Search Results

Search found 14399 results on 576 pages for 'python noob'.

Page 382/576 | < Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >

  • How to separate comma separeted data from csv file?

    - by Rahul
    I have opened a csv file and I want to sort each string which is comma separeted and are in same line: ex:: file : name,sal,dept tom,10000,it o/p :: each string in string variable I have a file which is already open, so I can not use "open" API, I have to use "csv.reader" which have to read one line at a time.

    Read the article

  • PyParsing: Is this correct use of setParseAction()?

    - by Rosarch
    I have strings like this: "MSE 2110, 3030, 4102" I would like to output: [("MSE", 2110), ("MSE", 3030), ("MSE", 4102)] This is my way of going about it, although I haven't quite gotten it yet: def makeCourseList(str, location, tokens): print "before: %s" % tokens for index, course_number in enumerate(tokens[1:]): tokens[index + 1] = (tokens[0][0], course_number) print "after: %s" % tokens course = Group(DEPT_CODE + COURSE_NUMBER) # .setResultsName("Course") course_data = (course + ZeroOrMore(Suppress(',') + COURSE_NUMBER)).setParseAction(makeCourseList) This outputs: >>> course.parseString("CS 2110") ([(['CS', 2110], {})], {}) >>> course_data.parseString("CS 2110, 4301, 2123, 1110") before: [['CS', 2110], 4301, 2123, 1110] after: [['CS', 2110], ('CS', 4301), ('CS', 2123), ('CS', 1110)] ([(['CS', 2110], {}), ('CS', 4301), ('CS', 2123), ('CS', 1110)], {}) Is this the right way to do it, or am I totally off? Also, the output of isn't quite correct - I want course_data to emit a list of course symbols that are in the same format as each other. Right now, the first course is different from the others. (It has a {}, whereas the others don't.)

    Read the article

  • Django finding which field matched in a multiple OR query

    - by Greg Hinch
    I've got a couple models which are set up something like this: class Bar(models.Model): baz = models.CharField() class Foo(models.Model): bar1 = models.ForeignKey(Bar) bar2 = models.ForeignKey(Bar) bar3 = models.ForeignKey(Bar) And elsewhere in the code, I end up with an instance of Bar, and need to find the Foo it is attached to in some capacity. Right now I came up with doing a multiple OR query using Q, something like this: foo_inst = Foo.objects.get(Q(bar1=bar_inst) | Q(bar2=bar_inst) | Q(bar3=bar_inst)) What I need to figure out is, which of the 3 cases actually hit, at least the name of the member (bar1, bar2, or bar3). Is there a good way to do this? Is there a better way to structure the query to glean that information?

    Read the article

  • Testing for the existence of a field in a class

    - by Brett
    Hi, i have a quick question. I have a 2D array that stores an instance of a class. The elements of the array are assigned a particular class based on a text file that is read earlier in the program. Since i do not know without looking in the file what class is stored at a particular element i could refer to a field that doesn't exist at that index (referring to appearance when an instance of temp is stored in that index). i have come up with a method of testing this, but it is long winded and requires a second matrix. Is there a function to test for the existence of a field in a class? class temp(): name = "default" class temp1(): appearance = "@"

    Read the article

  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

    Read the article

  • Looping through a directory on the web and displaying its contents (files and other directories) via

    - by al jaffe
    In the same vein as http://stackoverflow.com/questions/2593399/process-a-set-of-files-from-a-source-directory-to-a-destination-directory-in-pyth I'm wondering if it is possible to create a function that when given a web directory it will list out the files in said directory. Something like... files[] for file in urllib.listdir(dir): if file.isdir: # handle this as directory else: # handle as file I assume I would need to use the urllib library, but there doesn't seem to be an easy way of doing this, that I've seen at least.

    Read the article

  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

    Read the article

  • Improving the join of two wave file?

    - by kaki
    I have written a code for joining two wave files.It works fine when i am joining larger segments but as i need to join very small segments the clarity is not good. I have learned that the signal processing technique such a windowed join can be used to improve the joining of file. y[n] = w[n]s[n] Multiply value of signal at sample number n by the value of a windowing function hamming window w[n]= .54 - .46*cos(2*Pi*n)/L 0 I am not understanding how to get the value to signal at sample n and how to implement this?? the code i am using for joining is import wave m=['C:/begpython/S0001_0002.wav', 'C:/begpython/S0001_0001.wav'] i=1 a=m[i] infiles = [a, "C:/begpython/S0001_0002.wav", a] outfile = "C:/begpython/S0001_00367.wav" data= [] data1=[] for infile in infiles: w = wave.open(infile, 'rb') data1=[w.getnframes] data.append( [w.getparams(), w.readframes(w.getnframes())] ) #data1 = [ord(character) for character in data1] #print data1 #data1 = ''.join(chr(character) for character in data1) w.close() output = wave.open(outfile, 'wb') output.setparams(data[0][0]) output.writeframes(data[0][1]) output.writeframes(data[1][1]) output.writeframes(data[2][1]) output.close()

    Read the article

  • How do I compare two complex data structures?

    - by Phil H
    I have some nested datastructures, each something like: [ ('foo', [ {'a':1, 'b':2}, {'a':3.3, 'b':7} ]), ('bar', [ {'a':4, 'd':'efg', 'e':False} ]) ] I need to compare these structures, to see if there are any differences. Short of writing a function to explicitly walk the structure, is there an existing library or method of doing this kind of recursive comparison?

    Read the article

  • Pickling a class definition

    - by Giorgio
    Is there a way to pickle a class definition? What I'd like to do is pickle the definition (which may created dynamically), and then send it over a TCP connection so that an instance can be created on the other end. I understand that there may be dependencies, like modules and global variables that the class relies on. I'd like to bundle these in the pickling process as well, but I'm not concerned about automatically detecting the dependencies because it's okay if the onus is on the user to specify them.

    Read the article

  • How to write data by dynamic parameter name

    - by Maxim Welikobratov
    I need to be able to write data to datastore of google-app-engine for some known entity. But I don't want write assignment code for each parameter of the entity. I meen, I don't want do like this val_1 = self.request.get('prop_1') val_2 = self.request.get('prop_2') ... val_N = self.request.get('prop_N') item.prop_1 = val_1 item.prop_2 = val_2 ... item.prop_N = val_N item.put() instead, I want to do something like this args = self.request.arguments() for prop_name in args: item.set(prop_name, self.request.get(prop_name)) item.put() dose anybody know how to do this trick?

    Read the article

  • Django - urls.py - Filenames with a hash/pound (#) sign?

    - by miya
    I'm using django and realized that when the filename that the user wants to access (let's say a photo) has the pound sign, the entry in the url.py does not match. Any ideas? url(r'^static/(?P<path>.*)$', 'django.views.static.serve', {'document_root': MEDIA_ROOT}, it just says: "/home/user/project/static/upload/images/hello" does not exist when actually the name of the file is: hello#world.jpg Thanks, Nico

    Read the article

  • Djangoo Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

    Read the article

  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

    Read the article

  • wsgi-served page does not refresh

    - by Steve
    I recently got my first app to work in uWSGI with Cherokee. I used the following code taken from the uWSGI docs: def application(environ, start_response): start_response('200 OK', [('Content-Type', 'text/plain')]) yield 'Hello World\n' The page correctly reads Hello World. When I change that text to New Thing and refresh, nothing changes. What am I forgetting? What I've tried: clearing browser history and cache stopping and starting Cherokee

    Read the article

  • Need a workaround to filter on related model and aggregated fields in Django

    - by parxier
    I opened a ticket for this problem. In a nutshell here is my model: class Plan(models.Model): cap = models.IntegerField() class Phone(models.Model): plan = models.ForeignKey(Plan, related_name='phones') class Call(models.Model): phone = models.ForeignKey(Phone, related_name='calls') cost = models.IntegerField() I want to run a query like this one: Phone.objects.annotate(total_cost=Sum('calls__cost')).filter(total_cost__gte=0.5*F('plan__cap')) Unfortunately Django generates bad SQL: SELECT "app_phone"."id", "app_phone"."plan_id", SUM("app_call"."cost") AS "total_cost" FROM "app_phone" INNER JOIN "app_plan" ON ("app_phone"."plan_id" = "app_plan"."id") LEFT OUTER JOIN "app_call" ON ("app_phone"."id" = "app_call"."phone_id") GROUP BY "app_phone"."id", "app_phone"."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan"."cap" and errors with: ProgrammingError: column "app_plan.cap" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan".... Is there any workaround apart from running raw SQL?

    Read the article

  • Should I use a metaclass, class decorator, or override the __new__ method?

    - by 007brendan
    Here is my problem. I want the following class to have a bunch of property attributes. I could either write them all out like foo and bar, or based on some other examples I've seen, it looks like I could use a class decorator, a metaclass, or override the __new__ method to set the properties automagically. I'm just not sure what the "right" way to do it would be. class Test(object): def calculate_attr(self, attr): # do calculaty stuff return attr @property def foo(self): return self.calculate_attr('foo') @property def bar(self): return self.calculate_attr('bar')

    Read the article

  • How to display multiple images?

    - by misterwebz
    I'm trying to get multiple image paths from my database in order to display them, but it currently doesn't work. Here's what i'm using: def get_image(self, userid, id): image = meta.Session.query(Image).filter_by(userid=userid) permanent_file = open(image[id].image_path, 'rb') if not os.path.exists(image.image_path): return 'No such file' data = permanent_file.read() permanent_file.close() response.content_type = guess_type(image.image_path)[0] or 'text/plain' return data I'm getting an error regarding this part: image[id].image_path What i want is for Pylons to display several jpg files on 1 page. Any idea how i could achieve this?

    Read the article

  • Pass errors in Django using HttpResponseRedirect

    - by JPC
    I know that HttpResponseRedirect only takes one parameter, a URL. But there are cases when I want to redirect with an error message to display. I was reading this post: How to pass information using an http redirect (in Django) and there were a lot of good suggestions. I don't really want to use a library that I don't know how works. I don't want to rely on messages which, according to the Django docs, is going to be removed. I thought about using sessions. I also like the idea of passing it in a URL, something like: return HttpResponseRedirect('/someurl/?error=1') and then having some map from error code to message. Is it good practice to have a global map-like structure which hard codes in these error messages or is there a better way? Or should I just use a session EDIT: I got it working using a session. Is that a good practice to put things like this in the session?

    Read the article

  • PyGTK: Trouble with size of ScrolledWindow

    - by canavanin
    Hi everyone! I am using PyGTK and the gtk.Assistant. On one page I have placed a treeview (one column, just strings) in a gtk.ScrolledWindow (I wanted the vertical scrollbar, since the list contains about 35 items). Everything is working fine; the only thing that bugs me is that I have not been able to figure out from the documentation how to set the size of the scrolled window. Currently only three items are displayed at a time; I would like to set this number to 10 or so. Below is the code. As you can see I have tried using a gtk.Adjustment to influence the scrolled window's size, but as - once more - I have been incompetent at retrieving the required info from the documentation, I don't actually know what values should be put into there. self.page7 = gtk.VBox() # The gtk.Adjustment: page_size = gtk.Adjustment(lower=10, page_size=100) # just used some arbitrary numbers here >_< scrolled_win = gtk.ScrolledWindow(page_size) scrolled_win.set_policy(gtk.POLICY_AUTOMATIC, gtk.POLICY_AUTOMATIC) # only display scroll bars when required self.character_traits_treeview = gtk.TreeView() self.character_traits_treestore = gtk.TreeStore(str) self.character_traits_treeview.set_model(self.character_traits_treestore) tc = gtk.TreeViewColumn("Character traits") self.character_traits_treeview.append_column(tc) cr = gtk.CellRendererText() tc.pack_start(cr, True) tc.add_attribute(cr, "text", 0) self.character_trait_selection = self.character_traits_treeview.get_selection() self.character_trait_selection.connect('changed', self.check_number_of_character_trait_selections) self.character_trait_selection.set_mode(gtk.SELECTION_MULTIPLE) self.make_character_traits_treestore() # adding the treeview to the scrolled window: scrolled_win.add(self.character_traits_treeview) self.page7.pack_start(scrolled_win, False, False, 0) self.assistant.append_page(self.page7) self.assistant.set_page_title(self.page7, "Step 7: Select 2-3 character traits") self.assistant.set_page_type(self.page7, gtk.ASSISTANT_PAGE_CONTENT) self.assistant.set_page_complete(self.page7, False) def check_number_of_character_trait_selections(self, blah): # ... def make_character_traits_treestore(self): # ... I know I should RTFM, but as I can't make head or tail of it, and as further searching, too, has been to no avail, I'm just hoping that someone on here can give me a hint. Thanks a lot in advance! PS: Here are the links to: the gtk.ScrolledWindow documentation the gtk.Adjustment documentation

    Read the article

  • Validating key/certificate pairs with M2Crypto when a certificate chain is needed

    - by Charles Duffy
    M2Crypto.X509.X509 objects have a verify(pkey) method, which provide a means of testing that a given certificate does in fact sign a specified key. This is a good and useful thing -- except that sometimes the certificate I want to verify in this way is invalid without the use of an intermediate certificate, which this API does not appear to allow a way to specify. Is there an alternate means of validating a certificate / private key pair which will work even when the certificate is unable to stand alone?

    Read the article

  • passing self data into a recursive function

    - by user272689
    I'm trying to set a function to do something like this def __binaryTreeInsert(self, toInsert, currentNode=getRoot(), parentNode=None): where current node starts as root, and then we change it to a different node in the method and recursivly call it again. However, i cannot get the 'currentNode=getRoot()' to work. If i try calling the funcion getRoot() (as above) it says im not giving it all the required variables, but if i try to call self.getRoot() it complains that self is an undefined variable. Is there a way i can do this without having to specify the root while calling this method?

    Read the article

< Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >