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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • What did I do wrong with this function?

    - by Felipe Galdino Campos
    I don't know what I did - it's wrong . Can someone help me? def insert_sequence(dna1, dna2, number): '''(str, str, int) -> str Return the DNA sequence obtained by inserting the second DNA sequence at the given index. (You can assume that the index is valid.) >>> insert_sequence('CCGG', 'AT', 2) 'CCATGG' >>> insert_sequence('TTGC', 'GG', 2) 'TTGGGC' ''' index = 0 result = ''; for string in dna1: if index == number: result = result + dna2 result = result + string index += 1 print(result)

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • How to check wether a path represented by a QString with german umlauts exists?

    - by MB
    Hey, i get a QString which represents a directory from a QLineEdit. Now i want to check wether a certain file exists in this directory. But if i try this with os.path.exists and os.path.join and get in trouble when german umlauts occur in the directory path: #the direcory coming from the user input in the QLineEdit #i take this QString to the local 8-Bit encoding and then make #a string from it target_dir = str(lineEdit.text().toLocal8Bit()) #the file name that should be checked for file_name = 'some-name.txt' #this fails with a UnicodeDecodeError when a umlaut occurs in target_dir os.path.exists(os.path.join(target_dir, file_name)) How would you check if the file exists, when you might encounter german umlauts?

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • Where is the help.py for Android's monkeyrunner

    - by Keyboardsurfer
    Hi, I just can't find the help.py file in order to create the API reference for the monkeyrunner. The command described at the Android references monkeyrunner <format> help.py <outfile> does not work when i call monkeyrunner html help.py /path/to/place/the/doc.html. It's quite obvious that the help.py file is not found and the monkeyrunner also tells me "Can't open specified script file". But a locate on my system doesn't bring me a help.py file that has anything to do with monkeyrunner or Android. So my question is: Where did they hide the help.py file for creating the API reference?

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  • Pyqt - QMenu dynamically populated and clicked

    - by mleep
    I need to be able to know what item I've clicked in a dynamically generated menu system. I only want to know what I've clicked on, even if it's simply a string representation. def populateShotInfoMenus(self): self.menuFilms = QMenu() films = self.getList() for film in films: menuItem_Film = self.menuFilms.addAction(film) self.connect(menuItem_Film, SIGNAL('triggered()'), self.onFilmSet) self.menuFilms.addAction(menuItem_Film) def onFilmRightClick(self, value): self.menuFilms.exec_(self.group1_inputFilm.mapToGlobal(value)) def onFilmSet(self, value): print 'Menu Clicked ', value

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  • Can this django query be improved?

    - by Hobhouse
    Given a model structure like this: class Book(models.Model): user = models.ForeignKey(User) class Readingdate(models.Model): book = models.ForeignKey(Book) date = models.DateField() One book may have several readingdates. How do I list books having at least one readingdate within a specific year? I can do this: from_date = datetime.date(2010,1,1) to_date = datetime.date(2010,12,31) book_ids = Readingdate.objects\ .filter(date__range=(from_date,to_date))\ .values_list('book_id', flat=True) books_read_2010 = Book.objects.filter(id__in=book_ids) Is it possible to do this with one queryset, or is this the best way?

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  • I can't login to my Django app when debug is set to False

    - by Eric
    I have a very strange problem, and I don't know how to fix or debug it. Short Story: I get locked out of my Django app when Debug is set to False. Long story: Case 1 (the first time it happened): 1. I enter my login info, but It just redirects to the login page. 2. I restart the server, try to login, and it works fine, I get in. 3. a few hours later I come back, log out, try to log back in and I can't. It just redirects to the login page. Case 2 (I figure out how to provoke the login failure): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a server error. 4. I log out and try to log back in, and I can't, just get redirected back to the login page. Case 3 (I can't provoke the login failure with Debug set to True): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a traceback. 4. I log out and log back in, everything works. 5. I wait and play around with it and can't get the login to fail while in Debug mode. Please help!

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  • Add string to another string

    - by daemonfire300
    Hi there, I currently encountered a problem: I want to handle adding strings to other strings very efficiently, so I looked up many methods and techniques, and I figured the "fastest" method. But I quite can not understand how it actually works: def method6(): return ''.join([`num` for num in xrange(loop_count)]) From source (Method 6) Especially the ([numfor num in xrange(loop_count)]) confused me totally.

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  • How would make this run with an if statement and one for loop?

    - by Nick Jacobs
    I'm trying to get this to run by using an if statment, a for loop, and a list. The list is part of the parameters. I am not sure how to write the if statement and have the program loop through all of the different words and set everything how it is supposed to be. newSndIdx=0; for i in range (8700, 12600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (15700, 17600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (18750, 22350+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (23700, 27250+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (106950, 115300+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx+=1

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  • how to let the parser print help message rather than error and exit

    - by fluter
    Hi, I am using argparse to handle cmd args, I wanna if there is no args specified, then print the help message, but now the parse will output a error, and then exit. my code is: def main(): print "in abing/start/main" parser = argparse.ArgumentParser(prog="abing")#, usage="%(prog)s <command> [args] [--help]") parser.add_argument("-v", "--verbose", action="store_true", default=False, help="show verbose output") subparsers = parser.add_subparsers(title="commands") bkr_subparser = subparsers.add_parser("beaker", help="beaker inspection") bkr_subparser.set_defaults(command=beaker_command) bkr_subparser.add_argument("-m", "--max", action="store", default=3, type=int, help="max resubmit count") bkr_subparser.add_argument("-g", "--grain", action="store", default="J", choices=["J", "RS", "R", "T", "job", "recipeset", "recipe", "task"], type=str, help="resubmit selection granularity") bkr_subparser.add_argument("job_ids", nargs=1, action="store", help="list of job id to be monitored") et_subparser = subparsers.add_parser("errata", help="errata inspection") et_subparser.set_defaults(command=errata_command) et_subparser.add_argument("-w", "--workflows", action="store_true", help="generate workflows for the erratum") et_subparser.add_argument("-r", "--run", action="store_true", help="generate workflows, and run for the erratum") et_subparser.add_argument("-s", "--start-monitor", action="store_true", help="start monitor the errata system") et_subparser.add_argument("-d", "--daemon", action="store_true", help="run monitor into daemon mode") et_subparser.add_argument("erratum", action="store", nargs=1, metavar="ERRATUM", help="erratum id") if len(sys.argv) == 1: parser.print_help() return args = parser.parse_args() args.command(args) return how can I do that? thanks.

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  • django admin site - filtering available objects for user

    - by JPG
    I have models that belong to some 'group' (Company class). I want to add users, who will also belong to a one group and should be able to edit/manage/add objects with membership in associated group. something like: class Company() class Something() company = ForeignKey(Company) user Microsoft_admin company = ForeignKey(Company) and this user should only see and edit objects belonging to associated Company in the Admin Interface. How to acomplish that?

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  • Appengine filter inequality and ordering fails

    - by davezor
    I think I'm overlooking something simple here, I can't imagine this is impossible to do. I want to filter by a datetime attribute and then order the result by a ranking integer attribute. When I try to do this: query.filter("submitted >=" thisweek).order("ranking") I get the following: BadArgumentError: First ordering property must be the same as inequality filter property, if specified for this query; received ranking, expected submitted Huh? What am I missing? Thanks.

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  • google contacts api service account oauth2.0 sub user

    - by user3709507
    I am trying to use the Google Contacts API to connect to a user's contact information, on my Google apps domain. Generating an access_token using the gdata api's ContactsService clientlogin function while using the API key for my project works fine, but I would prefer to not store the user's credentials, and from the information I have found that method uses OAuth1.0 So, to use OAuth2.0 I have: Generated a Service Account in the developer's console for my project Granted access to the service account for the scope of https://www.google.com/m8/feeds/ in the Google apps domain admin panel Attempted to generate credentials using SignedJwtAssertionCredentials: credentials = SignedJwtAssertionCredentials( service_account_name=service_account_email, private_key=key_from_p12_file, scope='https://www.google.com/m8/feeds/', sub=user_email') The problem I am running into is that attempting to generate an access token using this method fails. It succeeds in generating the token when I remove the sub parameter, but then that token fails when I try to fetch the user's contacts. Does anyone know why this might be happening?

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  • App Engine Django Form Uniqueness Validation?

    - by GeekTantra
    Is there a simpler way to use uniqueness validation with Django Forms in AppEngine? I understand that performance would be problem if we keep an uniqueness constraint but since the amount of data being added is very small performance is not a big concern, rather development time is a concern here. Any help is appreciated.

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  • problem installing mysqldb for python2.6

    - by apoorva
    Hi.. My mysql database is located on a remote machine... So i dont have any local copy of mysql on my local machine.. i get the registry key error... (file not found)... serverKey = _winreg.OpenKey(_winreg.HKEY_LOCAL_MACHINE, options['registry_key']) WindowsError: [Error 2] The system cannot find the file specified I think it requires to have a local copy of mysql... How do i install the mysqldb for database residing on another machine???

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  • How to make django test framework read from live database?

    - by lfborjas
    I realize there's a similar question here, but this one has a different approach: I have a django app that does queries over data indexed with djapian ; I'd like to write unit tests for this app's search component, and, obviously, I'd need the django settings module and all connections with the database active, so the test runner that django provides seems ideal. however, the django testing framework creates a dummy database and I'd hate to dump all my data to a fixture and then index it (the tests would take forever!); My data isn't at risk because the tests would only read from the database, so, how could this be achieved? -I'm new at this whole unit testing thing, so the solution of writing a new test runner I read in that similar question doesn't enlighten me a bit, at least not without some details

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  • How to discover table properties from SQLAlchemy mapped object

    - by ssaboum
    Hi, My point is i have a class mapped with a table, in my case in a declarative way, and i want to "discover" table properties, columns, names, relations, from this class : engine = create_engine('sqlite:///' + databasePath, echo=True) # setting up root class for declarative declaration Base = declarative_base(bind=engine) class Ship(Base): __tablename__ = 'ships' id = Column(Integer, primary_key=True) name = Column(String(255)) def __init__(self, name): self.name = name def __repr__(self): return "<Ship('%s')>" % (self.name) So now my goal is from the "Ship" class to get the table columns and their properties from another piece of code. I guess i can deal with it using instrumentation but is there any way provided by the SQLAlchemy API ? Thank you.

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  • Function for averages of tuples in a dictionary

    - by Billy Mann
    I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

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  • A RAM error of big array

    - by flint
    I have a big file, more than 400M. In that file, there are 13496*13496 number, means 13496 rows and 13496 cols. I want to read them to a array. This is my code: _L1 = [[0 for col in range(13496)] for row in range(13496)] _L1file = open('distanceCMD.function.txt') while (i<13496): print "i="+str(i) _strlf = _L1file.readline() _strlf = _strlf.split('\t') _strlf = _strlf[:-1] _L1[i] = _strlf i += 1 _L1file.close() And this is my error massage: MemoryError: File "D:\research\space-function\ART3.py", line 30, in <module> _strlf = _strlf.split('\t')

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  • django url matching

    - by ben
    can anyone see why this wouldn't be working. Fairly new to django so any help would be much appreciated actual url: http://127.0.0.1:8000/2010/may/12/my-second-blog-post/ urls.py: (r'(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, slug_field='slug',template_name='blog/detail.html')),

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  • Problem opening Solr *.jsp pages with urllib2.urlopen.

    - by nestling
    I'm trying to open a page at http://localhost:8983/solr/admin/stats.jsp but urllib2.urlopen returns a blank string. It works fine for solr/ and solr/admin, but for all the pages above /solr/admin/ I get nothing but a blank string. 76]: t = urllib2.urlopen('http://localhost:8983/solr/admin/stats.jsp') 77]: s = t.read() 78]: s 78]: 79]: type(s) 79]: <type 'str'> 80]: urllib2.urlopen('http://localhost:8983/solr/admin/registry.jsp').read() 80]: In [84]: urllib2.urlopen('http://localhost:8983/solr/admin/schema.jsp').read() Out[84]: I know this isn't a problem with urllib2, but beyond that I am at a loss. I wish solr (or jetty) had an easy to get to log file, so that perhaps it could tell me its side of the story.

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  • argparse coding issue

    - by Carl Skonieczny
    write a script that takes two optional boolean arguments,"--verbose‚" and ‚"--live", and two required string arguments, "base"and "pattern". Please set up the command line processing using argparse. This is the code I have so far for the question, I know I am getting close but something is not quite right. Any help is much appreciated.Thanks for all the quick useful feedback. def main(): import argparse parser = argparse.ArgumentParser(description='') parser.add_argument('base', type=str) parser.add_arguemnt('--verbose', action='store_true') parser.add_argument('pattern', type=str) parser.add_arguemnt('--live', action='store_true') args = parser.parse_args() print(args.base(args.pattern))

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  • how do i insert spaces into a string using the range function?

    - by user1319219
    If I have a string, for example which reads: 'Hello how are you today Joe' How am I able to insert spaces into it at regular intervals? So for example I want to insert spaces into it using the range function in these steps: range(0,27,2). So it will look like this: 'He lo ho w ar e yo u to da y Jo e' It now has a space at every 2nd index going up to it's end. How do I do this does anyone know? thanks.

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