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  • How do I write a Oracle SQl query for this tricky question...

    - by atrueguy
    Here is the table data with the column name as Ships. +--------------+ Ships | +--------------+ Duke of north | ---------------+ Prince of Wales| ---------------+ Baltic | ---------------+ In the Outcomes table, transform names of the ships containing more than one space, as follows: Replace all characters between the first and the last spaces (excluding these spaces) by symbols of an asterisk (*). The number of asterisks must be equal to number

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  • User has many computers, computers have many attributes in different tables, best way to JOIN?

    - by krismeld
    I have a table for users: USERS: ID | NAME | ---------------- 1 | JOHN | 2 | STEVE | a table for computers: COMPUTERS: ID | USER_ID | ------------------ 13 | 1 | 14 | 1 | a table for processors: PROCESSORS: ID | NAME | --------------------------- 27 | PROCESSOR TYPE 1 | 28 | PROCESSOR TYPE 2 | and a table for harddrives: HARDDRIVES: ID | NAME | ---------------------------| 35 | HARDDRIVE TYPE 25 | 36 | HARDDRIVE TYPE 90 | Each computer can have many attributes from the different attributes tables (processors, harddrives etc), so I have intersection tables like this, to link the attributes to the computers: COMPUTER_PROCESSORS: C_ID | P_ID | --------------| 13 | 27 | 13 | 28 | 14 | 27 | COMPUTER_HARDDRIVES: C_ID | H_ID | --------------| 13 | 35 | So user JOHN, with id 1 owns computer 13 and 14. Computer 13 has processor 27 and 28, and computer 13 has harddrive 35. Computer 14 has processor 27 and no harddrive. Given a user's id, I would like to retrieve a list of that user's computers with each computers attributes. I have figured out a query that gives me a somewhat of a result: SELECT computers.id, processors.id AS p_id, processors.name AS p_name, harddrives.id AS h_id, harddrives.name AS h_name, FROM computers JOIN computer_processors ON (computer_processors.c_id = computers.id) JOIN processors ON (processors.id = computer_processors.p_id) JOIN computer_harddrives ON (computer_harddrives.c_id = computers.id) JOIN harddrives ON (harddrives.id = computer_harddrives.h_id) WHERE computers.user_id = 1 Result: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | HARDDRIVE TYPE 25 | But this has several problems... Computer 14 doesnt show up, because it has no harddrive. Can I somehow make an OUTER JOIN to make sure that all computers show up, even if there a some attributes they don't have? Computer 13 shows up twice, with the same harddrive listet for both. When more attributes are added to a computer (like 3 blocks of ram), the number of rows returned for that computer gets pretty big, and it makes it had to sort the result out in application code. Can I somehow make a query, that groups the two returned rows together? Or a query that returns NULL in the h_name column in the second row, so that all values returned are unique? EDIT: What I would like to return is something like this: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | NULL | 14 | 27 | PROCESSOR TYPE 1 | NULL | NULL | Or whatever result that make it easy to turn it into an array like this [13] => [P_NAME] => [0] => PROCESSOR TYPE 1 [1] => PROCESSOR TYPE 2 [H_NAME] => [0] => HARDDRIVE TYPE 25 [14] => [P_NAME] => [0] => PROCESSOR TYPE 1

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  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

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  • Sql server 2000 -Space find

    - by Adu
    This is Query: CREATE TABLE #TempTable(datasize varchar(200)) INSERT #TempTable EXEC sp_spaceused 'Table1' When executing this query error message shown as below "Column name or number of supplied values does not match table definition" How can i solve this problem?

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  • MySQL More Tables or More Rows

    - by Pez Cuckow
    I am working on a game that I am going to open to the public to have on their game. The game stores lots of information (about 300 rows) per website and spends a lot of time updating values within this MySQL database. Is it better (faster/efficient) to add a new table for every website or to just have 1000's of rows in one table and add a column "website_id" or similar?

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  • I want to display the missing (non-matching) records

    - by Eric
    Is there a way to program the following SQL query SELECT dbo.Assets_Master.Serial_Number, dbo.Assets_Master.Account_Ident, dbo.Assets_Master.Disposition_Ident FROM dbo.Assets_Master LEFT OUTER JOIN dbo.Assets ON dbo.Assets_Master.Serial_Number = dbo.Assets.Serial_Number WHERE (dbo.Assets.Serial_Number IS NULL) in c# .net code using dataviews or data relation or something else? I have a spreadsheet of about 4k rows and a data table that should have the same records but if not I want to display the missing (non-matching) records from the table. Thanks, Eric

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  • How to make an add friend/defriend function in PHP?

    - by user300371
    I have created a site where people can create a profile. But I am trying to figure out how to start on making an add friend button so users can have friends. In my user table, i have user_id, first_name, last_name, email, etc. Should I somehow relate the user_id of the user and the friend in a friend table? I am a novice to programming, so these things are still new to me. Thanks!

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  • jquery function call with parameters

    - by Kaushik Gopal
    Hi a newb question: I have a table with a bunch of buttons like so: <tr class="hr-table-cell" > <td>REcord 1</td> <td> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(222445,704);" /> </td> </tr> <tr class="hr-table-cell" > <td>REcord 1</td> <td align="center" class="hr-table-bottom-blue-border" valign="middle"> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(237760,776);" /> </td> </tr> I have my jquery like so: <script type="text/javascript"> // JQUERY stuff $(document).ready(function(){ function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } }); This doesn't seem to work.I thought this means, the function is ready only after the dom is ready. After the dom is ready and i click the button, why is not recognizing the function declaration within the .ready() function? However if i use the function directly: <script type="text/javascript"> function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } This works. I want to get my fundamentals straight here... If i do the declaration without the .ready() , does that mean i'm using plain vanilla jscript? If i were to do this with the document.ready - the usual jquery declaration way, what would i have to change to make it work? I understand there are much better ways to do this like binding with buttons etc, but I want to know why this particular way doesn't seem to be working. Thanks. Cheers. K

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  • How to define variable for Trac TicketQuery?

    - by JOM
    Using TRAC TicketQuery template for sprint to show what's going on. How would I type name of current sprint only ONCE, when template needs it in multiple location? For example "Sprint1" is needed is 6 places: = New items = [[TicketQuery(milestone=Sprint1,status=new,format=table,order=priority,col=id|summary|priority|component|owner|type)]] = Items in progress = [[TicketQuery(milestone=Sprint1,status=in_progress,format=table,order=priority,col=id|summary|priority|component|owner|type)]]

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  • Netbeans code templates' modifiers

    - by hsz
    Hello ! I set a new PHP code template in Netbeans: /* @var $$${name}Table Model_${name}_Table */ $$${name}Table = Container::get('model')->get('${name}_Table'); and if I use as ${name} some value - shop - I have in output: /* @var $shopTable Model_shop_Table */ $shopTable = Container::get('model')->get('shop_Table'); Is it possible to add some modifier to the second and fourth ${name} so I will have it started with upper letter ? Shop_Table instead of shop_Table

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  • SQL for sorting boolean column as true, null, false

    - by petehern
    My table has three boolean fields: f1, f2, f3. If I do SELECT * FROM table ORDER BY f1, f2, f3 the records will be sorted by these fields in the order false, true, null. I wish to order them with null in between true and false: the correct order should be true, null, false. I am using PostgreSQL.

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  • ActiveRecord finding from inside a serialized field

    - by JP
    While working with ActiveRecord I have a table which stores a serialized array of participant usernames for each row. Is there an easy way to search for all rows who contain a specific user? I realise I could just make a new linked table for the participants, but I feel like that would increase my overhead unnecessarily -- what do you think?

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  • How to use Linq To Sql to get Users who has less than 2 photos?

    - by Mike108
    The scenario is I want to get the users who has less than 2 photos. There are two table: [Users] (UserId, UserName) [UserPhotos] (PhotoId, PhotoName, UserId) UserId is a Foreign Key but I do not want to use association like user.Photos. A user may have none photo in the [UserPhotos] table. How to use Linq To Sql to get List<User> who has less than 2 photos?

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  • Sort by ranking algorithm using will-paginate

    - by bearwithclaws
    I'm creating a digg-like site using Ruby on Rails that ranks the item (based on this algorithm). I'm using the will-paginate gem list the items in pages. The problem is, will-paginate only allows me to insert ':order =' based on the table data. I would like to make will-paginate to sort by a number which is calculated using a function based on different fields on the table (e.g number of votes, age hours). How can I do that?

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  • Are Conditional subquery

    - by Tobias Schulte
    I have a table foo and a table bar, where each foo might have a bar (and a bar might belong to multiple foos). Now I need to select all foos with a bar. My sql looks like this SELECT * FROM foo f WHERE [...] AND ($param IS NULL OR (SELECT ((COUNT(*))>0) FROM bar b WHERE f.bar = b.id)) with $param being replaced at runtime. The question is: Will the subquery be executed even if param is null, or will the dbms optimize the subquery out?

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  • filter by multiple attributes

    - by cosy
    I have the table : id id_products id_atribut name value 1 13 8 autdio 2.1 2 13 9 hdd 200 Gb 3 13 10 cd-rom 2 4 20 8 audio 2.1 the problem is, how can i select from this table where name="audio" and value="2.1" and name="hdd" and value="200 gb" and return id_products=13 .... How can i do this?

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  • Layout issue regarding a JQuery smoothDivScroll

    - by MichaelMcCabe
    Hi all. I have been scratching my head for a while on this one. I dont really play around with HTML formatting that often. I have a smoothDivScroll using JQuery (http://maaki.com/thomas/SmoothDivScroll/) to scroll through dynamically generated images. What I want it for, is to have multiple small images lined up right next to each other, and each image has a section of writting underneath. about 25 images, 140px width each in a 7560px span. I acheived this great by putting a table inside the div, and each image inside a<td>.This works problem i have, is that i need the slider to start from the furthest RIGHT image, and slide automatically left. This is acheived by (if you look at the link above) - startAtElementId: But if I am using a table inside the div, it is taking the TABLE as a element and not the TD... so it doesnt work. I know this because if I change every image to be inside tables (i.e 25 tables), it works... but obviously then the formatting is not how I want. Can anyone think of a way I can use this slider (modifications to the js code or not), with 25 images that NEED to be right next to each other, no gap. I guess this is more of a formatting question, than about the slider. Because I only know ONE way of doing what I want, and thats to have below which will not alow me to set startAtElementId. <div class="scrollableArea"> <table width="7560px" class="index-body"> <tr> <td width="140px"><center><a onclick="__doPostBack('getEarlierDate');" ><img src="../images/olderGraphs.gif" width="140" height="60"></a>Click for more</center></td> <td width="300px"><center><a onclick="__doPostBack('chartClicked25');" ><cewolf:img chartid="verticalbar25" renderer="cewolf" width="300" height="60"/></a><c:out value="${date25}"/></center></td> <td width="300px"><center><a onclick="__doPostBack('chartClicked24');" ><cewolf:img chartid="verticalbar24" renderer="cewolf" width="300" height="60"/></a><c:out value="${date24}"/></center></td> and so on

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  • iPhone: custom cell is overlaping with each other

    - by Nandakishore
    hi i am working on Table view, my Table view first custom cell is over ride other cell when Scrolling this is my code import UIKit/UIKit.h @interface MyTweetViewController : UIViewController { IBOutlet UITableView *tweetsTableView; NSMutableArray *tweetArray; } @property (nonatomic, retain) IBOutlet UITableView *tweetsTableView; @end import "MyTweetViewController.h" @implementation MyTweetViewController @synthesize tweetsTableView; (void)viewDidLoad { tweetArray = [[NSMutableArray alloc] init]; [tweetsTableView setBackgroundColor:[UIColor clearColor]]; [super viewDidLoad]; } pragma mark - pragma mark Table view data source (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { // Return the number of sections. return 1; } (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { // Return the number of rows in the section. return [tweetArray count]; } (CGFloat)tableView:(UITableView *)tableView heightForRowAtIndexPath:(NSIndexPath *)indexPath { return 80; } - (void)tableView:(UITableView *)tableView willDisplayCell:(UITableViewCell *)cell forRowAtIndexPath:(NSIndexPath *)indexPath { [cell setBackgroundColor:[UIColor clearColor]]; } //Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *identifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:identifier]; if(!cell) { cell = [[UITableViewCell alloc] initWithStyle:UITableViewStyleGrouped reuseIdentifier:identifier]; cell.selectionStyle = UITableViewCellSelectionStyleNone; } cell.accessoryType = UITableViewCellAccessoryNone; UILabel * name = [[UILabel alloc]initWithFrame:CGRectMake(72,3,242,15)]; name.text = (NSString*)[(Tweet*)[tweetArray objectAtIndex:indexPath.row] userName]; [name setFont:[UIFont fontWithName:@"Helvetica" size:14]]; name.textColor=[UIColor colorWithRed:250 green:250 blue:210 alpha:0.5]; [name setBackgroundColor:[UIColor clearColor]]; UILabel * tweetLabel = [[UILabel alloc]initWithFrame:CGRectMake(72,20,242,60)]; tweetLabel.text = (NSString*)[(Tweet*)[tweetArray objectAtIndex:indexPath.row] tweet]; tweetLabel.numberOfLines = 3; tweetLabel.textColor=[UIColor colorWithRed:252 green:148 blue:31 alpha:1]; [tweetLabel setFont:[UIFont fontWithName:@"Helvetica" size:12]]; [tweetLabel setBackgroundColor:[UIColor clearColor]]; NSLog(@" lblUserTweet : %@ ",name.text); UIImageView *myImage = [[UIImageView alloc]initWithFrame:CGRectMake(6,3,58,49)]; NSURL url = [NSURL URLWithString:[(Tweet)[tweetArray objectAtIndex:indexPath.row] image_url]]; NSData *data = [NSData dataWithContentsOfURL:url]; [myImage setImage: [UIImage imageWithData:data]]; [cell.contentView addSubview:myImage]; [cell.contentView addSubview:tweetLabel]; [cell.contentView addSubview:name]; return cell; } (void)dealloc { [tweetsTableView release]; [tweetArray release]; [super dealloc]; }

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