Search Results

Search found 17029 results on 682 pages for 'python modules'.

Page 384/682 | < Previous Page | 380 381 382 383 384 385 386 387 388 389 390 391  | Next Page >

  • [Django] How to find out whether a model's column is a foreign key?

    - by codethief
    I'm dynamically storing information in the database depending on the request: // table, id and column are provided by the request table_obj = getattr(models, table) record = table_obj.objects.get(pk=id) setattr(record, column, request.POST['value']) The problem is that request.POST['value'] sometimes contains a foreign record's primary key (i.e. an integer) whereas Django expects the column's value to be an object of type ForeignModel: Cannot assign "u'122'": "ModelA.b" must be a "ModelB" instance. Now, is there an elegant way to dynamically check whether b is a column containing foreign keys and what model these keys are linked to? (So that I can load the foreign record by it's primary key and assign it to ModelA?) Or doesn't Django provide information like this to the programmer so I really have to get my hands dirty and use isinstance() on the foreign-key column?

    Read the article

  • Getting unpredictable data into a tabular format

    - by Acorn
    The situation: Each page I scrape has <input> elements with a title= and a value= I don't know what is going to be on the page. I want to have all my collected data in a single table at the end, with a column for each title. So basically, I need each row of data to line up with all the others, and if a row doesn't have a certain element, then it should be blank (but there must be something there to keep the alignment). eg. First page has: {animal: cat, colour: blue, fruit: lemon, day: monday} Second page has: {animal: fish, colour: green, day: saturday} Third page has: {animal: dog, number: 10, colour: yellow, fruit: mango, day: tuesday} Then my resulting table should be: animal | number | colour | fruit | day cat | none | blue | lemon | monday fish | none | green | none | saturday dog | 10 | yellow | mango | tuesday Although it would be good to keep the order of the title value pairs, which I know dictionaries wont do. So basically, I need to generate columns from all the titles (kept in order but somehow merged together) What would be the best way of going about this without knowing all the possible titles and explicitly specifying an order for the values to be put in?

    Read the article

  • Find subset with K elements that are closest to eachother

    - by Nima
    Given an array of integers size N, how can you efficiently find a subset of size K with elements that are closest to each other? Let the closeness for a subset (x1,x2,x3,..xk) be defined as: 2 <= N <= 10^5 2 <= K <= N constraints: Array may contain duplicates and is not guaranteed to be sorted. My brute force solution is very slow for large N, and it doesn't check if there's more than 1 solution: N = input() K = input() assert 2 <= N <= 10**5 assert 2 <= K <= N a = [] for i in xrange(0, N): a.append(input()) a.sort() minimum = sys.maxint startindex = 0 for i in xrange(0,N-K+1): last = i + K tmp = 0 for j in xrange(i, last): for l in xrange(j+1, last): tmp += abs(a[j]-a[l]) if(tmp > minimum): break if(tmp < minimum): minimum = tmp startindex = i #end index = startindex + K? Examples: N = 7 K = 3 array = [10,100,300,200,1000,20,30] result = [10,20,30] N = 10 K = 4 array = [1,2,3,4,10,20,30,40,100,200] result = [1,2,3,4]

    Read the article

  • twisted reactor stops too early

    - by pygabriel
    I'm doing a batch script to connect to a tcp server and then exiting. My problem is that I can't stop the reactor, for example: cmd = raw_input("Command: ") # custom factory, the protocol just send a line reactor.connectTCP(HOST,PORT, CommandClientFactory(cmd) d = defer.Deferred() d.addCallback(lambda x: reactor.stop()) reactor.callWhenRunning(d.callback,None) reactor.run() In this code the reactor stops before that the tcp connection is done and the cmd is passed. How can I stop the reactor after that all the operation are finished?

    Read the article

  • Dynamically setting the queryset of a ModelMultipleChoiceField to a custom recordset

    - by Daniel Quinn
    I've seen all the howtos about how you can set a ModelMultipleChoiceField to use a custom queryset and I've tried them and they work. However, they all use the same paradigm: the queryset is just a filtered list of the same objects. In my case, I'm trying to get the admin to draw a multiselect form that instead of using usernames as the text portion of the , I'd like to use the name field from my account class. Here's a breakdown of what I've got: # models.py class Account(models.Model): name = models.CharField(max_length=128,help_text="A display name that people understand") user = models.ForeignKey(User, unique=True) # Tied to the User class in settings.py class Organisation(models.Model): administrators = models.ManyToManyField(User) # admin.py from django.forms import ModelMultipleChoiceField from django.contrib.auth.models import User class OrganisationAdminForm(forms.ModelForm): def __init__(self, *args, **kwargs): from ethico.accounts.models import Account self.base_fields["administrators"] = ModelMultipleChoiceField( queryset=User.objects.all(), required=False ) super(OrganisationAdminForm, self).__init__(*args, **kwargs) class Meta: model = Organisation This works, however, I want queryset above to draw a selectbox with the Account.name property and the User.id property. This didn't work: queryset=Account.objects.all().order_by("name").values_list("user","name") It failed with this error: 'tuple' object has no attribute 'pk' I figured that this would be easy, but it's turned into hours of dead-ends. Anyone care to shed some light?

    Read the article

  • Help calling class from a class above.

    - by wtzolt
    Hello, How to call from class oneThread: back to class fun:? As in, address a class written below. Is it possible? class oneThread(threading.Thread): def __init__(self): threading.Thread.__init__(self) self.start() def run(self): print "1" time.sleep(1) print "2" time.sleep(1) print "3" self.wTree.get_widget("entryResult").set_text("Done with One.") # How to call from here back to class fun, which of course is below...? class fun: wTree = None def __init__( self ): self.wTree = gtk.glade.XML( "main.glade" ) self.wTree.signal_autoconnect( {"on_buttonOne" : self.one} ) gtk.main() def one(self, widget): oneThread(); gtk.gdk.threads_init() do=fun()

    Read the article

  • How do I use django settings in my logging.ini file?

    - by slypete
    I have a BASE_DIR setting in my settings.py file: BASE_DIR = os.path.dirname(os.path.abspath(__file__)) I need to use this variable in my logging.ini file to setup my file handler paths. The initialization of logging happens in the same file, the settings.py file, below my BASE_DIR variable: LOG_INIT_DONE=False if not LOG_INIT_DONE: logging.config.fileConfig(LOGGING_INI) LOG_INIT_DONE=True Thanks, Pete

    Read the article

  • Most efficient way to update attribute of one instance

    - by Begbie00
    Hi all - I'm creating an arbitrary number of instances (using for loops and ranges). At some event in the future, I need to change an attribute for only one of the instances. What's the best way to do this? Right now, I'm doing the following: 1) Manage the instances in a list. 2) Iterate through the list to find a key value. 3) Once I find the right object within the list (i.e. key value = value I'm looking for), change whatever attribute I need to change. for Instance within ListofInstances: if Instance.KeyValue == SearchValue: Instance.AttributeToChange = 10 This feels really inefficient: I'm basically iterating over the entire list of instances, even through I only need to change an attribute in one of them. Should I be storing the Instance references in a structure more suitable for random access (e.g. dictionary with KeyValue as the dictionary key?) Is a dictionary any more efficient in this case? Should I be using something else? Thanks, Mike

    Read the article

  • Generating two thumbnails from the same image in Django

    - by Titus
    Hello, this seems like quite an easy problem but I can't figure out what is going on here. Basically, what I'd like to do is create two different thumbnails from one image on a Django model. What ends up happening is that it seems to be looping and recreating the same image (while appending an underscore to it each time) until it throws up an error that the filename is to big. So, you end up something like: OSError: [Errno 36] File name too long: 'someimg________________etc.jpg' Here is the code: def save(self, *args, **kwargs): if self.image: iname = os.path.split(self.image.name)[-1] fname, ext = os.path.splitext(iname) tlname, tsname = fname + '_thumb_l' + ext, fname + '_thumb_s' + ext self.thumb_large.save(tlname, make_thumb(self.image, size=(250,250))) self.thumb_small.save(tsname, make_thumb(self.image, size=(100,100))) super(Artist, self).save(*args, **kwargs) def make_thumb(infile, size=(100,100)): infile.seek(0) image = Image.open(infile) if image.mode not in ('L', 'RGB'): image.convert('RGB') image.thumbnail(size, Image.ANTIALIAS) temp = StringIO() image.save(temp, 'png') return ContentFile(temp.getvalue()) I didn't show imports for the sake of brevity. Assume there are two ImageFields on the Artist model: thumb_large, and thumb_small. If this isn't the correct way to do it, I'd appreciate any feedback. Thanks!

    Read the article

  • How to make scipy.interpolate give a an extrapolated result beyond the input range?

    - by Salim Fadhley
    I'm trying to port a program which uses a hand-rolled interpolator (developed by a mathematitian colleage) over to use the interpolators provided by scipy. I'd like to use or wrap the scipy interpolator so that it has as close as possible behavior to the old interpolator. A key difference between the two functions is that in our original interpolator - if the input value is above or below the input range, our original interpolator will extrapolate the result. If you try this with the scipy interpolator it raises a ValueError. Consider this program as an example: import numpy as np from scipy import interpolate x = np.arange(0,10) y = np.exp(-x/3.0) f = interpolate.interp1d(x, y) print f(9) print f(11) # Causes ValueError, because it's greater than max(x) Is there a sensible way to make it so that instead of crashing, the final line will simply do a linear extrapolate, continuing the gradients defined by the first and last two pouints to infinity. Note, that in the real software I'm not actually using the exp function - that's here for illustration only!

    Read the article

  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

    Read the article

  • Scrapy Not Returning Additonal Info from Scraped Link in Item via Request Callback

    - by zoonosis
    Basically the code below scrapes the first 5 items of a table. One of the fields is another href and clicking on that href provides more info which I want to collect and add to the original item. So parse is supposed to pass the semi populated item to parse_next_page which then scrapes the next bit and should return the completed item back to parse Running the code below only returns the info collected in parse If I change the return items to return request I get a completed item with all 3 "things" but I only get 1 of the rows, not all 5. Im sure its something simple, I just can't see it. class ThingSpider(BaseSpider): name = "thing" allowed_domains = ["somepage.com"] start_urls = [ "http://www.somepage.com" ] def parse(self, response): hxs = HtmlXPathSelector(response) items = [] for x in range (1,6): item = ScrapyItem() str_selector = '//tr[@name="row{0}"]'.format(x) item['thing1'] = hxs.select(str_selector")]/a/text()').extract() item['thing2'] = hxs.select(str_selector")]/a/@href').extract() print 'hello' request = Request("www.nextpage.com", callback=self.parse_next_page,meta={'item':item}) print 'hello2' request.meta['item'] = item items.append(item) return items def parse_next_page(self, response): print 'stuff' hxs = HtmlXPathSelector(response) item = response.meta['item'] item['thing3'] = hxs.select('//div/ul/li[1]/span[2]/text()').extract() return item

    Read the article

  • matplotlib.pyplot, preserve aspect ratio of the plot

    - by Headcrab
    Assuming we have a polygon coordinates as polygon = [(x1, y1), (x2, y2), ...], the following code displays the polygon: import matplotlib.pyplot as plt plt.fill(*zip(*polygon)) plt.show() By default it is trying to adjust the aspect ratio so that the polygon (or whatever other diagram) fits inside the window, and automatically changing it so that it fits even after resizing. Which is great in many cases, except when you are trying to estimate visually if the image is distorted. How to fix the aspect ratio to be strictly 1:1? (Not sure if "aspect ratio" is the right term here, so in case it is not - I need both X and Y axes to have 1:1 scale, so that (0, 1) on both X and Y takes an exact same amount of screen space. And I need to keep it 1:1 no matter how I resize the window.)

    Read the article

  • Programmatically sync the db in Django

    - by Attila Oláh
    I'm trying to sync my db from a view, something like this: from django import http from django.core import management def syncdb(request): management.call_command('syncdb') return http.HttpResponse('Database synced.') The issue is, it will block the dev server by asking for user input from the terminal. How can I pass it the '--noinput' option to prevent asking me anything? I have other ways of marking users as super-user, so there's no need for the user input, but I really need to call syncdb (and flush) programmatically, without logging on to the server via ssh. Any help is appreciated.

    Read the article

  • Application closes on Nokia E71 when using urllib.urlopen

    - by sammr
    Hello, Im running the following code on my Nokia E71. But after the text input, the program closes abruptly. I have a GPRS connection on my phone,but i still seem to be having some problem with urllib.urlopen The code is as follows : import appuifw,urllib amountInDollars = appuifw.query(u"Enter amount in Dollars","text") data=urllib.urlopen("http://www.google.com").read() appuifw.note(u"Hey","info") Any way to fix this problem ? Thank You

    Read the article

  • Multiprocessing Bomb

    - by iKarampa
    I was working the following example from Doug Hellmann tutorial on multiprocessing: import multiprocessing def worker(): """worker function""" print 'Worker' return if __name__ == '__main__': jobs = [] for i in range(5): p = multiprocessing.Process(target=worker) jobs.append(p) p.start() When I tried to run it outside the if statement: import multiprocessing def worker(): """worker function""" print 'Worker' jobs = [] for i in range(5): p = multiprocessing.Process(target=worker) jobs.append(p) p.start() It started spawning processes non-stop, without any way of to terminating it. Why would that happen? Why it did not generate 5 processes and exit? Why do I need the if statement?

    Read the article

< Previous Page | 380 381 382 383 384 385 386 387 388 389 390 391  | Next Page >