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  • User has many computers, computers have many attributes in different tables, best way to JOIN?

    - by krismeld
    I have a table for users: USERS: ID | NAME | ---------------- 1 | JOHN | 2 | STEVE | a table for computers: COMPUTERS: ID | USER_ID | ------------------ 13 | 1 | 14 | 1 | a table for processors: PROCESSORS: ID | NAME | --------------------------- 27 | PROCESSOR TYPE 1 | 28 | PROCESSOR TYPE 2 | and a table for harddrives: HARDDRIVES: ID | NAME | ---------------------------| 35 | HARDDRIVE TYPE 25 | 36 | HARDDRIVE TYPE 90 | Each computer can have many attributes from the different attributes tables (processors, harddrives etc), so I have intersection tables like this, to link the attributes to the computers: COMPUTER_PROCESSORS: C_ID | P_ID | --------------| 13 | 27 | 13 | 28 | 14 | 27 | COMPUTER_HARDDRIVES: C_ID | H_ID | --------------| 13 | 35 | So user JOHN, with id 1 owns computer 13 and 14. Computer 13 has processor 27 and 28, and computer 13 has harddrive 35. Computer 14 has processor 27 and no harddrive. Given a user's id, I would like to retrieve a list of that user's computers with each computers attributes. I have figured out a query that gives me a somewhat of a result: SELECT computers.id, processors.id AS p_id, processors.name AS p_name, harddrives.id AS h_id, harddrives.name AS h_name, FROM computers JOIN computer_processors ON (computer_processors.c_id = computers.id) JOIN processors ON (processors.id = computer_processors.p_id) JOIN computer_harddrives ON (computer_harddrives.c_id = computers.id) JOIN harddrives ON (harddrives.id = computer_harddrives.h_id) WHERE computers.user_id = 1 Result: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | HARDDRIVE TYPE 25 | But this has several problems... Computer 14 doesnt show up, because it has no harddrive. Can I somehow make an OUTER JOIN to make sure that all computers show up, even if there a some attributes they don't have? Computer 13 shows up twice, with the same harddrive listet for both. When more attributes are added to a computer (like 3 blocks of ram), the number of rows returned for that computer gets pretty big, and it makes it had to sort the result out in application code. Can I somehow make a query, that groups the two returned rows together? Or a query that returns NULL in the h_name column in the second row, so that all values returned are unique? EDIT: What I would like to return is something like this: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | NULL | 14 | 27 | PROCESSOR TYPE 1 | NULL | NULL | Or whatever result that make it easy to turn it into an array like this [13] => [P_NAME] => [0] => PROCESSOR TYPE 1 [1] => PROCESSOR TYPE 2 [H_NAME] => [0] => HARDDRIVE TYPE 25 [14] => [P_NAME] => [0] => PROCESSOR TYPE 1

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  • Is the time cost constant when bulk inserting data into an indexed table?

    - by SiLent SoNG
    I have created an archive table which will store data for selecting only. Daily there will be a program to transfer a batch of records into the archive table. There are several columns which are indexed; while others are not. I am concerned with time cost per batch insertion: - 1st batch insertion: N1 - 2nd batch insertion: N2 - 3rd batch insertion: N3 The question is: will N1, N2, and N3 roughly be the same, or N3 N2 N1? That is, will the time cost be a constant or incremental, with existence of several indexes? All indexes are non-clustered. The archive table structure is this: create table document ( doc_id int unsigned primary key, owner_id int, -- indexed title smalltext, country char(2), year year(4), time datetime, key ix_owner(owner_id) }

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • How to exclude rows where matching join is in an SQL tree

    - by Greg K
    Sorry for the poor title, I couldn't think how to concisely describe this problem. I have a set of items that should have a 1-to-1 relationship with an attribute. I have a query to return those rows where the data is wrong and this relationship has been broken (1-to-many). I'm gathering these rows to fix them and restore this 1-to-1 relationship. This is a theoretical simplification of my actual problem but I'll post example table schema here as it was requested. item table: +------------+------------+-----------+ | item_id | name | attr_id | +------------+------------+-----------+ | 1 | BMW 320d | 20 | | 1 | BMW 320d | 21 | | 2 | BMW 335i | 23 | | 2 | BMW 335i | 34 | +------------+------------+-----------+ attribute table: +---------+-----------------+------------+ | attr_id | value | parent_id | +---------+-----------------+------------+ | 20 | SE | 21 | | 21 | M Sport | 0 | | 23 | AC | 24 | | 24 | Climate control | 0 | .... | 34 | Leather seats | 0 | +---------+-----------------+------------+ A simple query to return items with more than one attribute. SELECT item_id, COUNT(DISTINCT(attr_id)) AS attributes FROM item GROUP BY item_id HAVING attributes > 1 This gets me a result set like so: +-----------+------------+ | item_id | attributes | +-----------+------------+ | 1 | 2 | | 2 | 2 | | 3 | 2 | -- etc. -- However, there's an exception. The attribute table can hold a tree structure, via parent links in the table. For certain rows, parent_id can hold the ID of another attribute. There's only one level to this tree. Example: +---------+-----------------+------------+ | attr_id | value | parent_id | +---------+-----------------+------------+ | 20 | SE | 21 | | 21 | M Sport | 0 | .... I do not want to retrieve items in my original query where, for a pair of associated attributes, they related like attributes 20 & 21. I do want to retrieve items where: the attributes have no parent for two or more attributes they are not related (e.g. attributes 23 & 34) Example result desired, just the item ID: +------------+ | item_id | +------------+ | 2 | +------------+ How can I join against attributes from items and exclude these rows? Do I use a temporary table or can I achieve this from a single query? Thanks.

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  • Oracle access from iOS

    - by Michael Lowman
    I'm developing an iPad app that needs read-only access to an Oracle database. Is there any way to do this? As far as I can see, the only options are using OCI, which requires a prebuilt binary in the form of the instant client (and not built for ARM), or OJDBC drivers. Both of these seem to be out of the question. In my research I have discovered that libmysqlclient compiles for arm with minimal tuning. This is a stretch, but is there any possible way to use this to my advantage? I have seen this product providing odbc connectivity through the use of a Windows gateway machine using the ODBC client libraries, but this solution really isn't an option for me at the present time. Any ideas?

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  • query excuting problem

    - by srini-r85
    hi, i tried to execute following query in php script. $db_selected = mysql_select_db("lumiinc1_sndemo1", $con); if ($db_selected) { echo "database connected"; } else { die ("Can\'t use db : " . mysql_error()); } $sql = "INSERT INTO `markers` ( `name`, `address`, `lat`, `lng`, `id` ) SELECT `name`, `street`, `latitude`, `longitude`, `lid` FROM `location` WHERE NOT EXISTS ( SELECT * FROM `markers` WHERE `location`.`lid` = `markers`.`id` )"; $result = mysql_query($sql); if ($result) { echo "Query executed OK"; } else { die("Invalid query: " . mysql_error()); } script does not show any error.also query executed.but i didn't get my expected result.at the same i try this query in phpmyAdmin i got my expected result. i dont know the cause of this problem. plz any one find the problem . thanks

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  • Fetch image from folder via datatable does not work after placing image in subdirectory

    - by Arnold Bishkoff
    I am having trouble wrapping my head around the following I have code that fetches an image via smarty in a line img src="getsnap.php?picid={$data[$smarty.section.sec.index].picno|default:$nextpic}&typ=pic&width={$config.disp_snap_width}&height={$config.disp_snap_height}" class="smallpic" alt="" / this works if i pull the image from /temp/userimages/userid/imageNo.ext but because an OS can segfault if you store too many folders or images in a directory i have code that assigns the user image to a subdirectory based upon division of a subdir per 1000 userids. so in thise case i have user id 94 whos images get stored in /siteroot/temp/userimages/000000/94/pic_1.jpg (through 10) or tn_1 (through 10).jpg here is the code for getsnap.php <?php ob_start(); if ( !defined( 'SMARTY_DIR' ) ) { include_once( 'init.php' ); } include('core/snaps_functions.php'); if (isset($_REQUEST['username']) && $_REQUEST['username'] != '') { $userid = $osDB-getOne('select id from ! where username = ?',array(USER_TABLE, $_REQUEST['username']) ); } else { // include ( 'sessioninc.php' ); if( !isset($_GET['id']) || (isset($_GET['id'])&& (int)$_GET['id'] <= 0 ) ) { $userid = $_SESSION['UserId']; } else { $userid = $_GET['id']; } } if (!isset($_GET['picid']) ) { if ((isset($_REQUEST['type']) && $_REQUEST['type'] != 'gallery') || !isset($_REQUEST['type']) ) { $defpic = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and default_pic = ? and active = ? ',array(USER_SNAP_TABLE, $userid,'0','Y','Y' ) ); if ($defpic != '') { $picid = $defpic; } else { $picid = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and active=? order by rand()',array(USER_SNAP_TABLE, $userid,'0','Y' ) ); } unset( $defpic); } } else { $picid = $_GET['picid']; } $typ = isset( $_GET['typ'])?$_GET['typ']:'pic' ; $cond = ''; if ( ($config['snaps_require_approval'] == 'Y' || $config['snaps_require_approval'] == '1') && $userid != $_SESSION['UserId'] ) { $cond = " and active = 'Y' "; } $sql = 'select * from ! where userid = ? and picno = ? '.$cond; //Get the pic $row =& $osDB-getRow ( $sql, array( USER_SNAP_TABLE, $userid, $picid ) ); //Okay pic was found in the DB, Lets actually do something // $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; $img = getPicture($zimg, $userid, $picid, $typ, $row); //$img = getPicture($userid, $picid, $typ, $row); //$img = getPicture($dir, $userid, $picid, $typ, $row); $ext = ($typ = 'tn')?$row['tnext']:$row['picext']; // Now pic is built as // something pic_x.ext ie pic_2.jpg if ( $img != '' && ( ( hasRight('seepictureprofile') && ( $config['snaps_require_approval'] == 'Y' && $row['active'] == 'Y' ) ||$config['snaps_require_approval'] == 'N' ) || $userid == $_SESSION['UserId'] ) ) { $img2 = $img; //$img2 = $dir.'/'.$img; } else { $gender = $osDB-getOne( 'select gender from ! where id = ?', array( USER_TABLE, $userid ) ) ; if ($gender == 'M') { $nopic = SKIN_IMAGES_DIR.'male.jpg'; } elseif ($gender == 'F') { $nopic = SKIN_IMAGES_DIR.'female.jpg'; } elseif ($gender == 'D') { $nopic = SKIN_IMAGES_DIR.'director.jpg'; } $img2 = imagecreatefromjpeg($nopic); $ext = 'jpg'; } ob_end_clean(); header("Pragma: public"); header("Content-Type: image/".$ext); header("Content-Transfer-Encoding: binary"); header("Cache-Control: must-revalidate"); $ExpStr = "Expires: " . gmdate("D, d M Y H:i:s", time() - 30) . " GMT"; header($ExpStr); $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; //header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); //header("Content-Disposition: attachment; filename=$dir.'/'.profile_".$userid."".$typ.".".$ext); //header("Content-Disposition: attachment; filename=profile"$dir".'/'.".$userid."_".$typ.".".$ext); header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); /* if ($_SESSION['browser'] != 'MSIE') { header("Content-Disposition: inline" ); } */ if ($ext == 'jpg') { imagejpeg($img2); } elseif ($ext == 'gif') { imagegif($img2); } elseif ($ext == 'png') { imagepng($img2); } elseif ($ext == 'bmp') { imagewbmp($img2); } imagedestroy($img2); ?

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  • Incorrect string encodings

    - by James
    Note: I have read all of the related PHP, UTF-8, character encoding articles that are usually suggested, but my question relates to data inserted before I applied such techniques. I am wishing to retrospectively fix all character encoding problems. Now all connections are set as utf8 using PDO. PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8' Unfortunately, a large amount of data was inserted that is of questionable encoding before I had implemented correct character encoding practices. As displayed by: $sql = "SELECT name FROM data LIMIT 3"; foreach ($pdo->query($sql) as $row) { $name = $row['name']; echo $name . "\n"; echo utf8_encode($name) . "\n"; echo utf8_decode($name) . "\n"; echo htmlspecialchars($name, ENT_QUOTES, 'UTF-8') . "\n"; echo htmlspecialchars(utf8_encode($name), ENT_QUOTES, 'UTF-8') . "\n"; echo htmlspecialchars(utf8_decode($name), ENT_QUOTES, 'UTF-8') . "\n"; echo '<hr/>'; } Which produces: Antonín Dvořák AntonÃÆín DvoÃâ¦Ãâ¢ÃÆák Anton??­n Dvo??????¡k Antonín Dvořák AntonÃÆín DvoÃâ¦Ãâ¢ÃÆák ---------- Ô±Ö€Õ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿Ö€ÕµÕ¡Õ¶ ñÃâ¬Ã¡Ã´ ýáùáÿÃâ¬ÃµÃ¡Ã¶ ????? ?????????? Ô±Ö€Õ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿Ö€ÕµÕ¡Õ¶ ñÃâ¬Ã¡Ã´ ýáùáÿÃâ¬ÃµÃ¡Ã¶ ---------- Tiësto Tiësto Tiësto Tiësto Tiësto Tiësto ---------- When removing 'SET NAMES utf8' with PDO it produces the data: Antonín DvoÅák Antonín DvoÃÂák Antonín Dvorák Antonín DvoÅák Antonín DvoÃÂák Antonín Dvorák ---------- ???? ????????? Ô±ÖÕ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿ÖÕµÕ¡Õ¶ ???? ????????? ???? ????????? Ô±ÖÕ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿ÖÕµÕ¡Õ¶ ???? ????????? ---------- Tiësto Tiësto Ti?sto Tiësto Tiësto ---------- And here is a dump of the database rows concerned: DROP TABLE IF EXISTS `data`; CREATE TABLE IF NOT EXISTS `data` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(80) NOT NULL, PRIMARY KEY (`id`), KEY `name` (`name`(10)), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=0; INSERT INTO `data` (`id`, `name`) VALUES (0, 'Antonín Dvořák'), (1, 'Ô±Ö€Õ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿Ö€ÕµÕ¡Õ¶'), (2, 'Tiësto'); The 3rd and 6th lines of the 3rd row "Tiësto" are then correctly echoed. I'm just unsure what is the best way to correct encodings/detect the encodings of bad strings and correct, etc.

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  • Currently using View, Should I use a hard table instead?

    - by 1001010101
    I am currently debating whether my table, mapping_uGroups_uProducts, which is a view formed by the following table: CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `db`.`mapping_uGroups_uProducts` AS select distinct `X`.`upID` AS `upID`,`Z`.`ugID` AS `ugID` from ((`db`.`mapping_uProducts_Products` `X` join `db`.`productsInfo` `Y` on((`X`.`pID` = `Y`.`pID`))) join `db`.`mapping_uGroups_Groups` `Z` on((`Y`.`gID` = `Z`.`gID`))); My current query is: SELECT upID FROM uProductsInfo \ JOIN fs_uProducts USING (upID) column \ JOIN mapping_uGroups_uProducts USING (upID) -- could be faster if we use hard table and index \ JOIN mapping_fs_key USING (fsKeyID) \ WHERE fsName="OVERALL" \ AND ugID=1 \ ORDER BY score DESC \ LIMIT 0,30; which is pretty slow. (for 30 results, it requires about 10 secondes). I think the reason for my query being so slow is definitely due to the fact that that particular query relies on a VIEW which has no index to speed things up. +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ | 1 | PRIMARY | mapping_fs_key | const | PRIMARY,fsName | fsName | 386 | const | 1 | Using temporary; Using filesort | | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 19706 | Using where | | 1 | PRIMARY | uProductsInfo | eq_ref | PRIMARY | PRIMARY | 4 | mapping_uGroups_uProducts.upID | 1 | Using index | | 1 | PRIMARY | fs_uProducts | ref | upID | upID | 4 | db.uProductsInfo.upID | 221 | Using where | | 2 | DERIVED | X | ALL | PRIMARY | NULL | NULL | NULL | 40772 | Using temporary | | 2 | DERIVED | Y | eq_ref | PRIMARY | PRIMARY | 4 | db.X.pID | 1 | Distinct | | 2 | DERIVED | Z | ref | PRIMARY | PRIMARY | 4 | db.Y.gID | 2 | Using index; Distinct | +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ 7 rows in set (0.48 sec) The explain here looks pretty cryptic, and I don't know whether I should drop view and write a script to just insert everything in the view to a hard table. ( obviously, it will lose the flexibility of the view since the mapping changes quite frequently). Does anyone have any idea to how I can optimize my schema better?

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  • Error in computed Field of select Query

    - by Shehzad Bilal
    This Query is giving me an error of #1054 - Unknown column 'totalamount' in 'where clause' SELECT (amount1 + amount2) as totalamount FROM `Donation` WHERE totalamount > 1000 I know i can resolve this error by using group by clause and replace my where condition with having clause. But is there any other solution beside using having clause. If group by is the only solution then I want to know why I have to use group by clause even I havent use any aggregate function thanks.

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  • Returning multiple aggregate functions as rows

    - by SDLFunTimes
    I need some help formulating a select statement. I need to select the total quantity shipped for each part with a distinct color. So the result should be a row with the color name and the total. Here's my schema: create table s ( sno char(5) not null, sname char(20) not null, status smallint, city char(15), primary key (sno) ); create table p ( pno char(6) not null, pname char(20) not null, color char(6), weight smallint, city char(15), primary key (pno) ); create table sp ( sno char(5) not null, pno char(6) not null, qty integer not null, primary key (sno, pno) );

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  • alter mysqldump file before import

    - by julio
    Hi-- I have a mysqldump file created from an earlier version of a product that can't be imported into a new version of the product, since the db structure has changed slightly (mainly altering a column that was NOT NULL DEFAULT 0 to UNIQUE KEY DEFAULT NULL). If I just import the old dump file, it will error out since the column that has default values of 0 now breaks the UNIQUE constraint. It would be easy enough to either manually alter the mysqldump file, or import into a temp table and change it, then copy to the new table. However, is there a way to do this programatically, so it will be repeatable and not manual? (this will need to happen for many instances of this product). I'm thinking something like disabling key constraints for the import, then setting all values that = 0 to NULL, then re-enabling the key constraints? Is this possible? Any help appreciated.

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  • GROUP BY a date, with ordering by date.

    - by standard
    Take this simple query: SELECT DATE_FORMAT(someDate, '%y-%m-%d') as formattedDay FROM someTable GROUP BY formatterDay This will select rows from a table with only 1 row per date. How do I ensure that the row selected per date is the earliest for that date, without doing an ordered subquery in the FROM? Cheers

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  • Query multiple currencies

    - by TiuTalk
    I need store multiple currencies on my database... Here's the problem: Example Tables: [ Products ] id (INT, PK) name (VARCHAR) price (DECIMAL) currency (INT, FK) [ Currencies ] id (INT, PK) name (VARCHAR) conversion (DECIMAL) # To U$ I'll store the product price with the currency selected by the user... Later I need to search the products using a price interval like "Search products with price from U$ 50 to U$ 100" and I need the system convert these values "on the fly" to run the SQL Query and filter the products. And I really don't know how to make this query... :/

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  • PHP FUNCTION TO AUTOMATICALLY REMOVE WHITESPACE AND TRIM DOWN IDENTIFIERS

    - by H8 MY H0ST
    I HAVE A WEBSITE WHICH GETS WAY TOO MUCH TRAFFIC. MY HOST IS MAKING ME UPGRADE AND I'M LIKE MAN MY SITE MAKES $0 CUZ I AINT NO SPAMMER YA DIGG? I WILL CUT DOWN ON THE BANDWITH AND THEY'RE LIKE OKAY. GONNA DO GZIP. BUT I NEED LIKE A FUNCTION TO STRIP ALL WHITESPACE AND EXTRA SHIT FROM OUTPUT TOO IF POSSIBLE. AND THEN STUFF THAT CAN TURN MY #WRAPPER INTO LIKE #A #B #C ?? USING ZEND FRAMEWORK AT THE MOMENT. THANK YOU ALL VERY MUCH FOR YOUR TIME.

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  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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