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  • Wordpress SQL_CALC fix causes PHP error

    - by ok1ha
    I'm looking for some followup on an older topic for Wordpress where SQL_CALC was found to slow things down when you have a large DB in Wordpress. I have been using the code, at the bottom of this post, to get around it but it does generate an error in my error log. How would I prevent this error? PHP Warning: Division by zero in /var/www/vhosts/domain.com/httpdocs/wp-content/themes/greatTheme/functions.php on line 19 The original thread: http://wordpress.org/support/topic/slow-queries-sql_calc_found_rows-bringing-down-site?replies=25 The code in my functions.php: add_filter('pre_get_posts', 'optimized_get_posts', 100); function optimized_get_posts() { global $wp_query, $wpdb; $wp_query->query_vars['no_found_rows'] = 1; $wp_query->found_posts = $wpdb->get_var( "SELECT COUNT(*) FROM wp_posts WHERE 1=1 AND wp_posts.post_type = 'post' AND (wp_posts.post_status = 'publish' OR wp_posts.post_status = 'private')" ); $wp_query->found_posts = apply_filters_ref_array( 'found_posts', array( $wp_query->found_posts, &$wp_query ) ); $wp_query->max_num_pages = ceil($wp_query->found_posts / $wp_query->query_vars['posts_per_page']); return $wp_query; }

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  • Is it possible to integrate user databases between Drupal and an ASP&SQL Server platform?

    - by hecatomber
    We have a game project designed on ASP&SQL Server, and we need to integrate it's user database with Drupal. This would be easier from Project to Drupal (since there is user_save and user_delete functions available globally by using drupal bootstrap) but I'm not sure if we can execute PHP functions on an ASP platform. Is there any documentation for this kind of problems? What do you suggest?

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  • Django database - how to add this column in raw SQL.

    - by alex
    Suppose I have my models set up already. class books(models.Model): title = models.CharField... ISBN = models.Integer... What if I want to add this column to my table? user = models.ForeignKey(User, unique=True) How would I write the raw SQL in my database so that this column works?

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  • differentiating results of sql right join

    - by Sourabh
    Hi I have a below SQL query SELECT `User`.`username` , Permalink.perma_link_id, Permalink.locale, Permalink.title, DATEDIFF( CURDATE( ) , Permalink.created ) AS dtdiff, `TargetSegment`.segment_text, TargetSegment.source_segment_id ,TargetSegment.perma_link_id ,TargetSegment.created ,TargetSegment.updated, DATEDIFF( CURDATE( ) , TargetSegment.updated ) AS datediff FROM `users` AS `User` RIGHT JOIN perma_links AS `PermaLink` ON ( `PermaLink`.`username` = `User`.`username` ) RIGHT JOIN target_segments AS `TargetSegment` ON ( `TargetSegment`.`username` = `User`.`username` ) RIGHT JOIN source_segments AS `SourceSegment` ON ( `SourceSegment`.`source_detail_id` = `PermaLink`.`source_detail_id` ) LEFT JOIN source_details AS `SourceDetail` ON ( `SourceSegment`.`source_detail_id` = `SourceDetail`.`id` ) WHERE `TargetSegment`.`username` = "xxxx" AND `TargetSegment`.`segment_text` <> "" AND `Permalink`.`perma_link_id` = `TargetSegment`.`perma_link_id` AND `TargetSegment`.`source_segment_id` = `SourceSegment`.`id` AND `Permalink`.`source_detail_id` = `SourceDetail`.`id` ORDER BY `TargetSegment`.`updated` DESC LIMIT 0 , 10 This SQL is fetching correct results for me.I want to identify from which table each row if from , to be specific which result is due to PermaLink table and which is from TargetSegment table. is this achievable ?

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  • Running a sharded DB from a single machine

    - by ming yeow
    This sounds kinda dumb, but I have a sharded DB that I no longer think I need to run on 2 machines, and would like to run on one single machine instead. Any ideas on how that can potentially be done? There are lots of resources on how i can achieve the converse, but very little on how this can be done

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  • Get the sum by comparing between two tables

    - by Ismail Gunes
    I have to tables ProdBiscuit As tb and StockData As sd , I have to get the sum of the quantity in StockData (quantite) with the condition of if (sd.status0 AND sd.prodid = tb.id AND sd.matcuisine = 3) Here is my sql query SELECT tb.id, tb.nom, tb.proddate, tb.qty, tb.stockrecno FROM ProdBiscuit AS tb JOIN (SELECT id, prodid, matcuisine, status, SUM(quantite) AS rq FROM StockData) AS sd ON (tb.id = sd.prodid AND sd.status > 0 AND sd.matcuisine = 3) LIMIT 25 OFFSET @Myid This gives me no rows at all ? There is only 3 rows in ProdBiscuit and 11 rows in Stockdata and there is only 2 rows in StockData good with the condition. And as shown in the picture there is only two rows which give the condition. What is wrong in my query ? PS: The green lines on the image shows the condition in my query.

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  • How can I remove this query from within a loop?

    - by Chris
    I am currently designing a forum as a personal project. One of the recurring issues I've come across is database queries in loops. I've managed to avoid doing that so far by using table joins or caching of data in arrays for later use. Right now though I've come across a situation where I'm not sure how I can write the code in such a way that I can use either of those methods easily. However I'd still prefer to do at most 2 queries for this operation rather than 1 + 1 per group of forums, which so far has resulted in 5 per page. So while 5 isn't a huge number (though it will increase for each forum group I add) it's the principle that's important to me here, I do NOT want to write queries in loops What I'm doing is displaying forum index groupings (eg admin forums, user forums etc) and then each forum within that group on a single page index, it's the combination of both in one page that's causing me issue. If it had just been a single group per page, I'd use a table join and problem solved. But if I use a table join here, although I can potentially get all the data I need it'll be in one mass of results and it needs displaying properly. Here's the code (I've removed some of the html for clarity) <?php $sql= "select * from forum_groups"; //query 1 $result1 = $database->query($sql); while($group = mysql_fetch_assoc($result1)) //first loop {?> <table class="threads"> <tr> <td class="forumgroupheader"> <?php echo $group['group_name']; ?> </td> </tr> <tr> <td class="forumgroupheader2"> <?php echo $group['group_desc']; ?> </td> </tr> </table> <table> <tr> <th class="thforum"> Forum Name</th> <th class="thforum"> Forum Decsription</th> <th class="thforum"> Last Post </th> <tr> <?php $group_id = $group['id']; $sql = "SELECT forums.id, forums.forum_group_id, forums.forum_name, forums.forum_desc, forums.visible_rank, forums.locked, forums.lock_rank, forums.topics, forums.posts, forums.last_post, forums.last_post_id, users.username FROM forums LEFT JOIN users on forums.last_post_id=users.id WHERE forum_group_id='{$group_id}'"; //query 2 $result2 = $database->query($sql); while($forum = mysql_fetch_assoc($result2)) //second loop {?> So how can I either a) write the SQL in such a way as to remove the second query from inside the loop or b) combine the results in an array either way I need to be able to access the data as an when so I can format it properly for the page output, ie within the loops still.

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  • A logical problem with two tables

    - by Luke
    Hey guys, I created a list for fixtures. $result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date"); $i = 1; $d = "Start"; while ($row = mysql_fetch_assoc($result)) { $odate = $row['date']; $date=date("F j Y", $row['date']); echo "<p>Fixture $i - $d to $date</p>"; } As you can see from the query, the date is displayed from the fixtures table. The way my system works is that when a fixture is "played", it is removed from this table. Therefore when the entire round of fixtures are complete, there wont be any dates for that round in this table. They will be in another table. Is there anyway I can run an other query for dates at the same time, and display only dates from the fixtures table if there isnt a date in the results table? "SELECT * FROM ".TBL_CONF_RESULTS." WHERE compid = '$_GET[id]' && type2 = '2' ORDER BY date" That would be the second query!

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  • Problem with joining to an empty table

    - by Imran Omar Bukhsh
    I use the following query: select * from A LEFT JOIN B on ( A.t_id != B.t_id) to get all the records in A that are not in B. The results are fine except when table B is completely empty, but then I do not get any records, even from table A. Later It wont work yet! CREATE TABLE IF NOT EXISTS T1 ( id int(11) unsigned NOT NULL AUTO_INCREMENT, title varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, t_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Dumping data for table T1 INSERT INTO T1 (id, title, t_id) VALUES (1, 'apple', 1), (2, 'orange', 2); -- -- Table structure for table T2 CREATE TABLE IF NOT EXISTS T2 ( id int(11) NOT NULL AUTO_INCREMENT, title varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, t_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; -- -- Dumping data for table T2 INSERT INTO T2 (id, title, t_id) VALUES (1, 'dad', 2); Now I want to get all records in T1 that do not have a corresponding records in T2 I try SELECT * FROM T1 LEFT OUTER JOIN T2 ON T1.t_id != T2.t_id and it won't work

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  • Select where a value present

    - by Roy
    First a database example: id, product_id, cat, name, value -------------------------------- 1,1,Algemeen,Processor,2 Ghz 2,1,Algemeen,Geheugen,4 GB 3,2,Algemeen,Processor,3 Ghz 4,2,Algemeen,Geheugen,4 GB 5,3,Beeldscherm,Inch,22" 6,3,Beeldscherm,Kleur,Zwart 7,3,Algemeen,Geheugen,3 GB 8,3,Algemeen,Processor,3 Ghz I want with one query to select the follow id's: 1,2,3,4,7,8 Because the cat = algemeen and the name = processor by these products. ID 5,6 are only present by product 3. So, the entry's (cat and name) which are present by all products (product_id) have to be selected. The database contains 80.000 entry's with a lot of diffrent cat's, name's and value's. Is this possible with one query or is some php necessary? How do I do this? My apologies for the bad English.

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  • Error during data UPDATE in php

    - by Piyush
    $sql = "UPDATE tblprofile SET name = '$membername' , f_h_name = '$fathername', maritalS = '$mstatus' , dob = '$dob' , occupation = '$occupation' , nominee = '$nominee' , address1 = '$address1' , address2 = '$address2', city = '$city', district = '$district', state = '$state', pin = '$areapin', mobile = '$mobileno', email = '$email', PANno = '$panno', bankname = '$bankname', branch = '$branch', accountno = '$accountno' WHERE userId = '$_SESSION['UserId']' "; //line 212 if(mysql_query($sql)) { echo "Updation Done."; } Error comes in browser : Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\xampp\htdocs\303\saveEditProfile.php on line 212

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  • Confused as to why my PHP include isn't working

    - by Sam
    I had a prototype of my website working correctly, meaning it connected to the database correctly. This was done with just one file called "connect.php" which had mysql_connect() and such inside it. I then separated the connect information into to separate files, one containing the account information (account.php) and one containing the connect function (connect.php), with correct information (I triple checked) and it isn't connecting properly. All I can think of is that I'm not including it the right way. This is what I have in a file: <?php include('account.php'); include('connect.php'); include('functions.php'); ..... ?>

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  • indexing question

    - by user522962
    I have a table w/ 3 columns: name, phone, date. I have 3 indexes: 1 on phone, 1 on date and 1 on phone and date. I have the following statement: SELECT * FROM ( SELECT * FROM people WHERE phone IS NOT NULL ORDER BY date DESC) as t GROUP BY phone Basically, I want to get all unique phone numbers ordered by date. This table has about 2.5 million rows but takes forever to execute....are my indexes right? UPDATE: My EXPLAIN statement comes back with 2 rows: 1 for primary table and 1 for derived table. It says I am using temporary and using filesort for my primary table. For my derived table, it says my possible keys are (phone), and (phone, date) but it is using filesort.

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  • Archiving rows dynamically

    - by Serge
    I was wondering what would be the best solution to dynamically archive rows. For instance when a user marks a task as completed, that task needs to be archived yet still accessible. What would be the best practices for achieving this? Should I just leave it all in the same table and leave out completed tasks from the queries? I'm afraid that over time the table will become huge (1,000,000 rows in a year or less). Or should I create another table ie task_archive and query that row whenever data is needed from it? I know similar questions have been asked before but most of them where about archiving thousands of rows simultaneously, I just need to know what would be the best method (and why) to archive 1 row at a time once it's been marked completed

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  • Find node level in a tree

    - by Álvaro G. Vicario
    I have a tree (nested categories) stored as follows: CREATE TABLE `category` ( `category_id` int(10) unsigned NOT NULL AUTO_INCREMENT, `category_name` varchar(100) NOT NULL, `parent_id` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`category_id`), UNIQUE KEY `category_name_UNIQUE` (`category_name`,`parent_id`), KEY `fk_category_category1` (`parent_id`,`category_id`), CONSTRAINT `fk_category_category1` FOREIGN KEY (`parent_id`) REFERENCES `category` (`category_id`) ON DELETE SET NULL ON UPDATE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_spanish_ci I need to feed my client-side language (PHP) with node information (child+parent) so it can build the tree in memory. I can tweak my PHP code but I think the operation would be way simpler if I could just retrieve the rows in such an order that all parents come before their children. I could do that if I knew the level for each node: SELECT category_id, category_name, parent_id FROM category ORDER BY level -- No `level` column so far :( Can you think of a way (view, stored routine or whatever...) to calculate the node level? I guess it's okay if it's not real-time and I need to recalculate it on node modification.

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  • Zip multiple database PDF blob files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include '../config.php'; include '../connect.php'; $session = $_GET['session']; $query = "SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session = '$session'"; $result = mysql_query($query) or die('Error, query failed'); $files = array(); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { $files[] = "$username-$description.pdf"; } $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); exit(); ?>

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  • Problem while redirecting user after registration

    - by Eternal Learner
    I am creating a simple website . My situation is like this. After registering an user, I want to redirect the user after say 3 seconds to a main page(if the registration succeeds) . The code I have now is as below $query = "INSERT INTO Privileges VALUES('$user','$password1','$role')"; $result = mysql_query($query, $dbcon) or die('Registration Failed: ' . mysql_error()); print 'Thanks for Registering , You will be redirected shortly'; ob_start(); echo "Test"; header("Location: http://www.php.net"); ob_flush() I get the error message Warning: Cannot modify header information - headers already sent by (output started at/home/srinivasa/public_html/ThanksForRegistering.php:27) in /home/srinivasa /public_html/ThanksForRegistering.php on line 35. What do I need to do now ?

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  • Storing database records into array

    - by zerey
    I would want to create an array that will hold records retrieved from a database using a query of SELECT statement. The records to be retrieved have multiple fields such as lastname, firstname, mi and 20 more fields. What would be the best approach on coding this function? alright i have followed what prisoner have given below.. the next question is how do i search through this kind of array using queries? for example i want to search for a username..

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  • How do I choose what and when to cache data with ob_start rather than query the database?

    - by Tim Santeford
    I have a home page that has several independent dynamic parts. The parts consist of a list of recent news from the company, a site statistics panel, and the online status of certain employees. The recent news changes monthly, site statistics change daily, and online statuses change on a per minute bases. I would like to cache these panels so that the db is not hit on every page load. Is using ob_start() then ob_get_contents() to cache these parts to a file the correct way to do this or is there a better method in PHP5 for doing this? In asking this question I'm trying to answer these additional questions: How can I determine the correct approach for caching this data without doing extensive benchmarking? Does it make sense to cache these parts in different files and then join them together per requests or should I re-query the data and cache once per minute? I'm looking for a rule of thumb for planning pages and for situations where doing testing is not cost effective (The client is not paying enough for it I mean). Thanks!

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  • Separating Variables Inside an Array

    - by Jake Avila Talledo
    Hey i have an array an I need to separate each value so it would be something like this $arry = array(a,b,c,d,e,f) $point1 = (SELECT distance FROM Table WHERE Origin = a AND Destination = b); $point2 = (SELECT distance FROM Table WHERE Origin = b AND Destination = c); $point3 = (SELECT distance FROM Table WHERE Origin = c AND Destination = d); $point4 = (SELECT distance FROM Table WHERE Origin = d AND Destination = e); $point5 = (SELECT distance FROM Table WHERE Origin = e AND Destination = f); $point6 = (SELECT distance FROM Table WHERE Origin = f AND Destination = g); $point7 = (SELECT distance FROM Table WHERE Origin = g AND Destination = f); $total_trav = $point1+$point2+$point3+$point4+$point5+$point6+$point7

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  • Want to avoid the particular rows from select join query... See description

    - by OM The Eternity
    I have a Select Left Join Query whis displays me the rows for the latest changedone(its a time) column name ("field" should not be equal) column name ("trackid" should not be equal), and column name "Operation should be "UPDATE" ", below is the query I am talking about... SELECT j1. * FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON ( j1.trackid != j2.trackid AND j1.field != j2.field AND j1.changedone < j2.changedone ) WHERE j1.operation = 'UPDATE' AND j2.id IS NULL Now here I don't want a row to be displayed with a two particular column's value i.e. "field's value" the value is "LastvisitDate" and "hits" Now if if append the condition in the above query that " AND j1.field != 'lastvistDate' AND j1.field != 'hits' " theni do not get any result... The table structure is jos_audittrail: id trackid operation oldvalue newvalue table_name live changedone(its a time) I hope i have given the details properly If u still find something missing I will try to provide it more better way... Pls help me to avoid those two rows with those to mentioned value of "field"

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  • show count of rows between 2 dates

    - by hello
    I am trying to show the number of rows that have a created_at date between 2 dates. Here is my code: $result=mysql_query("select * from payments where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'") or die('You need to add an administrator ' ); $counter = mysql_query("select * from payments where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'"); $row = mysql_fetch_array($result); $id = $row['id']; $num = mysql_fetch_array($counter); $countjan = $num["id"]; However when i echo (<?php echo"$jan";?>)this shows as 0 any idea how i can get this to work P.s there is 1 row within this date range

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