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  • retriving row of grid

    - by madhu
    i have data grid to which data is getting from database.after getting the data i hvve to show entire row information in an alert box.can any one help me thanks in advance. my function code is private function fetch(event:Event):void { var selectedRow:Object = event.currentTarget.selectedItem; Alert.show(""+selectedRow.Details); } iam calling this method on click event of grid

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  • SQL Server Maximum row size

    - by DannySmurf
    Came across this error today. Wondering if anyone can tell me what it means: Cannot sort a row of size 9522, which is greater than the allowable maximum of 8094. Is that 8094 bytes? Characters? Fields? Is this a problem joining multiple tables that are exceeding some limit?

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  • With jQuery and I need help getting individual table row titles attributes from an xml file

    - by bfsarmi
    I'm usig tablesorter jQuery to parse this xml file <?xml version="1.0" encoding="iso-8859-1"?> <CATALOG> <CD> <TITLE>Title 01</TITLE> <ARTIST>Artist 01</ARTIST> <COUNTRY>Country 01</COUNTRY> <PRICE>10.00</PRICE> <YEAR>2010</YEAR> <INFO>Tooltip Info 01</INFO> </CD> <CD> <TITLE>Title 02</TITLE> <ARTIST>Artist 02</ARTIST> <COUNTRY>Country 02</COUNTRY> <PRICE>9.00</PRICE> <YEAR>2009</YEAR> <INFO>Tooltip Info 02</INFO> </CD> <CD> <TITLE>Title 03</TITLE> <ARTIST>Artist 03</ARTIST> <COUNTRY>Country 03/COUNTRY> <PRICE>8.00</PRICE> <YEAR>2008</YEAR> <INFO>Tooltip Info 03</INFO> </CD> </CATALOG> and with this code <script type="text/javascript"> $(document).ready(function(){ $.ajax({ type: "GET", url: "file.xml", dataType: "xml", success: function(xml){ $(xml).find("CD").each(function(){ $("#tablebody").append('<tr><td>' + $(this).find("TITLE").text() + '</td><td>'+ $(this).find("ARTIST").text() + '</td><td>'+ $(this).find("COUNTRY").text() + '</td><td>'+ $(this).find("PRICE").text() + '</td><td>'+ $(this).find("YEAR").text() + '</td></tr>'); }); } }); }); </script> I'm new at javascript and have been trying with no luck for a couple of hrs to get the text from the INFO/INFO tags in the xml file to show as title attributes for each table row. The reason for that is that I need to have individual popup tooltips on mouse-over each table row. Many Thanks in advance for any kind of help or suggestions!

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  • display several items in one row of a listview in android

    - by Sephy
    I don't now if this title is very clear, but I would like to understand how this is possible : And how we can have 2 elements on the same row of the listview, and handle different clicks, as the listview deals with handling the click on a child. Thanks for anyone who could point me in the right direction.

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  • multi row header on Google Visualizations

    - by Elzo Valugi
    Hi, I am trying to create a DataTable with a multi row header. I'll exemplify here: | 2008 | 2009 | --------------------------------------------------------- | price | qty. | price | qty | --------------------------------------------------------- | 93993 | 34434 | 34244 | 3434 | ..... The years headers can be fixed as I don't want to do sorting by that. Is there a way to do that in Google Visualizations?

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  • Get previous and next row from current id

    - by Hukr
    How can I do to get the next row in a table? `image_id` int(11) NOT NULL auto_increment `image_title` varchar(255) NOT NULL `image_text` mediumtext NOT NULL `image_date` datetime NOT NULL `image_filename` varchar(255) NOT NULL If the current image is 3 for example and the next one is 7 etc. this won’t work: $query = mysql_query("SELECT * FROM images WHERE image_id = ".intval($_GET['id'])); echo $_GET['id']+1; How should I do? thanks

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  • In R, How to add Row for Information:

    - by Moe
    Hi, I'm trying to add a Row to my data.frame to spit out the average of the column. This is my data frame: Weight Response 1 Control 59 0.0 2 Treatment 90 0.8 3 Treatment 47 0.1 4 Treamment 106 0.1 5 Control 85 0.7 6 Treatment 73 0.6 7 Control 61 0.2 I'd like it to become: Weight Response 1 Control 59 0.0 2 Treatment 90 0.8 3 Treatment 47 0.1 4 Treamment 106 0.1 5 Control 85 0.7 6 Treatment 73 0.6 7 Control 61 0.2 8 AVERAGES 74 0.3 Thanks!

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  • Adding A New Row Using SQL Server Management Studio

    - by Soo
    I'm learning how to use SQL Server Management Studio and can't figure out how to insert a new row into a table. Table Structure: ID, Field1, Field2 Query: INSERT INTO Table (Field1,Field2) VALUES(1,2) Error: Major Error 0x80040E14, Minor Error 25503 I'm probably missing something very noobie like. Any help would be appreciated.

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  • SQL Join only returning 1 row.

    - by kevin
    Not quite sure what I'm missing, but my SQL statement is only returning one row. SELECT tl.*, (tl.topic_total_rating/tl.topic_rates) as topic_rating, COUNT(pl.post_id) - 1 as reply_count, MIN(pl.post_time) AS topic_time, MAX(pl.post_time) AS topic_bump FROM topic_list tl JOIN post_list pl ON tl.topic_id=pl.post_parent WHERE tl.topic_board_link = %i AND topic_hidden != 1 ORDER BY %s I have two tables (post_list and topic_list), and post_list's post_parent links to a topic_list's topic_id. Instead of returning all the topics (where their board's topic_board_link is n), it only returns one topic.

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  • Get Row of DataGrid in User Control Page

    - by Romil
    My Question is related to access the rows in one page and putting conditions in another page. I need to check whether a datagrid has row in it or not. DataGrid is in .aspx page. Based on this checking i need to write a condition in .ascx page. the .ascx on which condition is checked is linked to .aspx page. Meaning that UserControl1.ascx is Register with Default.aspx page I am using VS 2003 Please advice Thanks

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  • LINQ display row numbers

    - by timvaines
    I simply want to include a row number against the returned results of my query. I found the following post that describes what I am trying to achieve but gives me an exception http://vaultofthoughts.net/LINQRowNumberColumn.aspx "An expression tree may not contain an assignment operator" In MS SQL I would just use the ROWNUMBER() function, I'm simply looking for the equivalent in LINQ.

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