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  • SUM a pair of COUNTs from two tables based on a time variable

    - by Kevin O.
    Been searching for an answer to this for the better part of an hour without much luck. I have two regional tables laid out with the same column names and I can put out a result list for either table based on the following query (swap Table2 for Table1): SELECT Table1.YEAR, FORMAT(COUNT(Table1.id),0) AS Total FROM Table1 WHERE Table1.variable='Y' GROUP BY Table1.YEAR Ideally I'd like to get a result that gives me a total sum of the counts by year, so instead of: | REGION 1 | | REGION 2 | | YEAR | Total | | YEAR | Total | | 2010 | 5 | | 2010 | 1 | | 2009 | 2 | | 2009 | 3 | | | | | 2008 | 4 | I'd have: | MERGED | | YEAR | Total | | 2010 | 6 | | 2009 | 5 | | 2008 | 4 | I've tried a variety of JOINs and other ideas but I think I'm caught up on the SUM and COUNT issue. Any help would be appreciated, thanks!

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  • Should I change $_REQUEST to $_POST

    - by Scarface
    Hey guys quick question, I have a checkbox system where a list of items can be checked and deleted on the click of a button. I currently use request and it does the job but I was wondering if $_REQUEST was some sort of security risk or improper. If anyone has any advice I would appreciate it. Should I change to $_POST? If so, what is the best way to go about it? foreach ($_REQUEST as $key=>$value) { if (substr($key,0,3)==="img") { $id = substr($key,3); if(isset($_REQUEST['Delete'])) { $sql = 'SELECT file_name,username FROM images WHERE id=?'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($id)); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $image=$row['file_name']; $user=$row['username']; $myFile = "$user/images/$image"; unlink($myFile); } <input id=\"img".$id."\" name=\"img".$id."\" type=\"checkbox\">

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  • Get the names of IDs from different table

    - by user896692
    I have an array with a lot of data from a database. In the array, there are two fields called teameinsid and teamzweiid. The query is a very simple one : $spiel = mysql_query("select teameinsid, teamzweiid from begegnung", $connection) or die("Keine passende Begegnung"); What I need is to search in the database for the names of these IDs. The names are in a different table. What I have now is the following: while($tmp = mysql_fetch_array($spiel)){ $teins = $tmp['teameinsid']; $tzwei = $tmp['teamzweiid']; } So I know the two IDs, but I don't know where to save the names. If I try: $name = mysql_query("select name from team where teameinsid = $teins", $con) it gets overwritten every time. How can I manage this?

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  • How to find intersect rows when condition depend on some columns in one table

    - by user3695637
    Table subscribe subscriber | subscribeto (columns) 1 | 5 1 | 6 1 | 7 1 | 8 1 | 9 1 | 10 2 | 5 2 | 6 2 | 7 There are two users that have id 1 and 2. They subscribe to various user and I inserted these data to table subscribe. Column subscriber indicates who is subscriber and column subscribeto indicates who they've subscribe to. From the above table can conclude that; user id=1 subscribed to 6 users user id=2 subscribed to 3 users I want to find manual of subscription (like Facebook is manual friends) user 1 subscribe to user 5,6,7,8,9,10 user 2 subscribe to user 5,6,7 So, Manual subscription of user 1 and 2 are: 5,6,7 And I'm trying to create SQL statement.. I give you user table for my SQL statement and I think we can use only subscribe table but I can't figure out. Table user userid (columns) 1 2 3 ... ... SQL "select * from user where (select count( 1 ) from subscribe where subscriber = '1' and subscribeto = user.userid) and (select count( 1 ) from subscribe where subscriber = '2' and subscribeto = user.userid);" This SQL can work correctly, but it very slow for thousands of columns. Please provide better SQL for me, Thanks.

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  • SQL Select -> product -> comments -> user

    - by user1492716
    thanks for yout time helping on this ;) I'm new to SQL and wish to solve somethign in just one query and i dont know how to do it.- Basically I've a table of products, a table of users and a table of comments, linked by products.id - comments.pid and user.id - comments.uid , i wish to know what is the best practice to create just 1 query and get all products with child comments, including username.

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  • is Payment table needed when you have an invoice table like this?

    - by EBAGHAKI
    this is my invoice table: Invoice Table: invoice_id creation_date due_date payment_date status enum('not paid','paid','expired') user_id total_price I wonder if it's Useful to have a payment table in order to record user payments for invoices. payment table can be like this: payment_id payment_date invoice_id price_paid status enum('successful', 'not successful')

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  • Problem with sending "SetCookie" first in php code

    - by Camran
    According to this manual: http://us2.php.net/setcookie I have to set the cookie before anything else. Here is my cookie code: if (isset($_COOKIE['watched_ads'])){ $expir = time()+1728000; //20 days $ad_arr = unserialize($_COOKIE['watched_ads']); $arr_elem = count($ad_arr); if (in_array($ad_id, $ad_arr) == FALSE){ if ($arr_elem>10){ array_shift($ad_arr); } $ad_arr[]=$ad_id; setcookie('watched_ads', serialize($ad_arr), $expir, '/'); } } else { $expir = time()+1728000; //20 days $ad_arr[] = $ad_id; setcookie('watched_ads', serialize($ad_arr), $expir, '/'); } As you can see I am using variables in setting the cookie. The variables comes from a mysql_query and I have to do the query first. But then, if I do, I will get an error message: Cannot modify header information - headers already sent by ... The error points to the line where I set the cookie above. What should I do?a

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  • Can I do this in only one query ?

    - by Paté
    Merry christmas everyone, I Know my way around SQL but I'm having a hard time figuring this one out. First here are my tables (examples) User id name friend from //userid to //userid If user 1 is friend with user 10 then you a row with 1,10. User 1 cannot be friend with user 10 if user 10 is not friend with user 1 so you have 1,10 10,1 It may look weird but I need those two rows per relations. Now I'm trying to make a query to select the users that have the most mutual friend with a given user. For example User 1 is friend with user 10,9 and 7 and user 8 is friend with 10,9 and 7 too ,I want to suggest user 1 to invite him (like facebook). I want to get like the 10 first people with the most mutual friend. The output would be like User,NumOfMutualFriends I dont know if that can be done in a single query ? Thanks in advance for any help.

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • SQL Server - How Do I Substract 2 Hours from Formatted Time

    - by user1842653
    I need to know how to add 2 hours to the below 'Completed' timestamp. Here is the Select statement Select Tsk.task_id,Tsk.org_id,Tsk.completed,Tsk.assgn_acct_id,name FROM tdstelecom.tasks As Tsk WHERE Tsk.task_id = '11094836' AND DATE(Tsk.completed) < CURDATE() AND DATE(Tsk.completed) >= DATE_SUB(CURDATE (),INTERVAL 180 DAY) Here are the results: 2012-08-22 14:18:14 Desired results: 2012-08-22 16:18:14

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  • displaying search results with two or more queries

    - by fusion
    in my search form, if the user types 'good', it displays all the results which contain the keyword 'good'. however if the user types in 'good sweetest', it displays no results because there is no record with the two words appearing together; BUT appearing in an entry at different places. for example, the record says: A good action is an ever-remaining store and a pure yield the user types in 'good', it will show up this record, but if the user types in 'good' + 'pure', it will not show anything. what i would like is that if the user types in 'good' + 'pure' it should records containing these keywords highlighting them. search.php code: $search_result = ""; $search_result = $_POST["q"]; $search_result = trim($search_result); //Check if the string is empty if ($search_result == "") { echo "<p class='error'>Search Error. Please Enter Your Search Query.</p>" ; exit(); } if ($search_result == "%" || $search_result == "_" || $search_result == "+" ) { echo "<p class='error1'>Search Error. Please Enter a Valid Search Query.</p>" ; exit(); } $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . mysql_real_escape_string($search_result) .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } function highlightWords($string, $word) { $string = preg_replace("/".preg_quote($word, "/")."/i", "<span class='highlight'>$0</span>", $string); /*** return the highlighted string ***/ return $string; } ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:18px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> search.html: <form name="myform" class="wrapper"> <input type="text" name="q" onkeyup="showUser()" class="txt_search"/> <input type="button" name="button" onclick="showUser()" class="button"/> <p> <div id="txtHint"></div> </form>

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  • Set AUTO_INCREMENT value programmatically

    - by Tim
    So this works... ALTER TABLE variation AUTO_INCREMENT = 10; But I want to do this; ALTER TABLE variation AUTO_INCREMENT = (SELECT MAX(id)+1 FROM old_db.varaition); but that doesnt work, and neither does; SELECT MAX(id)+1 INTO @old_auto_inc FROM old_db.variation ALTER TABLE variation AUTO_INCREMENT = @old_auto_inc; So does anyone know how to do this? ( I'm trying to ensure that AUTO_INCREMENT keys dont collide between an old and a new site and need to do this automatically. So I can just run a script when the new db goes live )

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  • How do I do Textbox Submit

    - by Newb
    Hello everyone, I have a search box and a buttion. currently a user enter some text and press the search button. But I want to add another feature that instead of clicking the search button people can hit enter to search. How can I do that? Here is my code sample: <form method="post" action=""> <input id="search" name="search" type="text" /> <input id="search_btn" name="search_btn" type="submit" /> </form> Thanks in advance

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  • php for-loop issue

    - by rajesh1984
    Heya, I have a loop which generates a table code for a specific number of times. What I'm having problems with is to echo a variable inside the loop. The loop runs 10 times, and there are 10 text messages sent to the page, so my problem is how do I get each of the looped tables to echo one of the text messages each time?

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  • Storing affiliate leads and conversions

    - by James Jeffery
    I've created an affilaite system that tracks leads and conversions. The leads and conversions records will go into the millions so I need a good way to store them. Users will need to track the stats hourly, daily, weekly and monthly. Whats the best way to store the leads and conversions?

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  • displaying search results of more than one word

    - by fusion
    in my search form, if the user types 'good', it displays all the results which contain the keyword 'good'. however if the user types in 'good sweetest', it displays no results because there is no record with the two words appearing together; BUT appearing in an entry at different places. for example, the record says: A good action is an ever-remaining store and a pure yield the user types in 'good', it will show up this record, but if the user types in 'good' + 'pure', it will not show anything. or if the record contains the keyword 'good-deeds' and if the user types in 'good deeds' without the hyphen, it will not show anything. what i would like is that if the user types in 'good' + 'pure' or 'good deeds' it should records containing these keywords highlighting them. search.php code: $search_result = ""; $search_result = $_POST["q"]; $search_result = trim($search_result); //Check if the string is empty if ($search_result == "") { echo "<p class='error'>Search Error. Please Enter Your Search Query.</p>" ; exit(); } if ($search_result == "%" || $search_result == "_" || $search_result == "+" ) { echo "<p class='error1'>Search Error. Please Enter a Valid Search Query.</p>" ; exit(); } $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . mysql_real_escape_string($search_result) .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } function highlightWords($string, $word) { $string = preg_replace("/".preg_quote($word, "/")."/i", "<span class='highlight'>$0</span>", $string); /*** return the highlighted string ***/ return $string; } ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:18px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> search.html: <form name="myform" class="wrapper"> <input type="text" name="q" onkeyup="showUser()" class="txt_search"/> <input type="button" name="button" onclick="showUser()" class="button"/> <p> <div id="txtHint"></div> </form>

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  • Is it expensive to hold on to PreparedStatements? (Java & JDBC)

    - by sbook
    I'm trying to figure out if it's efficient for me to cache all of my statements when I create my database connection or if I should only create those that are most used and create the others if/when they're needed.. It seems foolish to create all of the statements in all of the client threads. Any feedback would be greatly appreciated.

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  • Is this a secure way to structure a mysql_query in PHP

    - by Supernovah
    I have tried and tried to achieve an SQL injection by making custom queries to the server outside of firefox. Inside the php, all variables are passed into the query in a string like this. Note, by this stage, $_POST has not been touched. mysql_query('INSERT INTO users (password, username) VALUES(' . sha1($_POST['password']) . ',' . $_POST['username'] . ')); Is that a secure way to make a change?

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  • Reverse wildcard search in codeigniter

    - by Andy Platt
    I am implementing a snippet-based content management system into my current project. Snippets can be associated with a page either by exact match of the full url falling back to a wildcard match on a partial url or finally a default snippet. To implement this I have a created table of page associations with a wildcard flag, the system first checks the current url against the non-wildcard associations and if it doesn't find a match it checks against the partial url's where the wildcard flag is set. In order to achieve this I am getting all the partial url's from the database and putting them into an array then walking the array to check for a match against the current url: protected function _check_wildcard($url = NULL) { if($url) { $q = $this->db->where('wildcard' ,'Y') ->from('content') ->get(); $wildcards = $q->result_array(); foreach($wildcards AS $wildcard) { if(strpos($url,$wildcard['url']) > 0) { return $wildcard['snipppet_id']; } } } else { return NULL; } } Can anyone suggest a better way to do this - preferably one that doesn't involve having to constantly download the full list of all the wildcards each time I load a page as I am afraid that this will have a negative effect on the scalability of the system down the line?

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  • SQL Outer joins

    - by dsquaredtech
    Three tables courses,registration,students columns in students firstname,lastname,studentid,major,admitdate,graddate,gender,dob columns in registration courseid,studentid columns in courses coursenumber,coursename,credits select statement I need to modify select lastname as 'Last Name',sum(credits) as 'Credits Registered For' from students as s inner join registration as r on s.studentid = r.studentid inner join courses as c on c.coursenumber = c.courseid group by last name; the question on the lab is... Modify the previous query to show all students, even if they have not registered for a class. You should have 14 rows. Students who are not registered will show NULL in output. I know this requires outer join of some sort but I'm not fully grasping these joins i've read multiple posts on here and other sites but can't seem figure it out.

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  • How to join this table?

    - by pamella
    ads table img90.imageshack.us/img90/6295/adsvo.png phones table img194.imageshack.us/img194/3713/phones.png cars table img35.imageshack.us/img35/1035/carsm.png i have 3 tables ads,cars and phones. i want to join tables is based on category in ads table. and i tried this query but no luck,any helps? SELECT * FROM `ads` JOIN `ads.category` ON `ads.id` = `ads.category.id` ** i cant add comment any of your post,but i want it to be automatic based on category in ads table. for example :- if in table have phones category,i will automatic join phones table then SELECT * FROM `ads` JOIN `phone` ON `ads.id` = `phone.id` if in table have cars category,i will automatic join cars table SELECT * FROM `ads` JOIN `cars` ON `ads.id` = `cars.id`

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