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  • How do I create a Django ModelForm, so that it's fields are sometimes required, sometimes not?

    - by Graf
    Ok, here is the question. Imagine I have a ModelForm which have only two fields. like this one: class ColorForm(forms.Form): color_by_name = forms.CharField() color = forms.IntegerField(widget = forms.Select(choices=COLOR_CHOICES)) So a user can either input a color name, a choose it from a list. Color is required, but that doesn't mean, that user should enter it manually. There do I put validation, so that my code checks if user selected color in dropdownlist and if not then he should write it manually?

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  • Google App Engine getting verbose_name of a property from an instance

    - by Brian M. Hunt
    Given a model likeso: from google.appengine.ext import db class X(db.Model): p = db.StringProperty(verbose_name="Like p, but more modern.") How does one access verbose_name from x=X() (an instance of X)? One might expect that x.p.verbose_name would work, or alternatively x.properties()['p'].verbose_name, but neither seems to work. Thanks! EDIT: x.name.verbose_name = x.p.verbose_name

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  • Improving the join of two wave file?

    - by kaki
    I have written a code for joining two wave files.It works fine when i am joining larger segments but as i need to join very small segments the clarity is not good. I have learned that the signal processing technique such a windowed join can be used to improve the joining of file. y[n] = w[n]s[n] Multiply value of signal at sample number n by the value of a windowing function hamming window w[n]= .54 - .46*cos(2*Pi*n)/L 0 I am not understanding how to get the value to signal at sample n and how to implement this?? the code i am using for joining is import wave m=['C:/begpython/S0001_0002.wav', 'C:/begpython/S0001_0001.wav'] i=1 a=m[i] infiles = [a, "C:/begpython/S0001_0002.wav", a] outfile = "C:/begpython/S0001_00367.wav" data= [] data1=[] for infile in infiles: w = wave.open(infile, 'rb') data1=[w.getnframes] data.append( [w.getparams(), w.readframes(w.getnframes())] ) #data1 = [ord(character) for character in data1] #print data1 #data1 = ''.join(chr(character) for character in data1) w.close() output = wave.open(outfile, 'wb') output.setparams(data[0][0]) output.writeframes(data[0][1]) output.writeframes(data[1][1]) output.writeframes(data[2][1]) output.close()

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  • Can I get the amount of time for which a key is pressed on a keyboard

    - by Adi
    Dear all, I am working on a project in which I have to develop bio-passwords based on user's keystroke style. Suppose a user types a password for 20 times, his keystrokes are recorded, like holdtime : time for which a particular key is pressed. digraph time : time it takes to press a different key. suppose a user types a password " COMPUTER". I need to know the time for which every key is pressed. something like : holdtime for the above password is C-- 200ms O-- 130ms M-- 150ms P-- 175ms U-- 320ms T-- 230ms E-- 120ms R-- 300ms The rational behind this is , every user will have a different holdtime. Say a old person is typing the password, he will take more time then a student. And it will be unique to a particular person. To do this project, I need to record the time for each key pressed. I would greatly appreciate if anyone can guide me in how to get these times. Editing from here.. Language is not important, but I would prefer it in C. I am more interested in getting the dataset.

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  • My QFileSystemModel doesn't work as expected in PyQt

    - by Skilldrick
    I'm learning the Qt Model/View architecture at the moment, and I've found something that doesn't work as I'd expect it to. I've got the following code (adapted from Qt Model Classes): from PyQt4 import QtCore, QtGui model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) #prints True print model.data(parentIndex).toString() #prints name of current directory childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows #prints 0 (even though the current directory has directory and file children) The question: Is this a problem with PyQt, have I just done something wrong, or am I completely misunderstanding QFileSystemModel? According to the documentation, model.rowCount(parentIndex) should return the number of children in the current directory. The QFileSystemModel docs say that it needs an instance of a Gui application, so I've also placed the above code in a QWidget as follows, but with the same result: import sys from PyQt4 import QtCore, QtGui class Widget(QtGui.QWidget): def __init__(self, parent=None): QtGui.QWidget.__init__(self, parent) model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) print model.data(parentIndex).toString() childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows def main(): app = QtGui.QApplication(sys.argv) widget = Widget() widget.show() sys.exit(app.exec_()) if __name__ == '__main__': main()

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  • threading.local equivalent for twisted.web?

    - by defnull
    In asynchronous environments, threading.local is not guaranteed to be context-local anymore, because several contexts may coexist within a single thread. Most asynchronous frameworks (gevent, eventlet) provide a get_current_context() functionality to identify the current context. Some offer a way to monkey-patch threading.local so it is local to 'greenthreads' or other framework-specific contexts. I cannot find such a functionality in the twisted documentation. How do I do this?

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  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • Is there a replacement for Paste.Template?

    - by Jorge Vargas
    I have grown tired of all the little issues with paste template, it's horrible to maintain the templates, it has no way of updating an old project and it's very hard to test. I'm wondering if someone knows of an alternative for quickstart generators as they have proven to be useful.

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  • How to make django test framework read from live database?

    - by lfborjas
    I realize there's a similar question here, but this one has a different approach: I have a django app that does queries over data indexed with djapian ; I'd like to write unit tests for this app's search component, and, obviously, I'd need the django settings module and all connections with the database active, so the test runner that django provides seems ideal. however, the django testing framework creates a dummy database and I'd hate to dump all my data to a fixture and then index it (the tests would take forever!); My data isn't at risk because the tests would only read from the database, so, how could this be achieved? -I'm new at this whole unit testing thing, so the solution of writing a new test runner I read in that similar question doesn't enlighten me a bit, at least not without some details

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  • Django: where do I call settings.configure?

    - by RexE
    The Django docs say that I can call settings.configure instead of having a DJANGO_SETTINGS_MODULE. I would like my website's project to do this. In what file should I put the call to settings.configure so that my settings will get configured at the right time? Edit in response to Daniel Roseman's comment: The reason I want to do this is that settings.configure lets you pass in the settings variables as a kwargs dict, e.g. {'INSTALLED_APPS': ..., 'TEMPLATE_DIRS': ..., ...}. This would allow my app's users to specify their settings in a dict, then pass that dict to a function in my app that augments it with certain settings necessary to make my app work, e.g. adding entries to INSTALLED_APPS. What I envision looks like this. Let's call my app "rexe_app". In wsgi.py, my app's users would do: import rexe_app my_settings = {'INSTALLED_APPS': ('a','b'), ...} updated_settings = rexe_app.augment_settings(my_settings) # now updated_settings is {'INSTALLED_APPS': ('a','b','c'), 'SESSION_SAVE_EVERY_REQUEST': True, ...} settings.configure(**updated_settings)

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  • removing the single quote from a list of

    - by tanky
    I need to append/format a url with a list of ids for an api call however, when i put the list at the end of the api https://api.twitter.com/1.1/users/lookup.json?user_id=%s'%a i just get an empty string as a response. i have tried turning the list into a string and removing the square brackets doing a = str(followers['ids'])[1:-1] but i still get the same problem. and im assuming that its being caused by the single quote at the start. i have tried removing the apostrophe from the string doing a.replace("'", "") and now i have run out of ideas thanks

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  • how to show the right word in my code, my code is : os.urandom(64)

    - by zjm1126
    My code is: print os.urandom(64) which outputs: > "D:\Python25\pythonw.exe" "D:\zjm_code\a.py" \xd0\xc8=<\xdbD' \xdf\xf0\xb3>\xfc\xf2\x99\x93 =S\xb2\xcd'\xdbD\x8d\xd0\\xbc{&YkD[\xdd\x8b\xbd\x82\x9e\xad\xd5\x90\x90\xdcD9\xbf9.\xeb\x9b>\xef#n\x84 which isn't readable, so I tried this: print os.urandom(64).decode("utf-8") but then I get: > "D:\Python25\pythonw.exe" "D:\zjm_code\a.py" Traceback (most recent call last): File "D:\zjm_code\a.py", line 17, in <module> print os.urandom(64).decode("utf-8") File "D:\Python25\lib\encodings\utf_8.py", line 16, in decode return codecs.utf_8_decode(input, errors, True) UnicodeDecodeError: 'utf8' codec can't decode bytes in position 0-3: invalid data What should I do to get human-readable output?

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  • I can't login to my Django app when debug is set to False

    - by Eric
    I have a very strange problem, and I don't know how to fix or debug it. Short Story: I get locked out of my Django app when Debug is set to False. Long story: Case 1 (the first time it happened): 1. I enter my login info, but It just redirects to the login page. 2. I restart the server, try to login, and it works fine, I get in. 3. a few hours later I come back, log out, try to log back in and I can't. It just redirects to the login page. Case 2 (I figure out how to provoke the login failure): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a server error. 4. I log out and try to log back in, and I can't, just get redirected back to the login page. Case 3 (I can't provoke the login failure with Debug set to True): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a traceback. 4. I log out and log back in, everything works. 5. I wait and play around with it and can't get the login to fail while in Debug mode. Please help!

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  • Testing for the existence of a field in a class

    - by Brett
    Hi, i have a quick question. I have a 2D array that stores an instance of a class. The elements of the array are assigned a particular class based on a text file that is read earlier in the program. Since i do not know without looking in the file what class is stored at a particular element i could refer to a field that doesn't exist at that index (referring to appearance when an instance of temp is stored in that index). i have come up with a method of testing this, but it is long winded and requires a second matrix. Is there a function to test for the existence of a field in a class? class temp(): name = "default" class temp1(): appearance = "@"

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  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

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  • How to cutomize a modelform widget in django 1.1?

    - by muudscope
    I'm trying to modify a django form to use a textarea instead of a normal input for the "address" field in my house form. The docs seem to imply this changed from django 1.1 (which I'm using) to 1.2. But neither approach is working for me. Here's what I've tried: class HouseForm(forms.ModelForm): address = forms.Textarea() # Should work with django 1.1, but doesn't class Meta: model = House #widgets = { 'address': forms.Textarea() } # 1.2 style - doesn't work either.

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  • Django, url tag in template doesn't work: NoReverseMatch

    - by Lukasz Jocz
    I've encountered a problem with generating reverse url in templates in django. I'm trying to solve it since a few hours and I have no idea what the problem might be. URL reversing works great in models and views: # like this in models.py @models.permalink def get_absolute_url(self): return ('entry', (), { 'entry_id': self.entry.id, }) # or this in views.py return HttpResponseRedirect(reverse('entry',args=(entry_id,))) but when I'm trying to make it in template I get such an error: NoReverseMatch at /entry/1/ Reverse for ''add_comment'' with arguments '(1L,)' and keyword arguments '{}' not found. My file structure looks like this: project/ +-- frontend ¦   +-- models.py ¦   +-- urls.py ¦   +-- views.py +-- settings.py +-- templates ¦   +-- add_comment.html ¦   +-- entry.html +-- utils ¦   +-- with_template.py +-- wsgi.py My urls.py: from project.frontend.views import * from django.conf.urls import patterns, include, url urlpatterns = patterns('project.frontend.views', url(r'^entry/(?P<entry_id>\d+)/', 'entry', name="entry"), (r'^entry_list/', 'entry_list'), Then entry_list.html: {% extends "base.html" %} {% block content %} {% for entry in entries %} {% url 'entry' entry.id %} {% endfor %} {% endblock %} In views.py I have: @with_template def entry(request, entry_id): entry = Entry.objects.get(id=entry_id) entry.comments = entry.get_comments() return locals() where with_template is following decorator(but I don't think this is a case): class TheWrapper(object): def __init__(self, default_template_name): self.default_template_name = default_template_name def __call__(self, func): def decorated_func(request, *args, **kwargs): extra_context = kwargs.pop('extra_context', {}) dictionary = {} ret = func(request, *args, **kwargs) if isinstance(ret, HttpResponse): return ret dictionary.update(ret) dictionary.update(extra_context) return render_to_response(dictionary.get('template_name', self.default_template_name), context_instance=RequestContext(request), dictionary=dictionary) update_wrapper(decorated_func, func) return decorated_func if not callable(arg): return TheWrapper(arg) else: default_template_name = ''.join([ arg.__name__, '.html']) return TheWrapper(default_template_name)(arg) Do you have any idea, what may cause the problem? Great thanks in advance!

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  • How to sort a Pandas DataFrame according to multiple criteria?

    - by user1715271
    I have the following DataFrame containing song names, their peak chart positions and the number of weeks they spent at position no 1: Song Peak Weeks 76 Paperback Writer 1 16 117 Lady Madonna 1 9 118 Hey Jude 1 27 22 Can't Buy Me Love 1 17 29 A Hard Day's Night 1 14 48 Ticket To Ride 1 14 56 Help! 1 17 109 All You Need Is Love 1 16 173 The Ballad Of John And Yoko 1 13 85 Eleanor Rigby 1 14 87 Yellow Submarine 1 14 20 I Want To Hold Your Hand 1 24 45 I Feel Fine 1 15 60 Day Tripper 1 12 61 We Can Work It Out 1 12 10 She Loves You 1 36 155 Get Back 1 6 8 From Me To You 1 7 115 Hello Goodbye 1 7 2 Please Please Me 2 20 92 Strawberry Fields Forever 2 12 93 Penny Lane 2 13 107 Magical Mystery Tour 2 16 176 Let It Be 2 14 0 Love Me Do 4 26 157 Something 4 9 166 Come Together 4 10 58 Yesterday 8 21 135 Back In The U.S.S.R. 19 3 164 Here Comes The Sun 58 19 96 Sgt. Pepper's Lonely Hearts Club Band 63 12 105 With A Little Help From My Friends 63 7 I'd like to rank these songs in order of popularity, so I'd like to sort them according to the following criteria: songs that reached the highest position come first, but if there is a tie, the songs that remained in the charts for the longest come first. I can't seem to figure out how to do this in Pandas.

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