Search Results

Search found 14486 results on 580 pages for 'python idle'.

Page 378/580 | < Previous Page | 374 375 376 377 378 379 380 381 382 383 384 385  | Next Page >

  • django-uni-form helpers and CSRF tags over POST

    - by linked
    Hi, I'm using django-uni-forms to display my fields, with a rather rudimentary example straight out of their book. When I render the form fields using <form>{%csrf_tag%} {%form|as_uni_form%}</form>, everything works as expected. However, django-uni-form Helpers allow you to generate the form tag (and other helper-related content) using the following syntax -- {% with form.helper as helper %}{% uni_form form helper%}{%endwith%} -- This creates the <form> tag for me, so there's nowhere to embed my own CSRF_token. When I try to use this syntax, the form renders perfectly, but without a CSRF token, and so submitting the form fails every time. Does anyone have experience with this? Is there an established way to add the token? I much prefer the second syntax, for re-use reasons. Thanks!

    Read the article

  • converting a treebank of vertical trees to s-expressions

    - by Andreas
    I need to preprocess a treebank corpus of sentences with parse trees. The input format is a vertical representation of trees, like so: S =NP ==(DT +def) the == (N +ani) man =VP ==V walks ...and I need it like: (S (NP (DT the) (N man)) (VP (V walks))) I have code that almost does it, but not quite. There's always a missing paren somewhere. Should I use a proper parser, maybe a CFG? The current code is at http://github.com/andreasvc/eodop/blob/master/arbobanko.py The code also contains real examples from the treebank.

    Read the article

  • SQLAlchemy introspection of ORM classes/objects

    - by Adam Batkin
    I am looking for a way to introspect SQLAlchemy ORM classes/entities to determine the types and other constraints (like maximum lengths) of an entity's properties. For example, if I have a declarative class: class User(Base): __tablename__ = "USER_TABLE" id = sa.Column(sa.types.Integer, primary_key=True) fullname = sa.Column(sa.types.String(100)) username = sa.Column(sa.types.String(20), nullable=False) password = sa.Column(sa.types.String(20), nullable=False) created_timestamp = sa.Column(sa.types.DateTime, nullable=False) I would want to be able to find out that the 'fullname' field should be a String with a maximum length of 100, and is nullable. And the 'created_timestamp' field is a DateTime and is not nullable.

    Read the article

  • Sqlalchemy layout with WSGI application

    - by TheDude
    I'm working on writing a small WSGI application using Bottle and SqlAlchemy and am confused on how the "layout" of my application should be in terms of SqlAlchemy. My confusion is with creating engines and sessions. My understanding is that I should only create one engine with the 'create_engine' method. Should I be creating an engine instance in the global namespace in some sort of singleton pattern and creating sessions based off of it? How have you done this in your projects? Any insight would be appreciated. The examples in the documentation dont seem to make this entirely clear (unless I'm missing something obvious). Any thoughts?

    Read the article

  • getting global name not defined error

    - by nashr rafeeg
    i have the following class class notify(): def __init__(self,server="localhost", port=23053): self.host = server self.port = port register = gntp.GNTPRegister() register.add_header('Application-Name',"SVN Monitor") register.add_notification("svnupdate",True) growl(register) def svn_update(self, author="Unknown", files=0): notice = gntp.GNTPNotice() notice.add_header('Application-Name',"SVN Monitor") notice.add_header('Notification-Name', "svnupdate") notice.add_header('Notification-Title',"SVN Commit") # notice.add_header('Notification-Icon',"") notice.add_header('Notification-Text',Msg) growl(notice) def growl(data): s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((self.host,self.port)) s.send(data) response = gntp.parse_gntp(s.recv(1024)) print response s.close() but when ever i try to use this class via the follwoing code i get 'NameError: global name 'growl' is not defined' from growlnotify import * n = notify() n.svn_update() any one has an idea what is going on here ? cheers nash

    Read the article

  • some register.inclusion_tag error in my code using django

    - by zjm1126
    my helloworld_tags: from django import template register = template.Library() def show_profile(): return {"eee": '333'} register.inclusion_tag("b.html")(show_profile) my view: def b(request): return render_to_response('b.html') my html: {% load helloworld_tags%} dsad {{ eee }} but only show 'dsad' ,not show 'dsad333' why?? thanks

    Read the article

  • Django: Is there any way to have "unique for date range"?

    - by tomwolber
    If my model for Items is: class Item(models.Model): name = models.CharField(max_length=500) startDate = models.DateField("Start Date", unique="true") endDate = models.DateField("End Date") Each Item needs to have a unique date range. for example, if i create an Item that has a date range of June 1st to June 8th, how can I keep and Item with a date range of June 3rd to June 5th from being created (or render an error with template logic)?

    Read the article

  • Will this SQL screw up

    - by Joshua
    I'm sure everyone knows the joys of concurrency when it comes to threading. Imagine the following scenario on every page-load on a noobily set up MySQL db: UPDATE stats SET visits = (visits+1) If a thousand users load the page at same time, will the count screw up? is this that table locking/row locking crap? Which one mysql use.

    Read the article

  • Django - foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = type_g.type_id, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT n.*, l.* FROM objtree_nodes n JOIN objtree_labels l ON (n.node_id = l.node_id) WHERE n.type_id = 15 AND n.parent_id = 50 AND l.type_id = 1 Any help is GREATLY appreciated. Regards

    Read the article

  • Find next lower item in a sorted list

    - by Sebastian
    Hey guys, let's say I have a sorted list of Floats. Now I'd like to get the index of the next lower item of a given value. The usual for-loop aprroach has a complexity of O(n). Since the list is sorted there must be a way to get the index with O(log n). My O(n) approach: index=0 for i,value in enumerate(mylist): if value>compareValue: index=i-1 Is there a datatype for solving that problem in O(log n)? best regards Sebastian

    Read the article

  • How can I login in a website with Pyhon?

    - by Shady
    How can I do it? I was trying to enter some specified link (with urllib), but to do it, I need to log. I have this source from the site <form id="login-form" action="auth/login" method="post"> <div> <!--label for="rememberme">Remember me</label><input type="checkbox" class="remember" checked="checked" name="remember me" /--> <label for="email" id="email-label" class="no-js">Email</label> <input id="email-email" type="text" name="handle" value="" autocomplete="off" /> <label for="combination" id="combo-label" class="no-js">Combination</label> <input id="password-clear" type="text" value="Combination" autocomplete="off" /> <input id="password-password" type="password" name="password" value="" autocomplete="off" /> <input id="sumbitLogin" class="signin" type="submit" value="Sign In" /> It's possible?

    Read the article

  • gae error : Error: Server Error, how to debug it .

    - by zjm1126
    when i upload my project to google-app-engine , it show this : Error: Server Error The server encountered an error and could not complete your request. If the problem persists, please report your problem and mention this error message and the query that caused it. why ? how can i debug this error ? thanks

    Read the article

  • Use Regular expression with fileinput

    - by chrissygormley
    Hello, I am trying to replace a variable stored in another file using regular expression. The code I have tried is: r = re.compile(r"self\.uid\s*=\s*('\w{12})'") for line in fileinput.input(['file.py'], inplace=True): print line.replace(r.match(line), sys.argv[1]), The format of the variable in the file is: self.uid = '027FC8EBC2D1' I am trying to pass in a parameter in this format and use regular expression to verify that the sys.argv[1] is correct format and to find the variable stored in this file and replace it with the new variable. Can anyone help. Thanks for the help.

    Read the article

  • Pygame, sounds don't play

    - by terabytest
    I'm trying to play sound files (.wav) with pygame but when I start it I never hear anything. This is the code: import pygame pygame.init() pygame.mixer.init() sounda= pygame.mixer.Sound("desert_rustle.wav") sounda.play() I also tried using channels but the result is the same

    Read the article

  • All minimum spanning trees implementation

    - by russtbarnacle
    I've been looking for an implementation (I'm using networkx library.) that will find all the minimum spanning trees (MST) of an undirected weighted graph. I can only find implementations for Kruskal's Algorithm and Prim's Algorithm both of which will only return a single MST. I've seen papers that address this problem (such as http://fano.ics.uci.edu/cites/Publication/Epp-TR-95-50.html) but my head tends to explode someway through trying to think how to translate it to code. In fact i've not been able to find an implementation in any language!

    Read the article

  • How to get a template tag to auto-check a checkbox in Django

    - by Daniel Quinn
    I'm using a ModelForm class to generate a bunch of checkboxes for a ManyToManyField but I've run into one problem: while the default behaviour automatically checks the appropriate boxes (when I'm editing an object), I can't figure out how to get that information in my own custom templatetag. Here's what I've got in my model: ... from django.forms import CheckboxSelectMultiple, ModelMultipleChoiceField interests = ModelMultipleChoiceField(widget=CheckboxSelectMultiple(), queryset=Interest.objects.all(), required=False) ... And here's my templatetag: @register.filter def alignboxes(boxes, cls): """ Details on how this works can be found here: http://docs.djangoproject.com/en/1.1/howto/custom-template-tags/ """ r = "" i = 0 for box in boxes.field.choices.queryset: r += "<label for=\"id_%s_%d\" class=\"%s\"><input type=\"checkbox\" name=\"%s\" value=\"%s\" id=\"id_%s_%d\" /> %s</label>\n" % ( boxes.name, i, cls, boxes.name, box.id, boxes.name, i, box.name ) i = i + 1 return mark_safe(r) The thing is, I'm only doing this so I can wrap some simpler markup around these boxes, so if someone knows how to make that happen in an easier way, I'm all ears. I'd be happy with knowing a way to access whether or not a box should be checked though.

    Read the article

  • csrf error in django

    - by niklasfi
    Hello, I want to realize a login for my site. I basically copied and pasted the following bits from the Django Book together. However I still get an error (CSRF verification failed. Request aborted.), when submitting my registration form. Can somebody tell my what raised this error and how to fix it? Here is my code: views.py: # Create your views here. from django import forms from django.contrib.auth.forms import UserCreationForm from django.http import HttpResponseRedirect from django.shortcuts import render_to_response def register(request): if request.method == 'POST': form = UserCreationForm(request.POST) if form.is_valid(): new_user = form.save() return HttpResponseRedirect("/books/") else: form = UserCreationForm() return render_to_response("registration/register.html", { 'form': form, }) register.html: <html> <body> {% block title %}Create an account{% endblock %} {% block content %} <h1>Create an account</h1> <form action="" method="post">{% csrf_token %} {{ form.as_p }} <input type="submit" value="Create the account"> </form> {% endblock %} </body> </html>

    Read the article

  • Get wrong PATH_INFO after rewriting in lighttpd

    - by Satoru.Logic
    In my lighttpd config file, I have a rewrite rule like this: $HTTP["host"] == "sub.example.com" { url.rewrite = ( "^/(.*)" => "/sub/$1" ) } So when a user visits http://sub.example.com, she's actually visiting http://example.com/sub. The problem is that the PATH_INFO seems wrong, URL: http://sub.example.com/extra PATH_INFO: expected: /extra what I get: /sub/extra Now whenever I call request.get_path(), it returns something like http://sub.example.com/sub/extra, which is not what I want. Of course, I can just override the get_path method of the request class, but I wonder if there is a simpler way like changing the lighttpd config?

    Read the article

  • any faster alternative??

    - by kaushik
    I have to read a file from a particular line number and i know the line number say "n": i have been thinking of two choice: 1)for i in range(n) fname.readline() k=readline() print k 2)i=0 for line in fname: dictionary[i]=line i=i+1 but i want to know faster alternative as i might have to perform this on different files 20000 times. is there is any other better alternatives?? thanking u

    Read the article

  • any faster alternative??

    - by kaushik
    cost=0 for i in range(12): cost=cost+math.pow(float(float(q[i])-float(w[i])),2) cost=(math.sqrt(cost)) Any faster alternative to this? i am need to improve my entire code so trying to improve each statements performance. thanking u

    Read the article

  • What could cause Django to start failing its own tests after an OS and Django reinstall?

    - by Macha
    I had to reinstall my OS, and so, I reinstalled django 1.1. Since reinstalling, when I run tests in my app, I get several failures from django.contrib.auth. Logs: http://dpaste.com/178153/ I asked on #django, and no one is too sure what the cause of the errors are. Some of my own code fails its tests, because it's not fully written yet, but that shouldn't cause django to fail it's core tests... I have included django.contrib.admin, which was mentioned as a possible cause.

    Read the article

  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

    Read the article

< Previous Page | 374 375 376 377 378 379 380 381 382 383 384 385  | Next Page >