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  • jQuery plugin options: required, optional, inaccessible

    - by Trevor Hartman
    I'm curious how to specify options to a jQuery plugin in a way that some are required, some are optionally overridden, and some can't be touched. I started off with the usual: jQuery.fn.plugin = function (options){ var defaults = { username: "", posts:10, api: "http://myapi.com" } var settings = jQuery.extend({}, defaults, options); } Let's say I want username to be required, posts is optional (defaults to 10) and you (you being the user of the plugin) can't change api, even if they try. Ideally, they'd all still be in the same data structure instead of being split into separate objects. Ideas?

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  • Histogram matching - image processing - c/c++

    - by Raj
    Hello I have two histograms. int Hist1[10] = {1,4,3,5,2,5,4,6,3,2}; int Hist1[10] = {1,4,3,15,12,15,4,6,3,2}; Hist1's distribution is of type multi-modal; Hist2's distribution is of type uni-modal with single prominent peak. My questions are Is there any way that i could determine the type of distribution programmatically? How to quantify whether these two histograms are similar/dissimilar? Thanks

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  • Avoid implicit conversion from date to timestamp for selects with Oracle using Hibernate

    - by sapporo
    I'm using Hibernate 3.2.7.GA criteria queries to select rows from an Oracle Enterprise Edition 10.2.0.4.0 database, filtering by a timestamp field. The field in question is of type java.util.Date in Java, and DATE in Oracle. It turns out that the field gets mapped to java.sql.Timestamp, and Oracle converts all rows to TIMESTAMP before comparing to the passed in value, bypassing the index and thereby ruining performance. One solution would be to use Hibernate's sqlRestriction() along with Oracle's TO_DATE function. That would fix performance, but requires rewriting the application code (lots of queries). So is there a more elegant solution? Since Hibernate already does type mapping, could it be configured to do the right thing? Update: The problem occurs in a variety of configurations, but here's one specific example: Oracle Enterprise Edition 10.2.0.4.0 Oracle JDBC Driver 11.1.0.7.0 Hibernate 3.2.7.GA Hibernate's Oracle10gDialect Java 1.6.0_16

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  • JQuery JQGrid local data loading issue

    - by ollie314
    Hi, I've got a problem with the following code <script type="text/javascript"> var mydata = [ {id:"1",name:"foo"},{id:"2",name:"bar"} ]; jQuery(document).ready(function() { jQuery("#lgrid").jqGrid({ data: mydata, datatype: "local", height: 150, width:600, rowNum: 10, rowList: [10,20,30], colNames:['id','name'], colModel:[ {name:'id',index:'id', width:60, sorttype:"int"}, {name:'name',index:'name', width:60}], pager: "#pgrid", viewrecords: true, caption: "Contacts" }); }); </script> And In the body .... <table id="lgrid"></table> <div id="pgrid"></div> With this code, I never display the data into the grid. Somebody has an idea about this issue ? Thanks.

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  • call WCF Service from SSL Enabled website

    - by Usama Khalil
    how can i call service from a ssl enabled website to a WCF service with basicHTTPBinding. i am getting the error The requested service, 'http://10.5.1.111/HRMSService/VehicleMaintenance/VehicleMaintenance.svc/test' could not be activated. See the server's diagnostic trace logs for more information. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.ServiceModel.ServiceActivationException: The requested service, 'http://10.5.1.111/HRMSService/VehicleMaintenance/VehicleMaintenance.svc/test' could not be activated. See the server's diagnostic trace logs for more information. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using

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  • Unit Testing functions within repository interfaces - ASP.net MVC3 & Moq

    - by RawryLions
    I'm getting into writing unit testing and have implemented a nice repository pattern/moq to allow me to test my functions without using "real" data. So far so good.. However.. In my repository interface for "Posts" IPostRepository I have a function: Post getPostByID(int id); I want to be able to test this from my Test class but cannot work out how. So far I am using this pattern for my tests: [SetUp] public void Setup() { mock = new Mock<IPostRepository>(); } [Test] public void someTest() { populate(10); //This populates the mock with 10 fake entries //do test here } In my function "someTest" I want to be able to call/test the function GetPostById. I can find the function with mock.object.getpostbyid but the "object" is null. Any help would be appreciated :) iPostRepository: public interface IPostRepository { IQueryable<Post> Posts {get;} void SavePost(Post post); Post getPostByID(int id); }

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  • Tomcat fails on first request in combination with jsvc

    - by Roalt
    I have a web application where the first request may take a few seconds as some singletons are initialised. I've used the mod_proxy and jsvc construction mentioned in this question and described on this page to connect apache with tomcat (data is served via SSL) For the sample Tomcat application, everything works as it should. However, when using my application I get the following error in my apache log: [Wed Feb 10 09:48:29 2010] [error] [client 130.12.1.26] (70014)End of file found: proxy: error reading status line from remote server localhost [Wed Feb 10 09:48:29 2010] [error] [client 130.12.1.26] proxy: Error reading from remote server returned by /MyWebApp/MyWebApp.faces and I get the following error in my tomcat output: 10/02/2010 09:48:29 9947 jsvc.exec error: Service exit with a return value of 1 I'm not an expert on this so I would like to know what's the cause of the problem and where I should look for an answer?

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  • Can you add identity to existing column in sql server 2008?

    - by bmutch
    In all my searching I see that you essentially have to copy the existing table to a new table to chance to identity column for pre-2008, does this apply to 2008 also? thanks. most concise solution I have found so far: CREATE TABLE Test ( id int identity(1,1), somecolumn varchar(10) ); INSERT INTO Test VALUES ('Hello'); INSERT INTO Test VALUES ('World'); -- copy the table. use same schema, but no identity CREATE TABLE Test2 ( id int NOT NULL, somecolumn varchar(10) ); ALTER TABLE Test SWITCH TO Test2; -- drop the original (now empty) table DROP TABLE Test; -- rename new table to old table's name EXEC sp_rename 'Test2','Test'; -- see same records SELECT * FROM Test;

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  • Failed opening 'SiteTest: Firefox.php' when running Yii Functional Test

    - by Phelios
    Warning: include(): Failed opening 'SiteTest: Firefox.php' for inclusion ... \yii\framework\YiiBase.php on line 418 Yii v1.1.10 PHPUnit v3.6.10 PHPUnit_Selenium v 1.2.6 I get this error when trying to run the example on the book "Agile Web Development with Yii 1.1 and PHP5" I kind of feel that there is a problem with the phrase SiteTest:, it shouldn't be there. But, how do I fix this? UPDATE (SOLVED): Apparently, the problem is not the warning shown above, but there is another error down the road. It says that "curl_init()" is undefined. I already enabled the php_curl extension, but the PHP from CLI is not using the same .ini file as the apache one. So, after I enabled the php_curl in the CLI version of the ini, it works fine now (still giving the warning, but the test is running).

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  • How can a 1Gb Java heap on a 64bit machine use 3Gb of VIRT space?

    - by Graeme Moss
    I run the same process on a 32bit machine as on a 64bit machine with the same memory VM settings (-Xms1024m -Xmx1024m) and similar VM version (1.6.0_05 vs 1.6.0_16). However the virtual space used by the 64bit machine (as shown in top under "VIRT") is almost three times as big as that in 32bit! I know 64bit VMs will use a little more memory for the larger references, but how can it be three times as big? Am I reading VIRT in top incorrectly? Full data shown below, showing top and then the result of jmap -heap, first for 64bit, then for 32bit. Note the VIRT for 64bit is 3319m for 32bit is 1220m. * 64bit * PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 22534 agent 20 0 3319m 163m 14m S 4.7 2.0 0:04.28 java $ jmap -heap 22534 Attaching to process ID 22534, please wait... Debugger attached successfully. Server compiler detected. JVM version is 10.0-b19 using thread-local object allocation. Parallel GC with 4 thread(s) Heap Configuration: MinHeapFreeRatio = 40 MaxHeapFreeRatio = 70 MaxHeapSize = 1073741824 (1024.0MB) NewSize = 2686976 (2.5625MB) MaxNewSize = -65536 (-0.0625MB) OldSize = 5439488 (5.1875MB) NewRatio = 2 SurvivorRatio = 8 PermSize = 21757952 (20.75MB) MaxPermSize = 88080384 (84.0MB) Heap Usage: PS Young Generation Eden Space: capacity = 268500992 (256.0625MB) used = 247066968 (235.62142181396484MB) free = 21434024 (20.441078186035156MB) 92.01715277089181% used From Space: capacity = 44695552 (42.625MB) used = 0 (0.0MB) free = 44695552 (42.625MB) 0.0% used To Space: capacity = 44695552 (42.625MB) used = 0 (0.0MB) free = 44695552 (42.625MB) 0.0% used PS Old Generation capacity = 715849728 (682.6875MB) used = 0 (0.0MB) free = 715849728 (682.6875MB) 0.0% used PS Perm Generation capacity = 21757952 (20.75MB) used = 16153928 (15.405586242675781MB) free = 5604024 (5.344413757324219MB) 74.24378912132907% used * 32bit * PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 30168 agent 20 0 1220m 175m 12m S 0.0 2.2 0:13.43 java $ jmap -heap 30168 Attaching to process ID 30168, please wait... Debugger attached successfully. Server compiler detected. JVM version is 14.2-b01 using thread-local object allocation. Parallel GC with 8 thread(s) Heap Configuration: MinHeapFreeRatio = 40 MaxHeapFreeRatio = 70 MaxHeapSize = 1073741824 (1024.0MB) NewSize = 1048576 (1.0MB) MaxNewSize = 4294901760 (4095.9375MB) OldSize = 4194304 (4.0MB) NewRatio = 8 SurvivorRatio = 8 PermSize = 16777216 (16.0MB) MaxPermSize = 67108864 (64.0MB) Heap Usage: PS Young Generation Eden Space: capacity = 89522176 (85.375MB) used = 80626352 (76.89128112792969MB) free = 8895824 (8.483718872070312MB) 90.0629940005033% used From Space: capacity = 14876672 (14.1875MB) used = 14876216 (14.187065124511719MB) free = 456 (4.3487548828125E-4MB) 99.99693479832048% used To Space: capacity = 14876672 (14.1875MB) used = 0 (0.0MB) free = 14876672 (14.1875MB) 0.0% used PS Old Generation capacity = 954466304 (910.25MB) used = 10598496 (10.107513427734375MB) free = 943867808 (900.1424865722656MB) 1.1104107034039412% used PS Perm Generation capacity = 16777216 (16.0MB) used = 11366448 (10.839889526367188MB) free = 5410768 (5.1601104736328125MB) 67.74930953979492% used

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  • many-to-many query

    - by kofto4ka
    Hello, guys! I have a problem and I dont know what is better solution. Okay, I have 2 tables: posts(id, title), posts_tags(post_id, tag_id). I have next task: must select posts with tags ids for example 4, 10 and 11. Not exactly, post could have any other tags at the same time. So, how I could do it more optimized? Creating temporary table in each query? Or may be some kind of stored procedure? In the future, user could ask script to select posts with any count of tags (it could be 1 tag only or 10 at the same time) and I must be sure that method that I will choose would be the best method for my problem. Sorry for my english, thx for attention.

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  • php / mysql pagination

    - by arrgggg
    Hi, I have a table with 58 records in mysql database. I was able to connect to my database and retrive all records and made 5 pages with links to view each pages using php script. webpage will look like this: name number john 1232343456 tony 9878768544 jack 3454562345 joe 1232343456 jane 2343454567 andy 2344560987 marcy 9873459876 sean 8374623534 mark 9898787675 nancy 8374650493 1 2 3 4 5 that's the first page of 58 records and those 5 numbers at bottom are links to each page that will display next 10 records. I got all that. but what I want to do is display the links in this way: 1-10 11-20 21-30 31-40 41-50 51-58 note: since i have 58 records, last link will display upto 58, instead of 60. Since I used the loop to create this link, depending on how many records i have, the link will change according to the number of records in my table. How can i do this? Thanks.

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  • finishing some functions in this code

    - by osabri
    i have problem to finish some functions in this code program lab4; var inFile : text; var pArray : array[1..10]of real; //array of 10 integer values containing patterns to search in a given set of numbers var rArray : array[1..10]of integer; //array containing result of pattern search, each index in rArray coresponds to number of occurences of //pattern from pArray in sArray. var sArray : array[1..100] of real; //array containing data read from file var accuracy : real; (****************************************************************************) function errMsg:integer; begin if ParamCount < 3 then begin writeln('Too few arguments'); writeln('Usage: ./lab4 lab4.txt <accuracy> <pattern_1> <pattern_2> <pattern_n>'); errMsg:=-1; end else if ParamCount > 12 then begin writeln('Too many arguments'); writeln('Maximum number of patterns is 10'); errMsg:=-1; end else begin assign(inFile,ParamStr(1)); {$I-} reset(inFile); if ioresult<>0 then begin writeln('Cannot open ',ParamStr(1)); errMsg:=-1; end else errMsg:=0; end; end; (****************************************************************************) procedure readPattern; var errPos,idx:integer; begin if errMsg=0 then begin for idx:=1 to ParamCount-2 do begin Val(ParamStr(idx+2),pArray[idx],errPos); writeln('pArray:',pArray[idx]:2:2); end; end; end; (****************************************************************************) procedure getAccuracy; //Function should get the accuracy as the first param (after the program name) begin (here where i stopped : (( ) end; (****************************************************************************) function readSet:integer; //Function returns number of elements read from file var idx,errPos:integer; var sChar: string; begin if errMsg=0 then begin idx:=1; repeat begin readln(inFile,sChar); VAL(sChar,sArray[idx],errPos); writeln('sArray:',sArray[idx]:2:2); idx:=idx+1; end until eof(inFile)=TRUE; end; readSet:=idx-1; end; (****************************************************************************) procedure searchPattern(sNumber:integer); //Function should search and count pattern(patterns) occurence in a given set what the best solution for this part?? (****************************************************************************) procedure dispResult; //Function should display the result of pattern(patterns) search begin (****************************************************************************) begin readPattern; getAccuracy; searchPattern(readSet); dispResult; end.

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  • my server suddenly crashes every 2 days or so. Programmer has no idea, please help find the cause, here is the top

    - by Alex
    Every couple of days my server suddenly crashes and I must request hardware reset at data center to get it back running. Today I came back to my shell and saw the server was dead and "top" was running on it, and see below for the "top" right before the crash. I opened /var/log/messages and scrolled to the reboot time and see nothing, no errors prior to the hard reboot. (I checked in /etc/syslog.conf and I see "*.info;mail.none;authpriv.none;cron.none /var/log/messages" , isn't this good enough to log all problems?) Usually when I look at the top, the swap is never used up like this! I also don't know why mysqld is at 323% cpu (server only runs drupal and its never slow or overloaded). Solver is my application. I don't know whats that 'sh' doing and 'dovecot' doing. Its driving me crazy over the last month, please help me solve this mystery and stop my downtimes. top - 01:10:06 up 6 days, 5 min, 3 users, load average: 34.87, 18.68, 9.03 Tasks: 500 total, 19 running, 481 sleeping, 0 stopped, 0 zombie Cpu(s): 0.0%us, 96.6%sy, 0.0%ni, 1.7%id, 1.8%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 8165600k total, 8139764k used, 25836k free, 428k buffers Swap: 2104496k total, 2104496k used, 0k free, 8236k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 4421 mysql 15 0 571m 105m 976 S 323.5 1.3 9:08.00 mysqld 564 root 20 -5 0 0 0 R 99.5 0.0 2:49.16 kswapd1 25767 apache 19 0 399m 8060 888 D 79.3 0.1 0:06.64 httpd 25781 apache 19 0 398m 5648 492 R 79.0 0.1 0:08.21 httpd 25961 apache 25 0 398m 5700 560 R 76.7 0.1 0:17.81 httpd 25980 apache 25 0 10816 668 520 R 75.0 0.0 0:46.95 sh 563 root 20 -5 0 0 0 D 71.4 0.0 3:12.37 kswapd0 25766 apache 25 0 399m 7256 756 R 69.7 0.1 0:39.83 httpd 25911 apache 25 0 398m 5612 480 R 58.8 0.1 0:17.63 httpd 25782 apache 25 0 440m 38m 648 R 55.2 0.5 0:18.94 httpd 25966 apache 25 0 398m 5640 556 R 55.2 0.1 0:48.84 httpd 4588 root 25 0 74860 596 476 R 53.9 0.0 0:37.90 crond 25939 apache 25 0 2776 172 84 R 48.9 0.0 0:59.46 solver 4575 root 25 0 397m 6004 1144 R 48.6 0.1 1:00.43 httpd 25962 apache 25 0 398m 5628 492 R 47.9 0.1 0:14.58 httpd 25824 apache 25 0 440m 39m 680 D 47.3 0.5 0:57.85 httpd 25968 apache 25 0 398m 5612 528 R 46.6 0.1 0:42.73 httpd 4477 root 25 0 6084 396 280 R 46.3 0.0 0:59.53 dovecot 25982 root 25 0 397m 5108 240 R 45.9 0.1 0:18.01 httpd 25943 apache 25 0 2916 172 8 R 44.0 0.0 0:53.54 solver 30687 apache 25 0 468m 63m 1124 D 42.3 0.8 0:45.02 httpd 25978 apache 25 0 398m 5688 600 R 23.8 0.1 0:40.99 httpd 25983 root 25 0 397m 5272 384 D 14.9 0.1 0:18.99 httpd 935 root 10 -5 0 0 0 D 14.2 0.0 1:54.60 kjournald 25986 root 25 0 397m 5308 420 D 8.9 0.1 0:04.75 httpd 4011 haldaemo 25 0 31568 1476 716 S 5.6 0.0 0:24.36 hald 25956 apache 23 0 398m 5872 644 S 5.6 0.1 0:13.85 httpd 18336 root 18 0 13004 1332 724 R 0.3 0.0 1:46.66 top 1 root 18 0 10372 212 180 S 0.0 0.0 0:05.99 init 2 root RT -5 0 0 0 S 0.0 0.0 0:00.95 migration/0 3 root 34 19 0 0 0 S 0.0 0.0 0:00.01 ksoftirqd/0 4 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/0 5 root RT -5 0 0 0 S 0.0 0.0 0:00.15 migration/1 6 root 34 19 0 0 0 S 0.0 0.0 0:00 .06 ksoftirqd/1 here is a normal top, when server is working fine: top - 01:50:41 up 21 min, 1 user, load average: 2.98, 2.70, 1.68 Tasks: 271 total, 2 running, 269 sleeping, 0 stopped, 0 zombie Cpu(s): 15.0%us, 1.1%sy, 0.0%ni, 81.4%id, 2.4%wa, 0.1%hi, 0.0%si, 0.0%st Mem: 8165600k total, 2035856k used, 6129744k free, 60840k buffers Swap: 2104496k total, 0k used, 2104496k free, 283744k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 2204 apache 17 0 466m 83m 19m S 25.9 1.0 0:22.16 httpd 11347 apache 15 0 466m 83m 19m S 25.9 1.0 0:26.10 httpd 18204 apache 18 0 481m 97m 19m D 25.2 1.2 0:13.99 httpd 4644 apache 18 0 481m 100m 19m D 24.6 1.3 1:17.12 httpd 4727 apache 17 0 481m 99m 19m S 24.3 1.2 1:10.77 httpd 4777 apache 17 0 482m 102m 21m S 23.6 1.3 1:38.27 httpd 8924 apache 15 0 483m 99m 19m S 22.3 1.3 1:13.41 httpd 9390 apache 18 0 483m 99m 19m S 18.9 1.2 1:05.35 httpd 4728 apache 16 0 481m 101m 19m S 14.3 1.3 1:12.50 httpd 4648 apache 15 0 481m 107m 27m S 12.6 1.4 1:18.62 httpd 24955 apache 15 0 467m 82m 19m S 3.3 1.0 0:21.80 httpd 4722 apache 15 0 503m 118m 19m R 1.7 1.5 1:17.79 httpd 4647 apache 15 0 484m 105m 20m S 1.3 1.3 1:40.73 httpd 4643 apache 16 0 481m 100m 20m S 0.7 1.3 1:11.80 httpd 1561 root 15 0 12900 1264 828 R 0.3 0.0 0:00.54 top 4434 mysql 15 0 496m 55m 4812 S 0.3 0.7 0:06.69 mysqld 4646 apache 15 0 481m 100m 19m S 0.3 1.3 1:25.51 httpd 1 root 18 0 10372 692 580 S 0.0 0.0 0:02.09 init 2 root RT -5 0 0 0 S 0.0 0.0 0:00.03 migration/0 3 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/0 4 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/0 5 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/1 6 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/1 7 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/1 8 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/2 9 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/2 10 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/2 11 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/3 12 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/3 13 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/3 14 root RT -5 0 0 0 S 0.0 0.0 0:00.03 migration/4 15 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/4 16 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/4 17 root RT -5 0 0 0 S 0.0 0.0 0:00.02 migration/5 18 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/5 19 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/5 20 root RT -5 0 0 0 S 0.0 0.0 0:00.01 migration/6 21 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/6 22 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/6 23 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/7

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  • Packet Crafting on a Mac

    - by JayCrossler
    I think (based on searching the forums), that NetCat is the best option, but wanted to hear if others are preferable. Anyone have good success with a packet-crafting tool (specifically on Mac)? I've tried HPing, but had some issues. I'm looking into NetCat ('nc' on mac) now, but it's not working as I had thought. Basically, I captured some packets that a remote control sends over a wifi network to turn lights on and off (using X10 controllers), and am looking for a way to replay them by crafting a TCP packet from the command line. I used Wireshark to sniff the traffic, so I know the package is: DEVICE -sendplc-"C4 DIM 10" I'm trying: echo 'DEVICE -sendplc-"C4 DIM 10"' nc 192.168.2.196 6003 but there's no response from the receiving system. The exact bytestream is (if anyone wants to check that I got the right dataframe): 08004642f1b400260897ad6308004500004b08e240004006aaf5c0a802c1c0a802c4d8d7177399aab39 e57ff4753801880ae37ea00000101080a323353ce01b406424445564943457e73656e64706c637e2243 34204f4e220a Next step I'm going to check is to make sure the packet arrives exactly by sniffing and compare it to the original. [EDIT: Also at ServerFault now: Packet Crafting on a Mac, so this one becomes a duplicate across the two sites]

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  • Efficient way to create/unpack large bitfields in C?

    - by drhorrible
    I have one microcontroller sampling from a lot of ADC's, and sending the measurements over a radio at a very low bitrate, and bandwidth is becoming an issue. Right now, each ADC only give us 10 bits of data, and its being stored in a 16-bit integer. Is there an easy way to pack them in a deterministic way so that the first measurement is at bit 0, second at bit 10, third at bit 20, etc? To make matters worse, the microcontroller is little endian, and I have no control over the endianness of the computer on the other side.

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  • What happens when several Java servlet apps running on the same port ?

    - by Frank
    Something strange happened to my servlets and I think I've figured out why, yet I'm more confused. I used Netbean6.7 to develop a Paypal IPN (Instant Payment Notification) message servlet, it listens on port 8080 by default for Paypal IPN messages. I used some sample Java code from it's web site, but when it ran, only about 1 in 10 messages came through, and they looked correct, but why 1 in 10 ? Not 100% or none ? So I asked some questions here and got some advices, one in particular points me to Google's App Engine, so I downloaded it and ran the demo guestbook while my IPN servlet is still running on Netbeans, the strange thing happened, after I entered "appengine-java-sdk-1.3.2\bin\dev_appserver.cmd appengine-java-sdk-1.3.2\demos\guestbook\war" from the command prompt, I went to the following url on my browser "http://localhost:8080/", I thought I would see the Google demo guestbook page, NO, what I saw was another servlet I developed 2 years ago : "Web Academy", online course registration app. How can that happen ? I never started it, and I haven't touch that project for years. I guess because it's also listening on port 8080, so now I understand why the IPN messages only came through 1 in 10 times, because another servlet was also listening on that port and could have got the messages intended for IPN, or some how those two servlets' processes mixed up and therefore couldn't respond to Paypal properly, and failed. In order to verify some of my guesses, I turn off Netbeans, and ran the Google guestbook again at the prompt, this time on my browser http://localhost:8080/ points to the demo guestbook page. My Urls look like this : [A] Paypal IPN : http://localhost:8080/PayPal_App/PayPal_Servlet [B] Web Academy : http://localhost:8080/ So now, my questions are : <1> Why the "Web Academy" servlet was auto started when I ran the Paypal servlet ? <2> If I change the IPN listening port to 8083, would that mean I can run both of them on my PC at the same time without affecting each other ? <3> But I still don't understand, [A] and [B] look different, if a page for [A] is refreshed, it should show the Paypal content, and another page looking at [B] should show the Web Academy content, and that's exactly what happens when I started Netbeans to run the Paypal servlet, both pages show their respective content correctly side by side without interfering with each other, how come the IPN messages couldn't get through 100% of the time ? <4> In Netbeans how to assign 8080 to servlet [A] and assign port 8083 to servlet [B] ? <5> How to turn off auto start of Web Academy by Netbeans ?

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  • DB2 load partitioned data in parallel

    - by Erik Paulson
    I have a 10-node DB2 9.5 database, with raw data on each machine (ie node1:/scratch/data/dataset.1 node2:/scratch/data/dataset.2 ... node10:/scratch/data/dataset.10 There is no shared NFS mount - none of my machines could handle all of the datasets combined. each line of a dataset file is a long string of text, column delimited. The first column is the key. I don't know the hash function that DB2 will use, so dataset is not pre-partitioned. Short of renaming all of my files, is there any way to get DB2 to load them all in parallel? I'm trying to do something like load from '/scratch/data/dataset' of del modified by coldel| fastparse messages /dev/null replace into TESTDB.data_table part_file_location '/scratch/data'; but I have no idea how to suggest to db2 that it should look for dataset.1 on the first node, etc.

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  • Store data for songs MySQL DB

    - by Johan
    I'm storing a huge set of songs in a MySQL database. This is what I store in the 'songs' table: CREATE TABLE `songs` ( `song_id` int(10) unsigned NOT NULL auto_increment, `song_artist` varchar(255) NOT NULL, `song_track` varchar(255) NOT NULL, `song_mix` varchar(255) NOT NULL, `song_title` text NOT NULL, `song_hash` varchar(40) NOT NULL, `song_addtime` int(10) unsigned NOT NULL, `song_source` text NOT NULL, `song_file` varchar(255) NOT NULL, PRIMARY KEY (`song_id`) ) ENGINE=MyISAM AUTO_INCREMENT=1857 DEFAULT CHARSET=latin1 Now I'd like to keep track of how many plays each song has, and other song-specific data that relates to the song. I don't want to keep adding fields to the 'songs' table for this. How can I store song related data a more efficient way? What's the best practice here?

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  • How to count incrementally in SQL SERVER

    - by joe
    Hi Folks, I am assigned a problem which i am not sure how to write it in SQL SEVER (version 5/8) yet. Here is the simple query and its output: Select location, date_time, Item_sold From Product Location Date_time Item_sold VA 12/10/2010 1:30:00 PM Candy VA 12/10/2010 3:30:00 PM Chips VA 12/13/2010 12:50:00 AM Wine DC 12/13/2010 8:00:00 AM Gum DC 12/13/2010 12:30:00 PM Bags DC 12/13/2010 1:16:00 PM Cheese DC 12/13/2010 12:00:00 AM Hotdog NJ 12/15/2010 12:00:00 AM Coffee NJ 12/15/2010 1:15:00 PM Beers NJ 12/15/2010 3:45:00 AM Cream Here is my desired output, which I guess a while/for loop or a pivot function could do the job but my experience is not there yet. Basically, I need to count the number of item sold from the Item_sold column incrementally (base line date starts from 12/8 to 12/9, 12/8 to 12/10, 12/8 to 12/11, 12/8 to 12/12...) I was wondering if anyone could edcuate and solve this problem. Many thanks in advance, Joe Location 12/8 |12/8-12/9 |12/8-12/10 |12/8 - 12/11 |12/8 - 12/12 |12/8 - 12/13 VA 0 0 2 0 0 3 DC 0 0 0 0 0 4

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  • How can I make Excel's MIN function ignore zeroes in a set?

    - by mfg
    In Excel, I have the following formula =(MIN(H69,H52,H35,H18)*(1/H18))*10 that is supposed to return the MIN of a range, and divide it by the current cell (*(1/H18) ), then multiply by 10. I am having difficulty with adding a type of NULLIF statement. I want to be able to have (the possibility for) blank rows, and have the MIN function ignore zero/blank fields while selecting the next lowest value (all are between 1.0-0.1). Is there a modifier i can apply to the MIN function to make it not compare zeroes in the MIN set? Is there a better funtion than MIN to use? This is to prevent the following situation: users will need to eliminate fields that are zeros from the form, theres 2 formula edits per entry, averaging 4 entries per use, so 8 possible errors per form use...

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  • Estimate serialization size of objects?

    - by Stefan K.
    In my thesis, I woud like to enhance messaging in a cluster. It's important to log runtime information about how big a message is (should I prefer processing local or remote). I could just find frameoworks about estimating the object memory size based on java instrumentation. I've tested classmexer, which didn't come close to the serialization size and sourceforge SizeOf. In a small testcase, SizeOf was around 10% wrong and 10x faster than serialization. (Still transient breaks the estimation completely and since e.g. ArrayList is transient but is serialized as an Array, it's not easy to patch SizeOf. But I could live with that) On the other hand, 10x faster with 10% error doesn't seem very good. Any ideas how I could do better?

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  • can lapply not modify variables in a higher scope

    - by stevejb
    I often want to do essentially the following: mat <- matrix(0,nrow=10,ncol=1) lapply(1:10, function(i) { mat[i,] <- rnorm(1,mean=i)}) But, I would expect that mat would have 10 random numbers in it, but rather it has 0. (I am not worried about the rnorm part. Clearly there is a right way to do that. I am worry about affecting mat from within an anonymous function of lapply) Can I not affect matrix mat from inside lapply? Why not? Is there a scoping rule of R that is blocking this?

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  • I am trying to move a rectangle in Pygame using coordinates but won't work

    - by user1821449
    this is my code import pygame from pygame.locals import * import sys pygame.init() pygame.display.set_caption("*no current mission*") size = (1280, 750) screen = pygame.display.set_mode(size) clock = pygame.time.Clock() bg = pygame.image.load("bg1.png") guy = pygame.image.load("hero_stand.png") rect = guy.get_rect() x = 10 y = 10 while True: for event in pygame.event.get(): if event.type == pygame.QUIT: sys.exit() if event.type == KEYDOWN: _if event.key == K_RIGHT: x += 5 rect.move(x,y)_ rect.move(x,y) screen.blit(bg,(0,0)) screen.blit(guy, rect) pygame.display.flip() it is just a simple test to see if i can get a rectangle to move. Everything seems to work except the code I put in italic.

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  • Optimising speeds in HDF5 using Pytables

    - by Sree Aurovindh
    The problem is with respect to the writing speed of the computer (10 * 32 bit machine) and the postgresql query performance.I will explain the scenario in detail. I have data about 80 Gb (along with approprite database indexes in place). I am trying to read it from Postgresql database and writing it into HDF5 using Pytables.I have 1 table and 5 variable arrays in one hdf5 file.The implementation of Hdf5 is not multithreaded or enabled for symmetric multi processing.I have rented about 10 computers for a day and trying to write them inorder to speed up my data handling. As for as the postgresql table is concerned the overall record size is 140 million and I have 5 primary- foreign key referring tables.I am not using joins as it is not scalable So for a single lookup i do 6 lookup without joins and write them into hdf5 format. For each lookup i do 6 inserts into each of the table and its corresponding arrays. The queries are really simple select * from x.train where tr_id=1 (primary key & indexed) select q_t from x.qt where q_id=2 (non-primary key but indexed) (similarly five queries) Each computer writes two hdf5 files and hence the total count comes around 20 files. Some Calculations and statistics: Total number of records : 14,37,00,000 Total number of records per file : 143700000/20 =71,85,000 The total number of records in each file : 71,85,000 * 5 = 3,59,25,000 Current Postgresql database config : My current Machine : 8GB RAM with i7 2nd generation Processor. I made changes to the following to postgresql configuration file : shared_buffers : 2 GB effective_cache_size : 4 GB Note on current performance: I have run it for about ten hours and the performance is as follows: The total number of records written for each file is about 6,21,000 * 5 = 31,05,000 The bottle neck is that i can only rent it for 10 hours per day (overnight) and if it processes in this speed it will take about 11 days which is too high for my experiments. Please suggest me on how to improve. Questions: 1. Should i use Symmetric multi processing on those desktops(it has 2 cores with about 2 GB of RAM).In that case what is suggested or prefereable? 2. If i change my postgresql configuration file and increase the RAM will it enhance my process. 3. Should i use multi threading.. In that case any links or pointers would be of great help Thanks Sree aurovindh V

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