Search Results

Search found 25118 results on 1005 pages for 'jquery ui tabs'.

Page 382/1005 | < Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >

  • How can i check if key is pressed during click event with jquery?

    - by daniel smith
    Hi, I would like to catch a click event with jquery and be able to tell if a key was pressed at the same time so i can fork within the callback function based on the keypress. for example: $("button").click(function() { if([KEYPRESSED WHILE CLICKED]) { do something... } else { do something different... } }); Does anyone know if this is possible at all or how it can be done if it is possible?

    Read the article

  • How to give user message and choice before ActionLink

    - by RememberME
    I have the following link. On click, I'd like to check the item.primary_company field and if populated, give the user a warning and ask if they would like to continue. How can I do this? <a href="<%= Url.Action("Activate", new {id = item.company_id}) %>" class="fg=button fg-button-icon-solo ui-state-default ui-corner-all"><span class="ui-icon ui-icon-refresh"></span></a>

    Read the article

  • Jquery: Is there some way to make val() return an empty string instead of 'undefined' for an empty list?

    - by Chris
    With Jquery, is there some way to make val() return an empty string instead of 'undefined' when called against an empty list of elements? E.g., I have this code: var x = $('#my-textbox-id').not('.watermark').val(); The idea is that I want to get the value of my textbox, but I want an empty string if it is currently showing the watermark (i don't want the watermark value!). The selector works, but i don't want 'undefined' - I want an empty string ''.

    Read the article

  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

    Read the article

  • Is there a jQuery widget equal to DOJO's TitlePane?

    - by Bill Caswell
    I like the visual behavior of the DOJO TitlePane widget, but it has too much other bunk for my purpose. http://dojotoolkit.org/reference-guide/dijit/TitlePane.html#dijit-titlepane Is anyone aware of a jQuery widget that provides the same ability to expose and hide content in a stacked manner with the little flippy-arrow, pane highlighting on mouse over, etc? An accordion does not accomplish my goal being able to have multiple panes open at the same time. Thanks in advance.

    Read the article

  • jQuery - Show field based on value of a type-hidden on refresh.

    - by Sebhael
    Hello, I'm trying to create something in jQuery and having a bit of problems with it. I'm not too adept on the framework, so I'm sure this is all wrong. Anyways, the ultimate goal is a full form that contains 3 radio buttons - depending on the value of the button, a LI is shown. I have all of that done, but my problem is coming with validation. If something fails then the page is reloaded and the div that was selected doesn't show without clicking another radio first, then back to the original. This process is basically the same as someone came up with here. Here's what I got so far. HTML <li> <label> License (radio) </label> <label for="commercial" class="checkBox"> Commercial </label> <input type="radio" name="license" value="commercial" id="commercial" class="checkBox" <?php echo set_radio('license', 'commercial'); ?> /> <label for="abandonware" class="checkBox"> Abandonware </label> <input type="radio" name="license" value="abandonware" id="abandonware" class="checkBox" <?php echo set_radio('license', 'abandonware'); ?> /> <label for="freeware" class="checkBox"> Freeware </label> <input type="radio" name="license" value="freeware" id="freeware" class="checkBox" <?php echo set_radio('license', 'freeware'); ?> /> </li> This is followed by three LI's that contain id="commercial, abandonware, and freeware" and class="licenseli" My jQuery is, as said, something from here. $('li.licenseli').hide(); $('input[name=license]:radio').change(function(){ var Type = $(this).val(); // Get value of radio $('li.licenseli').slideUp(); // Hide non-selected $('li#'+Type).slideDown(); // Show Selected }); So what I need help with is I have a hidden input that retrieves the value of the radio box from validation - I want to take this value (or the radio's if possible?) and have the original selected option's LI already visible.

    Read the article

  • How to get object values and properties in jquery ?

    - by Rachel
    I am using jQuery selector to get the values of all CMS components on the page using $('div.cmscomponent') but how can I test this to see if am actually getting the list of compoents on the page. I use: var temp = $('div.cmscomponent'); alert(temp); and result that I get is [object OBJECT] and so how can I test this ? and how can I get values of the object and its properties.

    Read the article

  • Weirdness using jquery's .html() function to set <a></a> with a special character &#10003; (checkmar

    - by Sam
    Hey all, I'm trying to have the following tag toggle between a "-" and the checkmark character (✓) <a id='p_4' class='fancy_button orange bls_button' href='#'>-</a> And here's the jquery code: if (button.text() == '-') { button.html('&#10003'); } This works in FF3.6 and IE8, but not in WebKit (Chrome or iPhone safari). Is there something I'm doing wrong, or does webkit just not like .html("✓") Thanks, Sam

    Read the article

  • WPF tabswitch/ render takes too much time..

    - by Socrates
    I have a WPF application with many tabs.. in one tab.. i make a verycomplex vector drawing consisting of thousands of drawing visuals.. (this represents a machine and all elements need to be interactable..) It takes 3/4 seconds for drawing this for the first time..After the first draw it should be done.. The problem is if i switch to another tab and comeback, it takes atlease 2,3 seconds to show the tabpage with drawing again.. Since there is no redraw, why should it take so much time..?

    Read the article

< Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >