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  • allowing bb code but not java script

    - by user1405062
    Hello im trying to get the hang of using bb codes onto my normal php site ( not forum or anything just a normal site ) I have seen a few posts like this one http://www.pixel2life.com/forums/index.php?/topic/10659-php-bbcode-parser/ which says i need a bb parser. I was just wondering can anyone show me how i would use one ? I have a status box were users can update there status but i would like to allow bb codes but not java script. So when im doing my inserting into the db i strip the status like so.. $status= mysql_real_escape_string($_POST['status']); $status2= strip_tags($status); And that stops the java script and tags from getting though but i need the bb code tags to come though but carry on blocking the java script code is there anyway to do this ? Also then i just echo it out echo $status2 ; But just plain text shows so was just wondering if anyone knows how to let though bb code and stop java script and could some one show me how to use the bb parasher ? also need to know how to echo out the bb coding...

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  • Deleting unneeded rows from a table with 2 criteria

    - by stormbreaker
    Hello. I have a many-to-many relations table and I need to DELETE the unneeded rows. The lastviews table's structure is: | user (int) | document (int) | time (datetime) | This table logs the last users which viewed the document. (user, document) is unique. I show only the last 10 views of a document and until now I deleted the unneeded like this: DELETE FROM `lastviews` WHERE `document` = ? AND `user` NOT IN (SELECT * FROM (SELECT `user` FROM `lastviews` WHERE `document` = ? ORDER BY `time` DESC LIMIT 10) AS TAB) However, now I need to also show the last 5 documents a user has viewed. This means I can no longer delete rows using the previous query because it might delete information I need (say a user didn't view documents in 5 minutes and the rows are deleted) To sum up, I need to delete all the records that don't fit these 2 criterias: SELECT ... FROM `lastviews` WHERE `document` = ? ORDER BY `time` DESC LIMIT 10 and SELECT * FROM `lastviews` WHERE `user` = ? ORDER BY `time` DESC LIMIT 0, 5 I need the logic. Thanks in advance.

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  • Comparing date range quarters sql server

    - by CR41G14
    I have a policies in a system PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 POL214 23/08/2012 29/09/2012 I am asking a user for a reporting date, the user enters 24/10/2012 this becomes @StartDate From this I derive what the quarter is by the month: set @currentMonth = Month(@StartDate) if @currentMonth = 1 or @currentMonth = 2 or @currentMonth = 3 begin set @startmonth = 1 set @endmonth = 3 end if @currentMonth = 4 or @currentMonth = 5 or @currentMonth = 6 begin set @startmonth = 4 set @endmonth = 6 end if @currentMonth = 7 or @currentMonth = 8 or @currentMonth = 9 begin set @startmonth = 7 set @endmonth = 9 end if @currentMonth = 10 or @currentMonth = 11 or @currentMonth = 12 begin set @startmonth = 10 set @endmonth = 12 end I then get a date range: @quarterStartDate = CAST(CAST(YEAR(@StartDate) AS varchar) + '-' + CAST(@startMonth AS varchar) + '-' + '01') AS Date) @quarterEndDate = CAST(CAST(YEAR(@EcdDate) AS varchar) + '-' + CAST(@endMonth AS varchar) + '-' + '31') AS Date) This will give me 01-10-2012 and 31-12-2012. Basically I need a script to only bring back the policies that are in this quarter. The policy doesn't have to span the entire quarter date range, just exist in the quarter date range. The results expected would be PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 Pol123 appears because it spans over the quarterly date range. Pol212 is there because it expires in that quarter date range. Pol214 does not appear because it neither spans, expires or starts in this quarter. Any help would be greatly appreciated

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  • [PHP] Local/Dev/Live deployment - best workflow

    - by Adam Kiss
    Hello, situation We our little company with 3 people, each has a localhost webserver and most projects (previous and current) are on one PC network shared disk. We have virtual server, where some of our clients' sites and our site. Our standard workflow is: Coder PC ? Programmer localhost ? dev domain (client.company.com) ? live version (client.com) It often happens, that there are two or three guys working on same projects at the same time - one is on dev version, two are on localhost. When finished, we try to synchronize the files on dev version and ideally not to mess up any files, which *knock knock * doesn't happen often. And then one of us deploys dev version on live webserver. question we are looking for a way to simplify this workflow while updating websites - ideally some sort of diff uploader or VCS probably (Git/SVN/VCS/...), but we are not completely sure where to begin or what way would be ideal, therefore I ask you, fellow stackoverflowers for your experience with website / application deployment and recommended workflow. We probably will also need to use Mac in process, so if it won't be a problem, that would be even better. Thank you

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  • where to store information like gender and year of birth?

    - by fayer
    i have users and i need them to specify a gender (male, female) and year of birth (1930, 1931...1999, 2000). i wonder where i should store these values: in the database? in php file? if i store them in the database i have to manually create all entries first. but a good thing is that the user table will have constraints so the gender field will always be male or female, it cannot be something else. if i store them in the php file (eg. as html) then i can easily add/remove values. but a con is that i dont have the constraints in database, so another value could be stored as gender by mistake, even though i could add validation in php backend so even if someone hacked the html it is not stored unless it's either male or female. what is best practice to do this? thanks

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  • Perl Script to search and replace in .SQL query file with user inputs

    - by T.Mount
    I have a .SQL file containing a large number of queries. They are being run against a database containing data for multiple states over multiple years. The machine I am running this on can only handle running the queries for one state, in one year, at a time. I am trying to create a Perl script that takes user input for the state abbreviation, the state id number, and the year. It then creates a directory for that state and year. Then it opens the "base" .SQL file and searches and replaces the base state id and year with the user input, and saves this new .SQL file to the created directory. The current script I have (below) stops at open(IN,'<$infile') with "Can't open [filename]" It seems that it is having difficulty finding or opening the .SQL file. I have quadruple-checked to make sure the paths are correct, and I have even tried replacing the $path with an absolute path for the base file. If it was having trouble with creating the new file I'd have more direction, but since it can't find/open the base file I do not know how to proceed. #!/usr/local/bin/perl use Cwd; $path = getcwd(); #Cleans up the path $path =~ s/\\/\//sg; #User inputs print "What is the 2 letter state abbreviation for the state? Ex. 'GA'\n"; $stlet = <>; print "What is the 2 digit state abbreviation for the state? Ex. '13'\n"; $stdig = <>; print "What four-digit year are you doing the calculations for? Ex. '2008'\n"; $year = <>; chomp $stlet; chomp $stdig; chomp $year; #Creates the directory mkdir($stlet); $new = $path."\/".$stlet; mkdir("$new/$year"); $infile = '$path/Base/TABLE_1-26.sql'; $outfile = '$path/$stlet/$year/TABLE_1-26.sql'; open(IN,'<$infile') or die "Can't open $infile: $!\n"; open(OUT,">$infile2") or die "Can't open $outfile: $!\n"; print "Working..."; while (my $search = <IN>) { chomp $search; $search =~ s/WHERE pop.grp = 132008/WHERE pop.grp = $stdig$year/g; print OUT "$search\n"; } close(IN); close(OUT); I know I also probably need to tweak the regular expression some, but I'm trying to take things one at a time. This is my first Perl script, and I haven't really been able to find anything that handles .SQL files like this that I can understand. Thank you!

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  • % confuses python raw sql query

    - by Jonathan
    Following this SO question, I'm trying to "truncate" all tables related to a certain django application using the following raw sql commands in python: cursor.execute("set foreign_key_checks = 0") cursor.execute("select concat('truncate table ',table_schema,'.',table_name,';') as sql_stmt from information_schema.tables where table_schema = 'my_db' and table_type = 'base table' AND table_name LIKE 'some_prefix%'") for sql in [sql[0] for sql in cursor.fetchall()]: cursor.execute(sql) cursor.execute("set foreign_key_checks = 1") Alas I receive the following error: C:\dev\my_project>my_script.py Traceback (most recent call last): File "C:\dev\my_project\my_script.py", line 295, in <module> cursor.execute(r"select concat('truncate table ',table_schema,'.',table_name,';') as sql_stmt from information_schema.tables where table_schema = 'my_db' and table_type = 'base table' AND table_name LIKE 'some_prefix%'") File "C:\Python26\lib\site-packages\django\db\backends\util.py", line 18, in execute sql = self.db.ops.last_executed_query(self.cursor, sql, params) File "C:\Python26\lib\site-packages\django\db\backends\__init__.py", line 216, in last_executed_query return smart_unicode(sql) % u_params TypeError: not enough arguments for format string Is the % in the LIKE making trouble? How can I workaround it?

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  • Complex multiple join query across 3 tables

    - by Keir Simmons
    I have 3 tables: shops, PRIMARY KEY cid,zbid shop_items, PRIMARY KEY id shop_inventory, PRIMARY KEY id shops a is related to shop_items b by the following: a.cid=b.cid AND a.zbid=b.szbid shops is not directly related to shop_inventory shop_items b is related to shop_inventory c by the following: b.cid=c.cid AND b.id=c.iid Now, I would like to run a query which returns a.* (all columns from shops). That would be: SELECT a.* FROM shops a WHERE a.cid=1 AND a.zbid!=0 Note that the WHERE clause is necessary. Next, I want to return the number of items in each shop: SELECT a.*, COUNT(b.id) items FROM shops a LEFT JOIN shop_items b ON b.cid=a.cid AND b.szbid=a.zbid WHERE a.cid=1 GROUP BY b.szbid,b.cid As you can see, I have added a GROUP BY clause for this to work. Next, I want to return the average price of each item in the shop. This isn't too hard: SELECT a.*, COUNT(b.id) items, AVG(COALESCE(b.price,0)) average_price FROM shops a LEFT JOIN shop_items b ON b.cid=a.cid AND b.szbid=a.zbid WHERE a.cid=1 GROUP BY b.szbid,b.cid My next criteria is where it gets complicated. I also want to return the unique buyers for each shop. This can be done by querying shop_inventory c, getting the COUNT(DISTINCT c.zbid). Now remember how these tables are related; this should only be done for the rows in c which relate to an item in b which is owned by the respective shop, a. I tried doing the following: SELECT a.*, COUNT(b.id) items, AVG(COALESCE(b.price,0)) average_price, COUNT(DISTINCT c.zbid) FROM shops a LEFT JOIN shop_items b ON b.cid=a.cid AND b.szbid=a.zbid LEFT JOIN shop_inventory c ON c.cid=b.cid AND c.iid=b.id WHERE a.cid=1 GROUP BY b.szbid,b.cid However, this did not work as it messed up the items value. What is the proper way to achieve this result? I also want to be able to return the total number of purchases made in each shop. This would be done by looking at shop_inventory c and adding up the c.quantity value for each shop. How would I add that in as well?

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  • Insert names into table if not already existing

    - by John
    I am trying to build an application that allows users to submit names to be added to a db table (runningList). Before the name is added tho, I would like to check firstname and lastname against another table (controlList). It must exist in (controlList) or reply name not valid. If the name is valid I would like to then check firstname and lastname against (runningList) it make sure it isnt already there. If it isnt there, then insert firstname & lastname. If it is there, reply name already used. Below is code that worked before I tried to add the test against the controlList, I somehow broke it altogether while trying to add the extra step. if (mysql_num_rows(mysql_query('SELECT * FROM runninglist WHERE firstname=\'' .$firstname . '\' AND lastname=\'' . $lastname . '\' LIMIT 1')) == 0) { $sql="INSERT INTO runninglist (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; } else { echo "This name has been used."; } Any direction would be appreciated. Thanx John

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  • How to prevent users to change url parameter in PHP?

    - by Sachin
    I am developing a site where I am sending parameters like ids by url. I have used urlencode and base64encode to encode the parameters. My problem is that how can I prevent the users or hackers to play with url paramenters Or give access only if the parameter value is exist in database? I have at least 2 and at most 5 parameter in url so is this feasible to check every parameter is exist in database on every page? Thanks

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  • PHP classes, parse syntax errors when using 'var' to declare variables

    - by jon
    I am a C# guy trying to translate some of my OOP understanding over to php. I'm trying to make my first class object, and are hitting a few hitches. Here is the beginning of the class: <?php require("Database/UserDB.php"); class User { private var $uid; private var $username; private var $password; private var $realname; private var $email; private var $address; private var $phone; private var $projectArray; public function _construct($username) { $userArray = UserDB::GetUserArray($username); $uid = $userArray['uid']; $username = $userArray['username']; $realname = $userArray['realname']; $email = $userArray['email']; $phone = $userArray['phone']; $i = 1; $projectArray = UserDB::GetUserProjects($this->GetID()); while($projectArray[$i] != null) { $projectArray[$i] = new Project($projectArray[$i]); } UserDB.php is where I have all my static functions interacting with the Database for this User Class. I am getting errors using when I use var, and I'm getting confused. I know I don't HAVE to use var, or declare the variables at all, but I feel it is a better practice to do so. the error is "unexpected T_VAR, expecting T_VARIABLE" When I simply remove var from the declarations it works. Why is this?

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  • how do I copy value from one table and inserted to another in the same database??

    - by mathew
    I am having a tough time to do this... I have created two table say table-1 and table-2 in same database.what I want is I need to copy some values from table-1 and insert the same to table-2. I have tried many ways but it does not seems work. below is my code can any one tell me where I am missing?? $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $resultb = mysql_query("SELECT * FROM table-2")or die(mysql_error()); $row = mysql_fetch_array($resultb); $days = (strtotime(date("Y-m-d")) - strtotime($row['regtime'])) / (60 * 60 * 24); if($row > 0 && $days < 1){ $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_close($db); }else{ $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $result = mysql_query("SELECT * FROM table-1 WHERE regtime = DATE(NOW()) ORDER BY rank ASC LIMIT 1;")or die(mysql_error()); $row = mysql_fetch_array($result); $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_query("INSERT INTO table-2 (regtime,person,catog,position,location,rank) VALUES(NOW(),'$person','$catogr','$position','$location','$rank')"); mysql_close($db); }

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  • PHP PDO Parameters from a function returned array

    - by noko
    I've got a function written that runs a query based on parameters passed to the function. I can't seem to figure out why doing the following returns a result: function test($function_returned_array) { $variable = 'Hello World'; $sql = 'SELECT `name`, `pid` FROM `products` WHERE `name` IN (?)'; $found = $this->db->get_array($sql, $variable); } While this doesn't return any results: function test2($function_returned_array) { $sql = 'SELECT `name`, `pid` FROM `products` WHERE `name` IN (?)'; $found = $this->db->get_array($sql, $function_returned_array[0]); } $function_returned_array[0] is also equal to 'Hello World'. Shouldn't they both return the same results? When I echo the values of $variable and $function_returned_array[0], they are both 'Hello World' Here's the relevant parts of my PDO wrapper: public function query(&$query, $params) { $sth = $this->_db->prepare($query); if(is_null($params)) { $sth->execute(); } else if(is_array($params)) { $sth->execute($params); } else { $sth->execute(array($params)); } $this->_rows = $sth->rowCount(); $this->_counter++; return $sth; } public function get_array(&$query, $params, $style = PDO::FETCH_ASSOC) { $q = $this->query($query, $params); return $q->fetchAll($style); } I'm using PHP 5.3.5. Any help would be appreciated.

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  • Converting SQL with subselect in select to HQL

    - by UltraVi01
    I have the following SQL that I am having problems converting to HQL. A NPE is getting thrown -- which I think has something to do with the SUM function. Also, I'd like to sort on the subselect alias -- is this possible? SQL (subselect): SELECT q.title, q.author_id, (SELECT IFNULL(SUM(IF(vote_up=true,1,-1)), 0) FROM vote WHERE question_id = q.id) AS votecount FROM question q ORDER BY votecount DESC HQL (not working) SELECT q, (SELECT COALESCE(SUM(IF(v.voteUp=true,1,-1)), 0) FROM Vote v WHERE v.question = q) AS votecount FROM Question AS q LEFT JOIN q.author u LEFT JOIN u.blockedUsers ub WHERE q.dateCreated BETWEEN :week AND :now AND u.id NOT IN ( SELECT ub.blocked FROM UserBlock AS ub WHERE ub.blocker =:loggedInUser ) AND (u.blockedUsers IS EMPTY OR ub.blocked !=:loggedInUser) ORDER BY votecount DESC

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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  • Fetching a result twice with deferend name

    - by user1799842
    I have 1 table with tasks named opentask:columns: id,title,description,expires,creator_id,creator_name, executer_id, executer_name, priority_id, status_id1 table with users named user: with columns: user_id, username What I want is to create a query where there will be all columns from opentask table where the executer_id will be equal to the user_id of user table AND the creator_id will be equal to the user_id again. This creates a confusion because the first equality excludes the second.So I need somehow to create a query where I will include the usernames for the executer with something like where "opentask.executer_id=user_user_id" and at the same time I will include the username again (as a differend name?) for the creator with something like "where opentask.executer_id=user_user_id"So I try this, which of course I know that is missing something, can you help? SELECT DISTINCT id, title, description, expires, creator_id, executer_id, oc_opentask.priority_id, oc_opentask.status_id, priority_name, status_name, user_id, username, (SELECT username FROM oc_opentask, oc_user WHERE oc_opentask.creator_id=oc_user.user_id) AS username2 FROM oc_opentask, oc_opentask_priority, oc_user, oc_opentask_status WHERE oc_opentask.priority_id=oc_opentask_priority.priority_id AND oc_opentask.executer_id=oc_user.user_id AND oc_opentask.status_id=oc_opentask_status.status_id ORDER BY oc_opentask.expires DESC

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  • SQL Query That Should Return Least two days record

    - by Aryans
    I have a table "abc" where i store timestamp having multiple records let suppose 1334034000 Date:10-April-2012 1334126289 Date:11-April-2012 1334291399 Date:13-April-2012 I want to build a sql query where I can find at first attempt the records having last two day values and so second time the next two days . . . Example: Select *,dayofmonth(FROM_UNIXTIME(i_created)) from notes where dayofmonth(FROM_UNIXTIME(i_created)) > dayofmonth(FROM_UNIXTIME(i_created)) -2 order by dayofmonth(FROM_UNIXTIME(i_created)) this query returns all the records date wise but we need very most two days record. Please suggest accordingly. Thanks in advance

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  • Copying a database into a new database including structure and data

    - by Jason
    In phpMyAdmin under operations I can "Copy database to:" and select Structure and data CREATE DATABASE before copying Add AUTO_INCREMENT value I need to be able to do that without using phpMyAdmin. I know how to create the database and user. I have a source database that's a shell that I can work from so all I really need is the how to copy all the table structure and data part. (I know, the harder part) system() & exec() are not options for me which rules out mysqldump. (I think) How can I loop through each table and recreate it's structure and data? Is it just looping through the results of SHOW TABLES then for each table looping through DESCRIBE tablename Then, is there an easy way for getting the data copied?

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  • Input html tag not parsing properly in php

    - by Akaash
    I have a database with names that I would like displayed in the form of a table with checkboxes. Everything works until I try to place the html tag into my php code. When I put the input tag in it gives me the error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' I can't see where I would put a comma or semi colon. <form> <?php $name = $_POST['name']; $host = "mysql16.000webhost.com"; $user_name = "a1611480_akaash"; $pwd = "****"; $database_name = "a1611480_akaash"; $db = mysql_connect($host, $user_name, $pwd); mysql_select_db($database_name); $result = mysql_query("SELECT name FROM Sort"); $var = array(); while ($row = mysql_fetch_array($result)) { $var[] = $row['name']; } $unique = array_unique($var); foreach ($unique as $value) { echo "<p class = Body_text><label>$value</label> <input type="checkbox" name="name" value="$value" /> </p>\n"; } ?> </form>

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  • check for several conditions when a user logs in

    - by paul
    I would like to accomplish the following: If a username or password field is null, notify the user. If user name already exists, do not insert into the database and notify user to create a different name. if the username is unique and password is not null, return the username to the user. As of now it always returns "Please enter a different user name." I believe the issue has to do with the database query but I am not sure. If anyone can have a look and see if I am making an error, I greatly appreciate it, thanks. if ($userName or $userPassword = null) { echo "Please enter a user name and password or return to the homepage."; } elseif (mysql_num_rows(mysql_query("SELECT count(userName) FROM logininfo WHERE userName = '$userName'")) ==1) { echo "Please enter a different user name."; } elseif ($userName and $userPassword != null) { echo "Your login name is: $userName"; }

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