I just set rtnValue to 1 or 0. Public Function func1() As Boolean Dim rtnValue As Integer = 0 Return rtnValue = 1 End Function Public Function func2() As Boolean Dim rtnValue As Integer = 0 Return rtnValue = 0 End Function

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  • Servlet as Proxy via https

    - by khiem77
    Hi i tried to implement a servlet with servlet (in tomcat 6) which act as as a proxy (for browser), it takes the parsed url, use apache httpclient to get the result & push it back to the client (browser), with http it works well, doesnt work with https , seems the problem concerns unsupported CONNECT method in servlet-api & servlet even doesn't see the request is there any solution/workaround for this? thanx in advanced

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  • freeing a memory twice

    - by benjamin button
    Hi, AFAIAK, freeing a NULL will result in nothing.i mean nothing is being done by the compiler/no functionality is performed. Still i do see some statements where people say that one of the scenario,where a memory corruption can occur is "freeing a memory twice"? Is this still true?

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  • conditions on count in a select

    - by Luca Romagnoli
    Hi, i have a table like this: Table(MissioneID, Type) Type can be 1,2 or 3 i have to count missions by type value: ex. if table's content is: MissioneID Type 1,1 1,2 1,1 2,3 1,2 The result of query is MissioneID,Count1,Count2,Count3 1, 2,2,0 2,0,0,1 How can i do? thanks

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  • How do I pass a conditional expression as a parameter in Ruby?

    - by srayhan
    For example this what I am trying to do, def method_a(condition, params={}, &block) if condition method_b(params, &block) else yield end end and I am trying to call the method like this, method_a(#{@date > Date.today}, {:param1 => 'value1', :param2 => 'value2'}) do end The result is the condition is always evaluated to true. How do I make it work?

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  • SharpDX Not Implemented Exception

    - by clamp
    What could be the reason I am getting a SharpDX NotImplemented Exception? SharpDX.SharpDXException: HRESULT: [0x80004001], Module: [General], ApiCode: [E_NOTIMPL/Not implemented], Message: Not implemented at SharpDX.Result.CheckError() at SharpDX.MediaFoundation.MediaFactory.Startup(Int32 version, Int32 dwFlags) at SharpDX.MediaFoundation.MediaManager.Startup(Boolean useLightVersion) this is on windows 8 desktop. the same code runs fine on windows 7.

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  • how to get latet entry of a item when item have multiple rows?

    - by I Like PHP
    i have an table tbl_exp id| exp_id|qnty| last_update 1 | 12 | 10|2010-05-18 19:34:29 2 | 13 | 50|2010-05-19 19:34:29 3 | 12 | 50|2010-05-19 19:34:29 4 | 15 | 50|2010-05-18 19:34:29 5 | 18 | 50|2010-05-20 19:34:29 6 | 13 | 70|2010-05-20 19:34:29 now i need only latest entry of each exp_id id| exp_id|qnty| last_update 3 | 12 | 50|2010-05-19 19:34:29 6 | 13 | 70|2010-05-20 19:34:29 4 | 15 | 50|2010-05-18 19:34:29 5 | 18 | 50|2010-05-20 19:34:29 please suggest me the mysql query to retrive above result?? thanks!

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  • piping to variables

    - by lego69
    cut -d" " -f2 ${2} | $callsTo hello, can somebody please explain can I pipe the result of cut to variable callsTo, and how will it be stored, as the string or list?

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  • Add Page Tab dialog not working

    - by Sim
    I was always using the direct Add to Page Tab URL like this: http://www.facebook.com/dialog/pagetab?app_id=238557109577754&redirect_uri=http://www.facebook.com And today that URL gives me "Sorry, something went wrong.". Did something changed on Facebook side? Or is it a temporary bug? Note that I have tried other redirect_uri params, such as the URL of the location where the app is hosted. It does always result in the same error.

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  • join two tables but want one matching columns instead of showing it separately sql server 2008

    - by amby
    Hi i want to display join result of two tables but don't want to show matching column separately. I want it one instead of two. so please tell me what query should i use for this. I m using sql server 2008 and my query is like: select * from Customer_Order, optRelation where Customer_Order.orderNumber = optRelation.orderNumber AND optRelation.orderNumber = 21. please reply soon

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  • How to select with Linq to Entity from one table with two different variables?

    - by George
    I have a table where I have items under two different types as you can see below: How can I select from this table with Linq to Entity to get the result with two variables? where ItemType = Type1 and ItemType == Type2 .... select new {typeOne == "", typeTwo == ""}; ID ItemName ItemType 1 ItemOne Type1 2 ItemTwo Type1 3 ItemThree Type1 4 ItemFour Type1 5 ItemTFive Type2 6 ItemSix Type2 7 ItemSeven Type2 8 ItemEight Type2

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